The solution for the given system of equation is (x, y, z) is = (0 , (3-4t) , t) by Gaussian elimination method.
In the question ,it is given that the system of equations are ,
3x + 3y + 6z = 9
x + y + 2z = 3
2x + 5y + 10z = 15
-x + 2y + 4z = 6
we have to solve the equations for x, y , z.
writing the given equations in augmented matrix form , we get
\(\left[\begin{array}{ccc}3&3&6\\1&1&2\\2&5&10\\-1&2&4\\\end{array}\right]\) = \(\left[\begin{array}{ccc}9\\3\\15\\6\\\end{array}\right]\)
Applying R₁ → 1/3R₁
\(\left[\begin{array}{ccc}1&1&2\\1&1&2\\2&5&10\\-1&2&4\\\end{array}\right]\) =\(\left[\begin{array}{ccc}3\\3\\15\\6\\\end{array}\right]\)
Apply R₂ → R₂ - R₁
\(\left[\begin{array}{ccc}1&1&2\\0&0&0\\2&5&10\\-1&2&4\\\end{array}\right]\)=\(\left[\begin{array}{ccc}3\\0\\15\\6\\\end{array}\right]\)
After applying more row operations in the above matrix ,to make the lower triangle matrix 0 ,we get ,
\(\left[\begin{array}{ccc}1&0&0\\0&1&2\\0&0&0\\0&0&0\\\end{array}\right]\) =\(\left[\begin{array}{ccc}0\\3\\0\\0\\\end{array}\right]\)
The above result can be expressed as x = 0 and y + 2z = 3 .
So , the system of equations have infinite solutions .
So , the solution x, y, and z expressed in terms of the parameter t is
(0 , (3-2t) , t) .
Therefore , the solution is (x, y, z) is = (0 , (3-2t) , t) .
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This question is incomplete. The complete question is
Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, y, and z in terms of the parameter t.)
3x + 3y + 6z = 9
x + y + 2z = 3
2x + 5y + 10z = 15
−x + 2y + 4z = 6
If function f has zeros at -3 and 4, which graph could represent function f?
1. A resident lot has the shape of a parallelogram. Its base measures 20 meters. The distance between the
parallel sides is 8 meters. What is the area of the lot?
Answer:
160 m²
Step-by-step explanation:
Given :
A parallelogram shaped lot :
Base of lot = 20 m
Distance between parallel sides, = height of lot = 8 m
The area of the lot can be obtained using the area formula of a parallelogram :
Area = base * height
Area = 20 m * 8 m
Area = 160 m²
Can someone please help !
Answer:
The x intercept is 8; the y intercept is 4.
Step-by-step explanation:
To find the x-intercept, you always use a value of y = 0 because if y doesn't equal to 0, then the point will not be on the x-axis, and thus it would not be the x intercept.
So, if we plug in y = 0, we get:
2x + 4(0) = 16
Since anything multiplied by 0 is 0, we have:
2x = 16
x = 8
Therefore, the x intercept is 8.
To find the y intercept, we have to pretend that x = 0, so that the point will fall on the y axis.
Thus, we get:
2*(0) + 4y = 16
Since anything multipled by 0 is just 0, we have:
4y = 16
y = 4
Therefore, the y intercept is 4.
help please
A. 12
B. 6
C. 2
D. 15
Answer:
6
Step-by-step explanation:
2x + 3 = 15
- 3 -3
__________
2x = 12
_______
2 2
That cancels out 2x so x = 6
Answer:
The answer to this equation would be B. 6!
Step-by-step explanation:
2x + 3 = 15 Subtract 3 from left and right side. Variable needs to be left alone. 15 will turn into 12. 2x = 12 x= 6 since 2 x 6 = 12 or divide 12 by 2 and get 6Check Answer:
2(6) + 3 = 15
2x6 =12
12 + 3 =15
Someone please help I’ll give points
Answer:
Step-by-step explanation:
40 or less for males 35 or less for females
Which of the following would be true regarding the following exponential expression?
3m 7/9
A - The exponent of 3 is 7/9.
B - If written in radical form, 9 would be the exponent
inside the radicand.
C - The rational exponent is 9/7.
Report an Error
question 4 of 5
D - If written in radical form, 7 would be the index.
E - If written in radical form, 9 would be the index.
Answer:
A - The exponent of 3 is 7/9.
Step-by-step explanation:
The expression 3^(7/9) can be read as "3 to the power of 7/9".
This means that the number 3 is being multiplied by itself 7/9 times.
For example
3^(2/3) can be written as cube root of 3, cube root of 3 is equal to 3^(1/3) .
When the exponent of an expression is a fraction, it can be written in radical form, with the denominator of the fraction as the index of the radical. However, it's not true in this case as the index is not 9 but 7.
So, the correct answer is A - The exponent of 3 is 7/9.
ROUND OF THE UNDERLINED DIGIT IN EACH DICEMAL NUMBER
1. 25.5678
2.0.8974
3.12.9542
Answer:
I think 25.5678
it's the correct answer
Step-by-step explanation:
gamsahamnida
Which is the equation for the line that passes through (5,-3) and has a slope of 6?
So ummm. I kind of got this wrong, and I had to delete my answer, I swear, I am SOOOO sorry. If there is a way I can give your points back I will do so.
So um yeah, just ignore this.
x² + 8x+16=0
Solve for x.
Answer:
factor it :
(x+4)(x+4)=0
x+4=0
x= -4
. Question 3 Terrance made a list of his expenses. He is creating a check off matrix to organize when his bills are due. A check off matrix is a table without dollar amounts. You can use a matrix to indicate what time of the year an expense will occur Help Terrance complete his check off matrix by placing an X in the correct cells of the table according to his list of expenses, mortgage payment monthly • Utilities, monthly • Insurance quarterly • Internet monthly cell phone monthly . car loan: semiannually lawn care: monthly, April-September • food: monthly day care every other month beginning with February gym membership: annually. July . в тухх, m. AL 10pt Oct Dec Nov Feb Mar Sep Jul Jun Aug May Jan x Expense mortgage payment X X X x x X x insurance y internet cellphone car loan 1 x Iawn care X x X x food X day Care rym membership
=====================================================
Explanation:
The first two rows are already done. They have X's for every month to indicate a monthly payment regularly throughout the year without any extra conditions/requirements.
The third row will have exactly 4 copies of X in it. Two of them are already placed for January and April. The other two payments are in July and October. Notice the months are spaced 3 apart and how 12/4 = 3.
The fourth row will have X's across every cell in the same way the first row does since the internet bill is monthly. The same applies to the cell phone bill and food rows.
Something like the car loan will only have 2 copies of X in that row. Semiannual means twice a year, aka every 6 months. One copy of X is already placed for us in this row. This is in January (month 1). Six months later in month 1+6 = 7 (July) is when the next car loan payment occurs.
Lawn care will have X's only for the months of April through September; any other month won't have an X.
Day care will have X's for February, April, June, August, October, December. We start with February and alternate each month to fill out the rest of the year. This is due to the phrasing "every other month".
The gym membership will have one X for July only, since it's an annual payment.
Two tangents are drawn to a circle from an external point. If the measure of the major arc is 286º, what is the measure, in degrees, of the angle formed by the two tangents?
The measure for the angle between the intersecting tangents drawn to a circle from an external point is equal to 106°
What are angles between intersecting tangentsThe angle between two tangent lines which intersect at a point is 180 degrees minus the measure of the arc between the two points of tangency.
minor arc measure = 360° - 286°
minor arc measure = 74°
angle between the tangents = 180 - 74°
angle between the tangents = 106°
Therefore, the measure for the angle between the intersecting tangents drawn to a circle from an external point is equal to 106°
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Select all the correct answers. What are the solutions of this equation? x2-x-56=0
The roots of the quadratic equation x² - x - 56 = 0 is x = -7 or x = 8
What is Quadratic Equation?A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.
The roots of the quadratic equations are
x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )
where ( b² - 4ac ) is the discriminant
when ( b² - 4ac ) is positive, we get two real solutions
when discriminant is zero we get just one real solution (both answers are the same)
when discriminant is negative we get a pair of complex solutions
Given data ,
Let the equation be represented as A
Now , the value of A is
x² - x - 56 = 0 be equation (1)
On simplifying the equation , we get
x² - 8x + 7x - 56 = 0
Taking the common terms in the equation , we get
x ( x - 8 ) + 7 ( x - 8 ) = 0
Now , on factorizing the equation , we get
( x + 7 ) ( x - 8 ) = 0
We have two factors which can solve the equation ,
when ( x + 7 ) = 0
Subtracting 7 on both sides of the equation , we get
x = -7
And , when ( x - 8 ) = 0
Adding 8 on both sides of the equation , we get
x = 8
Therefore , the roots of the equation are x = -7 and x = 8
Hence , the quadratic equation is solved
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Answer:
x = 8
x = -7
Step-by-step explanation:
To find the solutions of the quadratic equation x^2 - x - 56 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 1, b = -1, and c = -56. Plug these values into the formula and calculate the discriminant (the value inside the square root):
Discriminant (D) = b^2 - 4ac = (-1)^2 - 4(1)(-56) = 1 + 224 = 225
Now, calculate the two possible solutions:
x1 = (-(-1) + √225) / (2(1)) = (1 + 15) / 2 = 16 / 2 = 8
x2 = (-(-1) - √225) / (2(1)) = (1 - 15) / 2 = -14 / 2 = -7
So, the correct solutions to the equation x^2 - x - 56 = 0 are:
x = 8 (x = 0 is not a solution)
x = -7
Find the angle between u=
= (8,- 2) and v= (9,3). Round to the nearest tenth of a degree.
A 32.5
B 6.3
C 42.5
D 16.3
Answer:
the angle between u=(8, -2) and v=(9,3) is 32.5°
Step-by-step explanation:
u=(8,-2)=(u1,u2)→u1=8, u2=-2
v=(9,3)=(v1,v2)→v1=9, v2=3
We can find the angle between two vectors using the formula of dot product:
u . v =║u║║v║cos α (1)
And the dot product is:
u . v = u1 v1 + u2 v2
u . v = (8)(9)+(-2)(3)
u . v = 72-6
u . v = 66
║u║=√(u1²+u2²)
║u║=√((8)²+(-2)²)
║u║=√(64+4)
║u║=√(68)
║u║=√((4)(17))
║u║=√(4)√(17)
║u║=2√(17)
║v║=√(v1²+v2²)
║v║=√((9)²+(3)²)
║v║=√(81+9)
║v║=√(90)
║v║=√((9)(10))
║v║=√(9)√(10)
║v║=3√(10)
Replacing the known values in the formula of dot product (1):
u . v =║u║║v║cos α
66 = 2√(17) 3√(10) cos α
Multiplying:
66 = 6√((17)(10)) cos α
66 = 6√(170) cos α
Solving first for cos α: Dividing both sides of the equation by 6√(170):
Simplifying: Dividing the numerator and denominator on the left side of the equation by 6:
(66/6)/(6√170/6)=cosα→11/√170=cosα→cosα=11/√170
cosα=11/13.03840481→cosα=0.84366149
]
The principal randomly selected six students to take an aptitude test. Their scores were: 76.5 85.2 77.9 83.6 71.9 88.6 Determine a 90% confidence interval for the mean score for all students.
Answer:
90% Confidence Interval = [75.50, 85.74]
Step-by-step explanation:
The principal randomly selected six students to take an aptitude test. Their scores were: 76.5 85.2 77.9 83.6 71.9 88.6 Determine a 90% confidence interval for the mean score for all students.
Step 1
We find the Mean and Standard deviation
Mean = Sum of terms/Number of terms
Mean = 76.5 + 85.2 + 77.9 + 83.6 + 71.9 + 88.6/6
Mean = 483.7/6
Mean = 80.61666667
Approximately = 80.62
Stand Deviation =
√(x - mean)²/n - 1
= √193.9483333/6 - 1
= √38.78966667
= 6.228135087
Approximately = 6.23
Step 2
If you look at the question, our number of samples is 6. This is a small sample size and it is less than 30 hence, the formula for Confidence Interval that we would be using is
Confidence Interval = Mean ± t × Standard deviation/√n
Where t = test score of the 90% confidence interval
Degrees of freedom = n - 1
= 6 - 1 = 5
t score for a 90% confidence interval = 2.015
Hence, Confidence Interval =
80.62 ± 2.015 × 6.23/√6
80.62 ± 2.015 × 2.5433868496
80.62 ± 5.1249245019
Confidence interval
= 80.62 - 5.1249245019
= 75.495075498
≈ 75.50
= 80.62 + 5.1249245019
= 85.744924502
≈ 85.74
90% Confidence Interval = [75.50, 85.74]
A tutor charges $12 for each hour she works and
charges a one time material cost of $35 Write an
equation that relates the number of hours h the tutor
worked at a job for which she charged $71?
Answer:
71 = 35 + 12h
Step-by-step explanation:
71 = 35 + 12h
-35
36 = 12h
/12
3 = h
She worked 3 hours to charge that much
In triangle ABC, AB = 6, BC = 8, and angle ABC = 90 degrees. Find the area of triangle ABC.
Answer:
24
Step-by-step explanation:
The formula for area of any triangle is (length * width) * 1/2. This makes the angle of 90 degrees irrelevant.
6 x 8 = 48
48 / 2 = 24
You save 30% of your income and use 10% of the reminder for internet purchase. What percentage of your income is left for other purposes?
Let's assume that your income is 100 units for simplicity.
You save 30%, which is 30 units, leaving you with 70 units.
You then use 10% of the reminder (70 units), which is 7 units, for internet purchases.
So the total amount you have spent on saving and internet purchases is 30 + 7 = 37 units.
The remaining amount for other purposes is 100 - 37 = 63 units.
Therefore, the percentage of your income that is left for other purposes is:
63 / 100 x 100% = 63%.
So, 63% of your income is left for other purposes after saving 30% and spending 10% of the reminder on internet purchases.
Please look at the graphs in the photo. Thank you!
(a). The graph of y = -f(x) is shown in the image below.
(b). The graph of y = g(-x) is shown in the image below.
How to draw the graph of the transformed functions?By reflecting the parent absolute value function g(x) = |x + 2| - 4 over the x-axis, the transformed absolute value function can be written as follows;
y = -f(x)
y = -|x + 2| - 4
Part b.
In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):
y - y₁ = m(x - x₁)
Where:
x and y represent the data points.m represent the slope.First of all, we would determine the slope of this line;
Slope (m) = rise/run
Slope (m) = -2/4
Slope (m) = -1/2
At data point (0, 5) and a slope of -1/2, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 5 = -1/2(x - 0)
g(x) = -x/2 + 5, -4 ≤ x ≤ 4.
y = g(-x)
y = x/2 + 5, -4 ≤ x ≤ 4.
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3) Mya ran 5/8 mile, Hank 4/7 ran mile, and Tommy ran7/11 mile. Who ran the farthest? And please tell me how you solved this
Answer:
Tommy
Step-by-step explanation:
tommy=63%
mya=62%
hank=57%
Answer:
Tommy, 7/11 miles
Step-by-step explanation:
5/8 equals .625, 4/7 equals .571, 7/11 equals .636. Therefore, Mya ran the farthest
Graph the equation below by plotting the
y-intercept and a second point on the
line. When you click Done, your line will
appear
Answer:
Plot the y-intercept at (0, 2). Plot your second point at (-1, -1).
Step-by-step explanation:
I attached an image of what the finished graph should look like when you press done. *rotate the image so the grey is on the bottom*
Question 19 of 23What is the location of the point on the number line that is of the way fromA = -6 to B=9?O A. 1OB. -3OC. 0O D. -1SUBMIT
So the point we are looking for is located x units at the left of A. This distance x is equivalent to 2/5 of the total distance between A and B. If this distance is d then x meets the following:
\(x=\frac{2}{5}d\)The distance between A and B can be found by substracting their values:
\(d=B-A=9-(-6)=9+6=15\)Then x is equal to:
\(x=\frac{2}{5}\cdot15=\frac{30}{5}=6\)So the point we are looking for is 6 units at the right of A then its position in the number line is:
\(A+6=-6+6=0\)AnswerThen the answer is option C.
In a study of 30 high school students, researchers found a high correlation, 0.93, between amount of exercise and weight lost. Which of the following statements is TRUE? The researchers proved that exercise causes weight loss, but only for high school students. There is a strong positive linear association between weight loss and exercise, but the researchers have not proven causation. The researchers proved that exercise causes weight loss. 93% of the high school students studied lost weight.
Answer:
Option A is true
The researchers proved that exercise causes weight loss only for high school students.
Step-by-step explanation:
We are told that the researchers found a high correlation, 0.93, between amount of exercise and weight lost.
Now, looking at each of the options;
- A is True because due to the high correlation, the research proves that exercise causes weight loss but only for high school students.
- B is not true because we are told the correlation is very high at 0.93. Thus, it is untrue that there is no proven causation.
-C is not true because there's no where that the researchers have completely proved that exercise causes weight loss generally. It is only peculiar to the high school students studied.
-D is not true because the 93% is just a correlation and not a percentage of those who lost weight
Answer:
There is a strong positive linear association between weight loss and exercise, but the researchers have not proven causation
Step-by-step explanation:
Recall that correlation measures the strength and direction of linear association. So r= 0.93 indicates a strong positive linear association. Recall also, that correlation doesn't imply causation. Causation is a direct change in one variable causing a change in some outcome.
Correct answer please
Answer:
50.75
Step-by-step explanation:
We have:
\(E[g(x)] = \int\limits^{\infty}_{-\infty} {g(x)f(x)} \, dx \\\\= \int\limits^{1}_{-\infty} {g(x)(0)} \, dx+\int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx+\int\limits^{\infty}_{6} {g(x)(0)} \, dx\\\\= \int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x+3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x)\frac{2}{x} } \, dx + \int\limits^{6}_{1} {(3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {8} \, dx + \int\limits^{6}_{1} {\frac{6}{x} } \, dx\\\\\)
\(=8\int\limits^{6}_{1} \, dx + 6\int\limits^{6}_{1} {\frac{1}{x} } \, dx\\\\= 8[x]^{^6}_{_1} + 6 [ln(x)]^{^6}_{_1}\\\\= 8[6-1] + 6[ln(6) - ln(1)]\\\\= 8(5) + 6(ln(6))\\\\= 40 + 10.75\\\\= 50.74\)
What are multiplication facts that equal 9
Answer:
3*3 4.5*2 9*1
Step-by-step explanation:
Answer:
1×9,2×4.5,3×3,9×1
Step-by-step explanation:
I hope this helps in any way.
Have a great day!
Pleas I need help ASAP
NOTE: sorry if im wrong
ANSWER: C.
Answer:
a)
c)
d)
Step-by-step explanation:
a) true : from inspection of the graph, when h=0, g=50, so g(0)=50
b) false : we are told that h is hours after 8:00am. Therefore, when h=12, this would be 8:00pm
c) true : from inspection of the graph, the maximum temperature occurs when h=7. We are told that h is hours after 8:00am, so when h=7 this would be 15:00 = 3.00pm
d) true : from inspection of the graph, we can see that when h=11, g≈62 and when h=8, g≈74. Therefore g(11) < g(8)
e) false : at 8.00am, h=0 and g=50. At 1.00pm, h=5 and g≈71. 71-50=21. 21≠10.
4. Make a table and graph the function. (1 point)
y = 4x + 2
Use the following table to find the probability that a randomly chosen member of the Student Government Board is a graduate student or lives in on-campus housing. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.
Students on the Student Government Board
On-Campus Housing Off-Campus Housing
Freshman 2 2
Sophomore 2 4
Junior 0 3
Senior 4 2
Graduate Student 2 0
The probability that a randomly chosen member of the Student Government Board is a graduate student or lives in on-campus housing is 8/25 or 0.32 (rounded to the nearest millionth).
1. Calculate the total number of students on the Student Government Board by summing up the numbers in the table:
Total Students = 2 + 2 + 2 + 4 + 0 + 3 + 4 + 2 = 19
2. Calculate the total number of graduate students on the Student Government Board:
Total Graduate Students = 2 + 0 = 2
3. Calculate the total number of students living in on-campus housing:
Total On-Campus Housing = 2 + 2 + 0 + 4 + 2 = 10
4. Calculate the probability of selecting a graduate student from the Student Government Board by dividing the total number of graduate students by the total number of students:
Probability of Graduate Student = Total Graduate Students / Total Students = 2 / 19
5. Calculate the probability of selecting a student living in on-campus housing by dividing the total number of students in on-campus housing by the total number of students:
Probability of On-Campus Housing = Total On-Campus Housing / Total Students = 10 / 19
6. Calculate the probability that a randomly chosen member of the Student Government Board is a graduate student or lives in on-campus housing by summing up the probabilities from steps 4 and 5:
Probability = Probability of Graduate Student + Probability of On-Campus Housing = 2 / 19 + 10 / 19
7. Simplify the fraction if necessary. In this case, the fraction cannot be simplified further, so the final probability is 2 / 19 + 10 / 19 = 12 / 19.
8. Convert the fraction to a decimal by dividing the numerator by the denominator: 12 / 19 ≈ 0.631578947, which rounds to 0.632 (rounded to the nearest thousandth).
9. Finally, express the probability as a fraction in lowest terms: 12 / 19 is already in lowest terms.
Therefore, the probability that a randomly chosen member of the Student Government Board is a graduate student or lives in on-campus housing is 12/19 or approximately 0.632 (rounded to the nearest thousandth).
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what is the solution to the equation below? sqrt 2-3x / sqrt 4x =2
The solution to the equation sqrt 2-3x / sqrt 4x = 2 is x = -2/3.
To solve the equation, we must first clear the denominators and simplify the equation. We can do this by multiplying both sides by sqrt(4x) and then squaring both sides. This gives us:
sqrt 2-3x = 4sqrt x
2 - 6x + 9x² = 16x
9x² - 22x + 2 = 0
Using the quadratic formula, we can find that x = (-b ± sqrt(b² - 4ac)) / 2a. Plugging in a = 9, b = -22, and c = 2, we get:
x = (-(-22) ± sqrt((-22)² - 4(9)(2))) / 2(9)
x = (22 ± sqrt(352)) / 18
x = (22 ± 4sqrt22) / 18
Simplifying this expression, we get:
x = (11 ± 2sqrt22) / 9
Therefore, the solution to the equation is x = -2/3.
To solve the equation sqrt 2-3x / sqrt 4x = 2, we must clear the denominators and simplify the equation. This involves multiplying both sides by sqrt(4x) and then squaring both sides.
After simplifying, we end up with a quadratic equation. Using the quadratic formula, we can find that the solutions are x = (11 ± 2sqrt22) / 9.
However, we must check that these solutions do not result in a division by zero, as the original equation involves square roots. It turns out that the only valid solution is x = -2/3.
Therefore, this is the solution to the equation.
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Aris and Josiah are reading a 50-page book for their ELA class. Aris wants to know what page Josiah is reading. Josiah gives her two hints: 1. The product of the two page numbers he can see is 930. 2. The page he is reading is an odd numbered page.
Answer:
31
Step-by-step explanation:
Let x and (x + 1) be the page numbers Josiah can see
Hint 1: x(x + 1) = 930
⇒ x² + x = 930
⇒ x² + x - 930 = 0
Using quadratic formula,
\(x = \frac{-b\pm\sqrt{b^2 -4ac} }{2a}\)
a = 1, b = 1 and c = -930
\(x = \frac{-1\pm\sqrt{1^2 -4(1)(-930)} }{2(1)}\\\\= \frac{-1\pm\sqrt{1 +3720} }{2}\\\\= \frac{-1\pm\sqrt{3721} }{2}\\\\= \frac{-1\pm61 }{2}\\\)
\(x = \frac{-1-61 }{2}\;\;\;\;or\;\;\;\;x= \frac{-1+61 }{2}\\\\\implies x = \frac{-62 }{2}\;\;\;\;or\;\;\;\;x= \frac{60 }{2}\\\\\implies x = -31\;\;\;\;or\;\;\;\;x= 30\)
Sice x is a page number, it cannot be negative
⇒ x = 30 and
x + 1 = 31
The two pages Josiah can see are pg.30 and pg.31
Hint 2: The page he is reading is an odd number
Out of the pages 30 and 31, 31 is an odd number
Thereofre, Josiah is reading page 31
I need help please and thank you