Answer:
4 is greater
Step-by-step explanation:
A negative divided by a positive = a negative.
No matter what y is, it will be a negative number.
Meaning, 4 a positive number, will be greater no matter what y is
Solve for a in terms of b, c, and d.
c=a+b–d
What is the measure of angle P? q is 65° P is 67°
this IXL is due tomorrow so I need help fast make sure to explain
Check the picture below.
The average number of employees that call in sick for the day over the course of a year is 24.
The number of employees that call in sick in 12 days are 24, 36, 19, 21, 29, 29, 24, 14, 18, 30, 22 and 15
Enter the sample mean the box.
The sample mean for the number of employees calling in sick over the 12 days is 24.25.
To find the sample mean, we need to calculate the average of the given numbers. The numbers represent the number of employees who called in sick over 12 days.
The number of employees calling in sick for the 12 days provided are: 24, 36, 19, 21, 29, 29, 24, 14, 18, 30, 22, and 15.
To find the sample mean, we sum up all the numbers and divide by the total number of days (12 in this case).
Sum of the numbers: 24 + 36 + 19 + 21 + 29 + 29 + 24 + 14 + 18 + 30 + 22 + 15 = 291
Sample mean = Sum of numbers / Number of days = 291 / 12 = 24.25.
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HELP ASAP!!! LOTS OF POINTS!
The perimeter of a square is 20 meters. Explain how you can use this information to find the area of the same square.
Combine the formula for the perimeter and area of a square into a single formula. Then substitute P=20 and solve for s using the order of operations.
You can use the formula for the perimeter of a square to find the length of one of the square's sides. Then substitute that information into the formula for the area of a square and solve.
You can determine the length of one of the square's sides from the given information. Substitute the value for into each of the formulas for a square's perimeter and area. The value of P will be equal to the value of A .
Use the formula for the area of a square to find the length of a single side of the square. Then substitute that information into the formula for the perimeter of a square and solve.
Answer:
You can use the formula for the perimeter of a square to find the length of one of the square's sides. Then substitute that information into the formula for the area of a square and solve.
Step-by-step explanation:
Taking the exam same as you 90 % sure this is right
The area of the square can be gotten by using the perimeter of the square to get the length of the square. Then, we use the length to find the area of the square.
Properties of a square.All the sides are equalAll the angles are equal.All the sides are parallel to each other.Therefore,
perimeter of a square = 4l
where
l = length of squareTherefore,
4l = 20
divide both sides by 4
l = 20 / 4
l = 5 meters
Therefore,
area of the square = l²
where
l = side lengtharea of the square = 5²
area of the square = 25 cm²
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This function has a local minimum at x= with output value: And a local maximum at x=With output value:
minimum:10
output :509
maximum:5
output: 634
Explanation
Step 1
graph the function:
to do this, you need put values for x, and you will get a set of values for y, those formed pairs are the coordinates,
we can see, there are a minimun and a maximum
Step 2
find the minimum
To find the local minimum of any graph, you must first take the derivative of the graph equation, set it equal to zero and solve for
\(f(x)=2x^3-45x^2+300x+9\)a) derivate
\(\begin{gathered} f(x)=2x^3-45x^2+300x+9 \\ \end{gathered}\)To take the derivative of this equation, we must use the power rule
\(\begin{gathered} f(x)=2x^3-45x^2+300x+9 \\ f^{\prime}(x)=(2\cdot3)x^{(3-1)}-(45\cdot2)x^{2-1}+300x^{(1-1)}+9 \\ f^{\prime}(x)=6x^2-90x+300 \end{gathered}\)solve for x by applying the quadratic formula
\(ax^2+bx+c=0\rightarrow6x^2-90x+300=0\)\(\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{replace} \\ x=\frac{-(-90)\pm\sqrt[]{90^2-4\cdot6\cdot300}}{2\cdot6} \\ x=\frac{90\pm\sqrt[]{8100-7200}}{12} \\ x=\frac{90\pm\sqrt[]{900}}{12} \\ x=\frac{90\pm30}{12} \\ so \\ x_1=\frac{90+30}{12}=\frac{120}{12}=10 \\ x_2=\frac{90-30}{12}=\frac{60}{12}=5 \end{gathered}\)then, let's find the output when x=5
\(\begin{gathered} f(x)=2x^3-45x^2+300x+9 \\ f(5)=2\cdot5^3-45\cdot5^2+300\cdot5+9 \\ f(5)=250-1125+1500+9 \\ f(5)=634 \end{gathered}\)so,infelection point is (5,634)
Step 3
Now, the output when x=10
\(\begin{gathered} f(x)=2x^3-45x^2+300x+9 \\ f(10)=2\cdot10^3-45\cdot10^2+300\cdot10+9 \\ f(10)=2000-4500+3000+9 \\ f(10)=509 \end{gathered}\)inflection point (10,509)
Step 3
so, at x=5 and x=10 we have two inflection points, to know if those points are minimum we need to check the second derivate of the fucntion
\(\begin{gathered} f^{\prime}(x)=6x^2-90x+300 \\ f^{\prime^{\prime}}(x)=12x^{}-90 \end{gathered}\)now, check if f''(x) is greater than zero
a)at x=5
\(\begin{gathered} f^{\prime^{\prime}}(x)=12x^{}-90 \\ f^{\prime^{\prime}}(5)=12\cdot5^{}-90 \\ f^{\prime^{\prime}}(5)=60-90=-30 \\ f^{\prime^{\prime}}(5)=-30 \end{gathered}\)it is smaller than zero, it means (5,634) is a maximum
b)at x=10
\(\begin{gathered} f^{\prime^{}}^{\prime}(x)=12x^{}-90 \\ f^{\prime^{}\prime}(10)=12\cdot10-90 \\ f^{\prime^{}\prime}(10)=120-90 \\ f^{\prime^{}\prime}(10)=30 \end{gathered}\)it is greater than zero, it means (10,509) is a minimum
I hope this helps you
Please help!!!
D is f(x)=500(x+30000)
Answer:
The correct answer is A
Step-by-step explanation:
The books sold are 30,000, so that is our total sale for January. His sales are decreasing by an average of 500 books per month, which means he is losing sales so it is a negative value, and we multiply that by x (number of months) since the question has not stated the number of months. Therefore, the equation would be f(x) = 30,000 - 500x
Hope this is of help!
How do i solve this?
Answer:
Step-by-step explanation:
hello:
(2+4)/-2 = 6/-2 = -3
(2-4)/-2 = -2/-2 = 1
an quadratic equation is : (x+3)(x-1) =x²+2x-3
all quadratic are : a(x+3)(x-1) a in R
Is (x-7) a factor of (x2-5x+14)?
Yes or no
Answer:
Step-by-step explanation:
Is the given equation factorable?
(x - 7)(x - 2) = x^ - 9x + 14 That doesn't work.
-7 * - 2 = 14 but the middle term is - 9 not - 5
x - 7 is not a factor of x^ - 5x + 14
What is?
Something very ugly (x - 2.5 +/- 2.783 i )
A group of 3 workers needs 20 days to do a certain job. How long would it take a group of 4 workers to do the same job, if each worker performs at the same rate?
A. 24
B. 20
C. 18
D. 15
The time that it will take a group of 4 workers to do the same job, if each worker performs at the same rate is D. 15.
What is an expression?It should be noted that an expression simply illustrates the relationship between the variables that are given.
In this case, the group of 3 workers needs 20 days to do a certain job. Let the time taken for the 4 workers be x. This will bee illustrated as:
3/4 = x/20
Cross multiply.
4x = 3 × 20
4x = 60
Divide
x = 60 / 4
x = 15
They will use 15 days to to the job.
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no one got brainiest for my question
Answer:
you have to give it pretty sure
Step-by-step explanation:
4. A container in the shape of a cylinder is 15.5 cm high and has a diameter
of 12.8 cm. How many milliliters of chocolate milk will the container hold
if it is filled to the top? About how many liters would that be?
1993.5232 ml chocolate milk will the container hold if it is filled to the top.
What is Volume?volume is the amount of space in a certain 3D object
Given:
h= 15.5 cm, d= 12.8 cm , r= 6.4 cm
Volume of cylinder,
=πr²h
=3.14*6.4*6.4*15.5
=1993.5232 cm³
=1993.5232 ml
Hence, 1993.5232 ml chocolate milk will the container hold if it is filled to the top.
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Consider the pth percentile of a continuous random variable. Which of the following statements are always true? Select all that apply. The area under the curve to the left of the pth percentile is equal to (1-p). The area under the curve to the right of the pth percentile is equal to p. The area under the curve to the left of the pth percentile is equal to p. The area under the curve to the right of the ph percentile is equal to (1-p). The pth percentile is positive.
The correct statements regarding the pth percentile of a continuous random variable are: the area under the curve to the left of the pth percentile is equal to p, and the area under the curve to the right of the pth percentile is equal to (1-p).
In general, when considering the pth percentile of a continuous random variable, the following statements are always true:
1. The area under the curve to the left of the pth percentile is equal to p: This statement is correct. The pth percentile is the value below which p percent of the data falls. Therefore, the area under the curve to the left of the pth percentile represents p percent of the total area.
2. The area under the curve to the right of the pth percentile is equal to (1-p): This statement is also correct. Since the total area under the curve is equal to 1, the remaining area to the right of the pth percentile is (1 - p).
3. The pth percentile is positive: This statement is not necessarily true. The pth percentile can be positive, zero, or negative depending on the distribution of the random variable. It is possible for a significant portion of the data to fall below zero, resulting in a negative pth percentile.
Therefore, the correct statements are:
- The area under the curve to the left of the pth percentile is equal to p.
- The area under the curve to the right of the pth percentile is equal to (1-p).
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Directions: Find the specified term of the geometric sequences given the first term and the common ratio.
Step-by-step explanation:
As you know
\( a_{n} = a_{1} \times {r}^{n - 1} \)
1.
\(3 \times {3}^{4} = {3}^{5} \\ 3 \times {3}^{6} = {3}^{7} \\ 3 \times {3}^{8} = {3}^{9}\)
2.
\(2 \times {2}^{4} = {2}^{5} \\ 2 \times {2}^{6} = {2}^{7} \\ 2 \times {2}^{8} = {2}^{9}\)
3.
\( - \frac{1}{2} \times {( - 6)}^{4} = { \frac{ - 1}{2} } \times {6}^{4} \\ - \frac{1}{2} \times {( - 6)}^{6} = { \frac{ - 1}{2} } \times {6}^{6} \\ - \frac{ 1}{2} \times {( - 6)}^{8} = { \frac{ - 1}{2} } \times {6}^{8} \)
What is the unit rate per student?
12 students ate 4.5 pizzas
Answer:
5,200rs
Step-by-step explanation:
Answer:
0.37
Step-by-step explanation:
please mark me as brainlest
A medical researcher needs 7 people to test the effectiveness of an experimental drug. If 15 people have volunteered for the test, in how many ways can 7people be selected?
Given:
A medical researcher needs 7 people to test.
15 people have volunteered for the test.
To find:
We need to find a number of ways to select 7 from 15 people.
Explanation:
The number of ways to select 7 from 15 people can be found by the given formula.
\(nC_r=\frac{n!}{r!(n-r)!}\)Substitute n=1`5 and r=7 in the formula.
\(15C_7=\frac{15!}{7!(15-7)!}\)\(15C_7=\frac{15\times14\times13\times12\times11\times10\times9\times8!}{7\times6\times5\times4\times3\times2\times(8)!}\)\(15C_7=15\times13\times11\times3\)\(15C_7=6435\)Final answer:
The number of ways = 6435 ways.
Casey's mom is the baseball coach for his team. She spent $150 on baseballs. Each baseball cost $5. How many baseballs did she buy?
Answer:
nicw
Step-by-step explanation:
150-5=145
3) If 3 folders cost $2.70, then how much would 8 folders cost? *
2p
O (1) $6.90
(2) $7.02
(3) $7.20
(4) $8.13
GUYS HELP MEEEE
Answer:
2.70/3=0.9
0.9x8=7.20
Answer is 3 - $7.20
Find the phasor representation of the following current: i=[300cos(200t+45∘)−100sin(200t−30∘)]A
The phasor representation of the given current expression is i = 150√2e²(j200t) + 50je²(j200t)
To find the phasor representation of the given current:
i = [300cos(200t + 45°) - 100sin(200t - 30°)]A
the current expression in terms of a phasor notation using Euler's formula:
i = Icos(ωt + θ) + jsin(ωt + θ)
Where:
I is the amplitude of the current,
ω is the angular frequency,
t is time,
θ is the phase angle,
j is the imaginary unit (j² = -1).
Comparing this form to the given expression,
Icos(ωt + θ) = 300cos(200t + 45°)
jsin(ωt + θ) = -100sin(200t - 30°)
From the first equation identify:
I = 300
θ = 45°
ωt = 200t
From the second equation identify:
I = 100
θ = -30°
ωt = 200t
To convert the given expressions into the phasor notation combine the real and imaginary parts:
i = (Icosθ + jIsinθ)e²(jωt)
For the first term:
Icosθ = 300cos(45°) = 300 × (√2/2) = 150√2
For the second term:
jsinθ = -100sin(-30°) = -100 ×(-1/2) = 50
Combining the real and imaginary parts,
i = (150√2 + 50j)e²(j200t)
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Darryl is draining a large tank. The tank started with
1200 gallons. Darryl can drain 75 gallons from the
tank each hour. Write an equation that can be used to
find g, the remaining gallons in the tank, after h
hours.
Answer:
Step-by-step explanation:
1200 divided by 75 = 16 hours to drain all of the gallons in the tank
in still water , your small boat averages 8 miles per hour. it takes you the same amount of time to travel 15 miles downstream , with the current , as 9 miles upstream , against the current. what is the rate of the water's current?
Answer:
in still water, a boat averages 8 miles per hour. It takes the same amount of time to travel 30 miles downstream, with the current, as 18 miles upstream, against the current. What is the rate of the water's current.
Step-by-step explanation:
Let c=speed of current in mph
c+8=speed of boat downstream in mph
c-8=speed of boat upstream in mph
Travel time= distance/speed
30/8+c=18/8-c
240-30c=144+18c
48c=96
c=2 mph
ans
rate of water's current = 2 mph
Multiply and simplify.
(3x + 5) (2x^2 – 3x + 2)
Enter your answer, in standard form, in the box.
Answer:
6x³ + x² - 9x +10
Step-by-step explanation:
This one uses typical FOIL multiplication.
We are given the expression (3x + 5) (2\(x^{2}\) – 3x + 2)
Using FOIL, we multiply every term in all ways. We can rewrite the expression as (3x · 2\(x^{2}\)) + (3x · -3x) + (3x · 2) + (5 · 2\(x^{2}\)) + (5 · -3x) + (5 · 2)
Which simplifies to 6x³ - 9x² + 6x + 10x²- 15x + 10
Which we can further simplify to 6x³ + x² - 9x +10
Answer:6x³ + x² - 9x +10
Step-by-step explanation:
a restaurant offers salads with 2 types of lettuce, 3 different toppings, and 3 different dressings. how many different salads could be ordered?
Answer:
36 different salads can be ordered
Step-by-step explanation:
What is the solution set of - lxl= -8?
Answer:
8
Step-by-step explanation:
The absolute value of |x| is x
-x = -8
Distribute the - on the other side but since two negatives make a positive:
- and - = +
x = 8
Hope this helped.
there are 300 pages in a workbook. every chapter has 25 pages. which equation can be solved to find how many chapters are in the workbook?
Number of chapters in the workbook = 12
What is a linear equation?
An algebraic equation of the form y=mx+b is referred to as a linear equation. m is the slope, and b is the y-intercept, and all that is involved is a constant and a first-order (linear) term. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables." from Wolfram MathWorld: linear.Total number of pages = 300
1 Chapter = 25 Pages
Divide 300 by 25 to figure out the total number of chapters in the workbook.
Number of chapters in the workbook = 300/25 = 12
Therefore, Number of chapters in the workbook = 12
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Can a line be measured?
Answer:
yeah .It can be measured
PLEASE HELP xoxo The students at Christina's school voted for a new school color. 10 students voted for orange and the other 90 students voted for purple. What percentage of the students voted for orange?
Answer:
10%
Step-by-step explanation:
10+90= 100 students total
10 is 10% of 100
Percentage:
The ratio of the volume of water in a glass jar to the volume of water in a ceramic jar is 2:3. If the volume of water in the glass jar is increased by 200%, by what percentage should the volume of water in the ceramic jar be increased such that both jars each end up with the same volume of water?
Answer:
100%
glass.......x
ceramic....y
x:y = 2:3
x/y = 2/3
after the increase in both jars:
3x:ny = 1:1
3x/ny = 1
3/n × x/y = 1
3/n × 2/3 = 1
3/n = 3/2
n = 2
volume of vater in the ceramic (y) is two times larger than before
2y = y + y = y + 100%y
you increased one more time the original volume of water or 100% of the original volume
what are the effects of cross-linking in polymers?
In addition to decreasing , solubility, and permeability, cross-linking improves polymer strength, stiffness, and temperature resistance.
The process of creating chemical linkages between polymer molecules to form a three-dimensional network is known as cross-linking. The polymer is stronger and more rigid thanks to this network of molecules, which also boosts its resistance to heat and chemicals. In addition to increasing the polymer's durability and resistance to environmental changes, cross-linking also decreases the polymer's flammability, solubility, and permeability. The polymer becomes more stable and less prone to deformation as a result of cross-linking, which also raises the melting point of the polymer. A polymer's characteristics can be modified by cross-linking to fit the needs of certain applications. For instance, cross-linking might be to boost a polymer's strength to satisfy. For example, cross-linking can be employed to make a polymer stronger to fulfil the demands of a particular application or less flammable to make it safer to use. In a variety of sectors, cross-linking is a crucial component of polymer chemistry and polymer engineering.
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Graph the system of equations on your graph paper to answer the question.
Y=x-4
g= -3+6
What is the solution for this system of equations?
Enter your answer in the boxes.
April is arranging place cards for a wedding reception on a table the brides fa
Using the greatest common factor, it is found that the greatest number of cards that she can place in a row is of 14.
How to find the greatest number of cards that she can place in a row?The number of cards for each family is given as follows:
April's family: 154.Groom's family: 140.We want to find a way to distribute them having the same number of cards in each row, hence this is possible finding the greatest common factor (GCF) of the numbers of 154 and 140.
The GCF is found factoring both numbers 154 and 140 simultaneously by prime factors, as follows:
154 - 140|2 (both 154 and 140 are divisible by 2).
77 - 70|7 (both 77 and 70 are divisible by 11).
11 - 7
There are no numbers for which both 11 and 7 are divisible by, hence the greatest number of cards that she can place in a row is:
gcf(154, 140) = 2 x 7 = 14.
Missing information
The complete problem is:
April is arranging place cards for a wedding reception on a table. The bride's family has 154 cards and the groom's family has 140 cards. She wants the arrangements for the two families to have the same number of cards in each row. What is the greatest number of cards that she can place in a row?
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