Someone please help me I’ll give out brainliest please don't answer if you don’t know

The value of x in the given equation i.e \(\frac{16x+12}{2}=100\) is 11.825

Given that equation  \(\frac{16x+12}{2}=100\)  and asked to evaluate the value of x in the given equation

⇒ \(\frac{16x+12}{2}=100\)(given equation)

To solve the given equation, need to use the various mathematical  operations i.e division and subtraction)

⇒8x+6=100 ( using the operation division)

⇒8x=100-6 (using the operation subtraction)

⇒8x=94

⇒x=\(\frac{94}{8}\)(using the operation division)

⇒x=11.825

By using the mathematical  operations i.e division and subtraction the value of x came as 11.825

⇒Therefore, The value of x in the given equation i.e \(\frac{16x+12}{2}=100\) is 11.825

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The trigonometric function gives the ratio of different sides of a right-angle triangle. The value of sine and cosine will be always less than a unit.

In a unit circle, the radius of the circle represents the hypotenuse of the triangle. Since the hypotenuse is the largest side of the triangle, the ratio of the perpendicular to the hypotenuse and the base to the hypotenuse both will be less than the hypotenuse, therefore, 1. Hence, the value of sine and cosine will be always less than a unit.

In construction, we use trigonometry. For figuring areas of triangular shapes, similar to many concepts and phenomena in mathematics.

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The value of x in the following diagram in which the length of Q to line EF is 3x+1 and the length of Q from the line HG is x+8, is 3.5 units.

The line which is drawn from the center of the circle perpendicular to  the chord in the circle bisect the chord into two equal shape.

In the given, diagram the length of Q to line EF is 3x+1 and the length of Q from the line HG is x+8.

These both the lines are equal in length as both are drawn from the center of the circle and has a perpendicular bisector for the 15 units length chord in the circle. Thus,

\(3x+1=x+8\\3x-x=8-1\\2x=7\\x=\dfrac{7}{2}\\x=3.5\)

Thus, the value of x in the following diagram in which the length of Q to line EF is 3x+1 and the length of Q from the line HG is x+8, is 3.5 units.

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Answer:

i think 45

Step-by-step explanation:

Asked yourself what was wrong and how you would

Answer:

1/6 2/6 1/3

Step-by-step explanation:

one of those 3

The equation for the function is f(x) = 3 * cos (16x + \(\frac{16\pi }{3}\) ) + 5.

What is an equation?

A assertion that two expressions with variables and/or numbers are equal is referred to as an equation. The fundamental driving forces behind the evolution of mathematics have been attempts to logically solve equations, which are really questions.

We know that f(x) = a cos (bx + c) + d.

We are given

a = 3 which is the amplitude

Period = 8π

b = 16

Phase shift = \(\frac{c}{b}\)

⇒\(\frac{\pi }{3}\) = \(\frac{c}{16}\)

⇒ c = \(\frac{16\pi }{3}\)

d = 5 as there is upward translation

So, from this we get the equation as

⇒f(x) = 3 * cos (16x + \(\frac{16\pi }{3}\) ) + 5

Hence, the equation for the function is f(x) = 3 * cos (16x + \(\frac{16\pi }{3}\) ) + 5.

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Question: Write an equation for a function with the given characteristics. A cosine curve with a period of 8π, an amplitude of 3, a right phase shift of π/3, and a vertical translation up 5 units.

f(x) = ______________

The stack of 31 sheets of aluminum will be approximately 7.099 inches thick.



- One sheet of aluminum is 0.229 inches thick.
- To find the thickness of a stack of sheets, we need to multiply the thickness of one sheet by the number of sheets.
- So, to find the thickness of 31 sheets of aluminum, we need to multiply 0.229 inches by 31.
- 0.229 x 31 = 7.099 inches.
- Therefore, the stack of 31 sheets of aluminum will be approximately 7.099 inches thick.



To determine the thickness of a stack of 31 sheets of aluminum, we need to consider the thickness of one sheet and then multiply it by the number of sheets in the stack.

Firstly, we are given that one sheet of aluminum is 0.229 inches thick. This means that if we were to measure the thickness of one sheet using a ruler or calipers, we would get a reading of 0.229 inches.

Next, we need to find the thickness of 31 sheets of aluminum. To do this, we need to multiply the thickness of one sheet by the number of sheets. This can be expressed as:

Thickness of stack = Thickness of one sheet x Number of sheets

Substituting the values we have:

Thickness of stack = 0.229 x 31

Multiplying these two values gives us:

Thickness of stack = 7.099 inches

Therefore, the stack of 31 sheets of aluminum will be approximately 7.099 inches thick.

In conclusion, we can determine the thickness of a stack of sheets by multiplying the thickness of one sheet by the number of sheets. In this case, we were given the thickness of one sheet of aluminum and the number of sheets in the stack, which allowed us to calculate the thickness of the entire stack.

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The best way is to Keep track of how many times you roll a 1, 2, 3, or 4 in 30 rolls. These will represent the days the temperature is above 80° F in June. So, correct option is D.

Option A is not the best way to perform the simulation because it requires repeating the 30 rolls 20 times, which can be time-consuming and may not accurately reflect the true probabilities.

Option B is also not the best way to perform the simulation because it only accounts for the total number of times a temperature above 80°F is rolled, but not how many times it is rolled in a sequence. This can lead to inaccurate results, as consecutive days of above-80°F temperatures are more or less likely depending on the previous day's temperature.

Option C is better than option A because it involves repeating the 30 rolls 100 times, which increases the accuracy of the simulation. However, this may still be time-consuming and unnecessary.

Option D is the best way to perform the simulation because it tracks the number of days the temperature is above 80°F in June based on 30 rolls, which accurately reflects the probabilities given in the problem statement.

This method is efficient and effective in providing an accurate estimate of the probability of having 20 or more days above 80°F in June. Therefore, Option D is the best way to perform the simulation.

So, correct option is D.

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No Solution.

Since, the x-axis (equation y=0) does not intersect y=-7 at any point. The given pair of equations has no solution

Consider the pair of linear equations in two variables x and y.

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

Here a1, b1, c1, a2, b2, c2 are all real numbers.

Note that, a12 + b12 ≠ 0, a22 + b22 ≠ 0

1. If (a1/a2) ≠ (b1/b2), then there will be a unique solution. If we plot the graph, the lines will intersect. This type of equation is called a consistent pair of linear equations.

2. If (a1/a2) = (b1/b2) = (c1/c2), then there will be infinitely many solutions. The lines will coincide. This type of equation is called a dependent pair of linear equations in two variables

3. If (a1/a2) = (b1/b2) ≠ (c1/c2), then there will be no solution. If we plot the graph, the lines will be parallel. This type of equation is called an inconsistent pair of linear equations.

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a = 5, b = 25, c = 0

step by step explanation:

Let the three numbers be a, b, and c. Then, we have the following system of equations:

a + b = c + 20 (1)

a + c = b + 30 (2)

b + c = a + 40 (3)

Adding all three equations together, we get:

2(a + b + c) = 90

Simplifying, we get:

a + b + c = 45

Now, using the hint given in the problem, we can write:

c = x - 10

b = a + 20

a + (a + 20) = (x - 10) + 30

Simplifying this equation, we get:

2a + 20 = x + 20

Solving for x, we get:

x = 2a

Substituting this value of x in the equation c = x - 10, we get:

c = 2a - 10

Now we can express b and c in terms of a:

b = a + 20

c = 2a - 10

Therefore, three numbers that satisfy the given conditions are:

a = 5, b = 25, c = 0

We can verify that the sum of any pair exceeds the third by the given amounts:

a + b = 30 > c + 20 = 20

a + c = 5 > b + 30 = 25

b + c = 15 > a + 40 = 45

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Answer:

It's quite easy

Step-by-step explanation:

people less than 30 years = frequency of people 0 to 15 + 15 to 30 = 8+15 =23

Therefore there are 23 people less than 30 years old.

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Answer:

B. 39.4

Step-by-step explanation:

H is 60, so the new equation would be 60 - 20.6.

60 - 20.6

60.0 - 20.6

The rest of the work is attached.

Answer:

SA = 94 ft²

Step-by-step explanation:

To find the surface area of a rectangular prism, you can use the equation:

SA = 2 ( wl + hl + hw )

SA = surface area of rectangular prism

l = length

w = width

h = height

In the image, we are given the following information:

l = 4

w = 5

h = 3

Now, let's plug in the information given to us to solve for surface area:

SA = 2 ( wl + hl + hw)

SA = 2 ( 5(4) + 3(4) + 3(5) )

SA = 2 ( 20 + 12 + 15 )

SA = 2 ( 47 )

SA = 94 ft²

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Answer: where's the question?

Step-by-step explanation:

Answer:

your question please

Step-by-step explanation:

Answer:

112 inches.

Step-by-step explanation:

L(k)=8(12)+2k

L(k)=96+2k

L(8)=96+2(8)

L(8)=96+16

L(8)=112in

Answer:

112 inches.

step by step

Y= 96 +2x

watch out for the change of units of feet and in.

Answer:

1/20 of a gallon

Step-by-step explanation:

If she divides 1/4 into 5 glasses, the answer would be 0.05, or 1/20 gallons.

Answer: 157.5

Step-by-step explanation:

I would add 45 % again and you'd get 90 % or

150.00 the find 10 % of 75 which is 10*75/100 or 7.5

then add 150.00+ 7.5 = 157.5

Parallel lines are two straight lines that never cross. For this to happen, the lines have to have the same slope.

In this case, the equation given is in what's called "slope-intersect" form. The general form of the slope intercept formula is y=mx + b where m is the slope of the line and b is the point on the Y-axis where the line crosses.

The equation given is y=5x+3 and since the 5 is in the place of m from the general equation, 5 is the slope. Since parallel lines have the same slope, 5 is the answer.

Slope-Intercept Form:

When we're given a linear equation we can immediately see if it's in the slope-intercept form if it follows the format  y=mx+b. As long as y does not have a coefficient the slope and y-intercept are the values of m and b.

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This statement ''The proportion in the body of a normal distribution can never be less than 0.50.'' is false because the proportion in the body of a normal distribution can be less than 0.50, depending on the location of the mean and the spread of the distribution.

In fact, for a normal distribution with a mean of μ and standard deviation of σ, approximately 68% of the area under the curve falls within one standard deviation of the mean (i.e., between μ - σ and μ + σ), which means the proportion in the body of the distribution is about 0.68.

The remaining 32% is split evenly between the tails of the distribution, which means the proportion in each tail is about 0.16.

So, the proportion in the body of the distribution is greater than 0.50.

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Answer:

Step-by-step explanation:

Siny= 4xy +x²

dy/dx(cos y) =4y+ 4x(dy/dx)+2x

making dy/dx the subject

dy/dx(cos y)-4x(dy/dx)=4y+2x

dy/dx(cos y -4x)=4y+2x

dy/dx=(4y+2x)/(cos y -4x)

Answer:

The pizza restaurant put 1/10 of the sauce on each pizza.

Step-by-step explanation:

Take the 3/5, and on a calculator divide the 3 by the 5:

0.6

Then, take the 0.6 and divide it by the 6 pizzas:

0.1, converted into a fraction equals 1/10.

The pizza restaurant put 1/10 of the sauce on each pizza.

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Answer:

(1,0)

Step-by-step explanation:

This is because a system of equations is when two lines cross to form a point that they share. (1,0) is the point where the two lines cross/intersect.

Answer:

(1,0)

Step-by-step explanation:

The answer is where the ines intersect to form a point.

Answer:

13x+38

Step-by-step explanation:

Answer: The answer is B. It is not a function because the domain(x) is repeating and if the x was not repeating it would have been a function :)

Step-by-step explanation:

The right Riemann sum approximation for the integral from 5 to 12 of f(x) * dx, using the subintervals [5,6], [6,9], [9,11], and [11,12], is 5(2) + 3(3) + (-1)(2) + 4(1) = 11.

The right Riemann sum approximation is a method to estimate the area under a curve by dividing the interval into subintervals and using rectangles to approximate the area. In this case, we divide the interval from 5 to 12 into four subintervals: [5,6], [6,9], [9,11], and [11,12]. Each subinterval has a specific width, determined by the difference between its endpoints.

To approximate the area under the curve, we evaluate the value of f(x) at the right endpoint of each subinterval. Referring to the given table, f(6) = 2, f(9) = 3, f(11) = -1, and f(12) = 4. These values represent the heights of the rectangles that approximate the curve within each subinterval.Calculating the area contribution for each subinterval involves multiplying the width of the subinterval by its corresponding height. For the subinterval [5,6], the rectangle's height is 2 and the width is 1, resulting in an area contribution of 2 * 1 = 2. Moving to the subinterval [6,9], the rectangle's height is 3 and the width is 3, giving an area contribution of 3 * 3 = 9.

Similarly, for the subinterval [9,11], the rectangle's height is -1 and the width is 2, resulting in an area contribution of -1 * 2 = -2. Lastly, for the subinterval [11,12], the rectangle's height is 4 and the width is 1, giving an area contribution of 4 * 1 = 4.By summing up the area contributions from each subinterval, we obtain 2 + 9 + (-2) + 4 = 11. Therefore, the right Riemann sum approximation for the integral from 5 to 12 of f(x) * dx is 11. This approximation provides an estimate of the total area under the curve within the specified interval, using rectangles with the right endpoints as the heights.

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The given integral is ∫(0 / x² √(2² + 490)) dx. To solve this integral, we can make a substitution by letting x = 7tan(θ), where θ is between -π/8 and π/8. Then, dx = 2sec²(θ) dθ. The given integral is ∫(0 / x² √(2² + 490)) dx, and after making the substitution x = 7tan(θ), the integral becomes ∫(0 / 98sec³(θ) √(1 + 122.5tan²(θ))) dθ.

Substituting these expressions in the integral, we have ∫(0 / (7tan(θ))² √(2² + 490))(2sec²(θ)) dθ. Simplifying further, we get ∫(0 / 49tan²(θ) √(4 + 490))(2sec²(θ)) dθ. Rearranging the expression under the square root, we have ∫(0 / 49sec²(θ) √(4(1 + 122.5tan²(θ))))(2sec²(θ)) dθ. This can be simplified to ∫(0 / 98sec³(θ) √(1 + 122.5tan²(θ))) dθ.

In summary, the given integral is ∫(0 / x² √(2² + 490)) dx, and after making the substitution x = 7tan(θ), the integral becomes ∫(0 / 98sec³(θ) √(1 + 122.5tan²(θ))) dθ.

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The given integral is ∫(0 / x² √(2² + 490)) dx. To solve this integral, we can make a substitution by letting x = 7tan(θ), where θ is between -π/8 and π/8. Then, dx = 2sec²(θ) dθ. The given integral is ∫(0 / x² √(2² + 490)) dx, and after making the substitution x = 7tan(θ), the integral becomes ∫(0 / 98sec³(θ) √(1 + 122.5tan²(θ))) dθ.

Substituting these expressions in the integral, we have ∫(0 / (7tan(θ))² √(2² + 490))(2sec²(θ)) dθ. Simplifying further, we get ∫(0 / 49tan²(θ) √(4 + 490))(2sec²(θ)) dθ. Rearranging the expression under the square root, we have ∫(0 / 49sec²(θ) √(4(1 + 122.5tan²(θ))))(2sec²(θ)) dθ. This can be simplified to ∫(0 / 98sec³(θ) √(1 + 122.5tan²(θ))) dθ.

In summary, the given integral is ∫(0 / x² √(2² + 490)) dx, and after making the substitution x = 7tan(θ), the integral becomes ∫(0 / 98sec³(θ) √(1 + 122.5tan²(θ))) dθ.

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B....................

Answer:

b. Arithmetic .

Step-by-step explanation:

b because  to get the next term you add 8.