Solve y(y−10)+30=0 by using the quadratic formula. If there is no real solution

Answers

Answer 1

Answer:

The answer is below:

Step-by-step explanation:

Rewrite: y(y−10)+30=0 into

y^2-10y+30

Quadratic formula:

Hope this helps!

Solve Y(y10)+30=0 By Using The Quadratic Formula. If There Is No Real Solution

Related Questions

value of 6 in 2,016?​

Answers

Ones is the place value of the digit 6 in the number 2,016 and 6 is the face value of the digit 6 in the number 2,016.

Given, a number 2,016

we have to find the place and face value of 6 in the given number 2,016.

So, the Place value of 6 in the given number is ones.

Ones is the place value of the digit 6 in the number 2,016

Also, the Face value of 6 in the given number is 6.

6 is the face value of the digit 6 in the number 2,016

Hence, Ones is the place value of the digit 6 in the number 2,016 and 6 is the face value of the digit 6 in the number 2,016.

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You are baking chocolate chip cookies. The recipe asks for 3 3/4 cups of flour and you want to make 2 times the original recipe.
A. 1 1/2 cups
B. 30/4 cups
C. 7 2/4 cups
D. 7 1/2 cups

Answers

You are baking chocolate chip cookies. The recipe asks for 3 3/4 cups of flour and you want to make 2 times the original recipe.
A. 1 1/2 cups
B. 30/4 cups
C. 7 2/4 cups
D. 7 1/2 cups
The answer will be d

PLease see attached. This is an algebra question

PLease see attached. This is an algebra question

Answers

The solution for the given expression is 16.

Power Rules

There are different power rules, see some them:

1. Multiplication with the same base: you should repeat the base and  add the exponents.

2. Division with the same base: you should repeat the base and  subctract the exponents.

3.Power. For this rule, you should repeat the base and multiply the exponents.

4. Zero Exponent. When you have an exponent equals to zero, the result must be 1.

First, you apply the Power Rules - Power for  \((\frac{2^2x^2y}{xy^3} )^2}\). For this rule, you should repeat the base and multiply the exponents. Thus, the result will be:\(\frac{16x^4y^2}{x^2y^6}\).

After that, you should apply the  Power Rules - Division . For this rule, you should repeat the base and  subctract the exponents. Thus, the result will be:\(\frac{16x^2}{y^4}\).

Now, you should replace the variable x by 4 and the variable y by 2. Thus, the result will be:\(\frac{16*4^2}{2^4}=\frac{16*16}{16} =16*1=16\)

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3/4-1/2 porfa es para hoy​

Answers

Answer:

1/4

Step-by-step explanation:

... aver si esto ayuda

REAL CASE SCENARIO) - A client of yours comes to you wondering about overtime. They are working regular 45 hour weeks and not receiving overtime. Without actual specific information on certain necessities, you know your client is a hourly vet tech (does not require a degree) at a local Veterinary office with 4 veterinarians and approx. 10 total staff. Explain your answer using reasonable rational assumptions about information you will need to answer your client.

Does this EE deserve overtime pay? This problem is worth 5 POINTS! A detailed answers citing specific law requirements is required.

In your answer you should address if this employee would be exempt or not (give specific reasons) and if the EE would typically be covered by FLSA (give your reasons and provide logical assumptions when needed).

Answers

The vet tech and his colleagues should be getting overtime pay because they are working more than 40 hours per week.

What is an extra hour?

An overtime is a term that refers to the extra time that a worker works in a company. Usually this time is paid in addition to her salary.

What does FLSA stand for?

FLSA stands for the Fair Labor Standards Act. This law establishes the parameters and guidelines that an employer must follow to pay their employees' salaries.

A very important aspect of this law is that it establishes exceptions for those employees who must receive overtime pay.

According to these guidelines, the veterinary technician must receive overtime pay because a weekly shift of more than 40 hours is required.

When must overtime be paid?

According to the Fair Labor Standards Act (FLSA) the employer must pay their employees overtime once they are required to work more than 40 hours per week. Once the employee works more than that time, he must start counting the hours he worked extra to collect an additional cost.

In this case, the vet tech's employer should pay him for the 5 hours of overtime he is doing. Adicionalmente,

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Rita read 1,362 words in 6 minutes. Joy read 1,456 words in 7 minutes. Who read at the faster rate? Joy read at the faster rate because 208 words per minute < 227 words per minute. Rita read at the faster rate because 227 words per minute > 208 words per minute. Joy read at the faster rate because 208 words per minute > 227 words per minute. Both Rita and Joy read at the same rate.

Answers

The correct answer is "Rita read at the faster rate because 227 words per minute > 208 words per minute".

How do you calculate rate of something?

The rate of something is a measure of how fast or slow it changes over time or another variable. The general formula for calculating rate is:

Rate = Change in value / Time interval or Change in value / Change in another variable Rates can be expressed in different units, such as miles per hour, dollars per day, or units per minute. It's important to ensure that the units are consistent throughout the calculation to obtain accurate results. In summary, the rate of something can be calculated by dividing the change in value by the time interval or the change in another variable.

To find out who read at the faster rate, we need to calculate the rate of reading for each person. We can do this by dividing the number of words read by the time taken to read them.

Rita's reading rate = 1362/6 = 227 words per minute

Joy's reading rate = 1456/7 = 208 words per minute

Therefore, Rita read at a faster rate than Joy, with a reading rate of 227 words per minute compared to Joy's reading rate of 208 words per minute.

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Which fractions are equivalent to 812?

Answers

Answer:

812/1 = 1624/2 = 2436/3

= 3248/4 = 4060/5 = 4872/6

= 5684/7 = 6496/8 = 7308/9

= 8120/10 = 8932/11 = 9744/12

= 10556/13 = 11368/14 = 12180/15

= 12992/16 = 13804/17 = 14616/18

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

The list tends to be much bigger.

Hope this helps!

Answer:

See below.

Step-by-step explanation:

Fractions equivalent to 8/12:

2/316/2424/3636/4840/60And on and on.

There is an infinite amount, but this is how far I can get.

The equation of the line is

The equation of the line is

Answers

Answer:

  y = -x +3

Step-by-step explanation:

You want the slope-intercept equation of the line with the same intercept as -3y = -9 +3x, and the same slope as -2x -2y = -8.

Slope-intercept form

The slope-intercept form of the equation of a line is ...

  y = mx +b . . . . . where m is the slope, and b is the y-intercept

For the given equations, we can put them in this form to find the desired parameters.

  -3y = -9 +3x

  y = -x +3 . . . . . . . . . . divide both sides by -3

We observe that the y-intercept is +3, which we will need for our answer.

The slope-intercept form of the second equation is ...

  -2x -2y = -8

  x + y = 4 . . . . . . . . . . divide by -2

  y = -x +4 . . . . . . . . . . subtract x

We observe that the slope (coefficient of x) is -1, which we will need for our answer.

Desired equation

We want the equation of the line with slope -1 and y-intercept 3. It is ...

  y = -x +3 . . . . . . . . . . same as the equation of the first line

__

Additional comment

The slope-intercept equation (green) is plotted using dots, so that you can see it is coincident with the line described by the first equation (red). Parallel lines have the same slope, so our desired line must be parallel to the blue line. (It is.)

The equation of the line is

Thereare 3 roses and 8 daisies in a vase, what is the ratio to daisies to all the flowers in the vase

Answers

Answer:

8:11

Step-by-step explanation:

There are 8 daisies and it is the ratio to flowers, not roses so there are 11 flowers, 8+3=11 so 8:11

This question has two parts. First, answer Part 1. Then, answer Part 2.
Part 1

Which expression does NOT produce the same value for p = 2 as the expression below?

2(p – 1)
A.
p + 2 – p
B.
p – 2 + p
C.
2 + p – 2
D.
2p – 1
Part 2

Which expression is equivalent to 2(p – 1)?
A.
p + 2 – p
B.
p – 2 + p
C.
2 + p – 2
D.
2p – 1

Answers

The answer will be a

find the equation of the line through point (4,-7) and parallel to y = -2/3x + 3/2.

Answers

Answer:

y = -2/3 x - 13/3

Step-by-step explanation:

y = -2/3 x + 3/2

y = mx + b

m = -2/3

The slope of the given line is -2/3. Parallel lines have equal slopes, so our line also has slope -2/3.

m = -2/3

y = mx + b

y = -2/3 x + b

Substitute the given point for x and y and solve for b.

-7 = -2/3 (4) + b

-21/3 = -8/3 + b

b = -13/3

Answer: y = -2/3 x - 13/3

Tasha used the pattern in the table to find the value of 4 Superscript negative 4.

Powers of 4
Value
4 squared
16
4 Superscript 1
4
4 Superscript 0
1
4 Superscript negative 1
One-fourth
4 Superscript negative 2
StartFraction 1 Over 16 EndFraction

She used these steps.

Step 1 Find a pattern in the table.
The pattern is to divide the previous value by 4 when the exponent decreases by 1.
Step 2 Find the value of 4 Superscript negative 3.
4 Superscript negative 3 = StartFraction 1 Over 16 EndFraction divided by 4 = StartFraction 1 Over 16 EndFraction times one-fourth = StartFraction 1 Over 64 EndFraction
Step 3 Find the value of 4 Superscript negative 4.
4 Superscript negative 4 = StartFraction 1 Over 64 EndFraction divided by 4 = StartFraction 1 Over 64 EndFraction times one-fourth = StartFraction 1 Over 256 EndFraction
Step 4 Rewrite the value for 4 Superscript negative 4.
StartFraction 1 Over 256 EndFraction = negative StartFraction 1 Over 4 Superscript negative 4 EndFraction

Answers

The value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.

In the given table, Tasha observed a pattern in the powers of 4. When the exponent decreases by 1, the previous value is divided by 4. Using this pattern, she determined the values for 4 squared, 4 Superscript 1, 4 Superscript 0, 4 Superscript negative 1, and 4 Superscript negative 2.

To find the value of 4 Superscript negative 3, she divided the previous value (StartFraction 1 Over 16 EndFraction) by 4, resulting in StartFraction 1 Over 64 EndFraction.

Similarly, for 4 Superscript negative 4, she divided the previous value (StartFraction 1 Over 64 EndFraction) by 4, yielding StartFraction 1 Over 256 EndFraction.

Finally, to rewrite the value for 4 Superscript negative 4, she expressed it as negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.

Therefore, the value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction, which simplifies to StartFraction 1 Over 256 EndFraction

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Which expression is equivalent to x + y + x + y + 3(y + 5)?

Answers

Answer:

2x + 5y + 15

Step-by-step explanation:

Step 1: Combine like terms

2x + 2y + 3(y + 5)

Step 2: Distribute

2x + 2y + 3y + 15

Step 3: Combine like terms

2x + 5y + 15

Answer: 2x + 5y + 15

Step-by-step explanation:

Which expression is equivalent to x + y + x + y + 3(y + 5)?

Find the value of (f o g)' at the given value.

Find the value of (f o g)' at the given value.

Answers

To find the value of (f o g)' at a given value, you first need to understand the concept of composite functions and the chain rule of differentiation. Let's break it down step by step.

To find the value of (f o g)' at a given value, you need to evaluate g(x) and f(x), find their derivatives, and use the chain rule to find the derivative of (f o g) at the given value. It is important to understand the concepts of composite functions and the chain rule to be able to solve problems involving these concepts.

What are composite functions? Composite functions are functions that are formed by composing two or more functions. The notation used to denote composite functions is (f o g)(x), which means that the output of function g is used as the input for function f. In other words, we first evaluate g(x), and then use the result as the input for f(x).

What is the chain rule of differentiation? The chain rule of differentiation is a method used to find the derivative of composite functions. It states that if a function is composed of two or more functions, then its derivative can be found by taking the derivative of the outer function and multiplying it by the derivative of the inner function.

To find the value of (f o g)' at a given value, we need to follow these steps:1. Find g(x) and f(x)2. Find g'(x) and f'(x)3. Evaluate g(x) at the given value4. Use the chain rule to find (f o g)' at the given value

step 1: Find g(x) and f(x)Let's say that we have two functions: g(x) = x^2 + 3x + 1 and f(x) = sqrt(x). To find (f o g)(x), we first need to evaluate g(x) and then use the result as the input for f(x). Therefore, (f o g)(x) = f(g(x)) = sqrt(x^2 + 3x + 1)

Step 2: Find g'(x) and f'(x)To find g'(x), we need to take the derivative of g(x) using the power rule and the sum rule. Therefore, g'(x) = 2x + 3To find f'(x), we need to take the derivative of f(x) using the power rule and the chain rule. Therefore, f'(x) = 1/2(x)^(-1/2)

Step 3: Evaluate g(x) at the given valueSuppose we want to find (f o g)' at x = 2. To do this, we need to first evaluate g(x) at x = 2. Therefore, g(2) = 2^2 + 3(2) + 1 = 11

Step 4: Use the chain rule to find (f o g)' at the given value now we can use the chain rule to find (f o g)' at x = 2. Therefore, (f o g)'(2) = f'(g(2)) * g'(2) = 1/2(11)^(-1/2) * (2)(3) = 3/sqrt(11)

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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.

Answers

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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Isaac goes to the Saturday market with $42 cash. He buys two posters that each cost SP. He leaves the market with $21 cash. What equation
represents this situation?
• 42-p-p=21
• 42/p=21
• 42-p+p=21
•21+42=2•P

Answers

The first equation that represents 42 - p -p= 21 is correct.

What is equation and there uses?

An equation is a mathematical statement that express the equality between two or more number of expressions. An equal sign is mandatory for equation. An equation is used to determine unknown values in terms of variables. In our everyday life equation is used by many professionals necessarily. By using equation many complicated problems can be easily solved within a limited time.

What equation represent the statements given in question?

Isaac has $42 cash in hand when arrived Saturday market.

He buys two posters that each cost selling price or SP.

when he leaved the market had $21 cash in hand.

assume, each poster has a price = p

The situation is represented by the following.

initial amount - cost for two posters = final amount

42 - p - p = 21

hence, the first equation that given in the question is correct.

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pleaae tell fast plzzzzzzzzzzz​

pleaae tell fast plzzzzzzzzzzz

Answers

Answer:

k=4/3

Step-by-step explanation:

5(2k-1)-k=7

10k-5-k=7

9k=12

k=4/3

Geraint has 2p and 50p coins in the ratio 20 : 3

Write the ratio of the value of the 2p coins to the value of 50p coins in its
simplest form.

Answers

the answer is 1p:25p :)

What does it mean to simplify???

Answers

(In math) to combine like terms together without solving
Simplify means to make something simpler.

Example:
2/4 = 1/2; Fraction was simplified to make it simpler

4x = 8
x = 2

The equation was simplified to simplest terms of 1x.

A baker fulfilled an
order for 175 cupcakes
for a part. The
customer said that
92% of the cupcakes
were eaten. How many
cupcakes were eaten at
the party?

Answers

Answer:

161

Step-by-step explanation:

175 x 0.92 = 161

Answer:

161 cupcakes were eaten

Step-by-step explanation:

92÷100×100

Only 14 were left

I hope this helps

ABCD is a rectangle. Its diagonals are AC and BD. If AC = 12cm, then BD = _______cm

Answers

Answer:

\(BD = 12\ cm\)

Step-by-step explanation:

Given

Shape: Rectangle

Diagonals: AC and BD

\(AC = 12\ cm\)

Required

Determine BD

From the question, we understand that the shape is a rectangle and its diagonals are AC and BD

Every rectangle has 2 diagonals, both of which are equal.

This implies that:

\(BD = AC\)

Recall that:

\(AC = 12\ cm\)

Hence,

\(BD = 12\ cm\)

If qs bisects pqt, sqt= (8x-25), pqt-(9x+34) and sqr= 112 find each measure​

If qs bisects pqt, sqt= (8x-25), pqt-(9x+34) and sqr= 112 find each measure

Answers

As it is written this question isn't very clear, and I'm not positive that the entire thing can be answered. I don't know where point R is. Is there a picture that goes with this problem? If so, maybe that would make it more clear. What I can do is show you how to solve for x. While I don't believe this is the final answer, I believe it is a step toward the right answer. We know what ray QS bisects angle PQT. If you draw out angle PQT and ray QS you can see that angle PQS is congruent to angle SQT. Because of the definition of angle bisector. This also means that angle SQT is half of PQT. Because of this we know that we can set the measure of PQT equal to 2 times the measure of SQT. So we can set up and solve the following equation as such:

2(8x-25) = 9x +34

16x - 50 = 9x +34

7x -50 = 34

7x = 84

x = 12

Again I this doesn't seem to be your final answer. To find the answer the measures of each angle you're going to want to plug 12 in for x for one of the angles. So I'll do it for angle SQT.

8(12) - 25

96 -25

71

So the measure of angle SQT should be 71. Therefore since QS bisects PQR, the measure of angle PQS should also be 71. The measure of PQT should be double that which makes it 142. I'm not positive that this is all the problem is looking for, but I think that's most of it. Hope this helps!

PLEASE ANSWER
Rectangle ABCD is shown below with a line EF drawn through its center. If the rectangle is dilated using a scale factor of 2 and a line is drawn through the center of the new dilated figure, what relationship will that line have with line EF in the drawing below?

PLEASE ANSWERRectangle ABCD is shown below with a line EF drawn through its center. If the rectangle

Answers

Answer:

The new line will be perpendicular to line EF because both the lines are drawn through the center of the figures (rectangle ABCD and rectangle A'B'C'D') causing both of the lines to intersect each other. Rectangle ABCD will get bigger causing to form rectangle A'B'C'D' because it is dilated with a scale factor of 2. Rectangle A'B'C'D' will contain the new line and line EF.

Hope this helps and stay safe, happy, and healthy, thank you :) !!

Help I would appreciate it

Help I would appreciate it

Answers

Answer:

it is option C

hope it helps

97 And 83

A car is traveling at 50 miles per hour. What is its speed in feet per second? (Round your answer one decimal place.)
feet per second

Answers

50 miles per hour

264,000 feet in 60 minutes

4,400 feet per minute

73.33... feet per second

73.3 feet per second (rounded to the nearest tenth)!

Answer:

73.3 feet per second is the answer

21
х
15
X
(Round to the nearest tenth)

2115X(Round to the nearest tenth)

Answers

Answer:

that would be 6

x = 6

Step-by-step explanation:

A pair of shoes usually sells for $69. If the shoes are 40% off, and sales tax is 7%, what is the total price of the shoes, including tax?

Answers

69 * 0.40 = 27.6

69 - 27.6 = 41.4

41.4 + 41.4(0.07) = $44.30

If the triangle on the grid below is translated by using the rule (x, y) right-arrow (x + 5, y minus 2), what will be the coordinates of B prime?

If the triangle on the grid below is translated by using the rule (x, y) right-arrow (x + 5, y minus

Answers

Answer:

Option (2)

Step-by-step explanation:

If a point having coordinates (x, y) is translated by 'h' units right and 'k' units down,

New coordinates of the point will be,

(x, y) → [(x + h), (y - k)]

Coordinates of the vertices of the given triangle ABC are,

A(-1, 0), B(-5, 0) and C(-1, 2)

If this triangle is shifted 5 units right and 2 units down then the coordinates of point B will be,

B(-5, 0) → B'[(-5 + 5), (0 -2)]

             → B'(0, -2)

Therefore, coordinates of vertex B' will be (0, -2).

Option (2) will be the answer.

Answer:

(0,-2) is Correct

Have a Blessed day!

what are the features of the function g if g(x)= f(x+4) +8

Answers

The domain, range, x-intercept, or y-intercept of g(x) = f(x + 4) + 8. The features of g depend on the corresponding features of f.

Given the function g(x) = f(x + 4) + 8, let's examine its features:

Domain:

The domain of the function g will be the same as the domain of the function f, which depends on the restrictions or constraints of f.  However, it is important to note that shifting the input by 4 units (x + 4) does not inherently change the domain unless there are specific restrictions imposed by f.

Range:

Similar to the domain, the range of the function g will depend on the range of the function f.

x-intercept:

The x-intercept of a function is the point where the graph intersects the x-axis, meaning the y-coordinate is zero (y = 0). To find the x-intercept of g(x), we set g(x) = 0 and solve for x.

0 = f(x + 4) + 8

By subtracting 8 from both sides:

-8 = f(x + 4)

Since the exact value of x that makes f(x + 4) equal to -8. The x-intercept will depend on the behavior of f.

y-intercept:

The y-intercept of a function is the point where the graph intersects the y-axis, meaning the x-coordinate is zero (x = 0). To find the y-intercept of g(x), we substitute x = 0 into the function:

g(0) = f(0 + 4) + 8

g(0) = f(4) + 8

Again, the specific value of f(4) will depend on the behavior of the function f.

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Use the histogram to answer the following questions.
Frequency
The frequency of the class 90-93 is
The frequency of the class 94-97 is
This means that a total of
5.5
5
4.5
Your answers should be exact numerical values.
The frequency of the class 86-89 is
86
94
90
Duration of Dormancy (minutes)
dormancy periods were recorded.

Answers

The frequency of the class 86-89 is 1/3.The frequency of the class 90-93 is 2/5.The frequency of the class 94-97 is 4/15.This means that a total of 15 dormancy periods were recorded.

How to calculate a probability?

The parameters that are needed to calculate a probability are listed as follows:

Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.

The total number of periods is given as follows:

5 + 6 + 4 = 15.

The frequency of each class is given as follows:

86 - 89: 5/15 = 1/3.90 - 93: 6/15 = 2/5.94 - 97: 4/15.

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Use the histogram to answer the following questions.FrequencyThe frequency of the class 90-93 isThe frequency
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