The solution to the equation is f = 16. The value of f can be found by multiplying both sides of the equation by 8.
How we solve the equation: 2 = f/8 for f?To solve the equation 2 = f/8 for f, we aim to isolate f on one side of the equation.
To do so, we can multiply both sides of the equation by 8, as this will cancel out the denominator of f/8.
By multiplying 2 by 8, we obtain 16 on the left side of the equation.
On the right side, the 8 in the denominator cancels out with the 8 we multiplied, leaving us with just f.
we find that f = 16 is the solution to the equation.
This means that if we substitute f with 16 in the equation, we will have a true statement: 2 = 16/8, which simplifies to 2 = 2.
f = 16 satisfies the original equation and is the solution.
It's important to note that when solving equations, we perform the same operation on both sides to maintain equality.
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For the following hypothesis test: H
0
:μ≥64 H
A
:μ<64 α=0.01 Given n=40,σ=12, and
x
ˉ
=62.7. State the critical value z. −1.96 1.28 +/−2.58 −2.33
The correct critical value for this hypothesis test is -2.33.
In the given hypothesis test, where the null hypothesis (H₀) states that μ ≥ 64 and the alternative hypothesis (Hₐ) states that μ < 64, we need to find the critical value z for a significance level (α) of 0.01.
Since the alternative hypothesis is one-tailed (μ < 64), we are interested in the left-tail area of the standard normal distribution.
For a significance level of 0.01, the critical value z can be found by looking up the z-value that corresponds to an area of 0.01 in the left tail of the standard normal distribution.
The critical value z for α = 0.01 is approximately -2.33.
Therefore, the correct critical value for this hypothesis test is -2.33.
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A pinata spilled open and released 50 pounds of candy.if every child there scooped up 5/7 of a pound of candy,how many kids are there
Answer:
1.42857143
Step-by-step explanation:
Answer:
70
Step-by-step explanation:
Which rute yields the dilation of the figure BCE centered at the origin?
A
0.24
XY)--(
xy.4)
D
6.5. - *
Kayla purchased 0.1 pounds of medium binder clips and 0.2 pounds of jumbo binder clips.
What was the total cost?
if
standard paper clips-$4 per lb
jumbo binder clips-$6 per lb
colored paper clips-$5 per lb
medium binder clips- $5 per lb
The total cost of Kayla's purchase of 0.1 pounds of medium binder clips and 0.2 pounds of jumbo binder clips is $1.20.
To calculate the total cost, we need to determine the cost of each type of binder clip separately and then sum them up.
The cost of medium binder clips is $5 per pound, and Kayla purchased 0.1 pounds. Therefore, the cost of medium binder clips is 0.1 pounds * $5 per pound = $0.50.
The cost of jumbo binder clips is $6 per pound, and Kayla purchased 0.2 pounds. Thus, the cost of jumbo binder clips is 0.2 pounds * $6 per pound = $1.20.
Finally, to find the total cost, we add the individual costs together: $0.50 + $1.20 = $1.70.
Therefore, the total cost of Kayla's purchase of 0.1 pounds of medium binder clips and 0.2 pounds of jumbo binder clips is $1.70.
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write down the solution to this equation x^2+4x=56 correct to one decimal place
Answer:
x = -9.7 or +5.7
Step-by-step explanation:
You want the approximate solution to x² +4x = 56.
GraphThe solution is found easily by rewriting the equation to the form ...
x² +4x -56 = 0
The solution(s) will be the x-intercept(s) of the graph of x² +4x -56.
The solutions are -9.7 and +5.7.
Completing the squareWe can add 4 to both sides of the equation to complete the square. (This added value is the square of half the x-coefficient.)
x² +4x +4 = 56 +4
(x +2)² = 60
x +2 = ±√60 = ±2√15
x = -2 ±2√15
x ≈ -2 ± 7.7 = -9.7, +5.7
in a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. two simulations will be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325. simulation a will consist of 1,500 trials with a sample size of 100. simulation b will consist of 2,000 trials with a sample size of 50.
The sample size for Simulation A is greater than then the sample size for Simulation B and the variability of Simulation A will be less then the variability of Simulation B.
What is sampling distribution ?
An example of a sampling distribution is a probability distribution of a statistic that is derived from repeated sampling of a particular population.
It depicts a spectrum of potential results for a statistic, such as the mean or mode of a variable, for a population.
Given,
Two simulations will be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325.
Simulation A will consist of 1500 trials with a sample size of 100.
Simulation B will consist of 2000 trials with a sample size of 50.
Center for Simulation A and Simulation B will be roughly equal.
Overall Sample size of Simulation A will be
= 1500 * 100 = 150000
Overall Sample size of Simulation B will be
= 2000 * 50 = 100000
Hence, the sample size for Simulation A is greater than then the sample size for Simulation B and the variability of Simulation A will be less then the variability of Simulation B.
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The complete question is -
In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations will be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325. Simulation A will consist of 1,500 trials with a sample size of 100. Simulation B will consist of 2,000 trials with a sample size of 50. Which of the following describes the center and variability of simulation A and simulation B?
A) The centers will roughly be equal, and the variabilities will roughly be equal.
B) The centers will roughly be equal, and the variability of simulation A will be greater than the variability of simulation B.
C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
D) The center of simulation A will be greater than the center of simulation B, and the variability of simulation A will roughly be equal to the variability of simulation B.
E) The center of simulation A will be less than the center of simulation B, and the variability of simulation A will be greater than the variability of simulation B.
Simplify the following algebraic expression:-
\(\mathrm {\cfrac{2}{3}\:y -2(\cfrac{4}{3}\:y+z)}\)
\(\huge\text{Hey there!}\)
\(\huge\textbf{ORIGINAL equation:}\)
\(\mathsf{\dfrac{2}{3}y - 2(\dfrac{4}{3}y + z)}\)
\(\huge\textbf{DISTRIBUTE \boxed{\rm{\bf -2}} within the}\\\\\huge\textbf{parentheses:}\)
\(\mathsf{\dfrac{2}{3}y - 2(\dfrac{4}{3}y + z)}\)
\(\mathsf{= \dfrac{2}{3}y - 2(\dfrac{4}{3}y) - 2(z)}\)
\(\mathsf{= \dfrac{2}{3}y - \dfrac{8}{3}y - 2z}\)
\(\huge\textbf{COMBINE the like terms:}\)
\(\mathsf{= (\dfrac{2}{3}y - \dfrac{8}{3}y) - (2z)}\)
\(\mathsf{= \dfrac{2}{3}y - \dfrac{8}{3}y - 2z}\)
\(\mathsf{-2y - 2z}\)
\(\huge\text{Therefore your answer should be:}\)
\(\huge\boxed{\mathsf{-2y - 2z}}\huge\checkmark\)
\(\huge\text{Good luck on your assignment \& enjoy your day!}\)
The cost of 2 kg of mushrooms and 2.5 kg of turnips is £8.55. The cost of 3 kg of mushrooms and 4 kg of turnips is £13.10. Work out the cost of a) 1 kg of turnips. b) 1 kg of mushrooms. check image
If the cost of 2 kg of mushrooms and 2.5 kg of turnips is £8.55 and the cost of 3 kg of mushrooms and 4 kg of turnips is £13.10, then cost of 1 kg of turnips is £1.1 and cost of 1 kg of mushrooms is £2.9.
Given that the cost of 2 kg of mushrooms and 2.5 kg of turnips is £8.55 and the cost of 3 kg of mushrooms and 4 kg of turnips is £13.10.
We are required to find the cost of 1 kg of mushrooms and the cost of 1 kg of turnips.
Cost is basically the expenditure that we do in order to buy or produce a product.
Suppose the cost of 1 kg of mushrooms be x and the cost of 1 kg of turnips be y. The equations will be as under:
2x+2.5y=8.55------1
3x+4y=13.10-------2
Equation1 *3 and Equation2 *2.
6x+7.5y=25.65-----3
6x+8y=26.20-------4
Subtract 4 from 3.
6x+7.5y-6x-8y=25.65-26.20
-0.5y=-0.55
y=1.1
Put the value of y in 1.
2x+2.5*1.1=8.55
2x+2.75=8.55
2x=8.55-2.75
2x=5.80
x=2.9
Hence if the cost of 2 kg of mushrooms and 2.5 kg of turnips is £8.55 and the cost of 3 kg of mushrooms and 4 kg of turnips is £13.10, then cost of 1 kg of turnips is £1.1 and cost of 1 kg of mushrooms is £2.9.
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Question 37 1 pts Which of the following is a solution to the differential equation: t². d^2y/dt^2 - 6t dy,dt + 12 = 0
a.y=t² + 1 b.y=t³+2t^4
c.no solution d.y = t-1 Question 38 1 pts Newton's law of cooliing states that the rate of change of the temperature T of an object is proportional to the temperature difference between the temperature S of the surroundings and the temperature T. Write down the differential equation. A cup of tea is prepared from boiling water at 100 degrees and cools to 50 degrees in 3 minutes. The temperature in the room is 20 degrees. What will the tea temperature be after a very long time? a.dT/dt=k(S-T); T≈ 20 degrees after a very long time b.dt/dT =k(ST); T≈ 30 degrees after a very long time c.dt/dT =K(S-T); T≈ 0 degrees after a very long time d.dt/dT = K (S+T); T≈ 30 degrees after a very long time
Question 37: The following is a solution to the differential equation y = t - 1. d.
Question 38: The tea temperature be after a very long time is dT/dt = k(S - T); T ≈ 20 degrees after a very long time. a.
To determine the solution to the given differential equation: t²(d²y/dt²) - 6t(dy/dt) + 12 = 0, we can solve the equation by assuming a solution in the form of y = tⁿ, where n is a constant.
By differentiating y with respect to t, we can substitute the derivatives into the differential equation to determine the value of n.
Let's differentiate y = tⁿ with respect to t:
dy/dt = n × tⁿ⁻¹
d²y/dt² = n(n-1) × tⁿ⁻²
Substituting these derivatives into the differential equation:
t²(n(n-1)tⁿ⁻²) - 6t(ntⁿ⁻¹) + 12 = 0
Simplifying the equation:
n(n-1)tⁿ - 6ntⁿ + 12 = 0
n(n-1)tⁿ - 6ntⁿ = -12
Since this equation must hold for all values of t, the coefficients of the tⁿ terms on both sides of the equation must be equal.
We can equate the coefficients:
n(n-1) = 0
n = 0 or n = 1
The general solution to the differential equation is y = c₁ + c₂ × t, where c₁ and c₂ are constants.
According to Newton's law of cooling, the rate of change of the temperature T of an object is proportional to the temperature difference between the object's temperature T and the surroundings' temperature S.
We can write the differential equation as follows:
dT/dt = k(S - T)
dT/dt represents the rate of change of temperature, k is the proportionality constant, and (S - T) represents the temperature difference between the object and the surroundings.
The cup of tea starts at 100 degrees and cools to 50 degrees in 3 minutes, with the room temperature at 20 degrees.
We can assume that the temperature of the tea will tend toward the room temperature as time goes to infinity.
This option correctly represents that as time goes to infinity, the temperature T of the tea will approach the temperature S of the surroundings, which is approximately 20 degrees.
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la+xl/2 - la-xl/2, if a= -2, x= -6
HELP!!!
Answer: 2
Step-by-step explanation:
1) substitute
2) calculate the difference before the absolute value
3) calculate the absolute value
4) convert into whole numbers/reduce
5) subtract the whole numbers
this is what i think might be wrong
I need help please !
Answer:
(-3,-2), (-3,-5), (-4,-5), (-7,-2)
Step-by-step explanation:
I need some help with these two questions please help!
Answer:
Step-by-step explanation:
-10.6*0.5=m+11.7
-5.3=m+11.7
-5.3-11.7=m
-17=m
14.2=2(-5.8+t)
14.2=-11.6+2t
14.2+11.6=2t
25.8=2t
25.8/2=t
12.9=t
(28 ⋅ 3−5 ⋅ 60)−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 228
The answer would look like this:
(2^8 × 5^–5 × 19^0)–2 ×× 228 = (2^–16 × 5^10 × 19^0) × × 2^28 = (2^–16 × 5^10 × 1) × × 2^28 = (2^–16 × 5^10 × 1) × 5^–8 × 2^–12 × 2^28 = (2^–16 × 2^–12 × 2^28) ×(5^10 ×5^–8) = 2^–28 × 2^28× 5^2 = 2^0 × 25 = 25
derive an equation that relates the initial release height hx of block x and the speed vs of the two-block system after the collision in terms of mx , my , and fundamental constants, as appropriate.
The law of conservation of energy and momentum can be used to construct the equation that connects the initial release height of block x (hx) and the speed of the two-block system following the collision (v s).
Block x's initial kinetic energy (0.5 * m x * v x2) and potential energy (m x * g * hx) are both equal to the total kinetic energy of both blocks after the collision (0.5 * (m x + m y) * v s).
Combining everything, we get the following equation:
m x * g * hx + 0.5 * m x * v x2 = 0.5 * (m x + m y) * v s2.
where g is the acceleration brought on by gravity, v x is the starting speed of block x, and m x and m y are the masses of blocks x and y.
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Alguien sabe la respuesta?
According to the triangle:- perpendicular (p) = 8√3
hypotenuse (h) = x
\( \sec(60) = \frac{p}{h} \)
\( \frac{8 \sqrt{3} }{x} = \sin(60) \\ \frac{8 \sqrt{3} }{x} = \frac{ \sqrt{3} }{2} \\ 2\times 8 \cancel{ \sqrt{3} } = x \times \cancel{ \sqrt{3} } \\ 2 \times 8 = 16 = x = hypotenuse\)
Your Answer :- hypotenuse = X = 16
Please help me it would mean the world. Extra points!
The answer is 15in^2 provided by my teacher I just need the work.
A transformation is applied to a figure to create a new figure. Which transformation does NOT preserve congruence?
answer choices
a. A reflection across the x-axis
b. A translation 7 units down
c. A dilation by a scale factor of 5
d. A rotation of 900 clockwise
Dilation by a scale factor of 5 does not preserve congruence, hence the correct answer is option c.
1. Rotation transformation: A rotation is a transformation in which the object is rotated about a fixed point. The direction of rotation can be clockwise or anticlockwise.
2. Reflection transformation: In a reflection transformation, all the points of an object are reflected or flipped on a line called the axis of reflection or line of reflection.
3. Translation transformation: Translation means the displacement of a figure or a shape from one place to another. In translation, a figure can move upward, downward, right, left or anywhere in the coordinate system. In translation, only the position of the object changes, its size remains the same.
4. Dilation transformation: Dilation is a transformation, which is used to resize the object. Dilation is used to make the objects larger or smaller. This transformation produces an image that is the same as the original shape. But there is a difference in the size of the shape. A dilation should either stretch or shrink the original shape.
Congruence is preserved by reflection, translation & rotation, as the image & pre-image have the same side lengths & angle measurements. But in case of dilation transformation, the side lengths change, hence this transformation does not preserve congruence.
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The value of a car in 1990 is 7700 dollars and the value is expected to go down by 390 dollars per year for the next 10 years.
The value of the car in 2000 is expected to be $3800, given a starting value of $7700 in 1990 and a decrease of $390 per year for 10 years.
To find the value of the car in each subsequent year, we can subtract $390 from the previous year's value. Let's calculate the value of the car for each year from 1990 to 2000.
Year 1990: $7700
Year 1991: $7700 - $390 = $7310
Year 1992: $7310 - $390 = $6920
Year 1993: $6920 - $390 = $6530
Year 1994: $6530 - $390 = $6140
Year 1995: $6140 - $390 = $5750
Year 1996: $5750 - $390 = $5360
Year 1997: $5360 - $390 = $4970
Year 1998: $4970 - $390 = $4580
Year 1999: $4580 - $390 = $4190
Year 2000: $4190 - $390 = $3800
Therefore, the value of the car is expected to be $3800 in the year 2000.
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Bedroom rent
1 $500
2 $625
3 $700
what would be the likely cost of a 4 bedroom apartment?
Answer:
maybe $825
Step-by-step explanation:
Im not sure but I think Its accurate
Richard sold cupcakes and cookies yesterday. Each cupcake sold for $1.75 and each cookie sold for $0.75. At the end of the day, Richard had sold $49.25 worth of cookies and cupcakes. If he sold 35 cupcakes and cookies combined, how many cupcakes were sold and how many cookies were sold?
Answer:
20 cupcakes
15 cookies
Step-by-step explanation:
20*$1.75=$35
15*$0.75=$14.25
$35+$14.25=$49.25
Answer:
23 cupcakes and 12 cookies
Step-by-step explanation:
While measuring a cloth of length 1.5 meters, it wasmeasured as 1.53 meters. Find the percentage error inmeasuring the cloth.
we have that
1.5 meters represents 100%
so
Applying proportion
Find out how much percentage represents the difference (1.53-1.50=0.03 m)
100/1.5=x/0.03
solve for x
x=(100/1.5)*0.03
x=2%
therefore
the answer is 2%What is (gof)(x) if f(x) = 3x - 1 and g(x) = 4x² + 9?
Step-by-step explanation:
(gof)(x) is basically g(f(x))
= 4 × (3x - 1)² + 9
= 4 × (9x² - 6x + 1) + 9
= 36x² - 24x + 4 + 9
= 36x² - 24x + 13
Find x .
Please help I’m begging
Answer:
x = 103
Step-by-step explanation:
Using the far right intersection, we can figure out that in inner angle is 32 degrees.
32 + 34 = 66 which is the angle of the left side of the middle cross.
x = 37 + 66 = 103
Please help me asap
heeeeeeeeeeeeeellllllllppp
Answer:
Step-by-step explanation:
let price of one pretzel=x
price of one soda=y
3x+4y=11.25 ...(1)
5x+2y=8.25 ...(2)
multiply by 2
10x+4y=16.50 ...(3)
(3)-(1) gives
7x=5.25
x=0.75
from (1)
3(0.75)+4y=11.25
2.25+4y=11.25
4y=11.25-2.25
4y=9
y=9/4=2.25
cost of one pretzel=$0.75
cost of one soda=$2.25
An invoice dated september 9 in the amount of $50,000 is received by ralph corp. on september 12. the invoice carries terms of 3/10, n/30. on september 16, ralph mails a check for $3,000 as partial payment on the invoice. what is the outstanding balance on the invoice?
The outstanding balance on the invoice is $47,000. Ralph Corp. received an invoice dated September 9 for $50,000 with terms of 3/10, n/30.
On September 16, Ralph mailed a partial payment of $3,000, leaving a remaining balance of $47,000.
The terms of 3/10, n/30 mean that the buyer (Ralph Corp.) is entitled to a discount of 3% if the payment is made within 10 days of the invoice date, and the full payment is due within 30 days without any discount.
Since Ralph Corp. made a partial payment of $3,000 on September 16, which is within the 10-day discount period, this amount qualifies for the discount. The discount can be calculated as 3% of $50,000, which equals $1,500. Therefore, the effective payment made by Ralph Corp. is $3,000 - $1,500 = $1,500.
To determine the outstanding balance, we subtract the effective payment from the original invoice amount: $50,000 - $1,500 = $47,000. Thus, the outstanding balance on the invoice is $47,000, indicating the remaining amount that Ralph Corp. needs to pay within the designated 30-day period.
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Find the shaded area. Round your answer to the nearest tenth, if necessary.
Area of the Trapezoid =
Area of the Triangle =
Total Shaded Area =
Area of trapezoid = 675 in², Area of triangle = 54 in² and Total Shaded Area = 621 in²
What is trapezoid?A trapezοid, alsο knοwn as a trapezium, is a flat clοsed shape having 4 straight sides, with οne pair οf parallel sides.
The parallel sides οf a trapezium are knοwn as the bases, and its nοn-parallel sides are called legs. A trapezium can alsο have parallel legs. The parallel sides can be hοrizοntal, vertical οr slanting.
The perpendicular distance between the parallel sides is called the altitude.
From the figure given:
Area of trapezoid \(\rm = \frac{a + b}{2} \cdot h\)
Area of trapezoid \(\rm = \frac{24 + 51}{2} \cdot 18\)
Area of trapezoid = 675 in²
Area of triangle = 1/2 × base × height
Area of triangle = 1/2 × 9 × 12
Area of triangle = 54 in²
Total Shaded Area = 675 - 54
Total Shaded Area = 621 in²
Thus, Area of trapezoid = 675 in², Area of triangle = 54 in² and Total Shaded Area = 621 in²
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Find the solution to the differential equation dzdt=7te7z that passes through the origin.
The answer is \(z &=-0.14\left[\ln \left(1-24.5 t^2\right)\right]\end{aligned}$$\)
What do you understand by differential equation?
An ordinary derivative or a partial derivative can both be found in a differential equation. The differential equation describes the relationship between the variable that is constantly varying with respect to the change in another quantity, and the derivative represents a rate of change.
Equations with General Differential. Consider the differential equation y′=3x2, which has a derivative and is an illustration of a differential equation. The variables x and y are related because y is an unidentified function of x. The derivative of y is also on the equation's left-hand side.
Given equation:
\($$\begin{aligned}&e^{-7 z} d z=7 t d t \\&:(-1 / 7) e^{-7 z}=3.5 t^2+C\end{aligned}$$\)
\($C=-1 / 7$\)
\($$(-1 / 7) e^{-7 z}=3.5 t^2-1 / 7$$\)
\($$e^{-7 z}=1-24.5 t^2$$\)
\($$\begin{aligned}-7 z &=\ln \left(1-24.5 t^2\right) \\z &=-0.14\left[\ln \left(1-24.5 t^2\right)\right]\end{aligned}$$\)
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pls help :(
y= _x +_
Find the equation of the line
hi, I'm no bot just in case...
the grapgh of the line shows y intercept of -9 and rate of change by 4
SoThe equation of the lline will be: \(y=4x-9\)
Which of these equations has no solutions?
a
2(x - 7) = 2x - 14
3(2x + 1) = 6x + 1
15x - 30 = 0
2x + 1 = 5x - 3
Answer:
2(x - 7) = 2x - 14
Step-by-step explanation:
→ Expand out equation
2x - 14 = 2x - 14
→ Minus 2x from both sides
-14 = -14