Suppose a rubber ball collides head-on with a more massive steel ball traveling in the opposite direction with equal speed. Which ball, if either, receives the larger impulse? Match the words in the left column to the appropriate blanks in the sentences on the right

Answers

Answer 1

In this head-on collision between a rubber ball and a more massive steel ball traveling in opposite directions with equal speed, both balls receive the same impulse. This is because the impulse experienced by each object is equal and opposite, as described by Newton's third law of motion.

.Suppose a rubber ball collides head-on with a more massive steel ball traveling in the opposite direction with equal speed. Which ball, if either, receives the larger impulse? The more massive steel ball traveling in the opposite direction with equal speed will receive a larger impulse.

What is impulse?

Impulse can be defined as the change in momentum. Mathematically, the impulse is equal to the force multiplied by the time over which it acts or: J = F ΔtImpulse has both direction and magnitude. Therefore, it's a vector quantity. The unit of impulse is the Newton-second (Ns) or kilogram-meter per second (kgm/s).

What is momentum?

Momentum is the product of an object's mass and velocity. It can also be defined as the quantity of motion that an object has. Mathematically, momentum (p) = mass (m) x velocity (v)Therefore, impulse can be defined as the change in momentum over a period of time.

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Related Questions

On the moon, the acceleration of gravity is 1.6 m/s2. If an object has a
mass on Earth of 5.1 kg, what is its mass on the moon?

Answers

Answer:

5.1 kg

Explanation:

Its mass on the moon is 5.1 kg because mass is an intrinsic property of a material and does not change with location. Although, its weight might vary because its acceleration of gravity g is dependent on the mass M and radius r of the planet(in this case, moon) involved g = GM/r². Since weight W = mg is dependent o g, weight varies but mass remains constant.

In which direction of the wave motion do longitudinal waves transfer energy?
A-perpendicular
B- parallel
C- close
D-equal

Answers

Answer:

B, Parallel.

Explanation:

Mark as brainliest pls!

The wave motion does longitudinal waves transfer energy in the direction Parallel to the wave motion. Hence, option B is correct.

What is a Wave?

Waves are disturbances that move regularly and orderly from one location to another. Although sound, lighting, and the movement of elementary particles all have wave-like characteristics, surface waves that move on water are the most well-known.

The disturbance periodically oscillates with a set frequency and wavelength in the simplest waves (see periodic motion). In contrast to electromagnetic waves, which do not require a medium to travel and may move through a vacuum, mechanical waves, like sound, need a medium to go through. A medium's characteristics determine how a wave will travel across it. Seismic wave is also seen.

Therefore, option B is correct.

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37.9kg skydiver leaps out of plane what is force that skydiver pull up on earth with

Answers

The force that the skydiver pull up on the earth with a mass of 37.9 kg is 371.42 N.

What is force?

Force can be defined as the product of mass and acceleration.

The force that the skydiver pull up on the earth with is the same as its weight. To calculate the weight of the skydiver, we use the formula below.

Formula:

W = mg........ Equation 1

Where:

W = Weight of the skydiverm = Mass of the skydiverg = Acceleration due to gravity

From the question,

Given:

m = 37.9 kgg = 9.8 m/s²

Substitute these values into equation 1

W = 37.9×9.8W = 371.42 N.

Hence, the force that the skydiver pull up on the earth is 371.42 N.

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Order these space notes in the bass clef from highest space to lowest space?

1) E
2)C
3)A
4)G

Answers

Aware is 3(A) I hope this helps

Answer:

g e c a

Explanation:

Hope I helped!

10(x-5)=80I understand what im doing but I am stuck

Answers

\(10(x-5)=80\)

Expand the left hand side using distributive property:

\(10x-50=80\)

Add 50 to both sides:

\(\begin{gathered} 10x-50+50=80+50 \\ 10x=130 \end{gathered}\)

Divide both sides by 10:

\(\begin{gathered} x=\frac{130}{10} \\ x=13 \end{gathered}\)

Answer:

x = 13

Please help me. I will do what I can to get you points.

Please help me. I will do what I can to get you points.

Answers

Answer:

the last one

Explanation:

its the sun when the earth turns towards the sun it gives us heat not solar radiation.

The main reason a person weighs less at the equator than at the poles involves theA) spin of the Earth.B) influence of the Sun, Moon, and all the planets.C) law of action and reaction

Answers

The main reason a person weighs less at the equator than at the poles is due to the Earth's rotation, which causes a centrifugal force at the equator due to law of planet motion.

This centrifugal force is caused by the Earth's rotation around its axis, which is faster at the equator than at the poles. As a result, objects at the equator are moving faster and experience a weaker gravitational pull towards the Earth's center compared to objects at the poles due to law of planet motion.

The difference in gravitational force between the equator and the poles is relatively small, around 0.5%, but it is still measurable. The gravitational force at the poles is stronger because the Earth's rotation is slower there, so there is less centrifugal force pushing objects away from the Earth's center.

The influence of the Sun, Moon, and planets on a person's weight is much smaller than the effect of the Earth's rotation. These celestial bodies do have an effect on the Earth's gravitational field, but their impact is relatively minor compared to the Earth's rotation.

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When measuring the battery base voltage with a voltmeter, the vehicle engine should be _____ and all the accessories should be turned _____.
fast idling; on
running; on
off; off
running; off

Answers

When measuring the battery base voltage with a voltmeter, the vehicle engine should be running and all the accessories should be turned off and potential difference.

Thus, The term "voltmeter" refers to the instrument used to measure the electric potential difference between two locations in an electric circuit. It is connected at the same time.

Analogue voltmeters, which move a pointer around a scale in proportion to the voltage sensed, can be made using a galvanometer and a series resistor. Meters that use amplifiers can measure microvolts or less. An analog-to-digital converter is used by digital voltmeters to display voltage as a numerical value.

A wide range of designs are available for voltmeters, some of which are powered independently (by a battery, for instance) and others of which are powered directly by the source of the voltage that is being measured.

Thus, When measuring the battery base voltage with a voltmeter, the vehicle engine should be running and all the accessories should be turned off and potential difference.

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cepheid variables are located in two different galaxies, a and b. both stars have the same average apparent magnitude. the star in galaxy a has a bright-dim-bright period of 10 days. the star in galaxy b has a bright-dim-bright period of 30 days. which of the two galaxies is at a greater distance?

Answers

Galaxy B is at a greater distance.

When cepheid variables are located in two different galaxies, A and B, both stars have the same average apparent magnitude. The star in the galaxy A has a bright-dim-bright period of 10 days. The star in galaxy B has a bright-dim-bright period of 30 days, hence galaxy B is at a greater distance compared to galaxy A.

Cepheid variable, one of a class of variable stars whose periods (i.e., the time for one cycle) of variation are closely related to their luminosity and that are therefore useful in measuring interstellar and intergalactic distances.

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How much work is required to move an electron

through a potential difference of 3.00 volts?

(1) 5.33 × 10^–20 J (3) 3.00 J

(2) 4.80 × 10^–19 J (4) 1.88 × 10^19 J

Answers

Answer:

(2) the work required to move the electron is 4.8 x 10⁻¹⁹ J.

Explanation:

Given;

potential difference, V = 3.00 volts

charge of electron, q = 1.6 x 10⁻¹⁹ C

The work required to move an electron is calculated as;

W = Vq

where;

W is the work done in Joules

Substitute the given values and solve for W;

W = (3.00)(1.6 x 10⁻¹⁹)

W = 4.8 x 10⁻¹⁹ J.

Therefore, the work required to move the electron is 4.8 x 10⁻¹⁹ J.

How much work is done to move a 1,000 N car 20 meters?

Answers

Answer:

The answer is 20,000 J

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question

force = 1,000 N

distance = 20 m

We have

workdone = 1000 × 20

We have the final answer as

20,000 J

Hope this helps you

Consider an airplane flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. Calculate the pressure at this point. Assume incompressible flow. Given: p _1 =7.01×10^4 N/m^2 and rho=0.909kg/m^3 . The pressure at a point on the wing is ×10 ^4 N/m^2

Answers

An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The  pressure at the point on the wing is  \(P = 6.96 * 10^4 N/m^2\).

To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.

The equation is as follows:

P + 1/2 * ρ * \(V^2\) = constant

where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.

Given:

\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)

ρ = \(0.909 kg/m^3\) (density of the fluid)

\(V_1 = 42 m/s\) (velocity of the airplane)

\(V_2 = 88 m/s\) (velocity at the point on the wing)

To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:

\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\)  * ρ * \(V_2^2\)

Substituting the given values:

\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)

Simplifying the equation:

\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)

7.01 × 10^4 + 804.906 = P + 3526.242

\(P + 4329.148 = 7.01 *10^4\)

\(P = 7.01 * 10^4 - 4329.148\)

\(P = 6.96 * 10^4 N/m^2\)

Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)

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A toroidal solenoid of square cross-section is made with inner and outer radii of 3.0 and 4.0 cm. How many turns of wire are necessary to obtain a self-inductance of 1.15 H

Answers

To find the number of turns of wire necessary to obtain a self-inductance of 1.15 H for a toroidal solenoid of square cross-section with inner and outer radii of 3.0 and 4.0 cm, we can use the formula for the self-inductance of a toroidal solenoid:

L = μ₀N²πr² / (2πr + πd)

where L is the self-inductance, N is the number of turns of wire, r is the mean radius (the average of the inner and outer radii), d is the cross-sectional diameter (in this case, equal to the side length of the square cross-section), and μ₀ is the permeability of free space (4π x 10^-7 H/m).

Plugging in the given values, we get:

1.15 = (4π x 10^-7)(N²π(0.035+0.04)²) / (2π(0.04) + π(0.01))

Simplifying, we get:

1.15 = 1.053 x 10^-6 N²

Solving for N, we get:

N = √(1.15 / 1.053 x 10^-6) ≈ 1093 turns

Therefore, approximately 1093 turns of wire are necessary to obtain a self-inductance of 1.15 H for the given toroidal solenoid.
To find the number of turns of wire necessary for a toroidal solenoid with a square cross-section, inner radius of 3.0 cm, outer radius of 4.0 cm, and a self-inductance of 1.15 H, we can use the formula for the self-inductance of a toroidal solenoid:

L = (μ₀ * N² * A * h) / (2 * π * R)

where:
L = self-inductance (1.15 H)
μ₀ = permeability of free space (4π × 10⁻⁷ H/m)
N = number of turns of wire (unknown)
A = cross-sectional area of the solenoid (square cross-section)
h = height of the solenoid (which is the difference between the outer and inner radii, 4.0 cm - 3.0 cm = 1.0 cm)
R = average radius of the solenoid (which is the average of the inner and outer radii, (3.0 cm + 4.0 cm) / 2 = 3.5 cm)

First, convert the measurements from cm to meters:
h = 1.0 cm * 0.01 m/cm = 0.01 m
R = 3.5 cm * 0.01 m/cm = 0.035 m

Rearrange the formula to solve for N:

N = sqrt((2 * π * R * L) / (μ₀ * A * h))

Since A is not provided, you will need the value of the square cross-sectional area to calculate the exact number of turns (N). Once you have that value, plug it into the formula, and solve for N.

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1. What are the effects of weather and climate on the picture?



2. What are 3 potential solutions to the problem in the picture?



3. How could a scientist model the problem and test different solutions to find the most effective fix?

1. What are the effects of weather and climate on the picture?2. What are 3 potential solutions to the

Answers

The effect of weather and climate on the picture is erosion. The 3 potential solutions to the erosion are Planting of a cover crop, Build Terraces, and Create diversions to Help Drainage.

What is erosion?

Erosion is defined as the washing away of the topmost portion of the soil which can occur due to natural causes or through the activities of man.

The natural causes of erosion is related to changes in weather and climate through rain, rivers, floods, lakes, and the ocean.

The three potential solutions to the problem of erosion include the following:

Planting of a cover crop: This helps in the prevention of erosion because the cover crops have root systems with different depths which helps the soil to absorb more water and hold the soil surface

Building of Terraces: This helps to prevent erosion by dividing slopes so that surface runoff is intercepted and carried to a protective outlet.

Creation of diversions to help drainage.

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Question 18 of 20 Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of planet B. Which statement correctly explains the weight you would experience on each planet? A. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same. B. You would weigh the same on both planets because your mass would adjust depending on the planet's speed. C. You would weigh less on planet B because it is traveling twice as fast as planet A. O D. You would weigh more on planet B because it is traveling twice as fast as planet A. ​

Answers

Answer:A, you would weigh the same on both planets because their masses and the distance to their centers of gravity are the same

Explanation:

Answer this question using the wave interference graph

Answer this question using the wave interference graph

Answers

The wavelength of the wave 1 is 8 unit. wavelength is nothing but distance of the wave to complete one cycle. or wavelength is the distance between two points which are in same phase.

A fundamental idea in physics, wavelength is an important characteristic of waves. It describes the separation between two parallel, in-phase points, such as two crests or two troughs.

The qualities of a wave, such as its frequency and energy, are determined by its wavelength. While in certain forms of waves, like sound waves, wavelength affects pitch and tone, with electromagnetic waves, various wavelengths correlate to different colors in the visible spectrum.

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Determine the direction and magnitude of the electric field at the point P. The charges are separated by a distance 2a, and point P is a distance x from the midpoint between the two charges.

Answers

The direction of the electric field at point P is to the left which is. The answer is\(qx-2ax\)

To determine the electric field at point P, we can use Coulomb's law, which states that the electric field at a point in space due to a point charge is given by:

\(E = k*q/r^2\)

where E is the electric field, k is Coulomb's constant, q is the charge of the point charge, and r is the distance between the point charge and the point where we want to find the electric field.

In this case, we have two point charges with charge +q and -q, separated by a distance 2a, as shown below:

      +q        -q

--------|--------|--------

  a     x        a

The midpoint between the two charges is at a distance a from each charge, so the distance from each charge to point P is given by:

\(r1 = sqrt(x^2 + a^2)r2 = sqrt(x^2 + a^2)\)

Using Coulomb's law, we can find the electric field due to each charge at point P:

\(E1 = kq/r1^2E2 = k(-q)/r2^2 = -k*q/r2^2\)

The electric field at point P due to the two charges is the vector sum of the electric fields due to each charge:

E = E1 + E2

The direction of the electric field at point P is determined by the signs of the charges. Since the positive charge is closer to point P, its electric field points towards the positive charge. The negative charge is farther away from point P, so its electric field points away from the negative charge. Therefore, the electric field at point P points to the left.

The magnitude of the electric field at point P is given by:

|E| = |E1 + E2| = |E1| + |E2|

Substituting the expressions for E1 and E2 and simplifying, we get:

\(|E| = kq(1/r1^2 - 1/r2^2)\)

Substituting the expressions for r1 and r2, we get:

\(|E| = kq(2*a^2 - x^2)/[(x^2 + a^2)^3/2]\)

Therefore, the direction of the electric field at point P is to the left and its magnitude is given by:

\(|E| = kq(2*a^2 - x^2)/[(x^2 + a^2)^3/2]\)

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reselasie3. An object of mass 900 kg is hanging from a ceilingby means of two strings. The first string (7₁) makes anangle of 40 degree with the horizontal-right. The second string(T₂) makes an angle of 20 degree with the horizontal-left.Calculate the tension in the first string (7₁) (2 point)A. O12034.001 NB. O14675.062 NC. 5790.32 ND. 09570.261 NE. 13316.872 N

reselasie3. An object of mass 900 kg is hanging from a ceilingby means of two strings. The first string

Answers

First, find the weight of the object.

W = m g = 900 x 9.8 = 8,820 N

T2x = -t2 cos 20

t1 x = t1cos 40

mgx= 0

T2y= t2 sin 20

t1y= t1 sin 40

mgy= - mg

X and y components of resultant (R)

Rx = t1x -t2x + mgx

Rx= -t2 cos 20 + t1cos 40 (3)

Ry = t2 sin 20 + t1 sin 40 - mg(2)

Rx, and Ry = 0

0 = -t2 cos 20 + t1cos 40 (3)

0= t2 sin 20 + t1 sin 40 - mg (4)

Solve (3)

0 = -t2 cos 20 + t1cos 40

t2 cos 20 = t1 cos 40

t2 = t1 cos40/cos20

t2 = 0.815 t1

Substitute t2 in 4

0 = t2 sin 20 + t1 sin 40 - mg

0 = (0.815 t1) sin 20 + t1 sin 40 - 8,820

0= t1 ( 0.815 sin 20 + sin 40 ) -8820

0 = 0.921 t1 -8820

8820 = .921 t1

t1 = 8820/0.921

t1= 9570.261N (option D)

reselasie3. An object of mass 900 kg is hanging from a ceilingby means of two strings. The first string

Twenty or so years ago, a cup of coffee was 8 fl. oz and contained about 45 kcal, today a standard mocha is 16 fl. oz and contains how many kcals?:

Answers

Answer:

16fl = 90 kacl because 8 fl double = 16 fl so 45 kcal = 90 kcal (double )

Un trozo de metal de 12 gr, tiene una densidad de 4 /^3 y esta sumergido por medio de una cuerda en una pileta de aceite de densidad 1,5 /^3, como muestra la figura . ¿Cuánto vale la tensión de esa cuerda?

Answers

Answer:

¢

Explanation:

Given that:

Mass of metal = 12g = 0.012

Density of metal = 4 g/cm³ = 4000kg/m³

Density of oil = 1.5g/cm³ = 1500 kg/m³

Recall : density = mass / volume

Volume of metal, V = mass / density = 0.012/ 4000 = 0.000003

0.000003

T + Density of oil * g * V - (0.012 * 9.8) = 0

T + 1500 * 9.8 * 0.000003 - 0.1176 = 0

T = 0.0441 - 0.1176 = 0

T = 0.1176 - 0.0441

T = 0.0735N

Tension, T

Jessica stretches her arms out 0.60 m from the center of her body while holding a 2.0 kg mass in each hand. She then spins around on an ice rink at 1.1 m/s.
a. What is the combined angular momentum of the masses?
b. If she pulls her arms into 0.15 m, what is her new linear speed?

I'm really confused ab the explanations behind this. help, please

Answers

Answer:

a.) L = 2.64 kgm^2/s

b.) V = 4.4 m/s

Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.

So,

Radius r = 0.6 m

Mass M = 2 kg

Velocity V = 1.1 m/s

Angular momentum L can be expressed as;

L = MVr

Substitute all the parameters into the formula

L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1

the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1

b. If she pulls her arms into 0.15 m,

New radius = 0.15 m

Using the same formula again

L = 2( MVr)

2.64 = 2( 2 × V × 0.15 )

1.32 = 0.3 V

V = 1.32/0.3

V = 4.4 m/s

Her new linear speed will be 4.4 m/s

a 110 volt wall outlet supplies power to a stereo with a resistance of 10 ohms. how much current is flowing through the stereo?​

Answers

Answer:

look in internet u can find online converter and there u will get a rel answer

Explanation:

IS IT right to the left a b c d

Answers

Answer:

c ok      

Explanation: right?

Answer:

16

Explanation:

Suppose that a particular artillery piece has a range of R=9240 yards. Find the range in miles

Answers

Answer:

5.25[mile]

Explanation:

We must remember that the yard is a measure of length of the imperial system and that a Mile is also a unit of length of that system.

Therefore we must use a conversion factor that relates the yard to the mile.

\(9240 [yard]*[\frac{0,000568182miles}{1yard} ]=5.25[miles]\)

what would happen if you used very large amplitudes? check your hypothesis by trial. what amplitude did you use? what is the result?

Answers

The amplitude of a wave is proportional to the amount of energy it carries. When the amplitude of a wave is increased, the energy carried by the wave also increases. This can result in several potential outcomes, depending on the specific wave system being considered.

In mechanical wave systems, such as a vibrating string or a loudspeaker, using very large amplitude can cause the system to become nonlinear, meaning that the wave behavior deviates from the expected linear relationship between the wave amplitude and energy. Nonlinearities can cause the wave to generate harmonics, which are higher frequency components in the wave spectrum. They can also cause the wave to become distorted, producing a sound that is different from the original waveform. In extreme cases, the system can become mechanically unstable and break or stop functioning altogether.

In electromagnetic wave systems, such as radio waves or light waves, very large amplitudes can cause similar nonlinear distortions. They can also cause unwanted interference with other signals in the system, as well as increase the risk of damage to the transmitting or receiving equipment.

It is important to use appropriate amplitudes for the specific wave system being considered, as excessive amplitudes can result in unwanted side effects and potentially cause damage to the system.

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The density of a particular kind of glass is 2.40 g/cm^3 what is the volume of a 34.82?

Answers

The volume occupied of  a particular kind of glass with a density of 2.40 g/cm^3l and a mass of  34.82 g is: 14.508 cm^3

The density formula and the procedure we will use is:

d = m/v

Where:

v= volumed= densitym= mass

Information about the problem:

d= 2.40 g/cm^3m = 34.82 gv = ?

Applying the density formula and clearing the volume we get:

d = m/v

v = m/ d

v = 34.82 g/2.40 g/cm^3

v = 14.508 cm^3

What is density?

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

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The density of a particular kind of glass is 2.40 g/cm^3 what is the volume of a 34.82?

Which one best represents the heat capacity of a system represented by identical quantum harmonic oscillators?

Answers

Even when we don't know its exact location, a classical particle has a specific position at a specific moment. For a quantum particle, this is no longer valid. The probability densities and energy eigenfunctions for the quantum oscillator go over the boundaries of the conventional turning points.

The analog of the classical harmonic oscillator in quantum mechanics is called the quantum harmonic oscillator. One of the most crucial model systems in quantum mechanics is the arbitrary smooth potential, which is one of the most common ways that a smooth potential can be represented as a harmonic potential at a stable equilibrium point. It is referred to as "harmonic" because the solution of Newton's second law, a second-order differential equation that governs the motion of the item, is a series of sines and cosines of time with a specific frequency, exactly like the outcome.

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an object is subject to two forces that do not point in opposite directions. is it possible to choose their magnitudes so that the object is in equilibrium? explain.

Answers

No, it is not possible to choose the magnitudes of two forces subjected to the object that do not point in the opposite direction so that the object is in equilibrium.

To counteract each other, the two forces that are operating on it must be acting in the opposing direction. Equilibrium is defined as the condition in which the sum of forces/actions acting on the body is zero. It is a state in which a body experiences no energy transfers. Different types of forces (external and internal most commonly gravity and inter-atomic forces) are experienced by objects.    

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Liquid pools of methane are found on the surface of Titan, one of Saturn's moons. The temperature on the surface of Titan is -180°C. What is this value on the Fahrenheit scale?

Answers

Answer:

-292 degrees F

Explanation:

C = 5/9( F -32)

-180 = 5/9 (F-32)

F =  -292 degrees

someone plss asnwer i need help amswer only if u know it​

someone plss asnwer i need help amswer only if u know it

Answers

Answer:

going backwards message me if u have any problems

Answer:

slowing down

Explanation:

the opposite of positive is negative right?

so negative acceleration is deceleration

hope i helped!

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