If the uncertainty in the position of an electron is equal to the radius of the n=1 Bohr orbit, about 0.529×10⁻¹⁰ m, a) The minimum uncertainty is 5.29×10⁻²⁴ kg m/s. b) The magnitude of the momentum of the electron in the n=1 Bohr orbit is 5.08×10⁻²⁴ kg m/s.
a) We can use the Heisenberg uncertainty principle to find the minimum uncertainty in the corresponding momentum component:
Δx Δp ≥ h/4π
Δp ≥ h/4πΔx
Δp ≥ (6.626×10⁻³⁴ J s) / (4π × 0.529×10⁻¹⁰ m)
Δp ≥ 5.29×10⁻²⁴ kg m/s
b) We can compare this with the magnitude of the momentum of the electron in the n=1 Bohr orbit, which is given by the formula p = mv, where m is the mass of the electron and v is its velocity.
For an electron in the n=1 Bohr orbit, the velocity is given as v = αc/n, where α is the fine-structure constant, c is the speed of light, and n is the principal quantum number.
For n=1, we have:
v = αc
p = mv = mαc
Substituting the values of m and α, we get:
p = (9.11×10⁻³¹ kg) (1/137) (2.998×10⁸ m/s)
p = 5.08×10⁻²⁴ kg m/s
Therefore, the magnitude of the momentum of the electron in the n=1 Bohr orbit is greater than the minimum uncertainty in the corresponding momentum component, as expected from the uncertainty principle.
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How are sound waves similar to light waves?
Answer:
Sound and light are similar in that both are forms of energy that travel in waves.
Explanation:
They both have properties of wavelength, freqency and amplitude. ... Sound can only travel through a medium (substance) while light can travel through empty space. Sound is a form of mechanical energy caused by vibrations of matter.
Answer:
When light moves from one medium (like air) to another medium (like water) it will change directions. This is a "wave-like" behavior and is called refraction. In this way light behaves like other waves such as sound waves. The speed of the light wave also changes when it moves from medium to medium.
Explanation:
Which object would sink in honey, which has a density of 1.4 g/cm³?
Object 1 (0.9 g/cm³)
Object 2 (1.2g /cm³)
Object 3 (0.2 g/cm³)
Object 4 (2.3 g/cm³)
Answer:
objective 4
Explanation:
i took the unit test review and the regular unit test
Object 4 with a density of 2.3 g/cm³ would sink in honey, which has a density of 1.4 g/cm³, therefore the correct option is option D.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
The mathematical formula for density is given below
ρ =m /v
where ρ is the density of the substance
m is the mass of the substance
v is the volume of the substance
As per the law of floatation, the objects those have less density than the honey do not sink in the honey which has a density of 1.4 g/cm³.
As per the given options, object 1 has a density of 0.9 g/cm³ which is less than the density of honey 1.4 g/cm³, therefore it would not sink in the honey. similarly, objects 2 and object, 3 have a density that is less than the density of the honey, therefore they would float instead of sinking in the honey.
The only object 4 has a density of 2.3 g/cm³ which is more than the density of honey, therefore it would sink on the honey.
Hence, the correct answer is object 4.
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Question 6 of 25For an object that is moving with zero acceleration, what does the speed vstime graph look like?O A. A horizontal line, not on the x-axis.OB. A graph curving downward.C. A horizontal line on the x-axis.O D. A graph curving upward.
A horizontal line, not on the x-axis.
A 100kg diver jumps off a 40m cliff. Ignoring the affects of air resistance, determine the
time it would take for the diver to reach the water.
Answer:2.86seconds
Explanation:
H=gt^2/2
t=2h/g
how is this possible
Answer: I'm sorry what's wrong with your money
Explanation:
Answer: LOL YO I HAVE 5K IN GROUP FUNDS
Explanation:
Describe the force exerted by a magnet
The force that a magnet exerts on certain materials, including other magnets, is called magnetic force.
Where is the magnetic force exerted?A force that is applied to an item by a person or another object is known as an applied force. A desk is being subjected to applied force if someone is moving it across the room. The person's force applied to the desk is known as the applied force.Magnetic force is the force that a magnet applies to specific materials, such as other magnets. The force, which consists of both attractive and repulsive forces, is applied over a distance. Two magnets' north and south poles are attracted to one another whereas two north poles or two south poles are repellent to one another.Learn more about Magnetic force refer to ;
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Metals are often used for making designer jewelry because they
A) conduct electricity
B) do not conduct heat well
C) are shiny
D) are strong but can be bent
E) c and d
Answer:
E
Explanation:
Metals (the ones used to make jewelry) are valuable, Resistant to corrosion, and retain their appearance well over long periods of time.
(Pls mark me brainliest)
Metals are often used for making designer jewelry because they have a combination of properties that make them suitable for this purpose. One important property is their ability to be shaped and bent without breaking, which makes them ideal for creating intricate designs.
This property is due to their strength and flexibility, which allows them to be manipulated into various shapes and forms. Additionally, metals are often shiny and can be polished to a high gloss, which adds to their aesthetic appeal. While some metals such as gold and silver are good conductors of electricity, their conductivity is not the primary reason for their use in jewelry making. Similarly, while metals do conduct heat, their thermal conductivity is not a major factor in their use for making jewelry. Therefore, option E, which includes both C and D, is the most appropriate answer.
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How far can a person run in 13.22 minutes if he or she runs at an average speed of 12.33 km/hr?
Answer:
2.72 km
Explanation:
(12.33 km)/ 1 hr * (1 hr)/ 60 min
0.2055 km/ min
distance=rate * time (assuming v is constant,
a=0)
(0.2055 km/ min)*(13.22 min)
2.72 km OR 2716.71 m
the osmotic pressure is 1.66 torr at 21 °c for a solution containing 7.50 mg of a protein dissolved in water to give 10.00 ml of solution. determine the molar mass of the protein.
The molar mass of the protein is M = 8304 gm/ mol. when the osmotic pressure is 1.66 torr at 21 °c for a solution containing 7.50 mg of a protein dissolved in water to give 10.00 ml of solution.
We know that osmotic pressure depends upon the concentration of solution and temperature by the relation
P = i CRT
Here p is osmotic pressure = 1.66 torr = .00218 atm
1atm = 760 torr
Here i is called as the vant hoff factor
C is concentration = mole / volume = w/ MV
V is volume = 10ml or .01Lt
W = weight of protein in mg = 7.5 mg = 7.5 × 10^-3 gm
T is temperature in kelvin = 273 + 21 => 294K
R is gas constant = 0.0821 Lt atm / mol / K
.00218 = 7.5 × 10^-3 × .0821 × 294 / M × .01
M = 8304 gm/ mol .
Here we have calculate molar mass of protein.
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Does the amount of water present in a calorimeter affect the change in temperature? how?.
Water has a high specific heat, that makes it is difficult to increase the temperature of water. However, it also has the capacity to retain heat, which allows the other substance inside the calorimeter to absorb that heat.
Calorimetry is one technique that we can use to measure the amount of heat involved in a chemical or physical process. It is used to measure amounts of heat transferred to or from a substance.
A calorimeter is a device that is used to measure the amount of heat involved in a chemical or physical process. Water is best to use in a calorimeter because it has a high specific heat, also, other liquids such as ethanol can also be used. However, for practical reasons such as water's ability to be easily measured as well as its affordability, it is known to be the best choice.
This means that we can still measure the temperature using a standard thermometer. If a substance reached excessive temperatures, then we would need to use an expensive thermometer to measure it.
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1. What is the final temperature of two cups of water being mix together? Cup 1 mass is 150
kg and has a temperature of 30 degrees Celsius; Cup 2 mass is 250 kg and has a temperature of
75 degrees Celsius. Specific heat for water (4186)
The final temperature of the two cups of water being mixed together, given that one cup has a temperature of 30 °C and the other has 75 °C, is 58.13 °C
How do i determine the final temperature of the two cups?To obtain the final temperature of the two cups of water, we must obtain the equilibrium temperature of the two cups of water mixture. Details below:
Mass of water in cup 1 (M) = 150 KgTemperature of water in cup 1 (T) = 30 °CMass of water in cup 2 (Mᵥᵥ) = 250 KgTemperature of water in cup 2 (Tᵥᵥ) = 75 °CSpecific heat capacity of the water = 4186 J/KgºC Equilibrium temperature (Tₑ) =?Heat loss by cup 2 = Heat gain by cup 1
MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)
250 × 4186 (75 - Tₑ) = 150 × 4186(Tₑ - 30)
1046500(75 - Tₑ) = 627900(Tₑ - 30)
Clear bracket
78487500 - 1046500Tₑ = 627900Tₑ - 18837000
Collect like terms
78487500 + 18837000 = 627900Tₑ + 1046500Tₑ
97324500 = 1674400Tₑ
Divide both side by 1674400
Tₑ = 97324500 / 1674400
Tₑ = 58.13 °C
From the above calculation, the equilibrium temperature is 58.13 °C.
Thus, we can conclude that the final temperature of the two cups of water is 58.13 °C
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A sledder starts from rest atop a 5.0-m high hill (A). She sleds to the bottom and up to the top of the adjacent 3.0-m high hill. How fast is the sledder going at point B? Ignore friction.
When, sledder starts from rest a top a 5.0-m high hill (A). She sleds to the bottom and up to top of the adjacent 3.0-m high hill. Then, the sledder is going at approximately 6.26 m/s at point B.
To determine the speed of the sledder at point B, we can use the principle of conservation of energy. The sledder starts with potential energy at the top of the first hill and converts it into kinetic energy at the bottom of the second hill.
At the top of the first hill (point A), the sledder has only potential energy, given by:
Potential energy at point A = mass × gravity × height_A
At the bottom of the second hill (point B), the sledder has both potential and kinetic energy. The total mechanical energy is conserved, so:
Potential energy at point A = Kinetic energy at point B + Potential energy at point B
The potential energy at point B is given by;
Potential energy at point B = mass × gravity × height_B
Since the sledder starts from rest at point A, the kinetic energy at point A is zero. Therefore, the potential energy at point A is equal to the total mechanical energy at point B:
Potential energy at point A = Kinetic energy at point B + Potential energy at point B
mass × gravity × height_A = (1/2) × mass × velocity_B² + mass × gravity × height_B
Simplifying and rearranging the equation, we get;
(1/2) × mass × velocity_B² = mass × gravity × (height_A - height_B)
Canceling out the mass on both sides, we have;
(1/2) × velocity_B² = gravity × (height_A - height_B)
Now, we will solve for velocity_B;
velocity_B = √[2 × gravity × (height_A - height_B)]
Substituting the given values;
gravity ≈ 9.8 m/s²
height_A = 5.0 m
height_B = 3.0 m
velocity_B = √[2 × 9.8 m/s² × (5.0 m - 3.0 m)]
velocity_B = √(2 × 9.8 m²/s² × 2.0 m)
velocity_B ≈ √(39.2 m²/s²)
velocity_B ≈ 6.26 m/s
Therefore, the sledder is going at approximately 6.26 m/s at point B.
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which of the following statements about mass movement is true? group of answer choices water plays no part in mass movement events. some mass movements occur with no discernible trigger. saturation with water increase friction among particles. all mass movement events have a discernible trigger.
The true statement about mass movement is: some mass movements occur with no discernible trigger.
Mass movements can be caused by various factors, such as changes in slope, water saturation, or even sudden events like earthquakes, not all events have a discernible trigger. Some events occur due to natural processes such as erosion or weathering, while others may be influenced by human activity.
However, water does play a significant role in mass movement events, as saturation with water can increase friction among particles and trigger movement. Sometimes they can happen without a clear, identifiable cause.
Therefore some mass movements occur with no discernible trigger.
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How will the element Ca + O bond ?
Answer:
Ionic bonding
Explanation:
Since Ca is a metal and O is a nonmetal, they will experience ionic bonding. This means that Ca will "donate" two of its valence electrons to O. This will give both Ca and O a complete octet.
Answer:
CaO
Explanation:
Depending on the element "a" stands for, there is not enough info to conclude how these elements would bond. however, if they are typed out correctly then one possible bond would be CaO. I am assuming that the C and O represent Carbon and Oxygen.
which of the following is incorrect for nuclear forces
a) they are attractive in nature
b) they are short range forces
c) they obey inverse square law
d) they are non conservative in nature
Answer:
c they obey inverse square law
Give one concrete example of the following concepts in relation to your daily routine at home.
1. Law of Inertia
2. Law of Acceleration
3. Law of Interaction
4. Work and Power
5. PE to KE
6. Sound and Light
7. Heat and Electricity
Answer:
Example for 1. Law of Inertia
Falling forward while getting down from a moving bus:
When a passenger gets down from a moving bus, their upper body is still in motion, and when it comes in contact with the ground which is at rest, their body topples forward due to the inertia of motion.
Example for 2. Law of Acceleration
Hitting a Ball:
A ball develops a certain amount of acceleration after being hit. The acceleration with which the ball moves is directly proportional to the force applied to it. This means that the harder you hit the ball, the faster it will move
Example for 3. Law of Interaction
Walking:
Whenever people walk, their foot exerts a force on the ground. The ground then exerts an equal force which points in the opposite direction. It is this force (force due to friction) that allows the person to move forward.
Example for 4. Work and Power
As P=F.v
Cycling:
A person riding a bicycle possesses some amount of energy. This energy is utilized by the cyclist to do work on the paddles of the bicycle by applying some force and enabling the bicycle to move forward.
Example for 5. PE to KE
An apple hanging on a tree:
It has the potential energy due to its raised position. When the apple falls from the tree. The falling apple has the kinetic energy. Thus the potential energy stored in the apple in its raised position changes into the kinetic energy when the apple is falling. This kinetic energy does work on stone as the apple strikes the stone, and it makes the stone to move into the ground.
Example for 6. Sound and Light
TV:
We see TV takes electrical energy as input and produces. light energy, sound energy.
Example for 7. Heat and Electricity
The electric heaters:
An electric heater is an electrical device that converts an electric current into heat.
This sport involves travelling down a
fast-flowing river in an inflatable boat.
What is called?
Answer: rafting
Explanation:
this sport is called rafting because they go down a river with fast paced water and a blow up boat because they do it for a thrill like a water ride.
Rank the electric potential energy of the charged particles from highest to lowest.
Answer:
1, 2, 3, 4
Explanation:
Just did it on Edge
-----
Answer:
1234 is correct
Explanation:
eleven wa=eighs 47 kg. her height is 1.63 m. what is her bmi
Answer:
17.7kg/\(m^{2}\)
Explanation:
BMI =
= \(\frac{weight (kg)}{height (m) . height (m)}\)
= 47kg/(1.63m×1.63m)
= 17.689kg/\(m^{2}\)
≈ 17.7kg/\(m^{2}\)
When two forces act in the same direction on an object, the net force is found by ....................the forces.
1. adding
2.subtracting
3.multipling
4.dividing
Answer:
By ADDING the forces
Explanation:
if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, what is the net force direction on the cart?
The net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.
The net force direction can be determined by finding the net vector sum of the forces acting on it.
Since the first person pulled the cart to the right with a force of 10n,
Assuming the right direction as positive, this force can be represented as a vector ⇒(+)10n
Similarly, as the second person pulls the cart to the left, the force can be represented as a vector ⇒ (-)3n,
∴ Net force = Net vector sum of the forces
=(+10n) + (-3n)
⇒Net force = +7n
Thus, the net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.
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Answer: 7n
Explanation:
Consider a straight length of wire placed in a uniform magnetic field. What is the magnitude of the force per meter of length on the wire if it is carrying a 9.00 A current while being oriented perpendicular to a 0.740 T uniform magnetic field
The magnitude of the force per meter of length on the wire cannot be determined without knowing the length of the wire. However, using the formula F = I x L x B, we can calculate the force if the length is known.
The magnitude of the force per meter of length on the wire can be determined using the formula F = I x L x B, where F is the force, I is the current, L is the length, and B is the magnetic field strength.
Given that the wire is carrying a current of 9.00 A and is oriented perpendicular to a uniform magnetic field of 0.740 T, we can substitute these values into the formula.
To find the force per meter of length, we need to determine the length of the wire. However, this information is not provided in the question. Therefore, we cannot calculate the exact force per meter of length.
However, I can still provide an example to illustrate how to calculate the force per meter of length.
Let's assume the wire has a length of 2 meters. Using the formula F = I x L x B, we can substitute the values:
F = 9.00 A x 2 m x 0.740 T
F = 13.32 N
So, if the wire has a length of 2 meters, the magnitude of the force on the wire would be 13.32 N.
In conclusion, the magnitude of the force per meter of length on the wire cannot be determined without knowing the length of the wire. However, using the formula F = I x L x B, we can calculate the force if the length is known. An example was provided assuming a wire length of 2 meters, resulting in a force of 13.32 N.
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How does Earth's magnetic field protects our atmosphere? Explain one theory for why Mars no longer has an atmosphere,
Answer:
Mars doesn't have an intrinsic global magnetic field, but the solar wind directly interacts with the atmosphere of Mars, leading to the formation of a magnetosphere from magnetic field tubes.
Explanation:
Explain how the velocity of an object changes in respect to time.
Answer:
Is this your ans of this question
Answer:
The rate of change in the velocity of an object per unit time is referred as acceleration and the kind of motion is known as accelerated motion. The acceleration is positive when it is in the direction of velocity and negative when it is opposite to the direction of velocity.
Explanation:
HOPE YOU UNDERSTAND
Consider two identical baseballs which start at the same location; their terminal speed at this location is 32 m/s. At t = 0s, Ball A is thrown straight up at m/s; Ball B is thrown at 16m/s 30.0° below the horizontal at 32 m/s. How do the magnitudes of the baseballs' accelerations32 2at t = 0s compare (do not neglect air resistance)?
Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is B
Explanation:
From the question we are told that
The terminal velocity of both balls is \(v_t = 32 \ m/s\)
The speed with which ball A is thrown up at t =0 s is \(v__A}} = 16\sqrt{2}\)
The speed with which ball B is thrown 30° below the horizontal at t =0 s is
\(v__{B}} = 32\sqrt{2}\)
Generally the acceleration of ball A is (g i.e acceleration due gravity)given that it is thrown straight up
Generally the vertical acceleration of ball B is mathematically represented as
\(a = gcos (90 - 30)\)
\(a = gcos (60)\)
Generally the ratio of both acceleration is
\(\frac{a__{{A}}}{a__{{B}}}} =\frac{g}{gsin(60)}\)
=> \(\frac{a__{{A}}}{a__{{B}}}} = \frac{1}{sin (60)}\)
=> \(\frac{a__{{A}}}{a__{{B}}}} = \frac{1}{\frac{\sqrt{3} }{2} }\)
=>\(\frac{a__{{A}}}{a__{{B}}}} = \frac{2}{\sqrt{3} }\)
Rationalizing
=> \(\frac{a__{{A}}}{a__{{B}}}} = \frac{2}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} }\)
=> \(\frac{a__{{A}}}{a__{{B}}}} = \frac{2 \sqrt{3} }{3}\)
=>\(a__{B}} = \frac{2\sqrt{3} }{3} * a__{A}}\)
How much weight is generated by an 80 kg person on planet earth? On the moon?
A drag racer starts at rest and reaches a speed of 386.0 km/h with an average acceleration of 16.5 m/s2. How long does this acceleration take?
Answer:
about 16.5 by-
wait DO UR OWN MATH lol
Explanation:
Which change corrects the error in his steps?
Charlie writes the steps shown to describe the use
of a transistor in a closed circuit with flowing current.
Using a Transistor to Amplify a Signal
1. Current (1) flows from the base to the emitter.
2. An input causes a small increase in voltage
across the base and emitter.
3. Ji increases a small amount.
4. Current (12) flowing from the emitter to the
collector changes a large amount.
O Change the title to "Using a Transistor as a
Switch."
O Change step 1 to say that no current flows in the
transistor at the start.
O Reverse the sizes of the changes in current in
steps 3 and 4.
O Reverse the direction of current in step 4.
Answer:
answer is D
Explanation:
took test and got 100%
The change that corrects the error in his steps is reverse the direction of current in step 4.
What is amplifier?An amplifier, is an electronic device that can be used to increase output power.
Observed steps in using a transistor to Amplify a SignalCurrent (1) flows from the base to the emitter. An input causes a small increase in voltage across the base and emitter. Ji increases a small amount.Current (2) flowing from the emitter to the collector changes a large amount.Thus, the change that corrects the error in his steps is reverse the direction of current in step 4.
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Many exotic materials are being used in vehicle construction today, different steels, alloys, plastics, etc. Pick a material group that you think will increase in use by vehicle manufacturers, and discuss how you think this construction method will affect collision repair methods in the future.
The increased use of advanced composite materials in vehicle construction will require collision repair methods to adapt and evolve. Collision repair technicians will need to acquire the necessary expertise, training, and equipment to effectively repair composites. Additionally, the cost of composite repairs may be higher, impacting insurance rates and repair costs for vehicle owners.
Plastics, specifically advanced composite materials, are expected to increase in use by vehicle manufacturers in the future. This construction method will have a significant impact on collision repair methods.
Composite materials, such as carbon fiber-reinforced polymers (CFRP), offer numerous advantages for vehicle construction, including their high strength-to-weight ratio, corrosion resistance, and design flexibility. These materials are lighter than traditional metals while maintaining comparable strength, which contributes to improved fuel efficiency and reduced emissions in vehicles.
However, the increased use of advanced composite materials in vehicle construction poses challenges for collision repair. Repairing composites requires specialized knowledge, tools, and techniques that may be different from traditional metal repairs. Composites may require specific curing processes, such as autoclave or vacuum infusion, and specialized repair materials, including adhesives and resins.
Additionally, composite repairs may involve intricate processes such as layup, curing, and finishing, which demand a higher level of expertise and training for collision repair technicians. The repair process may require different equipment, such as infrared heaters or ultrasonic testing devices, to ensure proper repairs and structural integrity.
Moreover, the cost of repairing composite materials is often higher compared to traditional metal repairs. Advanced composite materials can be more expensive to purchase, and the specialized repair techniques and materials add to the overall repair costs.
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The increase in use of exotic materials such as composites and high-strength plastics in vehicle construction will require different collision repair techniques such as plastic welding or resin infusion. This progression implies a shift towards more complex, technologically advanced repairs and potentially higher costs.
Explanation:In the field of vehicle construction, one can predict an increase in the use of exotic materials, such as composites and high-strength plastics. These materials present unique properties of high strength and lightness, in line with industry trends to substitute traditional materials like steel.
This shift will likely impact future collision repair methods. The use of exotic materials, particularly high-strength plastics and composites, could necessitate different techniques of repair, such as plastic welding or resin infusion. Rather than typical methods of hammering dents from steel-body vehicles, mechanics will need to adapt to these newer, more complicated repair processes. They would require specialized training and likely advanced technical equipment.
Therefore, it is plausible that evolving the use of these materials could significantly shape the future of collision repairs—moving towards complex methods, relying more on sophisticated technology and skilled workers. This evolution could also possibly lead to higher repair costs as complexity increases.
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Which three characteristics make a glowing piece of charcoal a blackbody radiator? A. The frequencies of EMR it emits depend on its temperature. B. It emits only one frequency of EMR. C. It absorbs most of the EMR it receives. D. It emits a range of wavelengths of EMR.
Answer:
A. The frequencies of EMR it emits depend on its temperature
B. It emits only one frequency of EMR
C. It absorbs most of the EMR it receives
Explanation:
A blackbody is an object that absorbs most of the electromagnetic spectrum of energy that falls on it. According to law to reradiates most of the available energy back on top the outer space at an efficiency of 100% and thus radiation may be in the visible range of temperature than are in 1000K.Answer: it’s A C and D
Explanation:
i got it wrong because of the other answer but this is the right one