Somebody plz!!!! tell me which one I should insert correctly for each questions??
(WILL MARK AS BRAINLIEST)
thankssss :3

Answer: A

Step-by-step explanation: I would say A because the angle is greater than 90 degrees

Answer:

We have supplementary angles.

76 + 3x + 2 = 180

3x + 78 = 180

3x = 102

x = 34

Answer:

A negative correlation means one variable decreases as the other increases.

Answer:

-3 < w < 8 or (-3, 8)

Step-by-step explanation:

Am i get it right?

Answer:

it is 8 -3 to the power of 5

Answer:

BF AND FG are the perpendicular because it is 90degree

Answer:

3rd option

Step-by-step explanation:

perpendicular means at 90 degree angles, all the other options are parallels

Hope this helped! pls give branliest so i can level up

Answer:

Step-by-step explanation:

For correct scientific notation, we need to have 1 number to the left of the decimal, and everything else to the right. Since our number is already less than 1, the exponent representing the number of places we move the decimal will be negative. We have to move the decimal 5 places to the right to get the 5 to the left of the decimal and everything else to the right, making this:

\(5.974*10^{-5\)

Finding the smallest possible integer value of k requires analyzing the given equation and determining the conditions under which one root is less than 1 and the other is greater than 1.

The equation is:

2^(2x) - 2(k-1)^(2x) + k = 0

Let's break down the conditions step by step.

1. Square root less than 1:

To make the square root less than 1, we need to substitute x = 1 into the equation and get a positive value. So if x = 1, then

2^(2*1) - 2(k-1)^(2*1) + k > 0

4 - 2(k-1)^2 + k > 0

Extensions and simplifications:

4 - 2(k^2 - 2k + 1) + k > 0

4 - 2k^2 + 4k - 2 + k > 0

-2k^2 + 5k + 2 > 0

2k^2 - 5k - 2 < 0 xss=removed xss=removed xss=removed xss=removed > 0.

Now we can combine both conditions to find the smallest integer value of k.

2k^2 - 5k - 2 < 0 > 0 (Condition 2)

By solving these conditions simultaneously, we can find the range of values of k that satisfy both conditions and determine the smallest integer value of k. However, this process requires calculations and algebraic manipulations beyond the scope of simple text-based answers.

It is recommended to use an algebraic calculator or software to solve the equation and find the smallest integer value of k that satisfies the given conditions. 

The colorimeter detects the voltage created when sunlight penetrates the specimen, so the voltage created is exactly proportional to the absorbance of the sample.

When charged electrons (current) are forced through a conducting loop by the weight of an electrical raceway power source, they can perform tasks like lighting a lamp. In a nutshell, voltage equals pressure and is expressed in volts (V).

Here,

The voltage generated by the uv spectrophotometer is inversely proportionate to the amount of light present and linearly proportional to the sample's absorbance.

This indicates that as the sample's absorbance rises, so does the energy the colorimeter generates.

Similar to this, the voltage generated by the colorimeter rises as light strength falls.

The Beer-Lambert Law, which says that a sample's absorbance is directly proportional to its concentration of the absorbing substance and its path length and inversely proportional to incident light intensity, describes this connection.

The colorimeter detects the voltage created when sunlight penetrates the specimen, so the voltage created is exactly proportional to the absorbance of the sample.

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The required  numbers is x=12 and y=24−x=24−12=12 i.e.(12,12).

What is differentiation ?

In math, isolation is one of the two important generalities piecemeal from integration. Isolation is a system of chancing the outgrowth of a function. Isolation is a process, in Maths, where we find the immediate rate of change in function grounded on one of its variables. The most common illustration is the rate change of relegation with respect to time, called haste. The contrary of chancing a outgrowth isanti-differentiation.

still, also the rate of change of x with respect to y is given by dy/ dx, If x is a variable and y is another variable. This is the general expression of outgrowth of a function and is represented as f'( x) = dy/ dx, where y = f( x) is any function.

Let the two number is x and y

According to given question.

Sum of two number =24

x+y=24

Then, y=24−x.......(1)

Again, product

 P=maximum=x × y

P=x(24−x 2)

P=24x−24x^2  .......(2)

We know that,

For maximum value

dP/dx =0

Now differentiating equation (2) with respect to x and we get,

dP/dx  =24−2x

⇒ 24−2x=0

⇒ 2x=24

⇒x=12

Again, differentiating equation (2) with respect to x and we get,

\(\frac{d^2p}{dx^2} = -2 < 0\)

Then,P is minimum at point x=12

Hence, the required  numbers is x=12 and y=24−x=24−12=12 i.e.(12,12)

This is the solution.

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Danielle viewed 7 movies on demand, thus you must divide her 35 dollars among them. So the monthly charge for Danielle's cable bill is $5.

Danielle pays a monthly charge of $69 for her cable bill.

She also pays a fee every time she watches a movie on demand.

Last month Danielle watched 7 movies on demand, and her total monthly bill was $104.

We have to find the monthly charge for Danielle's cable bill to choose.

Remove the monthly fee of 69 dollars for cable service from the total of 104 dollars, then check the statement to see that there is still a mystifying 35 dollars on it.

Danielle viewed 7 movies on demand, thus you must divide her 35 dollars among them, giving you the result of $5 per on-demand movie.

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Answer:

a. sine StartFraction pi Over 3 EndFraction = StartFraction opposite Over hypotenuse EndFractionEquals StartFraction opposite Over 1 EndFraction  Equals opposite

The length opposite the angle is the vertical distance from the x-axis on the graph.

Step-by-step explanation:

sin (π/3) = opposite/hypotenuse = opposite/1; The length opposite the angle is the vertical distance from the x-axis on the graph.

Unit circle is a circle centered at the origin, (0,0) with radius(r) i.,e r= 1.

The angle π/3 forms an arc of length S and the x-axis and y-axis divide the coordinate plane and the unit circle as it is centered at (0.0).

Also, the terminal side intersect the circle at (x, y). Thus;

sin (π/3) = opposite/hypotenuse = opposite/1

Thus;

sin (π/3) = opposite

Also, the length opposite the angle is the vertical distance from the x-axis on the graph.

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The equation lim(x→1) [x^2/(x-2)] / (x-1) = lim(x→1) (x^2) is correct due to the cancellation of the common factor of (x-1) in both the numerator and denominator. This cancellation allows us to simplify the expression and evaluate the limit.

In the given equation, we have the limit of the expression [x^2/(x-2)] / (x-1) as x approaches 1. We can rewrite this expression as (x^2) / [(x-2)(x-1)]. By factoring out the common factor of (x-1) in the numerator and denominator, we obtain [(x-1)(x+1)] / [(x-2)(x-1)].

Since the factor (x-1) is common in both the numerator and denominator, it cancels out, resulting in the simplified expression of (x+1) / (x-2).

Now, as x approaches 1, we can substitute the value into the simplified expression to evaluate the limit, giving us (1+1) / (1-2) = 2 / -1 = -2.

Therefore, the equation lim(x→1) [x^2/(x-2)] / (x-1) = lim(x→1) (x^2) is correct, and the value of the limit is -2.

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The probability that a random sample of 36 gas stations will provide an average gas price within 0.50 of the population mean is 0.691, assuming that the population is normally distributed and the population standard deviation is known.

To calculate the probability that a random sample of 36 gas stations will provide an average gas price within 0.50 of the population mean, we need to use the central limit theorem and assume that the population is normally distributed.

Assuming that the population standard deviation is known, we can use the formula for the standard error of the mean:

SE = σ / √n

where SE is the standard error of the mean, σ is the population standard deviation, and n is the sample size.

Since we want the average gas price of the sample to be within $0.50 of the population mean, we can set up the following inequality:

|\(\bar X\) - μ| < 0.50

where \(\bar X\)is the sample mean and μ is the population mean.

We can rearrange this inequality as follows:

-0.50 < \(\bar X\) - μ < 0.50

Next, we can standardize the sample mean by subtracting the population mean and dividing by the standard error:

-0.50 < (\(\bar X\) - μ) / (σ / √n) < 0.50

Multiplying both sides by √n/σ, we get:

-0.50(√n/σ) < (\(\bar X\) - μ) / σ < 0.50(√n/σ)

Finally, we can use the standard normal distribution to find the probability that the standardized sample mean falls within this interval. The probability can be calculated as follows:

P(-0.50(√n/σ) < Z < 0.50(√n/σ))

where Z is a standard normal random variable.

Using a standard normal table or a calculator, we can find that the probability is approximately 0.691.

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Question

What is the probability that a random sample of 36 gas stations will provide an average gas price (X¯) that is within $0.50 of the population mean (μ)?

If a number cube is rolled 25 times and 6 appears only four times, then the experimental probability of getting 6 is 4/25.

The experimental probability of an event happening is the number of times the event occurred divided by the total number of trials. In this case, a number cube is rolled 25 times and lands on 6 four times. Here are the steps to determine the experimental probability of landing on 6:

So, the experimental probability of landing on 6 is 4/25, which means that if we roll the number cube many more times, we would expect to get a 6 approximately 4 out of every 25 rolls.

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Answer:

i think 90

Step-by-step explanation:

No of boys = 40%

let total no. of children be as "x"

now, 40% of x= 2x/5.

and since boys differ girls by 18.

no. of girl would be x-2x/5=3x/5.

now No. of boys= 2x/5

and no. of girls= 3x/5

no. of total children would then be as = 3x/5 - 2x/5= 18

The value of "X" would then be as = 90

To find no. of boys we would do 2x/5 X 90= 36

and no. of girls = 3x/5 X 90= 54.

to prove my answer 54-36= 18

Hope it helps C":

Suppose there are X children at the childcare.

Thus :

boys + girls = X

__________________________

40% of the children are boys .

Thus :

There are 40/100 × X boys .

So : boys = 0.4X (( Ω ))

__________________________

There are 18 more girls than boys

Thus :

girls - boys = 18

girls - ( 40/100 X ) = 18

girls - 0.4X = 18

Add sides 0.4X

girls - 0.4X + 0.4X = 18 + 0.4X

girls = 18 + 0.4X (( μ ))

__________________________

Now It's time to put (( μ ))

and (( Ω )) in the above equation.

boys + girls = X

0.4X + 18 + 0.4X = X

0.8X + 18 = X

Subtract sides 0.8X

- 0.8X + 0.8X + 18 = 1X - 0.8X

18 = 0.2X

0.2X = 18

Divided sides by 0.2 (( 2/10 ))

2/10 ÷ 2/10 × X = 18 ÷ 2/10

X = 18 × 10/2

X = 18 × 5

X = 90

Thus there are 90 children at the childcare.

Done.....♥️♥️♥️♥️♥️

I) and II) are true because the limit of the function at x=2 is 5, which implies that f is continuous and differentiable at x=2. III) is false because the derivative of f does not need to be continuous at x=2.

Let f be a function such that lim h→0 (f(2+h) - f(2)) / h = 5.

We can calculate this limit as follows:

lim h→0 (f(2+h) - f(2)) / h = lim h→0 (f(2+h) / h) - (f(2) / h)

= lim h→0 f(2+h) / h - lim h→0 f(2) / h

= lim h→0 f(2+h) / h - 0

= lim h→0 f(2+h) / h

= 5

Therefore, I) and II) are true because the limit of the function at x=2 is 5, which implies that f is continuous and differentiable at x=2. III) is false because the derivative of f does not need to be continuous at x=2.

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Answer:

she would not be 23 until November of 1920 not January

Answer: (2 1/2, 0) (the last option)

Step-by-step explanation:

I guess the function is:

f(x) = (2  1/2) - (3  1/2)*x

now, the rule for f-1(x) that we know is:

f-1( f(x) ) = x.

So if we want to find the x-intercept of f-1(x), we must evaluate it in f(0)

f-1(f(0)) = 0.

And we have that f(0) = (2  1/2) - (3  1/3)*x = 2  1/2

This means that the x-intercept of f-1(x) will be when x= 2  1/2, so the intercept is:

(2 1/2, 0)

The mean of the reading scores is 11.67, and the standard deviation is 2.97. The mean of a set of numbers is found by adding up all the values and dividing by the total number of values.

In this case, the sum of the reading scores is 140, and since there are 12 students, the mean is 140/12 = 11.67.

The standard deviation measures the variability or spread of the data from the mean. To find the standard deviation, we need to calculate the deviations of each score from the mean, square them, find their sum, divide by the total number of scores, and then take the square root of that value. The deviations from the mean for this set of scores are: -4.67, -4.67, 2.33, 1.33, -0.67, 2.33, -1.67, -0.67, -2.67, 1.33, 3.33, and 3.33. Squaring these deviations, we get: 21.69, 21.69, 5.43, 1.78, 0.45, 5.43, 2.78, 0.45, 7.12, 1.78, 11.09, and 11.09. Summing up these squared deviations gives us 89.79. Dividing by the total number of scores (12), we get 89.79/12 = 7.48. Finally, taking the square root of this value gives us the standard deviation of 2.97.

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The statement is true.

An orthogonal set with the same dimension as the initial collection of vectors is created by the Gram-Schmidt process.

Given that,

From a linearly independent collection of {x₁, x₂,..., xp}, the gram-Schmidt process creates an orthogonal set of {v₁, v₂,..., vp} with the feature that for each k, the vectors v₁...vk span the same subspace as that spanned by x₁...xk.

Whether the claim is true or false must be determined.

The statement is true.

An orthogonal set with the same dimension as the initial collection of vectors is created by the Gram-Schmidt process. An orthogonal set is further linearly independent. The orthogonal set produced by the Gram-Schmidt process and the original set will cover the same subspace if their dimensions are the same.

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Answer:

-300

Step-by-step explanation:

Step 1:  Find the amount Elmer's funds decreased after purchasing the rabbits:

Let x represent Elmer's funds.

Since Elmer bought five rabbits for $10 each, he lost $10 5 times.

x - (10 * 5)

x - 50

Thus, Elmer lost (spent) $50 for the 5 rabbits.

Step 2:  Find the amount Elmer's funds decreased after purchasing the  cupboards:

Since Elmer bought four cupboards for $70 each, he lost $70 4 times:

x - (50 + (70 * 4))

x - (50 + 280)

x - 330

Thus, after purchasing the rabbits and cupboards, Elmer lost $330.

Step 3:  Find the amount Elmer's funds increased after finding the twenty-dollar bill:

Since Elmer found a twenty-dollar bill, he gained $20

x - (330 + 20)

x - 310

Step 4:  Find the amount Elmer's funds increased after returning one rabbit:

Since Elmer returned one rabbit, he gained $10:

x - (310 + 10)

x - 300

Thus, Elmer's funds changed totally by -$300.

Putting all the information together, we have:

x - 10 - 10 - 10 - 10 - 10 - 70 - 70 - 70 - 70 + 20 + 10

x - 50 - 280 + 30

x - 330 + 30

x - $300

Answer:

The vertex is option C: (-6, -2)

Step-by-step explanation:

The equation for a parabola is y = a(x – h)² + k where h and k are the y and x coordinates of the vertex, respectively. Thus, the vertex is (-6,2)

Pls mark brainliest.

Answer: $64

Step-by-step explanation:

Answer:

This question is unanwserable without the "Spider Tool" If you would like to revise it i'd be happy to help

Step-by-step explanation:

But the units are degrees

The maximum number of nonzero orthogonal vectors that can be found in ℝ³ is three, while in ℝⁿ it can be at most n.

In ℝ³, the maximum number of nonzero orthogonal vectors that can be found is three. To determine the orthogonal subsets, we can start by considering individual vectors and then expanding the subsets by adding orthogonal vectors one by one. For example, one possible maximal orthogonal subset is {v, w, x}, where v, w, and x are pairwise orthogonal. In this subset, y and z are not orthogonal to all the vectors within the group. Similarly, we can form other maximal orthogonal subsets such as {v, y, z} and {w, y, z}. However, it is not possible to form a subset with four nonzero orthogonal vectors in ℝ³.

In general, for ℝⁿ, the maximum number of nonzero orthogonal vectors that can be found is n. This is because in ℝⁿ, we can have n orthogonal basis vectors that span the entire space. These basis vectors are mutually orthogonal, meaning that each vector is orthogonal to all the other basis vectors. Therefore, by definition, we can have at most n nonzero orthogonal vectors in ℝⁿ.

Overall, the maximum number of nonzero orthogonal vectors in ℝ³ is three, while in ℝⁿ, it can be at most n.

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The mean crack size is 1.25 mm.

(a) To sketch the PDF and CDF, we can plot the given probability density function (PDF) on a graph paper.

The PDF f_X(x) is defined as follows:

f_X(x) = {

x/8 for 0 < x ≤ 2,

1/4 for 2 < x ≤ 5,

0 elsewhere

}

First, let's plot the PDF on the graph paper:

        |       .     .

   1/4  |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

   0.2  |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

        |       .     .

   0.1  |   .   .   .   .

        | . . . . . . . .

        +----------------

          0   2   4   6

The height of the PDF corresponds to the probability density at a given value of x.

Next, let's calculate the cumulative distribution function (CDF) to sketch it on the graph paper.

The CDF is obtained by integrating the PDF from negative infinity to x:

F_X(x) = ∫[0,x] f_X(t) dt

For 0 ≤ x ≤ 2:

F_X(x) = ∫[0,x] (t/8) dt = (1/8) * ∫[0,x] t dt = (1/8) * (t^2/2)|[0,x] = (1/8) * (x^2/2) = x^2/16

For 2 < x ≤ 5:The height of the PDF corresponds to the probability density at a given value of x.

Next, let's calculate the cumulative distribution function (CDF) to sketch it on the graph paper.

The CDF is obtained by integrating the PDF from negative infinity to x:

F_X(x) = ∫[0,x] f_X(t) dt

For 0 ≤ x ≤ 2:

F_X(x) = ∫[0,x] (t/8) dt = (1/8) * ∫[0,x] t dt = (1/8) * (t^2/2)|[0,x] = (1/8) * (x^2/2) = x^2/16

For 2 < x ≤ 5:The height of the PDF corresponds to the probability density at a given value of x.

Next, let's calculate the cumulative distribution function (CDF) to sketch it on the graph paper.

The CDF is obtained by integrating the PDF from negative infinity to x:

F_X(x) = ∫[0,x] f_X(t) dt

For 0 ≤ x ≤ 2:

F_X(x) = ∫[0,x] (t/8) dt = (1/8) * ∫[0,x] t dt = (1/8) * (t^2/2)|[0,x] = (1/8) * (x^2/2) = x^2/16

For 2 < x ≤ 5:F_X(x) = ∫[0,2] (t/8) dt + ∫[2,x] (1/4) dt = (1/8) * ∫[0,2] t dt + (1/4) * ∫[2,x] dt = (1/8) * (t^2/2)|[0,2] + (1/4) * (t)|[2,x] = (1/8) * 2 + (1/4) * (x-2) = 1/4 + (1/4) * (x-2) = 1/4 + (x-2)/4 = (x+1)/4

For x > 5:

F_X(x) = 1

Now, let's plot the CDF on the same graph paper:

        | . . . . . . . .

   1    | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

   0.8  | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

   0.6  | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

        | . . . . . . . .

   0.4  | . . . . . . . .

        |

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Answer:

39%

Step-by-step explanation:

83-last price

83 last price

100 x ?

100 * last price = 83 . x

x= 39

Hey there!

The answer is 100 square meters.

The formula for area is length times width, therefore we do 10 * 10, which gets us 100 square meters.

Have a terrificly amazing day! :D