The antenna of the microwave oven emits approximately 5.008 x 10²⁶ photons per second.
How we determine photons per second?To determine the number of photons emitted per second by the microwave oven's antenna, you'll first need to find the energy of a single photon at the given frequency, and then use that information to find how many photons are emitted per second.
Convert the frequency to hertz: 2560 MHz = 2.56 x 10⁹ Hz
So, the antenna of the microwave oven emits approximately 5.008 x 10²⁶ photons per second.
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14.a box of mass 40kg has a base of area 10m2 .calculate the pressure exerted by it on the ground (use 1kg-f=10n).
The pressure exerted by a box on the ground can be calculated by dividing the force exerted by the box on the ground by the area of the base of the box.
The force exerted by the box can be calculated using Newton's second law, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). In this case, the mass of the box is given as 40 kg. Since the box is at rest on the ground, the acceleration is 0. Therefore, the force exerted by the box is 0 N.
To calculate pressure, we need to convert the force from newtons to kilogram-force. Since 1 kg-f = 10 N, the force can be expressed as 0 N / 10 = 0 kg-f.
The pressure exerted by the box on the ground is calculated by dividing the force by the area of the base of the box. The area is given as 10 m^2. Therefore, the pressure exerted by the box on the ground is 0 kg-f / 10 m^2 = 0 kg-f/m^2.
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What is the full path to the directory that contains data files that change constantly, including email, print jobs, and proxy cache files?
/var is the full path to the directory that contains data files that change constantly, including email, print jobs, and proxy cache files.
The full set of information required to find a file or folder, beginning with the root element and concluding with all further subdirectories, is referred to as an absolute path. Websites and operating systems both employ absolute paths to find files and folders. An absolute path may also be referred to as a full path or an absolute pathname.
A full pathname, also known as a "absolute pathname," originates at the root directory and travels via a specific order of directories to reach a specific directory or file. A full pathname's leading character is always an underscore (/), since it always begins at the file system's root (slash).
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how did the ptolemaic model explain the apparent retrograde motion of the planets? the planets resided on giant spheres that sometimes turned clockwise and sometimes turned counterclockwise. the planets resided on giant spheres that sometimes turned clockwise and sometimes turned counterclockwise. the planets sometimes stopped moving and then reversed to move backward along their circular orbits. the planets sometimes stopped moving and then reversed to move backward along their circular orbits. the model showed that apparent retrograde motion occurs as earth passes by another planet inits orbit of the sun. the model showed that apparent retrograde motion occurs as earth passes by another planet inits orbit of the sun. the planets moved along small circles that moved on larger circles around earth.
Some planetary phenomena defied explanation by Aristotle's universe model. Retrograde motion was the most obvious of these. Each planet appears to move in reverse at times when it is in retrograde motion, slowing down briefly before picking up speed again. As they move through the sky, planets also get brighter or dimmer. Neither phenomenon could be adequately explained by Aristotle's model.
What is Aristotle's model ?
The celestial and the terrestrial were Aristotle's two divisions of the cosmos. The Earth, Moon, and the region between them, known as the sub lunar region, were all considered to be parts of the terrestrial realm. The terrestrial world was characterized by change and flaws.
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What is units and dimensions? what are dimensions less quantities?
Answer:
A dimension is a measure of a physical variable.
Unit is a way to assign a number or measurement to that dimension.
In dimensional analysis, a dimensionless quantity is a quantity to which no physical dimension is assigned, also known as a bare, pure, or scalar quantity or a quantity of dimension one, with a corresponding unit of measurement is the SI of the unit one, which is not explicity shown.
Suppose a man is sitting on a chair and exerting 100 N of force downward, while a spring beneath the chair exerts 150 N of force upward. If you assign a negative value to the downward force, what is the net force of this system?
A man is sitting on a chair and exerting 100 N of force downward, while a spring beneath the chair exerts 150 N of force upward. The net force acting on the system is in the upward direction with a magnitude of 50N.
Force is the product of mass and acceleration which is dependent on the rate of change of momentum.
According to the given question,
Magnitude of force in the downward direction = 100N
Downward force = 100N
Magnitude of force in the upward direction = 150N
Upward force = -150N
Net force on the system = Upward force + Downward force
Net force on the system = -150N + 100N
Net force on the system = -50N
Hence, the net force acting on the system is in the upward direction with a magnitude of 50N.
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Answer:
(Question) Which of the following best describes the sum of all forces acting on an object?
(Answer) net force, which is a vector sum
(Question) Suppose a man is sitting on a chair and exerting 100 N of force downward, while a spring beneath the chair exerts 150 N of force upward. If you assign a negative value to the downward force, what is the net force of this system?
(Answer) 50 N
(Question) During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?
(Answer) 20 N
(Question) Recall that the formula for momentum is: P=mv Which of the following correctly shows momentum being calculated?
(Answer) 45 kg*m/s=(9 kg) (5 m/s)
(Question) A hockey puck with a mass of 0.12 kg is traveling across the ice at a velocity of 150 m/s downfield. What is the momentum of the hockey puck?
(Answer) P=18 kg*m/s
Explanation:
I just finished the quick check UwU
The effect of gravity on a falling object can be modeled by a ball dropped
from different heights. What is a limitation of this model?
O A. Not all objects bounce, even though balls do.
B. Friction with air also affects the fall of the object.
C. Some balls float in water, while others sink.
O
D. The ball can be dropped from varying heights.
Answer:
B. Friction with air also affects the fall of the object.
Explanation:
The limitation of this experimental design is that friction with air also affects the fall of the object.
Therefore, it is difficult to measure effect of gravity on falling objects. Air resistance cause friction in the movement of an object falling. Frictional force resists the motion of an object subject to free fall.Therefore, the experiment will be biased due to the influence of the frictional force.
Simple Pendulum Shows Uniform or Non uniform Motion. Explain?
The speed of the bob in a simple pendulum changes every time from A to B. So, its motion can't be a uniform motion. Therefore, the motion of the bob in a simple pendulum is a non-uniform motion.
A simple pendulum is a weight (or bob) suspended from a string or rod, which is free to swing back and forth under the influence of gravity. It is an idealized model used to study the behavior of more complex pendulum systems and has been studied extensively in physics due to its simplicity and ubiquity in everyday life.
The motion of a simple pendulum can be described by a number of variables, including the length of the string, the mass of the bob, the angle at which the pendulum is released, and the amplitude and period of the pendulum's oscillations.
In the absence of friction, the motion of a simple pendulum is governed by the laws of conservation of energy and conservation of momentum.
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do rays traveling parallel to the axis of a concave mirror pass through the center of the curvature of the mirror after they are refelcted? explain
No, rays traveling parallel to the axis of a concave mirror do not pass through the center of curvature after they are reflected.
When parallel rays of light fall on a concave mirror, they are reflected and converge at a point called the focal point. The focal point is located on the principal axis, which is the line passing through the center of curvature and the midpoint of the mirror.
However, rays that pass through the center of curvature before reflection will reflect back upon themselves and pass through the center of curvature again after reflection. In other words, the rays that pass through the center of curvature are reflected back along their original path.
Rays that are not parallel to the principal axis will reflect and converge or diverge at different points depending on their angle of incidence and the position of the object relative to the mirror. The image formed by a concave mirror is a virtual or real image depending on the position of the object relative to the mirror and the distance of the image from the mirror.
In summary, parallel rays of light do not pass through the center of curvature of a concave mirror after reflection. Instead, they converge at a point called the focal point, which is located on the principal axis.
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No, rays traveling parallel to the axis of a concave mirror do not pass through the center of curvature of the mirror after they are reflected.
When a ray of light travels parallel to the axis of a concave mirror and strikes the mirror surface, it is reflected back towards the focal point of the mirror. This is known as the focal property of the concave mirror. The focal point lies on the principal axis, halfway between the vertex (center) of the mirror and the center of curvature.
However, the center of curvature is the point on the axis that is equidistant from every point on the surface of the mirror. Therefore, rays parallel to the axis will not necessarily pass through the center of curvature after they are reflected. In fact, rays passing through the center of curvature will be reflected back onto themselves, creating an image at the same location as the object (a 1:1 magnification).
So, while the focal point and center of curvature are related properties of a concave mirror, they serve different functions in determining the path of light rays as they reflect off the mirror surface.
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the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly
Answer: Car 5
Explanation:
Higher speeds mean higher braking times so the car with the highest braking distance was travelling the the fastest and the car with the lowest braking distance was traveling the slowest.
Braking distance = Stopping distance - Thinking distance.
Car Braking distance
1 38
2 50 = 65 - 15
3 75
4 75
5 14 = 23 - 9
Car 5 had the lowest braking distance so was going the slowest.
6. an aluminum cube has sides of length 1.80 m. what is the resistance between two opposite faces of the cube?
the resistance between two opposite faces of the cube is 1.53×10−8Ω.
What do you mean by resistance between two opposiye faces of cube?Along the 'face' diagonal, between two vertices. = 3 R 4 is the equivalent resistance between two vertices along the face diagonal.
Resistance R is provided by:
R = ρl/A
Where r denotes resistivity, l the length parallel to which current flows, and A the area through which current flows
In this instance,
\(R = pl/(l^2) = p/l (\) (taking side of cube as l) (taking side of cube as l)
We know that by dividing the cube into 27 smaller cubes, the volume of the cubes eventually equals the initial volume of the cube.
(essentially, mass conservation, but density cancellation on both sides)
\(l^3 = 27a^3l^3 = 27a^3\) (a is the side of one tiny cube) (a is the side of one small cube)
a = l/3
As a result, resistance across two opposed faces of a tiny cube is as follows:
r = (a)/a2 =/a = 3/l = 3R
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Think about the sound waves and light waves that are transmitted when you use a computer, watch TV, or use your phone. How are these waves similar? How are they different?
Answer:
Light and sound waves are different in the sense that:
Light can travel without a medium, and is a physical particle
Sound is a vibration in a medium
Light can be altered by a different medium
Same with sound
Explanation:
There's no answer list, but here are some answers.
An object is 12.0 cm from a
concave mirror with f = 15.0 cm.
Find the image distance.
(Mind your minus signs.)
(Unit = cm)
To find the image distance formed by a concave mirror, we can use the mirror equation:
1/f = 1/di + 1/do
Where:
f is the focal length of the mirror,
di is the image distance,
and do is the object distance.
In this case, the object distance (do) is given as 12.0 cm, and the focal length (f) is given as 15.0 cm. We can rearrange the equation to solve for the image distance (di):
1/di = 1/f - 1/do
Substituting the given values:
1/di = 1/15 - 1/12
To simplify this expression, we need to find a common denominator:
1/di = (12 - 15)/(12 * 15)
1/di = -3/180
Now, we can invert both sides to find di:
di = 180/-3
di = -60 cm
Therefore, the image distance is -60 cm. The negative sign indicates that the image is formed on the same side as the object (in this case, it is a virtual image).
Answer:
60 cm
Explanation:
the U (obj. distance) = 12 as it is a concave mirror then u = -12cm
the f = -15cm
by mirror formula
1/v + 1/u = 1/f
by substituting values
1/v + (1/-12) = 1/-15
1/v = 1/-15 -(1/-12)
1/v = 1/-15 + 1/12
by taking L C M 60
1/v = -(4/60) + 5/60
1/v = 1/60
so V = 60 cm
a 3.89 ωω resistor, a 7.75 ωω resistor, and a 9.05 ωω resistor are connected in series with a 12.0 v battery. what is the equivalent resistance?
The equivalent resistance of the 3.89 Ω, 7.75 Ω, and 9.05 Ω resistors connected in series with a 12.0 V battery is 20.69 Ω.
The equivalent resistance of resistors connected in series is equal to the sum of the resistance of each resistor. Therefore, the equivalent resistance is: R = 3.89 Ω + 7.75 Ω + 9.05 Ω = 20.69 Ω
So, the equivalent resistance of the 3.89 Ω, 7.75 Ω, and 9.05 Ω resistors connected in series with a 12.0 V battery is 20.69 Ω.
The equivalent resistance of an electrical circuit refers to the single resistance that would have the same effect as the combination of multiple resistors in the circuit. It is a measure of the total opposition to current flow in the circuit. The equivalent resistance can be found by using various methods such as series, parallel, and combination circuits. The equivalent resistance of a circuit depends on the individual resistances, the connections between them, and the voltage and current in the circuit.
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A freely falling object is dropped from rest after falling for 4 seconds how far has it fallen (m) a.) 4 b.)10 c.) 20 d.) 40 e.) 80 ab.) 200
=======================================================
Explanation:
We'll use the free fall formula, which is,
y = 0.5*g*t^2
where
t = time in secondsg = acceleration of gravity (in m/s^2)y = vertical distance the object has fallen (in meters)In this case,
t = 4 secondsg = 10 m/s^2 approximatelyNote: The freefall assumes the object is not thrown down, and simply dropped (so initial velocity is 0).
So,
y = 0.5*g*t^2
y = 0.5*10*4^2
y = 0.5*10*16
y = 5*16
y = 80
The object has fallen about 80 meters. This value is approximate because g = 10 is approximate. Use g = 9.81 for a more accurate value (though even then this value of g isn't exact either). In this case, your teacher has opted to use g = 10.
Another reason why 80 meters is an approximate value is because we haven't accounted for air resistance. As the object falls through the air, the air particles push up and resist the movement of the falling object, and therefore slow it down. Think of a parachute. For entry level physics courses, you'll ignore air resistance as it greatly complicates the problem. Though it's handy to keep it in mind for later physics courses down the road.
On the way home from school, you notice the speedometer on the car is at 5,200 miles. When you get home, the speedometer reads 5,208 miles. With only this information what value could you calculate?
O Velocity
O Displacement
O Acceleration
O Distance
Answer:
O Distance
Explanation:
With the given information, it is possible to find the distance of the car has traveled on the home from school.
This is possible because distance is the length of path a body covers.
From the given values:
Distance = 5208 - 5200 = 8miles
It is not possible to find the displacement because no direction was given.
Also velocity is not possible since the time frame of travel was not state.
If the gravitational force of attraction between two bodies is16 units, what will be the force if the distance between the masses is doubled
the force will be 4 units
Consider two objects of masses m1 and m2
, separated by a distance r.
According to Newton's law of gravitation,
F=(G M1 m2)/r²
On doubling the distance between two masses the gravitational force between them will become one-fourth.
16 x 1/4= 4 units
A horse pulls a wagon with a force of 200 N for a distance of 80 m. How much work
does the horse do?
Answer:
w=f×s
w = 16000 J, hope this helps
A stone is dropped from the top a 45m hign building how fast will it moving when it reaches the ground? Ande what will its velocity be?
Answer:
29.7 m/s fast, velocity is 29.7 m/s
Explanation:
Applying,
v² = u²+2gs...................... Equation 1
Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.
Given: u = 0 m/s (dropped from height), s = 45 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
v² = 0²+2×9.8×45
v² = 882
v = √(882)
v = 29.7 m/s.
Hence the stone will be moving 29.7 m/s fast and the velocity is also 29.7 m/s
Prank text my sister, I wanna see her reaction.
(346) 298-3870
Answer:
she is going to be mad dude
A plastic tube allows a flow of 12.9 cm°/s of
water through it.
How long will it take to fill a 227 cm bottle
with water?
Answer in units of s.
Answer:
It will take \(17.5968 s\) to fill a bottle with water.
Explanation:
Total capacity of tube \(=227\) cm.
Rate of full up the water in the tube \(=12.9 $\mathrm{cm}^{\circ} / \mathrm{s}$\)
Total full up the tube \(=\) rate \(\times\) time
\(T=r \times t\)
\(227 \mathrm{~cm}$$=12.9 \mathrm{~cm}^{\circ} / \mathrm{s} \times t\)
\(t=\frac{227}{12.9}\)
\(=17.5968s\)
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Hey, I'm a Turk. What language do you speak? I'm very curious.
Answer:
What languages do i sqeak?
English, Korean and Filipino
Uhh why are you asking it?
Need help with number 1
the first bright fringe above and the first bright fringe below are equal distances from the central maximum. we are given that the two bright fringes are 4.1 mm apart. what is the height above the central maximum, y1 , of the first bright spot above?
the height above the central maximum, y1, of the first bright spot above is half the distance between the two bright fringes, which is 2.05 mm.
The distance between two bright fringes is given as 4.1 mm. Since the first bright fringe above and the first bright fringe below are equal distances from the central maximum, we can say that the distance between the central maximum and the first bright fringe above is half of 4.1 mm, which is 2.05 mm. Therefore, the height above the central maximum, y1, of the first bright spot above is 2.05 mm.
Your question is about finding the height above the central maximum, y1, of the first bright spot above, given that the two bright fringes are 4.1 mm apart.
The height above the central maximum, y1, of the first bright spot above is 2.05 mm.
Since the first bright fringe above and the first bright fringe below are equal distances from the central maximum, we can divide the total distance between them by 2 to find the height above the central maximum, y1, of the first bright spot above. So, y1 = (4.1 mm) / 2 = 2.05 mm.
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A metal disk of radius 10 cm has a hole at a distance of 2.5 cm from the center. The size of the hole is 1 cm in diameter. If you heat the disk, what will happen to the size of the disk .
The size of the disc will Increase
The hole will enlarge in proportion to the metal if the disc is homogeneous and isotropic (the same in all directions). This is evident because, since the hole's edge is constructed of metal, the thermal expansion equation dL=LdT holds true for all lengths related to the metal, including the circle of the hole. Additionally, if the diameter of the hole increases, so does its circumference.
The analysis becomes more challenging if your disc has distinct areas formed of various metal kinds or if the metal that makes up your disc has an anisotropic crystal structure, meaning that it expands by different amounts in different directions. But given the total change in size is still an expansion, I believe the hole would become bigger in all scenarios.
Hence ,The size of the disc will Increase
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Find the magnitude α of the angular acceleration of the cylinder as the block descends.
2g/3r is the magnitude α of the angular acceleration of the cylinder as the block descends.
mg - T = ma
T = tension in rope
a = acceleration of block
Torque balance around cylinder
Torque = Iα= Tr
Icylinder = 0.5mr^2
α= a/r
0.5mr^2a/r = Tr
T = 0.5ma
mg - T = ma
mg - 0.5ma = ma
mg = 1.5ma
a = 2g/3
α= a/r = 2g/3r
The rate at which the angular velocity in a circular motion changes over time is known as the angular acceleration. Rotational acceleration is another name for it. Given that it has both a magnitude and a direction, it is a vector quantity. Angular acceleration is represented by the letter alpha.
Variable velocity is what causes the acceleration. The phrase "angular acceleration" is used to describe changes in rotational speed in rotating objects. According to the connection, the angular displacement of a rotating object depends on time t. Every time a body rotates, it experiences angular acceleration. A quantitative vector can be used to express the change in angular velocity per unit of time.
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a uniform meter stick is freely pivoted about the 0.20m mark. if it is allowed to swing in a vertical plane with a small amplitude
The period of the pendulum is approximately 2.01 seconds.
The period of a simple pendulum is determined by its length and the acceleration due to gravity. In this case, the length of the pendulum is 0.20 meters.
The period (T) of a pendulum can be calculated using the formula:
T = 2π√(L/g)
where L is the length of the pendulum and g is the acceleration due to gravity.
Substituting the given values into the formula:
T = 2π√(0.20/9.8)
Calculating the expression:
T ≈ 2π√(0.0204)
T ≈ 2π(0.143)
T ≈ 0.902π
T ≈ 2.01 seconds
Therefore, the period of the pendulum is approximately 2.01 seconds.
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a positive charge q moves with velocity in a magnetic field directed as shown. what is the magnetic force on the charge?
The magnetic force on the charge will be F = qv x B
Without a diagram or specific information about the velocity and direction of the magnetic field, I can't provide a definitive answer to your question. However, I can provide a general formula for calculating the
magnetic force on a charged particle moving in a magnetic field.
The magnetic force (F) on a charged particle with charge q moving with velocity v in a magnetic field with a magnetic field strength of B is given by the equation:
F = qv x B
where x represents the cross product between the velocity and magnetic field vectors.
In words, this equation means that the magnetic force on a charged particle is perpendicular to both its velocity and the magnetic field, and its magnitude depends on the charge of the particle, its velocity, and the strength and direction of the magnetic field.
Note that the direction of the magnetic force can be determined by the right-hand rule: if you point your right thumb in the direction of the particle's velocity and your fingers in the direction of the magnetic field, then the direction of the magnetic force is perpendicular to both your thumb and fingers, pointing in the direction your palm faces.
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A beam of light passing through a flint glass is incident on water. The index of refraction of water is 1.33 and the index of refraction of flint glass is 1.62. a. What is the critical angle of light that passes from the flint glass to water? b. What happens to the path of light if the angle of incidence is 60º? c. What happens to the value of the critical angle if the flint glass is replaced by a diamond? The index of refraction of diamond is 2.42.
The term refractve index refers to the value that shows the extent of bending of light waves as it travels from one medium to another.
a) Recall that;
n = 1/sinC
where C = critical angle
C = sin-1(1/n)
C = sin-1 (1/1.62)
C = 38.1 degrees
b) Since the angle of incidence has exceeded the critical angle, then there is total internal reflection of light.
c) If the flint glass id replaced by diamond;
C = sin-1(1/n)
C = sin-1 (1/2.42)
C = 24.4
The critical angle further decreases.
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help yall this is serious-
Answer:
convection: heat transfer by movement of currents inside a liquid, currents in the mantle, temp inside the house, red dye rises blue dye sinks,
radiation: heat from a bonfire, transfer of energy through space,
conduction: frying pan to cooking egg, candle heating up foil to chocolate chips
Explanation:
when a person holds a ball above earth's surface, where is this potential energy stored?
Answer:
in the ball
Explanation:
potential energy is where an object has energy, always, but it isn't always moving, and when you drop the ball, it has kinetic energy.