Somebody help me this is on my final and I don’t wanna fail it please somebody help me

The statements about the local maximums and minimums for the given function which are true include:

This is defined as the mathematical entities which assign unique outputs to given inputs and defines a relationship between the two variables.

According the the graph: over the interval [2, 4], the local minimum is –8 because the given minimum point is (3.4, -8) and over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0 and over the interval [3, 5], there is no maximum point hence why it is false.

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Answer:

B. 8

Step-by-step explanation:

(5)+3=8

Answer:

b. 8

Step-by-step explanation:

h(a)=a+3

h(5)=5+3

h(5)=8

Hello,

Ali is right, Khamis is wrong. Why because Khamis forgot to put the negative sign in front of 5b, it should be wrote -5b in the second line and not 5b.

And then Khamis should have divided -5b by -5b.

Good Luck

Answer:

domain (-3,0,2)

range (3,6,9)

Step-by-step explanation:

the domain is all the numbers on the x-axis or the input side and the range is all the numbers on the y-axis side or the output

a. The critical points of f are: (3, 0).

b. Linear equation for the side of the boundary of D between (12, 0) and (0, 7): y = (-7/12)x + 7.

c. Points on this side of the boundary that could be absolute minimum or maximum on D: (3, 0) and (12, 0).

d. Absolute maximum of f on D: 71 at (12, 0), absolute minimum: -10 at (3, 0).

We have,

To find the absolute maximum and minimum values of the function f(x, y) = y² + x² - 6x - 1 on the triangular region D with vertices (12, 0), (0, 7), and (0, -7), we can follow these steps:

a.

To find the critical points of f, we need to find where the gradient of f equals zero or is undefined.

Taking the partial derivatives of f with respect to x and y:

∂f/∂x = 2x - 6

∂f/∂y = 2y

Setting these partial derivatives equal to zero and solving for x and y, we get:

2x - 6 = 0 => x = 3

2y = 0 => y = 0

So the critical point is (3, 0).

b.

The linear equation for the side of the boundary of region D between (12, 0) and (0, 7) can be found using the two-point form of a linear equation:

(y - y1) = ((y2 - y1) / (x2 - x1)) x (x - x1)

Substituting the coordinates (12, 0) and (0, 7), we have:

(y - 0) = ((7 - 0) / (0 - 12)) x (x - 12)

Simplifying this equation gives:

y = (-7/12)x + 7

c.

To find the points on this side of the boundary that could potentially be the absolute minimum or maximum, we need to consider the endpoints of the side.

The endpoints are (12, 0) and (0, 7).

d.

To find the absolute maximum and minimum values of f on region D, we evaluate the function f at the critical point and the endpoints:

\(f(3, 0) = (0)^2 + (3)^2 - 6(3) - 1 = -10\\f(12, 0) = (0)^2 + (12)^2 - 6(12) - 1 = 71\\f(0, 7) = (7)^2 + (0)^2 - 6(0) - 1 = 48\)

Comparing these values, we see that the absolute maximum value is 71 and it occurs at the point (12, 0), while the absolute minimum value is -10 and it occurs at the point (3, 0).

Therefore, the absolute maximum of f on region D is 71 at (12, 0), and the absolute minimum is -10 at (3, 0).

Thus,

a. The critical points of f are: (3, 0).

b. Linear equation for the side of the boundary of D between (12, 0) and (0, 7): y = (-7/12)x + 7.

c. Points on this side of the boundary that could be absolute minimum or maximum on D: (3, 0) and (12, 0).

d. Absolute maximum of f on D: 71 at (12, 0), absolute minimum: -10 at (3, 0).

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Answer:

it's A cus i made a good grade so A is the right answer

Consider that in slope-intercept form the equation of a line is given by:

y = mx + b

where m is the slope and b the y-intercept.

Then, solve for y the given equation, as follow:

2x - 3y = -6 subtract 2x both sides

-3y = -2x - 6 divide by -3 both sides

y = 2/3 x + 2

The previous result is the equation is slope-intercept form.

The graph the previous equation, use the a pair of values for x and placed them in the coordinate system, after this, draw a straigh line which crosses the two points, as follow:

where we have use the values of x = -3 and x = 0 and the results for y are:

y = 2/3 (-3) + 2 = - 2 + 2 = 0

y = 2/3(0) + 2 = 2

Which correspond to the shown points (-3,0) and (0,2)

Answer: March to April shows the least increase of average temperature.

Answer:

It’s d

Step-by-step explanation:

Answer:b

Step-by-step explanation:

Answer: B). y=5x-6

Step-by-step explanation:

A is just the x-intercept

C is a parabola

D would just eventually equal to the x-intercept

Through deductive reasoning, we get B.

Answer:

you will spend 56 dollars

Step-by-step explanation:

According to the Pythagorean Theorem, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs of a right triangle.

In other words, \(a^2 + b^2 = c^2\) for the triangle depicted below.

The right triangle's legs, a and b, are perpendicular sides, and the hypotenuse, c, is the side that faces away from the right angle.

Construction projects and almost anything involving right triangles, such as roofing for homes, are common uses for this application.

Hypotenuse² = Base² + Perpendicular²

The Pythagorean Theorem is used in a variety of computations. For instance, it may be used to determine the height and distance of straight and fallen trees, as well as the steepness of hills and mountains.

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Answer:

Step-by-step explanation:

The question is asking how many times does 50 go into 425?

or 450/50 = ?

my calculator says it's 9 .  What does your calculator say?

since we now know it's 9 times,   we can just multiply 9 * 10 minutes

by observation of 9*10,  I get the answer,  what answer do you get?

Answer:

f(3)=201

f(2)=-4

Step-by-step explanation:

Plug in each value for x

\(3^{5} -2(3)^{3} +12\)

\(243-54+12=201\)

\(-2^{5} -2(-2)^{3} +12\)

\(-32+16+12=-4\)

Answer:

f(3) = 201

f(-2) = -4

Step-by-step explanation:

\(f(x) = x^5 - 2x^3 + 12\)

\(f(3) = (3)^5 - 2(3)^3 + 12\)

\(\implies f(3) = 243 - 54 + 12\)

\(\implies f(3) = 201\)

\(f(-2) = (-2)^5 - 2(-2)^3 + 12\)

\(\implies f(-2) = -32+16 + 12\)

\(\implies f(-2) = -4\)

The series of operations for each case are listed below:

In algebra, factor properties are commonly used to solve certain forms of polynomials in a quick and efficient way and whose effectiveness is sustained on all definitions and theorems known in real algebra. In this problem, we should explain and show what factor properties are used in each case:

Case 1

5 · x · y³ + 10 · x² · y                                             Given

5 · (x · y³ + 2 · x² · y)                                            GCF

5 · x · (y³ + 2 · x · y)                                              GCF

5 · x · y · (y² + 2 · x)                                              GCF

Case 2

6 · z · x + 9 · x + 14 · z + 21                                   Given

3 · x · (z + 3) + 7 · (z + 3)                                       GCF

(3 · x + 7) · (z + 3)                                                  Grouping

Case 3

a² + 2 · a - 63                                                       Given

(a + 9) · (a - 7)                                                       Quadratic trinomial

Case 4

6 · z² + 5 · z - 4                                                     Given

6 · [z² + (5 / 6) · z - 2 / 3]                                      GCF

6 · (z - 1 / 2) · (z + 4 / 3)                                         Quadratic trinomial

Case 5

81 · m² - 25                                                           Given

(9 · m + 5) · (9 · m - 5)                                           Difference of squares

Case 6

8 · x³ - 27                                                               Given

(2 · x - 3) · (4 · x² + 6 · x + 9)                                  Difference of cubes

4 · (2 · x - 3) · [x² + (3 / 2) · x + 9 / 4]                      Quadratic trinomial

Case 7

27 · b³ + 64 · z³                                                      Given

(3 · b + 4 · z) · (9 · b² - 12 · b · z + 16 · z²)               Sum of cubes

Case 8

2 · w³ - 28 · w² + 80 · w                                         Given

2 · w · (w² - 14 · w + 40)                                          GCF

2 · w · (w - 4) · (w - 10)                                             Quadratic trinomial

Case 9

200 · a⁴ - 18 · b⁶                                                     Given

2 · (100 · a⁴ - 9 · b⁶)                                                GCF

2 · (10 · a² + 3 · b³) · (10 · a² - 3 · b³)                       Difference of squares

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The Maclaurin series of the function f(x)=7x2e−5x can be written as f(x)=∑n=0[infinity]​cn​xn . Therefore, the first few coefficients of the Maclaurin series of \($f(x) = 7x^2 e^{-5x}$\) are\($c_0 = 0, c_1 = 0, c_2 = 7, c_3 = -35$\)and \($c_4 = \frac{245}{24}$ and $c_5 = \frac{14}{3}$.\)

The Maclaurin series of the given function \($f(x) = 7x^2 e^{-5x}$\) can be written as:

\($f(x) = \sum_{n=0}^\infty c_n x^n$ \\where $c_1 = c_2 = c_3 = c_4 = c_5 =$\)

To determine the values of \($c_1, c_2, c_3, c_4$ and $c_5$\)

, we need to find the derivative of f(x) and evaluate it at x=0.

Let's find the first few derivatives of f(x):\($$f(x) = 7x^2 e^{-5x}$$$$f'(x) = 14xe^{-5x} - 35x^2 e^{-5x}$$$$f''(x) = 14e^{-5x} - 70xe^{-5x} + 35x^2 e^{-5x}$$$$f'''(x) = 350x e^{-5x} - 210e^{-5x} - 105x^2 e^{-5x}$$$$f^{(4)}(x) = 1225x^2 e^{-5x} - 1400xe^{-5x} + 420e^{-5x}$$$$f^{(5)}(x) = 1225xe^{-5x} - 6125x^2 e^{-5x} + 2800xe^{-5x}$$$$f^{(6)}(x) = 6125x^2 e^{-5x} - 12250xe^{-5x} + 2800e^{-5x}$$\)

Now let's evaluate these derivatives at x=0:f(0) = 0

f'(0) = 0 - 0 = 0

f''(0) = 14 - 0 + 0 = 14

f'''(0) = 0 - 210 - 0 = -210

f^{(4)}(0) = 1225 - 1400 + 420 = 245

f^{(5)}(0) = 0 - 0 + 2800 = 2800

\($$$$f^{(6)}(0) = 0 - 12250 + 2800 = -9450$$\)

Hence, the Maclaurin series of f(x) is:\($$f(x) = c_0 + c_1 x + c_2 x^2 + c_3 x^3 + c_4 x^4 + c_5 x^5 + \cdots$$ $$f(0) = c_0 = 7(0)^2 e^0 = 0 \Rightarrow c_0 = 0$$$$\)\(f'(0) = c_1 = 0 \Rightarrow c_1 = 0$$$$f''(0) = c_2 = \frac{f''(0)}{2!} = \frac{14}{2} = 7 \Rightarrow c_2 = 7$$$$f'''(0) = c_3 = \frac{f'''(0)}{3!} = \frac{-210}{6} = -35 \Rightarrow c_3 = -35$$$$f^{(4)}(0) = c_4 = \frac{f^{(4)}(0)}{4!} = \frac{245}{24} \Rightarrow c_4 = \frac{245}{24}$$$$f^{(5)}(0) = c_5 = \frac{f^{(5)}(0)}{5!} = \frac{2800}{120} = \frac{14}{3} \Rightarrow c_5 = \frac{14}{3}$$\)

Therefore, the first few coefficients of the Maclaurin series of \($f(x) = 7x^2 e^{-5x}$\) are\($c_0 = 0, c_1 = 0, c_2 = 7, c_3 = -35$\)and \($c_4 = \frac{245}{24}$ and $c_5 = \frac{14}{3}$.\)

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In this study, 60 undergraduate students were recruited to examine the effect of recycling on the amount of wrapping paper used to wrap a gift. The students were randomly assigned to one of two rooms, one with a recycling bin and one with a trash bin.

The researchers, who were secretly interested in measuring the amount of paper used, found that the students in the room with the recycling bin used significantly more paper than those in the room with the trash bin. This experiment suggests that the presence of a recycling bin may not have a significant effect on reducing the amount of wrapping paper used.

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Answer:

-82

Step-by-step explanation:

84/21=4

-25x4=-100

-3x-6=18

-100+18=-82

Answer:

25% .70

Step-by-step explanation:

If we subtract 900 from 1,200, we get 300. If we take 300 and multiply it by 4, we get 1,200. meaning that 300 is going to be 25% so since 300 is taken away, the decrease is 25%. Im not so sure about the decay factor but since 25% .70 is our only answer with a 25% decrease, our answer is going to be D.

Answer:

What the other person said

Step-by-step explanation:

Solution B has a 100 times greater {H} than Solution A.

The pH of a solution is a measure of the concentration of hydrogen ions in the solution. A higher pH indicates a lower hydrogen ion concentration, and a lower pH indicates a higher hydrogen ion concentration. Therefore, Solution B has a higher hydrogen ion concentration than Solution A. To calculate the ratio of {H} between the two solutions, we must take the inverse of the pH difference. In this case, the difference is 3. Therefore, the ratio of {H} between the two solutions is 1/3, or 100 times greater {H} in Solution B than in Solution A.

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From the given figure , the special angle pair relationship between ∠1 and ∠3 are known as corresponding angles and are congruent.

As given in the question,

From the given figure:

line l is parallel to line m.

t is the transversal of line l and m

Relationship between angles for the parallel lines

∠1 and ∠2  are straight angles and are supplementary

∠3 and ∠2 are interior angles and are supplementary

⇒m(∠1 + ∠2) = m(∠3+∠2)

⇒m∠1= m∠3

Therefore, from the given figure , the special angle pair relationship between ∠1 and ∠3 are known as corresponding angles and are congruent.

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Answer:

\(32x^{2} + 1 / 16x\)

Step-by-step explanation:

x2+1/4x4

2x+(1/4*4x)

2x+(1/16x)

= 32x^2+1/16x

The probability that both the balls drawn are white is 2/7 when two balls are drawn successively without replacement from a box which contains 4 white balls and 3 red balls.

Two balls are drawn successively without replacement from a box which contains 4 white balls and 3 red balls.

Therefore, Total number of balls in the box = 4+ 3 = 7 balls

Thus, the probability that the first ball drawn is a white is = (Total number of white balls) /  ( Total number of balls)

=4/7

The next ball is drawn without replacement thus the number of balls in the box is 6.

And if 1 ball is picked in drawn n first tie, then remaining number of white balls is 3.

Thus, the probability that the second ball drawn is a white is = (Remaining number of total white balls) /  ( Remaining number of total balls)

= 3/6 = 1/2

Therefore, the probability that both the balls drawn are white is

= (4/7)*(1/2)

= 2/7

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Answer:

13

Step-by-step explanation:

Put n as 4

\(3(4)+1=12+1=13\)

Hope this helps :)

When constructing a histogram, the horizontal (x) axis represents the range of values of the variable being measured or observed, while the vertical (y) axis represents the frequency or count of observations falling within each interval or bin.

More specifically, the x-axis usually represents the range of possible values of the variable being measured or observed, divided into a series of intervals or bins. Each bin represents a range of values that fall within a certain interval or category. The width of the bins should be chosen carefully to ensure that the data is displayed clearly and accurately.

The y-axis represents the frequency or count of observations that fall within each bin. This can be represented as either the number of observations that fall within each bin or as a percentage of the total number of observations. The y-axis should also be chosen carefully to ensure that the data is displayed clearly and accurately.

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Answer:

4

Step-by-step explanation: