How long indicates your looking for what?
O distance
O speed
time
We are looking for Distance. Distance in physics is understood as the speed of an object multiplied by the total time taken by the object to travel the length of its path.
What is Distance?The units for each variable must be consistent with one another in order to accurately calculate the distance. For instance, if the distance is being calculated in terms of meters, the speed should be recorded in meters per unit of time.
Without taking into account direction, distance measures the length between two points or objects. Distance is a scalar property, which means it simply considers the overall magnitude and does not take start or endpoints into account.
The meter (m) is the commonly used unit of measurement for distance, but greater distances can also be expressed in kilometers (km), and smaller distances can be expressed in centimeters (cm) or millimeters (mm).
Therefore, We are looking for Distance. Distance in physics is understood as the speed of an object multiplied by the total time taken by the object to travel the length of its path.
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What part of the phospholipid bilayer “hates” water?
Answer:
Phospholipids are able to form cell membranes because the phosphate group head is hydrophilic (water-loving) while the fatty acid tails are hydrophobic (water-hating)
Answer:
Explanation:
the fatty acid tails are hydrophobic
they hates water
4. What would be the maximum speed, if the haul road were properly maintained with a rolling resistance of 50 pounds per ton
The maximum speed would depend on various factors and cannot be determined solely based on the rolling resistance of 50 pounds per ton.
The maximum speed of a vehicle is influenced by multiple factors, including but not limited to the rolling resistance. While the rolling resistance can affect the efficiency of the vehicle's motion, it is not the sole determinant of the maximum speed.
To calculate the maximum speed, additional factors such as the power output of the vehicle's engine, aerodynamic drag, road conditions, and other resistive forces need to be considered. These factors interact with each other, and their combined effect determines the vehicle's maximum achievable speed.
Rolling resistance is the force required to overcome the friction between the tires and the road surface. A rolling resistance of 50 pounds per ton implies that for every ton (2000 pounds) of weight, 50 pounds of force is needed to overcome the rolling resistance.
However, without information about the vehicle's weight, engine power, aerodynamic characteristics, and other relevant factors, it is not possible to calculate the maximum speed accurately.
The maximum speed of a vehicle cannot be determined solely based on the rolling resistance of 50 pounds per ton. Multiple factors, including the vehicle's weight, engine power, aerodynamic drag, and road conditions, play significant roles in determining the maximum speed. To accurately calculate the maximum speed, all relevant factors need to be considered in conjunction with the rolling resistance.
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Relación de conceptos e ideas:
1. Mantiene la integridad de los átomos, de las moléculas y de todos los cuerpos con los que nos relacionamos.
2. Científico cuyo nombre reciben las ecuaciones fundamentales del electromagnetismo.
4. Científico a quien se debe la idea de líneas de campo.
5. Científico que se considera el descubridor del electrón.
6. Científico a quien se debe la ley de la fuerza entre dos partículas cargadas en reposo.
7. Partículas responsables de que haya dos tipos de electricidad.
8. Nombre que recibe la cantidad mínima de carga eléctrica.
9. Instrumento utilizado por Coulomb para establecer la ley que lleva su nombre.
10. Ente que rodea a todo cuerpo cargado eléctricamente y que actúa sobre otros cuerpos con carga.
11. Nombre de la magnitud utilizada para caracterizar el campo eléctrico.
12. Líneas en el espacio que rodea a un cuerpo cargado, empleadas para caracterizar su campo eléctrico.
13. Energía de un sistema de cuerpos electrizados debida a la interacción eléctrica entre ellos.
14. Variación de la energía potencial por unidad de carga que tiene lugar cuando una partícula cargada se desplaza entre dos puntos de un campo eléctrico.
15. Nombre que comúnmente reciben en Física los aisladores.
16. Materiales en que los centros de carga positiva y negativa de sus moléculas no coinciden.
17. Materiales en que los centros de carga positiva y negativa de sus átomos o moléculas coinciden.
18. Cociente entre la magnitud del campo en el que se coloca un material y la magnitud del campo que resulta en su interior.
19. Dispositivo que puede ser empleado para acumular carga eléctrica y energía.
20. Magnitud que indica la carga eléctrica por voltio que puede almacenar un condensador.
21. Energía por unidad de volumen del campo eléctrico.
Respuestas
( ) Balanza de torsión
( ) Campo eléctrico
( ) Carga eléctrica elemental
( ) Charles A. Coulomb
( ) Circuito eléctrico
( ) Condensador
( ) Constante dieléctrica
( ) Densidad de energía
( ) Dieléctricos
( ) Dieléctricos no polares
( ) Dieléctricos polares
( ) Diferencia de potencial
( ) Electrones y protones
( ) Energía potencial eléctrica
( ) Intensidad de campo eléctrico
( ) Interacción electromagnética
( ) James C. Maxwell
( ) Joseph J. Thomson
( ) Líneas de campo eléctrico
( ) Michael Faraday
The terms for the statements given are, 1. Conservation of Matter, 2. James Clerk Maxwell, 3. Michael Faraday, 4. J.J. Thomson, 5. Charles-Augustin de Coulomb, 6. Electrons and protons, 7. Elementary charge, 8. Torsion balance, 9. Electric field, 10. Electric field strength, 11. Electric field lines, 12. Electrical potential energy, 13. Electric potential difference, 14. Dielectrics, 15. Polar materials, 16. Nonpolar materials, 17. Dielectric constant, 18. Capacitor, 19. Capacitance, 20.Electric energy density.
Fundamental forces, including electromagnetism, maintain atoms and bodies we interact with. Maxwell's equations unified electricity and magnetism. Faraday introduced field lines to visualize electric and magnetic fields. Thomson discovered electrons, while Coulomb established the law of force between charged particles. Protons and electrons create positive and negative electricity, and an elementary charge is the smallest charge carried by a single particle.
The electric field surrounds charged bodies and has a strength measured in volts per meter. Insulators prevent electrical flow and are useful in electronics. Polar and nonpolar materials have different arrangements of positive and negative charges. The dielectric constant measures the ratio of field magnitudes in and out of a material. Capacitors store electric charge and energy and have capacitance measured in farads. Electric energy density measures the energy per unit volume of the electric field.
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simple machines are in a mousetrap
Answer:
A mousetrap makes use of a simple machine called a lever.
Explanation:
In a second-class lever the effort force is at the other end, with the load in the middle. In a third-class lever, the load is at the end and the effort force is between the fulcrum and the load. When you set the mousetrap, you are using a second-class lever. Sorry if I get this wrong. I am in 5th grade! ♥
An eagle is flying above a mountain of height 2,700 m above sea level. Calculate the pressure on the eagle if the average density of air is 1.3 kg/m3,the atmospheric pressure at sea level is 76 cm Hg, and the density of mercury is 13,600 kg/m3.
Answer:
The correct option is;
(A) 25.8 cmHg
Explanation:
The given parameters are;
The height of the mountain over which the eagle is flying = 2700 m
The average density of air, ρₐ = 1.3 kg/m³
The atmospheric pressure at sea level = 76 cmHg = 0.76 mHg
The density of mercury, \(\rho _m\) = 13,600 kg/m³
The formula for pressure, p, is p = ρ·g·h
The pressure in the atmosphere = 13,600 × 0.76 × g = 10,336·g
The equivalent height of air is found as follows;
1.3 × g × h = 10,336·g
h = 10,336/1.3 = 7,950.769 meters
Therefore;
The pressure of the atmosphere at 2,700 meters, p₂₇₀₀ = (2,700/7,950.769) × 76 cm Hg
Which gives;
p₂₇₀₀ = 25.808 cmHg ≈ 25.8 cmHg.
Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of the coast and reflection of incoming waves.
Answer:
Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of the coast and reflection of incoming waves.
Explanation:
Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of the coast and reflection of incoming waves.
3. If I run 150m in 30 seconds, what speed will I have been running at?
Answer:
speed = distance/time
Explanation:
speed = 150/30
speed =5m/s
you were running fast .....5m/s is a good speed
Which of the following is not a benefit of stressing
a. Poor circulation
b. Increase speed and power
c.Increased flexibility
d. Minimized change injuries
Poor circulation is not a benefit of stretching.
How many minutes of stretching should a person perform before participating in physical activities?
Stretching for 5 to 10 minutes is probably enough for most activities. It's important, however, to adequately stretch all the muscles you'll be using. Three benefits of stretching before a workout include increased blood flow.
What are the 5 benefits of stretching?
Improve your performance in physical activities.Decrease your risk of injuries.Help your joints move through their full range of motion.Increase muscle blood flow.Enable your muscles to work most effectively.Improve your ability to do daily activities.Which benefit comes with flexibility?
Activities that lengthen and stretch muscles can help you prevent injuries, back pain, and balance problems. A well-stretched muscle more easily achieves its full range of motion.
Thus, poor circulation is the correct option.
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Gasses and plasma are called bank because their shape is always changing
Answer:
It is because gasses, liquids, and plasma are always changing shape they are named and classified as ‘fluid’.
a cylinder with cross-section area a floats with its long axis vertical in a liquid of density rho.
Part A
Pressing down on the cylinder pushes it deeper into the liquid. Find an expression for the force needed to push the cylinder distance z deeper into the liquid and hold it there.
Part B
A 5.0-cm-diameter cylinder floats in water. How much work must be done to push the cylinder 17 cm deeper into the water?
Answer:
a x = volume of liquid displaced moving cylinder distance x into liquid
F = a x ρ weight liquid displaced where ρ is density of liquid
F = a z ρ force required to push cylinder into liquid
A) F = a z ρ force required to push cylinder into liquid
B) W = F * z = a z^2 ρ work required to move distance z
W = (π * .025^2 m^2 * (.17 m)^2 * 9,800 N / m^3 = .56 N-m
(Note density of water = 1000 kg/m^3 = 9800 N/m^3) weight density
1. A 1000 kg bag of sand has an
acceleration of 0.5m/s/s. What is the
force on the bag?
Answer:
We conclude that the force on the bag is 500 N.
Explanation:
Given
Mass m = 1000 kgAcceleration a = 0.5 m/s²To determine
Force F = ?
We know that when a force is applied to a body, it produces acceleration.
Important Tip:
We can determine the force on the bag using the formula F = maUsing the formula
\(F = ma\)
where
\(F\) is the force \(m\) is the mass\(a\) is the accelerationnow substitute m = 1000, and a = 0.5 m/s² in the formula
\(F = ma\)
\(F = (1000)(0.5)\)
\(F=500\) N
Therefore, we conclude that the force on the bag is 500 N.
Bobo the clown carries two red balloons that rub against a circus elephant, causing thr baloons to seperate. Each balloon aquires 1.2x10^-7 of charge. How large is the electric orce between them when the balloons are seperated by a distance of 0.5m
The electric force between the two balloons is approximately 1.04 x \(10^{-12}\) N.
Coulomb's Law:
The electric force between two charged objects can be calculated using Coulomb's Law, which states that the magnitude of the electric force F between two charged objects is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:
F = k * (q1 * q2) / r²
where k is the Coulomb constant, which has a value of approximately 9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\).
In this case, each balloon acquires a charge of 1.2 x \(10^{-7}\) C, so the total charge on both balloons is 2 * 1.2 x \(10^{-7}\)C = 2.4 x \(10^{-7}\)C. The distance between the balloons is 0.5 m.
Plugging in these values into Coulomb's Law, we get:
F = (9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\)) * [(1.2)²x (\(10^{-7}\) C)²/ (0.5m)²]
Simplifying this expression gives:
F = 1.0368 x \(10^{-12}\) N
Therefore, the electric force between the two balloons is approximately 1.04 x\(10^{-12}\) N.
What is magnitude?
Magnitude refers to the size or extent of something, usually measured in numerical or quantitative terms. It can refer to a physical quantity, such as length, mass, or volume, or it can refer to other measurable attributes, such as brightness, intensity, or force. In general, magnitude is a relative measure, meaning that it is typically expressed as a comparison between two or more things.
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Predict how the force between the sheets would be different if this experiment were done with twice as much charge on each of the plates. Justify your prediction.
A 0.045-kg golf ball is dropped from rest. Is dropped from a height of 1.3m and comes back up at a height of .7m
The time to drop from 1.3m and velocity after height at 0.7 mis mathematically given as
t1 = 0.515 sec
v0 = 3.7m/s
What is the time to drop from 1.3m and velocity after height at 0.7?Question Parameters:
A 0.045-kg golf ball is dropped from rest.
Is dropped from a height of 1.3m and comes back up at a height of .7m
Generally, the equation for the time to drop from 1.3m is mathematically given as
yf - yi = vi t + a t^2/ 2
Therefore
0 - 1.3 = 0 - 9.8 t^2 /2
t1 = 0.515 sec
Hence, after its max height is 0.7 m,
vf^2 - vi^2 = 2 a (yf - yi)
0^2 - (v0)^2 = 2(-9.8)(0.7 - 0)
v0 = 3.7m/s
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What are the latitude and longitude coordinates for Location C? 1) 50N, 68S 2) 50N, 68W 3) 50S, 68E 4) 50S, 68W Which is farther- the distance between Location B and the Equator or the distance between Location C and the Equator? 1) Location B and the Equator 2) Location C and the Equator 3) Locations B and C are the same distance from the Equator 4) Cannot discern from the information provided
The latitude and longitude coordinates for Location C are given as 50S, 68W. Therefore, the correct answer is 4) Cannot discern from the information provided.
Latitude and longitudinal lines are shown on a globe of Earth as parallel and vertical lines. To determine which distance is farther, we need to compare the distance between Location B and the Equator with the distance between Location C and the Equator.
However, the latitude and longitude coordinates for Location B and the specific direction or coordinates of the Equator are not provided. Without this information, it is not possible to determine which distance is farther between Location B and the Equator or Location C and the Equator.
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a 18.0-kg child descends a slide 2.20 m high and reaches the bottom with a speed of 1.50 m/s .how much thermal energy due to friction was generated in this process?
The heat generated due to the friction in the given process is 367.83 J.
Frictional heat generates when two surfaces slide against each other. The heat generated due to the friction in the given process is 6.92.7 J.
Frictional heat:
This heat is generated when two surfaces slide against each other.
Potential energy :-
U= m g h;
Put the values
U= 18.0-kg* 9.8 m/s^2 *2.20 m
U=388.08 J
The Kinetic energy in the bottom:
K = 1/2 * m * v^2
= 1/2 * 18.0* 1.50^2
K= 20.25 J
So the friction heat,
Hf = U - K
Hf = 388.08 J -20.25 J
Therefore, the heat generated due to the friction in the given process is 367.83 J.
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dựa vào tính chất ảnh của vật tạo bởi gương phẳng hãy vẽ ảnh của vật sáng AB có dạng mũi tên được đặt theo vị trí tạo với GB một góc 60 độ
Explanation:
good luck with the one that was on the one that has to be done
Consider this conversion factor, 1.91 Royal Egyptian Cubit = 1.00 meter. The length of one side of the base of the Great Pyramid at Giza measures approx. 2.30 x 10^2. meters. What is the length in Royal Cubits?
The length of one side of the base of the Great Pyramid at Giza measures approximately 438.7 Royal Egyptian Cubits.
To convert the length of the base of the Great Pyramid from meters to Royal Cubits, we can use the given conversion factor:
1.91 Royal Egyptian Cubit = 1.00 meter
First, let's set up a proportion:
1.91 Royal Egyptian Cubit / 1.00 meter = x Royal Egyptian Cubit / 2.30 x 10^2 meters
Cross-multiplying and solving for x, we get:
x = (1.91 Royal Egyptian Cubit / 1.00 meter) * (2.30 x 10^2 meters)
x ≈ 438.7 Royal Egyptian Cubit
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What is the origin of all stars?
supernova
dwarfs
protostars
nebulae
Answer:
Protostars
Explanation:
ONLY ANSWER IF YOU KNOW FOR SURE PLEASE :)
answer all three please, it should not take long
Answer:
Question one is b, Question two is b, and question three is b, im pretty positive that what it is
One U.S. fluid gallon contains a volume of 231 cubic inches. How many liters of gasoline would you have to buy in Canada to fill a 14-gallon tank? (Note: 1L = 10 +3 cm 3.)
Since we have a 14 gallon tank this means that in total we need:
\(14\cdot231=3234\)cubic inches.
Now, we know that one inche is equal to 2.54 cm then we have that:
\(3234in^3\cdot\frac{2.54\text{ cm}}{1\text{ in}}\cdot\frac{2.54\text{ cm}}{1\text{ in}}\cdot\frac{2.54\text{ cm}}{1\text{ in}}=54995.76cm^3\)finally, and since a liter is equal to 1000 cubic centimeters we have that:
\(54995.76cm^3\cdot\frac{1\text{ L}}{1000cm^3}=54.99576\)Therefore we need 54.99576 liters of gasoline (this is approximately 55 liters)
Calculate the momentum of a 78 kg cheetah running at 24 m/s.
Answer:
1872 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 78 × 24
We have the final answer as
1872 kg.m/sHope this helps you
Block B (of mass m) is initially at rest. Block A (of mass 3m) travels toward B with an initial speed v0 (vee nought) and collides in an inelastic collision. Given that all surfaces have negligible friction, determine the maximum height h reached by the
two blocks.
Answer:
The maximum height reached by the two blocks is approximately 0.1147959 × v₀²
Explanation:
The mass of block B = m
The mass of block A = 3·m
The initial velocity of block B, v₂ = 0 m/s
The initial velocity of block A, v₁ = v₀
The amount of friction between the blocks and the surface = Negligible friction
By the Law of conservation of linear momentum, we have;
Total initial momentum = Total final momentum
3·m·v₁ + m·v₂ = (3·m + m)·v₃ = 4·m·v₃
Plugging in the values for the velocities gives;
3·m × v₀ + m × 0 = (3·m + m)·v₃ = 4·m·v₃
∴ 3·m × v₀ = 4·m·v₃
\(\therefore v_3 = \dfrac{3}{4} \times v_0 = 0.75 \times v_0\)
The kinetic energy, K.E. of the combined blocks after the collision is given as follows;
K.E. = 1/2 × mass × v²
\(\therefore K.E. = \dfrac{1}{2} \times 4\cdot m \times \left (\dfrac{3}{4} \cdot v_0 \right )^2 = \dfrac{9}{8} \cdot m\cdot v_0^2\)
The potential energy, P.E., gained by the two blocks at maximum height = The kinetic energy, K.E., of the two blocks before moving vertically upwards
The potential energy, P.E. = m·g·h
Where;
m = The mass of the object at the given height
g = The acceleration due to gravity
h = The height at which the object of mass, 'm', is located
Therefore, for h = The maximum height reached by the two blocks, we have;
P.E. = K.E.
\(m \cdot g \cdot h = \dfrac{9}{8} \cdot m\cdot v_0^2\)
\(h = \dfrac{\dfrac{9}{8} \cdot m\cdot v_0^2}{m \cdot g } = \dfrac{9}{8} \cdot \dfrac{ v_0^2}{ g } = \dfrac{9}{8} \cdot \dfrac{ v_0^2}{ 9.8} = \dfrac{42}{392} \cdot v_0^2 \approx 0.1147959 \cdot v_0^2\)
The maximum height reached by the two blocks, h ≈ 0.1147959·v₀².
The last thing I mention in the notes is that the Moon is slowing down the rotation of the earth hence after a few billion years the Moon and Earth will be tidal locked together in a synchronous orbit. When that happens what do you thing will happen to the visibility of the Moon in Earth's sky?
The same side of the Moon will always be facing the Earth when the Earth and Moon are tidally locked in a synchronous orbit, which implies that the Moon's rotation will be synchronized with its orbit around the Earth.
The Moon's appearance in the Earth's sky would change as a result. There wouldn't be any moon phases like there are now. Instead, only one side of the Moon would be permanently facing us and visible from Earth, with the other half remaining hidden. The viewable side would stay unchanged over time, giving Earth a static and unchanging picture of the Moon.
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Model B was accepted as the structure of the Universe for over 1,000 years. However, it had a major flaw that couldn't be explained. What was that flaw?
Model B is the Heliocentric Theory which cannot explain retrograde.
Model B is the Geocentric Theory which cannot explain retrograde.
Model B is the Heliocentric Theory which cannot explain the Law of Universal Gravitation.
Model B is the Geocentric Theory which cannot explain the Law of Universal Gravitation.
The Geocentric Theory, which cannot explain backward, is Model B.
Why didn't the heliocentric paradigm gain traction?Because its proponents were unable to explain why the relative positions of the stars appeared to stay the same despite the Earth's changing perspectives as it rotated around the Sun, The solar system's heliocentric, or Sun-centered, model was never generally accepted.
Why is the heliocentric paradigm more popular than the geocentric model?Instead of Earth, as was previously thought to be the case according to the geocentric model, the heliocentric model puts the Sun at the core of the solar system. Our greater knowledge of astronomy was built on this advancement, which brought us closer to the true nature of the solar system and the universe.
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A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(unit = m)
The wavelength of a wave with an amplitude of 0.0800m, moving at 7.33 m/s, and a time period of 0.230 s is 1.6849 m.
A wave with an amplitude of 0.0800m is moving at 7.33 m/s. One oscillator in the wave takes 0.230 s to move from one crest to the next. Given data; Amplitude = A = 0.0800 m, Velocity = v = 7.33 m/s, Time = t = 0.230 sThe formula for calculating the wavelength is Wavelength (λ) = Velocity / Frequency. The formula for calculating frequency is: Frequency = 1 / Time PeriodThe time period of one oscillation in the wave is calculated using the given data; Frequency = 1 / Time Period, Time period (T) = Time / Number of oscillationsTime period (T) = 0.230 / 1 = 0.230 sSubstituting frequency in the wavelength formula; λ = v / f, Where f = 1 / Tλ = v / (1 / T) = v * Tλ = 7.33 * 0.230λ = 1.6849 m. Therefore, the wavelength of the wave is 1.6849 m.In summary, a wave with an amplitude of 0.0800m is moving at 7.33 m/s. One oscillator in the wave takes 0.230 s to move from one crest to the next. The wavelength of the wave can be found by using the formula λ = v/f. Since the formula for frequency is f = 1/T, the time period (T) of one oscillation in the wave can be calculated using the given data. Then, substituting frequency in the wavelength formula, we get the value of wavelength. So, the wavelength of the wave is 1.6849 m.For more questions on wavelength
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URGENT! i don't understand how displacement works and it'd be nice if you could also show steps on how to do it:( THank you!
Calculate the total displacement of a mouse walking along a ruler, if it begins at the x=5cm, and then does the following:
It walks to x=12cm
It then walks a displacement of -8cm
Lastly, it walks to the location x=7cm
Question 1 options:
60 miles
1 mile
60 miles per hour
Trick question. You can't go 60 miles if an hour has 60 minutes
Answer:
Explanation:
You can drive at 60 miles per hour
D = 60 miles
t = 1 hour
Speed:
V = D / t = 60 / 1 = 60 mph
give any 2 evidence of the unsual expansion of water
Answer:
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense.
Explanation:
The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.