Some pastries are cut into rhombus shapes before serving.

A rhombus with horizontal diagonal length 4 centimeters and vertical diagonal length 6 centimeters.
Please hurry (will give brainliest)
What is the area of the top of this rhombus-shaped pastry?

10 cm2
12 cm2
20 cm2
24 cm2

Answer:

Brainiest

Step-by-step explanation:

17 1/2

To determine if it would be unusual to randomly select 12 people and find that fewer than 5 recognize the Yummy brand name, we can use the concept of standard deviation and z-scores.

First, we need to calculate the z-score, which measures how many standard deviations an observation is from the mean. The formula for calculating the z-score is:

z = (x - μ) / σ

where

z = (5 - 9.3) / 0.99

z = -4.394

Next, we can consult a standard normal distribution table or use statistical software to find the corresponding percentile associated with the z-score. This percentile represents the probability of randomly selecting a group of 12 people with fewer than 5 recognizing the Yummy brand name.

In this case, the z-score of -4.394 corresponds to an extremely low percentile, close to 0.

The exact probability can be determined using the z-score and the standard normal distribution table.

Since the probability is extremely low, it would be considered unusual to randomly select 12 people and find that fewer than 5 recognize the Yummy brand name.

However, it's important to note that the definition of "unusual" may vary depending on the specific criteria or threshold chosen.

In statistical terms, a common threshold for defining unusual events is a significance level of 5% (or 0.05). If the probability of observing the event is lower than the significance level, it is considered unusual.

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The consumption bundle that will not be the consumer's choice, given the assumptions of choosing the optimal bundle, is option B) 30 snacks and 12 meals. To determine the optimal consumption bundle, we need to consider the consumer's budget constraint and maximize their utility.

Given that the price of snacks is $4 and the price of meals is $10, and the consumer has $240 remaining on their meal card, we can calculate the maximum number of snacks and meals that can be purchased within the budget constraint.

For option A) 5 snacks and 20 meals, the total cost would be $4 × 5 + $10 × 20 = $200. Since the consumer has $240 remaining, this bundle is feasible.

For option B) 30 snacks and 12 meals, the total cost would be $4 × 30 + $10 × 12 = $240. This bundle is on budget constraint, but it may not be the optimal choice since the consumer could potentially consume more meals for the same cost.

For option C) 20 snacks and 16 meals, the total cost would be $4 × 20 + $10 × 16 = $240. This bundle is also on budget constraint.

Since options A, C, and D are all feasible within the budget constraint, the only bundle that will not be the consumer's choice is option B) 30 snacks and 12 meals. The consumer could achieve a higher level of utility by reallocating some snacks to meals while staying within the budget constraint. Therefore, the correct answer is option B.

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The ratio using fraction notation of $5 to $35 would be 7.

A fraction represents a part of a number or any number of equal parts.

To convert a ratio into a fraction,

We will simply use the first number as the numerator and the second number as the denominator.

So the fraction = 35/5.

= 7

Since there are no more common factors, the fraction is in its lowest form which is 7.

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a) Jay will consume 50 barrels of beer.b) Jay will spend $2500 on beer.c) Jay's consumer surplus from beer consumption is $1250 where demand function is given.

a) To determine how many barrels of beer Jay will consume at a price of $50 per barrel, we can substitute this price into his demand function:

D(p) = 100 - p

D(50) = 100 - 50

D(50) = 50

Therefore, Jay will consume 50 barrels of beer.

b) To calculate how much money Jay will spend on beer, we multiply the price per barrel by the quantity consumed:

Money spent on beer = Price per barrel * Quantity consumed

Money spent on beer = $50 * 50

Money spent on beer = $2500

Jay will spend $2500 on beer.

c) The consumer surplus represents the difference between the maximum price a consumer is willing to pay and the actual price paid. In this case, Jay's consumer surplus can be calculated by finding the area of the triangle formed by the demand curve and the price axis. Since Jay's demand function is a straight line, the consumer surplus can be calculated as:

Consumer surplus = (1/2) * (Quantity consumed) * (Price per barrel)

Consumer surplus = (1/2) * 50 * $50

Consumer surplus = $1250

Jay's consumer surplus from beer consumption is $1250.

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Answer:

xd

Step-by-step explanation:

xd

se pone primero la x y despues la d, se dice gracias crick

Step-by-step explanation:

32 9655 9655 + 965 + 965 + 965 + 982

Answer:

slope=1  y-intercept=5

Step-by-step explanation:

there isn't much to it, but if you want me to show my work I will

Answer:

The average rate of change of the function for the interval [-4, 0] is  \(\frac{3}{4}\) ⇒ A

Step-by-step explanation:

The average rate of change of the function is the slope of the line that represents the function, m = Δy/Δx, where

From the given figure

→ The values of x in the interval [-4, 0] are -4 and 0

∵ The point (-4, 0) and (0, 3) lie on the line

∴ x1 = -4 and x2 = 0

∴ x2 = 0 and y2 = 3

∵ Δx = 0 - (-4) = 0 + 4 = 4

∵ Δy = 3 - 0 = 3

→ By using the rule of the slope above

∴ m = \(\frac{3}{4}\)

∵ The average rate of change of the function = the slope of the line

∴ The average rate of change of the function for the interval [-4, 0] is  \(\frac{3}{4}\)

Answer:

\(y=c_1\cos(x)+c_2\+\sin(x)+\sin^2(x)-\frac{1}{3}\sin^4(x)+\frac{1}{3}\cos^4(x)}}}\)

Step-by-step explanation:

Given the second-order differential equation, \(y'' + y = cos2(x)\), solve it using variation of parameters.

(1) - Solve the DE as if it were homogenous and find the homogeneous solution\(y'' + y = cos2(x) \Longrightarrow y'' + y =0\\\\\text{The characteristic equation} \Rightarrow m^2+1=0\\\\m^2+1=0\\\\ \Longrightarrow m^2=-1\\\\\ \Longrightarrow m=\sqrt{-1} \\\\\Longrightarrow \boxed{m=\pm i} \\ \\\text{Solution is complex will be in the form} \ \boxed{y=c_1e^{\alpha t}\cos(\beta t)+c_2e^{\alpha t}\sin(\beta t)} \ \text{where} \ m=\alpha \pm \beta i\)

\(\therefore \text{homogeneous solution} \rightarrow \boxed{y_h=c_1\cos(x)+c_2\sin(x)}\)

(2) - Find the Wronskian determinant

\(|W|=\left|\begin{array}{ccc}y_1&y_2\\y'_1&y'_2\end{array}\right| \\\\\Longrightarrow |W|=\left|\begin{array}{ccc}\cos(x)&\sin(x)\\-sin(t)&cos(x)\end{array}\right|\\\\\Longrightarrow \cos^2(x)+\sin^2(x)\\\\\Longrightarrow \boxed{|W|=1}\)

(3) - Find W_1 and W_2

\(\boxed{W_1=\left|\begin{array}{ccc}0&y_2\\g(x)&y'_2\end{array}\right| and \ W_2=\left|\begin{array}{ccc}y_2&0\\y'_2&g(x)\end{array}\right|}\)

\(W_1=\left|\begin{array}{ccc}0&\sin(x)\\\cos^2(x)&\cos(x)\end{array}\right|\\\\\Longrightarrow \boxed{W_1= -\sin(x)\cos^2(x)}\\\\W_2=\left|\begin{array}{ccc}\cos(x)&0\\ -\sin(x)&\cos^2(x)\end{array}\right|\\\\\Longrightarrow \boxed{W_2= \cos^3(x)}\)

(4) - Find u_1 and u_2

\(\boxed{u_1=\int\frac{W_1}{|W|} \ and \ u_2=\int\frac{W_2}{|W|} }\)\

u_1:

\(\int(\frac{-\sin(x)\cos^2(x)}{1}) dx\\\\\Longrightarrow-\int(\sin(x)\cos^2(x)) dx\\\\\text{Let} \ u=\cos(x) \rightarrow du=-sin(x)dx\\\\\Longrightarrow\int u^2 du\\\\\Longrightarrow \frac{1}{3}u^3\\ \\\Longrightarrow \boxed{u_1=\frac{1}{3}\cos^3(x)}\)

u_2:

\(\int\frac{\cos^3(x)}{1}dx\\ \\\Longrightarrow \int \cos^3(x)dx\\\\ \Longrightarrow \int (\cos^2(x)\cos(x))dx \ \ \boxed{\text{Trig identity:} \cos^2(x)=1-\sin^2(x)}\\\\\Longrightarrow \int[(1-\sin^2(x)})\cos(x)]dx\\\\\Longrightarrow \int \cos(x)dx-\int (\sin^2(x)\cos(x))dx\\\\\Longrightarrow \sin(x)-\int (\sin^2(x)\cos(x))dx\\\\\text{Let} \ u=\sin(x) \rightarrow du=cos(x)dx\\\\\Longrightarrow \sin(x)-\int u^2du\\\\\Longrightarrow \sin(x)-\frac{1}{3} u^3\)\

\(\Longrightarrow \boxed{u_2=\sin(x)-\frac{1}{3} \sin^3(x)}\)

(5) - Generate the particular solution

\(\text{Particular solution} \rightarrow y_p=u_1y_1+u_2y_2\)

\(\Longrightarrow y_p=(\frac{1}{3}\cos(x))(\cos(x))+(\sin(x)-\frac{1}{3} \sin^3(x))(\sin(x))\\\\ \Longrightarrow y_p=\frac{1}{3}\cos^4(x)+\sin^2(x)-\frac{1}{3}\sin^4(x)\\\\\Longrightarrow \boxed{y_p=\sin^2(x)-\frac{1}{3}\sin^4(x)+\frac{1}{3}\cos^4(x)}\)

(6) - Form the general solution

\(\text{General solution} \rightarrow y_{gen.}=y_h+y_p\)

\(\boxed{\boxed{y=c_1\cos(x)+c_2\+\sin(x)+\sin^2(x)-\frac{1}{3}\sin^4(x)+\frac{1}{3}\cos^4(x)}}}\)

Thus, the solution to the given DE is found where c_1 and c_2 are arbitrary constants that can be solved for given an initial condition. You can simplify the solution more if need be.

To find a common denominator for the fractions 2/8 and 1/3, we need to determine the least common multiple (LCM) of their denominators. The LCM of 8 and 3 is 24. Therefore, 24 is a common denominator for the fractions 2/8 and 1/3.

To find a common denominator for the fractions 2/8 and 1/3, we need to determine the least common multiple (LCM) of their denominators.

The denominator of the first fraction is 8, and the denominator of the second fraction is 3. To find the LCM of 8 and 3, we can list their multiples and find the smallest number that is divisible by both 8 and 3.

Multiples of 8: 8, 16, 24, 32, 40, 48, ...

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, ...

From the lists, we can see that the smallest number divisible by both 8 and 3 is 24. Therefore, 24 is a common denominator for the fractions 2/8 and 1/3.

To express the fractions with the common denominator of 24, we can multiply the numerator and denominator of each fraction by the appropriate factor. For the fraction 2/8, we multiply the numerator and denominator by 3 to get (2×3)/(8×3) = 6/24. For the fraction 1/3, we multiply the numerator and denominator by 8 to get (1×8)/(3×8) = 8/24.

Now both fractions have a common denominator of 24, and the fractions are 6/24 and 8/24.

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Answer:

3/2 of a mile

Step-by-step explanation:

The equation is 1/2 times something = 3/4 (because length times width is area)

you would divide 1/2 on both sides to get an unknown number(that represents the width)

3/4 divided by 1/2 is 3/2 of a mile !

Answer:

f(x) = −x2 + 4x + 12

Step-by-step explanation:

The statements that are true about the given algorithms are: I. Algorithm 1 does not work on lists where the smallest value is at the start of the list or the largest value is at the end of the list.  II. Algorithm 2 does not work on lists that contain all negative numbers or all numbers over 1000.

Algorithm 1's reliance on initializing minVal to the first value and maxVal to the last value can lead to incorrect results if the smallest or largest value is not properly updated during the iteration. Similarly, Algorithm 2's fixed initial values for minVal and maxVal can result in incorrect differences when dealing with lists containing all negative numbers or all numbers over 1000.

It is important to consider these limitations and potential failure cases when choosing and implementing an algorithm for calculating the difference between the smallest and largest values in a list.

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Answer:

A unit rate is a rate with 1 in the denominator

Step-by-step explanation:

Answer:

The fish jumped 7 inches from the sea then fell 7 inches down.

Step-by-step explanation:

Answer:

7-7

Step-by-step explanation:

7 adding a negative number means it is subtracting because you are taking away from the 7.

Sample 1: Mean=10.01, Standard deviation=13.90 Sample 2: Mean

=11.43, Standard deviation

=14.10

Sample size of 1st year = n1

= 1012Mean of 1st year sample

= X1 = 10.01Standard deviation of 1st year sample

= s1

= 13.90Sample size of 2nd year

= n2

= 1012Mean of 2nd year sample

= X2

= 11.43

Standard deviation of 2nd year sample = s2

= 14.10 Let us assume a significance level of α = 0.05, which implies that the critical region consists of 2.5% in both tails (since it is a two-tailed test).

Therefore, we do not have sufficient evidence to conclude that the mean number of hours per week spent on the Internet differs between 2010 and another year.

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The circumference of the circle in terms of π whose radius is given would be = 63π. That is option D.

To calculate the circumference of a circle, the formula that should be used would be given below.

That is;

circumference of circle= 2πr

The radius = 31½

circumference = 2×π × 31½

= 2×π× 63/2

= 63π

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Answer:

3

Step-by-step explanation:

3 is the only number here with factors of itself (3) and 1

Answer:

3

Step-by-step explanation:

Answer:

3•10^3 is 3,000, so the answer is 9,000

Remember that the slope-intercept equation of the line is:

where 'm' is the slope and b is the y-intercept.

In this case, we have the following:

therefore,, the slope is m = 2

The translated function is:

g(x) = √(x - 3) - 9

The transformations used here are:

Horizontal translation:

For a general function f(x), a horizontal translation of N units is written as:

g(x) = f(x + N).

Vertical translation:

For a general function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N.

So, if we have a translation of 3 units right and 9 units down, this would be written as:

g(x) = f(x - 3) - 9

Replacing f(x) by the actual function we get:

g(x) = √(x - 3) - 9

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Answer:

c) slope: -7 ; y-intercept: 2

Step-by-step explanation:

Note the slope intercept form:

y = mx + b

y = (x , y)

m = slope

x = (x , y)

b = y-intercept

Note in this case:

y = (-7)x + 2

y = y

m = -7

x = x

b = 2

c) slope: -7 ; y-intercept: 2 is your answer.

~

Using the Factor Theorem, it is found that the equation that is best used to determine the zeros of the graph of y = 4x^2 – 8x - 5 is:

A. (2x + 1)(2x - 5) = 0

The Factor Theorem states that a polynomial function with roots \(x_1, x_2, \codts, x_n\) is given by:

\(f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)\)

In which a is the leading coefficient.

In this problem, the function is:

y = 4x² - 8x - 5.

Which is a quadratic function with coefficients a = 4, b = -8, c = -5, hence the solutions are found as follows.

\(\Delta = (-8)^2 - 4(4)(-5) = 144\)

\(x_1 = \frac{8 + \sqrt{144}}{8} = \frac{5}{2}\)

\(x_2 = \frac{8 - \sqrt{144}}{4} = -\frac{1}{2}\)

Hence, applying the Factor Theorem:

\(y = \left(x - \frac{5}{2}\right)\left(x + \frac{1}{2}\right)\)

Multiplying by 2:

y = (2x - 5)(2x + 1).

Hence option A is correct.

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Answer:

The one on the right: none of these

The one on the left: linear pair

Step-by-step explanation:

hope this helps

sorry if not

Answer:

Step-by-step explanation:

140/0.35squared

=1142.857142

to 1 d,p=1142.9

B. No attempt is made to contact noncorrespondents.

Hence,B. No attempt is made to contact noncorrespondents.

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Answer:

what level math is this I am not too familiar with it

Answer:

The last one center is (-16,-4) radius is 6

Step-by-step explanation:

Equation of a circle ( x - h )^2 + ( y - k )^2 = r^2

R is radius

H and k are (h,k)

Answer:

Step-by-step explanation:

A