The composite functions (f/g)(x) and (f-g)(x) are (2x-1)/√(3x-5) and (2x-1) -√(3x-5)
Calculating the composite functions (f/g)(x) and (f-g)(x)To calculate (f/g)(x), we need to divide f(x) by g(x):
(f/g)(x) = f(x)/g(x) = (2x-1)/√(3x-5)
The domain of (f/g)(x) is the set of all x-values for which the denominator √(3x-5) is not equal to zero and non-negative
3x-5 ≥ 0, or x ≥ 5/3
Therefore, the domain of (f/g)(x) is x ≥ 5/3.
To calculate (f-g)(x), we need to subtract g(x) from f(x):
(f-g)(x) = f(x) - g(x) = (2x-1) - √(3x-5)
The domain of (f-g)(x) is the set of all x-values for which the expression inside the square root is non-negative:
3x-5 ≥ 0, or x ≥ 5/3
Therefore, the domain of (f-g)(x) is x ≥ 5/3.
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Bandhan Bank employee salary after 10 years
Answer:
- Banking Operations salary in India with less than 1 year of experience to 10 years ranges from ₹ 1.4 Lakhs to ₹ 7 Lakhs with an average annual salary of ₹ 3.1 Lakhs based on 261 latest salaries
Our customer retention rate has decreased 10% from last quarters goal of 250 consumers retained. We need to increase our current rate by at least 16% to meet this quarters goal. That means our target is?
well, on the last quarters we rambled about retaining 250 customers, but hell we ended up with 10% less than that
\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{10\% of 250}}{\left( \cfrac{10}{100} \right)250}\implies 25~\hfill \underset{current~amount}{\stackrel{250~~ - ~~25}{\text{\LARGE 225}}}\)
now, we need to increase our current amount by 16% more than that
\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{16\% of 225}}{\left( \cfrac{16}{100} \right)225}\implies 36~\hfill \underset{target~amount}{\stackrel{225~~ + ~~36}{\text{\LARGE 261}}}\)
An Airplane uses the equation y=0.28x+24 to calculate the fare y, in dollars, for a trip of x miles. What is the fare for 500-mile trip?
The fare for a 500-mile trip is 164.
What is the fare for a 500-mile trip?The equation provided in the question is known as a linear equation. A linear equation is an equation that has a single variable that is raised to the power of one.
The general form of a linear equation is:
y = mx + b
Where:
m = slope b = interceptIn the equation used to calculate the fare, y=0.28x+24, 0.28 is the variable cost and 24 is the fixed cost.
Cost of a 500-mile trip = y=0.28(500) +24
y = 140 + 24
y = 164
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20 points
5. According to a survey conducted by the ARSA 6th graders, 150 out
of 500 students ride the bus home from school. What percent of ARSA
students do not ride the bus home?
A 12.5%
B 30%
C 37.5%
D 70%
Ya girl need help :(
the data from an independent-measures research study produce a sample mean difference of 12 points and an estimated standard error of 4 points.if there are n
The option d is correct for the given problem.
What is test statistic?
A statistic used in statistical hypothesis testing is known as a test statistic. A hypothesis test is typically specified in terms of a test statistic, considered as a numerical summary of a data-set that reduces the data to one value that can be used to perform the hypothesis test.
Given:
The data from an independent-measures research study produce a sample mean difference of 12 points and an estimated standard error of 4 points.
Test statistics = (x bar - μ) / (σ / √n)
= 12 / 4
Test statistics = 3
Here the test statistics is 3.
Hence, the option d is correct for the given problem.
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Complete question:
The data from an independent-measures research study produce a sample mean difference of 12 points and an estimated standard error of 4 points. If there are n = 10 scores in each sample, then the value for the t statistic is ____.
Select one:
a. 2
b. 4
c. 1.63
d. 3
One runner had a personal best time, and the other runner neither trained nor had a personal best time
While one runner demonstrated dedication and improvement through a personal best time, the other runner's lack of training and absence of a personal best time suggest a more casual or unprepared approach to the race.
In a race between two runners, one of them had a personal best time, while the other runner neither trained nor had a personal best time.
The runner who had a personal best time implies that they had trained and put in effort to improve their performance. A personal best time suggests that they have achieved their highest level of performance in a race. This indicates that the runner has dedicated time and effort to their training regimen, focusing on improving their speed and endurance.
On the other hand, the runner who neither trained nor had a personal best time implies that they did not invest effort in training or actively seek to improve their performance. They may have participated in the race casually or without specific training goals in mind. As a result, they did not achieve a personal best time, indicating that they did not put in the necessary effort to reach their full potential.
In summary, while one runner demonstrated dedication and improvement through a personal best time, the other runner's lack of training and absence of a personal best time suggest a more casual or unprepared approach to the race.
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2./10
To rationalize the denominator of
311
you should multiply the expression by which fraction?
Complete Question:
To rationalize the denominator of 2√10/3√11 , you should multiply the expression by which fraction?
Answer:
Multiply by \(\frac{\sqrt{11}}{\sqrt{11}}\)
Step-by-step explanation:
Given
\(\frac{2\sqrt{10}}{3\sqrt{11}}\)
Required
To rationalize
To do this, we simply multiply the expression by the fraction of \(\frac{\sqrt{11}}{\sqrt{11}}\)
This gives:
\(\frac{2\sqrt{10}}{3\sqrt{11}} * \frac{\sqrt{11}}{\sqrt{11}}\)
\(\frac{2\sqrt{10 * 11}}{3\sqrt{11 * 11}}\)
\(\frac{2\sqrt{110}}{3\sqrt{121}}\)
Express \(\sqrt{121\) as 11
\(\frac{2\sqrt{110}}{3*11}\)
\(\frac{2\sqrt{110}}{33}\)
Hence:
\(\frac{2\sqrt{10}}{3\sqrt{11}}\) = \(\frac{2\sqrt{110}}{33}\)
Get it right please.
A zoologist recorded the speed of two cheetahs. Cheetah A ran 17 miles in 8 minutes. Cheetah B ran 56 miles in 20 minutes. Which statement is correct?
Cheetah A has a higher ratio of miles per minute than Cheetah B because 17 over 8 is less than 56 over 20.
Cheetah B has a higher ratio of miles per minute than Cheetah A because 17 over 8 is greater than 56 over 20.
Cheetah B has a higher ratio of miles per minute than Cheetah A because 17 over 8 is less than 56 over 20.
Both cheetahs have the same ratio of miles per minute.
The answer would be C - "Cheetah B has a higher ratio of miles per minute than Cheetah A because 17 over 8 is less than 56 over 20."
also "get it right please" ?! how rude
A) Find an equation for the line perpendicular to the tangent line to the curve y=x^3-4x+6 at the point (2,6)
-The equation is y=
b) What is the smallest slope on the curve? At what point on the curve does the curve have this slope?
-The smallest slope on the curve is
-The curve has the smallest slope at the point
c) Find equations for the tangent lines to the curve at the points where the slope of the curve is 8.
Answer:
f(x) = x³ - 4x + 6
f'(x) = 3x² - 4
a) f'(2) = 3(2²) - 4 = 12 - 4 = 8
6 = 8(2) + b
6 = 16 + b
b = -10
y = 8x - 10
b) 3x² - 4 = 0
3x² = 4, so x = ±2/√3 = ±(2/3)√3
= ±1.1547
f(-(2/3)√3) = 9.0792
f((2/3)√3) = 2.9208
c) 3x² - 4 = 8
3x² = 12
x² = 4, so x = ±2
f(-2) = (-2)³ - 4(-2) + 6 = -8 + 8 + 6 = 6
6 = -2(8) + b
6 = -16 + b
b = 22
y = 8x + 22
f(2) = 6
y = 8x - 10
The equation perpendicular to the tangent is y = -1/8x + 25/4
-The smallest slope on the curve is 2.92
The curve has the smallest slope at the point (1.15, 2.92)
The equations at tangent points are y = 8x + 16 and y = 8x - 16
Finding the equation perpendicular to the tangentFrom the question, we have the following parameters that can be used in our computation:
y = x³ - 4x + 6
Differentiate
So, we have
f'(x) = 3x² - 4
The point is (2, 6)
So, we have
f'(2) = 3(2)² - 4
f'(2) = 8
The slope of the perpendicular line is
Slope = -1/8
So, we have
y = -1/8(x - 2) + 6
y = -1/8x + 25/4
The smallest slope on the curveWe have
f'(x) = 3x² - 4
Set to 0
3x² - 4 = 0
Solve for x
x = √[4/3]
x = 1.15
So, we have
Smallest slope = (√[4/3])³ - 4(√[4/3]) + 6
Smallest slope = 2.92
So, the smallest slope is 2.92 at (1.15, 2.92)
The equation of the tangent lineHere, we set f'(x) to 8
3x² - 4 = 8
Solve for x
x = ±2
Calculate y at x = ±2
y = (-2)³ - 4(-2) + 6 = 6: (-2, 0)
y = (2)³ - 4(2) + 6 = 6: (2, 0)
The equations at these points are
y = 8x + 16
y = 8x - 16
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triangular prism: V = 42 cm3;
base length = 2 cm; base height
=
= 6 cm
h =
Answer:
7 cm
Step-by-step explanation:
base area = (base length x base height)/2 = (2x6)/2 = 6 cm^2
height = V / base area = 42 / 6 = 7 cm
PLS PLS PLS HELP ME! I WILL GIVE BRAINILIEST!
Answer:
I'm going to answer in the comments so no one steals this answer
Step-by-step explanation:
find ()
(x).
For f(x) = 4x +1 and g(x) = x2-5, find
BRAINLIST
Answer: answer is C
Step-by-step explanation:
A line passes through the point (-9,-6) and has a slope of -(2)/(3).
Answer:
\(\displaystyle y + 6 = -\frac{2}{3}(x + 9)\)
Explanation:
In the Point-Slope formula, \(\displaystyle y - y_1 = m(x - x_1),\)−C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with those minus symbols.
I am joyous to assist you at any time.
Please help will give brainliest
Answer:
Step-by-step explanation:
Ur welcome for nothink
show full solutions.15. Name the indicated parts of this diagram.
Given:
A circle with a center at C.
Required:
We need to find the names of the given parts.
Explanation:
Recall that radius is a line segment extending from the center of a circle to the circumference.
Line segment AC extends from the center C of a circle to the circumference.
\(AC=Radius\)Recall that the arc of a circle is defined as the part of the circumference of a circle.
AE is the part of the circumference of a circle.
\(AE=Arc\)Recall that a straight line segment joins and is included between two points on a circle.
D and E are two points on a circle.
A straight line DE line segment joins and is included between two points D and E on a circle.
\(DE=Chord\)Recall that meeting a curve or surface in a single point if a sufficiently small interval is considered a straight line tangent to a curve.
AB is tangent.
\(AB=Tangent\)Recall that an inscribed angle is an angle with its vertex "on" the circle, formed by two intersecting chords.
\(\measuredangle ADE=\text{ Inscribed angle.}\)Recall that a central angle is an angle formed by two radii with the vertex at the center of the circle.
\(\measuredangle ACE=\text{ Central angle}\)Recall that an angle formed by an intersecting tangent and chord has its vertex "on" the circle.
\(\measuredangle\measuredangle CAB=\text{ Tangent Chord Angle}\)Final answer:
\(AC=Radius\)\(AE=Arc\)\(DE=Chord\)\(AB=Tangent\)\(\measuredangle ADE=\text{ Inscribed angle.}\)\(\measuredangle ACE=\text{ Central angle}\)\(\measuredangle\measuredangle CAB=\text{ Tangent Chord Angle}\)M = I1+I₂ 31 +32 2 Now let's substitute in our given values. (-2 , 2) = ((-5 Find 2 and y2 We will now set up two equations to solve for our two unknowns of x2 and y₂. (-5 X2 (-5+₂) -5+22), (7+)) 2 - +₂)/2 = We will first want to multiply by 2 on both sides and will get −5+₂= -4 Adding 5 to both sides we get = 7 This is the coordinate of point B. Now we will set up the equation to solve for y2 +y2)/2 =
The coordinates of point B are (-3, 17).
The given equation is M = I₁ + I₂ = 31 + 32.
Now let's substitute in our given values:
(-2, 2) = ((-5 + x₂) / 2, (-5 + 2 + y₂) / 2)
We will now set up two equations to solve for our two unknowns, x₂ and y₂:
Equation 1: (-5 + x₂) / 2 = -4
Multiply both sides by 2:
-5 + x₂ = -8
Add 5 to both sides:
x₂ = -3
This gives us the x-coordinate of point B.
Equation 2: (-5 + 2 + y₂) / 2 = 7
Simplify:
(-3 + y₂) / 2 = 7
Multiply both sides by 2:
-3 + y₂ = 14
Add 3 to both sides:
y₂ = 17
This gives us the y-coordinate of point B.
Therefore, the coordinates of point B are (-3, 17).
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Susan determined that the expression below is equal to 7.59
15.91 - 8.32
Which expression can Susan use to check her answer?
A. 8.32 - 7.59
B. 8.32 + 7.59
C. 15.91 + 8.32
D. 15.91 + 7.59
Maya is estimating the product of 88 and 12. Which statements are true? Check all that apply.
If she rounds both values to the nearest ten, her estimate will be 800.
If she rounds both values to the nearest ten, her estimate will be 900.
If she rounds 88 to the nearest hundred and 12 to the nearest ten, her estimate will be 1,000
If she rounds both values to the nearest ten, her estimate will be 1,600.
If she rounds 88 to the nearest hundred and 12 to the nearest ten, her estimate will be 2,000.
Answer:
If she rounds 88 to the nearest hundred and 12 to the nearest ten, her estimate will be 1,000 because if you take 88x12, your answer is 1056. so knowing that the closest answer to 1056 is 1000 not 900.
Hope it helped!
Answer:
If she rounds 88 to the nearest hundred and 12 to the nearest ten, her estimate will be 1,000.
Step-by-step explanation:
if the system of equations y=b/6x-3 and y=2/3x-3 has infinitely many solutions, what is the value of b?
Answer:
b = 4
Step-by-step explanation:
4/6 is equivalent to 2/3, so with the slopes and y-intercepts being the same, there will be infinitely many solutions
Rewriting 3x^2=6x and solving with rewritten
Answer:
x = 0 , x = 2
Step-by-step explanation:
3x² = 6x ( subtract 6x from both sides )
3x² - 6x = 0 ← factor out 3x from each term
3x(x - 2) = 0
equate each factor to zero and solve for x
3x = 0 ⇒ x = 0
x - 2 = 0 ( add 2 to both sides )
x = 2
solutions are x = 0 , x = 2
Completing the square can be used to transform x²-6x+8=0 into the form (x - p)²= 9
What are the values of p and q?
Answer:
x² - 6x + 8 = 0
or, x² - (4+2)x + 8 = 0
or, x² - 4x - 2x + 8 = 0
or, x(x-4) -2(x -4)= 0
or , (x-4) (x-2) = 0
either,
x - 2 = 0
x = 2
OR,
x - 4 = 0
x = 4
next ,
x-p = 9
or, 2-p = 9
p= -7
either,
x-p = 9
or, 4 - p = 9
or, p= -5
hope this will help you
Find the slope and y intercept of the line 5x-9y=45
Answer:
slope = \(\frac{5}{9}\) , y- intercept = - 5
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given
5x - 9y = 45 ( subtract 5x from both sides )
- 9y = - 5x + 45 ( divide through by - 9 )
y = \(\frac{-5}{-9}\) x + \(\frac{45}{-9}\) , that is
y = \(\frac{5}{9}\) x - 5 ← in slope- intercept form
with slope m = \(\frac{5}{9}\) and y- intercept c = - 5
Use the histogram to answer the following questions.
Frequency
The frequency of the class 90-93 is
The frequency of the class 94-97 is
This means that a total of
5.5
5
4.5
Your answers should be exact numerical values.
The frequency of the class 86-89 is
86
94
90
Duration of Dormancy (minutes)
dormancy periods were recorded.
The parameters that are needed to calculate a probability are listed as follows:
Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.
The total number of periods is given as follows:
5 + 6 + 4 = 15.
The frequency of each class is given as follows:
86 - 89: 5/15 = 1/3.90 - 93: 6/15 = 2/5.94 - 97: 4/15.Learn more about the concept of probability at https://brainly.com/question/24756209
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if the area of polygon A is 72 and Q is a scaled copy and the area of Q is 5 what scale factor got 72 to 5
A area= 72
Q area =5
So, if we multiply the A area by the square of the scale factor ( since they are areas) we obtain area Q:
72 x^2 = 5
Solving for x:
x^2 = 5/72
x = √(5/72)
x= 0.26
Hatif has $150 in his account. He saves $80 each month. How long will it take before he has $630 in his account?
Answer:
6 months
Step-by-step explanation:
We can set up an equation based on his monthly savings to find out how long it will take for Hatif to reach $630 in his account.
Let's assume it takes Hatif "n" months to reach $630 in his account. Each month, he saves $80.
The equation representing the situation is:
$150 + $80n = $630
Now, let's solve for "n":
$80n = $630 - $150
$80n = $480
n = $480 / $80
n = 6
Therefore, it will take Hatif 6 months to reach $630 in his account.
Answer the attachment please
And subscribe to Offxcial Prxmiise
X=8 and y=3
Answer:
73
Step-by-step explanation:
8^2+3^2=64+9=73
I need help finding this answer because I am pretty sure it’s C but I don’t know
Answer: A) -9
Step-by-step explanation:
If x = -2
Then \(3^{x}\) = \(3^{-2}\)
So, it is -9
Is 4/5 and 5/6 equivalent or not
Answer:
For the two fractions 4/5 and 5/6, the least common denominator is 30. The fraction 4/5 is equivalent to 24/30 (To get this I multiplied both the numerator and denominator by 6). The fraction 5/6 is equivalent to 25/30 (To get this I multiplied both the numerator and denominator by 5).
Step-by-step explanation:
They are equivalent (Except for the numerator)
make x subject
u= cos 0.5x
By making x the subject of the formula in this equation u = cos(0.5x) gives x = 2cos⁻¹(u).
How to make x the subject of the formula?In Mathematics and Geometry, an equation can be defined as a mathematical expression which shows that two (2) or more thing are equal. This ultimately implies that, an equation is composed of two (2) expressions that are connected by an equal sign.
In this exercise, you are required to make "x" the subject of the formula in the given mathematical equation by using the following steps.
By taking the arc cosine of both sides of the equation, we have the following:
u = cos(0.5x)
cos⁻¹(u) = 0.5x
By multiplying both sides of the mathematical equation by 2, we have the following:
2 × cos⁻¹(u) = 0.5x × 2
x = 2cos⁻¹(u)
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These two triangles are similar .Find side lengths a and b .The two figures are not drawn to scale
Answer:
a = 6, b = 22.5
Step-by-step explanation:
One triangle is 2.5 times bigger than the other.
9*2.5=22.5 which means b = 22.5
15/2.5=6 which means a = 6
Similar triangles may or may not be congruent.
The values of a and b are 6 and 22.5, respectively.
Because the triangles are similar, then the following equivalent ratios are true.
\(\mathbf{10 : 4 = b : 9 = 15 : a}\)
First, we calculate b using:
\(\mathbf{10 : 4 = b : 9}\)
Express as fraction
\(\mathbf{\frac{10 }{ 4} = \frac{b } 9}\)
\(\mathbf{2.5 = \frac{b } 9}\)
Multiply both sides by 9
\(\mathbf{b = 2.5 \times 9}\)
\(\mathbf{b = 22.5}\)
Next, we calculate a using:
\(\mathbf{10 : 4 = 15 : a}\)
Express as fractions
\(\mathbf{\frac{4}{10} = \frac{a}{15}}\)
Multiply both sides by 15
\(\mathbf{a= 15 \times \frac{4}{10}}\)
\(\mathbf{a= 6}\)
Hence, the values of a and b are 6 and 22.5, respectively.
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