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Given that,

Energy \(H=2.7\times10^{31}\ W\)

Surface temperature = 11000 K

Emissivity e =1

(a). We need to calculate the radius of the star

Using formula of energy

\(H=Ae\sigma T^4\)

\(A=\dfrac{H}{e\sigma T^4}\)

\(4\pi R^2=\dfrac{H}{e\sigma T^4}\)

\(R^2=\dfrac{H}{e\sigma T^4\times4\pi}\)

Put the value into the formula

\(R=\sqrt{\dfrac{2.7\times10^{31}}{1\times5.67\times10^{-8}\times(11000)^4\times 4\pi}}\)

\(R=5.0\times10^{10}\ m\)

(b). Given that,

Radiates energy \( H=2.1\times10^{23}\ W\)

Temperature T = 10000 K

We need to calculate the radius of the star

Using formula of radius

\(R^2=\dfrac{H}{e\sigma T^4\times4\pi}\)

Put the value into the formula

\(R=\sqrt{\dfrac{2.1\times10^{23}}{1\times5.67\times10^{-8}\times(10000)^4\times4\pi}}\)

\(R=5.42\times10^{6}\ m\)

Hence, (a). The radius of the star is \(5.0\times10^{10}\ m\)

(b). The radius of the star is \(5.42\times10^{6}\ m\)

Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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Answer:

The sun would Expand/Grow

Explanation:

if gravity decreased the suns gasses would be more free to move away from the sun so hence that is the reason

Answer:You need to give more explanation sorry

Explanation:

Answer:

4.20 seconds

Explanation:

Supposing that silly goose weighs 69 pounds, we need to start on the math.

Simple maths, truly and really. 69/1=69, of course.

Therefore it will take 4.20 seconds for silly goose to hit the ground. if he is going to be a silly goose though, he can just go in the pond, instead of wasting his time.

Answer:

It is the smarter option.

Explanation:

Renewable energy is the cheapest source of new power generation for more than two-thirds of the world and has no fuel costs. It can reduce the economic burden of energy bills by eliminating fuel charges — especially when coupled with energy-efficiency upgrades in our homes and businesses.

Answer:

C

Explanation:

The answer is C because if you look at the 1 hour mark it shows 10km

Answer:It will be 10km/hour

Explanation:

A mineral association that should not be found in nature would be a rock that contains both early-forming mafic minerals (such as olivine, pyroxene, and amphibole) and late-forming felsic minerals (such as plagioclase feldspar, quartz, and potassium feldspar) together in the same rock.

Bowen's reaction series is a model that describes how different minerals crystallize from a cooling magma or lava. The minerals that crystallize first, called early forming minerals, are generally rich in iron and magnesium and include olivine, pyroxene, and amphibole. Later-forming minerals, on the other hand, are typically rich in silicon and aluminum and include plagioclase feldspar, quartz, and potassium feldspar.

Crystal settling is the process by which heavier, denser minerals settle to the bottom of a magma chamber due to gravity, while lighter, less dense minerals remain suspended in the magma. This process can occur as the magma cools and solidifies, or as the magma is intruded into existing rock.

Given this information, a mineral association that should not be found in nature would be a rock that contains both early-forming mafic minerals (such as olivine, pyroxene, and amphibole) and late-forming felsic minerals (such as plagioclase feldspar, quartz, and potassium feldspar) together in the same rock. Because these minerals crystallize out at different temperatures and pressures, it is unlikely that they would be found together in the same rock unless there was some form of re-melting or re-crystallization that brought them together.

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Plasma lacks a precise form or volume, much like gas. It completes the empty space. Even though it is in the gaseous form, there is a difference because some of the particles are plasma-ionized.

High-energy particles are free to move around and fill the area they inhabit in the state of matter known as gas.

Neutral atoms or molecules often make up gaseous substances like air.

The ionised gas known as plasma, on the other hand, contains both positively and negatively charged particles.

It develops when a gas is subjected to an intense electric field or heated to incredibly high temperatures.

Plasma is a substance that may be found in stars, lightning, and fluorescent lights. It is also an essential component of many modern technology, like plasma TVs and fusion reactors.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

If two vectors are equal, their components are also equal. For example, vector A and B both share the same x, y, and z components. By having the same components, the magnitude and direction does not change, which attest to how the vectors are identical.

So, if two vectors are equal, their components are also equal.

In vector mathematics, when two vectors are equal, it means their corresponding components are also equal. Thus, the magnitude and direction of the two vectors must be identical.

In the world of mathematics, specifically vector mathematics, if two vectors are equal, that means their corresponding components are also equal. A vector is typically described by its individual components which are its magnitude (size) and direction.

For example, if vector A and vector B are equal, and vector A = \((x_1, y_1)\) and vector B = \((x_2, y_2)\), then\(x_1 = x_2\) and \(y_1 = y_2\). This applies to vectors in two-dimensional and three-dimensional spaces as well. Therefore, equality in vectors involves the same direction and magnitude causing the corresponding components to be equal.

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Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A  = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

\(R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m\)

Therefore, the length of the wire is 134.62 m.

Answer:

I = 0.25 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.

V = I*R

where:

V = voltage [Volt]

I = amperage or current [amp]

R = resistance [ohm]

Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.

Rt = 2 + 8 + 14

Rt = 24 [ohm]

Now clearing I for amperage

I = V/Rt

I = 6/24

I = 0.25 [amp].

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer:

\(\boxed {\boxed {\sf 6,000 \ Newtons}}\)

Explanation:

Force is the product of mass and acceleration.

\(F=ma\)

The mass of the Kia Soul is 1200 kilograms and its acceleration is 5 meters per square second.

\(m= 1200 \ kg \\a= 5 \ m/s^2\)

Substitute the values into the formula.

\(F= 1200 \ kg * 5 \ m/s^2\)

Multiply.

\(F= 6000 \ kg*m/s^2\)

\(F= 6000 \ N\)

Answer:

Force

We know that

F = ma

F = Force

m = mass

a = acceleration

F = 1200 × 5

F = 6000 N

\( \\ \)

Ok force that control the flow of current

Answer:

A flow that counteracts the flow of the electrical current

Explanation:

That's what electrical resistance is.

Answer: \(0.00636\ rad/s^2\)

Explanation:

Given

CD has a playing time of \(t=74\ min\ or\ 74\times 60\ s\)

Initial angular speed of CD is \(480\ rpm\)

Final angular speed of DC is \(210\ rpm\)

Angular speed, when rpm is given

\(\omega =\dfrac{2\pi N}{60}\)

\(\omega_i=\dfrac{2\pi \times 480}{60}\\\\\Rightarrow \omega_i=16\pi \ rad/s\)

Final speed

\(\Rightarrow \omega_f=\dfrac{2\pi \times 210}{60}\\\\\Rightarrow \omega_f=7\pi \ rad/s\)

Using equation of angular motion

\(\Rightarrow \omega_f=\omega_i+\alpha t\)

Insert the values

\(\Rightarrow 7\pi =16\pi +\alpha \times 74\times 60\\\Rightarrow -9\pi =\alpha \cdot (4440)\\\\\Rightarrow \alpha=-\dfrac{9\pi}{4440}\\\\\Rightarrow \alpha=-0.00636\ rad/s^2\)

Magnitude of angular acceleration is \(0.00636\ rad/s^2\)

Answer:

a) v(f) = -4i - 5j

b) 4.18 m

Explanation:

The equation to be used for this question is

v(c)m(c) + v(t)m(t) = [m(c) + m(t)] v(f)

if we rearrange and make v(f) subject of formula, then

v(f) = v(c)m(c) + v(t)m(t) / [m(c) + m(t)]

One vehicle is headed towards south and the other vehicle, west when they collide they will travel together in a southwestern direction. This means that both vehicles are traveling in the negative direction taking a standard frame of reference. Thus, we can write the equation in component form by substituting the values as

v(f) = 1225(-9.5i) + 1654(-8.6j) / 1225 + 1654

v(f) = -11637.5i - 14224.4j / 2879

v(f) = -4i - 5j m/s

From the answer,

v(f) = √(4² + 5²)

v(f) = √41

v(f) = 6.4 m/s

And we know that

KE = ½mv²

Fd = umgd

And, KE = Fd, so

½mv² = umgd

½v² = ugd

Making d the subject of formula,

d = v²/2ug

d = 6.4² / 2 * 0.5 * 9.8

d = 41 / 9.8

d = 4.18 m

(a) The velocity of the system after collision is 4.04 i + 4.9 j.

(b)The distance traveled by the vehicles after collision is 1.73 m.

The given parameters;

Apply the principle of conservation of linear momentum to determine the velocity of the system after collision;

\(m_1u_x_1 + m_2 u_y_2 = V(m_1 + m_2)\\\\V = \frac{(1225\times 9.5)_x \ + \ (1654 \times 8.6)_y}{m_1 + m_2} \\\\V = \frac{(1225\times 9.5)_x \ + \ (1654 \times 8.6)_y}{1225+ 1654} \\\\V= \frac{(11,637.5)_x \ + \ (14,224.4)_y}{2879} \\\\V = 4.04x \ + 4.94y\\\\V = 4.04i \ + 4.9 j\)

The magnitude of the final velocity of the system is calculated as;

\(V = \sqrt{v_x^2 + v_y^2} \\\\V = \sqrt{(4.04)^2 + (4.9)^2} \\\\V = 6.35 \ m/s\)

The change in the mechanical energy of the system;

\(\Delta K.E = K.E_f - K.E_i\\\\\)

The initial kinetic energy of the cars before collision is calculated as;

\(K.E_i = \frac{1}{2} m_1u_1_x^2 \ + \frac{1}{2} m_1u_2_y^2 \\\\K.E_i = \frac{1}{2} (1225)(9.5)^2\ + \frac{1}{2} (1654)(8.6)^2\\\\K.E_i = 55,278.13_x \ + \ 61,164.92_y\\\\K.E_i = \sqrt{55,278.13^2 \ + \ 61,164.92^2} \\\\K.E_i = \sqrt{6,796,819,094.9} \\\\K.E_i = 82,442.82 \ J\)

The final kinetic energy of the system;

\(K.E_f = \frac{1}{2} (m_1 + m_2)V^2\\\\K.E_f = \frac{1}{2} (1225 + 1654)(6.35)^2\\\\K.E_f = 58,044.24 \ J\)

The change in kinetic energy is calculated as;

\(\Delta K.E = K.E_f -K.E_i\\\\\Delta K.E= (58,044.24) - (82,442.82)\\\\\Delta K.E = -24,398.58 \ J\)

Apply the principle of work-energy theorem, to determine the distance traveled by the vehicles after collision;

\(W = \Delta K.E\\\\- \mu Fd = - 24,398.58\\\\\mu mgd= 24,398.58\\\\d = \frac{24,398.58}{\mu mg} \\\\d = \frac{24,398.58}{0.5 \times 9.8(1225 + 1654)} \\\\d = 1.73 \ m\)

Thus, the distance traveled by the vehicles after collision is 1.73 m.

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Answer:

85

Explanation:

soln

given that;

frequency=17Hz

wavelength=5m

speed?

formula for wavelength is;

wavelength= speed/frequency

then ; making v the subject formula

we have that v=wavelength*frequency

v=17*5=>85ms

Answer:

647.19 J

Explanation:

By the conservation of energy, the potential energy when you toss the orange is converted to kinetic energy when it hits the sidewalk, so

Ef = Ei

KE = PE

KE = mgh

Where m is the mass, g is 9.8 m/s², and h is the height of the Tower. Replacing m by 0.13 kg and h by 508 meters, we get

KE = (0.13kg)(9.8 m/s²)(508 m)

KE = 647.19 J

So, the orange would have 647.19 J of kinetic energy when it hits the sidewalk.

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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Answer:

approximately -7.6 kJ

Explanation:

To solve this problem, we can use the ideal gas law: PV = nRT, where P is the pressure of the gas, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Since the expansion is isothermal, the temperature does not change, so we can assume T is constant.

We can rearrange the ideal gas law to solve for the pressure at the initial volume:

P = nRT / V

And then use this pressure to calculate the work done by the gas during the expansion using the formula:

W = -Pext * ΔV

Where Pext is the external pressure and ΔV is the change in volume (final volume - initial volume).

Substituting the known values:

n = 1450.0 mol T = 11.0 + 273.15 = 284.15 K V1 = 20.0 L V2 = 95.0 L R = 8.314 J/(mol*K)

We can calculate the initial pressure:

P1 = nRT/V1 = (1450.0 mol)(8.314 J/(mol*K))(284.15 K)/(20.0 L) = 27047.6 Pa

(Note that we converted the temperature to Kelvin.)

During the expansion, the external pressure is assumed to be constant, and equal to the pressure outside the system, so we can just use atmospheric pressure. Let's assume that the atmospheric pressure is 101325 Pa.

The change in volume is ΔV = V2 - V1 = 75.0 L

Then we can calculate the work done by the gas:

W = -Pext * ΔV = -(101325 Pa) * (75.0 L) = -7.6 kJ

(Note that we converted units from joules to kilojoules.

Therefore, the work done by the gas during the expansion is approximately -7.6 kJ. Note that the negative sign indicates that work is done on the gas by the surroundings.

Answer:

The pressure of the solid on the surface depends on the area of contact. The area of contact between the two surfaces. The greater the force or the smaller the area the greater the pressure.

(credits to the rightful owner for these answers :)

Answer:

Option (D)

Explanation:

Since acceleration of an object = Change in velocity with the change in time

a = \(\frac{v_2-v_1}{t_2-t_1}\) = \(\frac{\triangle v}{\triangle t}\)

Here \((v_1,t_1)\) and \((v_2,t_2)\) are the two points on the line on the graph.

Therefore, slope of the line will represent the acceleration (constant) at any point lying on the line.

For particle A,

Two points on the line are (0, 2) and (1, 0)

a = \(\frac{2-0}{0-1}\)

\(a_1\) = -2 meter per sec²

Similarly, for the particle B,

There are two points (0, 1) and (2, 0) on the line.

\(a_2\) = \(\frac{1-0}{0-2}\) = \(-\frac{1}{2}\)

\(a_2=-0.5\) meter per sec²

Therefore, at any moment of time acceleration of the particle A will be (-2) meter per sec² and for particle B will be (-0.5) meter per sec².

Option (D) will be the correct option.

The frequency of yellow light is 5.1 x 10¹⁴ Hz. The wavelength of yellow light is 588 nm.

As we know, The frequency of the wave is given by the equation, frequency = speed/wavelength

Rearrange this equation to solve for wavelength: wavelength = speed/frequency

From the above equation, we get that the wavelength is given by λ = c / ν,

where c is the speed of light and ν is the frequency of the wave.

According to the problem, The frequency of yellow light is given as,

ν = 5.1 x 10¹⁴ Hz.

The speed of light is given as,c = 3 x 10⁸ m/s.

Now, let's substitute the values in the formula to get the wavelength

,λ = c / ν

λ = (3 x 10⁸) / (5.1 x 10¹⁴)

λ = 0.000000000000588 m

Convert this value to nanometers (nm),λ = (0.000000000000588 m) x (1 nm / 10⁻⁹ m)λ = 588 nm

Therefore, the wavelength of yellow light is 588 nm.

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The vessel can be immersed to a depth of 0.3006 m in the deep vat of mercury without being crushed.

The question requires us to determine the depth to which a closed vessel that can sink to a depth of 41.0 m in water before the external pressure crushes it could be immersed in a deep vat of mercury without being crushed. We can determine this using the concept of pressure.Pressure is defined as the amount of force acting per unit area. Pressure is given by the formula:

P = F/A,

where P is pressure, F is force, and A is area. Since the area remains constant, we can say that pressure is directly proportional to force. Thus, the greater the force acting on an object, the greater the pressure exerted on the object. The pressure exerted by a liquid depends on the density of the liquid, the depth of the liquid, and the acceleration due to gravity. This can be expressed using the formula:

P = ρgh,

where P is pressure, ρ is density, g is acceleration due to gravity, and h is depth. Let us first calculate the pressure exerted by the water at a depth of

41.0 m:ρ of water = 1000 kg/m³g = 9.81 m/s²h = 41.0 m

Substituting these values in the formula, we get:

P = ρgh= (1000 kg/m³)(9.81 m/s²)(41.0 m)= 405570 Pa

Now, we need to determine the depth to which the vessel can be immersed in mercury without being crushed. Let us call this depth "d". The pressure exerted by the mercury at this depth is equal to the pressure exerted by the water at a depth of 41.0 m. Thus, we can equate the two pressure values:

ρ of mercury = 13600 kg/m³g = 9.81 m/s²P = 405570 Pa

Substituting these values in the formula, we get:ρgh = P(13600 kg/m³)(9.81 m/s²)(d) = 405570 PaSolving for d, we get:d = 0.3006 m.

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Answer:

I can say words like cheese and balls