When we are not sure if the distribution of a population was normal, we use t-procedures. These procedures are safe in most conditions.
However, there is a situation where we would not be safe using a t-procedure that is if the stemplot of the data has a large outlier. Therefore, option A is correct.Let's look at the other options:B. The sample standard deviation is large: A large standard deviation would lead to large variation in the data and the sample mean might not be an accurate representation of the population mean. In this case, we can use the t-procedure to calculate the confidence interval for the population mean, but the interval may not be very precise. Therefore, this option does not make the t-procedure unsafe.C.
A histogram of the data shows moderate skewness: We use t-procedures when the population is not normally distributed. A histogram of the data showing moderate skewness indicates that the distribution may not be normal, but it does not make the t-procedure unsafe. Therefore, this option is incorrect.D. The mean and median of the data are nearly equal: The mean and median of a dataset being nearly equal is a characteristic of a normal distribution. So, it is not a reason to avoid using the t-procedure. Therefore, this option is incorrect.In summary, we would not be safe using a t-procedure if the stemplot of the data has a large outlier.
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The total weight of a freight plane can be modeled by the function w(b) = 85b+ 90,000
The weight of a freight plane can be modeled by the function w(b) = 85b + 90,000, where b represents the number of items being carried.
The function w(b) = 85b + 90,000 represents the relationship between the number of items being carried (b) and the total weight of the freight plane (w). In this function, the coefficient of b (85) represents the weight of each individual item, and 90,000 is a constant term that represents the base weight of the plane without any cargo.
To calculate the weight of the plane for a given number of items, we substitute the value of b into the function. For example, if b = 100, we can find the weight by evaluating w(100) = 85(100) + 90,000 = 8,500 + 90,000 = 98,500. Therefore, when 100 items are carried, the total weight of the plane would be 98,500 units.
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"Complete Question"
The total weight of a freight plane can be modeled by the function w(b) = 85b + 90,000, where 'b' represents the number of bags of cargo on the plane. Determine the total weight of the freight plane when there are 120 bags of cargo.
Triangular prism B is the image of triangular prism A after dilation by a scale factor of 4. If the volume of triangular prism B is 4352 km^3 , find the volume of triangular prism A, the preimage
The volume of triangular prism A, the preimage, is 68 km³.When a triangular prism is dilated, the volume of the resulting prism is equal to the scale factor cubed times the volume of the original prism.
In this case, if triangular prism B is the image of triangular prism A after dilation by a scale factor of 4 and the volume of prism B is 4352 km³, we can find the volume of prism A by reversing the dilation.
Let V₁ be the volume of prism A. Since prism B is a dilation of prism A with a scale factor of 4, we can write:
V₂ = (scale factor)³ * V₁
Substituting the given values, we have:
4352 = 4³ * V₁
Simplifying:
4352 = 64 * V₁
Dividing both sides by 64:
V₁ = 4352 / 64
V₁ = 68 km³.
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HELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLO
Answer:
hi
Step-by-step explanation:
find the area of the kite. please help thank you
Answer:
1/2×d1×d2
=1/2× (4+4)(6+3)
=36
when you multiply a fucntion by -1, what is the effect on its graph
Answer:
The graph flips over the x-axis
Complete the recursive formula of the geometric sequence 27,−9,3,−1,
Step-by-step explanation:
a1 = 27
r = -9/27 = -⅓
the formula :
an = a1. r^(n-1)
= 27. (-⅓)^(n-1)
= 3³(-3`¹)^(n-1)
= 3³(-3)^(1-n)
Which congruence rule is the triangle.
ex. SSS, SAS, ASA, etc
Answer:
The congruence is RHS since they are both right triangles
Step-by-step explanation:
Find the critical value
t/α2
needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places.
Part 1 of 4
(a) For level
95%
and sample size
7
Criticalvalue=0
To construct a confidence interval, we need to determine the critical value based on the confidence level and sample size. For a 95% confidence level and a sample size of 7, the critical value is 2.571.
The critical value is used to calculate the margin of error for a confidence interval. It is based on the confidence level and sample size, and it is determined from a t-distribution table or a calculator.
For a 95% confidence level and a sample size of 7, we can find the critical value by looking at the t-distribution table with 6 degrees of freedom (df = n - 1). The 95% confidence level corresponds to a two-tailed test with an alpha level of 0.05, and the critical value for a t-distribution with 6 degrees of freedom and an alpha level of 0.025 (half of 0.05) is 2.571.
Therefore, to construct a 95% confidence interval for a sample size of 7, we can use the formula:
sample mean ± (critical value) x (standard error of the mean)
where the standard error of the mean is calculated as the sample standard deviation divided by the square root of the sample size.
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FIRST 2 PEOPLE TO ANSWER THIS GETS POINTS AND BRAINLIEST FOR THE BEST ANSWER!
Answer: 15 and 165
1. The sum of the angles here is 180 degrees and we have 2 values for both the angles, 2x-15 and 11x
2. We make an equation to find the value of x, 2x-15+11x=180
3. After solving we get 195=13x and when divided we get x=15
4. Plug 15 into both angle mesurements and we get <AOB is 15 and <BOC is 165
What is the slope of the line?
Answer:
The slope will be the same for a straight line no matter which two points you pick as you know. All you need to do is to calculate the difference in the y coordinates of the 2 points and divide that by the difference of the x coordinates of the points(rise over run). That will give you the slope.
Step-by-step explanation:
a street has parallel curbs 4040 feet apart. a crosswalk bounded by two parallel stripes crosses the street at an angle. the length of the curb between the stripes is 1515 feet and each stripe is 5050 feet long. find the distance, in feet, between the stripes?
The distance between the stripes is 4040 feet (distance between curbs) minus 1515 feet (length of the curb between the stripes), which equals 2525 feet.
To find the distance between the two parallel stripes in the crosswalk, we can use the given information about the street. The distance between the parallel curbs of the street is 4040 feet. The length of the curb between the stripes is 1515 feet, and each stripe is 5050 feet long.
Since the crosswalk is bounded by two parallel stripes, the distance between the stripes can be calculated by subtracting the length of the curb between the stripes from the distance between the curbs of the street.
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The ratio of Pine trees to Maple trees is 15:3,if there are 15 Maple Trees,how many pine trees are their
Answer:
The answer is 75 Pine Trees sorry the answer before was wrong. I fixed it now.
Step-by-step explanation:
The answer is 75 because it says the ratio is 15 Pine and 3 Maple so basically if there are 15 Maple Trees well 3 times 5 equals 15 and 15 times 5 equals 75.
Answer:
150 Pine Trees
In a survey given by camp counselors, campers were
asked if they like to swim and if they like to have a
cookout. The Venn diagram displays the campers'
preferences.
Camp Preferences
S
0.06
0.89
C
0.04
0.01
A camper is selected at random. Let S be the event that
the camper likes to swim and let C be the event that the
camper likes to have a cookout. What is the probability
that a randomly selected camper does not like to have a
cookout?
O 0.01
O 0.04
O 0.06
O 0.07
The probability is 0.96 that a randomly selected camper does not like to have a cookout, based on the given information and the complement rule of probability.
To determine the probability that a randomly selected camper does not like to have a cookout, we need to find the complement of the event C (the event that the camper likes to have a cookout).
Looking at the Venn diagram, we see that the probability of event C is 0.04 (represented by the intersection of circles C and A). Therefore, the probability of the complement of event C (not liking to have a cookout) is equal to 1 minus the probability of event C.
1 - 0.04 = 0.96
Hence, the probability that a randomly selected camper does not like to have a cookout is 0.96.
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What is the slope of this line?
A. 3
B. -1/3
C. -3
D. -2
E. 4
Answer:
-3
Step-by-step explanation:
Pick two points on the graph, lets go with (0, 4) and (1, 1)
y = mx + b
m is the slope and to figure it out use below formula
m = (y₂ - y₁) / (x₂ - x₁)
= (1 - 4) / (1 - 0)
= -3 / 1
= -3
Answer:
C. -3
Explanation:
Given problem;
To solve for the slope of the line;
The slope of a line is the vertical distance to the horizontal displacement on a line.
Slope = \(\frac{Vertical distance}{horizontal displacement}\)
For lines such as this, we use the formula below;
Slope = \(\frac{y_{2} - y_{1} }{x_{2} - x_{1} }\)
To find the slope reference the image attached;
point 1 (0,4) x₁ = 0 y₁ = 4
point 2 (2,-2) x₂ = 2 y₂ = -2
Now input the parameters and solve;
Slope = \(\frac{-2 - 4}{2 - (0)}\) = \(\frac{-6}{2}\)
Slope = -3
The slope of the line is -3
what is 25% off $27
Answer:
6.75 $
Step-by-step explanation:
25%
= 25 / 100
= 1 / 4
25% of $ 27
= ( 1 / 4 ) x ( 27 )
= ( 1 x 27 ) / 4
= 27 / 4
= 6.75 $
Answer:
$20.25
Step-by-step explanation:
Sabrina Uses a hose to fill a 20-gallon fish tank. The hose
puts out water at a rate of 3 gallons per minute. To start
with, the tank has 5 gallons of water in it.
A. How much water is in the tank after 2 minutes
of filling the tank with the hose?
B. Write an equation that represents the volume
Describe the shape of the distribution.
A. It is symmetric.
B. It is uniform.
C. It is bimodal.
D. It is skewed.
----------------------------------------------
6x + 2 = 1x
x = .....
----------------------------------------------
1) 6x + 2 = 1x
____________
6x + 2 = 1x
6x + 2 = x
6x = x - 2
5x = -2
5x/5 = -2/5
x = - 2/5 ☑
estimate the population mean with 90% confidence. i. is 125 in the confidence interval? ii. what is the relationship between the confidence interval and the hypothesis test?
Answer:
To estimate the population mean with 90% confidence, we can use a confidence interval. The formula for a confidence interval for the population mean is:
$\bar{x} \pm z_{\alpha/2}\frac{s}{\sqrt{n}}$
where $\bar{x}$ is the sample mean, $s$ is the sample standard deviation, $n$ is the sample size, $z_{\alpha/2}$ is the critical value of the standard normal distribution corresponding to the desired level of confidence (in this case, 90%), and $\alpha$ is the significance level, which is equal to $1 - \text{confidence level}$.
i. Without knowing the sample data, we cannot determine if 125 is in the confidence interval. However, if 125 is within the interval, then we can say with 90% confidence that the true population mean falls within that interval.
ii. The confidence interval and the hypothesis test are related in that they both provide information about the population mean.
The confidence interval provides a range of values that is likely to contain the true population mean with a certain level of confidence, while the hypothesis test tests a specific claim or hypothesis about the population mean.
If the null hypothesis is rejected in a hypothesis test, this may indicate that the true population mean falls outside of the confidence interval.
Conversely, if the null hypothesis is not rejected, the true population mean may fall within the confidence interval. However, it is important to note that the two methods are not equivalent and provide different types of information.
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On a number line, the distance between x and 8 is 2 units.
Which equation can be used to determine the possible values for x?
2−|x|=8
|8−x|=2
|2−x|=8
8−|x|=2
Answer:
|8−x|=2
Step-by-step explanation:
because you have to subtract them together to see how far apart they are
The formula below gives the sum of the degrees, S, of the interior angles of a polygon. If n represents the number of sides, which equation solves for n?
S = (n-2) x 180
F. n = s/180 + 2
G. n = 180s + 2
H. n = s+2/180
J. n = (s+2) x 180
Answer: F. n = s/180 + 2
Step-by-step explanation:
To find the equation that solves for n, we will isolate the n variable.
Given:
S = (n - 2) x 180
Divide both sides of the equation by 180:
\(\frac{S}{180}\) = n - 2
Add 2 to both sides of the equation:
\(\frac{S}{180}\) + 2 = n
Reflexive property:
n = \(\frac{S}{180}\) + 2
F. n = s/180 + 2
What is the least common denominator of the equation 3/4(x-3)-1/2=2/3
О2
9
12
36
Answer:
C: 12
Step-by-step explanation:
Edge 2020
give an example that shows that the variance of the sum of two random variables is not necessarily equal to the sum of their variances when the random variables are not independent.
Consider X and Y with Var(X) = Var(Y) = 2/3 and Cov(X, Y) = 2/3. Then, Var(X + Y) ≠ Var(X) + Var(Y) because X and Y are not independent.
Let's consider two random variables X and Y, where X and Y are not independent.
The variance of the sum of X and Y is given by:
Var(X+Y) = Var(X) + Var(Y) + 2Cov(X,Y)
where Cov(X,Y) is the covariance between X and Y.
If X and Y are independent, then Cov(X,Y) = 0 and we have:
Var(X+Y) = Var(X) + Var(Y)
However, if X and Y are not independent, then Cov(X,Y) ≠ 0 and the variance of the sum of X and Y is not necessarily equal to the sum of their variances.
For example, let's say X and Y are the number of heads obtained in two consecutive flips of a biased coin. If the coin is biased such that the probability of obtaining a head on the first flip is 0.6 and the probability of obtaining a head on the second flip is 0.8, then X and Y are not independent.
The variance of X is:
Var(X) = npq = 2(0.6)(0.4) = 0.48
The variance of Y is:
Var(Y) = npq = 2(0.8)(0.2) = 0.32
The covariance between X and Y is:
Cov(X,Y) = E(XY) - E(X)E(Y) = (0.6)(0.8) - (0.6)(0.6)(0.8)(0.2) = 0.048
Therefore, the variance of the sum of X and Y is:
Var(X+Y) = Var(X) + Var(Y) + 2Cov(X,Y) = 0.48 + 0.32 + 2(0.048) = 0.896
As we can see, the variance of the sum of X and Y is not equal to the sum of their variances (0.48 + 0.32 = 0.8). This is because X and Y are not independent and their covariance contributes to the variance of their sum.
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If x=−4,y=−2,andz=12, solve the following:
zx
Answer: - 48 (edit: omg i didnt see the minus)
Step-by-step explanation: i mean, only z multiply x
z = 12
x = 4
zx
= z multiply x
= 12 x - 4
= - 48
^_____^
Answer:
-48
Step-by-step explanation:
zx=12(-4)=-48
$1,030 at 5% compounded semiannually for 2 years.
Do not put commas or dollar signs in your answer. Round to the nearest cent.
…. I need help
Answer:
1,678
Step-by-step explanation:
1030(1.05)^10 = 1677.76
FIRST TO ANSWER CORRECTLY GETS BRAINLIEST
Answer:
d
Step-by-step explanation:
a ladder 10 feet long rests against a vertical wall. if the bottom of the ladder slides away from the wall at a rate of 1 feet/sec, how fast is the top of the ladder sliding down the wall when the bottom of the ladder is 6 feet from the wall?
The top of the ladder sliding down the vertical wall with -0.75 feet/s when the bottom of the ladder is 6 feet from the vertical wall using pythagoras theorem and then differentiate the equation.
Given that the ladder is 10 feet long.
To calculate
velocity with which top of the ladder sliding.
given
x= -6 feet
y = 8 feet
By pythagoras theorem
\(x^{2} +y^{2}\) = \(10^{2}\)
differentiate the given equation with respect to t
2 x \(\frac{dx}{dt} +\) 2 y \(\frac{dy}{dt}\) = 0
x * \(\frac{dx}{dt}\) = - y * \(\frac{dy}{dt}\)
\(\frac{dy}{dt}\)= \(\frac {\frac{-x dx}{dt}}{y}\)
\(\frac{dx}{dt}\) = \(V_{x}\) , \(\frac{dy}{dt}\) =\(V_{y}\)
\(V_{y}\) =-((-6)/8) *(1 feet)
\(V_{y}\) = -0.75 feet/s
so, the velocity at which the top of the ladder sliding down the vertical wall when the bottom of the ladder is 6 feet is -0.75 feet/s .
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Please help, Question in the picture!
Answer:
y = 1/3x + 6
Step-by-step explanation:
2. Sheila can frame in a room in 5 hours. David can do the same job in 4 hours.
Working together, how long would it take them to frame in a room?
Answer:
4.5 hours
Step-by-step explanation:
to find the average/middle (how long it would take them when working together) you add both numbers and divide by two
4+5=9
9÷2= 4.5
hope this helps chu <3
The time take by them to the job together is 5 hours.
What is time taken?Time Taken = 1 / Rate of Work If a piece of work is done in x number of days, then the work done in one day = 1/x Total Wok Done = Number of Days × Efficiency.
Efficiency and Time are inversely proportional to each other.
Given that, Sheila can frame in a room in 5 hours. David can do the same job in 4 hours.
We need to find the time taken by them if they work together,
So, the total hours taken by Sheila = 5 hours
So, she will do the work in 1 hour = 1/5 parts
Similarly, for David also, he will do in 1 hour = 1/4
Now, when they are working together in hour = 1/4 + 1/5
= 4+5 / 45 = 9/45 = 1/5
Since, there work in 1 hour = 1/5 units
That mean, they will do the whole work in 5 hours.
Hence, the time take by them to the job together is 5 hours.
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The cytoskeletal structure(s) that are composed of actin and regulate cell shape, cell movement, and muscle contraction include
The cytoskeletal structure composed of actin and involved in regulating cell shape, cell movement, and muscle contraction is called the actin cytoskeleton.
The actin cytoskeleton is a fundamental component of the cytoskeleton, a network of protein filaments within cells that provides structural support and plays essential roles in cellular processes. Actin filaments, also known as microfilaments, are polymers of actin protein subunits and form the main component of the actin cytoskeleton.
The actin cytoskeleton is involved in various cellular functions. It plays a crucial role in determining cell shape by providing structural support and contributing to the maintenance of cell integrity. Actin filaments are also responsible for generating the forces required for cell movement, including crawling, amoeboid movement, and migration of cells during processes such as wound healing.
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