The statement "velocity and acceleration are out of phase by a quarter of a period, which means that their graphs have the same shape but are shifted in time" is True.
This is because the motion of an object is determined by its position, velocity, and acceleration, and these three quantities are related to one another through calculus.
In simple words, the velocity is the rate of change of position with respect to time, whereas acceleration is the rate of change of velocity with respect to time.
When an object is oscillating, its velocity and acceleration graphs are sinusoidal, which means they follow a wave-like pattern.
The velocity graph lags behind the position graph by a quarter of a period, and the acceleration graph lags behind the velocity graph by another quarter of a period, making it a half period behind the position graph.
This is because the velocity is at its maximum when the position is at its equilibrium point, whereas the acceleration is at its maximum when the velocity is zero.
Because the velocity and acceleration graphs are sinusoidal, they have the same shape but are shifted in time. This can be demonstrated mathematically by using the trigonometric functions sine and cosine.
The sine function represents the position or displacement of an object as a function of time, whereas the cosine function represents the velocity or rate of change of position as a function of time.
The derivative of the cosine function is the negative sine function, which represents the acceleration or rate of change of velocity as a function of time.
Therefore, the statement "velocity and acceleration are out of phase by a quarter of a period, which means that their graphs have the same shape but are shifted in time" is true.
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a laser beam is deflected 22.6 degrees by a 30 60 90 prism while passing horizontally through. what is the prism's index of refraction?
Prism index of refraction is 2.40 if it is deflected by 22.6degrees by a 30-60-90 prism.
Refraction of light is perhaps of the most ordinarily noticed peculiarity, however different waves like sound waves and water waves additionally experience refraction. Refraction makes it feasible for us to have optical instruments, for example, amplifying glasses, focal points and crystals. It is likewise a result of the refraction of light that we can shine light on our retina..
Applying Snell's law at the point of refraction we get
μ₁sinθ₁ = μ₂sinθ₂
where μ₁ is refractive index of the prism,
μ₂ is the refractive index of the air,
sinθ₁ is the angle made by light with prism
and sinθ₂ is the angle made by light beam with air medium.
Now,we know that μ₂=1,θ₁ =22.6°,θ₂=90° - 22.6°=67.4°,μ₁=?
On putting we,get
=>μ₁ ˣ sin(22.6°)= 1 ˣsin(67.4°)
=>μ₁=sin(67.4°)/ sin(22.6°)
=>μ₁=0.923/0.384
=>μ₁=2.403
Hence, prism index of refraction is 2.403.
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HELP DUE IN AN HOUR!! said last answer choice was incorrect.
The momentum of a 5-kilogram object moving at 6 meters per second is-
The momentum of an object is 30 kgm/s . This can be calculated by using momentum formula see description below.
What is momentum?It is defined as the product between mass and velocity. Its symbol is p.
It is given by:
p = m * v
What information do we have?
Mass = 5kg
Velocity = 6 m/s
To find:
Momentum=?
On substituting the values:
p = m * v
p =5 kg * 6 m/s
p = 30 kgm/s
Thus, the momentum of an object is 30 kgm/s.
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What is the rate at which work is done?
Answer:
The rate at which work is done would be power. Bonus: The SI unit of work is Joules.
Explanation:
Hope this helped, nya~ :3
As a general rule, the normal distribution is used to approximate the sampling distribution of the sample proportion only if:
the underlying population is normal.
the population proportion rhorho is close to 0.50
None of the suggested answers are correct
the sample size ηη is greater than 30
np(1 - p) > 5
The correct answer for normal distribution is "np(1 - p) > 5".
The normal distribution is used to approximate the sampling distribution of the sample proportion only if the sample size is large enough, which is determined by the formula np(1 - p) > 5, where n is the sample size and p is the sample proportion. This criterion ensures that the sampling distribution is approximately normal, even if the underlying population is not normal or the population proportion is not close to 0.5.
Therefore, if the sample size is smaller than 30 and/or np(1 - p) is not greater than 5, the normal distribution may not be an appropriate approximation for the sampling distribution of the sample proportion. In those cases, other methods, such as the t-distribution or the binomial distribution, may be more appropriate.
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Electrostatic pressure derives from?
The distribution of electrical charges results in electrostatic pressure.
In the field of physics known as electrostatics, static electric charges are studied (static electricity). Some materials, like amber, have been known to capture light particles after rubbing since classical times. The word "electricity" thus derives from the Greek word for amber. Electric charges exert forces on one another, which results in electrostatic phenomena. Coulomb's law describes these forces.
The tension that builds up inside the sphere due to the charges in the same sphere repelling one another is known as electrostatic pressure. Like how a rubber band would be stretched from all points outward, stress would form in it. By maintaining electrostatic pressure and diffusion on the potassium cation, the resting membrane potential is kept constant.
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Un vehículo que desciende hacia la luna tiene una velocidad vertical hacia la superficie de la luna de 35 m/s. Al mismo tiempo, tiene una velocidad horizontal de 55m/s. ¿Cuál es la velocidad del vehículo en su trayectoria de descenso? ¿Qué ángulo forma la trayectoria con la vertical?
Answer:
1. La velocidad del vehículo en su trayectoria de descenso es 65.2 m/s.
2. El vehículo forma un ángulo de 57.5° con la vertical.
Explanation:
1. La magnitud de la velocidad del vehículo está dada por la suma de las componentes del vector en la dirección vertical (y) y horizontal (x):
\( v^{2} = v_{x}^{2} + v_{y}^{2} \)
\( v = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(55 m/s)^{2} + (35 m/s)^{2}} = 65.2 m/s \)
Entonces, la velocidad del vehículo en su trayectoria de descenso es 65.2 m/s.
2. El ángulo que forma la trayectoria con la vertical se puede calcular con trigonometría:
\( tan(\theta) = \frac{v_{x}}{v_{y}} \)
\( \theta = tan^{-1}(\frac{v_{x}}{v_{y}}) = tan^{-1}(\frac{55}{35}) = 57.5 ^{\circ} \)
Por lo tanto, el vehículo forma un ángulo de 57.5° con la vertical.
Espero que te sea de utilidad!
The net force on a moving object suddenly becomes zero and remains zero. the object will:_________-
If the net force on an object becomes zero and remains zero, the object will continue to move at constant velocity.
The net force acting on a body is the addition or the resultant of all the forces acting on the body. When the net force acting on a body is more than zero, it causes motion, but when it is zero, the object will remain at rest or will continue moving with uniform velocity.
This is in line with Newton's first law of motion which states that "a body will continue in its state of rest or will continue to move with uniform velocity unless it is acted upon by a force".
Thus, when the net force on a moving body becomes zero, it will not slow down or speed up, it will continue to move at the same speed. An example of this is when the passengers of a moving car fall forward when the car suddenly comes to a stop.
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Astronauts aboard the ISS appear as if they are floating
a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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1) A 1,600 kilogram car is also traveling in a straight line. Its momentum is 32,500 kg*m/s. What is the
velocity of the car?
Answer:
v = 20.31 m/s
Explanation:
p = mv -> v = p/m = 32,500 kg*m/s / 1,600 kg = 20.31 m/s
what type of stars can collapse in a supernova explosion and become neutron stars
Answer:
red supergiants can
an alligator crawls 25m to the left with an average velocity of -1.2m/s. how many seconds did the alligator crawl?
The time taken to cover a distance is the distance divided by velocity. The alligator will take 20.8 seconds to crawl 25 m with a velocity of 1.2 m/s.
What is velocity ?Velocity of an object is the measure of the distance covered by it per unit time. It is the rate of its speed. Velocity is a vector quantity thus, having magnitude and direction.
The higher the velocity, greater will be the distance covered within short time. Velocity is the ratio of change in distance to the change in time. It has the common unit of m/s.
Given that, distance covered by the alligator = 25 m
velocity = 1.2 m/s
then time = distance / velocity
t = 25 m/ 1.2 m/s = 20.8 s.
Therefore, the alligator crawls 20.8 seconds to reach 25 m.
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Two hockey pucks, each with a mass of 0.2 kg, slide across the ice and
collide. Before the collision, puck 1 is moving 16 m/s to the east and puck 2 is
moving 11 m/s to the west. After the collision, puck 1 is moving at 11 m/s to
the west. What is the velocity of puck 2?
A. 16 m/s west
B. 16 m/s east
C. 11 m/s east
D. 11 m/s west
HELPPP PLEASE I HAVE NO IDEA HOW TO DO THIS
Puck 1 after collision with Puck 2 moves towards the west with a speed of 11 m/s, so Puck 2 will move towards the east with a speed of 16 m/s. Hence, option B is correct.
What is collision?A collision, also known as an impact, occurs when two entities, such as two pool pieces, a country club, and a ball, a mallet and a nail, two rail cars when joined, or a tumbling object and a floor, suddenly and violently collide in close proximity to one another. The consequence of the impact is affected by the force, the length of time the items are in contact, the materials the two objects are made of, and other factors. According to conventional knowledge, a high-strength steel ball will rebound almost to the same spot from which it was dropped, in contrast to a mud or lead ball.
All of the kinetic energy of the colliding bodies is lost in a fully elastic impact, while the loss of kinetic energy is greatest in a perfectly plastic impact.
Therefore, the velocity of Puck 2 is 16 m/s towards the east direction.
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Describe how reactivity changes as you go down Group 1A.
Answer:
it is a the answer is a btw
Explanation:
at what distance from a 2.45*10^-6 C charge will the electric field be 100 N/C?
Answer:14.8
Explanation:
Trust me
The distance will be = 14.85 m
What is electric field ?A region around a charged particle or object within which a force would be exerted on other charged particles or objects.
given :
Charge (q)= 2.45*\(10^{-6}\) C
Electric field (EF) = 100 N/C
to find = ? distance (r)
Electric field = 1/4π∈o * (q/\(r^{2}\))
100 = 9 * \(10^{9}\) * ( 2.45*\(10^{-6}\) / \(r^{2}\))
\(r^{2}\) = 220.5
r= \(\sqrt{220.5}\)
r = 14.85 m
The distance will be = 14.85 m
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From this information, Jasmine concludes that "fertilizer b" is the best at increasing crop yields. Is Jasmine's conclusion scientifically valid? A. Yes, because "fertilizer b" increased her crop yield. B. No, because the different sections of her land were not equal in area. C. No, because the different sections of her land have different characteristics. D. No, because the crop yields were all equal.
Answer:
c
Explanation:
i just did this study island and the answer was wrong
how was mugabe able to build power and what type of power base
is he
Mugabe gained power by using political strategies, forming alliances, and exploiting his status as a liberation hero within ZANU-PF.
Robert Mugabe, the former president of Zimbabwe, was able to build power through a combination of political strategies and alliances. One key factor was his involvement in the liberation struggle against white minority rule in Rhodesia (now Zimbabwe).
Mugabe emerged as a prominent figure within the Zimbabwe African National Union (ZANU) party, which later merged with the Zimbabwe African People's Union (ZAPU) to form the Zimbabwe African National Union - Patriotic Front (ZANU-PF). Mugabe's role as a liberation hero and his ability to mobilize support among the majority black population of Zimbabwe gave him a strong power base.
Within ZANU-PF, Mugabe strategically positioned himself and gained influence by forming alliances and outmaneuvering rivals. He rose to become the party's leader and played a key role in negotiating the Lancaster House Agreement in 1979, which paved the way for Zimbabwe's independence in 1980. Mugabe became the country's first prime minister and later transformed the position into an executive presidency, consolidating his authority.
Mugabe maintained power through various means, including controlling key institutions such as the military, intelligence agencies, and the ruling party. He also utilized patronage networks, distributing resources and positions to loyal supporters within the party and government. Mugabe's policies, such as the controversial land reform program, further solidified his power base by appealing to nationalist sentiments and redistributing land from white farmers to black Zimbabweans.
However, Mugabe's consolidation of power was also marked by authoritarianism, human rights abuses, and a declining economy. His grip on power faced challenges over the years, including opposition movements, internal party factions, and economic crises. Ultimately, his rule came to an end in 2017 when he was ousted from power following a military intervention.
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If light travels at 3.00 x 10° m/s, how long does it take light from lightning to reach your house if the bolt was 6.4 x 103
m away from your house?
Answer:
2.13 x 10^-5
Explanation:
light travels at 3.00 x 10^8 m/s
it's like if someone asks how long would it take for a car to go 100 miles if it's traveling 50 miles per hour
you would do
100 ÷ 50
6.4 x 10^3 ÷ 3.00 x 10^8
2.13 x 10^-5
Which statement best describes how scientists and engineers work together in the research and development cycle? A. Scientists test designs made by engineers and then use the results to improve the designs. B. Scientists develop a new technology, and then engineers test it by doing experiments. C. Engineers come up with scientific questions when they are developing their design, and scientists do research to answer them. O D. Engineers make a scientific discovery, and then scientists perform research to verify it. please help asap if you can
C. Engineers come up with scientific questions when they are developing their design, and scientists do research to answer them
What is the mass of an object that has 795J of moving kinetic energy and is moving at 3.5 m/s ?
Given data
*The given energy is k = 795 J
*The speed of the object is v = 3.5 m/s
The formula for the kinetic energy of the object is given as
\(k=\frac{1}{2}mv^2\)*Here m is the mass of the object
Substitute the known values in the above expression as
\(\begin{gathered} 795=\frac{1}{2}m(3.5)^2 \\ m=129.79\text{ kg} \end{gathered}\)Hence, the mass of the object is m = 129.79 kg
Unpolarized light of intensity I_0 is incident on a stack of 7 polarizing filters, each with its axis rotated 15 (degrees) cw with respect to the previous filter.
Part A
What light intensity emerges from the last filter?
Each polarizing filter will only allow light waves that are oscillating in a plane perpendicular to its axis to pass through, while blocking those oscillating parallel to its axis.
Since the axis of each filter is rotated by 15 degrees with respect to the previous filter, the intensity of the light passing through will decrease by a factor of cos^2(15) for each filter, where cos(15) is the cosine of 15 degrees. Therefore, the intensity of the light emerging from the last filter will be I_0 * cos^2(15) raised to the power of 7, as there are 7 filters in the stack. This can be calculated as approximately 0.048 I_0 or about 4.8% of the original intensity I_0.
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Gravitational potential energy (Eg) and kinetic energy (Ek)
A 70.0 kg athlete is running at a 12m/s in the 100.0m dash. What is the kinetic energy of the athlete?
Answer:
hope it will help you
Explanation:
Answer:
\(\boxed {\boxed {\sf E_K= \ 5,040 \ J}}\)
Explanation:
Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:
\(E_K= \frac{1}{2} mv^2\)
The mass of the athlete is 70.0 kilograms. The velocity is 12 meters per second.
m= 70.0 kg v= 12 m/sSubstitute the values into the formula.
\(E_K= \frac{1}{2} (70.0 \ kg)(12 \ m/s)^2\)
Solve the exponent.
(12 m/s)² = (12 m/s)(12 m/s) = 144 m²/s²\(E_K= \frac{1}{2} (70.0 \ kg)(144 \ m^2/s^2)\)
Multiply the numbers together.
\(E_K= \frac{1}{2} (10, 080 \ kg*m^2/s^2)\)
\(E_K= 5,040 \ kg*m^2/s^2\)
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer is equal to 5,040 Joules.
\(E_K= 5.040 \ J\)
The athlete has 5,040 Joules of kinetic energy.
Need help on this or I’ll completely fail the last semester
Answer:
Its A I'm 99.9% sure
Explanation:
How is the density of a fish controlled? how is the density of a submarine controlled?
The density of a fish is controlled by the expansion and contraction of its air sacs while the density of a submarine is controlled by ballast tanks. It was emphasized earlier that buoyant forces does not equal an objects weight but does equal the weight of displaced water.
What are mass, density, and volume ?The three most fundamental characteristics of an object are mass, volume, and density. Volume indicates something's size, mass indicates how heavy it is, and density is calculated as mass divided by volume. Although you deal with mass and volume on a daily basis, the concept of density is less clear-cut and requires careful consideration.
Mass divided by density equals volume; and. Volume times density equals mass. A liquid's density is a gauge of how heavy it is relative to the amount being measured. The liquid that weighs heavier is more dense if you weigh two liquids with similar volumes or amounts.
The relationship between a substance's mass and the amount of space it occupies is known as its density (volume). The density of a substance is determined by the mass, size, and arrangement of its atoms.
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In an amusement park ride called The Roundup, passengers stand inside a 18.0 m-diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figure .
A)Suppose the ring rotates once every 4.40 s. If a rider's mass is 59.0 kg, with how much force does the ring push on her at the top of the ride?
B)Suppose the ring rotates once every 4.40 s. If a rider's mass is 59.0 kg, with how much force does the ring push on her at the bottom of the ride?
C)What is the longest rotation period of the wheel that will prevent the riders from falling off at the top?
a. The ring pushes on the rider with a force of 4.13 × 10^3 N at the top of the ride.
b. The ring pushes on the rider with a force of 5.81 × 10^3 N at the bottom of the ride.
c. The longest rotation period of the wheel that will prevent the riders from falling off at the top is 6.02 s.
A) At the top of the ride, the rider is in circular motion due to the normal force provided by the ring. The force of gravity acts downwards and the normal force acts upwards. The net force acting on the rider at the top is equal to the centripetal force required for circular motion.
The centripetal force is given by:
Fc = mv²/r
where m is the mass of the rider, v is the velocity of the rider in circular motion, and r is the radius of circular motion.
The velocity of the rider can be found from the period of rotation:
T = 2πr/v
v = 2πr/T
Substituting this expression for v into the expression for Fc, we get:
Fc = m(2πr/T)²/r = 4π²mr/T²
At the top of the ride, the normal force is equal to the centripetal force:
Fn = Fc = 4π²mr/T²
Substituting the given values, we get:
Fn = 4π²(59.0 kg)(9.81 m/s²)(9.00 m)/(4.40 s)² = 4.13 × 10³ N
B) At the bottom of the ride, the rider is still in circular motion due to the normal force provided by the ring. The force of gravity acts downwards and the normal force acts upwards. The net force acting on the rider at the bottom is equal to the sum of the centripetal force required for circular motion and the force of gravity:
Fnet = mv²/r + mg
where m is the mass of the rider, v is the velocity of the rider in circular motion, r is the radius of circular motion, and g is the acceleration due to gravity.
Using the same expressions for v and Fc as in part A, we can rewrite the above equation as:
Fnet = Fc + mg = 4π²mr/T² + mg
At the bottom of the ride, the normal force is equal to the net force:
Fn = Fnet = 4π²mr/T² + mg
Substituting the given values, we get:
Fn = 4π²(59.0 kg)(9.81 m/s²)(9.00 m)/(4.40 s)² + (59.0 kg)(9.81 m/s²) = 5.81 × 10³ N
C) The condition for the rider to not fall off at the top of the ride is that the centripetal force required for circular motion is greater than or equal to the force of gravity:
Fc ≥ mg
Substituting the expression for Fc from part A and solving for T, we get:
T ≤ 2π√(r/g)
Substituting the given values, we get:
T ≤ 2π√(9.00 m/9.81 m/s²) = 6.02 s
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A mass of 32 kg is being pulled by a rope with a force of 148 N at an angle of 22°. What is the work done on the mass if it has been moved 7.4 m? Input your answer with 1 decimal place
Answer:
W=mg=22.5 kg×9.8 m/s2=220.5 N W = m g = 22.5 kg × 9.8 m/s 2 = 220.5 N . By Newton's third law, we realize that the normal force exerted by the table on the box is equal to this value. The underlying logic is that the box is at rest, implying that the net force on it is zero.
a car travels at 90 km per hour how much distance in metre does the car travel in 25 seconds
Answer:
90000m÷3600s=25m25m×25s=625msConvert 60000cm to m
Answer:
The answer is 600 using metric system
Answer:
600 cm
Explanation:
60,000 ÷100=600
Need a quick answer for this one.
Answer:
mass
Explanation:
The formula based on Newton's second law: F = ma
where F is force. m is mass and a is acceleration.
in the question they said F = ka
k constant is actually the mass of the object
Answer:
mass
Explanation:
Need a quick answer for this one.