Isolate the variable by dividing each side by factors that don't contain the variable.
t=\(\frac{d}{r}\)
Sam feels that students score better on math tests that take place on Fridays. The school provides Sam with the school math test average, but they cannot separate them by date taken. The school is too large for him to ask every student, so he randomly selects a sample of willing students' test scores after the next Friday's math test. He uses the method of hypothesis testing to compare the Friday scores against the true average of all scores. Frame the correct set of hypotheses for his research. Decide where the rejection region will lie.
Answer:
H0 : μ ≤ x
H1 : μ > x
The hypothesis :
The null hypothesis, H0 : μ ≤ x
The alternative hypothesis, uses the Friday score samples to compare the hypothesis ;
The alternative hypothesis, H1 : μ > 8
For then null, the mean scores is assumed to be the same, and has such mean of Friday's test score takes the value of the population.
Let the population mean value = x
The alternative hypothesis is the claim that the sampled mean gives a greater value than the population mean :
H1 : μ > x
A researcher studies the amount of trash (in kgs per person) produced by households in city X. Previous research suggests that the amount of trash follows a distribution with density fθ(x) = θx^θ-1 / 9⁰ for x ϵ (0,9). The researcher wishes to verify a null hypothesis that θ = 14/10 against the alternative that θ = 14/11, based on a single observation. The critical region of the test she consideres is of the form C = {X < c}. The researcher wants to construct a test with a significance level a = 26.9/1000.
Find the value of C.
Provide the answer with an accuracy of THREE decimal digits.
Answer: _______
In the situation described above, calculate the power of the test for the alternative hypothesis. Provide the answer with an accuracy of THREE decimal digits.
Answer: ______
In the situation described above, provide the probability of committing an error of the second type. Provide the answer with an accuracy of THREE decimal digits.
Answer: ______
To find the value of C for the critical region, we need to determine the cutoff point below which we will reject the null hypothesis. In this case, the critical region is defined as C = {X < c}. To construct a test with a significance level of α = 26.9/1000, we need to find the corresponding quantile from the distribution.
To find the value of C, we calculate:
∫[0 to c] fθ(x) dx = α
∫[0 to c] θx^(θ-1) / 90 dx = 26.9/1000
Integrating the above expression, we get:
θ/90 * [x^θ / θ] [0 to c] = 26.9/1000
Simplifying further:
(c^θ / θ) / 90 = 26.9/1000
c^θ = (θ * 26.9 * 9) / (θ * 100)
c = [(θ * 26.9 * 9) / (θ * 100)]^(1/θ)
Now we can substitute the given values of θ = 14/10:
c = [(14/10 * 26.9 * 9) / (14/10 * 100)]^(10/14)
c = 0.400 (rounded to three decimal places)
Therefore, the value of C is 0.400.
To calculate the power of the test for the alternative hypothesis, we need to determine the probability of rejecting the null hypothesis when the alternative hypothesis is true.
Power = P(rejecting H0 | H1 is true)
Since we have a single observation, the power can be calculated as the probability of the observation falling in the critical region C when θ = 14/11.
Power = P(X < c | θ = 14/11)
Using the distribution function fθ(x) = θx^(θ-1) / 90, we can integrate from 0 to c with θ = 14/11:
∫[0 to c] fθ(x) dx = ∫[0 to c] (14/11) * x^(14/11 - 1) / 90 dx
Simplifying and integrating, we get:
∫[0 to c] (14/99) * x^(3/11) dx = Power
To evaluate this integral, we need to know the value of c, which we have already found to be 0.400. Substituting c = 0.400 into the integral expression and calculating, we get:
Power ≈ 0.302 (rounded to three decimal places)
Therefore, the power of the test for the alternative hypothesis is approximately 0.302.
The probability of committing an error of the second type is equal to 1 - Power. Probability of error of the second type ≈ 1 - 0.302 ≈ 0.698 (rounded to three decimal places). Therefore, the probability of committing an error of the second type is approximately 0.698.
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ZA and ZB are
m/A = (6x - 15)° and
m/B = (5x + 6)°, then find the
measure of A.
complementary angles. If
39-degree is the measure of the angle A.
What are complementary angles?When the sum of two angles is equal to 90 degrees, they are called complementary angles. For example, 30 degrees and 60 degrees are complementary angles.
Given, ∠A and ∠B are complementary angles
If ZA and ZB are complementary angles, then their measures add up to 90 degrees.
So, we can set up the following equation:
m/A + m/B = 90
Substituting the given measures, we get:
(6x - 15) + (5x + 6) = 90
Combining like terms, we get:
11x - 9 = 90
Adding 9 to both sides, we get:
11x = 99
Dividing both sides by 11, we get:
x = 9
Now that we know the value of x, we can find the measure of angle A:
m/A = (6x - 15)° = (6 * 9 - 15)° = 39°
Therefore, the measure of angle A is 39 degrees.
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What fraction of 60 is 90?
50 POINTS OwO
Step-by-step explanation:
90 / 60 = 3/2
When you multiply 3/2 with 60, you get 90.
Hence 3/2 of 60 is 90.
calculate mpg for w=1000,w=2000;calculate weight when mpg=30
Based on the information above, the car with 1,000 pounds more will only go 1,194 miles, and the one with 2,000 pounds more will only go 1,188 miles.
What does MPG stand for?MPG stands for miles per gallon, and refers to the distance in miles a vehicle travels for each gallon of fuel in its tank.
In general, a car consumes about 1,200 miles per gallon. However, when you add load to it, its fuel consumption is higher because it requires more force to move.
Additionally, some studies state that for every 1,000 pounds of weight added to the car, it will yield 0.5% less. So if the car has 1,000 more pounds, it's not going to go 1,200 miles per gallon, it's going to go 1,194 miles.
On the other hand, if 2,000 pounds of weight were added, the fuel economy would be 1% less, that is, it would travel 1,188 miles per gallon.
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Can someone please help??
Picture is below
Answer: 24
Step-by-step explanation:
all you have to do is 8x4=24. :) ur welcome
Answer:
I think its 32
A bottle of eyedrops holds 60 milliliters of fluid. H
ow is 60 milliliters expressed in liters?
Answer:
60 milliliters is expressed as 0.06 in liters
Step-by-step explanation:
The radius of a circle is 333 units. What is the diameter of the circle?
Answer: 666
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
consider rolling dice and getting a total of 8 which is more likely: rolling a total of 8 when two dice are rolled or rolling a total of 8 when three dice are rolled?
Rolling a total of 8 when two dice are rolled is more likely than rolling a total of 8 when three dice are rolled.
This is because there are more combinations of two dice that can add up to 8 (four combinations; 1-7, 2-6, 3-5, 4-4) than there are combinations of three dice (three combinations; 1-3-4, 2-2-4, 3-3-2).
Therefore, the probability of rolling a total of 8 with two dice is greater than the probability of rolling a total of 8 with three dice.
Additionally, the odds of rolling a total of 8 with two dice can be calculated using the formula (Number of favourable outcomes/Total number of outcomes) x 100%.
In this case, the formula would be (4/36) x 100%, which equals 11.11%. The odds of rolling a total of 8 with three dice is calculated using the same formula, which would be (3/216) x 100%, which equals 1.39%.
This shows that the odds of rolling a total of 8 with two dice is much greater than the odds of rolling a total of 8 with three dice.
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Given a list of candy in a field called Item and prices called Price on an empty PivotTable, how would you find out how many of each type of candy you have?
Answer:
Drag Item to both the VALUES and the ROWS area
Step-by-step explanation:
To find out how many of each type of candy you have; Drag Item to both the VALUES and the ROWS area
Let f(x)=x
2/3
+6 (a) Is f continuous at x=0 ? Yes No (b) Is f differentiable at x=0 ? Yes No
(a) No, f(x) is not continuous at x = 0.
(b) No, f(x) is not differentiable at x = 0.
(a) To determine if f(x) is continuous at x = 0, we need to check if the limit of f(x) as x approaches 0 exists and is equal to the value of f(0).
In this case, as x approaches 0, the expression x^(2/3) approaches 0, but the constant term 6 remains.
Therefore, the limit of f(x) as x approaches 0 does not exist since the terms do not approach a common value.
Additionally, the value of f(0) is 6. Since the limit does not exist or is not equal to f(0), f(x) is not continuous at x = 0.
(b) To determine if f(x) is differentiable at x = 0, we need to check if the derivative of f(x) exists at x = 0.
The derivative of f(x) is obtained by finding the derivative of each term separately and combining them.
However, the expression x^(2/3) does not have a derivative at x = 0 because the power 2/3 is not defined for negative values.
Therefore, the derivative of f(x) does not exist at x = 0, and f(x) is not differentiable at x = 0.
In summary, the function f(x) = x^(2/3) + 6 is not continuous at x = 0 because the limit of f(x) as x approaches 0 does not exist or is not equal to the value of f(0).
Additionally, f(x) is not differentiable at x = 0 because the expression x^(2/3) does not have a derivative at x = 0.
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On a certain hot summer day, 481 people used the public swimming pool. The daily prices are $1. 25 for children and $2. 25 for adults. Receipts for admission totaled $865. 25. How many children and how many adults swam at the public pool that day?
There were 481 people that utilized the public swimming pool that day, including 217 children and 264 adults.
what is equation ?An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence. In algebra, an equation is a mathematical statement that establishes the equality of two mathematical expressions. For instance, an equal sign separates the components 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula is used to express the connection between two phrases on either side of a letter.
given
The number of children =X=217
The number of adults=264
Let say the number of children are denoted by X
Then the number of adults are (481-X)
Price for children =1.25X
Price for adults=2.25(481-X)
Price for children +Price for adults=865.25
1.25X+2.25(481-X)=865.25
Solving for X:
1.25X+1082.25-2.25X=865.25
-X=865.25-1082.25
-X=-217
X=217
The number of children =X=217
The number of adults=(481-X)
The number of adults=(481-217)
The number of adults=264
There were 481 people that utilized the public swimming pool that day, including 217 children and 264 adults.
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Wednesday
A small package of 12 pencils costs $2.04. A large package of 60 pencils costs $9.60. Which is a
better deal? How do you know?
You can use a calculator but you must show your work and explain your thinking.
Answer:
60 pencil
Step-by-step explanation:
60 divided by 12 is 5
5 times $2.04= 10.2
so if you buy the 12 pack you would be spending more money!
When looking at a graph of a quadratic, how can you tell the solutions are complex numbers?
Answer:
the solutions are where the parabola crosses the x-axis; therefore, if the parabola does not cross the x-axis then the solutions can be considered to be imaginary (for example, the square root of a negative)
Step-by-step explanation:
Consider a scheduling problem, where there are five activities to be scheduled in four time slots. Suppose we represent the activities by the variables A,B,C,D, and E, where the domain of each variable is {1,2,3,4} and the constraints are A>D,D>E,C
=A,C>E,C
=D,B≥A, B
=C, and C
=D+1 [Before you start this, try to find the legal schedule(s) using your own intutions.] (a) Show how backtracking solves this problem. To do this, you should draw the search tree generated to find all answers. Indicate clearly the valid schedule(s). Make sure you choose a reasonable variable ordering. To indicate the search tree, write it in text form with each branch on one line. For example, suppose we had variables X,Y, and Z with domains t,f and constraints X
=Y and Y
=Z. The corresponding search tree is written as:
X=tY=t
Y=f
X=fY=tZ=t failure
Y=f failure
failure
Z=t solution
Z=f failure
Z=f solution
[Hint: It may be easier to write a program to generate such a tree for a particular problem than to do it by hand.] (b) Show how arc consistency solves this problem. To do this you must - draw the constraint graph; - show which elements of a domain are deleted at each step, and which arc is responsible for removing the element; - show explicitly the constraint graph after arc consistency has stopped; and - show how splitting a domain can be used to sove this problem.
a) The backtracking algorithm starts by assigning a value to the first variable, A. b) The arc consistency algorithm works by iteratively removing elements from the domains of the variables.
a) Backtracking
The backtracking algorithm starts by assigning a value to the first variable, A. There are four possible values that A can take, so the algorithm will explore four branches. For each branch, the algorithm then assigns a value to the second variable, B. There are four possible values that B can take, so the algorithm will explore another four branches. The algorithm continues in this way, assigning values to the variables one at a time.
The backtracking algorithm will eventually find a solution if there is one. However, the algorithm may also explore many branches that do not lead to a solution. This is because the backtracking algorithm does not consider the constraints until it has assigned a value to all of the variables.
The search tree for the scheduling problem is shown below.
A=1B=2C=3D=4E=1
A=1B=2C=3D=4E=2
A=1B=2C=3D=4E=3
A=1B=2C=3D=4E=4
A=1B=3C=2D=4E=1
A=1B=3C=2D=4E=2
A=1B=3C=2D=4E=3
A=1B=3C=2D=4E=4
A=2B=1C=3D=4E=1
A=2B=1C=3D=4E=2
A=2B=1C=3D=4E=3
A=2B=1C=3D=4E=4
A=2B=3C=1D=4E=1
A=2B=3C=1D=4E=2
A=2B=3C=1D=4E=3
A=2B=3C=1D=4E=4
b) Arc Consistency
The arc consistency algorithm works by iteratively removing elements from the domains of the variables. The algorithm starts by considering all of the arcs in the constraint graph. For each arc, the algorithm checks if there is any value in the domain of the first variable that is inconsistent with any value in the domain of the second variable. If there is any such value, the algorithm removes the value from the domain of the first variable.
The arc consistency algorithm continues in this way, iteratively removing elements from the domains of the variables. The algorithm terminates when no more elements can be removed.
The constraint graph for the scheduling problem is shown below.
A-------D
A-------E
B-------A
B-------C
C-------E
The arc consistency algorithm will remove the following elements from the domains of the variables:
A: 1, 4
B: 2, 4
C: 2, 4
D: 1, 3
E: 1, 3
After arc consistency has stopped, the constraint graph will be as follows:
A-------D
B-------C
C-------E
The arc consistency algorithm has reduced the size of the search space by removing 12 elements from the domains of the variables. This means that the backtracking algorithm will only have to explore 24 branches instead of 32 branches.
Splitting a Domain
The arc consistency algorithm can be used to solve the scheduling problem by splitting the domain of the variable D. The domain of D can be split into two sets: {1, 2} and {3, 4}. The arc consistency algorithm will then be able to find a solution to the problem by assigning a value to D from each of the two sets.
The following is the solution to the scheduling problem using splitting a domain:
A=1
B=2
C=3
D=1
E=4
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I NEED HELPPPPPPPPPPPPPPPPPPPPP
Answer:
Step-by-step explanation:
huh???????????????
Solve: Sin(11 pi/2 + x) = -1/2 for [Pi, 2Pi].
StartFraction 4 pi Over 3 EndFraction
StartFraction 5 pi Over 3 EndFraction
StartFraction 7 pi Over 6 EndFraction
StartFraction 11 pi Over 6 EndFraction
Answer: B
The answer above is correct. It would be 5pi/3.
Step-by-step explanation: Edge2021
I just got it right on my quiz.
The value of the x is equal to the 5pi/3.
The expression is
\(\sin \left(11\cdot \frac{\pi }{2}+x\right)=-\frac{1}{2},\:\pi \le \:x\le \:2\pi\)
The value of the given expression.
What is the expression?
An expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
We have,
\(\sin \left(11\cdot \frac{\pi }{2}+x\right)=-\frac{1}{2},\:\pi \le \:x\le \:2\pi\)
\(11\cdot \frac{\pi }{2}+x=\frac{7\pi }{6}+2\pi n,\:11\cdot \frac{\pi }{2}+x=\frac{11\pi }{6}+2\pi n\)
\(x=2\pi n-\frac{13\pi }{3},\:x=2\pi n-\frac{11\pi }{3}\)
\(x=\frac{5\pi }{3}\)
Therefore, The value of the x is equal to the 5pi/3.
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Maria's bill for lunch was $12.25. How much would her tip be if she leaves a 20% tip?
Answer:
$2.45
Step-by-step explanation:
First, we find how much 20% of 12.25 is:
we can convert 20% directly to a decimal:
20% = 0.2
Then we find
20% of 12.25 = 0.2 x 12.25 = 2.45
So Maria's tip would be $2.45
Let X and Y denote the tarsus lengths of male and female grackles, respectively. Assume that X is N(,) and Yis N(4,²). Given that the sample number of X and Y are n=m=25, and X = 33.8, S=3.9,Y=32.5, S=5.1. Use these observations to give a level a=0.05 test for H₁:μx = μy VS Hoxy. Give the p-value of this test. (10 pts)
To test the hypothesis H₁: μx = μy versus Hoxy, where μx and μy represent the means of X and Y respectively, we can perform a two-sample t-test. The test compares the means of two independent samples to determine if they are significantly different from each other.
The given information provides the sample means (X = 33.8, Y = 32.5) and the sample standard deviations (Sx = 3.9, Sy = 5.1). The sample sizes for both X and Y are n = m = 25.
Using this information, we can calculate the test statistic, which is given by:
t = (X - Y) / sqrt((Sx^2 / n) + (Sy^2 / m))
Plugging in the values, we get:
t = (33.8 - 32.5) / sqrt((3.9^2 / 25) + (5.1^2 / 25))
Next, we need to determine the degrees of freedom for the t-distribution. Since the sample sizes are equal (n = m = 25), the degrees of freedom for the test is given by (n + m - 2).
Using the t-distribution table or software, we can find the critical value corresponding to a significance level of α = 0.05 and the degrees of freedom.
Finally, we compare the calculated test statistic with the critical value. If the test statistic falls within the rejection region (i.e., the absolute value of the test statistic is greater than the critical value), we reject the null hypothesis. The p-value can also be calculated, which represents the probability of observing a test statistic as extreme or more extreme than the calculated value, assuming the null hypothesis is true.
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Obtain expressions in component form for the position vectors having the following polar coordinates. (a) 12.6 m,140
∘
counterclockwise from the +x axis
R
=m (b) 3.60 cm,40.0
∘
counterclockwise from the +x axis
R
=cm (c) 24.0 in., 200
∘
counterclockwise from the +x axis
R
= in.
(a) The position vector in component form for the polar coordinates (12.6 m, 140°) is (x, y) = (12.6 m * cos(140°), 12.6 m * sin(140°)). (b) The position vector in component form for the polar coordinates (3.60 cm, 40.0°) is (x, y) = (3.60 cm * cos(40.0°), 3.60 cm * sin(40.0°)). (c) The position vector in component form for the polar coordinates (24.0 in., 200°) is (x, y) = (24.0 in. * cos(200°), 24.0 in. * sin(200°)).
x`To obtain the expressions in component form for the position vectors with the given polar coordinates, we can use the following conversions:
For a polar coordinate (r, θ), where r is the magnitude and θ is the angle counterclockwise from the positive x-axis:
The x-component is given by: x = r * cos(θ)
The y-component is given by: y = r * sin(θ)
Let's calculate the expressions for each part:
(a) Polar coordinates: (12.6 m, 140°)
x-component: x = 12.6 m * cos(140°)
y-component: y = 12.6 m * sin(140°)
(b) Polar coordinates: (3.60 cm, 40.0°)
x-component: x = 3.60 cm * cos(40.0°)
y-component: y = 3.60 cm * sin(40.0°)
(c) Polar coordinates: (24.0 in., 200°)
x-component: x = 24.0 in. * cos(200°)
y-component: y = 24.0 in. * sin(200°)
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When an increase in one variable is associated with an increase in a second variable, the two variables are ______
When an increase in one variable is associated with an increase in a second variable, the two variables are known as positively correlated. The correlation coefficient is the measure of the degree of the relationship between two variables.
The correlation coefficient ranges from -1 to 1. A positive correlation coefficient indicates a positive relationship between two variables, while a negative correlation coefficient indicates an inverse relationship between two variables.
A positive correlation coefficient signifies that as one variable increases, the other variable also increases. For instance, the correlation between a person's height and weight is positive because as their height increases, so does their weight.
In the same way, as a person's income increases, so does their level of expenditure. Positive correlations can be either strong or weak.A strong correlation is indicated by a correlation coefficient close to 1, while a weak correlation is indicated by a correlation coefficient closer to zero.
For example, the correlation between a person's weight and the number of hours they exercise per week is strong. When a person's exercise time increases, so does their weight loss. In conclusion, when an increase in one variable is associated with an increase in a second variable, the two variables are positively correlated.
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In this problem, we want to find the general solution of the equation dxdy=lnyxy,y>1 Part 1. After separating variables, we have: dy=dx Part 2. Next, we integrate both sides of the equation above with respect to the appropriate variables to get: ∫=∫ Note: don't forget the differentials in your answer. Part 3. An antiderivative that results from the integral on the left hand side above is. NOTE: Type 'C1' for the arbitrary constant An antiderivative that results from the integral on the right hand side above is. NOTE: Type 'C2' for the arbitrary constant Part 4. Now, find the specific solution for which y=e when x=6. y=
we can put in the equation: y(ln(y) - 1) - xy = xy-ln(x) + C2y(ln(y) - 1) = 2xy-ln(x) + C2 y=e^(2x-1/6) x>0, s y=e^(2x-1/6), where x>0.
The given equation is dx/dy=ln(y/x)y>1Part 1. Separating the variables, we get:dy=ln(y/x) dxPart 2. Integrating both sides, we get:∫(1/y)dy=∫ln(y/x) dx Logarithmic rule to the right-hand side leads to:∫(1/y)dy=∫ln(y) dy - ∫ln(x) dy∫(1/y)dy= y(ln(y) - 1) - xy + C1where C1 is the constant of integrationPart 3. The antiderivative resulting from the integration on the left-hand side is:y(ln(y) - 1) - xy + C1and the antiderivative resulting from the integration on the right-hand side is:xy-ln(x) + C2Part 4. We want to find a specific solution for which y=e when x=6.We get: 1(ln(e) - 1) - 6e + C1= 0 + C2C1 + 1 - 6e = C2Now we know the value of C1, C2 and we can put in the equation: y(ln(y) - 1) - xy = xy-ln(x) + C2y(ln(y) - 1) = 2xy-ln(x) + C2 y=e^(2x-1/6) x>0, s y=e^(2x-1/6), where x>0.
We used the given equation to derive the general solution by separating variables and integrating. We found the constants of integration by using the given initial conditions. Finally, we used these constants to get the specific solution for a given value of x and y.
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Use the definition of similarity in terms of transformations to explain why two triangles are similar if all corresponding pairs of angles are congruent and all corresponding pairs of sides are proportional.
Two triangles are similar triangles if all corresponding pairs of angles are congruent and all corresponding pairs of sides are proportional, which can be explained using the definition of similarity in terms of transformations.
In geometry, two figures are considered similar if one can be transformed into the other through a combination of rigid motions (translation, rotation, and reflection) and dilations. When considering triangles, the definition of similarity states that two triangles are similar if their corresponding angles are congruent and their corresponding sides are proportional.
If all corresponding pairs of angles are congruent, it means that the angles in one triangle can be matched with the corresponding angles in the other triangle through rotations and/or reflections. This ensures that the relative shape and orientation of the triangles are the same.
Additionally, if all corresponding pairs of sides are proportional, it means that the lengths of the sides in one triangle are proportional to the lengths of the corresponding sides in the other triangle. This indicates that the triangles have the same shape but possibly different sizes, which can be achieved through dilations.
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Sue need to borrow $8000 to purchase a used car. The dealer arranges with a finance company to lend sue the money at 3.6% per year compounded monthly for 3 years.
What is sue’s monthly payment be?
Plz guys help me pass math
Question about financial application functions
Plz answer this last question on my test
Plz show all the working
God bless you brother or sister
Answer ASAP
Answer:
The monthly payment is $247.53
Step-by-step explanation:
We need to firstly calculate the total amount to be paid
We have this by using the compound interest formula;
A = I ( 1 + r/n)^nt
A is the total amount to be paid back
I is the amount borrowed which is $8,000
r is the interest rate = 3.6% = 0.036
n is the number of times in a year = 12 (monthly)
t is the number of years = 3
Substituting these values ;
A = 8000(1 + 0.036/12)^(12 * 3)
A = 8000(1 + 0.003)^36
A = 8000(1.003)^36
A = 8,910.94
The monthly payment is this amount divided by the number of months in 3 years which is 36
We have this as;
8,910.94/36 = $247.53
The volume of a cylinder is 24 cubic feet. The height is 6 feet.
Determine the radius of the cylinder. Use 3.14 for pi.
Answer:
1.13 ft
Step-by-step explanation:
use the equation then fill in the missing values. when you have your answer round to the nearest thousandths.
Calculate the average rate of change of the given function f over the intervals [a, a + h] where h = 1, 0.1, 0.01, 0.001, and 0.0001. f(x) = x^2/6, a=1
The average rate of change of f(x) over the intervals [1, 1.1], [1, 1.01], [1, 1.001], [1, 1.0001], and [1, 1.00001] are 1/3, 0.166, 0.0167, 0.00167, and 0.000167 respectively.
To calculate the average rate of change of a function f(x) over an interval [a, a + h], we use the formula:
(f(a + h) - f(a)) / h
In this case, f(x) = x^2/6 and a = 1. Therefore, we have:
f(a) = f(1) = 1^2/6 = 1/6
f(a + h) = f(1 + h) = (1 + h)^2/6 = (1/6)h^2 + (1/3)h + 1/6
Now we can calculate the average rate of change for each value of h:
For h = 1:
(f(1 + h) - f(1)) / h = ((1/6)(1)^2 + (1/3)(1) + 1/6 - 1/6) / 1 = 1/3
For h = 0.1:
(f(1 + h) - f(1)) / h = ((1/6)(0.1)^2 + (1/3)(0.1) + 1/6 - 1/6) / 0.1 = 0.166
For h = 0.01:
(f(1 + h) - f(1)) / h = ((1/6)(0.01)^2 + (1/3)(0.01) + 1/6 - 1/6) / 0.01 = 0.0167
For h = 0.001:
(f(1 + h) - f(1)) / h = ((1/6)(0.001)^2 + (1/3)(0.001) + 1/6 - 1/6) / 0.001 = 0.00167
For h = 0.0001:
(f(1 + h) - f(1)) / h = ((1/6)(0.0001)^2 + (1/3)(0.0001) + 1/6 - 1/6) / 0.0001 = 0.000167
Therefore, the average rate of change of f(x) over the intervals [1, 1.1], [1, 1.01], [1, 1.001], [1, 1.0001], and [1, 1.00001] are 1/3, 0.166, 0.0167, 0.00167, and 0.000167 respectively.
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What is the maximum point OR minimun point of this equation?
y = 1.8 ( x + 2.4 ) 2 + 2.4
Thanks for ur help!!!!!!!!
Select three ratios that are equivalent to 8:58,
Choose 3 answers:
(Choice A)
A
16:10
(Choice B)
B
50:80
(Choice C)
C
48:30
(Choice D)
D
32:20
(Choice E)
E
64:35
Answer:
Step-by-step explanation:
Given expression:
The ratio equivalent to 8:58
let us first reduce this ratio to the simplest term:
Divide by 2;
4 : 29
A. 16: 10
Reduce to the simplest term by dividing by 2;
4 : 5
B . 50:80
Reduce to the simplest term by dividing by 10;
5 : 8
C. 48 : 30
Reduce to the simplest term by dividing by 6:
8 : 5
D. 32 : 20
Divide through by 4;
8 : 5
E. 64 : 35
Cannot be further simplified
a sprint duathlon consists of a 5 km run, a 20 km bike ride, followed by another 5 km run. the mean finish time of all participants in a recent large duathlon was 1.67 hours with a standard deviation of 0.25 hours. suppose a random sample of 30 participants was taken and the mean finishing time was found to be 1.59 hours with a standard deviation of 0.30 hours. suppose the process of taking random samples of size 30 is repeated 200 times and a histogram of the 200 sample means is created. would the histogram be an approximate display of the population distribution, the distribution of a sample, or the sampling distribution of means?
The histogram of the 200 sample means would be an approximate display of the sampling distribution of means.
In this scenario, random samples of size 30 are taken from the population of duathlon participants. Each sample mean is calculated from the finishing times of the participants in that specific sample. The process is repeated 200 times, resulting in 200 sample means.
The sampling distribution of means refers to the distribution of these sample means. It shows the variation in the sample means that would be expected when repeatedly sampling from the same population.
The Central Limit Theorem states that under certain conditions (such as when the sample size is sufficiently large and the population distribution is not heavily skewed), the sampling distribution of means tends to follow a normal distribution, regardless of the shape of the population distribution. The mean and standard deviation of the sampling distribution of means can be calculated based on the population mean and standard deviation, as well as the sample size.
Therefore, the histogram of the 200 sample means would provide an approximation of the sampling distribution of means, which gives insights into the likely range and variability of the sample means that could be obtained from repeated sampling.
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if the investor uses simple random sampling to create a set of 10 groups, and then analyzed all the individuals in two groups, what kind of sampling is she doing?
The investor is doing a two-stage sampling or a two-phase sampling. This type of sampling involves two steps: first, a simple random sampling is used to create a set of groups, and then individuals are selected from within the selected groups for analysis.
In this case, the investor created 10 groups through simple random sampling and then selected and analyzed all the individuals in two groups. Random sampling is a statistical sampling technique where a sample is selected from a larger population so that each member of the population has an equal chance of being selected. This means that the sample should be selected randomly and not based on systematic or predetermined criteria.
The goal of random sampling is to produce a sample representative of the population, allowing for more accurate inferences about the population as a whole. Random sampling helps to eliminate bias in the sample selection process, improving the accuracy and validity of the results obtained from the sample.
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