Solve the equation 1/8(p + 24) = 9

Answer:i think its the second one

Step-by-step explanation:

The equation that represents the hanger is 5x + 2 = 17  

The given hanger is a balanced hanger where one block has some units and another block has small blocks which are the same as the first block.

To form an equation count the number of x and constant on the block making it equal to the 2nd block.

Here we have a hanger

In the given hanger,

There are 17 units on one side and it is balanced by 5 times x and 2

Hence, The equation represents the hanger is 5x + 2 = 17

(b) The diagrams can be drawn as shown in the figure

(c) From hanger (A)

The hanger has 20 on one block and another block is balanced by 4 times x and 5  

Hence, the required equation is 20 = 4x + 5

From Hanger (B)

The hanger has 30 on one block and another block is balanced by 4 times x  

Hence, The required equation is 30 = 4x

Therefore,

The equation that represents the hanger is 5x + 2 = 17

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9514 1404 393

Answer:

  (d)  105°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  28° + ∠DEF + 47° = 180°

  ∠DEF = 105° . . . . . . . . . . . subtract 75°, collect terms

The answer is:

Work/explanation:

Bear in mind that the sum of all the angles in a triangle is 180°.

Given two angles, we can easily find the third one.

Let's call it x.

Next, we set up an equation:

\(\sf{54+87+x=180}\)

\(\sf{141+x=180}\)

Subtract 141 on each side.

\(\sf{x=180-141}\)

\(\sf{x=39}\)

The slope of the line passing through the points (5, 3) and (8, 2) is -1/3.

To find the slope of the line passing through the points (5, 3) and (8, 2), we can use the formula for slope:

slope = (y2 - y1) / (x2 - x1)

Let's substitute the coordinates of the given points into the formula:

x1 = 5, y1 = 3

x2 = 8, y2 = 2

slope = (2 - 3) / (8 - 5)

Calculating the numerator and denominator:

slope = -1 / 3

Therefore, the slope of the line passing through the points (5, 3) and (8, 2) is -1/3.

Note: The slope represents the rate of change between the y-coordinates and x-coordinates of two points on a line. In this case, for every 3 units increase in the x-coordinate, the y-coordinate decreases by 1 unit.

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Answer:

$80

Step-by-step explanation:

15(x+20) = 1500

15x + 300 = 1500

Subtract 300 from each side

15x = 1200

Divide each side by 15

x = 80

The value of x that makes the line containing (1,2) and (5,3) perpendicular to the line containing (x,4) and (3,0) is x = 2.

To determine the value of x such that the line containing (1,2) and (5,3) is perpendicular to the line containing (x,4) and (3,0), we need to find the slope of both lines and apply the concept of perpendicular lines.

The slope of a line can be found using the formula:

slope = (change in y) / (change in x)

For the line containing (1,2) and (5,3), the slope is:

slope1 = (3 - 2) / (5 - 1) = 1 / 4

To find the slope of the line containing (x,4) and (3,0), we use the same formula:

slope2 = (0 - 4) / (3 - x) = -4 / (3 - x)

Perpendicular lines have slopes that are negative reciprocals of each other. In other words, if the slope of one line is m, then the slope of a line perpendicular to it is -1/m.

So, we can set up the equation:

-1 / (1/4) = -4 / (3 - x)

Simplifying this equation:

-4 = -4 / (3 - x)

To remove the fraction, we can multiply both sides by (3 - x):

-4(3 - x) = -4

Expanding and simplifying:

-12 + 4x = -4

Adding 12 to both sides:

4x = 8

Dividing both sides by 4:

x = 2

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Answer:

2 out of 6

Step-by-step explanation:

P( blue marble) = number of blue marbles / total marbles

                          = 2 /6

Answer: C

Step-by-step explanation:  the reason it is c is because  the total of marbles is six  and their is only 2 marbles  so it would be 2 out of 6 you could also use process of elimination

(A) The range and IQR for boxplot 1 is 10 and 6 respectively.

(B) The range and IQR for boxplot 2 is 12 and 7 respectively.

The interquartile range defines the difference between the third and the first quartile.

The formula for the interquartile range is given below.

Interquartile range = Upper Quartile – Lower Quartile = Q­3 – Q­1

The range is the difference between the lowest and highest values.

The formula for the interquartile range is given below.

Range = Maximum – Minimum

(A) For boxplot 1, we need to find the range and IQR from the given data set.

So, let 34 be the maximum and 24 be the minimum.

\(\text{Range}=\sf 34-24\)

\(\text{Range}=\sf10\)

Therefore, the range is 10.

Now time to find the IQR.

So, let 33 be Q3 and 27 be Q1.

\(\text{IQR}=\sf 33-27\)

\(\text{IQR}=\sf 6\)

Therefore, the IQR is 6.

(B) Now for boxplot 2, we will do the same thing as from part A.

Let's find the range.

So, let 24 be the maximum and 12 be the minimum.

\(\text{Range}=\sf 24-12\)

\(\text{Range}=\sf12\)

Hence, the range is 12.

Now for the IQR.

So, let 22 be Q3 and 15 be Q1.

\(\text{IQR}=\sf 22-15\)

\(\text{IQR}=\sf 7\)

Hence, the IQR is 7.

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Answer:

4476966756TTTVFD

Step-by-step explanation:

Answer: $2.60

Step-by-step explanation:

$1+$1.60=$2.60

Answer:

Con esto te sacas 10

2.5 cm

We want to solve the equation:

We distribute and sum:

As you can see, the equation has infinite solutions.

Answer:

slope of HI is -2

Step-by-step explanation:

so the line looks straight to me so just solve for the slope of D(8,32) E(12,24) which you solve with the equation y2 - y1/x2 - x1

so... 24 - 32 = -8 and 12 - 8 = 4

-8/4 = -2

I hope I helped you ;)

The two equations that have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p include the following:

B. 2.3p – 10.1 = 6.49p – 4

C. 230p – 1010 = 650p – 400 – p

From the information provided, we have the following equation:

2.3p – 10.1 = 6.5p – 4 – 0.01p

Next, we would simplify the given equation by collecting like terms as follows;

2.3p - 10.1 = 6.5p - 0.01p - 4 = 6.49p - 4

2.3p - 10.1 = 6.49p - 4

In Mathematics, the multiplication property of equality states that both sides of an equation will remain the same and equal, when both sides of the equations are multiplied by the same number.

By multiplying both sides of the given equation by 100, we have;

100 × (2.3p - 10.1) = 100 × (6.5p - 4 - 0.01p)

230p - 1010 = 650p - 400 - p

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Answer:

m9 = 115

m4 =110

m10=65

m11= 70

m8= 70

m5 = 65

m3 = 70

m14 = 115

The requried ball reached a maximum height of approximately 62 feet

Let the ball is thrown vertically upward, we can use the following formula to find the maximum height it reaches:

\(h(t) = -16t^2 + vt + h_0\)

here, h(t) is the height of the ball at time t, v is the initial velocity of the ball (in feet per second), and h0 is the initial height of the ball (in feet). We can also use the fact that the ball remains in the air for 3.8 seconds, which means that the time it takes to reach the maximum height is half of that or 1.9 seconds.

At the highest point, the ball's velocity is zero, so we can find the initial velocity by setting v = 0 in the above formula and solving for h₀:

h₀ = h(t) + 16t²

   = 4 + 16(1.9)²

   ≈ 4 + 57.76

   ≈ 61.76

Therefore, the ball reached a maximum height of approximately 62 feet

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Ten times to get the required amount of 100ml of milk for her recipe.

Avery needs to measure 100ml of milk for her recipe but she only has a 10ml measuring cup.

Therefore, she needs to determine how many times she will need to fill her 10ml measuring cup to get the required amount of milk.

To calculate this, we can divide the required amount of milk by the capacity of the measuring cup. In this case, we divide 100ml by 10ml to get:

100ml ÷ 10ml = 10

This means that A very will need to fill her 10ml measuring cup 10 times to get the required amount of milk for her recipe.

Another way to think about it is to consider that 100ml is ten times the capacity of the 10ml measuring cup. Therefore, Avery will need to fill the measuring cup ten times to get the required amount of milk.

In summary, Avery will need to fill her 10ml measuring cup ten times to get the required amount of 100ml of milk for her recipe. t

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Answer: 11

Step-by-step explanation:

f(t)=2(t)-3

f(t)=2t-3

f(7)=2(7)-3

f(7)=14-3

f(7)=11

Answer:

7.02

Step-by-step explanation:

20 ¢ x 5 = 1.00

3 x 3.99 = 11.97

11.97 + 1.00 = 12.97

20.00 - 12.97 = 7.02

Answer:

n | 0 | 0 1

| y 2 | 2 y 3 | 3 años

Step-by-step explanation:

A. The system of equations in standard form is: 4x + 5y = 540 and 3x + 5y = 440.

B. The y-intercept of the equation representing the prices on Saturday night is 108, and the y-intercept of the equation representing the prices at the matinee on the second day is 88.

A) Let's define the variables:

Let x represent the number of children attending.

Let y represent the number of adults attending.

On Saturday night:

The equation for the revenue generated on Saturday night is:

4x + 5y = 540 (since children's tickets cost $4 and adults' tickets cost $5, and the total revenue is $540).

Matinee on the second day:

The equation for the revenue generated at the matinee is:

3x + 5y = 440 (since children's tickets cost $3 and adults' tickets still cost $5, and the total revenue is $440).

Therefore, the system of equations in standard form is:

4x + 5y = 540

3x + 5y = 440

B) Let's rewrite the system of equations in slope-intercept form:

On Saturday night:

4x + 5y = 540

Rearranging the equation, we get:

5y = -4x + 540

Dividing both sides by 5, we get:

y = (-4/5)x + 108

The y-intercept of this equation is 108.

Matinee on the second day:

3x + 5y = 440

Rearranging the equation, we get:

5y = -3x + 440

Dividing both sides by 5, we get:

y = (-3/5)x + 88

The y-intercept of this equation is 88.

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Answer:

The original cost of the digital camera is Rs. 18,500.

Step-by-step explanation:

Let c be the original cost of the digital camera

Since VAT of 13% was added then we can say that the amount that was paid was 13% more than the original price. So the payment made was 113% of the original amount or 1.13 in decimal

Payment = original cost + 13% VAT

20, 905 = c + 0.13c

20, 905 = 1.13c

Divide both sides of the equation by 1.13

20905/1.13 = 1.13c/1.13

18,500 = c

c = Rs. 18,500

The given information does not provide any clear indication for determining the position that should be taken on 3/01 and 3/02. Without additional information, it is not possible to make a decision. The table only displays the closing prices of the July GBP Futures Contract on different days, and it is unclear what trading strategy or what scenario is being considered. Additional information about the goals and objectives, the market conditions, and other relevant factors would be necessary to make a decision about trading positions.

The slope of the line passing through the points (-6, 1) and (8, -7) is -4/7.

Slope is simply expressed as change in y over the change in x.

Slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given the data in the question;

Point A: ( -6,1 )

x₁ = -6

y₁ = 1

Point B: ( 8,-7 )

x₂ = 8

y₂ = -7

Now, plug the given x and y values into the slope formula above and simplify:

\(Slope\ m = \frac{y_2 - y_1}{x_2 - x_1} \\\\Slope\ m = \frac{-7 - 1}{8 - (-6)} \\\\Slope\ m = \frac{-7 - 1}{8 + 6} \\\\Slope\ m = \frac{-8}{14} \\\\Slope\ m = -\frac{4}{7}\)

Therefore, the slope of the line is -4/7.

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The area of ΔQRS is 26.10 square units.

What is triangle?

A triangle is a closed, two-dimensional geometric shape with three straight sides and three angles.

To find the area of \($\triangle QRS$\), we can use the formula:

\($Area = \frac{1}{2} \times base \times height$\)

where the base and height are the length of two sides of the triangle that are perpendicular to each other. We can find these sides using trigonometry.

First, we need to find the length of side \($QR$\). We can use the Law of Cosines:

\($QR^2 = QS^2 + RS^2 - 2(QS)(RS)\cos(R)$\)

where \($R$\) is the angle at vertex \($R$\). Substituting the given values, we get:

\($QR^2 = 9^2 + 5^2 - 2(9)(5)\cos(57^\circ)$\)

\($QR \approx 8.02$\)

Next, we need to find the height of the triangle, which is the perpendicular distance from vertex \($R$\) to side \($QS$\). We can use the sine function:

\($\sin(R) = \frac{opposite}{hypotenuse}$\)

\($\sin(57^\circ) = \frac{height}{8.02}$\)

\($height \approx 6.51$\)

Now we can find the area of the triangle:

\($Area = \frac{1}{2} \times QR \times height$\)

\($Area = \frac{1}{2} \times 8.02 \times 6.51$\)

\($Area \approx 26.10$\) square units

Therefore, the area of \($\triangle QRS$\) is approximately \($26.10$\) square units.

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Answer: in the third draw 33.33% people eliminated.

Step-by-step explanation:

I think u mean thousandths

after the decimal point each number from left to right is written with "-ths" at the end

like

10 = 1 tens

0.1 = 1 tenths

The sequence which is an arithmetic sequence is -2, -8, -14, -20, -26,

Arithmetic sequence is given by

where

n = nth term

a = first term

d = common difference

a = -48

d = -24 - (-48)

= -24 + 48

= 24

a3 = -48 + (3-1) 24

= -48 + (2)24

= -48 + 48

= 0

False

a = -2

d = -8 - (-2)

= -8 + 2

= -6

a3 = -2 + (3 - 1) -6

= -2 + (2)6

= -2 - 12

= -14

True

a = 1

d = 6 - 1

= 5

a3 = 1 + (3-1)5

= 1 + (2)5

= 1 + 10

= 11

False

a = -2

d = 6 - (-2)

= 6 + 2

= 8

a3 = -2 + (3-1)8

= -2 + (2)8

= -2+16

= 14

False

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Answer:

b is correct just took the quiz

Step-by-step explanation:

The solution of the expression is (a² - 2ab + b²).

Given that,

The expression is,

(a⁴ + 4b⁴) ÷ (a² + 2ab + 2b²)

Now, we can write the first term as,

(a⁴ + 4b⁴) = (a² - 2ab + b²) (a² + 2ab + b²)

Hence the expression is written as,

(a⁴ + 4b⁴) ÷ (a² + 2ab + 2b²)

[(a² - 2ab + b²) (a² + 2ab + b²)] ÷ (a² + 2ab + 2b²)

(a² - 2ab + b²) (a² + 2ab + b²) / (a² + 2ab + 2b²)

(a² - 2ab + b²)

Therefore, The solution is (a² - 2ab + b²).

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