Solve the following questions. Show the complete solution.

Answer please
wrong answer-reported​

Answer: Choice C

\(\begin{array}{|c|c|} \cline{1-2}x & y\\\cline{1-2}0 & 1\\\cline{1-2}2 & 2\\\cline{1-2}4 & 3\\\cline{1-2}6 & 4\\\cline{1-2}\end{array}\)

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Explanation:

There are four marked points on the line.

Each point is of the form (x,y)

Each of these points is then listed in the table format as shown above.

There are infinitely many other points on the line; however, we only select a few of them to make the table (or else we'd be here all day).

Extra side notes:

Answer:

the anwser is c

Step-by-step explanation:

trust me

The probability that a class of 50 has an average score that is less than 77 is approximately 11.90%.

To solve this problem, we need to use the central limit theorem, which states that the distribution of sample means will be approximately normal with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.
In this case, we have a population of marks on a biology final test that is normally distributed with a mean of 78 and a standard deviation of 6. We want to know the probability that a class of 50 has an average score that is less than 77.
Using the central limit theorem, we can calculate the standard error of the mean as follows:
standard error of the mean = standard deviation / square root of sample size
standard error of the mean = 6 / √50
standard error of the mean = 0.8485
Next, we need to calculate the z-score for a sample mean of 77:
z-score = (sample mean - population mean) / standard error of the mean
z-score = (77 - 78) / 0.8485
z-score = -1.18
We can use a standard normal distribution table or calculator to find the probability associated with a z-score of -1.18. The probability of a sample mean less than 77 is approximately 0.1190 or 11.90%.
Therefore, the probability that a class of 50 has an average score that is less than 77 is approximately 11.90%.

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Answer:

920.8

Step-by-step explanation:

Answer: 920.8

Step-by-step explanation:

13812 divided by 15 can easily be found by just regular division methods.

Answer:

what can i help u with

Step-by-step explanation:

No; the relation passes the vertical-line test. Yes; only one range value exists for each domain value

Yes; two domain values exist for range

yes; only one range value exists for each domain.

Answer:

Step-by-step explanation

\(\frac{-9}{-15}\)÷ \(\frac{x^{-1} }{x^{5} }\) ÷\(\frac{y^{-9} }{y^{-3} }\)

\(\frac{3}{5}\) ÷ \(x^{-1} -5\)÷ \(y^{-9} -(-3)\)

\(\frac{3}{5}\) ÷ \(x^{-6}\) ÷ \(y^{-9} +3\)

\(\frac{3}{5}\) ÷\(x^{-6}\) ÷\(y^{-6}\)

\(\frac{3}{5}\) ÷ \(\frac{1}{x^{6} }\)÷\(\frac{1}{y^{6} }\)

\(\frac{3}{5x^{6}y^{6} }\)

The probability that, in an hour, at least 4 cars will enter the car wash is 0.94.

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

It is given that:

Cars enter a car wash according to a Poisson process at a mean rate of 2 cars per half an hour.

Here the value of λ is:

λ = 2 cars/half an hour

λ = 4 cars/hour

The probability that, in an hour, at least 4 cars will enter the car wash:

P(x = 4) = 4⁴e⁻⁴/5

After solving:

P(x = 5) = 0.937 ≈ 0.94

Thus, the probability that, in an hour, at least 4 cars will enter the car wash is 0.94.

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Answer:

1. 7(g-5)

2. 12(5m+2n)

3. 2(11w+5)

4. 8(5a+b-3)

5. 4(r+7t-10)

Step-by-step explanation:

simply take out the most common multiple of these numbers

The expected frequency of east campus and passed is C. 42 students

The table for expected frequency is ,

East Campus West Campus Total

Passed (84*100)/22=42 (84*100)/200 =42 84

Failed (116*100)/200=58 (116*100)/22=58 116

Total 100 100 200

Passed = 84×100/200

= 42

Therefore, the expected frequency of East Campus and Passed is 42 students.

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Answer:

341.8801

Step-by-step explanation:

f(-3) ≠ f(3) and f(-3) ≠ -f(3), which means that the function f does not satisfy the properties required for it to be even or odd.

To determine whether the function f is even, odd, or neither, we need to evaluate the symmetry of the function with respect to the y-axis and the origin.

For a function to be even, it must satisfy the property f(x) = f(-x) for all values of x in the function's domain. This means that if we substitute -x for x in the function, we should obtain the same output as when we evaluate the function at x.

For a function to be odd, it must satisfy the property f(x) = -f(-x) for all values of x in the function's domain. This means that if we substitute -x for x in the function, we should obtain the negative of the output we obtain when we evaluate the function at x.

Let's evaluate the function f using the given points (-3,5) and (3,-5):

For the point (-3,5):

f(-3) = 5

For the point (3,-5):

f(3) = -5

We can see that f(-3) ≠ f(3) and f(-3) ≠ -f(3), which means that the function f does not satisfy the properties required for it to be even or odd.

We can conclude that the function f is neither even nor odd.

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Using the division operation, the number of 2/3's in 3 is 4

3 ÷ 2/3

change the sign to multiplication and take inverse of 2/3

3 × 3/2 = 9/2 = 4.5

We need only the whole number value .

Therefore, the number of 2/3's in 3 is 4.

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Answer:

12?

Step-by-step explanation:

Answer:The Answer is 10!!!

Step-by-step explanation:

If you plot (1,4) and (-5,-4) on a graph, you can see that you can form a right triangle.

you would count the values on the X-axis and on the Y-axis. The values are 6 and 8 respectively.

You put the values on the second power and add them. So the equation would be 6^2 + 8^2. The answer would be 100.  Because the Pythagorean Theorem is a^2 + b^2= c^2, you would square root would be 10. The distance between the two points is 10.

Answer:

15

Step-by-step explanation:

5g

g becomes 3, so 5*3

=15

Answer:

15

Step-by-step explanation:

5g g=3

5(3)

15

The probability that at least one of Blanca's cards has a number greater than at least one of Amira's cards is 0.705 or approximately 70.5%.

The total number of ways in which Blanca can choose two cards out of 23 is given by the combination formula C(23, 2), which is equal to 253.

The value of k can range from 3 (if Amira's cards are 1 and 2) to 25 (if Amira's cards are 24 and 25). Therefore, the total number of ways in which Blanca can pick two cards that are both greater than Amira's cards is:

C(23, 2) - C(2, 2) - C(3, 2) - ... - C(23, 2) = 23C(23, 1) - (C(2, 2) + C(3, 2) + ... + C(23, 2)) = 253 - 276 = -23

Since the result is negative, it means that there are no ways in which Blanca can pick two cards that are both greater than Amira's cards. Therefore, the probability of this case is 0.

P(Case 2) = (number of ways in which Blanca can pick one card greater than Amira's and one card less than Amira's) / (total number of ways in which Blanca can pick two cards out of 23) = 44,550 / C(23, 2) = 0.705

Finally, the probability of at least one of Blanca's cards having a number greater than at least one of Amira's cards is given by the sum of the probabilities of Case 1 and Case 2:

P(at least one of Blanca's cards is greater) = P(Case 1) + P(Case 2) = 0 + 0.705 = 0.705 or 70.5%

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Answer:

5

Step-by-step explanation:

y= mx+b

with m being slope and b being y-intercept

Answer:

5

Step-by-step explanation:

y=mx+b

b=5

Answer:

Option C is the correct option.

Step-by-step explanation:

\( {36}^{ \frac{1}{2} } \)

Write the number in exponential form with a base of 6

\( =( {6}^{2}) \: ^{ \frac{1}{2} } \)

Simplify the expression by multiplying the exponents

\( = 6\)

Hope this helps..

Best regards!!

Based on the ratio provided, maximum number of cups of salad dressing that can be made are 16 cups (Option E)

Based on the provided information, oil, vinegar, and water are mixed in the ratio of 3:2:1 to make salad dressing. In order to make salad dressing, 3 portion oil, 2 portion vinegar, and 1 portion water is used i.e., 3:2:1. Hence, for n number of cups, the ratio is 3n:2n:1n. Which means that when n = 1, the number of cups of dressing would be 3 + 2 + 1 = 6cups.

When Larry has 8 cups of oil, 7 cups of vinegar, and access to any amount of water, the maximum portion of oil that can be used is 8/3 and of vinegar that can be used is 7/2. Hence the limiting factor would be oil here. Hence the value of n would be taken as 8/3 for each ingredient. Therefore, 8+16/3+8/3 = 48/3 = 16. Hence the maximum number of cups that can be made is 16 cups.

Note: The question is incomplete. The complete question is Oil, vinegar, and water are mixed in a 3 to 2 to 1 ratio to make a salad dressing. If Larry has 8 cups of oil, 7 cups of vinegar, and access to any amount of water, what is the maximum number of cups of salad dressing he can make with the ingredients he has available, if fractional cup measurements are possible? A) 12 B) 13 C) 14 D) 15 E) 16.

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1. The quotient in lowest terms of the given rational division is (x+2)/(3x-9).

2. The values of r is A. x=-2 and B. x=0.

Factor is a quantity which when multiplied by another quantity, produces a given product. Factors are used to simplify and solve equations, as well as in other areas of mathematics. Factors can be numbers, variables, and expressions.

To find the lowest terms, we must divide the numerator and denominator by the same number. The largest common factor of the numerator and denominator is 3. Dividing both the numerator and denominator by 3, we get (x+2)/(3x-9) = (x+2)/(x-3).

The values of r that must be excluded from the domains of the expressions are x=0 and x=3. x=0 must be excluded because it will create a zero in the denominator which is not allowed. x=3 must also be excluded because it will create a zero in the numerator, and thus make the entire expression equal to 0. Thus, the correct answer is A. x=-2 and B. x=0.

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From the plot we deduce that

(h, k) = (1, 2)

Domain = all real numbers

Range = all real numbers

Transformations

The translation for the function

y = -(x - 1)^1/3 + 2

Shows a movement from the parent function y = x^1/3

-x^1/3 The negative sign is for reflection

-(x - 1)^1/3 represents translation right 1 unit

-(x - 1)^1/3 + 2 represents translation up 2 units

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-f(x) reflects f(x) over the x-axis

f(x) - a translates f(x) a units down.

f(x + b) translates f(x) b units to the left

1) Given f(x) = x², then g(x) = -f(x) = -x² is the graph of g(x) that has been reflected over the x-axis.

2) Given the function: h(x) = -x², then g(x) = h(x) - 4 = -x² - 4 is the equation for the graph of g(x) that has also been shifted down 4 units.

3) Given the function: k(x) = -x² - 4, then g(x) = k(x + 1) = -(x+1)² - 4 is the equation for the graph of g(x) that has been shifted left 1 unit.

Answer:

20/100 x 50 is 10

10% would be 10/100 is fraction form

I want to help you on the first thing you said,

so always consider a percent as a fraction but there denominator is ALWAYS 100 (a way to remember that is that the word "cent" means 100). The word "of" means multiplication so that means your multiplying it with 50 and just do the multiplication.

I'm really hoping you understand!

Answer: The answer is B.

I hope this helps

Step-by-step explanation:

Using the quadratic formula to find the solutions, we get x = (-10 ± √40)/6

From the question, we have the following parameters that can be used in our computation:

3x² + 10x + 5=0

Using the quadratic formula, we have

x = (-10 ± √(10² - 4 * 3 * 5))/(2 * 3)

Evaluate the products and the exponents

So, we have

x = (-10 ± √40)/6

Hence, the solution is x = (-10 ± √40)/6

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Answer:

x=1/3,-2

Step-by-step explanation:

Given the functions:

The answer is: C. -4x^2.

The distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

Speed can be thought of as the rate at which an object covers distance.

A fast-moving object has a high speed and covers a relatively large distance in a given amount of time, while a slow

moving object covers a relatively small amount of distance in the same amount of time.

To calculate the distance traveled over 9 hours at a speed of 840 km/h, follow these steps:

1. Identify the time and speed given in the student question: 9 hours and 840 km/h.

2. Use the formula for distance:

distance = speed × time.

3. Plug in the values:

distance = 840 km/h × 9 hours.

4. Calculate the distance:

distance = 7,560 km.

So, the distance traveled over 9 hours at a speed of 840 km/h is 7,560 km.

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Answer:

Step-by-step explanation:

The markings shown are typical of rulers graduated in inches and fractions. Metric rulers and engineering scales are typically graduated differently, often in units of 10ths or 100ths. Architectural scales are often graduated in ways that facilitate creating and reading inches and feet from drawings with different scale factors.

First, you notice that the markings are of different lengths. The longest marks have numbers beside them. These are whole inches.

First Ruler

The first ruler shown is measuring a length of 3 inches.

Halfway between the inch marks are marks that are slightly shorter. These are the 1/2 inch marks. The one midway between 4 and 5 represents 4 1/2 inches, for example.

__

The next shorter marks are in the middle of the two spaces created by the 1/2-inch marks. These are the 1/4 inch marks. The one to the left (toward the lower number) represents 1/4; the one to the right (toward the higher number) represents 3/4. Of course, the 1/2 inch mark also corresponds to 2/4.

Slightly shorter than the 1/4-inch marks, and in the middle of the spaces created by the 1/4-inch (and 1/2-inch) marks, are the 1/8-inch marks. You can see that each set of marks divides the previous distances in half.

Second, Third Rulers

On the second and third rulers shown, the end of the green bar is at the first 1/8-inch mark after the number. That means the length is the number plus 1/8. Those two rulers show lengths of 4 1/8 and 8 1/8, respectively.

__

Each successive level of marks is 1/2 the length of the previous level. So, the marks just shorter than 1/8 are 1/16. Finally, the shortest marks are 1/32 inch.

Fourth Ruler

The fourth ruler shows a length that is 1/16 inch less than 1/4 inch less than 5 inches. The length shown there is ...

  5 -1/4 -1/6

  = 5 - 4/16 -1/16

  = 5 -5/16

  = 4 11/16

You can also recognize that length as being ...

  4 1/2 + 1/8 + 1/16 = 4 + (8 +2 + 1)/16 = 4 11/16

As before, it follows that A3 is a maximal ideal of R, contradicting the fact that the chain is infinite. Therefore, R satisfies the ACC.

It is given that be an integral domain with a descending chain of ideals. Suppose that there exists an n such that for all i ≥ n, then ai = an. A ring satisfying this condition is said to satisfy the descending chain condition or DCC. Rings satisfying the DCC are called Artinian rings, after Emil Artin.

The statement to be proved is if R satisfies the descending chain condition, it must satisfy the ascending chain condition. Suppose, by contradiction, that R satisfies the DCC but does not satisfy the ACC. Then, there is an infinite ascending chain: A1 ⊂ A2 ⊂ A3 ⊂ A4 ⊂ ···.

Note that if R is an integral domain and if a ∈ R, then (a) is either (0) or is a maximal ideal in R. Hence, (0) is a minimal element in the collection of all proper ideals of R. Suppose A1 is a proper ideal of R that is maximal with respect to not being finitely generated. Since R satisfies the DCC, A1 cannot be infinite. Therefore, A1 is a finite set. Suppose A1 is not principal.

Then there exist two elements a, b ∈ A1 that do not belong to (a) and (b) respectively. This means that (a, b) is a proper ideal of R, properly containing A1, which contradicts the maximality of A1. Thus, A1 is a principal ideal generated by an element a1 ∈ A1.Suppose A2 = (a1, a2, a3, · · · , am) is a proper ideal properly containing A1. If A2 is finitely generated, then A2 ⊃ (a1) ⊃ (0) is a finite descending chain of ideals, which contradicts the DCC.

Thus, A2 is not finitely generated. By the maximality of A1, A2 must be principal, generated by an element a2 ∈ A2. It follows that a2 = c1a1 + c2a2 + · · · + cmam, where ci ∈ R for all i. Hence, (1 − c2)a2 = c1a1 + · · · + cmam, which means that a2 ∈ (a1). Therefore, (a1) = A1 = A2, and it follows that A2 is a maximal ideal of R.

Suppose A3 is a proper ideal properly containing A2. If A3 is finitely generated, then A3 ⊃ A2 ⊃ (0) is a finite ascending chain of ideals, which contradicts the ACC. Thus, A3 is not finitely generated. By the maximality of A2, A3 must be principal, generated by an element a3 ∈ A3.

As before, it follows that A3 is a maximal ideal of R, contradicting the fact that the chain is infinite. Therefore, R satisfies the ACC.

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