Submit a full solution (your final answer AND your work) to the problems below.

A company conducted a survey to determine the ages of its employees. The data collected showed that the range of the data set was 40 years. If I know that the youngest employee is 30, how old is the oldest employee?

Answer:

the approximate value of m is -0.12, indicating that the value of Ty's computer decreases by 0.12 (or 12%) each year.

Step-by-step explanation:

o express this depreciation rate as a slope in the equation y = mx + b, we need to determine how much the value changes (the "rise") for each year (the "run").

Since the value decreases by 12% per year, the slope (m) would be -12%. However, we need to express the slope as a decimal, so we divide -12% by 100 to convert it to a decimal:

m = -12% / 100 = -0.12

Answer:

A) 5

B) x-3

C) 2x+y

No, we can't conclude that the correlation coefficient differs from zero because the p-value, which is 0.0653 exceeds 0.05. The correct option is a.

Given that:

p-value  = 0.0653                        

Level of significance (p) = 0.05  

The null hypothesis is a typical statical theory that suggests that no statical relationship and significance exists in a set of given single observed variables, between two sets of observed data and measured phenomena.

The null hypothesis is significant because it offers a rough description of the phenomena inferred from the available evidence. It enables researchers to empirically test the relationship statement in a study.

Example: The null hypothesis is that the population density is the same across all states.

The hypothesis is

H0: p=0 vs HA: p \(\neq\) 0

We observe that,

p-value > p (level of significance)

So, fail to reject the null hypothesis (H0).

The correlation coefficient differs from zero when the p-value is less than 0.05.

Therefore, we can not conclude that the correlation coefficient differs from zero.

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Answer:

its A

Step-by-step explanation:

i did the test

Answer:

a

The sample size is  \(n = 219.2\)

b

The  sample size is  \(n = 537.5\)

Step-by-step explanation:

From the question we are told  that

    The standard deviation is  \(\sigma = 45 \minutes\)

    The  Margin of  Error is  \(E = \pm 5 \ minutes\)

Generally the margin of  error is mathematically represented as

         \(E = z * \frac{\sigma }{\sqrt{n} }\)

Where  n is the sample  size

    So

             \(n = [\frac{z * \sigma }{E} ]^2\)

Now  at  90%  confidence level the z value for the z-table is  

        z =  1.645

So

       \(n = [\frac{1.645 * 45 }{5} ]^2\)

       \(n = 219.2\)

The z-value at 99%  confidence level is  

        \(z = 2.576\)

This is obtained from the z-table  

   So the sample size is  

         \(n = [\frac{2.576 * 45 }{5} ]^2\)

        \(n = 537.5\)

For the 90% confidence interval, the sample size is 219.2 and for the 99% confidence interval, the sample size is 537.5 and this can be determined by using the formula of margin of error.

Given :

The formula of the margin of error can be used in order to determine the sample size is needed if the executive wants to be 90% confident of being correct to within 5 minutes.

\(\rm ME = z\times \dfrac{\sigma}{\sqrt{n} }\)

For the 90% confidence interval, the value of z is 1.645.

Now, substitute the values of all the known terms in the above formula.

\(\rm n=\left(\dfrac{z\times \sigma}{ME}\right)^2\)   --- (1)

\(\rm n=\left(\dfrac{1.645\times 45}{5}\right)^2\)

n = 219.2

Now, for 99% confidence interval, the value of z is 2.576.

Again, substitute the values of all the known terms in the expression (1).

\(\rm n=\left(\dfrac{2.576\times 45}{5}\right)^2\)

n = 537.5

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The value of XZ is given by 26.

Given that the triangles RST and XYZ are congruent to each other.

So, RS = XY, since corresponding parts of Congruent triangles are equal.

Given also that,

RS = 11x-1

XY = 9x+5

XZ = 7x+5

So, RS = XY gives

11x-1 = 9x+5

11x-9x = 5+1

2x = 6

x = 6/2

x = 3

Substituting the value of x in the value of XZ is given by,

XZ = 7x+5 = 7*3+5 = 21+5 = 26

Hence the value of XZ is 26.

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Answer:

340=10*340 calculated

Answer:

340

Step-by-step explanation:

i know math alot

Answer: The result of the exercise is BRL 15.00

Step by step explanation:

To find the total value, simply multiply the number of sheets and the price per copy.

\(\sf{ \bold{30 * 0.50} ={\boxed{\bold{15 \: \: real}}} }\)

Rpt: The result of the exercise is BRL 15.00

The point charges placed 0.500 m apart are 10.4 nC and 43.9 nC. Then, the electric field halfway between these charges will be -4824 N/C.

The physical field that surrounds particles with an electrical charge is called an electric field. All other charged particles in the field are affected by it, either being attracted to it or being repelled by it.

The electric field because of a point charge q is written as \(E=\frac{kq}{r^2}\)

Positive point charges cause the electric field to point away from the point, whereas negative point charges cause the electric field to point in the direction of the point. Then, the electric field of the midpoint p in the diagram is written as,

\(\begin{aligned}E_p&=\mathrm{\frac{k(10.4\;nC)}{(0.25\;m)^2}-\frac{k(43.9\;nC)}{(0.25\;m)^2}}\\&=\mathrm{\frac{k(10.4-43.9)\times10^{-9}\;C}{(0.25\;m)^2}}\\&=-\mathrm{\frac{9\times 10^9\;Nm^2/C^2\times 33.5\times10^{-9}\;C}{(0.25\;m)^2}}\\&=-\mathrm{4824\;N/C}\end{aligned}\)

The required answer is -4824 N/C.

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Answer:

7:01

29%

Doyan of low

Shiman 1-R-1

Flous 1-1 Gambe 1-4-20

12 dual purpose

Martins 1-2-3 Flores 1-2, 1-3, 14

Gamba 2-1-5

Custand 1-4, 2-1

Conditions " humanitarian groups Salahiel 1-1-1, 1-1-2, 1-2-3 1-R-5, 2-L-2, 2-L-3, 2-14, 2-1-5, 2-RI

Flores 1-30

Munting 1-2-4

Gumbon 1-1-3 CDP 1-1-3

Status oppose ending 742 Montoya 1-1, 1-2, 1-3

federal courts challenge

Gamboa 1-R-2 Custom 1-7

CDP 1-L-36, 1-2-4

de Vogue 1-2-1, 2-1-5, 2-L-6

7 expulsions at boders

root causes textul Amer.

Cop 1-L-34, 1-1-2, 1-R-4

Border Report 1-2

CDP 1-R-2, 1-R-3 Montoya 1-8

Custarda 2-2

=

CLOSE

Hopes this helps :)

Answer:

what

Step-by-step explanation:

what do you need help on?

Answer:

You have to apply Indices Law :

\( {a}^{m} \div {a}^{n} ⇒ {a}^{m - n} \)

So for this question :

\( \frac{ \sqrt[3]{x} }{ {x}^{ \frac{1}{8} } } \)

\( = \sqrt[3]{x} \div {x}^{ \frac{1}{8} } \)

\( = {x}^{ \frac{1}{3} } \div {x}^{ \frac{1}{8} } \)

\( = {x}^{ \frac{1}{3} - \frac{1}{8} } \)

\( = {x}^{ \frac{5}{24} } \)

Answer:

Y=KX so its 10=K2

Step-by-step explanation:

Plug in the Number OR K=y/x

Answer:

D

Step-by-step explanation:

Since there are two types of values here: tokens and dollars, we will need to use the same value across numerators and denominators in the ratio.

Choice D has 11 tokens over $2 equals to t tokens over $16. In both fractions the numerator is tokens and denominator is dollars.

Answer:

(−∞, 31/5) or x <31/5 (the graph will start a little bit past 6 and will be a open circle and head to the left)

Answer:

x< 6\(\frac{1}{5}\)

Step-by-step explanation:

7<-5(x -8) - 2  Distribute the 5

7<-5x + 40 - 2

7<-5x +38  Subtract 38 from both sides

-31<-5x  Divide both sides by -5

\(\frac{31}{5}\) >x  When you divide both sides by a negative number, you must flip the sign.

or

x < 6 \(\frac{1}{5}\)

Step-by-step explanation:

Let's assume the width of the rectangle is represented by "w" meters.

According to the given information, the length of the rectangle is 2 meters more than three times the width, which can be expressed as "3w + 2" meters.

The perimeter of a rectangle is given by the formula: 2(length + width).

We can now set up the equation using the given perimeter of 28 meters:

2(3w + 2 + w) = 28

Simplifying the equation:

2(4w + 2) = 28

8w + 4 = 28

8w = 28 - 4

8w = 24

w = 24/8

w = 3

Therefore, the width of the rectangle is 3 meters.

To find the length, we substitute the value of the width back into the expression for the length:

Length = 3w + 2

Length = 3(3) + 2

Length = 9 + 2

Length = 11

Hence, the length of the rectangle is 11 meters.

In summary, the width of the rectangle is 3 meters, and the length is 11 meters.

Answer:

Let's denote the width of the rectangle as w and the length as l.

According to the problem, we have two conditions:

1. The length is 2 m more than three times the width. This gives us the equation l = 3w + 2.

2. The perimeter of a rectangle is twice the sum of its length and its width, which gives us the equation P = 2(l + w). Substituting P = 28, we get 28 = 2(l + w).

Now, let's substitute the first equation into the second to solve for w:

28 = 2((3w + 2) + w) = 2(4w + 2) = 8w + 4

Subtract 4 from both sides:

24 = 8w

Divide both sides by 8 to solve for w:

w = 24 / 8 = 3 meters

Substitute w = 3 into the first equation to find l:

l = 3 * 3 + 2 = 9 + 2 = 11 meters

So, the width of the rectangle is 3 meters, and the length is 11 meters.

I think it's square and hexagon.

Answer:

180 clockwise

Step-by-step explanation:

180 clockwise because it is a obtuse angle

The expression of the statement that is given above can be written as follows: 262144y³ + 27.

To determine how to express the given statement the following should be carried out.

When a number is said to be cubed, it means that the number should be times by itself three consecutive times.

That is (64y + 3)³. This means that various components should be multiplied by itself three times. That is,

= 64×64×64(y)³ + 3×3×3

= 262144y³ + 27.

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Answer:

\(52.1-1.984\frac{12.3}{\sqrt{100}}=49.66\)    

\(52.1 +1.984\frac{12.3}{\sqrt{100}}=54.54\)    

The 95% confidence interval would be given by (49.66;54.54)    

Step-by-step explanation:

Information given

\(\bar X= 52.1\) represent the sample mean

\(\mu\) population mean (variable of interest)

s=12.3 represent the sample standard deviation

n=100 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\(\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}\)   (1)

The degrees of freedom are given by:

\(df=n-1=100-1=99\)

The Confidence is 0.95 or 95%, and the significance would be \(\alpha=0.05\) and \(\alpha/2 =0.025\), the critical value for this case is: \(t_{\alpha/2}=1.984\)

Replacing the info given we got:

\(52.1- 1.984\frac{12.3}{\sqrt{100}}=49.66\)    

\(52.1 +1.984\frac{12.3}{\sqrt{100}}=54.54\)    

The 95% confidence interval would be given by (49.66;54.54)    

The First mistake she made is simplifying 4(x+5) - 3x to be 4x+5-3x.

The mistake here is that she did not expand the 4(x+5) correctly. She forgot to multiply 4 by 5 to correctly expand the bracket. The correct expansion of "4(x+5)" is "4x + 20" and not "4x + 5"

The second mistake is that she simplified 4x+5-3x to be equal to 6. This is wrong.

"4x+5-3x" gives "x + 5" and not 6.

The correct simplification of the problem is as follows:

4(x+5) - 3x = 4x + 20 -3x

Collect like terms

=4x - 3x + 20

=x + 20

The correct answer should be x + 20

Hello !

Answer:

\(\Large \boxed{\sf length=13cm}\)

Step-by-step explanation:

The volume of a pyramid is given by \(\sf V_{pyramid}=\frac{1}{3} \times B\times h\) where B is the area of the base and h is the height.

This is a rectangular pyramid. We have where \(\sf B=l\times w\) l is the length and w is the width (breadth).

So \(\sf V_{pyramid}=\frac{1}{3} \times l\times w\times h\)

Given :

Let's replace h, w, l, \(\sf V_{pyramid}\) with their values in the previous formula :

\(\sf 728=\frac{1}{3} \times x\times 8 \times 21\\728=56x\)

Let's solve for x !

Divide both sides by 56 :

\(\sf \frac{56x}{56} =\frac{728}{56}\\ \boxed{\sf x=13cm}\)

Have a nice day ;)

Answer:

Part A:

To find the percentage of survey respondents who liked neither hamburgers nor burritos, we need to calculate the frequency in the "Does not like hamburgers" and "Does not like burritos" categories.

Frequency of "Does not like hamburgers" = Total in "Does not like hamburgers" category = 135

Frequency of "Does not like burritos" = Total in "Does not like burritos" category = 54

Total respondents who liked neither hamburgers nor burritos = Frequency of "Does not like hamburgers" + Frequency of "Does not like burritos" = 135 + 54 = 189

Percentage of survey respondents who liked neither hamburgers nor burritos = (Total respondents who liked neither hamburgers nor burritos / Total respondents) x 100

Percentage = (189 / 205) x 100 = 92.2%

Therefore, 92.2% of the survey respondents liked neither hamburgers nor burritos.

Part B:

To find the marginal relative frequency of all customers who like hamburgers, we need to divide the frequency of "Likes hamburgers" by the total number of respondents.

Frequency of "Likes hamburgers" = 110 (given)

Total respondents = 205 (given)

Marginal relative frequency = Frequency of "Likes hamburgers" / Total respondents

Marginal relative frequency = 110 / 205 ≈ 0.5366 or 53.66%

Therefore, the marginal relative frequency of all customers who like hamburgers is approximately 53.66%.

Part C:

To determine if there is an association between liking burritos and liking hamburgers, we can compare the joint and marginal frequencies.

Joint frequency of "Likes hamburgers" and "Likes burritos" = 29 (given)

Marginal frequency of "Likes hamburgers" = 110 (given)

Marginal frequency of "Likes burritos" = 70 (calculated by adding the frequency of "Likes burritos" in the table)

To assess the association, we compare the ratio of the joint frequency to the product of the marginal frequencies:

Ratio = Joint frequency / (Marginal frequency of "Likes hamburgers" x Marginal frequency of "Likes burritos")

Ratio = 29 / (110 x 70)

Ratio ≈ 0.037 (rounded to three decimal places)

9514 1404 393

Answer:

  4) y = -3(x+2)^2 +4; y = -3x^2-12x-8; ABC=(-3, -12, -8)

  5) y = 0.5(x-1)^2-2; y = 0.5x^2-x-1.5; (h,k) = (1, -2)

  6) y = -0.3(x+2)^2-6; y = -0.3x^2-1.2x-7.2; (h,k) = (-2, -6)

Step-by-step explanation:

Writing a quadratic equation through a set of points is most easily done using the regression function of a graphing calculator or spreadsheet.

4) see the first attachment

  y = -3(x+2)^2 +4 . . . vertex form

  y = -3x^2 -12x -8 . . . standard form (A, B, C) = (-3, -12, -8)

__

5) see the second attachment

  y = 0.5(x -1)^2 -2 . . . vertex form; vertex = (1, -2)

  y = 0.5x^2 -x -1.5 . . . standard form

__

6) see the third attachment

  y = -0.3(x +2)^2 -6 . . . vertex form; vertex = (-2, -6)

  y = -0.3x^2 -1.2x -7.2 . . . standard form

_____

Doing this without machine help requires you pick a form of the equation you want, fill in the x- and y-values for three of the given points, then solve the resulting equations for the unknown parameters. Usually, we use the form ...

  y = ax^2 +bx +c

which will result in three linear equations for a, b, c. Those can be solved by any of the usual methods.

Answer:

5.3%

Step-by-step explanation:

% Increase = Increase / Original Number × 100.

68/1283 * 100

= 5.3%

The value of y for the inequality is y  >  0

An inequality compares two values, showing if one is less than, greater than, or simply not equal to another value e.g. 5 < 6, x ≥ 2, etc.

The inequality 2 times the quantity y plus one third end quantity is greater than two thirds can be written as:

2(y + 1/3) > 2/3

To determine the value of y in the inequality, you need to solve for y. That is:

2(y + 1/3) > 2/3  

y + 1/3 > 1/3     (Divide both sides by 2)

y > 1/3 - 1/3     (Collect like terms)

y > 0

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