Answer: x= -7/2 x=1
Step-by-step explanation:
You first need to bring all terms to 1 side and make =0
Assuming there is a + in front of 14
2x²+14x=-9x+7
2x²+5x-7=0
multiply the first and last find 2 numbers that multiply to that number and add to the middle
+7 and -2 multiply to -14 but add to 5 substitute those numbers for the 5x
2x²+7x-2x-7 see how the 7x-2x is actually 5x. Just making it look diff
(2x²+7x)(-2x-7) put parentheses around the 1st 2 terms and last to group. This is not your factoring. you are going to take the GCF (greatest common factor from both)
x(2x+7)-1(2x+7) if the items in the parentheses are same, you did a good job so far. What is in the parenthesesis one of your factors and whatever leftover is your other
(2x+7)(x-1) =0 now set each =0 and solve for x
2x+7=0 x-1=0
2x=-7
x= -7/2 x=1
Use the distributive property to rewrite this expression in simplest form 6(n+5).
A
6n + 30
B
30n
C
36n
Answer:
6n+30
Step-by-step explanation:
Step 1:
Multiply 6 and n
6nStep 2:
Multiply 6 and 5
30Step 3:
Put together!
6n+30have a great day and thx for your inquiry :)
Answer:
the answer is A
Step-by-step explanation:
distributive property states
a(b+c)=ab+ac
therefore
6(n+5)=6n+30
Determine the inverse of the matrix c= [6, -7 -8, 9]
The inverse of the given matrix would be C. C ⁻¹ [-4.5, -3.5]
[ - 4 , - 3 ]
How to find the inverse ?The formula for finding the inverse of the matrix is;
= ( 1 / determinant ) x [ d , - b ]
[ - c , a ]
The inverse is therefore:
= 1 / 2 x [ 9 , 7 ]
= [- 4. 5 , - 3 . 5 ]
= [ - 4 , - 3 ]
So, the inverse of the matrix C is:
[ - 4. 5 , -3. 5 ]
[ - 4 , - 3 ]
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The most a baker can spend on strawberries is $95.00. Strawberries cost $3.99 per pound, and the produce supplier charges a $15.20 delivery fee. The following inequality, where s stands for the number of pounds of strawberries, represents this situation:
Answer:
3.99s + 15.20 = 95.00
Step-by-step explanation:
you would put 's' next to the 3.99 because that's what your multiplying or having more than 1 of, then you would add the 15.20 because it's just a one time delivery fee.
Answer:
The answer is 20
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form: s≥20
Interval Notation: [20,∞)
The graph of which equation is shown?
Answer:
it should be
C. y = 2x +2
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
The starting point is 2. Where the line touches the y axis. The line as you see is going down which is negative. Pick 2 points on the graph where it’s touching. It is going down by 2. Hope this helps!
shareholders. Calculate the amount of dividend r of dividend received by Bishwant. Curriculum Development Centre. Sanothimi. Bhaktanur 65 Vedanta Excel in Mathematics - Booeceived by Mrs. Rai. b) A Business Company sold 2,500 shares at Rs 1,200 per share. Bishwant bought 450 shares. If the company earned a net profit of Rs 39,00.000 in a year and it announced to distribute 18% dividend from the net profit to its shareholders, find the amount
3900000×18% = 702000
702000÷2500 = 280.8 per share dividend
450×280.8 = 126360
How many degrees is the measure of ∠4
?
Answer:
Below
Step-by-step explanation:
Angle 4 + 60 + 61 = straight line = 180 °
angle 4 = 180 - 60 - 61 = 59°
Which point would NOT be a solution to the system of linear inequalities shown below?
It's asking would not be a solution soo
(-10, -9) as you can see
You're welcome thank me later
I have a math test tomorrow and desperately need help with some questions. Could you answer this in the picture please
Step 1 : Given the function below
\(h(x)=xg(x^2)+R^{-1}(x)\)Step 2: Write the function for h(3), this is done by substituting 3 for x in the function h(x) above
\(\begin{gathered} h(x)=xg(x^2)+R^{-1}(x) \\ h(3)=3g(3^2)+R^{-1}(3)_{}_{} \\ h(3)=3\times g(9)+R^{-1}(3)_{} \end{gathered}\)Step 3: Write the corresponding value for the function g(9) and an inverse function of R⁻¹ (3) on the table.
\(\begin{gathered} g(9)\Rightarrow\text{ check the value of g(x) when x is 9} \\ g(9)=-5 \end{gathered}\)\(\begin{gathered} R^{-1}(3)\Rightarrow\text{check the value of x when }R^{-1}\text{ is 3} \\ R^{-1}(3)=4^{} \end{gathered}\)Step 4: Substitute the g(9) and R⁻¹ (3) values in the h(3) equation and simplify
\(\begin{gathered} h(3)=3\times g(9)+R^{-1}(3) \\ h(3)=3\times(-5)+4 \\ h(3)=-15+4 \\ h(3)=-11 \end{gathered}\)Hence, the value of h(3) is -11
The second option is the correct answer.
For a long distance person to person telephone call a telephone company charges 0.91 for the first minute 0.58 for each additional minute and 2.74 a service charge. If the cost of a call is 5.39 how long did the person talk
If the cost of a call is 5.39, obviously this person stayed more than one minute at the telephone. It will pay for:
2.74 for service charge;0.91 for the first minute;x for the additional minutes.If we will find out the value of x, we will know how much time this person paid for additional minutes. Let's make some subtractions:
The total minus the service charge: \(5.39-2.74=2.65\);2.65 minus the first minute: \(2.65-0.91=1.74\)So, this person paid 1.74 by additional minutes. Let's divide this value by the price for additional minute:
\(\frac{1.74}{0.58} =3\)
This means that it paid by 3 minutes additional.
Therefore, this people stayed at telephone by 3 + 1 = 4 minutes.
the area of a playground is 336 yd^2 . the width of the playground is 5 yd longer than its length. find the length and width of the playground.
Answer:
y x y + 5 = 336
2y + 5y = 336
10y = 336
y = 33.6
Write an equation that can be used to find 푚∠푀. Then, solve it. Round to the nearest degree.
Answer:
M = 27 degrees
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin M = opp side/ hypotenuse
Sin M = 5/11
Take the inverse sin of each side
sin ^-1 sin M = sin ^1 (5/11)
M = 27.03569179
To the nearest degree
M = 27 degrees
At a local park, a border for a miniature football field (rectangular) is being constructed. Designers want the border’s length to be 18 feet greater than its width. A maximum of 240 feet is available for the border. Write an inequality and solve to describe the possible widths of the miniature football field.
Answer:
Width <= 51 ft.
Step-by-step explanation:
Width = w
Length = w+18
Perimeter: 240 >= 2 (w+w+18)
4w + 36 <= 240
4w <= 204
w <= 51
A convex lens with focal length f centimeters will project the image of an object on a
point behind the lens. If an object is placed a distance of p centimeters from the lens,
then the distance q centimeters of the image from the lens is related to p and f by the
lens equation: 1/p+1/q=1/f
A. If the focal length of the convex lens is supposed to be 5 cm, and if the image is
formed 7 cm from the lens, find the distance from the lens to the object, p. (It’s not necessary to simplify your answer.)
B. Find an expression that gives q as a function of p, assuming that the focal length is a constant of 5 centimeters.
C. Sketch a graph of q as a function of p (i.e., q(p)), assuming that the focal length is a
constant of 5 centimeters. Show any important features of the graph.
D. Find limq(p) as p approaches infinity and limq(p) as p approaches 5from the positive side. What do these limits represent physically? What must
happen to the distance of the image and the object?
Answer:
A. Using the lens equation, 1/p + 1/q = 1/f, and substituting f = 5 cm and q = 7 cm, we can solve for p:
1/p + 1/7 = 1/5
Multiplying both sides by 35p, we get:
35 + 5p = 7p
Simplifying and rearranging, we get:
2p = 35
Therefore, the distance from the lens to the object, p, is:
p = 35/2 cm
B. Solving the lens equation, 1/p + 1/q = 1/f, for q, we get:
1/q = 1/f - 1/p
Substituting f = 5 cm, we get:
1/q = 1/5 - 1/p
Multiplying both sides by 5qp, we get:
5p = qp - 5q
Simplifying and rearranging, we get:
q = 5p / (p - 5)
Therefore, the expression that gives q as a function of p is:
q = 5p / (p - 5)
C. Here is a sketch of the graph of q(p):
The graph is a hyperbola with vertical asymptote at p = 5 and horizontal asymptote at q = 5. The image distance q is positive for object distances p greater than 5, which corresponds to a real image. The image distance q is negative for object distances p less than 5, which corresponds to a virtual image.
D. Taking the limit of q as p approaches infinity, we get:
lim q(p) = 5
This represents the horizontal asymptote of the graph. As the object distance becomes very large, the image distance approaches the focal length of the lens, which is 5 cm.
Taking the limit of q as p approaches 5 from the positive side, we get:
lim q(p) = -infinity
This represents the vertical asymptote of the graph. As the object distance approaches the focal length of the lens, the image distance becomes infinitely large, indicating that the lens is no longer able to form a real image.
In order for the lens to form a real image, the object distance p must be greater than the focal length f. When the object distance is less than the focal length, the lens forms a virtual image.
Indicate the method you would use to prove the two 's . If no method applies, enter "none".
SSS
ASA
SAS
AAS
None
The method you would use to prove the two triangles are congruent include the following: B. ASA.
What are the properties of similar triangles?In Mathematics and Geometry, two (2) triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.
Additionally, the lengths of corresponding sides are proportional to the lengths of corresponding altitudes when two (2) triangles are similar.
In Mathematics and Geometry, ASA is an abbreviation for Angle-Side- Angle and it states that when two (2) angles and their included side in two (2) triangles are congruent, then the triangles are said to be congruent.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
you did not provide enough information to answer the question
What is the slope of the line that passes through the points (8, -6) and (5, -1)
Answer:
-5/3
Step-by-step explanation:
trust me bro
Answer:
Use desmos
Step-by-step explanation:
Basically it is a graphing calculator put your points
The solids below are similar. give the scale factor, surface area ratio, and volume ratio.
Hello there. To solve this question, we'll have to remember some properties about scaling factor and ratios.
Given two solids that are similar:
We have to determine the scaling factor, the surface area and volume ratios.
First, the scaling factor, in the case of spheres, is the ratio between their radius.
In this case, we determine each ratio using the formula for the volume:
\(V=\dfrac{4\pi\cdot R^3}{3}\)For a sphere with radius R.
In our case, say the smaller sphere has radius r and the larger sphere has radius R.
Hence we have that:
\(V(r)=250=\dfrac{4\pi\cdot r^3}{3}\)Multiply both sides of the equation by a factor of 3/4pi
\(r^3=250\cdot\dfrac{3}{4\pi}=\dfrac{375}{2\pi}\)Take the cube root on both sides of the equation
\(r=\sqrt[3]{\dfrac{375}{2\pi}}\)We're not using an approximation here because we'll need this value until the end.
Now, for the sphere with radius R, we have
\(V(R)=686=\dfrac{4\pi \cdot R^3}{3}\)Multiply both sides by 3/4pi
\(R^3=686\cdot\dfrac{3}{4\pi}=\dfrac{1029}{2\pi}\)Take the cube root on both sides of the equation
\(R=\sqrt[3]{\dfrac{1029}{2\pi}}\)The scaling factor is given by:
\(\dfrac{R}{r}=\dfrac{\sqrt[3]{\dfrac{1029}{2\pi}}}{\sqrt[3]{\dfrac{375}{2\pi}}}=\sqrt[3]{\dfrac{343}{125}}\)Now, we can find an approximation for it as:
\(\text{ Scaling factor }=1.4\)In fact it is exact.
Now, to find the surface area and volume ratios, we use the formulas to show that:
The surface area of a sphere with radius R is
\(S=4\pi\cdot R^2\)Hence the ratio is
\(\text{ Surface area ratio }=\dfrac{4\pi R^2}{4\pi r^2}=\left(\dfrac{R}{r}\right)^2\)Plugging the solution we found, we get
\(1.4^2=1.96\)In a same manner for a volume, we get
\(\text{ Volume ratio }=\dfrac{\dfrac{4\pi R^3}{3}}{\dfrac{4\pi r^3}{3}}=\left(\dfrac{R}{r}\right)^3\)Hence we get
\(1.4^3=2.744\)These are the answers to this question.
4/5 x 7/12 please help
Answer:
28/60
Step-by-step explanation:
times numerator by the other numerator and times the denominator by the other denominator
22 divided by a number s
22 divided my 2 is 11
Answer:
22 divided by 2 is 11
Step-by-step explanation:
Find the measure for angle b
Carly took a $7,000, 3-year loan with an APR of 3.15%.
A)What is the monthly payment? B)What is the total amount of the monthly payments? C)What is the finance charge?
Answer:
A: 219.84
B: 219.84 x 36 = 7914.21
C: 7914.21 - 7000 = 914.24
Step-by-step explanation:
When Carly took a $7,000, 3-year loan with an APR of 3.15%, then
The monthly payment for the same will be $213.40The total amount of monthly payments will be $7,682.55; and The amount of finance charge for the same will be $682.55. What is the significance of monthly payments?Monthly payments can be referred to or considered as the monthly amount paid towards the partial repayment of a loan or an advance taken at a predetermined interest rate and time period.
Compounded Annuity = 7000(1+0.0315)^3
Compounded Annuity = $7,682.55.
Now, the amount of monthly payments for 3 years, or 36 months will be
Monthly payments = 7682.55 / 36
Monthly payments = $213.40
Finance Charge = Annuity – Principal
Finance Charge = 7682.55-7000
Finance Charge = $682.55
Therefore, the significance regarding monthly payments and the amounts of finance charge for the given condition has been aforementioned.
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Evaluate the surface integral. S xz dS S is the boundary of the region enclosed by the cylinder y2 + z2 = 16 and the planes x = 0 and x + y = 10
If you project S onto the (x,y)-plane, it casts a "shadow" corresponding to the trapezoidal region
T = {(x,y) : 0 ≤ x ≤ 10 - y and -4 ≤ y ≤ 4}
Let z = f(x, y) = √(16 - y²) and z = g(x, y) = -√(16 - y²), each referring to one half of the cylinder to either side of the plane z = 0.
The surface element for the "positive" half is
dS = √(1 + (∂f/∂x)² + (∂f/dy)²) dx dy
dS = √(1 + 0 + 4y²/(16 - y²)) dx dy
dS = √((16 + 3y²)/(16 - y²)) dx dy
The the surface integral along this half is
\(\displaystyle \iint_T xz \,dS = \int_{-4}^4 \int_0^{10-y} x \sqrt{16-y^2} \sqrt{\frac{16+3y^2}{16-y^2}} \, dx \, dy\)
\(\displaystyle \iint_T xz \,dS = \int_{-4}^4 \int_0^{10-y} x \sqrt{16+3y^2}\, dx \, dy\)
\(\displaystyle \iint_T xz \,dS = \frac12 \int_{-4}^4 (10-y)^2 \sqrt{16+3y^2} \, dy\)
\(\displaystyle \iint_T xz \,dS = 416\pi\)
You'll find that the integral over the "negative" half has the same value, but multiplied by -1. Then the overall surface integral is 0.
a restaurant offers 7 appetizers and 9 main courses. In how many ways can a person order a two-course meal
Wreh runs laps around a track every day after work. He runs at a constant rate and completes about 12 laps every 18 minutes.
How many minutes does it take Wreh to run 30 laps?
Solve this problem two different ways. Note: cross multiplication will only receive credit as one approach.
Answer:
It willtake 45 minutes
Step-by-step explanation:
divide 18 by 12= 1.5, so multiply 1.5 by 30
Tyere and his two brothers decide to split the cost of a new CD. If the CD costs $12.75, how much did each brother pay?
Answer:
6 dollars
Step-by-step explanation:
12+12 =6
Find the area of the polynomial:
A.) 6a^3 + 12a^2 − 15a
B.) 6a^3 + 12a − 15
C.) 6a^2 + 12a − 15
D.) 5a^2 + 7a − 2
y'all pls help me :(((((
Answer:
m = 1, n = 0
Step-by-step explanation:
Given the division expression,
\(5^{m}\) ÷ \(5^{n}\) = 5
Using the Zero Exponent Rule, \(a^{0} = 1\), which essentially means that any nonzero number raised to zero equal to 1. We should apply this property to the divisor, \(5^{n}\), so that you get a quotient of 1. Doing so leaves you with:
\(5^{m}\) ÷ \(5^{0}\) = \(5^{m}\) ÷ 1 = 5
This makes it easier to determine that the value of m = 1, because raising a number to an exponent of 1 results to the same number. In other words, \(5^{1} = 5\).
Therefore: \(5^{m}\) ÷ \(5^{n}\) = \(5^{1}\) ÷ \(5^{0}\) = 5 ÷ 1 = 5.
Hence, the correct answers are: m = 1, and n = 0.
The ratio of the number of miles run to the number of miles biked is equivalent for each row in the table. What is the relationship between distances biked and distances run?
The relationship between distances biked and distances run is
D(bike) = 2 × D(run)
Here, we have been shown that when distance run is, lets say x then distance run is 2x
When distance run is 2 then distance biked is 4, twice as distance run.
Again in distance run 3\(\frac{1}{2}\), distance biked is 7, so this proves that
D(bike) = 2 × D(run)
What is the importance of distance?The measurement of distance between two objects or points can be quantitative or occasionally qualitative. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over").
Since spatial thinking is a rich source of conceptual metaphors in human thought, the term is also frequently used metaphorically to denote a measure of the degree of separation or the statistical distance between two similar objects (such as edit distance between strings of text or statistical distance between probability distributions) (as exemplified by distance between people in a social network).
A metric space is a mathematical concept that is used to define the majority of these conceptions of distance, both literal and figurative.
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Here is a simple math question
Answer: range: 49-22=27
median: 40+41=81 81/2=40.5
mean: add up all the numbers=485 485/12=40.4
mode: 39, 40 and 46
Answer:
simple 49-22=27
mode 39, 40 and 46
Step-by-step explanation:
during pie eating contest my dad eat 5 4/12 and my mum ate 2 1/4 ow many pies did they eat together
Answer:
6 7/12
Step-by-step explanation:
find the value of x . PLEASE ANSWER QUICK ILL MARK BRAINLIEST
Answer:
x = 20
Step-by-step explanation:
90° - 76° = 14°
\((x-6)=14\)
\((x+6)=+6\) Add 6 to both sides
x = 20
Hence, x = 20
Answer: X=20
Right angles are 90 degrees and 90-76=14... X-6=14... add 6 to 14 and get 20. X=20. Don't quote me on it I haven't done this stuff in a year.