Sound is detected when a sound wave causes the eardrum to vibrate. typically, the eardrum has a diameter of 8.4mm in humans. 5.54 watts of energy is delivered to the eardrum each second when someone whispers (20 dB) in your ear.
To calculate the energy delivered to the eardrum each second when someone whispers in your ear, we need to consider the sound intensity and the effective area of the eardrum.
Given:
Diameter of the eardrum (d) = 8.4 mm = 0.0084 m
Sound intensity (I) = 20 dB
First, we need to convert the diameter of the eardrum to radius (r):
r = d / 2
r = 0.0084 m / 2
r = 0.0042 m
The effective area of the eardrum (A) can be calculated using the formula for the area of a circle:
A = π * r²
A = π * (0.0042 m)²
A = 0.0554 m²
Next, we need to convert the sound intensity from decibels (dB) to watts per square meter (W/m²). The formula for this conversion is:
I (W/m²) = \(10^{(I (dB) / 10)}\)
I (W/m²) = \(10^{(20 dB / 10)}\)
I (W/m²) = \(10^{2}\)
I (W/m²) = 100 W/m²
Now, we can calculate the energy delivered to the eardrum each second (E) using the formula:
E = I * A
E = 100 W/m² * 0.0554 m²
E ≈ 5.54 W
Therefore, approximately 5.54 watts of energy is delivered to the eardrum each second when someone whispers (20 dB) in your ear.
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Determine the average speed of an object that travels 200 miles in 4 hours.
Answer:
The average speed is 50 miles per hour
Explanation:
Speed is equals to distance divided by time
Then substitute your variables into the equation
Hope this helps
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A heating coil has a resistance of 22 Ω and can safely handle 15 A of current. What is the maximum voltage that it can be connected to without burning out?
Answer:
330 v
Explanation:
V=IR
V=22×15=330
Answer:
\(\huge\boxed{\sf V = 330\ V}\)
Explanation:
Given data:Resistance = R = 22 Ω
Current = I = 15 A
Required:Voltage = V = ?
Formula:V = IR (Ohm's Law)
Solution:Put the given data in the above formula.
V = (15)(22)
V = 330 V
It should have a maximum voltage of 330 V to avoid burning out.
\(\rule[225]{225}{2}\)
Which option is an example of a conceptual model?A. mental image of gas molecules as tiny ballsB. A weather map created by Doppler radarC. A clay ball with a slice cut out, showing the layers of EarthD. A diagram of a flagpole and its shadow with measurements provided to calculate the length of the shadow
From the given options let's select the example which shows a conceptual model.
A conceptual model can be said to be a model which shows an abstract representation of any concept which can be visualized or imagined than other models.
It is a model which the designers want users to understand.
From the list, the best option which is an example of a conceptual model is a mental image of gas molecules as tiny balls.
Let's say, for example, you imagine or have a mental picture of gas molecules using your imagination, it helps to understand how a vacuum system works and you can easily solve the problem if something goes wrong.
Therefore, the example of a conceptual model is:
A mental image of gas molecules as tiny balls.
• ANSWER:
A. mental image of gas molecules as tiny balls
(14.9) Atom 1 of mass 38.5 u and atom 2 of mass 40.5 u are both singly ionized with a charge of +e. After being introduced into a mass spectrometer (see the figure below) and accelerated from rest through a potential difference V = 8.09 kV, each ion follows a circular path in a uniform magnetic field of magnitude B = 0.680 T. What is the distance Δx between the points where the ions strike the detector?
The distance Δx between the points where the ions strike the detector is 0.0971 meters. In a mass spectrometer, ions are accelerated by a potential difference and then move in a circular path due to the presence of a magnetic field.
To solve this problem, we can use the equation for the radius of the circular path:
r = (m*v) / (|q| * B)
where m is the mass of the ion, v is its velocity, |q| is the magnitude of the charge, and B is the magnetic field strength. Since the ions are accelerated from rest, we can use the equation for the kinetic energy to find their velocity:
KE = q * V
where KE is the kinetic energy, q is the charge, and V is the potential difference.
Once we have the radius, we can calculate the distance Δx between the two points where the ions strike the detector. Since the ions follow circular paths with the same radius, the distance between the two points is equal to the circumference of the circle, which is given by:
Δx = 2 * π * r
By substituting the given values into the equations and performing the calculations, we find that Δx is approximately 0.0971 meters.
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What does the pressure at a point in a fluid depend on? Select all that apply: The depth of that point within the fluid. The pressure at the fluid's surface. The density of the fluid: The weight of the fluid directly above that point
The depth of that point within the fluid, the pressure at the fluid's surface, the density of the fluid, and the weight of the fluid directly above that point.
What is fluid?Fluid is a state of matter that is characterized by its ability to move and take on the shape of its container. Fluids are composed of particles that are free to move about, and can also exist as a gas or a liquid. Fluids are an important part of everyday life, with applications ranging from transportation of goods to the operation of complex machinery. Fluids are also used to study the behavior of particles in motion, as well as to understand the properties of matter in general.
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IF RONALD CAN TAKE 2 GOLIATH DILD0S HOW MANY CAN TONY TAKE
USING THE PYTHAGOREAN THEOREM
Answer:
69
Explanation:
a block of mass m is released from rest and slides down an incline, as shown in the figure. the length d of the incline is 0.8 m and the angle of the incline, θ, is 37°. a graph of the speed v as a function of time t of the block as it descends the incline is shown. how could a student use the graph and the information provided to determine whether the block-earth system is an open system or a closed system?
The system is open, because there is a net force exerted on the block.
What are some instances of kinetic energy?An individual strolling, a taking off baseball, a piece tumbling from a table and a charged molecule in an electric field are instances of dynamic energy at work. An item that isn't moving has zero motor energy.
The energy an item has as a result of motion is known as kinetic energy. A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the item, which then moves at a new, constant speed.
According to question:
On graphing free body diagram of the problem
There is a force = mgsin(37°)
So, the it is a open system.
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What is the voltage of the power source if a motor with a resistance of 20 2 draws a
current of 1.5 A?
Answer:
190v I believe
hope this helped a little and if it did pls mark brainiest :)
What variables have the most effect on the strength of the gravitational attraction between two massive objects?
Help
Answer:
The distance between the 2 centers of the object.
Explanation:
If it's harder to win a super bowl for the rams than the gravity means the chiefs will win it.
How much work is required to move it at constant speed 5.0 m along the floor against a friction force of 210 N .
The work required to move an object at constant speed along the floor against a friction force can be calculated using the formula:
Work = Force x Distance
In this case, the force is the friction force acting against the object, which is 210 N, and the distance is the distance the object is moved, which is 5.0 m.
Therefore, the work required to move the object at constant speed along the floor against the friction force of 210 N is:
Work = 210 N x 5.0 m = 1050 J (Joules)
The work required is 1050 Joules.
To calculate the work required, we need to multiply the force acting against the object by the distance the object is moved. In this case, the friction force acting against the object is given as 210 N, and the distance the object is moved is 5.0 m.
So, using the formula Work = Force x Distance, we can substitute the values to find the work required.
Multiplying 210 N by 5.0 m gives us a result of 1050 J (Joules).
Therefore, the work required to move the object at a constant speed along the floor against the friction force of 210 N is 1050 Joules.
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interior crocodile alligator i drive a chevrolet movie theater
Answer:
nah bro tesla
Explanation:
The diagram shows changes of state between solid, liquid, and gas. The atoms of a substance gain energy during a change of state. Before the change, the atoms are close together and cannot slide past one another. After the change, the substance can fill its container. A diagram has a triangle at center with gas on top, liquid on bottom right, solid on bottom left. An arrow from gas to liquid is labeled O, and an arrow from liquid to gas is labeled N. An arrow from solid to liquid is labeled P, and an arrow from liquid to solid is labeled Q. An arrow from solid to gas is labeled L, and an arrow from gas to solid is labeled M. Which arrow represents the change of state described above? L M N O
Answer:
L
Explanation:
Endurance is important for participating in sports because it __________. A. provides the energy needed to maintain physical activity for long periods of time B. decreases the amount of nutrients and oxygen to the tissues C. allows you short spurts of energy to be released D. allows slow releases of energy for a small amount of time Please select the best answer from the choices provided. A B C D
Answer:
A. Endurance is important for participating in sports because it provides the energy needed to maintain physical activity for long periods of time.
Endurance allows an individual to sustain prolonged physical activity by delivering oxygen and nutrients to the muscles, which helps to delay fatigue and improve overall performance. Endurance training can improve cardiovascular health, increase muscular endurance, and enhance overall physical fitness, making it an essential component of sports performance. Short spurts of energy (C) are more related to anaerobic activities and do not rely on endurance, while option B is incorrect as it contradicts the importance of endurance, and option D is a partial truth but not the most comprehensive answer.
the amount of gravitational force that acts on a space vehicle while in earth orbit is
The amount of gravitational force that acts on a space vehicle while in earth orbit is almost zero but not absolute zero.
There is no ground force or opposing natural force to gravity.
Because the earth is not a perfect sphere, the value of "g" is lowest at the equator. At the equator, its radius is at its largest. Thus, the equator is the location where g will be smallest according to the equation
g = GM/R2.
All items in the planet's gravitational field will be lost in space if gravity abruptly vanishes. We would experience levity. Essentially, if gravity is equal to zero, then there will be no acceleration caused by gravity.
Astronauts can float within their spaceship or outside during a spacewalk in microgravity. Moving heavy stuff is simple. Astronauts, for instance, can merely use their fingertips to manipulate machinery weighing hundreds of pounds.
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SOMEONE HELP ME PLEASE
Students are examining features of objects in the room, such as the opposite sides of a book, the top and bottom of a chalkboard, and the edge of the wall that touches the edge of the floor. Which property of shape is the focus
The focus of the examination is the property of shape known as "flatness" or "planarity."
In this scenario, the students are examining features of objects in the room, specifically the opposite sides of a book, the top and bottom of a chalkboard, and the edge of the wall that touches the edge of the floor. These observations indicate that the students are focusing on the property of shape known as "flatness" or "planarity."
"Flatness" refers to the characteristic of an object or surface that lacks curvature or unevenness. It implies that the object or surface can be described as a flat plane with two dimensions, such as a sheet of paper or a tabletop.
In the case of the objects mentioned by the students, they are examining the sides of the book, the top and bottom surfaces of the chalkboard, and the edge of the wall that meets the floor. These features are typically flat and demonstrate the property of planarity.
By examining these flat surfaces and their characteristics, the students can understand and differentiate the objects based on their shape and planar properties. This analysis allows them to recognize and classify objects based on their flatness or planarity.
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the speed of light changes when it goes from ethyl alcohol (nea = 1.249) to carbon tetrachloride (nct = 1.531). what is the ratio vct vea of the speeds?
The case of ethyl alcohol and carbon tetrachloride, the ratio vct/vea is 1.225, indicating that the speed of light is faster in ethyl alcohol than in carbon tetrachloride.
The ratio vct/vea of the speeds of light when it passes through ethyl alcohol and carbon tetrachloride can be calculated using the formula v = c/n, where c is the speed of light in a vacuum and n is the refractive index of the material.
Therefore, vct/vea = n(ea)/n(ct) = 1.531/1.249 = 1.225.
This means that the speed of light is about 1.225 times faster in ethyl alcohol than in carbon tetrachloride.
The ratio vct/vea of the speeds of light passing through ethyl alcohol and carbon tetrachloride can be calculated using the formula v = c/n, where c is the speed of light in a vacuum and n is the refractive index of the material. The speed of light in carbon tetrachloride is slower than in ethyl alcohol due to its higher refractive index. Thus, the ratio vct/vea is 1.531/1.249 = 1.225, which means that the speed of light is about 1.225 times faster in ethyl alcohol than in carbon tetrachloride.
The speed of light changes when it passes through different materials with varying refractive indices. In the case of ethyl alcohol and carbon tetrachloride, the ratio vct/vea is 1.225, indicating that the speed of light is faster in ethyl alcohol than in carbon tetrachloride.
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An eighth-grade class is studying the motion of objects. They have learned the following concepts about motion.
Motion occurs when there is a change in the position of an object with respect to a reference point.
While the speed of the object may change at various times during a trip the average speed for the trip is found by dividing the total distance by the total time.
The motion of the object can be changed by varying the amount of net force acting on the object or by varying the mass of the object.
The teacher asked students to design investigations to determine how changing the forces acting on an object or the mass of the object would change its motion.
The materials for the investigation included:
1 - toy cart
3 - 10N weights
1 - pulley
2 - meters of string
One group of students decided to design an investigation to determine how different amounts of mass on the toy cart would affect the speed of the toy cart. They set up their investigation as shown below:
The students performed several trials using different masses in the toy cart (M1). They hung a mass shown as (M2) to pull the toy cart as it dropped.
Below is a table they made to record their results.
Which of the following would be a way to test the effect changing the amount of force acting on the object has on the average speed of the object?
Move the cart at various speeds and determine the force at M1
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
Move the cart at various speeds and determine the force exerted by M2
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
How to test the effect of weight on the speed of object?In order to test the changing amount of force that is acting on the object has effect on the average speed of the object we have to change the amount of weight on the object and allows it to move to a certain point in this way we can check the effect of changing amount of weight on the speed of the object.
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Shawn and his bike have a total mass of 44.4 kg. Shawn rides his bike 0.53 km in 11.8 min at a constant velocity. The acceleration of gravity is 9.8 m/s 2 . What is Shawn’s kinetic energy? Answer in units of J.
Shawn's kinetic energy will be approximately 16.65J.
What is kinetic energy?Kinetic energy is the energy of motion. An object having some speed and mass will have kinetic energy while an object at rest will not have any kinetic energy since the speed of object at rest is zero.
Since at rest speed is zero. an object has kinetic energy only when it is in motion.
The formula for kinetic energy is given as
K.E = (1/2)mv²
where m = mass of object
v = speed of object.
Given;
mass = 44.4kg
distance = 0.53km
time = 11.8 mins
g = 9.8m/s2
Converting variables
0.53 km x 1000 m= 530m
11.8 mins x 60 seconds = 708 seconds
Finding the velocity;
Velocity = d/t
Velocity = 530/708
Velocity = 0.75m/s2
Finding the kinetic energy;
KE = (1/2)mv²
KE = (1/2) x 44.4 x 0.75
KE = 16.65J
In conclusion, while in motion, Shawn's kinetic energy is 16.65J.
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3. Mary Lou is running errands for her mother. She leaves her house and goes 1 mile north to the
bakery. She then goes 2.5 miles south to get her hair cut. She continues south for 1.5 miles to
check out a book from the library. She then goes 0.75 miles north to meet a friend. This entire
voyage lasts 3 hours.
a) What is the total distance traveled? 6
b) What is the total displacemen 7
c) What was her average speed?
8
d) What was her average velocity
Answer:
Explanation:
a) The total distance travelled by Mary will be addition of the distances travelled in all directions.
Total distance travelled = 1 mile + 2.5 mile + 1.5miles + 0.75 miles
Total distance travelled = 5.75 miles
Hence the total distance traveled by Mary in her entire journey is 5.75 miles
b) Displacement is the total distance travelled in a specified direction. The displacement = 2.5 miles + (1.5- 0.75) miles = 3.25 miles
c) Speed is the change in distance with respect to time.
Speed = distance/time
Speed = 5.75/30
Speed = 0.193mi/hr
d) Average velocity is the change in displacement with respect to time.
Velocity = displacement/time
Velocity = 3.750/30
Velocity = 0.125mi/hr
A 0.50 kg grenade explodes horizontally into three pieces. The first piece has a velocity of 10 m/s [N] and a mass of 0.10 kg. The second piece has a velocity of 5.0 m/s [S 10⁰ E ] and a mass of 0.20 kg. Find the velocity of the third piece.
The velocity of the third piece is mathematically given as
v=0.88m/s
What is the velocity of the third piece.?Generally, the equation for conservation is mathematically given as
\(m u=m_{1} v_{1 \mathrm{x}}+m_{2} v_{2 \mathrm{x}}+m_{1} v_{x}\)
Here, is the mass of the grenade, \(m_{1}, m_{2}, m_{3}\) the masses of the pieces after an explosion, and \(v_{1 \mathrm{x}}, v_{2 \mathrm{x}}\) are velocities of the first and second pieces after the explosion.
\(m u_{1} &=m_{1} v_{1 x}+m_{2} v_{2 \mathrm{x}}+m_{3} v_{x} \\0 &=0+(0.2 \mathrm{~kg})((5 \mathrm{~m} / \mathrm{s})\\v_{x} &=\frac{-0.173 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.578 \mathrm{~m} / \mathrm{s}\)
the equation for conservation
\(m u=m_{1} v_{1 y}+m_{2} v_{2 y}+m_{3} v_{y}\)
\(m u_{1} &=m_{1} v_{1 \mathrm{y}}+m_{2} v_{x y}+m_{3} v_{y} \\0 &=(0.10 \mathrm{~kg})(10 \mathrm{~m} / \mathrm{s})+(0.2 \mathrm{~kg})\left((5 \mathrm{~m} / \mathrm{s}) \cos 10^{\circ}\right)+(0.3 \mathrm{~kg}) v_{y} \\v_{y} &=\frac{-1.98 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.661 \mathrm{~m} / \mathrm{s}\)
In conclusion, the magnitude of the velocity
\(v=\sqrt{v_{\mathrm{x}}^{2}+v_{\mathrm{y}}^{2}}\)
\(Substitute $-0.578 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{s}}$ and $-0.661 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{y}}$\)
\(v &=\sqrt{v_{x}^{2}+v_{y}^{2}} \\&=\sqrt{(-0.578 \mathrm{~m} / \mathrm{s})^{2}+(-0.661 \mathrm{~m} / \mathrm{s})^{2}} \\&=0.88 \mathrm{~m} / \mathrm{s}\)
v=0.88m/s
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Please help me Calculate the total energy stored in the capacitor
La fórmula: P = W/t ó W = P x t. donde:
P = potencia
W = trabajo
t = tiempo
Otra fórmula de potencia es: P= I x V
Proceso de carga de un capacitor - condensador
Una fórmula muy importante que también hay que tener en cuenta es: V = q/C que indica que el voltaje es proporcional a la carga que hay en un condensador.
De la fórmula de potencia P= I x V y considerando que la corriente es constante (corriente continua), entonces la potencia es proporcional al voltaje. Si el voltaje aumenta en forma lineal, la potencia aumentará igual. Ver el siguiente diagrama.
Como la potencia varía en función del tiempo, no se puede aplicar la fórmula W = P x t, para calcular la energía transferida. Pero observando el gráfico, se ve que esta energía se puede determinar midiendo el área bajo la curva de la figura.
Energía Almacenada en un Condensador - Capacitor
El área bajo la curva es igual a la mitad de la potencia en el momento “t”, multiplicada por “t”.
Entonces: W = (P x t) / 2. Pero se sabe que P = V x I. Si se reemplaza esta última fórmula en la anterior se obtiene: W = (V x I x t) / 2, y como I x t = CV = Q, entonces para saber cuanta energía (W) hay en un condensador usamos una de las siguientes fórmulas:
W = (CV2/2) julios
W = (QV/2) julios
W = (Q2/2C) julios
, donde:
W = Trabajo (Energía) en julios
C = Capacidad en faradios
V = voltaje en voltios en los extremos del condensador
Q = carga del condensador
Answer with the given explanations below: First the given formula that looks like this is: or where:
P = power
W = work
t = time
Next with another given power formula that looks like this is:
This is the charging process of a capacitor - capacitor #1.
Then it's a very important given formula that it must also be taken into account is: which it was indicated that the voltage is proportional to the charge on a capacitor.
In the following below, from the given power formula that looks like this is: and we are considering that the current is the constant (direct current), and then the power is proportional to the voltage. If the voltage increases linearly, the power will increase the same. See the following diagram. (I'm sorry, Yhungbabe, I don't have the diagram to show you in order to refer to the total energy stored in the capacitor because I havenèt learned the energy stored in the capacitor)
Anyway, since the power varies as a function of the time, the given formula that looks like this is: cannot be applied to calculate the energy transferred. But looking at the graph, it seems that this energy can also be determined by measuring the area under the curve of the figure.
This is The Energy Stored in a Capacitor - Capacitor #2.
The area under the curve is equal to the half of the power at time "t", being multiplied by "t".
Then with the given formula below that looks like this is:
But it's known that If this is the last given formula is being replaced in the previous one, we obtain the new given formula that looks like this is: and as another new given formula that looks like this is: there's so to find out how much energy (W) that there's in a capacitor that we use in one of the new given formulas that looks like in the listed below are:
joules
joules
joules
Now finally where:
W = Work (In The Energy) in Joules
C = Capacity in the farads
V = voltage in the volts at the ends of the capacitor
Q = a capacitor charge
I apologize for the late answer and the replies, so anyway, I use the online language translator in order to translate Spanish to English for you in order to understand my work given below, so, I hope my answer with the given explanation below here is very helpful to your own question about how to calculate the total energy stored in the capacitor with the image has been provided, please mark me as Brainliest and have a great rest of the day! :D
Sincerely,
Jason Ta,
The Ambitious of The Brainly And The Role of The TDSB And WHCI Student of The High School.
A student pushed a book with a mass of 1kg across a desk with an acceleration of 0. 5m/s2, a distance of 20m for two and a quarter minutes. Provide the force, work, and power the student applied, did, and has
The required force is calculated to be 0.5 N, work is 10 J and power is 0.074 Watt.
The mass of the book is given as 1 kg.
The acceleration of the book is given as 0.5 m/s².
The distance moved by the book is given as 20 m.
The time taken to move the book is given as 2 1/4 minutes = 9/4 minutes.
The force applied on the book is given as,
F = m a = 1 × 0.5 = 0.5 N
where,
F is force
m is mass
a is acceleration
The expression for work is known to be,
W = F . s = 0.5 × 20 = 10 J
where,
W is work
s is distance
The relation for power is known to be,
P = W/t = 10/(9/4 × 60) = 0.074 Watt
where,
P is power
t is time
Thus, the force is 0.5 N, work is 10 J and power is 0.074 Watt.
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You have a light spring which obeys Hooke's law. This spring stretches 3.24 cm vertically when a 2.70 kg object is suspended from it. Determine the following.
In conclusion, the spring constant can be determined by dividing the force applied by the displacement. The spring constant measures the stiffness of the spring and determines the amount of force needed to stretch or compress it.
Based on the given information, we have a light spring that obeys Hooke's law. This law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.
In this case, the spring stretches 3.24 cm when a 2.70 kg object is suspended from it. To determine the following, we can use Hooke's law and the equation:
F = k * x
where F is the force applied, k is the spring constant, and x is the displacement of the spring.
To find the spring constant, we rearrange the equation as:
k = F / x
Given that the force applied is the weight of the object, which is equal to mass times acceleration due to gravity, we can calculate it as:
F = m * g
where m is the mass of the object and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Plugging in the values, we have:
F = 2.70 kg * 9.8 m/s^2
Next, we need to convert the displacement from centimeters to meters:
x = 3.24 cm * (1 m / 100 cm)
Now, we can calculate the spring constant:
k = (2.70 kg * 9.8 m/s^2) / (3.24 cm * (1 m / 100 cm))
Simplifying this expression will give us the value of the spring constant, which will be in units of N/m.
To summarize, we have a light spring that stretches 3.24 cm when a 2.70 kg object is suspended from it. To determine the spring constant, we used Hooke's law and calculated the force applied by the object's weight. We then converted the displacement from centimeters to meters and finally calculated the spring constant using the equation k = F / x.
In conclusion, the spring constant can be determined by dividing the force applied by the displacement. The spring constant measures the stiffness of the spring and determines the amount of force needed to stretch or compress it.
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If you rub a glass rod with a piece of silk, the rod becomes positively charged. This means that
Protons have moved to the rod
Friction destroyed the electrons in the rod
The silk has become negatively charged
Glass attracts more protons
Answer:
The silk has become negatively charged
determine the internal normal force at point cc . express your answer to three significant figures and include the appropriate units.
The internal normal force at point CC is 200.04 N.
Length of beam is 8 meters
Internal normal force at point CC
Impose equilibrium equations; the sum of forces acting in the vertical direction must be zero. That is,ΣFv = 0∑Fv=0There is a vertical reaction at A, and a vertical reaction at B.
Let us assume that both are upward. At the mid-span, there is a downward force due to the load, which acts as shown below:FBD of the beam shown above is as follows:
The free body diagram shows that the beam is subjected to a uniformly distributed load (UDL) of w kN/m over its entire length. At the mid-span, the load acting on the beam is half of the total load.
That is, 4w/2 = 2w kN. Summing the moments of forces about
Point C, it yields the following equation:ΣMC = 0∑MC=0Internal normal force can be determined using the formula as given below:N = (wL/8) × (2L/3) + wL/2N=200.04 N
The internal normal force at point CC is 200.04 N.
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If we place a nonpolar molecule in an electric field, which is true? The field induces a dipole moment, with the positive end of the molecule in the direction of the field vector. The field induces a dipole moment, with the negative end of the molecule In the direction of the field vector. The field induces a dipole moment, with the dipole axis perpendicular to the field vector.
When a nonpolar molecule is placed in an electric field, the field does not interact with the electrons in the molecule, which are evenly distributed. Therefore, the field does not induce a dipole moment in the molecule, meaning that there is no separation of charge within the molecule.
This is because the electric field can only affect polar molecules, which have a separation of charge. In contrast, nonpolar molecules have no net separation of charge and are therefore not affected by the electric field. Therefore, none of the options given in the question are true for nonpolar molecules. In summary, nonpolar molecules do not experience a dipole moment when placed in an electric field.
When you place a nonpolar molecule in an electric field, the correct statement is: The field induces a dipole moment, with the negative end of the molecule in the direction of the field vector.
In this situation, the electric field temporarily distorts the electron cloud of the nonpolar molecule, causing a temporary dipole moment. The electrons are attracted to the positive end of the field, while the nuclei are repelled. As a result, the negative end of the induced dipole moment aligns with the direction of the field vector, while the positive end aligns in the opposite direction.
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A driver starts his parked car and within 5 hr reaches a speed of 60 km/h, as he travels east. what is his acceleration?
Answer:
change in speed) / (time for the change)
and the direction of the change.
Acceleration = (60 - 0) km per hour / 5 sec = 12 km per hour per second, east.
I hear teachers all over the country complaining about that ugly unit.
It has to be changed to a more familiar unit of acceleration.
(12 km/hour) x (1 hour/3600sec) = 12,000/3600 = 3-1/3 meter/sec.
His acceleration is 3-1/3 meters per second² .
Explanation:
a
Answer:
u=0
v=60 km/ hr
60 \times 1000 \\ 60 \times 60 = 1800
t =5
t = 5 \times3600 = 18000
a= ?
a = v - u \div t
= 1800 - 0 \div 18000 \\
1m/s^2\: ans
I need help with this school work
Answer:
•battery
•Generator
•flywhell
•crank
Explanation:
the persons energy comes from his/her body that he/she gain from the food she/he eats
The is greater for low-mass stars than it is for high-mass stars. 2. The stars known as are the very largest and brightest of all the stars. 3. Most of the stars near the Sun are . 4. Stars are classified on the basis of their spectral type and 5. Cepheids are examples of . 6. are no longer generating energy through nuclear fusion. 7. Stars that are cooler than the Sun yet 100 to 1,000 times as luminous as the Sun are classified as .
Answer:
red giant stars/ red hyper giants
Explanation:
take stephenson 2-18 for example the star is only 3200k where the sun is around 5000k.