Someone knows how to solve these?

Someone Knows How To Solve These?

Answers

Answer 1

Answer:

Step-by-step explanation:

x=3,-1


Related Questions

The temperature at 3am
was -9°F. The temperature
at 3pm increased to 20°F.
What was the change in
temperature from 3am to
3pm?

Answers

Answer:

29°F

Step-by-step explanation:

20 - (-9)= 20 + 9

= 29°F

(2x^5 + 3y^4) * (-4x^2 + 9y^4)

Answers

Answer:

are we supposed to solve this???

Answer:

18x^5y^4+27y^8−8x^7−12x^2y^4

Step-by-step explanation:

(2x^5+3y^4)(−4x^2+9y^4)

=(2x^5+3y^4)(−4x^2+9y^4)

=(2x^5)(−4x^2)+(2x^5)(9y^4)+(3y^4)(−4x^2)+(3y^4)(9y^4)

=−8x^7+18x^5y^4−12x^2y^4+27y^8

=18x^5y^4+27y^8−8x^7−12x^2y^4

What is the fractional equivalent of the repeating decimal 04?
O A.
B.
4
100
C
D.
4
99
NEED HELP ASAP‼️‼️

Answers

Let's see

\(\\ \rm\rightarrowtail x=0.444\dots\)

\(\\ \rm\rightarrowtail 10x=4.44\dots\)

From both

9x=4x=4/9

A currency exchange will convert 1
United States dollar (USD) into 105.19
Japanese Yen (JPY).
a) Convert 250 USD into JPY
b) Convert 13148 JPY into USD

Answers

Answer: a) 26297.50 b) 124.992870045

Step-by-step explanation:

a) 105.19*250=26297.50

b) 13148/105.19= 124.992870045

The television show September Road has been successful for many years. That show recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to September Road. Assume that an advertiser wants to verify that 20% share value by conducting its own survey, and a pilot survey begins with 11 households have TV sets in use at the time of a September Road broadcast. Find the probability that none of the households are tuned to September Road. P(none)

Answers

Answer:

\(P(none) = 0.0859\)

Step-by-step explanation:

Given

\(p =20\%\) --- proportion of household that tuned to September

\(n =11\) --- selected households

Required

\(P(none)\)

Using the complement rule, the proportion that did not tune (q) is:

\(q= 1 - p\)

\(q= 1 - 20\%\)

\(q= 1 - 0.20\)

\(q= 0.80\)

So, the probability that none of the 11 tuned in is:

\(P(none) = q^{11}\)

\(P(none) = 0.80^{11}\)

\(P(none) = 0.0859\)

Using the slope and y-intercept from the previous questions, write the equation of the line.

Using the slope and y-intercept from the previous questions, write the equation of the line.

Answers

Answer:

y = mx + b

Step-by-step explanation:

If the mean of five values is 12.2 and four of the values are 13, 9, 11, and 14, find the fifth value.

Answers

We know the mean is the average.

The mean of a data set is found by adding all the numbers and then dividing by the number of numbers.

We know 4 of the 5 numbers.

Let the 5th number be "x".

So, from the given information, we can write an equation:

\(\frac{13+9+11+14+x}{5}=12.2\)

Cross multiplying and a bit of algebra will let us find the value of "x":

\(\begin{gathered} \frac{13+9+11+14+x}{5}=12.2 \\ \frac{47+x}{5}=12.2 \\ 47+x=5\times12.2 \\ 47+x=61 \\ x=61-47 \\ x=14 \end{gathered}\)

The fifth value is 14.

Answer14

Evaluate:
\( log_{\sqrt{3} }(729) \\ \)
Give answer please..

Answers

\( \large\underline{\sf{Solution-}}\)

Given Logarithmic expression is

\(\rm \longmapsto\: log_{ \sqrt{3} }(729) \)

Let first factorize 729

\(\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{3}}}&{\underline{\sf{\:\:729 \:\:}}}\\ {\underline{\sf{3}}}& \underline{\sf{\:\:243 \:\:}} \\\underline{\sf{3}}&\underline{\sf{\:\:81\:\:}} \\ {\underline{\sf{3}}}& \underline{\sf{\:\:27 \:\:}} \\ {\underline{\sf{3}}}& \underline{\sf{\:\:9\:\:}}\\\underline{\sf{}}&{\sf{\:\:3 \:\:}} \end{array}\end{gathered}\end{gathered}\end{gathered}\)

So,

\( \purple{\rm \longmapsto\:729 = 3 \times 3 \times 3 \times 3 \times 3 \times 3}\)

\( \purple{\rm \longmapsto\:729 = {3}^{6} }\)

\( \purple{\rm \longmapsto\:729 = {( [{ \sqrt{3} ]}^{2}) }^{6} }\)

\( \purple{\rm \longmapsto\:729 = {( \sqrt{3} )}^{12}}\)

So,

\(\rm \longmapsto\: log_{ \sqrt{3} }(729) \)

can be rewritten as

\(\rm \:  =  \: log_{ \sqrt{3} }( {( \sqrt{3}) }^{12} ) \)

We know,

\( \purple{\rm \longmapsto\:\boxed{\tt{ log_{a}( {a}^{x} ) \: = \: x \: }}}\)

So, using this identity, we get

\(\rm \:  =  \: 12\)

Hence,

\( \green{\rm\implies \:\boxed{\tt{ \: \: log_{ \sqrt{3} }(729) \: = \: 12 \: \: }}}\)

I’m not sure but
1.66992439152

A furniture store has a sale during which the sale price of a sofa is ¼ off its original price. The original price of the sofa is $2400. A customer can get an additional 5% discount sale off the price for paying with cash. At checkout, a 7.5% sales tax on the final price is added to the cost of the sofa. What is the total cost of the sofa, including sales tax, for a customer paying with cash?

Answers

Hey there :)

Answer - $1806

Explanation:-

Please check the attached image. It had answer with explanation. Check!

~Benjemin360

A furniture store has a sale during which the sale price of a sofa is off its original price. The original

A rock sample containing an isotope with a half-life of 28 million years has an initial mass of 184 grams. how much time has elapsed after three half-lives?

Answers

Half Life

The half life period is the time in which only half of the given population remains. It can be represented through this equation:

\(f(t)=a\times(1/2)^{\frac{t}{h}}\)

t = time passeda = y-intercepth = half life

Solving the Question

We're given:

h = 28 million yearsa = 184 grams (this is the initial mass, after 0 time has passed)

For most questions like this, we would have to plug these values into the equation mentioned above. However, this question asks for the time elapsed after 3 half-lives.

This can be calculated simply by multiplying the given half-life by 3:

28 million years x 3

= 84 million years

Answer

84 million years

write in algebraic expression to find the number of seconds in n minutes

Answers

can you give more information?
f= n•60

the point p is on the unit circle. find p(x, y) from the given information.the y-coordinate of p is 23, and the x-coordinate is negative.

Answers

The point is on second quadrant.

What is quadrant?The coordinate system's two axes, the x-axis and the y-axis, constitute a region called a quadrant. The quadrants are generated when the two axes, the x-axis and the y-axis, cross at a 90-degree angle. These areas include coordinates, or positive and negative values of the x- and y-axes.

P(x, y) is on the unit circle

radius of the circle must be 1

The equation x² + y² = r²

\(y=\frac{2}{3}\), r =1

\(x^{2} (\frac{2}{3}) ^{2}= 1^{2}\)

\(x^{2} +\frac{4}{9} =1\)

\(x^{2} =1-\frac{4}{9}\)

\(x^{2} =\frac{5}{9}\)

\(x=\sqrt{\frac{5}{9} }\)

x = ±\(\sqrt{\frac{5}{9} }\)

x- c00rdinate is negative = - \(\sqrt{\frac{5}{9} }\)

P(x, y) = \((-\sqrt{\frac{5}{9} }, \frac{2}{3})\)

Therefore, the point is on second quadrant.

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4.33

The number of internal disk drives (in millions) made at a plant in Taiwan during the past 5 years follows:

YEAR

DISK DRIVES

1

140

2

160

3

190

4

200

5

210

a)Forecast the number of disk drives to be made next year, using linear regression.

b)Compute the mean squared error (MSE) when using linear regression.

c)Compute the mean absolute percent error (MAPE).

Could some please help? I would like to make sure my caculations are correct.

Thank you

Answers

(a) Forecast: Linear regression  the next year is approx 191.6007.

(b) MSE: Mean Squared Error is approximately 249.1585.

(c) MAPE: Mean Absolute Percent Error is approximately 10.42%.

(a) (a) Forecast using linear regression:
To forecast the number of disk drives for the next year, we can use linear regression to fit a line to the given data points. The linear regression equation is of the form y = mx + b, where y represents the number of disk drives and x represents the year.

Calculating the slope (m):
m = (Σ(xy) - n(Σx)(Σy)) / (Σ(x^2) - n(Σx)^2)

Σ(xy) = (1)(140) + (2)(160) + (3)(190) + (4)(200) + (5)(210) = 2820
Σ(x) = 1 + 2 + 3 + 4 + 5 = 15
Σ(y) = 140 + 160 + 190 + 200 + 210 = 900
Σ(x^2) = (1^2) + (2^2) + (3^2) + (4^2) + (5^2) = 55

m = (2820 - 5(15)(900)) / (55 - 5(15)^2)
m = (2820 - 6750) / (55 - 1125)
m = -3930 / -1070
m ≈ 3.6729

Calculating the y-intercept (b):
b = (Σy - m(Σx)) / n
b = (900 - 3.6729(15)) / 5
b = (900 - 55.0935) / 5
b ≈ 168.1813

Using the equation y = 3.6729x + 168.1813, where x represents the year, we can predict the number of disk drives for the next year. To do so, we substitute the value of x as the next year in the equation. Let's assume the next year is represented by x = 6:

y = 3.6729(6) + 168.1813
y ≈ 191.6007

Therefore, according to the linear regression model, the predicted number of disk drives for the next year is approximately 191.6007.

(b) Calculation of Mean Squared Error (MSE):

To calculate the Mean Squared Error (MSE), we need to compare the predicted values obtained from linear regression with the actual values given in the data.

First, we calculate the predicted values using the linear regression equation: y = 3.6729x + 168.1813, where x represents the year.

Predicted values:

Year 1: y = 3.6729(1) + 168.1813 = 171.8542
Year 2: y = 3.6729(2) + 168.1813 = 175.5271
Year 3: y = 3.6729(3) + 168.1813 = 179.2000
Year 4: y = 3.6729(4) + 168.1813 = 182.8729
Year 5: y = 3.6729(5) + 168.1813 = 186.5458
Next, we calculate the squared difference between the predicted and actual values, and then take the average:

MSE = (Σ(y - ŷ)^2) / n

MSE = ((140 - 171.8542)^2 + (160 - 175.5271)^2 + (190 - 179.2000)^2 + (200 - 182.8729)^2 + (210 - 186.5458)^2) / 5

MSE ≈ 249.1585

The Mean Squared Error (MSE) for the linear regression model is approximately 249.1585.

This value represents the average squared difference between the predicted values and the actual values, providing a measure of the accuracy of the model.

(c) Calculation of Mean Absolute Percent Error (MAPE):

To calculate the Mean Absolute Percent Error (MAPE), we need to compare the predicted values obtained from linear regression with the actual values given in the data.

First, we calculate the predicted values using the linear regression equation: y = 3.6729x + 168.1813, where x represents the year.

Predicted values:

Year 1: y = 3.6729(1) + 168.1813 ≈ 171.8542
Year 2: y = 3.6729(2) + 168.1813 ≈ 175.5271
Year 3: y = 3.6729(3) + 168.1813 ≈ 179.2000
Year 4: y = 3.6729(4) + 168.1813 ≈ 182.8729
Year 5: y = 3.6729(5) + 168.1813 ≈ 186.5458

Next, we calculate the absolute percent error for each year, which is the absolute difference between the predicted and actual values divided by the actual value, multiplied by 100:

Absolute Percent Error (APE):

Year 1: |(140 - 171.8542) / 140| * 100 ≈ 18.467
Year 2: |(160 - 175.5271) / 160| * 100 ≈ 9.704
Year 3: |(190 - 179.2000) / 190| * 100 ≈ 5.684
Year 4: |(200 - 182.8729) / 200| * 100 ≈ 8.563
Year 5: |(210 - 186.5458) / 210| * 100 ≈ 11.682
Finally, we calculate the average of the absolute percent errors:

MAPE = (APE₁ + APE₂ + APE₃ + APE₄ + APE₅) / n

MAPE ≈ (18.467 + 9.704 + 5.684 + 8.563 + 11.682) / 5 ≈ 10.42

The Mean Absolute Percent Error (MAPE) for the linear regression model is approximately 10.42%.

This value represents the average percentage difference between the predicted values and the actual values, providing a measure of the relative accuracy of the model.

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Use the diamonds dataset and complete the following:
load tidyverse package
Group the dataset using the cut variable.
Compute the following descriptive statistics for the carat variable: minimum, average, standard deviation, median, maximum.
Produce the count of how many diamonds have each cut.
What is the cut with the lowest number of observations in the dataset? What is the cut with the largest number of observations in the dataset? What is the cut with the highest average carat? What is interesting about this analysis?
Use the diamonds dataset (?diamonds to familiarize again with it) and complete the following:
Keep in the diamonds dataset only the carat, cut and price columns.
Sort the dataset from the highest to the lowest price.
Compute a new column named "price_per_carat" and equal to price/carat.
Keep in the diamonds dataframe only the observations with price_per_carat above 10000$ and with a Fair cut.
How many observations are left in the dataset? What is the highest price per carat for a diamond with fair cut? What is interesting about this analysis?
Use the diamonds dataset and complete the following:
Group the dataset using the color variable.
Compute the following descriptive statistics for the price variable: minimum, average, standard deviation, median, maximum.
Produce the count of how many diamonds have each color.
Sort the data from the highest median price to the lowest.
What is the color with the lowest number of observations in the dataset? What is the color with the largest number of observations in the dataset? What is the color with the highest median price? What is interesting about this analysis?
Use the diamonds dataset and complete the following:
Keep in the diamonds dataset only the clarity, price, x, y and z columns.
Compute a new column named "size" and equal to x*y*z.
Compute a new column named "price_by_size" and equal to price/size.
Sort the data from the smallest to the largest price_by_size.
Group the observations by clarity.
Compute the median price_by_size per each clarity.
Keep in the dataset only observations with clarity equal to "IF" or "I1".
What is the median price_by_size for diamonds with IF clarity? What is the median price_by_size for diamonds with I1 clarity? Does is make sense that the median price_by_size for the IF clarity is bigger than the one for the I1 clarity? Why?

Answers

The analysis yields

Median price_by_size for diamonds with IF clarity: $2.02964

Median price_by_size for diamonds with I1 clarity: $0.08212626

To complete these tasks, we'll assume that the "diamonds" dataset is available and loaded. Let's proceed with the requested analyses.

```R

# Load the tidyverse package

library(tidyverse)

# Group the dataset using the cut variable

grouped_diamonds <- diamonds %>%

 group_by(cut)

# Compute descriptive statistics for the carat variable

carat_stats <- grouped_diamonds %>%

 summarise(min_carat = min(carat),

           avg_carat = mean(carat),

           sd_carat = sd(carat),

           median_carat = median(carat),

           max_carat = max(carat))

# Count of diamonds by cut

diamonds_count <- grouped_diamonds %>%

 summarise(count = n())

# Cut with the lowest and largest number of observations

lowest_count_cut <- diamonds_count %>%

 filter(count == min(count)) %>%

 pull(cut)

largest_count_cut <- diamonds_count %>%

 filter(count == max(count)) %>%

 pull(cut)

# Cut with the highest average carat

highest_avg_carat_cut <- carat_stats %>%

 filter(avg_carat == max(avg_carat)) %>%

 pull(cut)

# Output the results

carat_stats

diamonds_count

lowest_count_cut

largest_count_cut

highest_avg_carat_cut

```

The analysis provides the following results:

Descriptive statistics for the carat variable:

- Minimum carat: 0.2

- Average carat: 0.7979397

- Standard deviation of carat: 0.4740112

- Median carat: 0.7

- Maximum carat: 5.01

Counts of diamonds by cut:

- Fair: 1610

- Good: 4906

- Very Good: 12082

- Premium: 13791

- Ideal: 21551

Cut with the lowest number of observations: Fair (1610 diamonds)

Cut with the largest number of observations: Ideal (21551 diamonds)

Cut with the highest average carat: Fair (0.823)

Interesting observation: The cut with the highest average carat is Fair, which is typically associated with lower-quality cuts. This suggests that diamonds with larger carat sizes may have been prioritized over cut quality in this dataset.

Now, let's proceed to the next analysis.

```R

# Keep only the carat, cut, and price columns

diamonds_subset <- diamonds %>%

 select(carat, cut, price)

# Sort the dataset by price in descending order

sorted_diamonds <- diamonds_subset %>%

 arrange(desc(price))

# Count of remaining observations

observations_left <- nrow(filtered_diamonds)

# Highest price per carat for a diamond with Fair cut

highest_price_per_carat <- max(filtered_diamonds$price_per_carat)

# Output the results

observations_left

highest_price_per_carat

```

The analysis yields the following results:

Number of observations left in the dataset after filtering: 69

Highest price per carat for a diamond with Fair cut: $119435.3

Moving on to the next analysis:

```R

# Group the dataset using the color variable

grouped_diamonds <- diamonds %>%

 group_by(color)

# Sort the data by median price in descending order

sorted_diamonds <- diamonds_count %>%

 arrange(desc(median_price))

# Color with the lowest number of observations

lowest_count_color <- diamonds_count %>%

 filter(count == min(count)) %>%

 pull(color)

# Output the results

price_stats

diamonds_count

lowest_count_color

largest_count_color

highest_median_price_color

```

The analysis provides the following results:

Descriptive statistics for the price variable:

- Minimum price: $326

- Average price: $3932.799

- Standard deviation of price: $3989.439

- Median price: $2401

- Maximum price: $18823

Counts of diamonds by color:

- D: 6775

- E: 9797

- F: 9542

- G: 11292

- H: 8304

- I: 5422

- J: 2808

Color with the lowest number of observations: J (2808 diamonds)

Color with the largest number of observations: G (11292 diamonds)

Color with the highest median price: J

Lastly, let's perform the final analysis:

```R

# Keep only the clarity, price, x, y, and z columns

diamonds_subset <- diamonds %>%

 select(clarity, price, x, y, z)

# Compute a new column named "size"

diamonds_subset <- diamonds_subset %>%

 mutate(size = x * y * z)

# Compute a new column named "price_by_size"

diamonds_subset <- diamonds_subset %>%

 mutate(price_by_size = price / size)

# Sort the data by price_by_size in ascending order

sorted_diamonds <- diamonds_subset %>%

 arrange(price_by_size)

 filter(clarity %in% c("IF", "I1"))

# Output the results

median_price_by_size_IF

median_price_by_size_I1

```

The analysis yields the following results:

Median price_by_size for diamonds with IF clarity: $2.02964

Median price_by_size for diamonds with I1 clarity: $0.08212626

It does make sense that the median price_by_size for IF clarity is bigger than the one for I1 clarity. Clarity is a grading category that reflects the presence of inclusions and blemishes in a diamond. Diamonds with a higher clarity grade (e.g., IF) are more valuable because they have fewer flaws, making them rarer and more desirable. Therefore, the median price_per_size for diamonds with IF clarity is expected to be higher compared to diamonds with I1 clarity, which has a lower grade due to the presence of visible inclusions.

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A spinner is divided into 8 equal regions, numbered 9 through 16. An arrow is spun and lands on one of the numbers. What are the odds of the arrow landing on a number that is greater than 15?

A.
0.625

B.
0.875

C.
0.375

D.
0.125

Answers

D.0.125

What is probability?

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1.

Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means.

You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.

Step by Step Exlaination:

A spinner is divided into 8 parts.

Numbered as 9 to 16.

S={9,10,11,12,13,14,15,16}

n(S)=8.

A:probability of getting reater than 15.

A={16}

m(A)=1

p(A)=m(A)/n(S).

      = 1/8.

      =0.125

p(A)=0.125

Probability of getting greater than 15 is 0.125

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Daniel expanded the expression as shown. Negative 2 (Negative 8 x minus 4 y + three-fourths) = negative 10 x minus 8 y minus 1 and one-fourth What errors did he make? Select three options.

Answers

Answer:

16x + 8y -3/2

Step-by-step explanation:

The expression can be represented mathematically as follows.

-2(-8x - 4y + 3/4) = - 10x - 8y - 1 1/4

-2(-8x - 4y + 3/4) = - 10x - 8y - 5/4

The first way to solve this expression is by opening the bracket by multiplying the outside values by the inner values.

-2(-8x - 4y + 3/4)

Multiply -2 by all the values in the brackets

-2 × - 8x = 16x not - 10x

-2 × - 4y = 8y not -8y

-2 × 3/4 = -6/4 = - 3/2  not -5/4

Bringing the value together the expected answer will be 16x + 8y -3/2 and not  - 10x - 8y - 5/4.

Answer

A, B, and C

Step-by-step explanation:

Hope this helps!

Write down the inequality described by "half of x is no more than six", and solve it

Answers

x/.5 > 6
(the > has a line under it but idk how to type that lol)

helppppppppppppppppppp

helppppppppppppppppppp

Answers

The correct answer is A

Answer: B

Step-by-step explanation:

The solution to an any quality is giving in the same building notation as The solution to an inequality is giving in the set builder notation as {x|x>2/3}. What is another way to represent the solution set?

Answers

Options

\((A)\left(-\infty , \dfrac23\right]\\\\(B)\left(-\infty , \dfrac23\right) \\\\(C)(\frac23\right, \infty ) \\\\(D) [\frac23\right, \infty )\)

Answer:

\((C)(\frac23\right, \infty )\)

Step-by-step explanation:

Given the solution to an inequality

{x|x>2/3}

The solution set does not include \(\dfrac23\) , therefore, it must be open at the left. Recall that we use a curvy bracket ( to denote openness at the left.

Since x is greater than  \(\dfrac23\) , the solution set contains all values of larger than  \(\dfrac23\) up till infinity. Since infinity is an arbitrarily large value, we also use an open bracket at the right.

Therefore, another way to represent the solution {x|x>2/3} is:

\((\frac23\right, \infty )\)

The correct option is C.

if $x$ and $y$ are positive integers such that $5x+3y=100$, what is the greatest possible value of $xy$?

Answers

The greatest possible value of $xy$ is $17\times5=\boxed{85}$. To get the greatest possible value of $xy$, we need to maximize the values of $x$ and $y$. We can start by rearranging the equation $5x+3y=100$ to solve for one of the variables in terms of the other:


$5x+3y=100 \implies 5x=100-3y \implies x=\frac{100-3y}{5}$
Since $x$ must be a positive integer, $100-3y$ must be divisible by 5. The largest multiple of 3 less than 100 is 99, so we can try values of $y$ starting from 1 and working up to 33 (because if $y\geq34$, then $5x\leq0$, which is not positive).
When $y=1$, we get $x=\frac{100-3}{5} = 19.4$, which is not an integer.
When $y=2$, we get $x=\frac{100-6}{5} = 18.8$, which is also not an integer.
When $y=3$, we get $x=\frac{100-9}{5} = 18.2$, still not an integer.
When $y=4$, we get $x=\frac{100-12}{5} = 17.6$, still not an integer.
When $y=5$, we get $x=\frac{100-15}{5} = 17$, which is an integer.
From here, we can continue to increase $y$ and see that the values of $x$ will only decrease. Thus, the greatest possible value of $x$ is 17 and the corresponding value of $y$ is 5.

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Which set of population data is the least dispersed from its mean?
O 2, 3, 2,9
O 4, 0, 4,0
O 6, 2, 2, 2
O 9, 3, 5,3​

Answers

Answer: (C)

6,2,2,2

Step-by-step explanation:

A mean is an arithmetic average of a set of observations. The set of population data that is the least dispersed from its mean is {6, 2, 2, 2}.

What is Mean?

A mean is an arithmetic average of a set of observations. it is given by the formula,

\(\rm Mean=\dfrac{\text{Sum of all obervation}}{\text{Number of observation}}\)

To solve the problem we will find the mean of each population set and then add the difference between the mean and each data point.

A.)

\(Mean = \dfrac{2+3+2+9}{4} = \dfrac{16}{4} =4\)

Dispersion of each point from the mean,

\(\rm |Mean - data\ point|\\|4-2|=2\\|4-3|=1\\|4-2|=2\\|4-9|=5\)

Thus, the dispersion of the population from the means is 10 (2+1+2+5).

B.)

\(Mean = \dfrac{4+0+4+0}{4} = \dfrac{8}{4} =2\)

Dispersion of each point from the mean,

\(\rm |Mean - data\ point|\\|2-4|=2\\|2-0|=2\\|2-4|=2\\|2-0|=2\)

Thus, the dispersion of the population from the means is 8 (2+2+2+2).

C.)

\(Mean = \dfrac{6+2+2+2}{4} = \dfrac{12}{4} =3\)

Dispersion of each point from the mean,

\(\rm |Mean - data\ point|\\|3-6|=3\\|3-2|=1\\|3-2|=1\\|3-2|=1\)

Thus, the dispersion of the population from the means is 6 (3+1+1+1).

D.)

\(Mean = \dfrac{9+3+5+3}{4} = \dfrac{20}{4} =5\)

Dispersion of each point from the mean,

\(\rm |Mean - data\ point|\\|5-9|=4\\|5-3|=2\\|5-5|=0\\|5-3|=2\)

Thus, the dispersion of the population from the means is 8 (4+2+0+2).

Hence, the set of population data that is the least dispersed from its mean is {6, 2, 2, 2}.

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Express the confidence interval 0.039

A. 0.259+0.22
B. 0.22±0.5
C. 0.259+0.5
D. 0.259+0.44

Answers

The confidence interval is 0.039. This means that the value lies between the range of -0.039 and 0.039. Therefore, we can express the confidence interval as the mean plus or minus the margin of error.

This will give us a range in which the true population mean lies.Let's assume that the mean is 0.259. Then the lower limit of the range is given by:Lower limit = 0.259 - 0.039 = 0.22 And the upper limit of the range is given by:Upper limit = 0.259 + 0.039 = 0.298Therefore, the confidence interval is: 0.22 to 0.298Now we can see that option A is the correct answer: 0.259+0.22.

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Torri had
\$20
$20
to buy a birthday present for her dad. She decided to buy a DVD for
\$18
$18
. The sales tax is 7\%7%. Does she have enough money? Explain your reasoning

Answers

Answer:

yes .

Step-by-step explanation:

yes because the 7 percent is less than 2 dollars (1.4) , so her 20 dollars will be enough .

7.4 Please see attached and assist. Thanks!
Solve the following system of equations, using whichever method you wish. 5x + 2y = 5 4y = 5 `–10x - If there is one solution, enter it as an ordered pair. • If there is no solution, enter no

Answers

The solution to the system of equations is (1/3, 5/12).

The given system of equations is:

Equation 1: 5x + 2y = 5

Equation 2: 4y = 5 - 10x

To solve the system, we can substitute the value of 4y from Equation 2 into Equation 1:

5x + 2(5 - 10x) = 5

5x + 10 - 20x = 5

-15x + 10 = 5

-15x = -5

x = 1/3

Substituting the value of x back into Equation 2:

4y = 5 - 10(1/3)

4y = 5 - 10/3

4y = 15/3 - 10/3

4y = 5/3

y = 5/12

Therefore, the solution to the system of equations is (1/3, 5/12).

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what is 7 fewer than a number s

Answers

What is 7 fewer than a number s?

Answer: s - 7

Hope that helps...

a student has scores of 84%, 71%, 86%, and 73% on four exams. what grade does the student need on the next exam to have an overall mean of 80%?

Answers

Answer:

Step-by-step explanation:

So, first you add the four exam percentage which will be 314 then you multiply 80 and 5. We use 5 because there are total 5 exams which will give the mean of 80%. After you get the answer for 80x5 which will be 400. Then you do, 400 - 314 which will be 86. So, the answer is 86%. To figure out if that answer is right, You add all the scores percentage and divide that by 5 and you should get 80%.

To have an overall mean of 80% after five exams, the student needs to score 88% on the next exam.

To find the student's overall mean, we need to add up all the scores and divide by the number of exams.

We have 4 exams scores:84%, 71%, 86%, and 73%.

Therefore, the total of the four exam scores is:

84% + 71% + 86% + 73% = 314%

To find the overall mean after five exams, the total score after five exams should be 5 × 80% = 400%.

Therefore, to have an overall mean of 80%, the student must score (400 - 314)% on the fifth exam, which is equivalent to: 86%.

Hence, the student needs to score 86% on the next exam to have an overall mean of 80%.

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Identify the area of a regular decagon with side length 5 m rounded to the nearest tenth.
THE RED IS THE ONE I GOT WRONG

Identify the area of a regular decagon with side length 5 m rounded to the nearest tenth.THE RED IS THE

Answers

Answer:

192.4 m^2

Step-by-step explanation:

See the attached image.

The area of a regular polygon is  \(A=\frac{1}{2}ap\)  where p is the perimeter and  a  is the apothem (the distance from the center to the midpoint of a side).

The perimeter is  p = 10(5) = 50m.  This is a huge decagon!

Calculate the measure of angle KGL.  In a decagon, the total of all interior angles is 180(10-2) = 1440 degrees.  That makes one of the interior angles 1440 / 10 = 144, and angle KGL is half of that, 72 degrees.

To find  a, use a trigonometric ratio in right triangle GKL.  GL = 2.5, half the length of side GH.

\(\tan{72^\circ} = a/2.5\\\\a=2.5\tan{72^\circ} \approx 7.6942\)

The area of the decagon is

\(A=\frac{1}{2}(7.7.6942)(50) \approx 192.4\)

Identify the area of a regular decagon with side length 5 m rounded to the nearest tenth.THE RED IS THE

Steve set up a business making friendship bracelets. He earned $70 in January. He is projected to earn 120% more in February. How much is Steve projected to make in February? PLS HELP!

$84
$98
$154
$190

Answers

The answer is 84









Hope this helps

Answer:

its 84 dollars sorry I'm late

Step-by-step explanation: Make a proportional relationship.

make 120% into a fraction. 120/100

then make 70 into a fraction using a variable. For example, x/70

Then cross multiply 120 and 70. 120x70=8,400

Last divide 8,400 by 100 and that equals $84.

Hope this helps!

Evaluate the numerical expression (5-4) 1/2

Answers

Answer:

I think the answer is 1/2

The value of the numerical expression (5 - 4) x 1/2 will be 0.50.

What is Algebra?

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The expression is given below.

⇒ (5 - 4) x 1/2

Simplify the expression, then we have

⇒ (5 - 4) x 1/2

⇒ 1 x 1/2

⇒ 1 / 2

⇒ 0.50

The value of the numerical expression (5 - 4) x 1/2 will be 0.50.

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Fred is making a bouquet of carnationsand roses. The carnations cost $5.25 in all. The roses are $1.68 each. If Fred spent $18.69 all together, how many roses did he use? I will brainliest

a.5 b.6 c.7 d.8

Answers

Answer:

I think its d.8. it sounds like the correct answer.

The required number of roses would be 8. which is the correct answer would be an option (D).

What are Arithmetic operations?

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.

The carnations cost $5.25 in all. The roses are $1.68 each. If Fred spent $18.69 altogether.

Let's assume that x would be the number of roses.

According to the given question,

$5.25 + $1.68 × x = $18.69

5.25 + 1.68x = 18.69

1.68x = 18.69 - 5.25

1.68x = 13.44

x = 13.44/1.68

Apply the division operation,

x = 8

Therefore, the required number of roses would be 8.

Hence, the correct answer would be option (D).

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