someone help me asap i needa turn this in first thing tmr morning

When a random integer is selected from the range from 2 to 10,000,000,000, the approximate probability that the selected number is prime is 1/23.

Question: Consider a random integer selected from the range from 2 to 10,000,000,000. Approximately, what are the chances that the selected number is prime?
To determine the chances that a randomly selected number from the range of 2 to 10,000,000,000 is prime, we can use the concept of natural logarithm (ln) and the Prime Number Theorem.
The Prime Number Theorem states that the probability that a randomly chosen number near x is prime is approximately 1/ln(x). In this case, we are interested in the range from 2 to 10,000,000,000.
First, let's calculate ln(10,000,000,000). We can use the hint given in the question that ln(10) is approximately 2.30. Since the logarithm is a natural logarithm (base e), we have:
ln(10,000,000,000) = ln(10^10) = 10 * ln(10) = 10 * 2.30 = 23.
Now that we have ln(10,000,000,000) = 23, we can use the Prime Number Theorem to approximate the probability that a randomly chosen number from the given range is prime. The probability is approximately 1/ln(10,000,000,000) or 1/23.
Therefore, the chances that the selected number is prime are approximately 1/23.
In summary, when a random integer is selected from the range from 2 to 10,000,000,000, the approximate probability that the selected number is prime is 1/23.

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The corresponding change in y can be calculated as follows:

Change in y = a * (change in x)

Change in y = a * (-8)

Change in y = -8a

So, the corresponding change in y when x decreases by 8 units is -8a.

To determine the corresponding change in y when x decreases by 8 units in the linear equation ax + by = c, we need to examine the relationship between x and y in the equation.

In a linear equation of the form ax + by = c, the coefficients a and b represent the slopes of the x and y variables, respectively. The slope of the x variable (a) indicates how the y variable changes for a unit change in x. Similarly, the slope of the y variable (b) indicates how the x variable changes for a unit change in y.

To find the corresponding change in y when x decreases by 8 units, we need to consider the slope of the x variable (a) in the equation.

If x decreases by 8 units, we can represent this change as x - 8. To determine the corresponding change in y, we need to multiply the change in x by the slope of the x variable (a).

Therefore, the corresponding change in y can be calculated as follows:

Change in y = a * (change in x)

Change in y = a * (-8)

Change in y = -8a

So, the corresponding change in y when x decreases by 8 units is -8a.

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Answer:

A. 1,140 cm^2

Step-by-step explanation:

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Let's solve your inequality step-by-step.

\(2<2x+4<10\)

\(2 + -4 < 2x + 4 + -4 < 10 + -4\) (Add -4 to all parts)

\(-2 < 2x < 6\)

\(\frac{-2}{2} < \frac{2x}{2} < \frac{6}{2}\) (Divide all parts by 2)

\(-1 < x < 3\)

So the answer is : \(-1 < x < 3\)

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

18. An infant weighs 11 pounds which is equivalent to 4.98 kg. Using the 100/50/20 Rule, the required amount of fluid per day for an infant between 11-20 kg is 50 ml/kg/day. So, the required amount of fluid per day in ml is 4.98 kg x 50 ml/kg/day = 249 ml/day.

19. A child weighs 31lbs and 8 ozs which is equivalent to 14.21 kg. Using the 100/50/24 Rule, the required amount of fluid per day for a child over 20 kg is 20 ml/kg/day. So, the required amount of fluid per day in ml is 14.21 kg x 20 ml/kg/day = 284.2 ml/day.

If no oral fluids are consumed, the hourly IV flow rate to maintain proper hydration would be: 284.2 ml/day / 24 hours/day = 11.8 ml/hour.

The question is about fluid requirements for infants and children, and it is using the 100/50/20 Rule for Daily Fluid Requirements (DFR) to calculate the required amount of fluid per day for different weight ranges. The 100/50/20 Rule is a guideline used to determine the appropriate amount of fluid that infants and children should receive on a daily basis based on their weight. The rule states that for infants and children up to 10 kg, the recommended fluid intake is 100 ml/kg/day, for those between 11-20 kg it is 50 ml/kg/day, and for those over 20 kg it is 20 ml/kg/day.

The question also asking about the hourly IV flow rate to maintain proper hydration if no oral fluids are consumed.

This subject is part of pediatrics, more specifically in the field of fluid and electrolyte balance and management.

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The solution of the inequalities are;

2. x≥2

3. n≤ 0

4. n>3

5. n≤ 0

6. p≤ 1

7. k<2

8. n>6

9. a> 0

10. b> -4

It is important to note that inequalities are the mathematical expressions in which both sides are not equal

From the information given, we have;

2. 4x + 1 - 1≥ 8

collect like terms

4x ≥ 8

x≥2

3. -1 ≤ 2n +4 - 5

collect like terms

-1 -1 ≤2n

n≤ 0

4. -6 > 5n + 5 +4

collect like terms

n>3

5. 0 ≤ 2n + 3n

collect like term

n≤ 0

6. 2p - 4p ≤-2

collect the like terms

p≤ 1

7. 7 < -(-k-3) + 2

expand the bracket

7<k+ 5

k<2

8. 3-2(n -4) > -1

collect like terms

-2n>-12

n>6

9. -5(1 - 4a) >-5

expand the bracket

20a>0

a> 0

10. -2(b + 1) + 4 <10

expand the bracket

-2b < 8

b> -4

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The first four nonzero terms in the power series expansion for the general solution to the provided differential equation are:

y(x) = a_3 * x^3 + a_4 * x^4 + a_5 * x^5 + ...

To determine the power series expansion for the provided differential equation y''' + (x - 1)y' + y = 0 around x = 0, we assume a power series solution of the form:

y(x) = ∑[n=0 to ∞] (a_n * x^n)

where a_n represents the coefficients of the power series.

Differentiating y(x) with respect to x, we obtain:

y'(x) = ∑[n=0 to ∞] (n * a_n * x^(n-1)) = ∑[n=1 to ∞] (n * a_n * x^(n-1))

Differentiating y'(x) with respect to x again, we get:

y''(x) = ∑[n=1 to ∞] (n * (n-1) * a_n * x^(n-2))

Differentiating y''(x) with respect to x once more, we have:

y'''(x) = ∑[n=1 to ∞] (n * (n-1) * (n-2) * a_n * x^(n-3))

Substituting these derivatives into the provided differential equation, we obtain:

∑[n=1 to ∞] (n * (n-1) * (n-2) * a_n * x^(n-3)) + (x - 1) * ∑[n=1 to ∞] (n * a_n * x^(n-1)) + ∑[n=0 to ∞] (a_n * x^n) = 0

Now, let's separate the terms with the same power of x:

∑[n=1 to ∞] (n * (n-1) * (n-2) * a_n * x^(n-3)) + ∑[n=1 to ∞] (n * a_n * x^(n-1)) + ∑[n=0 to ∞] (a_n * x^n) - ∑[n=1 to ∞] (n * a_n * x^(n-1)) + ∑[n=1 to ∞] (a_n * x^n) = 0

Grouping the terms with the same power of x, we have:

∑[n=1 to ∞] [(n * (n-1) * (n-2) * a_n + a_n - (n * a_n)) * x^(n-3)] + a_0 + a_1 * x + ∑[n=2 to ∞] [(a_n - n * a_n) * x^(n-1)] = 0

Simplifying further, we obtain:

∑[n=1 to ∞] [(n * (n-1) * (n-2) * a_n + a_n - (n * a_n)) * x^(n-3)] + a_0 + a_1 * x + ∑[n=2 to ∞] [(1 - n) * a_n * x^(n-1)] = 0

Now, let's identify the coefficients of the terms for each power of x:

For x^(-3), we have:

n * (n-1) * (n-2) * a_n + a_n - (n * a_n) = 0

a_n * [n * (n-1) * (n-2) + 1 - n] = 0

a_n * [n^3 - 3n^2 + n + 1 - n] = 0

a_n * (n^3 - 3n^2 + 1) = 0

For x^(-2), we have:

a_0 = 0

For x^(-1), we have:

a_1 = 0

For x^0, we have:

a_2 - 2a_2 = 0

-a_2 = 0

a_2 = 0

For x^n (n ≥ 1), we have:

(1 - n) * a_n = 0

From these equations, we can see that a_0 = a_1 = a_2 = 0, and for n ≥ 3, a_n can be any value.

∴ y(x) = a_3 * x^3 + a_4 * x^4 + a_5 * x^5 + ...

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On her way to work each morning, Alexia purchases a small cup of coffee for $6.50 from the coffee shop. So the

Independent Quantity: time,    Units: days

Dependent Quantity: cost,    Units: dollar($)

The dependent and independent quantity or variable are the two main factors in an experiment.

In a scientific experiment, the variable that is altered or controlled to examine the effects on the dependent variable is referred to as an independent quantity.

In a scientific experiment, the variable under test and the measurement is the dependent quantity.

On the independent quantity, the dependent quantity is said to be "dependent." The impact on the dependent quantity is seen as the experimenter modifies the independent quantity, and this effect is noted.

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Answer:

first find the width

=11cm

find area

7×11=77

and=77

That's a question about the Pythagorean Theorem.

We use the Pythagorean Theorem to find the value of one side in a right triangle.

This theorem says that:

\(\boxed{a^2 = b^2 + c^2}\)

Okay, now, let's go to solve this problem! In our figure, we have two cathetus. Their values are 10 and 7 and we have to find the value of x (the hypotenuse). Let's change this information in that formula.

\(a^2 = b^2 + c^2\\x^2 = 10^2 + 7^2\\x^2 = 100 + 49\\x^2 = 149\\x = \sqrt{149}\)

Therefore, the value of x is \(\sqrt{149}\).

I hope I've helped. :D

Enjoy your studies! \o/

Answer:

8

Step-by-step explanation:

Pythahorean theorem

S2+S2=8^2(2)

2s2=64 (2)

S2=64

S=64^1/2

S=8

Answer:

y = 5

Step-by-step explanation:

The equation for a line is y = mx + b, with m representing slope and b representing y-intercept.

This yields an equation y = 0x + 5, or just y = 5 when simplifying.

Answer:

y = -2/3x -5

Step-by-step explanation:

First, let's fill in our equation of y = mx + b

(6, -9) is the coordinate we will be subsituting

If the equation that s to the one we are solving we must turn its slope into it's negative reciprocal, which would go from 3/2 to -2/3

Now let's substitute and solve

y = mx + b

(-9) = -2/3(6) + b

-9 = -4 +b

+4   +4

-5 = b

Now we create the equation

y = -2/3x -5

The inequality for the statement:-2/7 is at most the product of a number and -4/5. is --4x/5 ≤ -2/7

Information from the question

the statement: -2/7 is at most the product of a number and -4/5

Inequality is a means of representing the relationship existing between the positive and negative parts of equations, using other terms aside exactly using equal to

at most means the highest value hence the answer is either the number or less.

let the number be x

x * -4/5 ≤ -2/7

--4x/5 ≤ -2/7

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Answer:

10.48 miles ran in one hour .

Therefore, the measure of angle m is 26 degrees and the measure of angle n is 33 degrees.

Let's set up the equations based on the given information:

m = n - 7 (The measure of angle m is seven degrees less than the measure of angle n)

m + n = 59 (The sum of the two angles is 59 degrees)

To solve for the values of m and n, we can substitute the first equation into the second equation:

(n - 7) + n = 59

Combining like terms:

2n - 7 = 59

Add 7 to both sides:

2n = 66

Divide by 2:

n = 33

Substitute the value of n back into the first equation to find the value of m:

m = 33 - 7

m = 26

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Answer:

-2

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

I dont have an explanation, sorry

Answer:

You are correct, it is C.

Step-by-step explanation:

good job

Answer:

C )

Step-by-step explanation:

if re arranged the eq. becomes

3x2 - 5x - 6 = 0

a = 3, b = -5, c = -6

There are 24 students in the class in which 75% of the students are boys (18 boys)

An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the total amount of students in the class.

75% of the students are boys.There are 18 boys in the class, hence:

0.75x = 18

x = 24

There are 24 students in the class in which 75% of the students are boys (18 boys)

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The box and whisker plot can be created by :

Minimum value - 6

Maximum Value - 15

Median - 10

Quartiles - Q1 - 7.5, Q2 - 10, Q3 - 13.5

To create a box and whisker plot for the given data set {6,7,7,8,9,10,10,10,10,13,13,14,14,15,15}, we need to first find the minimum value, maximum value, median, and quartiles.

Minimum value: 6

Maximum value: 15

Median: To find the median, we need to first arrange the data set in ascending order:

6,7,7,8,9,10,10,10,10,13,13,14,14,15,15

The median is the middle value in the data set, which is 10.

Quartiles: To find the quartiles, we need to divide the data set into four equal parts.

First quartile (Q1): The first quartile is the median of the lower half of the data set. In our case, the lower half of the data set is:

6,7,7,8,9,10

The median of this set is (7+8)/2 = 7.5.

Second quartile (Q2): The second quartile is the median of the entire data set, which we already found to be 10.

Third quartile (Q3): The third quartile is the median of the upper half of the data set. In our case, the upper half of the data set is:

10,10,10,10,13,13,14,14,15,15

The median of this set is (13+14)/2 = 13.5.

Now, we can use the above information to create the box and whisker plot.

The horizontal line inside the box represents the median (10). The bottom of the box represents the first quartile (7.5), and the top of the box represents the third quartile (13.5). The whiskers extend from the box to the minimum value (6) and maximum value (15).

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Answer:

Part A:

The Standard Form equation of a line has the following formula:

Ax+By=C, where A, B, and C are integers, and A is non-negative.

We will assume that when renting a boat Sam paid fixed cost and rental charge per day.

y = the total rent

x = the number of days

Sam rented a boat at $225 for 2 days would mean:

y = 225 when x = 2 or if we plug into Ax+By=C:

2A + 225B = C since A is non-negative we divide both sides by A

2 + (B/A)225 = C/A

He rents the same boat for 5 days, he has to pay a total rent of $480 means:

y = 480 when x = 5 days

5A + 480B = C since A is non-negative we divide both sides by A

5 + (B/A)480 = C/A

Now we have:

2 + (B/A)225 = C/A

5 + (B/A)480 = C/A

Lets denote s = B/A  and t = C/A. Now we can write the following system of equations:

2 + 225s = t

5 + 480s = t

........

click here to see the system of equations solved for s and t

........

s = -1/85

t = -11/17 = -55/85

Now we can go back to:

B/A = -1/85 and C/A = -55/85

A = 85, B = -1, C = -55

The standard equation is:

85x - y = -55

Part B:

Using the equation 85x - y = -55 we solve for y

.......

click here to see the equation solved for y

........

y = 85x + 55

or in function notion y = f(x)

f(x) = 85x + 55

Part C:

The graph of y = 85x + 55 is:

Step-by-step explanation:

Answer:

y = 225/2x + 2

Step-by-step explanation:

30 lemon candies he give his friend.

It is given that a boy had 320 candies. There were 2 flavors. 7/16 were orange flavor and the rest were lemon. He gave his friend 30 orange candies and some lemon ones.

320 (7/16)  =   140  were orange

320 - 140  =  180  were lemon

Let x be the number of lemon ones he gave  away

So,

[ 140 - 30 ]  / [ 180 - x ] =  11/15

110  =  (11/15) ( 180 - x )

(15/11) (110)  = 180 - x

150  = 180  - x

x = 180  - 150  =   30

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1. Solve the inequalities for y:

First ineqaulity: divide both sides of the inequality by -2 (as you divide by a negative number the inequality sing change to the opposite):

Second inequality: divide both sides of the inequality by -5:

2. Define the kind of boundary line for each inequality:

When the inequality is < or > the boundary line is a dashed line.

When the inequality is ≥ or ≤ the boundary line is a solid line.

First inequality: as the inequality sing is > the boundary line is a dashed line.

Second inequality: as the inequality sing is ≤ the boundary line is a solid line.

3. Find two points (x,y) for each boundary line:

First inequality:

Line:

Find x when y is 0:

Point (-4,0)

Find y when x is 0:

Point (0,8)

______________

Second inequality:

Line:

Find x when y is 0:

Point (-10,0)

Find y when x is 0:

Answer:

3y / (y+3)

Step-by-step explanation:

3y^2 - 6y / y^2 + y - 6

= 3y(y-2) / (y+3)(y-2)

=3y / (y+3)

Answer:

3y / (y+3)

Step-by-step explanation:

Answer:

The amount he gains in 2 years is Rs. 250

Step-by-step explanation:

The parameters of the amount borrowed from the bank are;

The amount borrowed, P = Rs. 16,000

The interest rate of the amount borrowed, R = 12.5%

The number of years, T = 2 years

The simple interest, I = (P × R × T)/100 =  (Rs. 16,000 × 12.5 × 2)/100 = Rs. 4,000

The total amount the person is to pay bank to the bank = P + I = Rs. 16,000 + Rs. 4,000 = Rs. 20,000

The parameters of the amount lent to the shopkeeper are;

The amount lent, P = Rs. 16,000

The compound interest rate of the amount lent, R = 12.5%

The number of years, T = 2 years

The amount he receives from the shopkeeper after 2 years, A = P·(1 + R/n)^(n × T) = Rs. 16,000 × (1 + 0.125/1)^(1 × 2) = Rs. 20,250

The amount he gains in 2 years = The amount he receives from the shop keeper - The amount he gives to the bank = Rs. 20,250 - Rs. 20,000 = Rs. 250

The amount he gains in 2 years = Rs. 250.

Answer:

Step-by-step explanation:

P= a+b+c

P= 1512+223+314

=2049

Answer:

c = 3477 feet (As rounded to the nearest whole number)

Step-by-step explanation:

We will use the Sin ratio for this problem since the opposite side of the Angle 15 is given and we have to find the triangle's hypotenuse;

Sin(15) = \(\frac{900}{c}\)

=> Now isolate the variable c all to itself;

Sin(15) * c = 900

c = \(\frac{900}{Sin(15)}\)

c = 3477.33 or 3477 feet

Hope this helps!