Suppose the Sun suddenly shrinks in size, but the mass remains the same. According to the law of conservation of angular momentum, what would happen? Group of answer choices The Sun would rotate slower than it does now The rotation of the Sun will stay the same The force of gravity between the Sun and the planets will decrease The Sun would rotate faster than it does now The Sun's angular size in the sky will stay the same

During the winter solstice in the northern hemisphere, the subsolar point is located directly over the Tropic of Capricorn.

This means that the sun is directly overhead at the Tropic of Capricorn, which is located at 23.5 degrees south latitude. This is the point at which the sun is at its lowest point in the sky for those in the northern hemisphere, and it marks the beginning of the winter season. The winter solstice typically occurs on December 21 or 22 in the northern hemisphere.

In conclusion, it is stated that during the winter solstice in the northern hemisphere, the subsolar point is located at the Tropic of Capricorn.

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Answer:

The acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².

Explanation:

Given

To determine

Acceleration a = ?

Important Tip:

Using the formula

\(F = ma\)

where

now substituting F = 4000, m = 1240 in the formula

\(F = ma\)

\(4000\:=\:1240\:\times a\)

Switch sides

\(1240a=4000\)

Divide both sides by 1240

\(\frac{1240a}{1240}=\frac{4000}{1240}\)

Simplify

\(a=\frac{100}{31}\)

\(a=3.2\) m/s²

Therefore, the acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².

Newton's second law is the hardest to describe as it is about momentum  (F = ma), and a lot of people don't know the concept of momentum.

Newton's first law of motion:- every object moves in a straight line unless acted upon by a force.

Newton's 2nd law of motion:-the acceleration of an object is directly proportional to the net force exerted and inversely proportional to the item's mass. Newton's 2nd law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Newton's 3rd law of motion:- For every action, there's an equal and opposite reaction.

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The bungee jumper's acceleration is zero when she achieves her top speed. This is due to the fact that acceleration is the rate at which velocity changes, and since velocity is constant at maximum speed, there is neither change nor acceleration.

This is evident because when the bungee cord is completely stretched, the upward force is at its strongest. Within 2.4 seconds, or in the midst of the second free-fall phase, the jumper arrived at the highest position. Around -9.8 m/s2 of downward acceleration is present.

The elastic force from the bungee cord pushing up against the jumper as it expands slows his descent and temporarily stops him.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{500}{65} = 7.692307... \\ \)

We have the final answer as

Hope this helps you

The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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The speed in miles per hour is approximately 288.6 mph, and the speed in feet per second is approximately 678.2 ft/s.

To convert the speed from kilometers per hour to miles per hour, you can use the conversion factor of 0.6214 miles per kilometer. Multiplying the given speed of 464.5 km/hr by this conversion factor gives approximately 288.6 mph.

To convert the speed from kilometers per hour to feet per second, you need to go through two conversion steps.

First, convert kilometers per hour to meters per second by dividing by 3.6 (since there are 3.6 seconds in an hour).

Then, convert meters per second to feet per second by multiplying by 3.281 (since there are 3.281 feet in a meter).

By applying these conversion factors, the speed of 464.5 km/hr is approximately 678.2 ft/s.

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Answer:

The correct answer is the second option

Explanation:

The formula in question (for gravitational force) is provided below

F = G.m₁.m₂/r²

Where

F = force of gravity

G = gravity constant (6.674 × 10⁻¹¹ m.kg⁻¹.s⁻²)

m₁ and m₂ = are the masses of the objects

r² = distance between the centers of the two objects

From the above, it can be deduced that m₁ and m₂ are masses and hence can only be positive. Positives multiplied together only gives positive, thus the second option is correct.

Answer:

2. inference

Explanation:

if i get it right can i get branlist

Answer:D

Explanation:

i’m not sure if that’s right but that’s what i think

Answer: 10 blocks north

Explanation:

Answer:

4 blocks south

Explanation:

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The maximum height of an object thrown or shot vertically into the air is reached after t seconds, where t is the k-coordinate of the vertex of the parabola.

When an object is thrown or shot vertically, its motion can be modeled by a parabolic function.

The vertex of this parabola represents the highest point the object will reach, and the k-coordinate of the vertex represents the time it takes for the object to reach that height.

Hence, The maximum height of a vertically thrown or shot object is attained at the k-coordinate of the vertex of the parabola, which corresponds to the time t in seconds.

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These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.

Answer:

The time you enjoy wasting, is not wasted time

Explanation:

It's not a wasting time.

Answer:

40 kg

Explanation:

F = ma

F / a = m

2400 / 60  = 40 kg

When you park and your vehicle is facing uphill and there is no curb, your wheels should be turned so that they point towards the side of the road .

The use of physical precautions (eg bollards and barriers) is recommended to prevent vehicles crossing into walking areas, while “drive-through” parking is advised to reduce the need for reversing, combined with a one-way traffic flow system are called car parking safety rules .

If your vehicle rolls backward since , it is on a hill and it can roll back ,  you don’t want it rolling into Traffic. So you would turn your wheels towards the road so if the car rolls back it will go onto the ditch, or onto someone’s lawn and not into moving traffic.

If it ended up getting into the traffic it will be more dangerous for your car as well as for the other cars as it will increase the possibility of accident and cars can get damaged and you also will probably be held liable for the damage to the other car as well, so it is better if it rolls off of the roadway .

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Answer:

Wavelength = 1 meters

Explanation:

Given that,

Number of oscillations is 5

It passes through a point in 0.5 s

The speed of sound was recorded to be 10 m/s.

We need to find the wavelength of the sound.

Firstly, we will find frequency of this wave. Total no of oscillations per unit time is called frequency. So,

\(f=\dfrac{5}{0.5}\\\\f=10\ Hz\)

Now the speed of wave in terms of wavelength and frequency is given by :

\(v=f\lambda\)

Here, \(\lambda\) = wavelength

\(\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{10\ m/s}{10\ Hz}\\\\\lambda=1\ m\)

So, the wavelength of the sound is 1 meters.

The largest possible distance between speaker B and the observer at C is 1.37 m.

The largest possible distance between speaker B and the observer at C occurs when the difference in travel distances is just one half wavelength.

λ = v/f

λ = (343)/125

λ = 2.744

¹/₂λ = ¹/₂(2.744) = 1.37 m

Thus, the largest possible distance between speaker B and the observer at C is 1.37 m.

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Answer:

R and I will also change, but V will remain constant.

Explanation:

The reaction force to the Earth pulling down on a car parked on a flat driveway is the normal force exerted by the driveway on the car, which is equal in magnitude and opposite in direction to the weight of the car.

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. In the case of a car parked on a flat driveway, the force exerted by the Earth on the car is the weight of the car, which acts downward. According to Newton's third law, there must be an equal and opposite reaction force.

The reaction force to the Earth pulling down on the car is the force exerted by the car on the Earth. This force is commonly referred to as the normal force. The normal force is a contact force exerted by a surface to support the weight of an object resting on it and acts perpendicular to the surface.

In the case of a car parked on a flat driveway, the normal force exerted by the driveway on the car is equal in magnitude and opposite in direction to the weight of the car. This normal force counteracts the gravitational force pulling the car downward and prevents it from sinking into the ground. It ensures that the car remains in equilibrium and does not accelerate vertically.

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If a wave having a wavelength of 4.0 meters and an amplitude of 2.5 meters travels a distance of 24 meters in 8.0 seconds, the frequency of the wave would be 0.75 Hz.

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

As given in the problem a wave having a wavelength of 4.0 meters and an amplitude of 2.5 meters travels a distance of 24 meters in 8.0 seconds.

The number of waves in 24 meters = 24 / 4

                                                          = 6 waves

The number of waves that travels in 8 seconds = 6

The number of waves that travel in 1 second = 6 / 8

                                                                      = 0.75

Thus, the frequency of the wave would be 0.75 Hz.

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Considering the coordinates of the radars as well as the direction of the object in order to determine the object's position in terms of distance and angle. Sincе thе radars arе situatеd at (0,0) and thе sеcond radar is on thе еast sidе of thе first onе, wе can assumе that thе first radar is locatеd on thе x-pivot and thе sеcond radar is locatеd on thе positivе y-hub.

Lеt's say thе objеct is dеtеctеd at coordinatеs (x, y). The objесt's y-coordinativity will be negative and its x-coordinativity positive as it approaches the southern direction in the first quadrant.

We can use the distancе formula to determine the object's diameter from its origin (0, 0):

Distancée = (x + y) 2 The angle can be calculated with trigonometry. The angle can be summarized as:

= arctan(y/x) ii) We must consider the circles of overlap for each radar in order to calculate the overlap from the radar signal intersection in the first quadrant.

Due to the fact that both radars have distinctive overlap and divide the covered area into circles, the overlapped area will be the intersection of these circles.

Thе ovеrlapping arеa can bе calculatеd by finding thе arеa of thе intеrsеction of two circlеs. The formula for the area of the intersection of two circles can be complex and depends on the specific radii and dimensions that exist between the circles' centers.

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The event horizon of a black hole is the point of no return where the gravitational pull is so strong that not even light can escape. It is a boundary surrounding the black hole where the escape velocity exceeds the speed of light. At the event horizon, time and space are so distorted that the laws of physics as we know them cease to exist.

The exact nature of what lies beyond the event horizon is still a mystery as nothing can be observed beyond it. However, it is believed that all matter and energy that falls into the black hole accumulates at its center, known as the singularity.

The singularity is a point of infinite density and zero volume where the laws of physics break down completely, making it one of the most fascinating and mysterious entities in the universe.

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(a) The power required for the car to climb the hill at a steady speed is 15.56 kW.

(b) The power required for the car to climb the hill at a changing speed is  19.44 kW.

The power required for the car the move the incline is calculated as follows;

When the speed is steady, the average speed is calculated as;

v = ( 80km/h + 80 km/h) / 2 = 80 km/h = 22.22 m/s

P = Fv

where;

P = ( 700 N x 22.22 m/s )

P = 15,555.56 W = 15.56 kW

When the speed changes from 90 km/h to 110 km/h, the average speed is calculated as;

v = ( 90 km/h + 110 km/h ) / 2 = 100 km/h = 27.78 m/s

P = ( 700 N x 27,78 m/s )

P = 19,444.44 W = 19.44 kW

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Answer:

a. ω = 628.3 rad/s

b. v = 1256.6 m/s

Explanation:

a. La velocidad angular (ω) se puede calcular de la cantidad de vueltas que da el aspar por unidad de tiempo:

\( \omega = 1 \frac{vuelta}{0.01 s} \cdot \frac{2\pi rad}{1 vuelta} \)

\( \omega = 628.3 \frac{rad}{s} \)

b. La velocidad lineal (v) se calcula usando la siguiente ecuación:

\( v = \omega*r \)

En donde:

r: es el radio = 2 m

\( v = 628.3 rad/s*2 m = 1256.6 m/s \)

Espero que te sea de utilidad!        

1. The x component of the force is 4.4 N

2. The y component of the force is 3.5 N

The following data were obtained from the question:

1. How to determine the x component

x component = FCosθ

x component = 5.6 × Cos 39

x component = 4.4 N

2. How to determine the y component

y component = FSineθ

y component = 5.6 × Sine 39

y component = 3.5 N

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The development involves creating a shielding barrier to minimize external electro magnetic resonance interference with the extremity MRI system.

The improvement of a nearby electromagnetic safeguarding for a limit attractive reverberation imaging (X-ray) framework includes making a defensive hindrance to limit the obstruction of outside electromagnetic fields with the X-ray framework.

The objective is to safeguard the limit being imaged from outer electromagnetic sources that can contort the X-ray signals and influence picture quality. The protecting material utilized ought to have high penetrability and conductivity to divert or retain outside electromagnetic waves actually.

The advancement cycle ordinarily includes cautious plan and situation of the protecting material around the furthest point X-ray framework. The safeguarding might comprise of particular combinations, like mu-metal, or conductive foils, which make a Faraday confine like nook around the furthest point being imaged.

The adequacy of the protecting is tried by estimating the decrease in electromagnetic impedance and assessing the nature of X-ray pictures got with and without the safeguarding set up. Iterative changes and upgrades might be made to streamline the safeguarding execution.

The improvement of a nearby electromagnetic protecting for a limit X-ray framework assumes a urgent part in working on the precision and unwavering quality of furthest point imaging by limiting outer electromagnetic obstruction.

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The complete question is:

What are the key considerations and steps involved in the development of a local electromagnetic shielding for an extremity magnetic resonance imaging (MRI) system?

A subpanel in an older house that is wired with non-metallic sheathed cable (nm) has one circuit with a grounding wire. the grounding wire should be connected to a separate grounded buss bar.

Brass, Aluminum or Copper Bus bars are metal strips or rods. They come in a variety of shapes and sizes that determine the maximum current (ampacity) they can carry safely and reliably. This also means that it is important to install the best one for a particular application.

Its job is to receive power from the delivery point and distribute it to the output circuits. However, unlike cables, no insulation is usually required. Busbars are often arranged in separate housings. Bus bars are used as nodes or nodes in power distribution applications and can be housed in switchgear or control cabinets and bus bar enclosures.

The grounding bar is used in environments where a common grounding point or grounding point is required or required in the distribution network. One of the main advantages of brass, aluminum, or copper grounding bars is that they can be placed anywhere on the chassis or rack.

This makes installation faster and more efficient than cables. A grounded (or neutral) bus reduces the need for regular maintenance and reduces the risk of downtime. This is very important in industries where uninterrupted power distribution is essential. Telecom and power supplies are two prominent examples.

However, it is not uncommon for some neutral bus bars to have insulation.

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Answer:

false

Explanation:

sana po maktulong

The term that increases when air faces greater resistance against an object with a larger surface area is drag.

The drag force is created when a solid object moves through a fluid (liquid or gas), such as air, and experiences resistance to its motion.Drag can be affected by various factors, including the object's shape and surface area. In general, objects with larger surface areas will experience more drag than those with smaller surface areas because they create more friction with the surrounding fluid. For example, a flat, wide object like a barn door will experience more drag than a narrow object like a pencil because it has a larger surface area. Similarly, a parachute will experience a large amount of drag because of its large surface area, which creates a significant amount of friction with the air molecules around it.In order to minimize drag and increase efficiency, engineers and designers often try to create streamlined objects with minimal surface area. This can be seen in the design of cars, airplanes, and even swimsuits used by competitive swimmers. By minimizing drag, these objects are able to move more quickly and with less effort through their respective fluids.

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