If there is an increase in the equilibrium quantity of hamburgers, the supply shift in the market must have been greater than the demand shift.
Assuming that all demand-shift factors remain constant, the hamburger demand curve illustrates the relationship between hamburger price and quantity required by consumers. The factors influencing how many hamburgers consumers desire to purchase at a particular price are known as demand determinants.
If the price of hamburgers increases, the demand curve will move from the previous price to the new price. However, if any of the demand-shift variables change, such as the cost of hot dogs, the cost of hamburger buns, or the income of hamburger consumers, the demand curve will alter.
Demand is where the demand curve is located. Demanded quantity is the volume that customers want to purchase.
The position of the supply curve is referred to as supply. The quantity of supplies you desire to sell is referred to as the quantity supply.
In this instance, an increase in supply will result in a fall in the equilibrium price and a movement all along the demand curve. The quantity demanded changes, while the demand curve does not.
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3-4i/2+iCan you help me to solve this problem please
To solve this problem, we multiply and divide the given expression by 2-i:
\(\frac{3-4i}{2+i}(\frac{2-i}{2-i}).\)Recall that:
\((a+ib)(a-ib)=a^2+b^2.\)Therefore:
\(\frac{3-4i}{2+i}(\frac{2-i}{2-i})=\frac{(3-4i)(2-i)}{2^2+1^2}=\frac{(3-4i)(2-i)}{5}.\)Finally, multiplying the factors in the numerator, we get:
\(\frac{6-3i-8i-4}{5}.\)Finally, simplifying the above result, we get:
\(\frac{2-11i}{5}=\frac{2}{5}-\frac{11}{5}i.\)Answer: \(\begin{equation*} \frac{2}{5}-\frac{11}{5}i. \end{equation*}\)the distribution of grades was left-skewed, but the mean, median, and mode were all the same.
In your given situation, the distribution of grades is left-skewed, which indicates that the majority of the students scored higher grades, with fewer students receiving lower grades.
If the distribution of grades was left-skewed, it means that there were more students who scored higher grades than those who scored lower grades. This would result in a longer tail on the left side of the distribution curve. However, despite the skewness, the mean, median, and mode were all the same. This suggests that the majority of the grades fell around the same value, which is the central tendency of the distribution. The fact that the mean and median are the same suggests that the skewness was not significant enough to pull the mean away from the median. Therefore, in this case, the mean and median can be considered as representative of the typical grade achieved by the students.
. However, the mean, median, and mode are all the same, suggesting that the central tendency of the grades is consistent, and the overall distribution might be only slightly skewed.
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PLEASE HELP ASAPPPPP!!!!
Answer:
(3,-2)
Step-by-step explanation:
All the others are either negative, 0, or 1. The outlier is 3,-2 because no other coordinate has a positive 3 in the x position.
Hope this helps!!
Have an amazing day!!
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Tyrel evaluated the expression 2 1/2− 3/4. Which is one way he can check his work?
The value is 7/4 = 1.75
From the question, we have
\(2\frac{1}{2} -\frac{3}{4} \\=\frac{5}{2} -\frac{3}{4} \\=\frac{10-3}{4}\\=\frac{7}{4}=1.75\)
Subtraction:
The act of deleting items from a collection is represented by subtraction. Subtraction is denoted by the minus sign. For instance, supposing there are nine oranges stacked together (as indicated in the above image), four oranges are taken out and put in a basket, leaving nine – four oranges, or five oranges, in the stack. Therefore, 9 minus 4 equals 5, or the difference between 9 and 4. Different kinds of numbers can also use subtraction, which is not just applicable to natural numbers. This means that we can use several sets of objects, such as negative numbers, fractions, rational and irrational numbers, decimals, functions, matrices, and vectors, to explain reducing or eliminating physical and abstract values.
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Please Help.
A square prism and a cylinder have the same height. The area of the cross-section of the square prism is 314 square units, and the area of the cross-section of the cylinder is 50π square units. Based on this information, which argument can be made?
A. The volume of the square prism is one third the volume of the cylinder.
B. The volume of the square prism is half the volume of the cylinder.
C. The volume of the square prism is equal to the volume of the cylinder.
D. The volume of the square prism is twice the volume of the cylinder.
As we know, The volume of the square prism is twice the volume of the cylinder
To determine the relationship between the volume of the square prism and that of the cylinder, we need to find both volumes.
The volume of the square prism is V = Ah where A is the cross-sectional area and h its height. Since A = 314 square units,
V = 314 × h = 314h
Also, the volume of the cylinder is V = A'h where A' is the cross-sectional area of the cylinder and h' its height. Since the A' = 50π square units,
V' = 50π × h' = 50πh'
The ratio of the volume of the square prism to that of the cylindrical prism is V/V' = 314h/50πh'
Since the height of the square prism equals that of the cylinder, h = h'.
So, V/V' = 314h/50πh .
V/V' = 314/50π
if we take π = 3.14,
V/V' = 314/(50 × 3.14)
V/V' = 100/50
V/V' = 2
So, V = 2V'
Thus, the volume of the square prism is twice the volume of the cylinder.
So, the answer is D.
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Answer:
D. The volume of the square prism is twice the volume of the cylinder.
Step-by-step explanation:
took the test, got it right, comment below if you would like a step by step explanation
health programs routinely study the number of days that patients stay in hospitals. in one study, a random sample of 12 men had a mean of 7.95 days and a standard deviation of 6.2 days, and a random sample of 19 women had a mean of 7.1 days and a standard deviation of 5.0 days. the sample data will be used to construct a 95 percent confidence interval to estimate the difference between men and women in the mean number of days for the length of stay at a hospital. have the conditions been met for inference with a confidence interval?
The conditions for inference with a confidence interval have been met, and we can proceed to construct a confidence interval to estimate the difference between men and women in the mean number of days.
What is confidence interval ?
A confidence interval is a range of values that is likely to contain the true value of a population parameter with a certain level of confidence.
To determine if the conditions for inference with a confidence interval have been met, we need to check the following assumptions:
Random Sampling: The sample of men and women should be random and representative of the population.Normality: The distribution of the difference between the means should be approximately normal.Independence: The two samples should be independent of each other.Since the sample sizes are greater than 30 for both men and women, we can assume normality based on the Central Limit Theorem.
Also, since the samples are selected independently and randomly, the assumption of independence is met.
Therefore, the conditions for inference with a confidence interval have been met, and we can proceed to construct a confidence interval to estimate the difference between men and women in the mean number of days for the length of stay at a hospital.
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425% as a fraction in the simplest form
Answer:
174
Step-by-step explanation:
Answer:
\(4\frac{1}{4}\) or \(\frac{17}{4}\)
Step-by-step explanation:
1/4 divided by 2/5?
I WILL MARK THE BRAINLIEST
Answer:
I do believe The Answer Is 0.625
Answer:
5/8 or 0.625
Step-by-step explanation:
Hope this helps!
=
Interim Checkpoint: Grade 7 Checkpoint 4 - Part 1
Write an equation that you can use to solve for X.
Enter your answer in the box.
100°
60
60 is the amazing cool answer XD
A region is prone to flooding once every 20 years. If the probability of flooding in that region any one year is >o. What is the probabilit, of not flooding the next year
The probability of the region not flooding the next year is 19/20.
Given that a region is prone to flooding once every 20 years, we can calculate the probability of flooding in any one year as:
Probability of flooding in any one year = 1/20 = 0.05
Since the probability of flooding in any one year is greater than 0, the probability of not flooding in any one year would be:
Probability of not flooding in any one year = 1 - 0.05 = 0.95
Therefore, the probability of not flooding the next year in this region would be 0.95 or 95%.
Hi, I'd be happy to help you with your probability question.
The probability of flooding in the region any one year is 1/20 (once every 20 years). To find the probability of not flooding the next year, we need to find the complement of the probability of flooding.
Step 1: Determine the probability of flooding.
P(Flooding) = 1/20
Step 2: Find the complement probability.
P(Not Flooding) = 1 - P(Flooding)
Step 3: Calculate the probability of not flooding.
P(Not Flooding) = 1 - (1/20) = 19/20
The probability of the region not flooding the next year is 19/20.
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We can approach this problem using the concept of probability and complement rule.
Given that a region is prone to flooding once every 20 years, we can assume that the probability of flooding in any given year is 1/20 or 0.05 (since once in 20 years means once in 20 trials, and the probability of success in any one trial is 1/20).
Now, the probability of not flooding in the next year can be calculated using the complement rule, which states that the probability of an event happening is equal to 1 minus the probability of the event not happening.
Therefore, the probability of not flooding in the next year can be calculated as follows:
P(not flooding) = 1 - P(flooding)
P(not flooding) = 1 - 0.05
P(not flooding) = 0.95
So, the probability of not flooding in the next year is 0.95 or 95%. This means that there is a high likelihood that the region will not experience flooding in the next year.
However, it's important to note that the probability of flooding in any given year is still greater than 0, which means that there is always a possibility of flooding occurring, regardless of whether it occurred in the previous year or not.
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Simplify the following radical expression by rationalizing the denominator. (-6)/(\sqrt(5y))
The simplified radical expression by rationalizing the denominator is, \(\frac{-6}{\sqrt{5y}}\times\frac{\sqrt{5y}}{\sqrt{5y}}\) = \(\frac{-6\sqrt{5y}}{5y}$$\) = $\frac{-6\sqrt{5y}}{5y}$.
To simplify the radical expression by rationalizing the denominator, multiply both numerator and denominator by the conjugate of the denominator.
The given radical expression is \($\frac{-6}{\sqrt{5y}}$\).
Rationalizing the denominator
To rationalize the denominator, we multiply both the numerator and denominator by the conjugate of the denominator, \($\sqrt{5y}$\)
Note that multiplying the conjugate of the denominator is like squaring a binomial:
This simplifies to:
(-6√(5y))/(√(5y) * √(5y))
The denominator simplifies to:
√(5y) * √(5y) = √(5y)^2 = 5y
So, the expression becomes:
(-6√(5y))/(5y)
Therefore, the simplified expression, after rationalizing the denominator, is (-6√(5y))/(5y).
\($(a-b)(a+b)=a^2-b^2$\)
This is what we will do to rationalize the denominator in this problem.
We will multiply the numerator and denominator by the conjugate of the denominator, which is \($\sqrt{5y}$\).
Multiplying both the numerator and denominator by \($\sqrt{5y}$\), we get \(\frac{-6}{\sqrt{5y}}\times\frac{\sqrt{5y}}{\sqrt{5y}}\) = \(\frac{-6\sqrt{5y}}{5y}$$\)
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use the guidelines of this section to sketch the curve. y = 3^x2 − 25
Using all the guidelines of drawing a curve skitching in this section, the sketch of curve, y = ³√x² - 25 is present in above figure. So, option(c) is right answer here.
In geometry, curve sketching (or curve tracing) are methods for producing a rough idea of overall shape of a plane curve. We have a curve equation, f(x) or
\(y = \sqrt[3]{x² - 25}\). Guidelines or important points for curve sketching :
Determine the domain of the function and points of discontinuity.As we see provide equation or function has no point of discontinuity and domain is set of reals.
Intercepts : determine the x- and y-intercepts of the function, if possible. For x-intercept, we put y = 0 and solve the equation for x. Similarly, we set x= 0 for y-intercept.If x = 0 , then y = 0 so y-intercept= 0. Similarly, when y = 0 then x = ±5.
Symmetry : Determine whether the function is even, odd, or neither. For it, If f(−x) = f(x) for all x, domain then f(x) is even and symmetric about the y−axis. If f(−x) = −f(x) for all x in the domain, then f(x) is odd and symmetric about the origin.The value of f( -x) = \( \sqrt[3]{ { x}^{2} - 25} \) = f(x) ( since (-1)² = 1 ) , so, then y is even and symmetric about the y−axis.
Calculate the first derivative f′(x) and determine the critical points of the function.Differentiating equation (1), \( \frac{dy}{dx} = \frac{1}{3 }( x²- 25)^{-2/3}2x \)
Now, plug dy/dx = 0 for determining the critical points, \( \frac{1}{3} ( x²- 25)^{-2/3}2x = 0\)
So, critical points are x = 0, 5, -5.
Points of Inflection : Using the Second Derivative Test, determine the points of inflection that is f′′(x)=0.Differentiating again, equation,
\(f''(x) = \frac{ - 4x² }{3}( x² - 25)^{-5/2} + \frac{2}{3}( x² - 25)^{-1/3} \\\)
\(f''(x) = \frac{ - 4x² }{3}( x² - 25)^{-5/2} + \frac{2}{3}( x² - 25)^{-1/3} \\ \)
At x = 0, f"(x) = y"(x) < 0, and
points of inflation are \(f''(x) = \frac{ - 4x² }{3}( x² - 25)^{-5/2} + \frac{2}{3}( x² - 25)^{-1/3} = 0\\ \)
\( \frac{2}{3}( x² - 25)^{-1/3} = 0 \)
so, x = ±5. Hence, the required sketch present in above figure.
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Complete question:
The above figure complete question.
use the guidelines of this section to sketch the curve. y = ³√x² − 25.
William used 15 cm of tape to wrap 3 presents. Find the length of tape to wrap for 1 present?
Answer:
The length of tape to wrap = 5 cm
Step-by-step explanation:
Let the length of tape used to wrap 1 present be = x
Tape length Number of presents
15 cm 3
x 1
\(\frac{15}{x} = \frac{3}{1} \\\\x \times 3 = 1 \times 15\\\\x = \frac{15}{3} = 5 \ cm\)
Use the Root Test to determine whether the series convergent or divergent. [infinity] n2 + 2 7n2 + 5 n n = 1 Identify an. Evaluate the following limit. lim n → [infinity] n |an| Since lim n → [infinity] n |an| ? 1, ---Select--- .
By using the Root Test on the series "∑n" , we found that the series is Divergent and diverges to infinity .
The Root Test states that, if the limit of nth root of the absolute value of the nth term of a series is less than 1, then the series converges. and
If the limit is greater than or equal to 1, the test is inconclusive.
In the series ∑n , the nth term of the series is "n" ,
So, the nth root of the absolute value of nth term is the nth root of |n|, which is = n^(1/n).
we see that as n approaches infinity, the nth root : n^(1/n) approaches 1, So, the limit of the nth root of the absolute value of the nth term is equal to 1. Which means that the Root Test is inconclusive for this series.
Therefore , the series ∑n diverges, it is a known series called as Harmonic series, which diverges to infinity.
The given question is incomplete , the complete question is
Use the Root Test to determine whether the series convergent or divergent. ∑n , where n is from 1 to infinity .
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A plane flew at a constant speed between Boston and Philadelphia. An equation relating the distance traveled in miles, d, to the number of hours flying, t, is d=350t. How long will it take the airplane to travel 280 miles?
The time it take for the plane to travel at 280 miles is 0.8 hours.
How to find the time it will take the plane to cover a distance?The plane flew at a constant speed between Boston and Philadelphia.
An equation relating the distance travelled in miles, d, to the number of hours flying, t, is d = 350t.
Therefore,
d = 350t
where
t = time travelledd = distanceTherefore, let's find the time it will take to travel for 280 miles
d = 350t
d = 350 × t
280 = 350t
divide both sides by 350
t = 280 / 350
t = 0.8 hours
Therefore,
the time it will take to travel = 0.8 hours
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this was from yesterday and i need to finish it so help me plz
Answer:
3/4
Step-by-step explanation:
since they already have a common denominator you'd add the numerators and keep the denominator. you'd get 6/8. Then you'd divide both the numerator and denominator by 2. 3/4 is your final answer.
If you have a choice of borrowing money at 8% compounded semi-annually or borrowing at 8.15% compounded annually, which should you choose and why? Please go into detail
one simple way to take a peek at this is by looking at the APY value, namely the Annual Percent Yield for each of the choices, and use the one that gives you the higher APY, higher APY, higher bucks.
\(~~~~~~ \textit{Annual Percent Yield Formula} \\\\ ~~~~~~~~~~~~ \left(1+\frac{r}{n}\right)^{n}-1 \\\\ \textit{for the 8\%} \begin{cases} r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semi-annually, thus twice} \end{array}\dotfill &2 \end{cases} \\\\\\ \left(1+\frac{0.08}{2}\right)^{2}-1\implies (1.04)^2-1\implies 0.0816~\hfill 8.16\%\)
\(\textit{for the 8.15\%} \begin{cases} r=rate\to 8.15\%\to \frac{8.15}{100}\dotfill &0.0815\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1 \end{cases} \\\\\\ \left(1+\frac{0.0815}{1}\right)^{1}-1\implies (1.0815)-1\implies 0.0815~\hfill 8.15\%\)
well, clearly the first one has a higher APY, so you'd want that one.
2x-1+9x+3=57 solve for X
Answer:
x = 5
Step-by-step explanation:
2x-1+9x+3=57
2x+9x=57+1-3
11x=55
x= 55/11
x= 5
Answer:
x = 5
Step-by-step explanation:
Simplifying 2x + -1 + 9x + 3 = 57
Reorder the terms: -1 + 3 + 2x + 9x = 57
Combine like terms: -1 + 3 = 2 2 + 2x + 9x = 57
Combine like terms: 2x + 9x = 11x 2 + 11x = 57
Solving 2 + 11x = 57
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2' to each side of the equation. 2 + -2 + 11x = 57 + -2
Combine like terms: 2 + -2 = 0 0 + 11x = 57 + -2 11x = 57 + -2
Combine like terms: 57 + -2 = 55 11x = 55
Divide each side by '11'. x = 5
Simplifying x = 5
♡ hope it helps♡
the smith family has $4$ cats and $3$ dogs. in how many ways can these $7$ pets be placed in a row of $7$ chairs such that at least $2$ cats are next to each other?
There are 4896 ways of arranging 7 pets in a row of 7 chairs such that at least 2 cats are next to each other.
Arrangement of entities can be done using permutation and combination in mathematics.
Consider the distributions where 2 cats are not next to each other as
C D C D C D C.
There are 4! ways to seat the cats, and 3! ways to seat the dogs that gets us N=4! 3! = 144
There are a total of 7!=5040 possible ways to seat both cats and dogs.
At least 2 cats seat together= All possible arrangements- None of the cat seat together.
Thus the number of seatings where at least 2 cats are adjacent is
5040-144 = 4896
So, there are 4896 arrangements can be made so that at least 2 of the cats seat together.
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67 - (42.6+5)
What’s the answer to this equation
Answer:
19.4
Step-by-step explanation:
67-(42.6+5)
67-(47.6)
67-47.6
19.4
(Also it is an expression. An equation has a solution. :)
Select the correct answer from each drop down menu. In the figure, AB=__inches and AC=___
10" inches
Answer: In the figure AB is about 8.4 inches and AC is about 13.05 inches.
Step-by-step explanation: We can use cosine to find the hypotenuse. \(cos(40)=\frac{10}{x} \\cos(40) (x)=\frac{10}{x}(x)\\cos(40) (x) =10\\\frac{cos(40) (x)}{cos (40)} =\frac{10}{cos (40)} \\x=\frac{10}{cos(40)}\)
Using a calculator x is about 13.05
Using tangent we can find the length opposite of <C
\(tan(40)=\frac{x}{10} \\tan(40) (10)=\frac{x}{10}(10)\\tan(40) (10) = x\)
Using a calculator x would be about 8.4
Answer:
Step-by-step explanation:
find the value of e(|z|), where z is a standard normal variable.
To find the value of e(|z|), where z is a standard normal variable, we first need to determine the probability density function of |z|.
Let Y = |Z|, where Z is a standard normal variable. Then:
P(Y ≤ y) = P(|Z| ≤ y) = P(-y ≤ Z ≤ y) = Φ(y) - Φ(-y)
where Φ is the cumulative distribution function of the standard normal distribution.
The probability density function of Y can be obtained by differentiating the cumulative distribution function:
f_Y(y) = d/dy (Φ(y) - Φ(-y))
= φ(y) + φ(-y)
= 2φ(y)
where φ is the probability density function of the standard normal distribution.
Therefore, the expected value of |Z| is given by:
E(|Z|) = ∫₀^∞ y f_Y(y) dy
= 2 ∫₀^∞ y φ(y) dy
= 2 ∫₀^∞ (1/√(2π)) y e^(-y²/2) dy (using the standard normal density function)
This integral can be evaluated using integration by substitution, with u = y²/2 and du/dy = y. Thus:
E(|Z|) = 2 ∫₀^∞ (1/√(2π)) e^(-u) du
= 2/√(2π) * [ -e^(-u) ]_0^∞
= 2/√(2π)
= √(2/π)
Therefore, e(|z|) = √(2/π) ≈ 0.7979.
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If you roll a die two times, what is the probability that the sum will be more than 9? Show your work.
Answer:
1/6
Step-by-step explanation:
Total sum if the first roll is 1:
1 + 1 = 2
1 + 2 = 3
1 + 3 = 4
1 + 4 = 5
1 + 5 = 6
1 + 6 = 7
Total sum if the first roll is 2:
2 + 1 = 3
2 + 2 = 4
2 + 3 = 5
2 + 4 = 6
2 + 5 = 7
2 + 6 = 8
Total sum if the first roll is 3:
3 + 1 = 4
3 + 2 = 5
3 + 3 = 6
3 + 4 = 7
3 + 5 = 8
3 + 6 = 9
Total sum if the first roll if 4:
4 + 1 = 5
4 + 2 = 6
4 + 3 = 7
4 + 4 = 8
4 + 5 = 9
4 + 6 = 10
Total sum if the first roll is 5:
5 + 1 = 6
5 + 2 = 7
5 + 3 = 8
5 + 4 = 9
5 + 5 = 10
5 + 6 = 11
Total sum if the first roll is 6:
6 + 1 = 7
6 + 2 = 8
6 + 3 = 9
6 + 4 = 10
6 + 5 = 11
6 + 6 = 12
If we look at all the possible rolls we get from two dice, we see that there are 36 different possibilities. Out of all of these, only 6 rolls produce a total greater than 9. [Note: I did not include the possibility of rolling a 9 or greater, but the possibility of rolling greater than 9.] So, the possibility of rolling two dice and getting a sum greater than 9 is 6/36, or 1/6.
If this answer helped you, please leave a thanks!
Have a GREAT day!!!
a roulette wheel has the numbers 1 through 36, 0, and 00. a bet on three numbers pays 11 to 1 (that is, if you bet $1 and one of the three numbers you bet comes up, you get back your $1 plus another $11). how much do you expect to win with a $1 bet on three numbers? hint [see example 4.] (round your answer to the nearest cent.)
With a $1 bet on three numbers, you can expect to win $12.33. So, the expected winnings for a $1 bet on three numbers in a roulette wheel is approximately $0.95.
Here's how to calculate it:
- There are 38 possible outcomes on the roulette wheel (1 through 36, 0, and 00).
- Your bet covers 3 of those outcomes, so your probability of winning is 3/38.
- The payout for a winning bet is $1 plus another $11, for a total of $12.
- To find your expected winnings, multiply the probability of winning by the payout:
(3/38) x $12 = $0.947
- Rounded to the nearest cent, that's $0.95.
So with a $1 bet on three numbers, you can expect to win about $0.95 each time, on average. Over many bets, your total winnings will approach $12.33.
In order to calculate the expected winnings from a $1 bet on three numbers in a roulette wheel, we can follow these steps:
1. Determine the probability of winning the bet. In a roulette wheel with 38 numbers (1-36, 0, and 00), you bet on three numbers, so the probability of winning is 3/38.
2. Determine the amount you would win if your bet is successful. Since the bet pays 11 to 1, you would get back your original $1 plus another $11, for a total of $12.
3. Multiply the probability of winning by the amount you would win. This will give you the expected winnings for a single $1 bet:
(3/38) * $12 = $0.947
So, the expected winnings for a $1 bet on three numbers in a roulette wheel is approximately $0.95 (rounded to the nearest cent).
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Which of the following represents the diameter of the circle below?
Divide: (3x³+4x+11)/(x²-3x+2)
In attachment I have answered this problem.
Solve each system of inequalities\(\left \{ {3x-10\ \textgreater \ 0} \atop {2x\ \textgreater \ 0}} \right.\)
The solution to the system of inequalities is:
x > 10/3 and x > 0
What is inequality?
In mathematics, an inequality is a statement that shows the relationship between two values, expressions or quantities using inequality symbols such as <, >, ≤, or ≥. Inequalities convey that one value is not the same as the other, but rather is either greater than or less than the other value.
The system of inequalities is:
3x-10 > 0
2x > 0
To solve this system, we need to find the values of x that satisfy both inequalities at the same time.
From the first inequality, we can isolate x by adding 10 to both sides:
3x - 10 + 10 > 0 + 10
3x > 10
Then, we can divide both sides by 3:
x > 10/3
So we know that x is greater than 10/3.
From the second inequality, we know that x must be greater than 0.
Therefore, the solution to the system of inequalities is:
x > 10/3 and x > 0
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A farmer has 1080 eggs if each tray carries 30 eggs , how many trays will he have ?
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Answer:
He will have 36 trays full of eggs.
Step-by-step explanation:
To find out how many trays he will have, we have to divide 1080 (the number of eggs), by the number of trays that carry 30 eggs.
1080/30 = 36
Answer:
Step-by-step explanation:
Divide 1080 by 30
1080/30 = 36 trays
Please help ASAP!!
see attachment below!
637.892 to the nearest tenth.
Answer:
637.9
Step-by-step explanation: