Someone please answer fast

Answer:

30

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

i really don't have a method for this, just try a number you think is close, go up, or down depending on the number

1) a) The sum from i = 1 to n of 2^i is (2^(n+1) - 2) for n >= 1.

b) The sum from i = 1 to n of 1/(i(i+1)) is 1 - 1/(n+1) for n >= 1.

c) The inequality n! > 2^n holds for n >= 4.

2) The proof that sqrt(2) is irrational uses a proof by contradiction.

The sum of the first n odd positive integers is n^2.

3) |A intersect B| can be found by counting the common multiples of 8 and 125.

|A union B| can be found by adding the total number of multiples of 8 and 125, excluding the common multiples counted in the intersection.

1) a) To find the sum from i = 1 to n of 2^i, we can use the formula for the sum of a geometric series. The sum is given by (2^(n+1) - 2) for each n >= 1.

b) To find the sum from i = 1 to n of 1/(i(i+1)), we can use partial fraction decomposition. The sum is given by 1 - 1/(n+1) for each n >= 1.

c) To prove that n! > 2^n for each n >= 4, we can use mathematical induction. The base case is n = 4, and then we assume it holds for some k >= 4 and prove it for k + 1.

2) To prove that sqrt(2) is irrational, we can use a proof by contradiction. Assume that sqrt(2) is rational, express it as a fraction p/q in simplest form, and derive a contradiction by showing that p and q must have a common factor of 2.

To find the sum of the first n odd positive integers, we can use the formula for the sum of an arithmetic series. The sum is given by n^2 for each n >= 1.

3) To find |A intersect B|, we need to find the common multiples of 8 and 125 that are less than 100,000. By finding the least common multiple (LCM) of 8 and 125, which is 1000, we can count the number of multiples of 1000 that are less than 100,000.

To find |A union B|, we need to find the total number of multiples of 8 and 125, excluding any common multiples counted in |A intersect B|. By adding the number of multiples of 8 and 125, and subtracting |A intersect B|, we can find |A union B|.

To determine the number of students on the CS team, we can use the principle of inclusion-exclusion. By adding the number of students on the math team and the CS team, and subtracting the number of students on both teams, we can find the number of students on the CS team.

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In how many ways can 5 different novels, 3 different mathematics books, and 1 biology book be arranged on a bookshelf if the mathematics books must be together and the novels must be together?

To find the number of ways, in which 5 different novels, 3 different mathematics books, and 1 biology book can be arranged on a bookshelf if the mathematics books must be together and the novels must be together, we can use the concept of permutation formulae.

Permutation formulae is the formula used to find out the number of ways in which a set of things can be arranged or ordered without repetition of the arrangement. Here, the mathematics books must be together and the novels must be together. Therefore, we can group the mathematics books together as one book and the novels together as one book. That is, we have two groups, one of size 3 (mathematics books) and one of size 5 (novels).

Therefore, the problem now reduces to finding the number of ways in which two groups of books can be arranged on a shelf. This can be done by using the permutation formulae as follows:

First, we find the number of ways to arrange the two groups on the shelf, ignoring the order within the groups. There are two ways to arrange the two groups: either the mathematics books can come first or the novels can come first.

Second, we find the number of ways to arrange the mathematics books within their group. There are 3! = 6 ways to arrange the 3 mathematics books within their group.

Third, we find the number of ways to arrange the novels within their group. There are 5! = 120 ways to arrange the 5 novels within their group.

Therefore, the total number of ways to arrange the books is given by the product of the number of ways to arrange the two groups, the number of ways to arrange the mathematics books within their group, and the number of ways to arrange the novels within their group.

Thus, the number of ways to arrange the books is:2 x 6 x 120= 1440.

Answer: 1440 words

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Answer:

Aman is correct with his answer of 8.

Step-by-step explanation:

This is because the 3 in 5 - (-3) is NEGATIVE, not positive. 5 - 3 would be 2, however, 5 - (-3) would be 8. Double negatives make a positive.

Distances 18 feets

Time 3 second

How Many seconds are in 1hour? 60x60second

So he salís 18/3=6 feets per second

so multiply 6x60x60 and You get the resultver

Answer:

x=0

Step-by-step explanation:

Answer:

Step-by-step explanation:

David uses 1 table spoon of sugar for every 1.25 cups of water to prepare lemonade.

Therefore, Number of table spoons of sugar required (S) ∝ Cups of water required (w)

⇒ S ∝ w

⇒ S = kw

⇒ k = \(\frac{S}{w}\)

⇒ k = \(\frac{1}{1.25}\) = 0.8

So the formula to calculate the amount of water will be,

S = 0.8w

⇒ w = \(\frac{S}{0.8}\)

where k = proportionality constant

Now we can complete the table with the help of the formula.

Sugar (tbsp)                   Water (cups)

      1                                     1.25                                                                      

      7                                    8.75    

      3                                    3.75

      5                                    6.25

Answer:

k = 10

Step-by-step explanation:

30+2k+5k=100

Combine like terms

30 + 7k = 100

Subtract 30 from each side

30+7k-30 = 100-30

7k  = 70

Divide each side by 7

7k/7 = 70/7

k = 10

Answer:

k=10

Step-by-step explanation:

We are given the equation:

30+5k+2k=100

We want to find k, therefore we must isolate k on one side of the equation.

First, combine like terms on the left side of the equation. 5k and 2k can be added together.

30+5k+2k=100

30+(5k+2k)=100

30+7k=100

30 is being added to 7k. The inverse of addition is subtraction. Subtract 30 from both sides of the equation.

30-30+7k=100-30

7k= 100-30

7k= 70

k is being multiplied by 7. The inverse of multiplication is division. Divide both sides by 7.

7k/7=70/7

k=70/7

k= 10

The solution to the equation 30+5k+2k=100 is k=10

Answer:

49% chance

step by step

total number of students is 41, 21 picked chemistry

41-21 =20

20÷41 =0.487

0.487 rounded up to 2 decimal places x 100  =49

=49%

Answer:

42.875

Step-by-step explanation:

N = 3.5 cm

So volume = n3 = 3.5^3

Volume = 42.875

Answer:

no, because each y value corresponds to multiple x values. And the x values repeat each other.

Step-by-step explanation:

Answer:

No, because there is more than one of the same x value

Step-by-step explanation:

Answer:

pls is this a question or not.

Step-by-step explanation:

cos(90) = 0

around this point the cos function "mirrors" with opposite signs. cos(<90) is positive and cos(>90) is negative.

but |cos(90-a)| = |cos(90+a)| for 0 <= a <= 90

75 = 90 - 15

105 = 90 + 15

so, a = 15

and because of

|cos(90-a)| = |cos(90+a)| for 0 <= a <= 90

cos (90-15) = cos(75) = -cos(90+15) = -cos(105)

Answer:

4 times 5 equals 20 so that's your answer

Step-by-step explanation:

:)Hope this helps!!

Answer:

20 baseballs

Step-by-step explanation:

Luis has 4balls and Jonah has 5times(as many baseballs card as Luis)

5(4)=20

hence,Jonah has 20cards

The length of the diagonal of the square rounded to the nearest foot is 141.2 feet.

The area of a square is a product of it's any two sides or a product of diagonals divided by two. If the side has a length then the diagonal is a√2.

The perimeter of a square is the sum of the lengths of all the sides.

Given, A square garden has sides 100 ft long.
Now, If we draw a diagonal it becomes a right-angled triangle with a height of 100 ft and a base of 100 feet.

Therefore, By applying Pythagoras' theorem we have,

The length of the diagonal is = √(100² + 100²).

= √(10000 + 10000).

= √(20000) feet.

= 141.42 Or 141 feet.

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The distance from vector y to the plane spanned by u₁ and u₂ in R³ is approximately 3.6.

The distance from vector y to the plane in R³ spanned by u₁ and u₂, we can use the formula for the distance between a point and a plane.

The formula for the distance between a point P and a plane with normal vector N is given by

d = |(P - P₀) · N| / |N|

where P₀ is a point on the plane, · denotes the dot product, and |N| represents the magnitude of vector N.

In this case, the point P is represented by vector y, and the plane is spanned by the vectors u₁ and u₂. We need to find the normal vector N of the plane.

Since the plane is spanned by u₁ and u₂, we can find the normal vector N by taking the cross product of u₁ and u₂:

N = u₁ × u₂

Let's calculate the cross product:

N = [-3] [-2] [-4] × [ 2] [ 1] [ 2]

N = [(-4 × 2) - (1 × 2)] [(1 × -2) - (-4 × 2)] [(-3 × 2) - (1 × -2)]

N = [-8 - 2] [-2 - (-8)] [-6 - (-2)]

N = [-10] [ 6] [-4 ]

Now that we have the normal vector N, we can find the distance from y to the plane.

P₀ is any point on the plane. We can choose P₀ to be the origin (0, 0, 0) for convenience.

P₀ = [0] [0] [0]

Substituting the values into the distance formula

d = |(y - P₀) · N| / |N|

d = |[6] - [0]| · [-10] / |[-10]| [-8] - [0] [ 6] [6] - [0] [-4 ]

d = |[6] · [-10] / |[-10]| [-8] [ 6] [6] [-4 ]

d = | -60 + 48 - 24| / |-10| |-72 - 24 + 0| | 6| | 36 + 0 - 0| |-4 |

d = |-36| / 10 |-96| | 6| | 36| |-4 |

d = 36 / 10 96 6 36 4

d = 3.6

Therefore, the distance from vector y to the plane spanned by u₁ and u₂ in R³ is approximately 3.6.

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Answer:

a. y=x^2

Step-by-step explanation:

desmos graphing calculator

Answer:

PT=RT

PR is prependicular to qs

PQ=QR

QPR is congruent to SPR

Step-by-step explanation:

All the correct statements are,

⇒ PQR is supplementary to 2QPS.

⇒ PR = QS

⇒ PS is parallel to QR.

⇒ PT = RT

⇒ PR is perpendicular to QS.

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

Given that;

⇒ PQRS is a rhombus.

Now, We know that;

Two angles are supplementary when they add up to 180 degrees. Angles in rhombus are equal two to two.

We can assume that;

⇒ ∠PQR = a

⇒ ∠ QPS = b

Here, Besides, a rhombus is a quadrilateral and it is true that the interior angles of a quadrilateral add up to 360 degrees, thus:

⇒ 2a + 2b = 360°

⇒ a + b = 180°

Hence, PQR is supplementary to angle QPS.

Since, the four sides of a rhombus are all equals.

Hence, PR = QS

And, By definition of rhombus;

⇒ PS is parallel to QR.

⇒ PT = RT

⇒ PR is perpendicular to QS.

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The conditions that must be met to use the normal approximation for the confidence level are np>5 and n(1-p)>5

Sampling Distribution: A sampling distribution is a probability distribution of a statistic that is obtained through repeated sampling of a specific population. It describes a range of possible outcomes for a statistic, such as the mean or mode of some variable, of a population.

Given that the sampling distribution of the population proportion is based on a binomial distribution.

The conditions that must be met to use the normal approximation for the confidence level are np>5 and n(1-p)>5

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Where the above is given, the required angle m∠BAC = 45°.

In triangle ABC. AC represents the foreman’s line of sight to the top of the landfill. Landfill height is BC

The triangle is geometric shape which includes 3 sides and sum of interior angle should not grater than 180°

According to conditions angle b = 90°

The sum of angles of a triangle= 180°

That is a + b + c = 180

Therefore, c = a

       a = (180 - b)/2

          = (180 - 90) / 2

          = 90 / 2

          = 45°

Hence, the required angle m∠BAC = 45°

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Question 1 Create Triangle ABC by drawing AC. Segment AC represents the foreman’s line of sight to the top of the landfill. What is Angle m BAC?

A within-groups ANOVA, also known as a repeated-measures ANOVA, is used to analyze the differences between three or more groups of scores when each individual or subject is measured more than once.

This type of ANOVA is appropriate in situations where you have measured the same group of individuals or subjects under multiple conditions, treatments, or time points.

Here are some situations where it would be necessary to use a within-groups ANOVA:

A medical researcher investigating the effects of different dosages of a drug on blood pressure.

A psychologist interested in the effects of different types of therapy on depression.

An educational researcher wants to compare the effectiveness of three different teaching methods on students' test score.

In all of these situations, a within-groups ANOVA would be necessary to compare the means of the different conditions or treatments while accounting for the fact that each participant was measured multiple times.

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Answer: 50 + m

Step-by-step explanation:

From the question, Erica and John are making brackets and Erica makes 25 bracelets while John makes m more bracelets than Erica. The total number of bracelets made will be:

Erica bracelet = 25

John bracelet = 25 + m

Total bracelet = 25 + 25 + m

= 50 + m

The expression that represents the total number of bracelets Erica and John made is 50 + m

On average, Jacques won 7.10 marbles per classmate, including those who were absent from school.

Let's start with the total number of classmates. Jacques has 121 classmates, but 19.01% of them are not in school this week. To find out how many classmates are absent, we can multiply the total number of classmates by the percentage of classmates who are absent:

121 x 19.01% = 23

So, Jacques has 121 - 23 = 98 classmates present in school this week.

Now, let's calculate the total number of marbles Jacques won. We know that he won 36 marbles out of 5 classmates, so on average, he won 36 / 5 = 7.2 marbles per classmate. Similarly, he won 13 marbles out of 24 classmates, so on average, he won 13 / 24 = 0.54 marbles per classmate. For the remaining classmates, he won 11 marbles per classmate.

To calculate the total number of marbles Jacques won, we can add up the marbles he won from each group of classmates:

(7.2 x 5) + (0.54 x 24) + (11 x 74) = 856.96

Now, to find the average number of marbles Jacques won per classmate, we divide the total number of marbles he won by the total number of classmates, including those who were absent:

856.96 / 121 = 7.10

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Answer:

c

Step-by-step explanation:

c

Answer:

the answer is C ;D

Step-by-step explanation:

Answer:

130°

Step-by-step explanation:

20° + 30° =50°

a triangles full angle is 180°

180° - 50° = 130°

The point that is located at the ordered pair (4, -2) is given as follows:

Point B.

The general format of an ordered pair is given as follows:

(x,y).

In which the coordinates are given as follows:

On the coordinate plane, we have that:

Hence the coordinates for this problem are given as follows:

A(-2, 4), B(4, -2), C(-4, 2) and D(2, -4).

The graph is given by the image presented at the end of the answer.

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Answer:

The data is skewed left with an outlier.

Explanation:

Skewness occurs when the entries of the data set are either distributed more to the left or more to the right on the number line. In this case, most of the entries lie to the right, so the data set is skewed left.

We solved a problem after several missteps. One thing we are not certain of. We should:

When we are unsure about a part of a calculation, it is a good idea to check for hints that address that part of the calculation. This can help us confirm or correct your understanding of the problem. In addition, speaking with an instructor or classmate can provide valuable insight and help clarify any confusion.

Finally, if we still feel unsure, submitting our answer and then adjusting it based on feedback can help us improve our understanding and knowledge of the material. All of these options can help ensure that we have the most accurate and complete understanding of the problem.

This question should be provided with answer choices, which are:

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The amount of X and Y that can give Adam the most utility is (αI/ Px) units of good X and (βI/ Py) units of good Y.

The Cobb-Douglas utility function represents a consumer's preferences towards two goods, X and Y. The function for Adam's preferences is given by:

U(x,y)=x α * y β, where α + β = 1. Given the price of good X is Px, the price of good Y is Py, and Adam's disposable income is I.

The total expenditure (E) for two goods will be:

E= PxX + PyY, Where X is the quantity of good X and Y is the quantity of good Y.

Adam's income constraint can be represented as:

I = PxX + PyY

We can rewrite the above expression as:

X = (I/ Px) - ((Py/Px)Y)

Thus, Adam's utility function can be written as:

U = X α * Y β

Substituting X with the expression we derived above, we get:

U = [(I/ Px) - ((Py/Px)Y)] α * Y β

To get the optimal consumption bundle, we need to maximize the utility function, which is given by:

MUx/ Px = α(Y/X)β

Muy/ Py = β(X/Y)α

Multiplying the two equations, we get:

MUx * Muy = αβ

Now, substituting the value of α + β = 1 in the above equation, we get:

MUx * Muy = α(1 - α)

Similarly, dividing the two equations, we get:

MUx / Muy = α/β

Now, we have two equations and two unknowns. We can solve them to get the values of X and Y, which maximize Adam's utility.

After solving, we get:

X = (αI / Px)

Y = (βI / Py)

Thus, the amount of X and Y that can give Adam the most utility is (αI/ Px) units of good X and (βI/ Py) units of good Y.

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