Solve the system of equations using substitution. 3x + 2y = 7 y = –3x + 11

Answer:cow

Step-by-step explanation:

A dice has 6 sides. Therefore, when you roll a dice the probability of getting 1,2,3,5, or 6 is

Using the vertex of the quadratic equation, it is found that his minimum height will be of 25.875 feet.

A quadratic equation is modeled by:

\(y = ax^2 + bx + c\)

The vertex is given by:

\((x_v, y_v)\)

In which:

\(x_v = -\frac{b}{2a}\)

\(y_v = -\frac{b^2 - 4ac}{4a}\)

Considering the coefficient a, we have that:

In this problem, the equation is:

h(t) = 2t² - 5t + 29.

Hence the coefficients are a = 2 > 0, b = -5, c = 29, and the minimum height in feet is given by:

\(y_v = -\frac{(-5)^2 - 4(2)(29)}{4(2)} = 25.875\)

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Ben minimum height above the ground when climbing the tree would be 25.875 feet

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

h(t) = 2t² - 5t + 29

The minimum height is at h'(t) = 0, hence:

h'(t) = 4t - 5

4t - 5 = 0

t = 5/4

h(5/4) = 2(5/4)² - 5(5/4) + 29 = 25.875 feet

Ben minimum height above the ground when climbing the tree would be 25.875 feet

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Answer:

Car M:

50.4/2 = 25.2

car M uses up 1 gallon every 25.2 miles

Car P:

Just from the graph, you can see that it uses up 1 gallon every 30 miles

The two graphs vary the /miles slightly but it is around their zones of 25.2 and 30. It varies slightly because the cars may be traveling at a fast speed or slower speed thus using up more or less fuel by the time they've reached the recorded distances on the graphs.

Answer:

Monthly deposit= $323.78

Step-by-step explanation:

Giving the following information:

Future Value (FV)= 12,000*0.7= $8,400

Number of periods (n)= 2*12= 24

We weren't provided with the interest rate, suppose an annual interest rate of 8%.

Interest rate= 0.08/12= 0.00067

Now, to calculate the monthly deposit, we need to use the following formula:

FV= {A*[(1+i)^n-1]}/i

A= monthly deposit

Isolating A:

A= (FV*i)/{[(1+i)^n]-1}

A= (8,400*0.0067) / [(1.0067^24) - 1]

A= $323.78

Answer:

\(\dfrac{3}{10}\)

Step-by-step explanation:

Length of an arc\(=\dfrac{\theta}{2\pi}X 2\pi r=\theta r\)

If the central angle of the arc is \(\dfrac{3\pi}{5}\)

Length of an arc\(=\dfrac{3\pi r}{5}\)

Therefore:

Ratio of the length of the arc to the circumference

\(=\dfrac{3\pi r}{5}:2\pi r\\=\dfrac{3\pi r}{5*2\pi r}\\=\dfrac{3}{10}\)

Therefore, the arc is \(\dfrac{3}{10}\) of the circumference is this arc.

Answer: 3 /10

Step-by-step explanation: Khan Academy

Answer:

25 girls

Step-by-step explanation:

We Know

The ratio of boys to girls is 4:5. For every 4 boys, there are 5 girls.

To get from 4 to 20, we multiply by 5.

We Take

5 x 5 = 25 girls

So, there are 25 girls in class.

Answer: 25 girls are in the class

Step-by-step explanation: You can set up the ratio 4:5 as a fraction, \(\frac{4}{5}\) to find your answer. You are given the fact that 20 boys are in the class so now you can solve 2 ways.

Option 1 - Set up the equation algebraically as \(\frac{20}{x}\), where x = number of girls and set that equal to \(\frac{4}{5}\). This way allows you to see that the fraction must have the same ratio as 4:5. You can see that 4 x 5 = 20, so the multiple factor is 5. The variable x must equal 5 x 5, so x = 25.

Option 2 - Multiply the amount of boys given to you by the reciprocal of the ratio. Instead of using \(\frac{4}{5}\), you have to use \(\frac{5}{4}\) because there are more girls than boys in the class. This allows you to finish the problem by multiplying 20 x \(\frac{5}{4}\) to get the result of \(\frac{100}{4}\), which you may know simplifies into 25.

Answer:

sinx = e/f

cosx = d/f

tanx = e/d

Step-by-step explanation:

soh cah toa

sin= opposite/hypotenuse

cos= adjacent/hypotenuse

tan= opposite/adjacent

Answer:

3 Cups of flour

Step-by-step explanation:

1 batch of cookies = 1 cup of flour

2 batch of cookies = 2 cups of flour

3 batch of cookies = 3 cup of flour

I hope i helped you :)

Answer:the answer is 1

Step-by-step explanation:

Answer:

x would equal 1/4

x = 1/4

Step by step:

1. Distribute the equation on the left 4(2x+2). That would equal 8x+8 when you multiply 4 · 2x and 4 · 2

2. Rearrange the terms for the equation on the left side 8(2-3x). It should be 8(-3x+2)

3. Now distribute the left side. 8(-3x+2) = -24x+16

4. Now subtract 8 from both sides of the equation ( 8x+8-8 ) = (-24x+16-8)

You should get 8x= -24x+8

5. Now add 24x to both sides ( 8x+24x = -24x+8+24x )

6. Combine the like terms (8x+24x = 32x = 8)

7. Divide both sides by 32. 32/32 and 8/32

And that should get you 1/4

Hope the explanation helped

Answer:

x = 0.25

Step-by-step explanation:

The first step for this problem is  to multiply (2x+2) by 4 and (2-3x) by 8:

4(2x+2) = 8x+8

8(2-3x) = 16-24x

The equation becomes: 8x+8 = 16-24x

The second step for this problem is to move the terms with x to one side of the equals sign, and to move the terms without x to the other side.

8x+8 = 16-24x

8x+24x = 16-8

The third step is to combine like terms.

8x+24x = 32x

16-8 = 8

The equation becomes 32x = 8

The final step is to divide 8 by 32 to isolate the x:

32x = 8

x = 8/32 = 1/4 = 0.25

Answer:

1.

5

x

−

2

y

=

4

; (−1, 1)

2.

3

x

−

4

y

=

10

; (2, −1)

3.

−

3

x

+

y

=

−

6

; (4, 6)

4.

−

8

x

−

y

=

24

; (−2, −3)

5.

−

x

+

y

=

−

7

; (5, −2)

6.

9

x

−

3

y

=

6

; (0, −2)

7.

1

2

x

+

1

3

y

=

−

1

6

; (1, −2)

8.

3

4

x

−

1

2

y

=

−

1

; (2, 1)

9.

4

x

−

3

y

=

1

;

(

1

2

,

1

3

)

10.

−

10

x

+

2

y

=

−

9

5

;

(

1

5

,

1

10

)

11.

y

=

1

3

x

+

3

; (6, 3)

12.

y

=

−

4

x

+

1

; (−2, 9)

13.

y

=

2

3

x

−

3

; (0, −3)

14.

y

=

−

5

8

x

+

1

; (8, −5)

15.

y

=

−

1

2

x

+

3

4

;

(

−

1

2

,

1

)

16.

y

=

−

1

3

x

−

1

2

;

(

1

2

,

−

2

3

)

17.

y

=

2

; (−3, 2)

18.

y

=

4

; (4, −4)

19.

x

=

3

; (3, −3)

20.

x

=

0

; (1, 0)

Find the ordered pair solutions given the set of x-values.

21.

y

=

−

2

x

+

4

; {−2, 0, 2}

22.

y

=

1

2

x

−

3

; {−4, 0, 4}

23.

y

=

−

3

4

x

+

1

2

; {−2, 0, 2}

24.

y

=

−

3

x

+

1

; {−1/2, 0, 1/2}

25.

y

=

−

4

; {−3, 0, 3}

26.

y

=

1

2

x

+

3

4

; {−1/4, 0, 1/4}

27.

2

x

−

3

y

=

1

; {0, 1, 2}

28.

3

x

−

5

y

=

−

15

; {−5, 0, 5}

29.

–

x

+

y

=

3

; {−5, −1, 0}

30.

1

2

x

−

1

3

y

=

−

4

; {−4, −2, 0}

31.

3

5

x

+

1

10

y

=

2

; {−15, −10, −5}

32.

x

−

y

=

0

; {10, 20, 30}

Find the ordered pair solutions, given the set of y-values.

33.

y

=

1

2

x

−

1

; {−5, 0, 5}

34.

y

=

−

3

4

x

+

2

; {0, 2, 4}

35.

3

x

−

2

y

=

6

; {−3, −1, 0}

36.

−

x

+

3

y

=

4

; {−4, −2, 0}

37.

1

3

x

−

1

2

y

=

−

4

; {−1, 0, 1}

38.

3

5

x

+

1

10

y

=

2

; {−20, −10, −5}

Part B: Graphing Lines

Given the set of x-values {−2, −1, 0, 1, 2}, find the corresponding y-values and graph them.

39.

y

=

x

+

1

40.

y

=

−

x

+

1

41.

y

=

2

x

−

1

42.

y

=

−

3

x

+

2

43.

y

=

5

x

−

10

44.

5

x

+

y

=

15

45.

3

x

−

y

=

9

46.

6

x

−

3

y

=

9

47.

y

=

−

5

48.

y

=

3

Find at least five ordered pair solutions and graph.

49.

y

=

2

x

−

1

50.

y

=

−

5

x

+

3

51.

y

=

−

4

x

+

2

52.

y

=

10

x

−

20

53.

y

=

−

1

2

x

+

2

54.

y

=

1

3

x

−

1

55.

y

=

2

3

x

−

6

56.

y

=

−

2

3

x

+

2

57.

y

=

x

58.

y

=

−

x

59.

−

2

x

+

5

y

=

−

15

60.

x

+

5

y

=

5

61.

6

x

−

y

=

2

62.

4

x

+

y

=

12

63.

−

x

+

5

y

=

0

64.

x

+

2

y

=

0

65.

1

10

x

−

y

=

3

66.

3

2

x

+

5

y

=

30

Part C: Horizontal and Vertical Lines

Find at least five ordered pair solutions and graph them.

67.

y

=

4

68.

y

=

−

10

69.

x

=

4

70.

x

=

−

1

71.

y

=

0

72.

x

=

0

73.

y

=

3

4

74.

x

=

−

5

4

75. Graph the lines

y

=

−

4

and

x

=

2

on the same set of axes. Where do they intersect?

76. Graph the lines

y

=

5

and

x

=

−

5

on the same set of axes. Where do they intersect?

77. What is the equation that describes the x-axis?

78. What is the equation that describes the y-axis?

Part D: Mixed Practice

Graph by plotting points.

79.

y

=

−

3

5

x

+

6

80.

y

=

3

5

x

−

3

81.

y

=

−

3

82.

x

=

−

5

83.

3

x

−

2

y

=

6

84.

−

2

x

+

3

y

=

−

12

Step-by-step explanation:

Answer:

After filling in the formula and solving you’ll get 1.75 which is the same as 7/4

The equation of the parabola formed by the plane that is parallel to a generating line of a double napped cone is y = (A/B)x^2 + (6/B)x + (9/B + K/B).

The equation of a double napped cone is given by:

\(Ax^2 + By^2 + Cz^2 + 2Dxy + 2Exz + 2Fyz + 2Gx + 2Hy + 2Jz + K = 0\)

Where A, B, C, D, E, F, G, H, J and K are constants.

A plane that is parallel to a generating line of a double napped cone will intersect the cone at a single point, forming a parabola. The equation of a parabola can be written as:

y = ax^2 + bx + c

Where a, b, and c are constants.

We can find a, b and c by substituting the equation of the plane into the equation of the double napped cone.

For example, if the equation of the plane is x + y – z = 3 then we can substitute this into the equation of the double napped cone and solve for the coefficients a, b and c.

Substituting x + y – z = 3 into the equation of the double napped cone:

\(Ax^2 + By^2 + Cz^2 + 2Dxy + 2Exz + 2Fyz + 2Gx + 2Hy + 2Jz + K = 0\)

We get:

\(Ax^2 + B(x + 3)^2 + C(-x - 3)^2 + K = 0\)

Expanding, we get:

\(Ax^2 + Bx^2 + 6Bx + 9B + Cx^2 - 6Cx - 9C + K = 0\)

Grouping terms and solving for a, b and c, we get:

a = A/B

b = 6/B

c = 9/B + K/B

Therefore, the equation of the parabola formed by the plane that is parallel to a generating line of a double napped cone is y = (A/B)x^2 + (6/B)x + (9/B + K/B).

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We have: 540° = 180° - x° + 180° - 52° + 93° + 180° - (x+3)° + 180° - 78°

⇒ 2x° = 140° ⇒ x° = 70°

The answer is C. 70°

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The fraction that represents the pairs of socks each store will receive is 82/3.

A fraction is written in the form of a numerator and a denominator where the denominator is greater that the numerator.

Example: 1/2, 1/3 is a fraction.

We have,

Total number of pairs of socks = 346

Number of socks to be shipped = 346 - 100 = 246

Number of stores = 9

The number of pairs of socks each store will receive.

= 246/9

= 82/3

Thus,

The fraction is 82/3.

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The antiderivative of 7ex is 7ex, and the antiderivative of 6 sec2(x) is 6 tan(x). Thus, the most general antiderivative is F(x) = 7ex + 6 tan(x) + C, where C represents the constant of integration.

To find the antiderivative of the given function f(x) = 7ex 6 sec2(x), we integrate each term separately. The antiderivative of 7ex is simply 7ex, as the exponential function ex is its own antiderivative.

Next, we consider the antiderivative of 6 sec2(x). The derivative of the tangent function tan(x) is sec2(x), so the antiderivative of sec2(x) is tan(x). However, there is a coefficient of 6 in front of sec2(x), so the antiderivative becomes 6 tan(x).

Combining these results, we have F(x) = 7ex + 6 tan(x) as the antiderivative of the original function f(x) = 7ex 6 sec2(x). The "+ C" at the end represents the constant of integration, as any constant added to the antiderivative remains undetermined. Therefore, the most general antiderivative of f(x) is F(x) = 7ex + 6 tan(x) + C, where C is a constant.

To verify this result, we can differentiate F(x) and confirm that it indeed yields the original function f(x). Taking the derivative of F(x) with respect to x will give us back 7ex 6 sec2(x), thus confirming the correctness of the antiderivative.

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To show that `(n + 3)7 ∈ Θ(n7)`, we need to prove that `(n + 3)7 = Θ(n7)`.This can be done by showing that `(n + 3)7 = O(n7)` and `(n + 3)7 = Ω(n7)` .Now, let's prove the two parts separately:

Proof for `(n + 3)7 = O(n7)`.

We want to prove that there exists a positive constant c and a non-negative constant k such that `(n + 3)7 ≤ cn7` for all `n ≥ k`.Using the Binomial theorem, we can expand `(n + 3)7` as:```
(n + 3)7
= n7 + 7n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6 + 37
≤ n7 + 21n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6 + n7
≤ 2n7 + 21n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6
≤ 2n7 + 84n6 + 441n5 + 2205n4 + 10395n3 + 45045n2 + 153609n + 729
```Thus, we can take `c = 153610` and `k = 1` to satisfy the definition of big-Oh notation. Hence, `(n + 3)7 = O(n7)`.Proof for `(n + 3)7 = Ω(n7)`We want to prove that there exists a positive constant c and a non-negative constant k such that `(n + 3)7 ≥ cn7` for all `n ≥ k`.Using the Binomial theorem, we can expand `(n + 3)7` as:```
(n + 3)7
= n7 + 7n6(3) + 21n5(3)2 + 35n4(3)3 + 35n3(3)4 + 21n2(3)5 + 7n(3)6 + 37
≥ n7
```Thus, we can take `c = 1` and `k = 1` to satisfy the definition of big-Omega notation. Hence, `(n + 3)7 = Ω(n7)`.

As we have proved that `(n + 3)7 = O(n7)` and `(n + 3)7 = Ω(n7)`, therefore `(n + 3)7 = Θ(n7)`.Thus, we have shown that `(n + 3)7 ∈ Θ(n7)`.From the proof, we can see that we used the Binomial theorem to expand `(n + 3)7` and used algebraic manipulation to bound it from above and below with suitable constants. This technique can be used to prove the time complexity of various algorithms, where we have to find the tightest possible upper and lower bounds on the number of operations performed by the algorithm.

Hence, we have shown that `(n + 3)7 ∈ Θ(n7)` for non-negative integer n.

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Answer:

this is all I could find

Answer:

32

Step-by-step explanation:

If there are 6 eggs in a row and there are 4 rows, the total number of eggs = 6 x 4 = 24 eggs

The sum of eggs and bagels = 24 + 8 = 32

The curve of intersection between the cylinder x^2 + y^2 = 1 and the plane y + z = 2 is a circle lying on the plane y + z = 2. The parametric equations for this curve are x = cos(θ), y = sin(θ), and z = 2 - sin(θ), where θ is the parameter representing points on the circle.

To find the parametric equations for the curve of intersection between the cylinder and the plane, we can start by parameterizing the cylinder using the angle θ. Since the equation x^2 + y^2 = 1 represents a circle in the x-y plane with radius 1, we can use θ as a parameter to represent points on this circle.

The parametric equations for the cylinder are:

x = cos(θ)

y = sin(θ)

z = 2 - y

Next, we substitute these equations into the plane equation y + z = 2 to determine the intersection points. By substituting y and z, we have sin(θ) + 2 - sin(θ) = 2, which simplifies to sin(θ) - sin(θ) = 0. This implies that the plane equation is satisfied for any value of θ.

Therefore, the intersection between the cylinder and the plane is the entire cylinder itself, lying on the plane y + z = 2. The parametric equations for the curve of intersection are x = cos(θ), y = sin(θ), and z = 2 - sin(θ).

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Answer:

Step-by-step explanation:

The predicted gain (or loss) from a single trial is 53 cents per game on average.

A roulette wheel has the number 1 through 36, as well as 0 and 00. If you wager $1 that an odd number would show up, you will win or lose $1 depending on whether or not that occurrence occurs. If random variable X represents your net benefit, X=1 with probability 18/38 and X=-1 with probability 20/38.

E(X) = 1(18/38) – 1 (20/38) = -$.053

On average, the casino wins  5 cents for each game.

If the stakes are raised, the casino makes even more money:

E(X) = 10(18/38) – 10 (20/38) = -$.53

If the cost is $10 for each game, the casino wins an averaged of 53 cents per game. If 10,000 games are played in a single night, that's a cool $5300.

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The value of x that is not included in the domain of the function is 0, because it makes the expression undefined. This is because division by zero is undefined.

The given function is:y = 1/x + 12The value of x that is not included in the domain of the function can be found by analyzing the expression for the function’s domain. The denominator of the expression cannot be equal to 0, otherwise the expression will be undefined. Thus, it can be stated that x can be any real number except for 0.

The domain of the given function is all real numbers except for 0. When the value of x is 0, the denominator becomes zero, which makes the value of y infinite or undefined. In mathematical terms, we can represent this situation as follows:y = 1/0 + 12 => y = ∞. Hence, the value of x that is not included in the domain of the function is 0, because it makes the expression undefined. This is because division by zero is undefined.

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One possible value of ∠U is 80° (to the nearest degree).

A triangle is a three-sided polygon with three vertices. The triangle's internal angle, which is 180 degrees, is constructed.

To find the possible values of ∠U, we can use the Law of Cosines:

c² = a² + b² - 2ab cos(C)

Where c is the side opposite the angle we want to find (∠U), a and b are the other two sides, and C is the angle opposite side c.

In this case, we want to find ∠U, so we'll use side u as c and sides t and s (which we don't know yet) as a and b, respectively:

u² = t² + s² - 2ts cos(U)

Substituting the given values, we get:

340² = 620² + s² - 2(620)(s)cos(U)

Simplifying:

115600 = 384400 + s² - 1240s cos(U)

Subtracting 384400 and rearranging:

s² - 1240s cos(U) + 268800 = 0

Now we can use the quadratic formula to solve for s:

s = [1240 cos(U) ± √(1240² cos²(U) - 4(1)(268800))]/(2)

Simplifying under the square root:

s = [1240 cos(U) ± √(1537600 cos²(U) - 1075200)]/(2)

s = [1240 cos(U) ± √(409600 cos²(U) + 1742400)]/(2)

s = [620 cos(U) ± √(102400 cos²(U) + 435600)]

Since s must be positive, we can discard the negative solution, and we have:

s = 620 cos(U) + √(102400 cos²(U) + 435600)

Now we can use the fact that the sum of angles in a triangle is 180° to find ∠U:

∠U = 180° - ∠T - ∠S

Since we know ∠T = 110°, we just need to find ∠S. We can use the Law of Sines to do this:

sin(S)/s = sin(T)/t

sin(S) = (s/t)sin(T)

Substituting the values we know:

sin(S) = (620 cos(U) + √(102400 cos²(U) + 435600))/620 * sin(110°)

sin(S) ≈ (1.481 cos(U) + 2.225)/6.959

Now we can use a calculator to find the arcsin of both sides to get ∠S:

∠S ≈ arcsin((1.481 cos(U) + 2.225)/6.959)

Finally, we can substitute the values we found for ∠S and ∠T into the equation we found earlier for ∠U:

∠U = 180° - 110° - arcsin((1.481 cos(U) + 2.225)/6.959)

Simplifying:

∠U = 70° - arcsin((1.481 cos(U) + 2.225)/6.959)

Now we can use trial and error or a graphing calculator to find the values of ∠U that satisfy this equation. One possible solution is:

∠U ≈ 80°

Therefore, one possible value of ∠U is 80° (to the nearest degree).

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Answer:

38

Step-by-step explanation:

\( \frac{2}{3} \times 57 \\ divide \: 3 \: by \: 57 \\ 2\times 19 \\ = 38\)

Answer:

$6.80

Step-by-step explanation:

1.79 x 3.8 = 6.802

So $6.80

Answer:

46

Explanation:

In each number to the right of the equality sign, the tenths place is always the rightmost number in addition and the one place is the result of the addition.

For example, in 1 +3 = 34

Therefore, for 2 + 4 we have

Hence,

which is our answer!

Answer:

\((a)\ \sqrt5 <2.3 < 5.6\)

\((b)\ \sqrt 5 <2.4 < 5.6\)

\((e)\ \sqrt 8 <2.9\)

\((f)\ \sqrt5 <4.5 < 5\)

Step-by-step explanation:

Required

Which are true

\((a)\ \sqrt5 <2.3 < 5.6\)

Take square root of 5

\(2.2 <2.3 < 56\) --- This is true

\((b)\ \sqrt 5 <2.4 < 5.6\)

Take square root of 5

\(2.2 <2.4 < 56\)  --- This is true

\((c)\ 7.4 < 5 <5.5\)

This is false because \(7.4 > 5\)

\((d)\ \sqrt 3 <3 <3\)

This is false because \(3 = 3\) not \(3 < 3\)

\((e)\ \sqrt 8 <2.9\)

Take square root of 8

\(2.8 <2.9\) --- This is true

\((f)\ \sqrt5 <4.5 < 5\)

Take square root of 5

\(2.2 <4.5 < 5\) --- This is true