stella is driving down a steep hill. she should keep her car __________ to help _________.

The correct answer is e. 0.25. According to the Law of Universal Gravitation, the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This means that when the distance between the centers of two objects is doubled, the force between them is reduced to 1/4 of its original value.

Therefore, if the distance between the centers of two objects is doubled and the masses remain constant, the force between the objects is multiplied by a factor of 1/4, or 0.25. This is because the inverse square law states that the force decreases exponentially as the distance between the objects increases.

Understanding this law is important in many fields, including astronomy, physics, and engineering, as it helps to explain the behavior of celestial bodies and the forces that govern their motion.
According to the Law of Universal Gravitation, the gravitational force (F) between two objects with masses (m1 and m2) and a distance (r) between their centers is given by the equation:

F = G * (m1 * m2) / r^2

where G is the gravitational constant.

When the distance between the centers of the objects is doubled (2r), the new gravitational force (F') can be calculated as follows:

F' = G * (m1 * m2) / (2r)^2

Now, we can simplify this equation:

F' = G * (m1 * m2) / (4 * r^2)

From the original equation, we know that F = G * (m1 * m2) / r^2. Therefore, we can rewrite the new equation as:

F' = (1/4) * F

This shows that when the distance between the centers of two objects is doubled, the force between the objects is multiplied by a factor of 1/4 (0.25).

So, the correct answer is e. 0.25.

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The hanging mass will be 0.101 kg.

The formula for calculating the mass of a hanging wire is given as;

m = (π/4) * [(ρL² /Y) * ΔL + L * Δρ]

where; m is the mass of the hanging weight,

            ρ is the density of the wire,

            L is the length of the wire,

            Y is Young's modulus of the wire,

           ΔL is the extension of the wire and

         Δρ is the change in the density of the wire.

In this case,

ρ = 7.86 x 10³ kg/m³L

  = 2.9 mD

  = 0.48 mm

  = 0.48 x 10⁻³ m

  = 4.8 x 10⁻⁴ mY

  = 2.0 x 10¹¹ N/m²ΔL

  = 1.4 x 10⁻³ m

Let US calculate the mass of the wire;

A = (π/4) * D²A

    = (π/4) * (4.8 x 10⁻⁴)²A

    = 1.80955737 x 10⁻⁷ m²ρL

    = 7.86 x 10³ kg/m³ * 2.9m

    = 22.794 kg Y

   = 2.0 x 10¹¹ N/m²m_wire

   = ρLA / Lm_wire

   = 7.86 x 10³ kg/m³ * 1.80955737 x 10⁻⁷ m² / 2.9m

  = 4.9091761 x 10⁻⁴ kg

Let's calculate the mass of the hanging weight using the mass formula.

m = (π/4) * [(ρL² /Y) * ΔL + L * Δρ]

m = (π/4) * [(7.86 x 10³ * 2.9² / 2.0 x 10¹¹) * 1.4 x 10⁻³ + 2.9 * 4.8 x 10⁻⁴]

m = 0.100615775 kg

Therefore, the hanging mass will be 0.101 kg.

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Answer:

The North Pole.

Explanation:

According to the Lenz's law of electromagnetic induction, an induced elemagnetic force tends to give rise to the current. In reaction, this current's magnetic field try to oppose any replacement in the magnetic flux.

So,  as per the law of Lenz's electromagnetic induction, when the current passes in a coil in anti-clockwise direction, this will produce the opposite end of the coil in the north pole.

So, the correct answer is north pole.

Answer:

actually you can't find it without acceleration.

you need to use one of these three equations

1- Vf = Vi + at

2- 2ad = Vf^2 - Vi^2

3- d = Vit + 1/2 at^2

Jim Crow laws was the legal measure which allowed whites in southern states to keep blacks from voting after reconstruction ended.

These were the state and local laws which enforced racial segregation in the Southern part of the United States.

Due to this laws, whites in southern states kept blacks from voting after reconstruction ended.

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fyjvdng iuhp;iruohpgiryhgutnbrpybgiunpieohgiuojfhdnbj

sodium channel  is responsible for the rapid depolarization phase of potentials that originate in the sa nodal cells.

The resting membrane potential of the SA nodal cells is unstable and spontaneously depolarizes due to a pacemaker potential. The "strange" Na+ current and a drop in the conductance of the inward rectifier K+ channel are to blame for this.

The rapid transmission of depolarizing impulses throughout cells and cell networks by sodium channels, which enable the coordination of higher activities from locomotion to cognition, plays a key role in physiology. These channels hold a particular place in physiology history as well.

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Answer:

Explanation:El ejercicio vigoroso previene en mayor medida el síndrome metabólico (un conjunto de enfermedades que aumentan el riesgo cardiovascular         )

mientras que una reacción vigorosa se   produce entre el aluminio y el gas cloro. Como consecuencia de la gran cantidad de energía liberada se producen luz y calor

Answer:

78.35°

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

A layer of ethyl alcohol (n = 1.361) is on top of water (n = 1.333). To the nearest degree, at what angle relative to the normal to the interface of the two liquids is light totally reflected?

From Snell's Law,

(ni)/(nr) = Sin (θr) / Sin (θi)

Where

θi = Angle of Incidence

θr = Angle of refraction

ni = Refractive index given for ethyl alcohol

nr = Refractive index of medium from which light is refracted

ni = 1.361

nr = 1.333

, θr = 90° ( Critical Angle is reffered to as Angle of Incidence at refracted angle of 90°) (θi = θc)

(ni)/(nr) = Sin (θr) / Sin (θi)

1.361/ 1.333 = Sin (90°)/ Sin( θc)

1.021= 0.894/ Sin( θc)

Sin( θc)= (0.9794

θc = Sin⁻¹ 0.9794)

θc = 78.35°

a. Part A: The area of each plate is required for for a 0.300 uF capacitor is 1.56 × \(10^{-4}\) m².

b. Part B: If the electric field in the paper is not to exceed one-half the dielectric strength, the maximum potential difference that can be applied across the compactor is 2025 V.

To find the area of each plate required for a 0.300 uF capacitor, use the formula:

C = ε₀εrA/d

where C is the capacitance, ε₀ is the vacuum permittivity (8.85 × \(10^{-12}\) F/m), εr is the relative permittivity (dielectric constant), A is the area, and d is the distance between the plates. In this case,

C = 0.300 uF

εr = 2.10

d = 8.10 × \(10^{-5}\) m.

Rearrange the formula to find A:

A = Cd / (ε₀εr)

A = (0.300 × \(10^{-6}\) F)(8.10 × \(10^{-5}\) m) / (8.85 × \(10^{-12}\) F/m × 2.10)

A ≈ 1.56 × \(10^{-4}\) m²

Thus, the area of each plate required for a 0.300 uF capacitor is approximately 1.56 × \(10^{-4}\) m².

To find the maximum potential difference that can be applied across the capacitor, use the formula:

V = Ed

where E is the electric field and d is the distance between the plates. In this case, E is half the dielectric strength (50.0 MV/m / 2 = 25.0 MV/m), and d = 8.10 × \(10^{-5}\) m:

V = (25.0 × 10^6 V/m)(8.10 × 10^-5 m)

V ≈ 2025 V

Thus, the maximum potential difference that can be applied across the capacitor without exceeding one-half the dielectric strength is approximately 2025 V.

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Answer:

Displacement = 1725m

Explanation:

\(t = \frac{u-v}{a}\)

\(t = \frac{65-50}{0.5} = 30s\)

\(s = ut+\frac{1}{2}at^{2} \\s = 50*30 + \frac{1}{2} *0.5*30^{2} = 1725m\)

It is FALSE that the proportionality dependence of the current (i) through any conductor to the voltage (v) across it and its resistance (r) is true for all conductors regardless of temperature.

When the conductors have a higher temperature, the molecules in the conductor will be more crowded and the result is the resistance of the conductor will rise. Hence, the current flowing through the conductor will decrease in the same voltage.

In the lower temperature, the resistance of the conductor will decrease and lead to more current flowing through the conductor in the same voltage.

Thus, the conductor temperature has an effect on its resistance.

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According to the question we have These t-values are the confidence coefficients for each of the scenarios given.

To find the confidence coefficients using the t-table, you need to first determine the degrees of freedom (df) and the corresponding t-value for each given confidence level.

1. n = 12 with 95% confidence:
Degrees of freedom (df) = n - 1 = 12 - 1 = 11
For a 95% confidence level, the t-value from the t-table is approximately 2.201.

2. n = 15 with 95% confidence:
Degrees of freedom (df) = n - 1 = 15 - 1 = 14
For a 95% confidence level, the t-value from the t-table is approximately 2.145.

3. n = 21 with 96% confidence:
Degrees of freedom (df) = n - 1 = 21 - 1 = 20
For a 96% confidence level, the t-value from the t-table is approximately 2.528.

4. n = 27 with 92% confidence:
Degrees of freedom (df) = n - 1 = 27 - 1 = 26
For a 92% confidence level, the t-value from the t-table is approximately 2.056.

These t-values are the confidence coefficients for each of the scenarios given.

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objects that generate light are called as luminous objects

objects that do not generate light are called as luminous objects

objects in which light cannot pass through it is known as opaque

objects in which light pass partially through it is known as translucent

objects in which light can pass through it in known as transparent

Answer:

a) luminous objects.

= If light is emitted by object,the object is called Luminous Object.

Examples: Torch, Candle, etc.

b) non- luminous objects.

= Objects that cannot emit light energy by themselves are known as non-luminous objects.

Examples: Moon, wood, etc.

c) opaque objects.

= The object which do not allow the light to pass through are called opaque object.

Examples: stone, wood etc.

d) translucent objects.

= Those objects through which light can pass partially are called translucent objects.

Examples: paper, plastic, etc.

e) transparent objects.

= Those object through which light can pass easily are called transparent.

Examples: water, glass, etc.

Answer:

a) 37.5N

b) 9.375Joules

Explanation:

a) According to Hooke's law

F = ke

k is the spring constant

e is the extension;

F = 150 * 0.25

F = 37.5N

b) Work done on the spring = 1/2ke^2

Work done on the spring = 1/2 * 150 * 0.25^2

Work done on the spring  = 75 * 0.0625

Work done on the spring  = 9.375Joules

(a)  The force required to stretch the spring is of 37.5 N.

(b)  The work done on the spring is of 4.6775 J.

Given data:

The force constant of a spring is, k = 150 N/m.

The stretching distance of spring is, x = 0.25 m.

(a)  

When some force is experienced on the spring, then due to this force then it will displace. Then, the expression for the force applied on the spring is given as,

\(F = k \times x\)

Solve by substituting the values as,

\(F = 150 \times 0.25\\\\F = 37.5 \;\rm N\)

Thus, we can conclude that the force required to stretch the spring is of 37.5 N.

(b)

And the expression for the work done on the spring is given as,

\(W = \dfrac{1}{2}kx^{2}\)

Solving as,

\(W = \dfrac{1}{2} \times 150 \times 0.25^{2}\\\\W = 4.6875 \;\rm J\)

Thus, we can conclude that the work done on the spring is of 4.6775 J.

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We can use the kinematic equation and solve for the acceleration. The minimum acceleration required is found to be 1.62 m/s².

Given that the aeroplane needs to reach a forward velocity of 203.0 km/h, we first convert this velocity to meters per second (m/s). Since 1 km/h is equivalent to 0.2778 m/s, the forward velocity becomes 56.4 m/s.

To calculate the minimum uniform acceleration required, we can use the kinematic equation:

v^2 = u^2 + 2ad

where v is the final velocity, u is the initial velocity (which is 0 since the airplane starts from rest), a is the acceleration, and d is the distance covered during acceleration.

Rearranging the equation, we have:

a = (v^2 - u^2) / (2d)

Substituting the known values, we get:

a = (56.4^2 - 0^2) / (2 * 2000)

Simplifying this equation, we find that the minimum uniform acceleration required for the airplane to take off is approximately 1.62 m/s².

Therefore, the airplane needs to accelerate at a minimum uniform acceleration of 1.62 m/s² to reach a forward velocity of 203.0 km/h on a 2000-meter runway, starting from rest.

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The complete question is:

An airplane needs to reach a forward velocity of 203.0 km/h to take off. On a 2000-m runway, what is the minimum uniform acceleration necessary for the plane to take flight if it starts from rest?

Answer:

3,4,5,6,7,8,9,10

3. lithium

4. beryllium

5. boron

6. carbon

7. nitrogen

8. oxygen

9. fluorine

10. neon

those are the numbers in period 2 on the periodic table.

Explanation:

Answer:

i believe the answer is 2.44140625 grams remaining

Answer:

4.88g

Explanation:

We must first calculate how many half-life there are in 18 hours, knowing that each half life takes 2 hours.

18/2 = 9 Half life

Now, knowing this we can calculate the number of grams by applying 9 times the half life.

2500/2= 4.88 grams

Which means that after 18 hours there are 4.88 grams.

Based on the given information, the most appropriate classification for the state of the volcano would be "Active-Dormant."

The volcano's history of generating multiple lava flows over the past 10,000 years indicates that it has been active in the relatively recent past. The presence of lava flows that have spread over large areas suggests ongoing volcanic activity, although not necessarily in the immediate present.

Additionally, the mention of very little tephra (volcanic ash and fragments) indicates that the volcano is not currently experiencing explosive eruptions. Instead, it has been primarily characterized by effusive eruptions that produce lava flows.

The fact that people in the nearby town remember the last eruption, which caused some forest fires, further supports the classification of the volcano as active-dormant. While the volcano may not be actively erupting at the moment, the memory of the recent eruption and the potential for future volcanic activity suggests that it is still in a state of activity, albeit in a relatively dormant phase.

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Answer:

Two

Explanation:

Here, the electron configuration of carbon (C) shows that two unpaired electrons exist. In this case, the valency of the carbon atom is 2. When the carbon atom is excited more than this, the electron configuration of carbon changes again. The 2nd electron configuration of a carbon atom in excited state is C* (6) = 1s 2 2s 1 2p x1 2p y1 2p z1 .

Explanation:

Over the first 30.0 s, the undergoes a displacement of

(12 m/s) * (30.0 s) = 360 m

Over the next 8.00 s, the car accelerates from 12 m/s to a top speed of

12 m/s + (1.5 m/s²) * (8.00 s) = 24 m/s

and over this time interval, it is displaced an additional

(12 m/s) * (8.00 s) + 1/2 (1.5 m/s²) * (8.00 s)² = 144 m

For the last 12.0 s, the car moves at a constant speed of 24 m/s to cover a distance of

(24 m/s) * (12.0 s) = 288 m

So the car's net displacement is 360 m + 144 m + 288 m = 792 m. (The net displacement is the same as distance in this case because the car moves in only one direction.)

The correct answer is B. According to Newton's law of universal gravitation, the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

In simpler terms, as objects get closer together, the gravitational force between them increases.

When the distance between two objects decreases, the denominator of the equation (distance squared) becomes smaller, resulting in a larger force. Conversely, when the distance increases, the denominator becomes larger, resulting in a smaller force.

It is important to note that the mass of an object does not directly affect the strength of the gravitational force between two objects. However, a higher mass will lead to a greater gravitational force when compared to a lower mass, but only because the force is being exerted on a more massive object. The mass of an individual object doesn't directly affect the gravitational force it experiences from another object. option B

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The given statement "in a pitch situation, a vehicle's weight moves to either the right or left of the vehicle" is false because, in a yaw situation, a vehicle weight moves to either the right or left around the center of gravity.

The Society of Automotive Engineers (SAE) describes Vehicle Dynamics as the relationship between the forces exerted on a vehicle and the resulting motion. Three important motions of a vehicle are pitch, yaw, and roll.

Thus, when a vehicle's weight moves either to right or left of the vehicle, it indicates a yaw situation.

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While a rock thrown upward at 50 degrees to the horizontal rises, neglecting air drag, its horizontal component of velocity remains unchanged.

The horizontal component of velocity refers to the velocity in the horizontal direction, which is perpendicular to the vertical direction of the rock's motion. Neglecting air drag means that no external force acts on the horizontal component of velocity. According to Newton's first law of motion, an object in motion will continue to move at a constant velocity in the absence of external forces.

In this case, as the rock rises vertically, its horizontal component of velocity remains unaffected by the vertical motion. The force of gravity acts vertically downward and does not affect the horizontal motion of the rock. Therefore, the horizontal component of velocity remains unchanged throughout the rock's upward trajectory.

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No because it fails the vertical line test

The vertical line test is a test used to determine whether a relation is a function. It states that a relation is a function if and only if any vertical line intersects the graph of the relation at most once.

If a relation fails the vertical line test, it means that there are two or more points on the graph with the same x-coordinate, and therefore, the relation is not a function.

Therefore, for a relation to be a function, it must pass the vertical line test.

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Answer:

Distance 14

Displacement 10

Explanation:

Answer:

13.636364 m/s2

Answer:

Vf=60m/s

Vi=0 because it starts from rest

t=4.4s

a=?

a=Vf-Vi/t

a=60-0/4.4

a=60/4.4

a=13.63m/s^2

the work done on the car by the force of its engine is 78,000 J.

" The work done on the car by the force of friction is 24,000 J.

Increasing the car's kinetic energy at the end of the first 100 m is 54,000J

a. Completed work = force x distance. Engine output = 780 N, that is,

780 N x 100 m = 78,000 J.

b. Completed work = force x distance. Friction force = 240 N, that is,

240 N x 100 m = 24,000 J.

c. Kinetic energy = 1 \ 2 x m x v2

= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.

Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.

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The diameter of the smallest jovian planet is 3.96 times larger than the diameter of the largest terrestrial planet.

The jovian planets or also called giant gaseous planets are those that are far away in the solar system, which includes Jupiter, Saturn, Uranus, and Neptune, while terrestrial rocky planets include Mercury, Venus, the Earth planet and Mars.

Therefore, with this data, we can see that the jovian and terrestrial planets are different based on the composition of their surfaces and also due to the distance to the Sun.

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