Answer:
Aerobic exercise includes?
(C) All activities that make you tired and short of breathe.
2. Which choice is an intense exercise that involve short burst of activity in which the muscles worked so hard that they produce energy without using energy?
(B) anaerobic exercise
Explanation:
Which table correctly identifies the abbreviation for SI units of length mass volume and temperature
Answer:
Length: meter
Volume: cubic meter
Mass: kilogram
Temperature: kelvin
Explanation:
Answer:
length = meter/m
mass = kilogram/kg
volume = cubic meter/m^3
temperature = kelvin/o K
Explanation:
SI unit and abbreviations
What is the acceleration of a 56 kg object pushed with a force of 800 newtons?
Answer:
The acceleration of an object can be calculated using Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The equation is:
F = ma
where F is the force, m is the mass, and a is the acceleration.
So, if we know the mass of the object (m = 56 kg) and the force acting on it (F = 800 N), we can calculate the acceleration (a) by dividing the force by the mass:
a = F / m
a = 800 N / 56 kg
a = 14.28 m/s^2
So the acceleration is 14.28 m/s^2
What road would exert the least amount of friction on a car?
A road laid out on an air-hockey table, with a thin coat of ice on the table, and a little bit of oil or lard on top of the ice.
NOTE: The car couldn't actually GO anywhere on this road, because a car needs friction in order to move where you want it to. A car on THIS road would just go wherever the wind blew it.
Calculate the acceleration in meters per second-squared, of a car moving at 10 m/s that accelerates to 24 m/s over a time of 7 second--
Explanation:
v = u + at
24 = 10 + a * 7
24 = 10 * 7 a
a = 24 - 10/7
a = 14/7
a = 2m/sec^2
hope it helps you
Answer:
First calculate change in velocity:
final velocity = 20 m/s.
initial velocity = 30 m/s.
change in velocity = (20 - 30) = -10 m/s.
acceleration = -10 ÷ 25.
acceleration = -0.4 m/s 2
The acceleration value is negative here because the car is slowing down or decelerating.
Explanation:
Because of earth's motion in its orbit as the moon circles around it, a synodic month takes ___________________________________________ than a sidereal month.
Because of Earth's motion in its orbit, a synodic month takes about 2.2 days longer than a sidereal month.
Because of Earth's motion in its orbit as the moon circles around it, a synodic month takes longer than a sidereal month.
A synodic month, also known as a lunar month, is the time it takes for the moon to complete a full cycle of phases, from new moon to new moon. This cycle lasts approximately 29.5 days.
On the other hand, a sidereal month is the time it takes for the moon to complete one orbit around the Earth relative to the stars. This period lasts about 27.3 days.
The reason a synodic month takes longer is due to Earth's own motion around the sun. As Earth moves along its orbit, it takes extra time for the moon to catch up to the same phase relative to the sun.
To put it simply, imagine you and a friend are running in circles around a tree. If your friend is running slower than you, it will take them longer to reach a specific point on the tree, even though they are moving at a constant speed.
In summary, because of Earth's motion in its orbit, a synodic month takes about 2.2 days longer than a sidereal month.
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Absorption of a light wave occurs in what material?
Answer: I think Windows.
Explanation: The absorption of light makes an object dark or opaque to the wavelengths or colors of the incoming wave: Wood is opaque to visible light. Some materials are opaque to some wavelengths of light, but transparent to others. Glass and water are opaque to ultraviolet light, but transparent to visible light.
Option.D-All materials is the correct answer.
Any object, whether living or inert, has the ability to absorb light. Absorption is always influenced by the electromagnetic frequency of the light being transmitted (i.e., its color) and the composition of the object's atoms.
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How much power is used in question #2 if the power time was 100secs
I really need the Formula, substitute & solve , answer with units.
Answer:
I just put a random number for the work
Explanation:
I hope it is ok.
Constanza is on a commuter train between Richville and Shoptown. The train takes 35 minutes to cover the distance between the two towns. The train's average speed is 55 kilometers per hour. Use the the concepts of displacement, velocity, and acceleration to describe the train's motion. Calculate the parameters of motion where possible.
Answer:
1.) Displacement = 32.08m
2.) Velocity = 55km/h
3.) Acceleration = 94.29 km/h^2
Explanation:
Given that the train takes 35 minutes to cover the distance between the two towns. The train's average speed is 55 kilometers per hour. That is,
Time t = 35 minute
Convert it to hours by dividing it by 60
35/60 = 7/12 hours
Speed = 55 km/h
The displacement of the car is:
Displacement = 55 × 7/12 = 32.08 m
The velocity of the car will be 55 km/h
The acceleration of the car will be:
Acceleration = velocity/time
Substitute velocity and time into the formula
Acceleration = 55 ÷ 7/12
Acceleration = 94.29 km/h^2
a) When we blow air with our mouth narrow open, we feel the air cool. When the mouth
is made wide open, we feel the air warm. What are the thermodynamic processes involved in these processes? Explain. [2]
As the air is compressed, the work done on the air causes its temperature to increase.
What is Thermodynamic Process?
A thermodynamic process is a physical change that occurs in a system as it exchanges heat and/or work with its surroundings. It involves a change in one or more thermodynamic variables, such as temperature, pressure, volume, or entropy. There are four main types of thermodynamic processes: isothermal, adiabatic, isobaric, and isochoric.
When we blow air with our mouth narrow open, we feel the air cool because of the adiabatic expansion of the air. Adiabatic expansion is a thermodynamic process in which the air expands rapidly without losing or gaining any heat to or from the surroundings. As the air expands, it does work against the pressure of the surrounding atmosphere, and this work causes the temperature of the air to decrease. This is known as the Joule-Thomson effect.
On the other hand, when the mouth is made wide open, we feel the air warm because of the adiabatic compression of the air. Adiabatic compression is a thermodynamic process in which the air is compressed rapidly without losing or gaining any heat to or from the surroundings.
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Differents between foundamental quantity and derived quantities
Answer:
fundamental quantity can simply be defined as an independent quantity while derived quantity is dependent i.e. the derive their quantities from the fundamental
3. If the net work done on an object is negative, then the object's kinetic energy
a. decreases.
b. remains the same.
c. increases.
d. is zero.
Answer:
I think the answer is B I hope this helps also Im sorry If I'm wrong
question below
image below vvvvvv firsts gets brainiest
Answer:
4-12x
Explanation:
Please mark brainiest
A cart moving at a constant speed of 25 m/s possesses 438 J of kinetic energy what is the mass?
A cart moving at a constant speed of 25 m/s possesses 438 J of kinetic energy, and the mass of the car is 1.6 kg.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object to accelerate it. We must put in the effort to apply force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.
What does "constant speed" refer to?Definition: When an object is moving at a constant speed—that is, its speed does not change—we say it is moving at a constant speed. steady rate
Given:
KE = 500 J
v = 25 m/s
The formula for Kinetic Energy is given:
KE = ½ mv²
where: KE - Kinetic Energy
m - mass
v - velocity
Substituting the value of KE and v in the formula,
500 J = (½)(m)(25 m/s)²
m = (500 J)(2)/(25 m/s)²
m = 1.6 kg
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A tank with a diameter of 10 m is open at the top and contains water that is 12 m deep. There is a hole 1.0 m from the bottom of the tank with a diameter of 0.02 m. The speed of the water as it
exits the hole is most nearly
A
0.6m/s
B
4.5m/s
C
14.8m/s
D
15.5m/s
We have that The speed of the water as it exits the hole is most nearly
V=14.8m/s
From the question we are told that
A tank with a diameter of 10 m Contains water that is 12 m deep 1.0 m from the bottom of the tank A diameter of 0.02 mGenerally the equation for the Torricelli's Law is mathematically given as
\(V=\sqrt{2gh}\)
Where
\(H=12-1H=11\\\\Therefore\\\\\V=\sqrt{2*9.8*11}\\\\V=14.8m/s\)
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A rollercoaster was moving from point a to b, and then to c, with the instantaneous velocity 5m/s, 15m/s, and 10m/s,
respectively. the instaneous velocity at a point between b and c could be
a)
less than 5m/s.
b)
less than 10m/s.
greater than 10m/s.
d)
greater than 15m/s.
The Instantaneous velocity between point b and c could be less than 10 m/s.
What is instantaneous velocity?
Instantaneous velocity is the velocity of an object under motion at a specific point of time.
given the following parameters;
Instantaneous velocity at point b = 15 m/sInstantaneous velocity at point c = 10 m/sInstantaneous velocity between point b and c = 15 m/s - 10 m/s = 5 m/s
Thus, the Instantaneous velocity between point b and c could be less than 10 m/s.
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Which quantity is a vector quantity?
А.
acceleration
B.
mass
C.speed
D.
volume
Answer:
acceleration .......
A 5,000 kg truck moving at 8 m/s has the same momentum as a 2,500 kg car. What is the velocity of
the car?
Answer:
16m/s
Explanation:
Mv=mv
5000x8=2500x v
V=5000x8/2500
V=40000/2500
= 16m/s
. How does the intensity of sunlight received affect Earth’s temperatures?
Which statements apply to transverse waves? Check all that apply.
The question is incomplete as it does not have the options which are:
The waves have a trough.
Particles move only small distances.
particles travel the length of the wave, moving in an up-and-down motion.
The waves have a crest.
The energy is transferred perpendicular to the direction of the wave motion.
Answer:
The waves have a trough. Particles move only small distances. The waves have a crest. The energy is transferred perpendicular to the direction of the wave motion.Explanation:
Transverse waves are the waves which can be characterised easily by their oscillation in a perpendicular direction to the path of the wave propagation.
The particle follows the wave nature and moves only to a small distance like ripples in the water and these waves possess the trough, the lower part and the crest the upper part.
These waves can be observed in ripples of the water, in a string of the guitar while playing and the electromagnetic waves.
Thus, the selected options are correct.
A 0.150-kg rubber stopper is attached to the end of a 1.00-m string and is swung in a circle. If the rubber stopper is swung 2.3 m above the ground and released, how far will the stopper travel horizontally before hitting the ground?
The stopper travels approximately 4.5 meters horizontally before hitting the ground.
We can use conservation of energy to solve this problem. At the highest point of the stopper's motion, all of its energy is in the form of potential energy, and at the lowest point (when it hits the ground), all of its energy is in the form of kinetic energy.
The potential energy of the stopper at the highest point is:
Ep = mgh
where m is the mass of the stopper, g is the acceleration due to gravity, and h is the height above the ground. Plugging in the values given in the problem, we get:
Ep = (0.150 kg) * (9.81 m/s²) * (2.3 m) ≈ 3.2 J
At the lowest point, all of the potential energy has been converted to kinetic energy:
Ek = (1/2) * mv²
where v is the speed of the stopper just before it hits the ground. Since the stopper is released from rest, we can use conservation of energy to equate the potential energy at the highest point to the kinetic energy just before hitting the ground:
Ep = Ek
mgh = (1/2) * mv²
Solving for v, we get:
v = √(2gh)
where h is the height from which the stopper was released. Plugging in the values given in the problem, we get:
v = √(2 * 9.81 m/s² * 2.3 m) ≈ 6.6 m/s
Now we can use the time it takes for the stopper to fall to the ground to calculate the horizontal distance it travels. The time is given by:
t = √(2h/g)
Plugging in the values given in the problem, we get:
t = √(2 * 2.3 m / 9.81 m/s²) ≈ 0.68 s
During this time, the stopper travels a horizontal distance given by:
d = vt
Plugging in the values we just calculated, we get:
d = (6.6 m/s) * (0.68 s) ≈ 4.5 m
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if you remove ice cubes from the freezer with wet hands, the cubes often freeze to your fingers. how can the ice freeze the water on your hands? shouldn’t they melt instead?
Ice cubes freeze water on wet hands due to heat transfer, causing the water to freeze and stick to the cold surface.
At the point when you contact an ice block with wet hands, the water on your hands shapes a meager layer on the outer layer of the ice 3D square. This layer of water freezes immediately because of the super chilly temperature of the ice, making a meager layer of ice on your skin.
The ice shape can freeze the water on your hands since it is a lot colder than the edge of freezing over of water, which is 0°C (32°F). Despite the fact that the ice block is colder than the edge of freezing over of water, it doesn't make the water on your skin freeze strong in light of the fact that your body is continually producing heat, which assists with keeping the water in a fluid state.
Notwithstanding, assuming the temperature of your skin drops adequately low, the water will freeze strong. For this reason it is vital to eliminate ice 3D shapes from the cooler with dry hands to keep the water from sticking to your skin.
It is a typical misguided judgment that the ice ought to soften when it comes into contact with the warm skin, however as a general rule, the temperature contrast between the ice and the skin is sufficiently huge to make the water on the skin freeze, instead of dissolve the ice.
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Select the correct answer. A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car? A. The net force acting on the car from all directions is zero. B. The net force acting on the car is greater than the car's weight. C. The net force acting on the car is in the direction of the car's motion. D. The net force acting on the car is in the opposite direction of the car's motion.
Answer:
i think try theanswer
Explanation:
proper
Answer:
A
Explanation:
For an object to move with constant speed the forward force is opposed by the effects of forces. There is no resultant force acting or constant speed is a result of no resultant force.
Newton's second law states that an object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Newton's Second Law states: F = ma. F is the net force acting on an object.
Also if velocity or speed is constant the acceleration will be 0 the F=m×0
F=0.
A 1400 kg car is traveling at a rate of speed of 32 m/s for 2 hours. For the remaining 3 hours of the trip the car travels at an average rate of speed of 38 m/s. What was the average change in momentum?
The average change in momentum for the car during the trip is 8400 kg·m/s.
What is Momentum?
Momentum is a vector quantity, meaning it has both magnitude and direction. The direction of momentum is the same as the direction of velocity, and its magnitude is proportional to both the mass and the velocity of the object.
Then, we calculate the final momentum of the car during the remaining 3 hours:
Final momentum during the remaining 3 hours = mass × final velocity during the remaining 3 hours = m × v2
Now, we can calculate the average change in momentum:
Average change in momentum = Final momentum - Initial momentum
= (Final momentum during the first 2 hours + Final momentum during the remaining 3 hours) - Initial momentum
= [(m × v2) + (m × v2)] - (m × v1)
= 2m × v2 - m × v1
Plugging in the given values:
Mass of the car (m) = 1400 kg
Initial velocity (v1) = 32 m/s
Final velocity during the first 2 hours (v2) = 38 m/s
Average change in momentum = 2m × v2 - m × v1
= 2 × 1400 kg × 38 m/s - 1400 kg × 32 m/s
= 53200 kg·m/s - 44800 kg·m/s
= 8400 kg·m/s
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A car traveling at 40 m/s runs out of gas while traveling up a 6.0 degree slope. How far will it coast before starting to roll back down?
The car will coast for approximately 2087 meters before starting to roll back down the slope.
What is the distance the car will coast up a 6.0 degree slope at 40 m/s before starting to roll back down?To solve this problem, we need to find the distance the car will travel up the slope before coming to rest. This distance is equal to the distance the car will coast down the slope before starting to roll back.
We can use the conservation of energy principle to find the initial potential energy of the car, which will be converted to kinetic energy as the car coasts up the slope. At the point where the car comes to rest, all of the initial potential energy will have been converted to gravitational potential energy.
The initial potential energy of the car can be found using the formula:
PE = mgh
where m is the mass of the car, g is the acceleration due to gravity, and h is the height the car has traveled up the slope.
Since the car comes to rest at the top of the slope, all of the initial potential energy is converted to gravitational potential energy at this point. The gravitational potential energy can be found using the formula:
PE = mgh
where m is the mass of the car, g is the acceleration due to gravity, and h is the height the car has traveled up the slope.
Since the gravitational potential energy is equal to the initial potential energy, we can set the two formulas equal to each other:
\(mgh = 1/2 mv^2\)
where v is the final velocity of the car at the point where it comes to rest.
We can solve for h, the height the car has traveled up the slope:
\(h = 1/2 v^2/g\)
We can then use the formula for the distance traveled up the slope to find the distance the car will coast down the slope before starting to roll back:
d = h/sin(theta)
where theta is the angle of the slope.
Plugging in the values given in the problem, we get:
\(h = 1/2 (40 sin(6))^2 / 9.81 = 215.5 m\)
\(d = 215.5 / sin(6) = 2087 m\)
Therefore, the car will coast for approximately 2087 meters before starting to roll back down the slope.
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The distance it will coast before starting to roll back down is approximately 776.55 meters up the slope.
To solve this problem, we will use the concepts of kinetic energy, potential energy, and the conservation of mechanical energy. Initially, the car has kinetic energy (KE) due to its velocity (40 m/s) and no potential energy (PE) since we assume it starts at the bottom of the slope. When the car comes to a stop, all its kinetic energy is converted to potential energy.
First, we need to find the kinetic energy:
KE = (1/2) * m * v²
where m is the mass of the car and v is its velocity (40 m/s).
Next, we'll find the potential energy when the car comes to a stop:
PE = m * g * h
where g is the acceleration due to gravity (9.81 m/s²) and h is the height the car reaches on the slope.
Since the mechanical energy is conserved, KE = PE. We can set up the equation:
(1/2) * m * v² = m * g * h
The mass (m) can be canceled from both sides, leaving:
(1/2) * v² = g * h
Now we can find the height (h):
h = (1/2) * v² / g = (1/2) * (40 m/s)² / 9.81 m/s² ≈ 81.46 m
To find the distance the car traveled along the slope (d), we'll use the sine of the angle (6.0 degrees):
sin(6.0) = h / d
Solving for d:
d = h / sin(6.0) ≈ 81.46 m / sin(6.0) ≈ 776.55 m
The car will coast approximately 776.55 meters up the slope before starting to roll back down.
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A 6.46 kg object moving with a velocity of 5.23 m/s is struck from behind by a moving 11.77 kg object. They stick together, moving off with a mutual velocity of 17.93 m/s. What was the original velocity of the 11.77 kg object before the collision?
Answer:
is
Explanation:
e
The density of iron is 14.0 g/cm³. A worker in a science lab calculates the density of iron as 4.5
g/cm³. What is the percent error of the worker's measurement?
Answer:
Percent Error = 67.86%
Explanation:
The percent error can be calculated using the following equation:
| measured value - true value |
Percent Error = ------------------------------------------------- x 100%
true value
In this equation,
---> The "measured value" is the value found after performing an experiment.
---> The "true value" is the value you expect to find after performing an experiment.
In this case,
---> measured value = 4.5 g/cm³
---> true value = 14.0 g/cm³
| 4.5 g/cm³ - 14.0 g/cm³ |
Percent Error = ---------------------------------------- x 100% <----- Insert values
14.0 g/cm³
| -9.5 g/cm³ |
Percent Error = ------------------------ x 100% <----- Subtract
14.0 g/cm³
9.5 g/cm³
Percent Error = ------------------------ x 100% <----- Take absolute value
14.0 g/cm³
Percent Error = 0.6786 x 100% <----- Divide
Percent Error = 67.86% <----- Multiply
Why does a small piece of steel rod sinks while a large steel oil tanker floats?
Plss help thanks! pls include EXPLANATION and EXAMPLES that I can proof to people that has no knowledge
Answer:
Too what i know its because of the air
Explanation:
The steel rod is more dense and doesnt have air whil'st the oil tanker is less dense with lots of air
Which type of radioactive decay produces the highest-energy radiation?
A. Beta decay
B. Alpha decay
C. Electromagnetic decay
D. Gamma decay
SUBMIT
Help
Answer:
gamma decay
Explanation:
Answer: gamma decay
Explanation: I took the test
A copper sphere with density 8900 kg/m3, radius 5. 00 cm, and emissivity e = 1. 00 sits on an insulated stand. The initial temperature of the sphere is 300 K. The surroundings are very cold, so the rate of absorption of heat by the sphere can be neglected.
a. How long does it take the sphere to cool by 1. 00 K due to its radiation of heat energy? Neglect the change in heat current as the temperature decreases.
b. To assess the accuracy of the approximation used in part A, what is the fractional change in the heat current H when the temperature changes from 300 K to 299 K?
a.The time it will take the sphere to cool by 1. 00 K due to its radiation of heat energy is 3225s.
b. The fractional change in the heat current H when the temperature changes from 300 K to 299 K is 3.18 %.
(a) The rate of cooling of a copper sphere is given by Newton's law of cooling, i.e.,
H = kA(Ts - T0),
where k is the heat-transfer coefficient, A is the surface area of the sphere, Ts is the temperature of the surroundings, and T0 is the temperature of the sphere.
Since the surroundings are very cold, Ts can be taken to be zero.The heat transfer coefficient k depends on the emissivity e of the sphere and is given by:
k = σeA,
where σ is the Stefan-Boltzmann constant.
The surface area A of the sphere is:
A = 4πr²,
where r is the radius of the sphere.
The heat transfer coefficient k is therefore k = 4πr²σe.
Substituting the values of the parameters for the copper sphere in the above equations, we get
k = 4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = 0.0562 W/m²K⁴
H = kA(Ts - T0) = 0.0562(4π(0.05 m)²)(300 K - 0) = 1.41 W.
The rate of cooling of the sphere is therefore 1.41 W.
The heat capacity C of the sphere is given by
C = mCp,
where m is the mass of the sphere and Cp is the specific heat capacity of copper.
The mass of the sphere is m = (4/3)πr³ρ= (4/3)π(0.05 m)³(8900 kg/m³) = 0.0118 kg
The specific heat capacity of copper is Cp = 385 J/kgK.
The heat capacity of the sphere is therefore
C = 0.0118 kg × 385 J/kgK = 4.54 J/K.
The time Δt taken for the sphere to cool by ΔT = 1.00 K is given by
Δt = ΔQ/H = CΔT/H = (4.54 J/K)/(1.41 W) ≈ 3225s.
(b) The fractional change in the heat current H when the temperature changes from 300 K to 299 K is given by
ΔH/H = (dH/dT)ΔT/H,
where ΔT is the change in temperature and dH/dT is the rate of change of the heat current H with temperature.
To find dH/dT, we differentiate the equation
H = kA(Ts - T0) with respect to T and get dH/dT = -kA = -4πr²σe.
Substituting the values of the parameters for the copper sphere, we get
dH/dT = -4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = -0.0449 W/K/m².
The fractional change in the heat current is therefore:
ΔH/H = (dH/dT)ΔT/H = (-0.0449 W/K/m²)(-1 K)/(1.41 W) = 0.0318 or 3.18%.
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Which of the following is an example of thermal energy?
O Lightning
O Food
O Nuclear power
O Melting ice cream
Answer:
melting ice cream
Explanation:
in order for the ice cream to melt, thermal energy (heat) must be applied to it.