Sort the above sequence by using the selection sort (pseudocode is shown below). Find how many times numbers are compared and how many times numbers are swapped. Use graphs and words to explain why. (3 pts) Algorithm selection Sort(A) Input A array A Output A sorted array for it to A.length - 2 do mini fori + i +1 to A.length - 1 do if A[i]= 1 and A[j-1] > marked do A[i] + A[i-1] jj-1 Al marked return A
Answers
To sort the given sequence using the selection sort algorithm, we'll start by implementing the algorithm and then analyze the number of comparisons and swaps that occur.
Here's the modified pseudocode for selection sort:less
Copy code
Algorithm SelectionSort(A)
Input: Array A
Output: Sorted array A
for i = 0 to A.length - 2 do
min = i
for j = i + 1 to A.length - 1 do
if A[j] < A[min] then
min = j
swap A[i] with A[min]
return A
Now let's apply the selection sort algorithm to the given sequence: [3, 1, 4, 2, 5].
Initialization:
A = [3, 1, 4, 2, 5]
Comparisons: 0
Swaps: 0
First iteration (i = 0):
min = 0
Start the inner loop (j = i + 1 = 1 to 4):
Comparison: 1 (3 < 1? No)
Comparison: 2 (3 < 4? Yes, update min = 1)
Comparison: 3 (3 < 2? No)
Comparison: 4 (3 < 5? Yes, update min = 4)
Swap A[i] (3) with A[min] (1)
A = [1, 3, 4, 2, 5]
Comparisons: 4
Swaps: 1
Second iteration (i = 1):
min = 1
Start the inner loop (j = i + 1 = 2 to 4):
Comparison: 5 (3 < 4? Yes, update min = 2)
Comparison: 6 (3 < 2? No)
Comparison: 7 (3 < 5? Yes, update min = 4)
Swap A[i] (3) with A[min] (2)
A = [1, 2, 4, 3, 5]
Comparisons: 7
Swaps: 2
Third iteration (i = 2):
min = 2
Start the inner loop (j = i + 1 = 3 to 4):
Comparison: 8 (4 < 3? No)
Comparison: 9 (4 < 5? Yes, update min = 4)
No need to swap elements as A[i] (4) is already in the correct position
A = [1, 2, 4, 3, 5]
Comparisons: 9
Swaps: 2
Fourth iteration (i = 3):
min = 3
Start the inner loop (j = i + 1 = 4 to 4):
Comparison: 10 (3 < 5? Yes, update min = 4)
Swap A[i] (3) with A[min] (5)
A = [1, 2, 4, 5, 3]
Comparisons: 10
Swaps: 3
Fifth iteration (i = 4):
min = 4
Start the inner loop (j = i + 1 = 5 to 4):
No
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Related Questions
An electrical contractor employs 16 people. Five people earn $15 per hour, four people earn $17 per hour, and the remaining people earn $16 per hour. What is the total hourly wage earned by all 16 people
Answers
$255 per hour
Explanation:Total number of employed people = 16
(i) 5 people earn $15 per hour
That means that the total amount earned by those 5 is;
5 x $15 = $75 per hour
(ii) 4 people earn $17 per hour
That means that the total amount earned by those 4 is;
4 x $17 = $68 per hour
(iii) The remaining people earn $16 per hour.
There are 7 people remaining. i.e
16 - 5 - 4 = 7
That means that the total amount earned by those remaining (7) is;
7 x $16 = $112 per hour
The total hourly wage is therefore the sum of all the results in i, ii and iii. i.e
Total = $75 + $68 + $112
Total = $255
Therefore, the total hourly wage earned by all 16 people is $255
You find an unnamed fluid in the lab we will call Fluid A. Fluid A has a specific gravity of 1.65 and a dynamic viscosity of 210 centipoise [cP]. What is the kinematic viscosity of Fluid A, in units of stokes [St]
Answers
Answer:
1.2727 stokes
Explanation:
specific gravity of fluid A = 1.65
Dynamic viscosity = 210 centipoise
Calculate the kinematic viscosity of Fluid A
First step : determine the density of fluid A
Pa = Pw * Specific gravity = 1000 * 1.65 = 1650 kg/m^3
next : convert dynamic viscosity to kg/m-s
210 centipoise = 0.21 kg/m-s
Kinetic viscosity of Fluid A = dynamic viscosity / density of fluid A
= 0.21 / 1650 = 1.2727 * 10^-4 m^2/sec
Convert to stokes = 1.2727 stokes
5. The maximum scaffold height not requiring toeboards is 20 feet.
A. True
B. False
Answers
Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit length) that the water exerts on the pier. Assume that the flow can be approximated as an potential fluid flow around the front half of the cylinder, but due to flow seperation, the average pressure on the rea half is constant and approximately equal to 1/2 the pressure at point A.
Answers
Answer: hello the diagram related to your question is missing please the third image is the missing part of the question
Fx = 977.76 Ib/ft
Explanation:
Estimate the force that water exerts on the pier
V = 12 ft/s
D( diameter ) = 6 ft
first express the force on the first half of the cylinder as
Fx1 = - \(-2\int\limits^\pi _\frac{\pi }{2} {Ps*cos\beta *a} \, d\beta\) ---------------- ( 1 )
where ; Fy = 0
Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β ) ------------- ( 2 )
Input equation (2) into equation ( 1 ) (note : assuming Po = 0 )
attached below is the remaining part of the solution
Draw state diagram of the control software for a DVD player
Answers
Explanation:
this is the diagram of the control software for a DVD player
True or false, Increasing the spring force of the pressure plate that clamps the clutch disc to the flywheel increases torque capacity
but takes more foot pressure to operate the clutch pedal.
Answers
Answer: True
Explanation:
A contractor excavates 10,000 m3 soil at moist unit weight of 17.5 kN/m3 and moisture content of 10% from a borrow pit and transports it to a project site. The project has an area of 20,000 m2 to be filled with this compacted soil. If the required dry unit weight and moisture content of the compacted soil are 18.3 kN/m3 and 12.5% (assume there is no soil loss during transportation and compaction), what is the thickness of the compacted soil and how much water needs to be added?
Answers
Answer:
Part A
The thickness of the compacted soil is approximately 4.3467 × 10⁻¹ m
Part B
The weight of water to be added is approximately 19886.\(\overline{36}\) kN, the volume of the water added is approximately 2,027.77 m³
Explanation:
The parameters of the soil are;
The volume of sol the excavator excavates, \(V_T\) = 10,000 m³
The moist unit weight, W = 17.5 kN/m³
The moisture content = 10%
The area of the project, A = 20,000 m²
The required dry unit weight = 18.3 kN/m³
The required moisture content = 12.5%
Part A
Therefore, we have;
The moist unit weight = Unit weight = (\(W_s\) + \(W_w\))/\(V_T\)
The moisture content, MC = 10% = (\(W_w\)/\(W_s\)) × 100
∴ \(W_w\) = 0.1·\(W_s\)
∴ The moist unit weight = 17.5 kN/m³ = (\(W_s\) + 0.1·\(W_s\))/(10,000 m³)
1.1·\(W_s\) = 10,000 m³ × 17.5 kN/m³ = 175,000 kN
\(W_s\) = 175,000 kN/1.1 = 159,090.\(\overline{09}\) kN
For the required soil, we have;
The required dry unit weight = 18.3 kN/m³ = \(W_s\)/\(V_T\) = 159,090.\(\overline{09}\) kN/\(V_T\)
\(V_T\) = 159,090.\(\overline{09}\) kN/(18.3 kN/m³) ≈ 8,693.4923 m³
The total volume of the required soil ≈ 8,693.4923 m³
Volume \(V_T\) = Area, A × Thickness, d
∴ d = \(V_T\)/A
d = 8,693.4923 m³/(20,000 m²) ≈ 4.3467 × 10⁻¹ m
The thickness of the compacted soil ≈ 4.3467 × 10⁻¹ m
Part A
The moisture content, MC = 12.5% = (\(W_w\)/\(W_s\)) × 100
\(W_w\) = \(W_s\) × MC/100 = 159,090.\(\overline{09}\) kN × 12.5/100 = 19886.\(\overline{36}\) kN
The weight of water to be added, \(W_w\) = 19886.\(\overline{36}\) kN
Where the density of water, ρ = 9.807 kN/m³
Therefore, we have;
The volume of water, V = \(W_w\)/ρ
∴ V = 19886.\(\overline{36}\) kN/(9.807 kN/m³) ≈ 2027.77 m³
The volume of water, V ≈ 2027.77 m³
To allow two pieces of copper tubing to be joined by soldering or brazing without any fitting, which of the following must be used?
A. Fitting end
B. Sweat tree
C. Swage joint
D. Solder end
Answers
Option C is correct. Swage joints must be used to connect two pieces of copper tubing by soldering or brazing without the use of any fittings.
Swaging is the process of fitting the end of one copper tube over the other so that the junction may be brazed or soldered. It is used to unite two copper tubes of the same diameter.
In order to permanently unite fittings to pipes or cables (also known as wire ropes), swaging is most frequently used. After the parts are loosely assembled, the fitting is compressed and deformed by a mechanical or hydraulic tool.
A swage joints is a wire rope component by definition. By squeezing the fitting on the wire, it is fastened to the wire.
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Consider the join R ▷◁ S where the join predicate is R.a = S.b, given the following metadata about R and S:• Relation R contains 20,000 tuples and has 10 tuples per block• Relation S contains 5,000 tuples and has 10 tuples per block• Attribute b of relation S is the primary key for S, and every tuple in S matches 3 tuples in R• There exists a unclustered (secondary) index on R.a with height 3• There exists a clustered (primary) index on S.b with height 2• The main memory buffer can hold 5 blocks (B=5)Answer the following questions:a. If R ▷◁ S is evaluated with a block nested loop join, which relation should be the outer relation? Justify your answer. What is the cost of the join in number of I/O’s?b. If R ▷◁ S is evaluated with an index nested loop join, what will be the cost of the join in number of I/O’s? Show your cost analysis.c. What is the cost of a plan that evaluates this query using sort-merge join. Show the details of your cost analysis.d. Evaluate the cost of computing the R ▷◁ S using hash join assuming: i) The main memory buffer can hold 202 blocks, ii) The main memory buffer can hold 11 blocks
Answers
a. The outer relation for R ▷◁ S evaluated with a block nested loop join should be relation R. This is because relation R has more tuples than relation S, and using the smaller relation as the outer relation would require more I/O operations to access the matching tuples in the larger relation. The cost of the join in number of I/O's would be: 2000 (R blocks) + 600 (S blocks) = 2600 I/O's.
b. If R ▷◁ S is evaluated with an index nested loop join, the cost of the join in number of I/O's would be: 600 (S blocks) + 6000 (index blocks for R) + 18000 (data blocks for R) = 24600 I/O's.
c. The cost of a plan that evaluates this query using sort-merge join would be: 6000 (sort R by a) + 2500 (sort S by b) + 2000 (merge sorted R and S) = 10500 I/O's.
d. The cost of computing R ▷◁ S using hash join assuming: i) The main memory buffer can hold 202 blocks is 600 (S blocks) + 6000 (index blocks for R) + 18000 (data blocks for R) = 24600 I/O's, and ii) The main memory buffer can hold 11 blocks is 2000 (R blocks) + 600 (S blocks) + 6000 (index blocks for R) + 18000 (data blocks for R) = 24600 I/O's.
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What is land administration and cadastral survey
Answers
Cadastral surveying is the sub-field of cadastre and surveying that specialises in the establishment and re-establishment of real property boundaries. ... A cadastral surveyor must apply both the spatial-measurement principles of general surveying and legal principles such as respect of neighboring titles.
Need clear written step by step answers please.
Trimble R3 GPS system has an accuracy of + (5 mm + 1 ppm) in the vertical direction. What is the accuracy we are expected to get in the vertical direction for the location of a point that is 5 km away from the reference station? Assume that no other types of errors exist.
Answers
The expected accuracy in the vertical direction for a point located 5 km away from the reference station using the Trimble R3 GPS system, assuming no other errors, is approximately 6.5 mm.
The accuracy of the Trimble R3 GPS system in the vertical direction is given as + (5 mm + 1 ppm). Let's break down this accuracy specification. The "+ (5 mm + 1 ppm)" part means that there is a fixed error of 5 mm added to a proportional error that depends on the distance. The "1 ppm" stands for one part per million, which means the proportional error increases by 1 ppm for every 1 million units of distance.
To calculate the expected accuracy for a point 5 km (or 5,000 meters) away from the reference station, we need to consider both the fixed and proportional errors. The fixed error of 5 mm remains constant regardless of the distance. The proportional error can be calculated by multiplying the distance by the ppm value: (5,000 meters * 1 ppm) = 5 mm.
To find the overall expected accuracy, we add the fixed error and the proportional error: 5 mm + 5 mm = 10 mm. Therefore, the expected accuracy in the vertical direction for a point located 5 km away from the reference station using the Trimble R3 GPS system, assuming no other errors, is approximately 10 mm or 0.01 meters.
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calculate the reynolds number for a newtonian fluid with a dynamic viscosity of 0.52 ns/m2, density of 810 kg/m3, that flows through a pipe diameter of 20 mm, and a velocity of 2.6 m/s. is the flow laminar or turbulent?
Answers
If a liquid flow's Reynolds number is less than 1000 (or 2000), it is referred to as a streamline flow; by contrast, a flow with a Reynolds number higher than 4000 is referred to as a turbulent flow.
Re = VD/ or Re = VD/v is the formula for the Reynolds Number, where "V" stands for fluid velocity, "D" for characteristic distance, "" for fluid density, "v" for kinematic viscosity, and "" for dynamic viscosity, all of which can be found in data tables. When the Reynolds number is less than or equal to 2,000, the flow through a pipe is typically laminar; when it exceeds 2,000, the flow is often turbulent. Reynolds number, a dimensionless quantity, is used to categorize the flow pattern through a pipe as laminar or turbulent.
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What are the two signals that make up an FM radio wave?
Answers
1)amplitude modulation, or AM,
2)frequency modulation, or FM.
these are the two signals that make up the FM radio wave
Which option identifies the tool best to use in the following scenario?
Theresa has just purchased a crib and needs to assemble it quickly. The crib came with instructions, but no tools, and she does not know what she needs. On all of the screws in her kit, there is a six-sided hole in the head.
an Allen wrench
a Phillips screwdriver
a flathead screwdriver
an adjustable crescent wrench
NEXT QUESTION
Answers
Answer:
an Allen wrench
Explanation:
it is hexagonal
In the makeRoom method of the array-based implementation of the ADT list, it is possible that no items will be shifted. t/f
Answers
In the makeRoom method of the array-based implementation of the ADT list, it is possible that no items will be shifted this statement is true.
In the makeRoom method of the array-based implementation of the ADT list, space is allocated in the array to accommodate a new item to be inserted into the list. However, it is possible that there is already enough space in the array to accommodate the new item, and no items need to be shifted to make room for the new item.
In this case, the makeRoom method would simply return without shifting any items in the array. Therefore, it is possible that no items will be shifted in the makeRoom method of the array-based implementation of the ADT list.
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what is the condition for sampling frequency to reconstruct the information signal ?
Answers
A continuous time-varying 1-D signal is sampled by narrow sampling pulses at a regular rate fr = 1/T, which must be at least twice the bandwidth of the signal. At first, it may be somewhat surprising that the original waveform can be reconstructed exactly from a set of discrete samples.
How does concurrent engineering speed up product development?
A. The product and process are designed using computer-aided design.
B. The product and process are designed in series.
C. The product and process are designed in separate spaces.
D. The product and process are designed simultaneously.
Answers
Answer:
The product and process are designed simultaneously
Explanation:
PENN
A 4-pole, 60-Hz, 690-V, delta-connected, three-phase induction motor develops 20 HP at full-load slip of 4%. 1) Determine the torque and the power developed at 4% slip when a reduced voltage of 340V is applied. 2) What must be the new slip for the motor to develop the same torque when the reduced voltage is applied
Answers
Answer:
1. i. 20 Nm ii. 4.85 HP
2. 16.5 %
Explanation:
1) Determine the torque and the power developed at 4% slip when a reduced voltage of 340V is applied.
i. Torque
Since slip is constant at 4 %,torque, T ∝ V² where V = voltage
Now, T₂/T₁ = V₂²/V₁² where T₁ = torque at 690 V = P/2πN where P = power = 20 HP = 20 × 746 W = 14920 W, N = rotor speed = N'(1 - s) where s = slip = 4% = 0.04 and N' = synchronous speed = 120f/p where f = frequency = 60 Hz and p = number of poles = 4.
So, N' = 120 × 60/4 = 30 × 60 = 1800 rpm
So, N = N'(1 - s) = 1800 rpm(1 - 0.04) = 1800 rpm(0.96) = 1728 rpm = 1728/60 = 28.8 rps
So, T = P/2πN = 14920 W/(2π × 28.8rps) = 14920 W/180.96 = 82.45 Nm
T₂ = torque at 340 V, V₁ = 690 V and V₂ = 340 V
So, T₂/T₁ = V₂²/V₁²
T₂ = (V₂²/V₁²)T₁
T₂ = (V₂/V₁)²T₁
T₂ = (340 V/690 V)²82.45 Nm
T₂ = (0.4928)²82.45 Nm
T₂ = (0.2428)82.45 Nm
T₂ = 20.02 Nm
T₂ ≅ 20 Nm
ii. Power
P = 2πT₂N'
= 2π × 20 Nm × 28.8 rps
= 1152π W
= 3619.11 W
converting to HP
= 3619.11 W/746 W
= 4.85 HP
2) What must be the new slip for the motor to develop the same torque when the reduced voltage is applied
Since torque T ∝ sV² where s = slip and V = voltage,
T₂/T₁ = s₂V₂²/s₁V₁²
where T₁ = torque at slip, s₁ = 4% and voltage V₁ = 690 V and T₂ = torque at slip, s₂ = unknown and voltage V₂ = 340 V
If the torque is the same, T₁ = T₂ ⇒ T₂T₁ = 1
So,
T₂/T₁ = s₂V₂²/s₁V₁²
1 = s₂V₂²/s₁V₁²
s₂V₂² = s₁V₁²
s₂ = s₁V₁²/V₂²
s₂ = s₁(V₁/V₂)²
substituting the values of the variables into the equation, we have
s₂ = s₁(V₁/V₂)²
s₂ = 4%(690/340)²
s₂ = 4%(2.0294)²
s₂ = 4%(4.119)
s₂ = 16.47 %
s₂ ≅ 16.5 %
The thickness of the oil reservoir is 10cm, the production rate of oil is 100m3, the well radius is 10cm, the permeability of the reservoir is 1um2, the porosity is 0.2, the viscosity of the oil is 4mPa.S, the density of oil is 850kg/m3. If the flow regime can be considered as linear flow, can this flow in the reservoir satisfy Darcy's law?
Answers
Answer:
The thickness of the oil reservoir is 10cm, the production rate of oil is 100m3, the well radius is 10cm, the permeability of the reservoir is 1um2, the porosity is 0.2, the viscosity of the oil is 4mPa.s, the density of oil is 850kg/m3. If the flow regime can be considered as linear flow, can this flow in the reservoir satisfy Darcy's
compute the densities of totally crystalline and totally amorphous polypropylene
Answers
The densities of totally crystalline and totally amorphous polypropylene are 0.96 g/cm³ and 0.855 g/cm³, respectively.
Polypropylene is a type of thermoplastic polymer which has both amorphous and crystalline regions. It is often used in packaging, textiles, and other applications due to its high stiffness, resistance to heat, and good chemical resistance. The densities of totally crystalline and totally amorphous polypropylene can be computed as follows:
The density of totally crystalline polypropylene is approximately 0.96 g/cm³. This value is obtained by measuring the density of highly crystalline polypropylene samples that have been annealed to promote crystal growth. Crystalline polypropylene has a regular, ordered structure that is more dense than the amorphous regions.
The density of totally amorphous polypropylene is approximately 0.855 g/cm³. This value is obtained by measuring the density of polypropylene samples that have been melted and rapidly cooled to preserve their amorphous structure. Amorphous polypropylene has a random, disordered structure that is less dense than the crystalline regions.
In summary, the densities of totally crystalline and totally amorphous polypropylene are 0.96 g/cm³ and 0.855 g/cm³, respectively.
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which of the following is a secure doorway that can be used with a mantrap to allow an easy exit but actively prevents re-entrance through the exit portal?
Answers
For simple exit from a secure area, turnstiles are frequently employed.
What is mantrap door?A mantrap is a little space with an exit door on the other wall and an entrance door on one wall. A mantrap door cannot be opened until the door to its opposite has been shut and locked.
What are the three security types that should be used in a methodical manner to safeguard network infrastructure?Hardware, software, and cloud services are the three parts of network security. Servers or other devices known as hardware appliances carry out specific security operations in a networking environment.
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Crank OA rotates with uniform angular velocity 0 4 rad/s along counterclockwise. Take OA= r= 0.5
m,AB2r,and BC 2r.For the instant, 45,OA is horizontal and AB is vertical.
determine the angular velocity and angular acceleration of BC.
Answers
A thin plate 0.7 m long and 1.5 m wide is submerged and held stationary in a stream of water
Answers
The thickness of the boundary layer will be 0.436m. Distance downstream of the leading edge where this Reynolds number occur will be 3.08mm. The shear stress on the plate on this point is 1.055 N/m².
Why is the Reynolds number employed?Laminar or turbulent fluid flow is identified using the Reynolds number, abbreviated as Re. In all viscous flows, where a numerical model is chosen in accordance with pre-calculated Reynolds number, it is one of the primary regulating parameters.
How to solve the question?Given, Reynolds number, Re = 500000
length = 0.7 m
width = 1.5m
velocity, u = 1.5 m/s
the thickness of the boundary layer, Re = u×x/v
x = Re × v/u
x = 500000×1.31×10∧(-6)/1.5
x = 0.436m
distance downstream of the leading edge where this Reynolds number occur, δ = 5x/\(\sqrt{Re}\)
δ = 5×0.436/√500000
δ = 3.08 mm
The shear stress on the plate on this point,
τ = 0.332v(u/x)×√Re
τ = 0.332×1.31×10∧(-3) (1.5/0.436) √500000
τ = 1.055 N/m²
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The complete question is,
A thin plate 0.7 m long and 1.5 m wide is submerged and held stationary in a stream of water (T = 10°C) that has a velocity of 1.5 m/s. What is the thickness of the boundary layer on the plate for Re, 500,000 (assume the boundary layer is still laminar), and at what distance downstream of the leading edge does this Reynolds number occur? What is the shear stress on the plate on this point?
Tony works as a Sorter in a processing factory. Which qualifications does he most likely have?
teaching skills, for helping people perform farm tasks, and creative thinking skills, for finding ways to process food
safety skills, for handling tools and food products, and honesty, for following rules and regulations
accuracy, for closely inspecting equipment and operating heavy machinery safely
accuracy, for monitoring animals, and patience and determination, for observing and caring for animals
Answers
Answer:
answer is B
Explanation:
Blank is a set of rules that Access enforces to maintain consistency between related tables when you update data in a database? A. Litigation B. Normalization C. Fraternization D. Localization
Answers
When you update data in a database, Access enforces a set of guidelines called Litigation. to ensure consistency between linked tables.
Litigation is the process of taking a case to court. In the event that the parties are unable to settle a dispute amicably, they shall each present their separate cases to a court for judgement. It is a broad term for a drawn-out and occasionally challenging process. an attorney who specializes in the litigation of property disputes the act or process of litigating a case that has been in litigation for years the action, procedure, or practice of resolving a legal disagreement There are a few instances in which parties to a disagreement are unable to represent themselves in court, despite the fact that the American legal system normally forbids anyone without a personal interest in the dispute from filing a lawsuit.
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Car pool vehicles are those with
Answers
Answer:
The pavement of the carpool lanes is marked with the diamond symbol. These carpool lanes are reserved for buses and vehicles with a minimum of two or three people and that includes the driver
Explanation:
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Effectively,how many valence electrons are there in each atom within q silicon crystal?
Answers
Answer:
Four valence electrons
Silicon is having an atomic number of 14 which means It has two electrons in its first shell, eight electrons in the second shell, and four electrons in the third shell.
Knowing that the central portion of the link BD has a uniform cross-sectional area of 800 2, determine the magnitude of the load P for which the normal stress in that portion of BD is 50 .
Answers
Answer: 50
Explanation:
What is the basic requirement of measurements?
Answers
The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.
Answer:
The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.
Explanation:
Why is it important to keep portable welders properly tuned
Answers
It is important to keep welders properly tuned because it "Reduces air pollution" (Option A).
What are the types of welding?Welding machinery, welding guns, and welders are among the most important items for a welding expert to have. Welding machines provide heat that melts steel pieces, allowing them to be bonded.
Gas Steel Arc Welding (GMAW/MIG), Gas Tungsten Arc Welding (GTAW/TIG), Shielded Steel Arc Welding (SMAW), andFlux Cored Arc Welding are the four primary methods of welding.Most welders also use an angle grinder to smooth out joints, wire brushes to clean or abrade steel surfaces before welding etc.
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Full Question:
Why is it important to keep portable welders properly tuned?
a-Reduce air pollution
b-So they run quieter
c-To produce smoother welding current
d-All of the above