Solve the given equation w+19=47

Answer:

see below

Step-by-step explanation:

4x - 4(30-2x)=24

4x-120+8x=24

12x=144

X=12

then substitute

2(12) + y =30

y=30-24

y=6

9514 1404 393

Answer:

Step-by-step explanation:

If all of Brent's coins were pennies, their value would be 1.63. The value is actually 4.42 -1.63 = 2.79 more than that. Replacing a penny by a dime increases the value by .09. Hence there must be 2.79/.09 = 31 replacements.

Brent has 31 dimes and 132 pennies.

_____

Solution using an equation

You can write an equation that solve the problem in basically the same way. Let the variable represent the number of coins of highest value: d = dimes. Then the value (in cents) of the collection is ...

  1(163-d) +10d = 442

  9d +163 = 442 . . . . . . . . . . simplify (note 9 is the difference in value; 163 is the value of all pennies)

  9d = 442 -163 = 279 . . . . . . subtract 163

  d = 279/9 = 31 . . . . . . . . . . divide by 9

Brent has 31 dimes and 163-31 = 132 pennies.

Answer:

Step-by-step explanation:

Using the inscribed angle theorems, the measure of the indicated angles are:

1. m∠BOA = 26°

2. m∠BDA = 13°

3. m∠BCA = 13°

Based on the inscribed angle theorem, the following relationships are established:

Given:

Intercepted arc BA = 26°

1. ∠BOA is central angle

Thus:

m∠BOA = 26° (inscribed angle theorems)

2. ∠BDA is inscribed angle.

m∠BDA = 1/2(30) = 13° (inscribed angle theorems)

3. m∠BCA = m∠BDA = 13° (inscribed angle theorems)

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Answer:

40

Step-by-step explanation:

Try to get the variable alone by dividing 5/8 on both sides of the equations.

That cancels out the 5/8 on the left leaving u and the 25 on the right turns into 40. It turns into 40 because 25 divided by 5/8 equals 40.

Answer:

40

Step-by-step explanation:

Multiply both sides by 8/5

Answer:

Step-by-step explanation:

four times the sum of a number and 9 is 16

4 *(x + 9) = 16

4x + 36 = 16

4x = 16 - 36

4x = -20

x = -5

---------------

4 * (-5 + 9) = 16

16 = 16

true

$3200

The profit-maximizing quantity will take place where MR = MC—or at the last possible point before marginal costs start surpassing marginal revenue. The amount of goods produced at which marginal revenue equals marginal cost, or when MR = MC, is the decision that will maximize profits for the monopoly. If the monopoly produces less, MR > MC at given production levels, and the enterprise can increase profits by increasing output.

While a company produces more, MC > MR prevails, allowing it to increase profits even when it produces less overall. Therefore:

MC = change in total cost/change in quantity

      Change in quantity = 100 at each unit

      Change in total cost at 400 units = 2760 - 1960 = 800

      MC at 400 units  = 800/100 = 8

Under perfect competition, profit maximizing condition is where;

      P = MC

      At 400 units, P = MC = 8

Implies profit maximizing quantity is 400 units.

      Total revenue = Price x Quantity = 8 x 400 = $3200

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The case fatality rate is 400 * 100 / 1500 = 26.67 (option d).

For the first scenario, the data determine that there is a difference in average expenditure between the two countries (option c). The P-value of 0.063 suggests that there is a moderate level of statistical significance, indicating that the difference in average expenditure is likely not due to random chance.

In the second scenario, the fact that the 95% confidence interval for the average number of times participants saw their provider per year (3.3) ranges from 0.1 to 6.1 is of statistical use because it provides a range estimate within which the true population means is likely to fall. This interval helps account for the uncertainty associated with the sample estimate and provides a measure of the precision of the estimate (option a).

For the third scenario, the average operating margin is appropriate to use because it is a measure of central tendency that represents the typical financial performance of rural hospitals. The standard deviation provides information about the variability of the operating margins (option d).

In the fourth scenario, the consideration factor that will ultimately contribute to the spread of Ebola is the population density of the affected area (option b). While factors like the influence of non-indigenous people and climatic conditions may play a role, population density is a key determinant in the transmission and spread of infectious diseases.

For the fifth scenario, the case fatality rate is calculated by dividing the number of deaths from the disease (400) by the total reported cases (1500) and multiplying by 100. Therefore, the correct calculation is 400 * 100 / 1500 = 26.67 (option d). This indicates that the case fatality rate is approximately 26.67%.

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The amplitude, period, and midline of f(x) = -4 cos(2x - π) + 3 are 4, π and 3.

Given, the function is f(x) = -4 cos(2x - π) + 3 ---- (1)

We have to find the amplitude, period and midline of the function.

The standard form of a cosine function is,

g(x) = a cos(bx + c) + d --- (2)

Where, a is amplitude,

Period is 2π/b

d is midline

Comparing (1) and (2)

a = -4

b = 2

d = 3

Amplitude of the function is a = 4

The period of the function is

2π/b = 2π/2

Period = π

Midline of the function is d = 3

Therefore, the amplitude, period and midline of the function are 4 ,π and 3.

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For the situation where the null hypothesis (H0) is p=0.7 and the alternative hypothesis (HA) is p≠0.7 at α=0.01, we need to find the critical value(s) for z.

a)Since the alternative hypothesis is two-tailed (p≠0.7), we will divide the significance level (α) equally between the two tails. Thus, α/2 = 0.01/2 = 0.005. By looking up the corresponding value in the z-table, we can find the critical value. The critical value for a two-tailed test at α=0.005 is approximately ±2.58.

b) In the scenario where H0: p=0.5 and HA: p>0.5 at α=0.01, we are dealing with a one-tailed test because the alternative hypothesis is p>0.5. To find the critical value for t, we need to determine the value in the t-distribution with (n-1) degrees of freedom that corresponds to an area of α in the upper tail. Since α=0.01 and the degrees of freedom are not given, we cannot provide an exact value. However, if we assume a large sample size (which is often the case with hypothesis testing), we can use the normal distribution approximation and the critical value can be obtained from the z-table. At α=0.01, the critical value for a one-tailed test is approximately 2.33.

c) When H0: μ=20 and HA: μ≠20 at α=0.01, we are conducting a two-tailed test for the population mean. To find the critical value for z, we need to divide the significance level equally between the two tails: α/2 = 0.01/2 = 0.005. By looking up the corresponding value in the z-table, we find that the critical value for a two-tailed test at α=0.005 is approximately ±2.58.

d) In the situation where H0: p=0.7 and HA: p>0.7 at α=0.10 with n=340, we are performing a one-tailed test for the population proportion. To find the critical value for z, we need to determine the value in the standard normal distribution that corresponds to an area of (1-α) in the upper tail. At α=0.10, the critical value is approximately 1.28.

e) For H0: μ=30 and HA: μ<30 at α=0.01 with n=1000, we have a one-tailed test for the population mean. Similar to situation (b), assuming a large sample size, we can approximate the critical value using the z-table. At α=0.01, the critical value for a one-tailed test is approximately -2.33.

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(a) Find the dual of the LP.Primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\) subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n \leq\) \(b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n \leq b_m$ and $x_1, x_2,\)..., x_n\(\geq 0$\)

Let us find the dual of the above primal problem.

Dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq\)\(C_1$...$a_{1n}y_1+a_{2n}y_2+...+a_{mn}y_m \leq C_n$\)

and\($y_1, y_2, ..., y_m \geq 0$\)

(b) Find the standard form of the LP and dual.Standard form of the primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\)subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n +s_1 = b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n +s_m = b_m$\) and\($x_1, x_2, ..., x_n, s_1, s_2, ..., s_m \geq 0$\)

Standard form of the dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq 0$...$a_{1n}y\)

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Your answer is x=1/3

Good luck with your test!~ ^^

In the triangle, the values are p=10.3, \(\angle Q=19.5\textdegree\) and \(\angle R = 112.5\textdegree\).

The functiοns οf an angle in a triangle are knοwn as trigοnοmetric functiοns, cοmmοnly referred tο as circular functiοns. In οther wοrds, these trig functiοns prοvide the relatiοnship between a triangle's angles and sides. There are five fundamental trigοnοmetric functiοns: sine, cοsine, tangent, cοtangent, secant, and cοsecant.

Here in the given triangle PQR, \(\angle P = 48\textdegree\) , q=5 and r=13.

Now using law of cosine fοrmula,

=> \(p^2=q^2+r^2-2qr.cos\angle P\)

=> \(p^2=5^2+13^2-2.5.13.cos 48\textdegree\)

=> \(p^2=25+169-130cos48\textdegree\)

=> \(p^2=107\)

=> p = 10.3

Now using law of sine then,

=> \(\frac{p}{sinP}=\frac{q}{sinQ}\)

=> \(sinQ=\frac{q sinP}{p}\)

=> \(sin Q= \frac{5sin 48\textdegree}{10.3}\)

=> sin Q = 0.344

=>\(\angle Q = 19.5\textdegree\)

Now sum οf all angles in triangle is 180°. Then,

=>\(\angle P+\angle Q+\angle R = 180\textdegree\)

=> \(\angle R = 180-48-19.5=112.5\textdegree\)

Hence the answers are p=10.3, \(\angle Q=19.5\textdegree\) and \(\angle R = 112.5\textdegree\).

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The Michelson-Morley experiment was conducted in 1887 to detect the existence of the luminiferous ether, which was thought to be the medium through which light traveled.

Here is the procedure for the Michelson-Morley experiment:

1. Set up a light source, a half-silvered mirror, two mirrors, and two detectors in a square configuration.

2. Split the light beam using the half-silvered mirror so that one beam goes to one mirror and the other beam goes to the other mirror.

3. Reflect the beams back to the half-silvered mirror and combine them to produce an interference pattern.

4. Rotate the entire apparatus by 90 degrees and repeat the measurement.

5. Compare the interference patterns from the two orientations.

If there is a luminiferous ether, the speed of light should be faster in the direction of the ether flow and slower in the perpendicular direction. This should produce a difference in the interference patterns.

However, the Michelson-Morley experiment showed that there was no difference in the interference patterns, indicating that the luminiferous ether did not exist.

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Based on this information, No, the university administration should not trust the professor because the study was not taken from a random sample of scholarship athletes. Hence option C is correct.

According to the mentioned question, a university professor investigates how the sample was gathered since he does not think that there is a true difference in the GPA of male and female scholarship athletes. His inquiry reveals that the study was exclusively distributed to the basketball teams' athletes.

According to this data, the university administration shouldn't believe the professor because the study's participant pool did not consist of a representative sample of scholarship athletes.

The sample may not be representative of all university scholarship athletes since the study solely looks at basketball players. This may skew the results and make it challenging to extrapolate the conclusions to the larger group of scholarship athletes.

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Answer:

-45&-5 or -49&-1

Step-by-step explanation:

-45+(-5)

= -50

-49-1

= -50

Answer:

Hi I'm learning the same thing and I just got it I think it's C=43.98cm

Given:

The functions are:

\(f(x)=|3x-5|+7x\)

\(g(x)=-2x+9\)

To find:

The function \((f+g)(x)\).

Solution:

We have,

\(f(x)=|3x-5|+7x\)

\(g(x)=-2x+9\)

We know that,

\((f+g)(x)=f(x)+g(x)\)

On substituting the values of given functions, we get

\((f+g)(x)=|3x-5|+7x+(-2x+9)\)

\((f+g)(x)=|3x-5|+7x-2x+9\)

\((f+g)(x)=|3x-5|+5x+9\)

Therefore, the required function is \((f+g)(x)=|3x-5|+5x+9\).

Answer:

Bianca would be able to afford her dream car conveniently when she turns 16.

Step-by-step explanation:

Bianca was 5 years and wish to project her savings for the next 11 years.

On her 5th birthday, she saves $100

Her dad promises to double her money yearly with respect to a condition. So that;

On her 6th birthday, she would save $ 200

On her 7th birthday, she would save $400

On her 8th birthday, she would save $800

On her 9th birthday, she would save $1600

On her 10th birthday, she would save $ 3200

On her 11th birthday, she would save $ 6400

On her 12th birthday, she would save $12800

On her 13th birthday, she would save $25600

On her 14th birthday, she would save $51200

On her 15th birthday, she would save $102400

On her 16th birthday, she would save $204800

When she turns 16, she would have a total sum of $409500.

Therefore, Bianca would be able to afford her dream car conveniently when she turns 16.

Math SAT scores explain about 98.7% of the variation in the total SAT scores.

In statistics, correlation or dependence exists as any statistical relationship, whether causal or not, between two random variables or bivariate data.

A correlation exists as a statistical measure (expressed as a number) that defines the size and direction of a relationship between two or more variables. A correlation between variables, however, does not automatically mean that the change in one variable exists as the cause of the change in the values of the other variable.

Since r² exists = (0.9935)² = 0.9870, we interpret r² as 98.7% of the variation in the y variable exists explained by the x variable.

In context, math SAT score explains about 98.7% of the variation in total SAT score.

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The simplified rational expressions are given as follows:

The first rational expression is given as follows:

\(\sqrt[5]{288p^7}\)

The number 288 can be simplified as follows:

\(288 = 2^5 \times 3^2\)

\(p^7\), can be simplified as \(p^7 = p^5 \times p^2\), hence the simplified expression is given as follows:

\(\sqrt[5]{2^5 \times 3^2 \times p^5 \times p^2} = 2p\sqrt[5]{9p^2}\)

(as we simplify the exponents of 5 with the power)

The second expression is given as follows:

\((216r^{9})^{\frac{1}{3}}\)

We have that 216 = 6³, hence we can apply the power of power rule to obtain the simplified expression as follows:

Hence the simplified expression is of:

\((216r^{9})^{\frac{1}{3}} = 6r^3\)

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Answer:

B. 1 1/7

Step-by-step explanation:

Pls, choose me as brainliest!

Answer:

A(an)   altitude    of a prism is a perpendicular segment that joins the planes of the bases. (The height h is the length of one.)

Step-by-step explanation:

AN ALTITUDE -  An altitude of a triangle is a line segment that passes through a vertex and is perpendicular to (i.e. forms a right angle with) the base line (the side opposite the vertex). The expanded base of the altitude is the line that contains the opposing side. The foot of the altitude is the point where the extended base meets the altitude. The area of a triangle can be calculated using altitudes: one half of the product of an altitude's length and its base's length equals the triangle's area. As a result, the longest altitude is perpendicular to the triangle's shortest side. Through trigonometric functions, the heights are also connected to the triangle's sides.

Hence , the answer is an altitude .

Answer:

1) \(1.276 \times 10^{7}\,m\), 2) \(5.101 \times 10^{8}\,km^{2}\), 3) \(5.974 \times 10^{24}\,kg\), 4) \(7.723\times 10^{9}\), 5) \(1.350 \times 10^{18}\), 6) \(3.618\times 10^{8}\,km^{2}\)

Step-by-step explanation:

(This exercise is written in Portuguese and for that reason explanation will be held in Spanish, which has strong similarities with that language)

La notación científica presenta el siguiente formato:

\(x.y \times 10^{n}\)

Donde:

\(x\) - Un dígito entero.

\(y\) - Dígitos decimales consecutivos.

\(n\) - Grado de potencia.

Para cálculos cotidianos se recomienda el uso de tres decimales consecutivos. A continuación, se presentan los números convertidos a la forma de notación científica:

1) \(12.756.000\,m\)

El grado de la potencia es siete (7).

\(1.276 \times 10^{7}\,m\)

2) \(510.072.000\,km^{2}\)

El grado de la potencia es ocho (8).

\(5.101 \times 10^{8}\,km^{2}\)

3) \(5.973.600.000.000.000.000.000.000\,kg\)

El grado de la potencia es veinticuatro (24).

\(5.974 \times 10^{24}\,kg\)

4) \(7.722.522.000\)

El grado de la potencia es nueve (9).

\(7.723\times 10^{9}\)

5) \(1.350.000.000.000.000.000\)

El grado de la potencia es dieciocho (18).

\(1.350 \times 10^{18}\)

6) \(361.800.000\,km^{2}\)

El grado de la potencia es ocho (8).

\(3.618\times 10^{8}\,km^{2}\)

Answer:

-3<y<3 The filled in dot means 3 is greater than or equal to.

Answer:

15

Step-by-step explanation:

32 + 2* -4 - 9

32 - 8- 9

32 - 17

=15

Answer:

C

Step-by-step explanation:

32 + 2n - 9

23 + 2n

23 + 2(-4)

23 - 8

15

Best of Luck!

Answer:

the answer is 0.29

Step-by-step explanation:

hope this helps! :D

Answer:

0.29

Step-by-step explanation:

Hope this helped!

The quotient of 13 ÷ 8 as a mixed number is 1 5/8.

what is quotient?

In mathematics, a quotient refers to the result of dividing one number (the dividend) by another number (the divisor). It is the number of times the divisor can be subtracted from the dividend without producing a negative result.

what is mixed number ?

A mixed number has both  whole number and a fraction. It is a way of representing a number that is larger than one, but not a whole number. A mixed number is written as a whole number followed by a fraction, where the fraction represents a part of a whole.

In the given question,

To find the quotient of 13 ÷ 8 as a mixed number, we can follow these steps:

Divide 13 by 8:

Write the quotient (1) as the whole number part of the mixed number, and write the remainder (5) as the numerator of the fraction part. The denominator of the fraction part is the same as the divisor (8).

Therefore, the quotient of 13 ÷ 8 as a mixed number is 1 5/8.

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Solving an equation in algebra - mathematics will BOMDAS rule. Multiplication, division, addition, and subtraction are performed before.

However, in order to simplify things, if there are any exponential or logarithmic components, solve them first before applying BOMDAS to reduce them to a single solvable term. This is required by the rules.

So the list goes as

1. Exponents

2. Roots

3. Multiplication

4. Division

5. additional

6. Subtraction

However. Using a regular or scientific calculator will generate a lot of debate. A scientific calculator will adhere to the principles, while a typical calculator will evaluate from left to right or precisely the operator used first.

Using a scientific calculator, 5+2x3=11 instead of the normal one's 5+2x3=21.

Furthermore, the preferred behavior norm for division and multiplication is different.

Thus, people's difficulty with mathematics is not unjustified. The choice of how you want to approach it is ultimately up to you.

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Answer:

x = 83 degree

Step-by-step explanation:

x + 43 = 126 (sum of two interior opposite angle is equal to the exterior angle formed)

x = 126 - 43

x = 83 degree

Answer:

83 degrees

Step-by-step explanation:

To find this you first find the angle opposite to 126. To do this you subtract 126 from 180 as 180 degrees is a straight line, and we are looking for that missing angle.

This equals 54 degrees.

Now, 54 + 43 equals 97.

Because all interior angles of a triangle always equal 180, you can find that last angle by subtracting 97 from 180. This leaves you with 83 degrees.

The answer is true. A random variable is a variable whose value is subject to variations due to chance. The variance of a random variable measures how spread out its values are.

It is a measure of the average distance between the values of the variable and its expected value. In this case, V(cX) represents the variance of a new random variable obtained by multiplying X by a constant c. According to the properties of variance, V(cX) = c^2 V(X). Therefore, the equation V(cX) = 4V(X) can be rewritten as c^2 V(X) = 4V(X).
Dividing both sides of the equation by V(X), we get c^2 = 4. Taking the square root of both sides, we obtain c = 2 or c = -2. However, since c represents a scaling factor, we can disregard the negative solution. Therefore, c must be 2.
In conclusion, if V(cX) = 4V(X), then c must be 2. This result shows that multiplying a random variable by a constant affects its variance by the square of that constant.

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