suppose that ???? is a 3-by-3 matrix, and that {[ 1 0 5 ],[ 1 1 2 ]} is a basis for the nullspace of ????. find a nontrivial vector in the row space of a.

Answer:

10 feet

Step-by-step explanation:

a²+b²+=c²

a=8ft

b=6ft

\(\frac{AB}{A"B"} = \frac{1}{4}\)  equation clearly illustrates how AABO and AA"B"C relate to one another.

An equation is, for instance, 3x - 5 = 16. We can solve this equation and determine that the value of the variable x is 7.

The three main types of linear equations are the slope-intercept form, standard form, and point-slope form.

Considering the data:

Dilation by a scale factor of 4 from the origin in the form of an A'B'C' reflection over x = 1

<=> The two triangles are comparable to one another since triangles can have the same shape but differ in size, so A′′B′′C′′ is 4 times larger than ABC.

=> the connection between "ABC" and "A"B"C" .

\(\frac{AB}{A"B"} = \frac{1}{4}\)

We settle on C.

\(\frac{AB}{A"B"} = \frac{1}{4}\)  equation clearly illustrates how AABO and AA"B"C relate to one another.

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Answer:

3⁸

Step-by-step explanation:

27 = 3* 3 * 3 = 3³

9  = 3 * 3 = 3²

Write 27 and 9 with base 3.

Law of exponents:

         \(\boxed{(a^m)^n=a^{m*n} \ and \ \dfrac{a^m}{a^n}=a^{m-n}}\)

In exponent division, if bases are same, subtract the exponents/index.

\(\dfrac{27^6}{9^5}=\dfrac{(3^3)^6}{(3^2)^5}\)

       \(=\dfrac{3^{3*6}}{3^{2*5}}\\\\\\=\dfrac{3^{18}}{3^{10}}\\\\\\=3^{18-10}\\\\=3^{8}\)

The probability that a student scored less than 55% on the exam is 0.134%.

It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.

We have:

Mean of the sample = 70

Standard deviation = 5

= P(X<55%)

Z = (55-70)/5

Z = -3

P(X < -3)

From the Z table:

P(x<-3) = 0.0013499

or

P(x<-3) = 0.134%  

Thus, the probability that a student scored less than 55% on the exam is 0.134%.

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The value of the test​ statistic is - 0.462.

A standard deviation (or) would be a way of measuring of how widely distributed the data has been in relation towards the mean. A low standard deviation indicates that data is grouped around the mean, whereas a high standard deviation indicates that data is more spread out.

The null hypothesis is:

H0 = 0.25

The alternate hypothesis is:

H1 does not equal to 0.25,

the general formula for standard deviation is :-

σ=√1N∑Ni=1(Xi−μ)2 σ = 1 N ∑ i = 1 N ( X i − μ ) 2.

Our test statistic is:

t = (x- u) /s

In which X is the sample mean,  u is the population mean(the null hypothesis),   s is the standard deviation of the sample.

According to question,

x = 23/100

x = 0.23

u = 25/100

u= 0.25

s= √(0.25 * 0.75)/100

s = 0.0433

so for the value of t,

standard deviation = (x - u)/t

so , t=  (x- u) /s

t = (0.23 - 0.25)/0.0433

t = - 0.462

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The most effective way to use her 4 hours of study time to get the highest possibility or probability of test scores would be to spend 4 hours working on multiple-choice problems and 0 hours reviewing lecture notes.

From the information given, it is clear that working on multiple-choice problems is the most effective way to improve her test score. Therefore, the highest possibility or probability of test scores would be achieved by spending the most time working on multiple-choice problems.

The available time for studying is 4 hours, so the maximum time that can be spent working on multiple-choice problems is 4 hours. If she spends 4 hours working on multiple-choice problems, she will not have any time left to review lecture notes.

So, the most effective way to use her 4 hours of study time to get the highest possible test score would be to spend 4 hours working on multiple-choice problems and 0 hours reviewing lecture notes.

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The equation of a line that is parallel to the line 2x - 5y = 10 and passes through the point (-5, 1) is B. 2x - 5y = -5.

To find the equation of a line that is parallel to the line 2x - 5y = 10, we need to determine the slope of the given line first. The equation is in the form of Ax + By = C, where A = 2, B = -5, and C = 10.

To find the slope, we can rearrange the equation into slope-intercept form (y = mx + b), where m represents the slope.

2x - 5y = 10

-5y = -2x + 10

y = (2/5)x - 2

From this equation, we can see that the slope of the given line is 2/5.

A line that is parallel to this line will have the same slope. Therefore, the equation of the parallel line can be determined using the point-slope form (y - y1 = m(x - x1)), where (x1, y1) represents the coordinates of the given point (-5, 1).

Using the slope of 2/5 and the point (-5, 1), we can now check the options to see which ones satisfy the conditions:

A. y = -x - 1: This equation has a slope of -1, not 2/5. It is not parallel to the given line.

B. 2x - 5y = -5: This equation has the same slope of 2/5 and passes through the point (-5, 1). It satisfies the conditions and is parallel to the given line.

C. y = -x - 3: This equation has a slope of -1, not 2/5. It is not parallel to the given line.

D. 2x - 5y = -15y: This equation has a slope of 2/20, which simplifies to 1/10. It is not parallel to the given line.

E. -1 = -(x - 5): This equation does not represent a line. It is not a valid option.

Therefore, the equation of a line that is parallel to the line 2x - 5y = 10 and passes through the point (-5, 1) is B. 2x - 5y = -5.

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It should be 3 inches, but I am not sure what the length is of each button if i should subtract it or not.. otherwise it should be 3!!

Answer:

$5.80

Step-by-step explanation:

The 12 members spent $48 in total and the 8 nonmembers spent 68 in total. If you add those two together and divide by 20 you get 5.8.

Answer: B

Step-by-step explanation:

because there are 12 members and 8 nonmembers so

12 × 4= 48 8 × 8.50= 68 68+48 =116 116 ÷ 20 =5.8 or $5.80

The 80% confidence interval estimate for the average browsing time is approximately 12.648572 minutes to 14.548572 minutes.

To construct an 80% confidence interval estimate of the average browsing time for the population of crownfashion.com visitors this week, we can use the following formula:

Confidence Interval = \(\bar{X}\) ± Z \(\times\)  (σ/√n)

Where:

\(\bar{X}\) is the sample mean (average browsing time) = 13.6 minutes,

Z is the Z-score corresponding to the desired confidence level (80% confidence level corresponds to a Z-score of 1.28),

σ is the population standard deviation = 5.2 minutes,

n is the sample size = 49.

Plugging in these values, we can calculate the confidence interval as follows:

Confidence Interval = 13.6 ± 1.28 \(\times\) (5.2/√49)

Simplifying the expression:

Confidence Interval = 13.6 ± 1.28 \(\times\) (5.2/7)

Confidence Interval = 13.6 ± 1.28 \(\times\) 0.742857

Confidence Interval = 13.6 ± 0.951428

The lower bound of the confidence interval is 13.6 - 0.951428 = 12.648572, and the upper bound is 13.6 + 0.951428 = 14.548572.

Therefore, the 80% confidence interval estimate for the average browsing time is approximately 12.648572 minutes to 14.548572 minutes.

The margin of error indicated by the interval is half of the width of the confidence interval, which is (14.548572 - 12.648572) / 2 = 0.95 minutes.

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The probability density function for a normal distribution N(68, 5) reaches its maximum height at x = 68, which is the mean of the distribution. The function does not touch the x-axis at μ±30.

The probability density function (PDF) for a normal distribution is bell-shaped and symmetrical around its mean. In this case, the mean (μ) is 68, and the standard deviation (σ) is 5.

(a) To find the x value at which the PDF reaches a maximum, we look at the mean of the distribution, which is 68. The PDF is highest at the mean, and as we move away from the mean in either direction, the height of the PDF decreases. Therefore, the x value at which f(x) reaches a maximum is x = 68.

(b) The PDF of a normal distribution does not touch the x-axis at μ±30. The x-axis represents the values of x, and the PDF represents the likelihood of those values occurring. In a normal distribution, the PDF is continuous and never touches the x-axis. However, the PDF becomes close to zero as the values move further away from the mean. Therefore, the probability of obtaining values μ±30, which are 38 and 98 in this case, is very low but not zero. So, the PDF does not touch the x-axis at μ±30, but the probability of obtaining values in that range is extremely small.

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Answer:

2.4(12×4)

2.4* 48

= 115.2

brsimliest pls.

An increasing monotonic sequence is a sequence of numbers in which each term is greater than or equal to the preceding term.

We have,

An increasing monotonic sequence is a sequence of numbers in which each term is greater than or equal to the preceding term.

In other words,

The sequence is monotonically increasing, with no decreasing terms.

For example,

The sequence {1, 3, 5, 7, 9, ...} is an increasing monotonic sequence, as each term is greater than the one before it.

Thus,

An increasing monotonic sequence is a sequence of numbers in which each term is greater than or equal to the preceding term.

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The complete question

Increasing monotonic sequence:

The pair of linear equations 3x + 5y = 3 and 6x + ky = 8 does not have any solution for any value of k.

We can rewrite the equations as:

3x + 5y = 3

6x + ky = 8

To solve this system, we need to eliminate one of the variables. To do this, we can multiply the first equation by 2 and the second equation by -3. This will give us:

6x + 10y = 6

-18x - 3ky = -24

Now we can add the two equations together and get:

-12x - 3ky = -18

Since the coefficient of x is 0, this equation does not have any solution for any value of k.

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Answer:

number of message sent by Scott is 23

number of message sent by Christine is   30

number of message sent by Milan is 92

Step-by-step explanation:

Total message sent by Christine,Milan, and Scott : 145

Let number of message sent by Scott be x .

Given that Christine sent 7 more messages than Scott

number of message sent by Christine is   x+7

It is also given that  Milan sent 4 times as many messages as Scott

number of message sent by Milan is   4*x = 4x.

Thus, sum of message sent by Christine,milan, and Scott  in terms of x

= x + x + 7 + 4x = 6x + 7

we already know that Total message sent by Christine,milan, and Scott is 145

thus,  6x + 7 should be equal to 145

6x + 7 = 145

=>6x = 145 - 7 = 138

=> x = 138/6 = 23

Thus,  

number of message sent by Scott is x = 23

number of message sent by Christine is   x+7 = 23+7 = 30

number of message sent by Milan is   4x = 4*23 = 92

Answer:

$93 per hour ?

125-405 = 280

280÷3= 93 per hour

According to the Question, the principal is approximately $1191.11.

To find the principal, we can use the formula for simple interest:

Simple Interest = (Principal * Rate * Time) / 100

In this scenario, we need to find the principle. We know the annual rate is 8%, leading to the monthly rate being 8%/12 (since there are 12 months in a year). The period has been defined as ten months, and the simple interest is calculated as the difference between the final amount ($1200) and the principal.

Let's calculate the principal using the given information:

Simple Interest = (Principal * Rate * Time) / 100

1200 - Principal = (Principal * (8%/12) * 10) / 100

1200 - Principal = (Principal * 0.00667)

1200 = Principal + (Principal * 0.00667)

1200 = Principal * (1 + 0.00667)

1200 = Principal * 1.00667

Principal = 1200 / 1.00667

Principal ≈ $1191.11

Rounded to the nearest cent, the principal is approximately $1191.11.

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The following statement (d) "R must be an equivalence relation, and ([x]_R: x∈X) must equal P." is true

The relation R defined as R={(x,y):x∈A and y∈A for some A∈P} is an equivalence relation.

1. Reflexivity: Since the set P does not contain the empty set, Ø∉P, for any element x∈X, there exists a set A∈P such that x∈A. Therefore, (x,x)∈R for all x∈X, making R reflexive.

2. Symmetry: Let (x,y)∈R, which means there exists a set A∈P such that x∈A and y∈A. Since A is a subset of X, it follows that y∈A and x∈A as well. Hence, (y,x)∈R, and R is symmetric.

3. Transitivity: Let (x,y)∈R and (y,z)∈R, which means there exist sets A and B in P such that x∈A, y∈A, y∈B, and z∈B. Since the union of all sets in P is X, the union of A and B is also a set in P. Thus, x∈A∪B, and z∈A∪B. Therefore, (x,z)∈R, and R is transitive.

Since R is reflexive, symmetric, and transitive, it satisfies the properties of an equivalence relation.

Additionally, the equivalence classes ([x]_R: x∈X) of R are equal to the set P. Each equivalence class [x]_R represents a subset of X that contains all elements y∈X such that (x,y)∈R. In this case, for each x∈X, the corresponding equivalence class [x]_R is the set A∈P such that x∈A.

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Answer:

839 should be the answer?

Step-by-step explanation:

840-1?

Answer:

Step-by-step explanation:

Answer:

The correct options are;

Line CD is the perpendicular bisector of line AB

Line segment AB is perpendicular to line CD

Line segment AE is congruent to line segment BE

Step-by-step explanation:

From the construction, we have that the radius of circle A is equal to the radius of circle A as the circumference of circle A passes through the center of circle A

Therefore, the construction is the bisection of line segment AB by the construction of the perpendicular bisector CD, from which we have line segment AE is congruent to line segment BE and line segment AB is perpendicular to line CD

There are 3080 ways 3 men and 2 women can be chosen if they are equally considered, using the multiplication principle of counting

The multiplication principle states that if there are m ways to perform one task and n ways to perform another task, then there are m x n ways to perform both tasks together.

To find the number of ways to choose 3 men from the 12 men, we can use the formula for combination, which is: ⁿCᵣ = n! / (r! (n-r)!).

where n is the total number of men and r is the number of men chosen

so, the number of ways to choose 3 men from the 12 men = ¹²C₃ = 1.

Similarly, we evaluate the number of ways to choose 2 women from the 8 women

as = ⁸C₂ = 14

Now, using the multiplication principle, we can find the total number of ways 3 men and 2 women be chosen if they are equally considered.

220 x 14 = 3080

Therefore, there are 3080 ways 3 men and 2 women can be chosen if they are equally considered, using the multiplication principle of counting

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Answer:

mean = total divide by nõ of items

mean = 31•855

Step-by-step explanation:

add the total ..you will get

318•55

divide by 10

318•55 ÷ 10

31•855

Answer:

13.7

Step-by-step explanation:

Pythagorean theorem converse

Answer:

The value of x is 13.7.

Step-by-step explanation:

☆We are going to use the Pythagorean theorem to solve this.

☆Pythagorean Theorem:

\( {a}^{2} + {b}^{2} = {c}^{2} \)

☆Remmeber: a = leg, b = leg, c = hypotenuse or the diagonal.

☆Let's plug in according to the pythagorean theorem and solve!

\( {a}^{2} + {b}^{2} = {c}^{2} \\ {x}^{2} + {9.2}^{2} = {16.5}^{2} \\ {x}^{2} + 84.64 = 272.25 \\ \frac{ \: \: \: \: \: \: \: \: - 84.64 = - 84.64}{ {x}^{2} = \sqrt{187.61} } \\ x = 13.7\)

Answer:

The unknown number is \(\frac{1}{5}\)

Step-by-step explanation:

Let's make the unknown number x.

The sum of 5 TIMES a number (x) & 8 is 9.

Let's write it mathematically.

5x + 8 =9

We are trying to find the unknown number, so let's remove all the numbers from the left side to find x. Minus 8.

5x=1

5x is basically 5 times x, so to find x, we need to divide and from there we can remove 5.

x= \(\frac{1}{5}\)

Answer:

They each brought $22 to the fair

Step-by-step explanation:

8+3=11

11*2=22

Answer=22

(-5, 0 ) and (0, 5) are the ordered pair satisfies the inequality y < x+5

a relationship between two expressions or values that are not equal to each other is called 'inequality.

The given inequality is y < x+5

First, we have to find the x-intercept which occurs at y = 0

0 < x + 5

x<-5

For y-intercept,

y <  0+ 5

y <5

As a result, the obtained ordered pair is  (-5, 0 ) and (0, 5).

Hence, (-5, 0 ) and (0, 5) are the ordered pair satisfies the inequality y < x+5

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To compute the Laplace transform of the given function, we can use the linearity property of the Laplace transform and apply the transform to each term separately.

Using the Laplace transform pairs:

L{1} = 1/s

L{u(t)} = 1/(s+1)

L{e^(-6t)} = 1/(s+6)

L{cos(πt)} = s/(s^2+π^2)

Applying these transforms to the given function:

L{1 u^(5/2)(t) e^(-6t) cos(πt)} = L{1} * L{u^(5/2)(t)} * L{e^(-6t)} * L{cos(πt)}

Substituting the transform pairs:

= (1/s) * (1/(s+1)^(5/2)) * (1/(s+6)) * (s/(s^2+π^2))

Simplifying this expression, we can multiply the terms together:

= s / (s(s+1)^(5/2)(s+6)(s^2+π^2))

Therefore, the Laplace transform of the given function is:

L{1 u^(5/2)(t) e^(-6t) cos(πt)} = s / (s(s+1)^(5/2)(s+6)(s^2+π^2))

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