Starting from rest a car travels a distance 60km at a uniform acceleration of 2ms-2. How much time it takes?

Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

velocity of the bullet, v₀ = 250 m/s

mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

5 + 0 = v(2.02)

5 = 2.02v

v = 5/2.02

v = 2.48 m/s

Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

Answer:

C)Gravitational force would decrease by a factor of 2.

Explanation:

Hope this helps :)

Answer:

Hunubunununununununnunu

According to the question the initial kinetic energy of the bullet is 12 kg m²/s².

Kinetic energy is the energy of motion. It is the energy that an object has because of its motion. In other words, it is the energy possessed by a body due to its movement. Kinetic energy is measured in joules and is equal to the work done when an object is moved over a certain distance. Kinetic energy is always positive and is dependent on the mass of the object and its speed.

The initial kinetic energy of the bullet can be calculated using the equation KE = ½ mv², where m is the mass of the bullet (15 g) and v is the initial velocity of the bullet.
Plugging in the values, we get:
KE = ½ (15 g) (v²)
Plugging in the values, we get:
v = 8 mm/ 0.0010 s
Substituting the value of v into the equation for KE, we get:
KE = ½ (15 g) (8 mm/ 0.0010 s)²
Simplifying the equation, we get:
KE = 12 kg m²/s²
Therefore, the initial kinetic energy of the bullet is 12 kg m²/s².

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Taking into account the Newton's second law, the acceleration of the 100 g mass is 50 m/s².

Newton's second law states that this force will change the speed of an object because the acceleration and/or direction will change.

So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object:

F= m×a

where:

In this case, you know:

Replacing in Newton's second law:

5 N= 0.1 kg× a

Solving:

a= 5 N÷ 0.1 kg

a= 50 m/s²

Finally, the acceleration is 50 m/s².

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One of the most significant observations that has provided the most accurate values of the age, dark matter, dark energy content, and the average density of the universe is the cosmic microwave background (CMB) radiation.

The CMB radiation is the afterglow of the Big Bang and is a remnant of the hot, dense early universe. The CMB radiation provides a snapshot of the universe when it was only 380,000 years old, and its properties can be analyzed to infer the universe's current state.

By analyzing the CMB radiation, cosmologists have determined that the universe is approximately 13.8 billion years old. Furthermore, they have found that dark matter constitutes around 27% of the universe's total energy density, and dark energy constitutes around 68%.

The CMB radiation has also provided insight into the universe's average density. By measuring tiny fluctuations in the CMB, scientists have determined that the average density of the universe is very close to the critical density required for a flat universe. This result is consistent with the inflationary Big Bang model and the concept of a flat universe.

Therefore, the observation of the cosmic microwave background radiation has been crucial in providing some of the most accurate values of the age, dark matter, and dark energy content, and the average density of the universe.

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Answer:

Distance: 32 km

Displacement: 18 km

Explanation:

Distance is the total amount travelled. Displacement on the other hand is how far away an object is from its starting point.

Distance is a scalar quantity meaning it only has magnitude. Displacement is a vector quantity meaning it has magnitude and direction.

Distance is represented by "x" while displacement is represented as "Δx".

Note that "Δ" is the Greek letter "delta" which is used to represent a change in something.

Let's start by finding the distance.

Since distance is the total amount travelled, we can just add all of the values.

9km + 18km + 5km = 32 km

Then, we can find the displacement.

North and East are positive while South and West are negative.

If the athlete ran 9km East and 5km West, their displacement would be:

9km - 5km = 4km East

Now, we can set up a triangle to determine the displacement from the starting point.

18km North would be the longer leg, 4km East would be the shorter leg, and the displacement would be the hypotenuse.

Using Pythagorean's Theorem we find that:

\(a^2+b^2=c^2\\4^2+18^2=c^2\\16+324=c^2\\340=c^2\\c\approx18\)

Note that "a" and "b" represent the legs of the triangle while "c" represents the hypotenuse of the triangle.

The displacement is approximately 18m.

Answer:

Explanation:

Radius of first spherical ball =

2

2

​

cm=1cm

Radius of second spherical ball =

2

2

3

14.5

​

​

cm=

3

14.5

​

cm

Let the radius of the third ball be r cm.

Radius of the main spherical ball =

2

5

​

cm=2.5cm

Volume of main spherical ball = Volume of spherical ball  1+Volume of spherical ball 2+ Volume of spherical ball 3

Volume of a sphere =

3

4

​

πr

3

So,  

3

4

​

π×2.5

3

=

3

4

​

π1

3

+

3

4

​

π(

3

14.5

​

)

3

+

3

4

​

πr

3

⇒2.5

3

=1

3

+(

3

14.5

​

)

3

+r

3

⇒r

3

=15.625−1−14.5

⇒r

3

=0.125=0.5×0.5×0.5

⇒r=0.5

Answer:

Light waves are produced by vibrating electric charges

Explanation:

The smallest area that the window could be is 10200cm^2.

To find the area of a window, you need to measure its length and width, and then multiply them. The formula is:

Area = Length x Width.

We can see that the smallest area that the window could be would look at the lower values of the length and the width of the window so we would have;

Lower part of the length = 150 cm

Lower part of the width = 68 cm

Then the area would be now;

150 cm * 68 cm

= 10200cm^2

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An engine can be cool down by the below steps

Knowing how to cool an overheated engine is a significant expertise for any authorized driver. Having the option to analyze and fix your own issues can get you back out and about rapidly, forestall exorbitant mechanical issues, and assist you with realizing when to look for proficient assistance.

Steps which I can take to cool down an overheated engine of car:

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The lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

(a) μ = 0

The heavier block will accelerate to the right with an acceleration of:

a = F / m = k x / m = (3.70 N/m) (0.0864 m) / 0.261 kg = 1.22 m/s²

The lighter block will also accelerate to the right with an acceleration of 1.22 m/s².

(b) μ = 0.110

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m) (0.0864 m) / 0.261 kg - (0.110)(0.261 kg)(9.80 m/s²) = 0.68 m/s²

The lighter block will not accelerate because the force of friction is greater than the force of the spring.

(c) μ = 0.480

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m)(0.0864 m) / 0.261 kg - (0.480)(0.261 kg) (9.80 m/s²) = -0.82 m/s²

Therefore, the lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

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Answer:

A

Explanation:

Hooke's law! F(spring)=-kx

There's no tricky square law here. The spring constant doesn't change, only x (distance stretched) changes. Therefore, if distance is halved, Force will be halved.

The mass of air in the room is 604.8 kg

The volume of air in the room is:

Volume = length × width × height

= 10 m × 12 m × 4 m

= 480 cubic meters

The mass of air in the room can be calculated using the density of air:

Mass = Density × Volume

= 1.26\(kg/m^3\) × 480 \(m^3\)

= 604.8 kg

Therefore, the mass of air in the room is 604.8 kg

The mass of air in a given space can be calculated by multiplying the density of the air by the volume of the space. The density of air at a given temperature and pressure can be found in reference tables or online sources. Once the density is known, the volume of the space can be measured using appropriate tools and the mass of the air can be calculated.

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When a positive charge moves in the presence of a magnetic field, it experiences a force that is perpendicular to both its direction of motion and the direction of the magnetic field. This is known as the magnetic force or the Lorentz force.

In each of the six cases shown in the diagram, the direction of the magnetic force on the positive charge can be determined using the right-hand rule. Here are the steps to use the right-hand rule:1. Point the thumb of your right hand in the direction of the velocity of the positive charge.

Curl your fingers in the direction of the magnetic field.3. The direction in which your palm faces is the direction of the magnetic force on the positive charge.Using this rule, we can determine the direction of the magnetic force in each of the six cases as follows.The magnetic force is downwards4. The magnetic force is upwards5. The magnetic force is to the left6.

The magnetic force is to the right In summary, the direction of the magnetic force on a positive charge that moves in the presence of a magnetic field can be determined using the right-hand rule. The direction of the magnetic force is perpendicular to both the velocity of the charge and the direction of the magnetic field.

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Answer:

(a) 3.22 m

(b) The vertical velocity, \(v_y\), at maximum height is 0 m/s, the horizontal velocity, vₓ, is 12.72 m/s

(c) The acceleration at maximum height = g = 9.81 m/s²

(d) The time it takes for the paper to reach the balcony is 1.212 seconds

(e) The horizontal range, of the paper is 15.42 m.

Explanation:

(a) Given that we re given a projectile motion, we have the following governing equations;

y = y₀ + v₀·sin(θ₀)·t - 0.5×g·t²

\(v_y\) = v₀·sin(θ₀) - g·t

Where:

y = Height of the paper

y₀ = Initial height of the paper = Ground level = 0

v₀ = Inititial velocity of the paper = 15.0 m/s

θ₀ = Angle in which the paper is thrown = 32° above the horizontal

g = Acceleration due to gravity = 9.81 m/s²

t = Time taken to reach the height h

\(v_y\) = Vertical velocity of the paper

At maximum height, \(v_y\) = 0, therefore;

\(v_y\) = v₀·sin(θ₀)·t - g·t = 0

v₀·sin(θ₀) = g·t

t = v₀·sin(θ₀)/g = 15×sin(32°)/9.81 = 0.81 seconds

y = y₀ + v₀·sin(θ₀)·t - 0.5×g·t² = 0 + 15×sin(32°)×0.81-0.5×9.81×0.81² = 3.22 m

(b) The vertical velocity, \(v_y\), at maximum height = 0 m/s, the horizontal velocity, vₓ, = 15×cos(32°) = 12.72 m/s

(c) The acceleration at maximum height = g = 9.81 m/s²

(d) The time it takes to maximum height = 0.81 seconds

The time the paper will take to fall to 1.25 m above the ground, which is 3.22 - 1.25  = 1.97 meters below maximum height is therefore given as follows;

y = y₀ + v₀·sin(θ₀)·t - 0.5×g·t²

Where:

v₀ = 0 m/s at maximum height

y = -1.97 m downward motion

y₀ = 0 starting from maximum height downwards

1.97 = 0 + 0·sin(θ₀)·t - 0.5×9.81×t²

-1.97 =  - 0.5×9.81×t²

t = (-1.97)/(-0.5*9.81) = 0.402 seconds

The time the paper will take to fall to 1.25 m above the ground = 0.81+0.402 = 1.212 seconds

Therefore, the time it takes for the paper to reach the balcony = 1.212 seconds

(e) The horizontal range, x, is given by the relation;

x = x₀ + v₀·cos(θ₀)·\(t_{tot}\)

x₀ = Starting point of throwing the paper = 0

\(t_{tot}\) = Total time of flight of the paper

∴ x = x₀ + v₀·cos(θ₀)·\(t_{tot}\) = 0 + 15×cos(32°)×1.212 = 15.42 m

The horizontal range, of the paper = 15.42 m.

Following are the values:

Weight of the box: 147 N

Normal force: 127.05 N

Maximum static friction force: 40.66 N

Net force on the box: 57.83 N

Acceleration of the box: 3.855 m/\(s^2\)

To solve the problem, we can use the principles of Newtonian mechanics and consider the forces acting on the box.

1. Determine the gravitational force:

The weight of the box can be calculated as follows:

Weight = mass * acceleration due to gravity

Weight = 15 kg * 9.8 m/\(s^2\)

Weight = 147 N

2. Determine the normal force:

The normal force is the force exerted by the ramp perpendicular to its surface. It can be calculated using trigonometry:

Normal force = Weight * cos(angle of the ramp)

Normal force = 147 N * cos(30°)

Normal force = 127.05 N

3. Determine the maximum static friction force:

The maximum static friction force is given by:

Maximum static friction force = coefficient of static friction * normal force

Maximum static friction force = 0.32 * 127.05 N

Maximum static friction force = 40.66 N

4. Determine the net force on the box:

The net force acting on the box can be calculated by subtracting the friction force from the gravitational force:

Net force = Weight * sin(angle of the ramp) - friction force

Net force = 147 N * sin(30°) - 40.66 N

Net force = 98.49 N - 40.66 N

Net force = 57.83 N

5. Determine the acceleration of the box:

Using Newton's second law (F = ma), we can solve for the acceleration:

Net force = mass * acceleration

57.83 N = 15 kg * acceleration

acceleration = 57.83 N / 15 kg

acceleration = 3.855 m/\(s^2\)

Therefore, the box will experience an acceleration of 3.855 m/\(s^2\) while moving up the ramp.

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Hi there!

Part 1:

If the blocks are moving at a constant velocity:

∑F = 0

Begin by summing the forces acting on each block. Let the upward direction be positive.

∑F₁ = Ta - M₁g - Tb

∑F₂ = Tb - M₂g

Sum the forces:

∑F = Ta - M₁g - Tb + Tb - M₂g

∑F = Ta - M₁g - M₂g = 0

Solve for Tension A:

Ta = M₁g + M₂g (Let g = 9.8 m/s²)

Ta = 4.2(9.8) + 2.6(9.8) = 66.64 N

Now, solve for tension B using the summation of ∑F₁:

0 = Tb - M₂g

Tb = (2.6* 9.8) = 25.48 N

Part 2:

We can use the same method, but incorporate the acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

(M₁ + M₂)a + M₁g + M₂g = Ta

(4.2 + 2.6)(1.2) + 4.2(9.8) + 2.6(9.8) = 74.8 N

∑F₂ = Tb - M₂g

M₂a + M₂g = Tb  = 28.6 N

Part 3:

Since the top string experiences most of the tension, we can use its equation to calculate the maximum acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

a = (90 - M₁g - M₂g)/(M₁ + M₂)

a = 3.435 m/s²

Answer:

Since 10 J / 4.19 J /cal = 2.39 cal     is the heat absorbed by the ring

Q = Cs * m * (T2 - T1)      heat absorbed by ring

Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C)

10 J / 4.19 J /cal = 2.39 cal     is the heat absorbed by the ring, Q = Cs * m * (T2 - T1)      heat absorbed by ring. Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C).

The amount of heat required to raise the temperature per unit mass is known as specific heat capacity. The heat in Joules required to increase the temperature of 1 gram of sample by 1 Kelvin or degree Celsius is typically stated.

Water is an excellent temperature regulator because it has a very high specific heat capacity.

The amount of heat in joules needed to raise 1 gram of a substance by 1 Kelvin is known as the specific heat capacity (symbol: c). It could also be written as J/kgK. Molar heat capacity, measured in J/mol K, and volumetric heat capacity, measured in J/m3 K, are comparable values.

Therefore, 10 J / 4.19 J /cal = 2.39 cal     is the heat absorbed by the ring, Q = Cs * m * (T2 - T1)      heat absorbed by ring. Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C).

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The expression for the capacitance per meter of a coaxial cable is C = \frac{2\pi\epsilon_0}{\ln(b/a)}

The capacitance per unit length of a coaxial cable with inner radius a and outer radius b is given by:

C = \frac{2\pi\epsilon_0}{\ln(b/a)}

where \epsilon_0 is the permittivity of free space.

To find the capacitance per meter of the coaxial cable, we divide this expression by the length of the cable, L:

C_{\text{per meter}} = \frac{C}{L} = \frac{2\pi\epsilon_0}{L\ln(b/a)}

Since the cable is assumed to have air as the insulating material between the cylinders, we can assume that \epsilon_r = 1 and \epsilon = \epsilon_0 (the permittivity of free space), which gives us the above expression.

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Example of an elastic product: Smartphone

Explanation: A smartphone is an example of an elastic product. When the price of smartphones decreases, consumers tend to buy more of them, and when the price increases, consumers tend to buy fewer.

Example of an inelastic product: Prescription medication

Explanation: Prescription medication is an example of an inelastic product. Inelastic goods are those for which changes in price have little impact on the quantity demanded.

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A product concept is a detailed version of a new product idea stated in a way that consumers find meaningful; a is the way consumers perceive the actual or potential product.

A product may be described as- “an amazing, idea, approach, records, item, or carrier this is the quit end result of a procedure and serves as a want or want satisfier. it also includes a package deal of tangible and intangible attributes (benefits, functions, functions, makes use of) that a vendor offers to a consumer for buy.”

A purchaser is a person or a set who intends to reserve, or uses purchased goods, merchandise, or offerings normally for private, social, own family, family and comparable wishes, who isn't always without delay related to entrepreneurial or business sports. The time period maximum generally refers to someone who purchases items and offerings for non-public use.

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\(\\ \tt\bull\leadsto Speed=\dfrac{Distance}{Time}\)

\(\\ \tt\bull\leadsto Speed=210/35=6m/s\)

Answer:

6m per second

Explanation:

Distance=210m

Time=35s

speed=distance/time

speed= 210/35=6ms

Answer:

A bar magnet creates a magnetic field around it. The field cannot be seen, but its effects can be observed. This is how the magnetic field around a magnet is detected. Iron fillings can be used to study the presence of magnetic field and a compass can be used to plot the field lines.

Explanation:

The reflecting surface is 1.5*105 kilometers away from the source. Since the wave reflected back, it meets the criteria for an echo according to the definition: v = 2d/t, v = 3*108, t = 1*10-3, 3*108 = 2d/(1*10-3), 2d = 3*108*1*10-3, d = 300000/2, and d = 1.5*105 km.

Velocity, as opposed to speed, refers to the pace and directions of an object's movements as it moves down a path. Unlike velocity, which is a vector, speed is a scalar quantity.

Velocity is the rate at which displacement changes. The pace upon which speed increases is referred as accelerator. Because it consists of both the magnitude and direction, velocity is an vector quantity. Since acceleration is merely the rate at which velocity changes, it too is a vector quantity.

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Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load  distance=10 cm

We have to find the effort distance.

We know that

\(load\times load\;distance=Effort\times effort\;distance\)

Using the formula

\(800\times 10=200\times effort\;distance\)

Effort distance=\(\frac{800\times 10}{200}\)

Effort distance=\(\frac{8000}{200}\)

Effort distance=40 cm

Hence,  the effort distance will be 40 cm.

Answer:

10

Explanation:

Answer:

Explanation:

Using the formula

v = fλ

v is the speed

f is the frequency

λ is the wavelength

Given the following

v = 332m/s

Frequency is the number of oscillation completed in one second. Since 332 waves passes through a medium in one second, hence the frequency us 222 Hertz

From the formula

λ = v/f

λ = 332/332

λ = 1m

Hence the wavelength is 1m