Solve for y. 2 + y = 11
A) 9
B) 13
C) 8
D) 22
Answers
Answer:
the answer is y =9
Step-by-step explanation:
2 + 9=11
Answer:
A
Step-by-step explanation:
2+9=11
if not understood here's the explanation even further
2+y=11
y = 11
-2
y = 9
Related Questions
The point P(x, y) is on the terminal ray of angle theta. If theta is between pi and 3pi/2 radians and csc theta equals -5/2 what are the coordinates of P(x, y)?
Answers
Answer:
(-4.58, -2)
Step-by-step explanation:
\(\theta $ is in between \pi$ and $\frac{3\pi}{2}$ radians \\Therefore, \theta$ is in Quadrant III\\If \csc \theta = -\dfrac{5}{2}$ and cosec \theta = \dfrac{Hypotenuse}{Opposite} \\ $Therefore:\\Hypotenuse = 5\\Opposite $=-2\)
Using Pythagoras Theorem
\(5^2=(-2)^2+ x^2\\25=4+x^2\\x^2=21\\x=\sqrt{21} \approx 4.58\)
Since the angle is in the third Quadrant, Adjacent = -4.58.
Therefore, the coordinates of P(x,y) is (-4.58, -2)
Answer: a
Step-by-step explanation: edge 2021
freddy
a drew plan for a rectangular piece of material that will use for a blanket. Three of the vertices are (,), (,), and (,). What are the coordinates of the fourth vertex?
Answers
The fourth vertex's coordinates are as follows: ( 2.1, -3.6)
What are coordinates?A coordinate system in geometry is a method for determining the precise location of points or other geometrical objects on a manifold, such as Euclidean space, using one or more numbers, or coordinates.
So, let the missing coordinates be (a,b).
Let's now utilize the midpoint formula to locate the erroneous coordinate.
Let the reference point be (-2.3, 3.6) A.
Let point B be (2.3, 2.2).
(2.1, 2.2) Let C be the point.
The center of AC should be at BD.
Step 1: Locating the AC's midpoint
Middle pint of AC:
(-2.3 + 2.1/2), (-3.6 + 2.2/2)
(0.2/2), (1.4/2)
(-0.1, -0.7)
Let's equate the midpoints in step two.
The BD mid-point:
(a + -2.3/2), (b + 2.2/2) = (-0.1, -0.7)
(a + -2.3/2) = -0.1
(a -2.3/2) = -0.1*2
a = -0.2+2.3
a = 2.1
(b + 2.2/2) = -0.7
b + 2.2 = -0.7*2
b + 2.2 = -1.4
b = -1.4 -2.2
b = -3.6
Therefore, the fourth vertex's coordinates are as follows: ( 2.1, -3.6)
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Complete question:
Freddy drew a plan for a rectangular piece of material that hehe will use for a blanket. Three of the vertices are ( -2.3 and −3.6), (−2.3, and 2.2), and (2.1, and 2.2). What are the coordinates of the fourth vertex?
What is the derivative of ln ln 4x ))?
Answers
This question deals with the function H(x,y)=
1+x
2
+y
2
x
. Use software (see info about Maple on cover page) to graph H(x,y) for −3≤x≤3,−3≤y≤3. This can be accomplished using the following Maple code: with(plots): f:=(x,y)→x/(1+x
2
+y
2
): plot3d (f(x,y),x=−3..3,y=−3..3, view =−0.5..0.5, orientation =[70,60], axes = boxed, color = cyan ); If you have time, play with changing the options inside the plot3d command. a) Find and simplify H
x
(x,y) and H
y
(x,y). b) Solve for the two points where H
x
(x,y)=0 and H
y
(x,y)=0. Give their x,y,z coordinates.
Answers
The two points where Hx(x,y) = 0 and Hy(x,y) = 0 are (0,0,1) and (0,0,1).
To find and simplify Hx(x,y) and Hy(x,y), we need to differentiate H(x,y) with respect to x and y, respectively.
a) Differentiating H(x,y) with respect to x:
Hx(x,y) = ∂H/∂x = ∂(1+x^2+y^2)^-1/∂x
To simplify, we can use the chain rule:
\(Hx(x,y) = (-1)(1+x^2+y^2)^-2 * ∂(1+x^2+y^2)/∂xHx(x,y) = (-1)(1+x^2+y^2)^-2 * 2xHx(x,y) = -2x/(1+x^2+y^2)^2\)
b) Differentiating H(x,y) with respect to y:
Hy(x,y) = ∂H/∂y = ∂(1+x^2+y^2)^-1/∂y\
Using the chain rule:
\(Hy(x,y) = (-1)(1+x^2+y^2)^-2 * ∂(1+x^2+y^2)/∂yHy(x,y) = (-1)(1+x^2+y^2)^-2 * 2yHy(x,y) = -2y/(1+x^2+y^2)^2\)
To solve for the two points where Hx(x,y) = 0 and Hy(x,y) = 0, we set each derivative equal to zero and solve for x and y.
For Hx(x,y) = 0:
\(-2x/(1+x^2+y^2)^2 = 0\)
Simplifying, we get:
-2x = 0
x = 0
For Hy(x,y) = 0:
\(-2y/(1+x^2+y^2)^2 = 0\)
Simplifying, we get:
-2y = 0
y = 0
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What is the probability that the sample proportion is between 0.2 and 0.42?
Answers
The probability that the sample proportion is between 0.2 and 0.42 can be calculated using the standard normal distribution.
To calculate the probability, we need to assume that the sample proportion follows a normal distribution. This assumption holds true when the sample size is sufficiently large and the conditions for the central limit theorem are met.
First, we need to calculate the standard error of the sample proportion. The standard error is the standard deviation of the sampling distribution of the sample proportion and is given by the formula sqrt(p(1-p)/n), where p is the estimated proportion and n is the sample size.
Next, we convert the sample proportion range into z-scores using the formula z = (x - p) / SE, where x is the given proportion and SE is the standard error. In this case, we use z-scores of 0.2 and 0.42.
Once we have the z-scores, we can use a standard normal distribution table or a statistical software to find the corresponding probabilities. The probability of the sample proportion falling between 0.2 and 0.42 is equal to the difference between the two calculated probabilities.
Alternatively, we can use the z-table to find the individual probabilities and subtract them. The z-table provides the cumulative probabilities up to a certain z-score. By subtracting the lower probability from the higher probability, we can find the desired probability.
In conclusion, the probability that the sample proportion is between 0.2 and 0.42 can be calculated using the standard normal distribution and z-scores. This probability represents the likelihood of observing a sample proportion within the specified range.
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Marlon Audio Company manufactures video tapes. The desired speed of its model SF2000 is 4 inches per second. Any deviation from this value distorts pitch and tempo, resulting in poor sound quality. The company sets the quality specification to 4 t 0.17 inch per second because an average customer is likely to complain and return the tape if the speed is off by more than 0.17 inch per The cost per return is $28. The repair cost before the tape is shipped, however, is only $7 per tape. Required: 1. Compute L(x) if x is 4.12 inches per second. 2. Estimate the tolerance for the firm to minimize its quality-related cost (loss). (Round your answers to 4 decimal places.)
Answers
L(x) if x is 4.12 inches per second is $21.
To estimate the tolerance for the firm to minimize its quality-related cost (loss), we need to determine the range of acceptable speeds that minimize the cost. The tolerance can be calculated as the difference between the upper and lower limits of the acceptable speed range.
Given that the desired speed is 4 inches per second and the quality specification allows a deviation of 0.17 inches per second, we can calculate the upper and lower limits as follows:
Upper Limit = Desired Speed + Tolerance
Lower Limit = Desired Speed - Tolerance
Let's assume the tolerance is represented by 't'.
Upper Limit = 4 + t
Lower Limit = 4 - t
To minimize the quality-related cost, we want to find the smallest value of 't' that satisfies the condition.
The cost can be minimized when the difference between the upper and lower limits is equal to twice the return cost of $28.
Upper Limit - Lower Limit = 2 * $28
(4 + t) - (4 - t) = 2 * $28
2t = 2 * $28
t = $28
Therefore, the estimated tolerance for the firm to minimize its quality-related cost is 0.28 inches per second (rounded to 4 decimal places).
Note: In this scenario, the tolerance is set to 0.28 inches per second to ensure that the cost of returns is minimized for the company.
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What is 13.5 rounded to the nearest whole
number?
Answers
The nearest whole number after rounding is, 14
What is Rounding of a number ?Rounding a number to the nearest tenth means finding the nearest multiple of 0.1.
To do this, you need to look at the digit in the hundredths place (the second digit after the decimal point) of the number you want to round.
If that digit is 5 or greater, you round the number up by adding 0.1 to the nearest whole number.
If that digit is 4 or less, you round the number down by leaving the nearest whole number unchanged.
For example, rounding 3.456 to the nearest tenth gives 3.5, while rounding 3.444 to the nearest tenth gives 3.4.
Given that,
The decimal number 13.5,
after using rules of rounding,
it can be rounded as 14
Hence, the nearest whole number is 14
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Assume an economy in which only broccoli and cauliflower are produced. In year 1, there are 100 million pounds of broccoli produced and consumed and its price is $0.50 per pound, while 30 million pounds of cauliflower are produced and consumed and its price is $0.80 per pound. In year 2, there are 80 million pounds of broccoli produced and consumed and its price is $0.60 per pound, while 60 million pounds of cauliflower are produced and its price is $0.85 per pound. ) Using year 1 as the base year, calculate the GDP price deflator in years 1 and 2, and calculate the rate of inflation between years l and 2 from the GDP price deflator. b) Using year 1 as the base year, calculate the CPI in years 1 and 2, and calculate the CPI rate of inflation. c) Explain any differences in your results between parts (a and (b
Answers
In year 1, the GDP price deflator is calculated to be 0.66 (or 66%), and in year 2, it is 0.77 (or 77%). The rate of inflation between years 1 and 2, as measured by the GDP price deflator, is approximately 16.67%. In contrast, the CPI rate of inflation is calculated to be 20%. The differences in these results can be attributed to the differences in the composition and weighting of the goods included in the GDP price deflator and the Consumer Price Index (CPI).
a) The GDP price deflator measures the average price change of all goods and services produced in an economy. To calculate the GDP price deflator in year 1, we use the formula: (Nominal GDP / Real GDP) * 100. Given the quantities and prices of broccoli and cauliflower in year 1, the nominal GDP is (100 million * $0.50) + (30 million * $0.80) = $65 million, and the real GDP is (100 million * $0.50) + (30 million * $0.50) = $55 million. Thus, the GDP price deflator in year 1 is (65/55) * 100 = 118.18%. In year 2, the nominal GDP is (80 million * $0.60) + (60 million * $0.85) = $88 million, and the real GDP is (80 million * $0.50) + (60 million * $0.50) = $70 million. Therefore, the GDP price deflator in year 2 is (88/70) * 100 = 125.71%. The rate of inflation between years 1 and 2, as measured by the GDP price deflator, is ((125.71 - 118.18) / 118.18) * 100 = 6.36%.
b) The Consumer Price Index (CPI) measures the average price change of a basket of goods and services typically consumed by households. To calculate the CPI in year 1, we assign weights to the prices of broccoli and cauliflower based on their consumption quantities. The CPI in year 1 is (100 million * $0.50) + (30 million * $0.80) = $65 million. In year 2, the CPI is (80 million * $0.60) + (60 million * $0.85) = $81 million. The CPI rate of inflation between years 1 and 2 is ((81 - 65) / 65) * 100 = 24.62%.
c) The differences in the results between parts (a) and (b) can be attributed to the differences in the composition and weighting of goods included in the GDP price deflator and the CPI. The GDP price deflator considers the prices of all goods and services produced in the economy, reflecting changes in production patterns and the overall price level. On the other hand, the CPI focuses on a fixed basket of goods and services consumed by households, reflecting changes in the cost of living. The differences in the weighting and composition of goods between the two measures result in variations in the calculated inflation rates.
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I need help with this, PLEASE
Answers
Answer:
Mean = 3
Step-by-step explanation:
0 + 0 + 1 + 1 + 1 + 2 + 3 + 4 + 4 + 5 + 6 + 6 + 6 = 39
39/13 = 3
Answer:
The mean is 3
Step-by-step explanation:
If you add every x like this: 6+6+6+5+4+4+3+2+1+1+1 in your calculator, you'll get 39 then divide by the number of x's which is 13 you'll get 3. Good luck!!
Identify the scale factor used to dilate triangle ABC to triangle DEF.
A(2,6), B(4,2), C(8,8)
D(3,9), E(6, 3), F(12, 12)
A. 3/2
B. 3
C. 2
D. 5/2
Answers
solve for x
PLEASE HELP FAST
Answers
Answer:
x = 19.8
Step-by-step explanation:
Shona is buying a rug for her room. Store A has the rug for $45 with a 10% discount. Store B has the same rug for $46 and is offering a $10 off coupon. The sales tax is 6% on either purchase. If Shona only has $40 to spend, which store will she purchase the rug from, and how much will she have left over? Shona can afford the rug in store A. She will have $2. 93 left over. Shona can afford the rug in store B. She will have $1. 84 left over. Shona can afford the rug in store B. She will have $2. 93 left over. Shona can afford the rug in store A. She will have $1. 84 left over.
Answers
Percent is a part or amount in the given hundred. The value of the whole in the fraction part of 100 is percentage value of the number. The Shona can afford the rug in store B. She will have $1. 84 left over.
Given information-
Store A has the rug for $45 with a 10% discount.
Store B has the same rug for $46 and is offering a $10 off coupon.
The sales tax is 6%.
Total money is $40.
Percentage
Percent is a part or amount in the given hundred. The value of the whole in the fraction part of 100 is percentage value of the number.
a) The price of the rug at store A,
The price of the rug at store A after the 10 percent discount,
\(Pa=45-\dfrac{45}{100}\times10\)
\(P_a=45-4.5\)
\(P_a=40.5\)
The price of the rug at store A after the 10 percent discount is 40.5. The price of the rug at store A after the 6 percent sales tax.
\(P_a=40.5+\dfrac{40.5}{100} \times6\)
\(P_a=42.93\)
b) The price of the rug at store B,
The price of the rug at store B after the $10 off coupon
\(Pa=46-10\)
\(P_a=36\)
The price of the rug at store A after the $10 off coupon is 35. The price of the rug at store B after the 6 percent sales tax.
\(P_a=36+\dfrac{36}{100} \times6\)
\(P_a=38.16\)
Thus Shona buy rug from the store B.
The money she will left over,
\(=40-38.16=1.84\)
Thus the Shona can afford the rug in store B. She will have $1. 84 left over.
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Use the Regression tool on the accompanying wedding data, using the wedding cost as the dependent variable and attendance as the independent variable. Complete parts a through c.
Wedding Cost Attendance
58700 300
50000 350
47000 150
44000 200
35000 250
31500 150
31000 250
29000 300
28000 250
27000 200
27000 150
24000 200
22000 200
22000 200
21000 200
20000 200
19000 100
19000 150
18000 200
17000 150
15000 100
15000 100
14000 150
6000 50
4000 50
a. What is the regression model?
Wedding Cost=_______+_______×Attendance
(Round to three decimal places as needed.)
b. Interpret all key regression results, hypothesis tests, and confidence intervals in the regression output from part a.
Interpret the slope of the regression equation. Choose the correct answer below.
A.The slope indicates that for each increase of 1 in wedding cost, the predicted attendance is estimated to increase by a value equal to
b 1
B.The slope indicates that for each increase of 1 in attendance, the predicted wedding cost is estimated to increase by a value equal to
b 1
C. It is not appropriate to interpret the slope because it is outside the range of observed wedding costs.
D. It is not appropriate to interpret the slope because it is outside the range of observed attendances.
Interpret the Y-intercept of the regression equation. Choose the correct answer below.
A.The Y-intercept indicates that a wedding with a cost of $0 has a mean predicted attendance of b 0 people.
B. It is not appropriate to interpret the Y-intercept because it is outside the range of observed wedding costs.
C. It is not appropriate to interpret the Y-intercept because it is outside the range of observed attendances.
D.The Y-intercept indicates that a wedding with an attendance of 0 people has a mean predicted cost of $b 0.
Identify and interpret the meaning of the coefficient of determination in this problem. Select the correct choice below and fill in the answer box to complete your choice.
(Round to three decimal places as needed.)
A.The coefficient of determination is Upper R squared_______ This value is the probability that the correlation between the variables is statistically significant.
B.The coefficient of determination is Upper R squared________This value is the proportion of variation in attendance that is explained by the variation in wedding cost.
C.The coefficient of determination is Upper R squared_______ This value is the probability that the slope of the regression line is statistically significant.
D.The coefficient of determination is Upper R squared________ This value is the proportion of variation in wedding cost that is explained by the variation in attendance.
Interpret the values given in the test of the population slope. Use a=0.050 level of significance. State the null and alternative hypotheses the test.
Upper H 0H0:_________
Upper H 1H1:_________
(Round to two decimal places as needed.)
Identify the p-value.
The p-value is_______
(Round to three decimal places as needed.)
State the conclusion.
▼
Fail to reject
Reject
Upper H 0H0.
There
▼
is sufficient
is not sufficient
evidence of a linear relationship between wedding cost and attendance.
Identify and interpret the
9595%
confidence interval estimate of the population slope.
The confidence interval is nothingless than or equals≤
▼
b 0b0
beta 1β1
b 1b1
beta 0β0
less than or equals≤nothing. With
9595%
confidence, it can be said that true expected mean increase in
▼
wedding cost
attendance
per additional
▼
person attending
dollar spent on
the wedding is within the bounds of the confidence interval.
(Round to three decimal places as needed.)
c. If a couple is planning a wedding for
325325
guests, how much should they budget?
They should budget
$_____________
(Round to the nearest dollar as needed.)
Answers
The 95% confidence interval cestimate of the population slope is obtained from the regression output and provides a range of values within which we can be 95% confident that the true population slope falls.
Here, we have,
a. The regression model is:
Wedding Cost = b₀ + b₁ * Attendance
b. The interpretation of the slope of the regression equation is:
D. The slope indicates that for each increase of 1 in wedding cost, the predicted attendance is estimated to increase by a value equal to b1.
c. The interpretation of the Y-intercept of the regression equation is:
B. The Y-intercept indicates that a wedding with an attendance of 0 people has a mean predicted cost of $b0.
The coefficient of determination (R²) in this problem represents the proportion of variation in wedding cost that is explained by the variation in attendance.
Therefore, the correct interpretation is:
B. The coefficient of determination is R² = [value]. This value is the proportion of variation in wedding cost that is explained by the variation in attendance.
The null and alternative hypotheses for the test of the population slope are:
H₀: The population slope (b₁) is equal to 0.
H₁: The population slope (b₁) is not equal to 0.
The test statistic used to test the population slope is t-test.
The conclusion of the test should be based on the p-value obtained from the test. If the p-value is less than the significance level (0.05), we reject the null hypothesis and conclude that there is evidence of a linear relationship between wedding cost and attendance.
The 95% confidence interval estimate of the population slope is obtained from the regression output and provides a range of values within which we can be 95% confident that the true population slope falls.
To determine the budget for a wedding with 325 guests, we can use the regression model and substitute the value of attendance into the equation to get the predicted wedding cost.
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lily needs 16 inches of copper wire for an experiment.The wire is sold by the centimeter.Given that 1 inch = 2.54 centimeter, how many centimeters of wire does lily need.
Answers
Lily would need 40.64 centimeters of copper wire for her experiment.
Given data ,
We may use the conversion factor that 1 inch is equivalent to 2.54 centimeters to convert 16 inches to centimeters .
From the unit conversion ,
1 inch = 2.54 inches
Consequently, 16 inches is equivalent to :
40.64 centimeters are equal to 16 inches at 2.54 centimeters per inch.
Hence , Lily would thus want 40.64 centimeters of copper wire for her experiment.
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A trapezoid has bases of lengths 26 and 30. Find the trapezoid's height if it's area is 448
Answers
Answer:
16 units
Step-by-step explanation:
The formula for the area of a trapezoid is:
A = (1/2)h(b1 + b2)
We are given that the bases have lengths of 26 and 30 and the area is 448. Substituting these values into the formula above, we get:
448 = (1/2)h(26 + 30)
448 = (1/2)h(56)
Multiplying both sides by 2/56, we get:
16 = h
Therefore, the height of the trapezoid is 16 units.
Hope this helps you and have a great day!
-4×(-2)[2×(-6)+3×(2×6-4-4)]
Answers
\(\large{\underline {\underline {\frak {SolutioN:-}}}}\)
➝ -4 × (-2) [2 × (-6)+ 3×(2×6-4-4) ]
➝ -4 × (-2) [2 × (-6) + 3 × (12-4-4) ]
➝ -4 × (-2) [2 × (-6) + 3 × (12-8) ]
➝ -4 × (-2) [2 × (-6) + 3 × (4) ]
➝ -4 × (-2) [2 × (-6) + 12 ]
➝ -4 × (-2) [(-12) + 12 ]
➝ -4 × (-2) [0]
➝ -4 × 0
➝ 0
Answer:
-4*-2
Step-by-step explanation:
the multiple of both side is 4*2*,26+*32*--=6 44
How can you determine the sign of the
difference of two numbers before
you
subtract the
Answers
Answer:
Hi how are you doing today Jasmine
for rayleigh winds with an average wind speed of 8 m/s: a. how many hours per year do the winds blow at less than 13 m/s? (5') b. how many hours per year are wind speeds above 25 m/s? (5')
Answers
A. 7658.8 hr/year
B. 4.082 hr/year
C. 99206 kwh
Moreover, The annual average wind speed was calculated directly at 4.56 m/s. Using the Weibull distribution, the annual wind speed is 4.55 m/s, while using the Rayleigh distribution it is 4.523 m/s. The annual wind power density was directly calculated to be 114.54 W/m2.
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Evaluate the following integral to ∫ fx cos(x) (x − 2) dx.
Answers
The integral of the given function is (\(x^2\) sin(x) - 2x cos(x) + 2 sin(x)) + C.
To evaluate the integral ∫x cos(x) (x - 2) dx, we can expand the expression and then integrate it term by term.
Expanding the expression:
∫x cos(x) (x - 2) dx = ∫(\(x^2\) - 2x) cos(x) dx
Now, we can integrate term by term:
∫\(x^2\) cos(x) dx - ∫2x cos(x) dx
For the first term, we can use integration by parts. Let's choose u = \(x^2\) and dv = cos(x) dx.
Differentiating u, we get du = 2x dx.
Integrating dv, we get v = ∫cos(x) dx = sin(x).
Using integration by parts formula ∫u dv = uv - ∫v du, we have:
∫\(x^2\) cos(x) dx = \(x^2\)sin(x) - ∫2x sin(x) dx
Now, let's focus on the second term ∫2x sin(x) dx. We can again use integration by parts. Let's choose u = 2x and dv = sin(x) dx.
Differentiating u, we get du = 2 dx.
Integrating dv, we get v = -cos(x).
Using integration by parts, we have:
∫2x sin(x) dx = -2x cos(x) - ∫(-2 cos(x)) dx
= -2x cos(x) + 2 ∫cos(x) dx
= -2x cos(x) + 2 sin(x)
Bringing everything together, we have:
∫\(x^2\)cos(x) dx - ∫2x cos(x) dx = (\(x^2\)sin(x) - 2x cos(x) + 2 sin(x)) + C
Therefore, the evaluated integral is (\(x^2\)sin(x) - 2x cos(x) + 2 sin(x)) + C, where C is the constant of integration.
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bearing is measured from reference line clockwise or counter-clockwise. group of answer choices true false
Answers
Bearing is measured from reference line clockwise or counter-clockwise - FALSE.
A bearing is an angle that is calculated clockwise from the north.
The vertical angle between an object's direction and either north or another object is known as a bearing or azimuth in navigation. You can specify the angle value in a number of different angular units, including degrees, mils, and grad.
Angles are measured in comportments clockwise from north.
The direction of north must be identified before taking a bearing measurement.
The math exam question will typically include this north direction. The required angle is then measured in a clockwise fashion. Since all bearings must be reported in three figures, we must begin the three-figure bearing with zero if the angle measured is less than 100 degrees.
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The television show September Road has been successful for many years. That show recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to September Road. Assume that an advertiser wants to verify that 20% share value by conducting its own survey, and a pilot survey begins with 11 households have TV sets in use at the time of a September Road broadcast. Find the probability that none of the households are tuned to September Road. P(none)
Answers
Answer:
\(P(none) = 0.0859\)
Step-by-step explanation:
Given
\(p =20\%\) --- proportion of household that tuned to September
\(n =11\) --- selected households
Required
\(P(none)\)
Using the complement rule, the proportion that did not tune (q) is:
\(q= 1 - p\)
\(q= 1 - 20\%\)
\(q= 1 - 0.20\)
\(q= 0.80\)
So, the probability that none of the 11 tuned in is:
\(P(none) = q^{11}\)
\(P(none) = 0.80^{11}\)
\(P(none) = 0.0859\)
Tessa has $42 to spend at the county fair. Her admission
ticket cost $7.50. How much money could she spend on
games and food? Write an inequality to represent this
situation and solve.
can someone help me?
Answers
Answer
g is less than or equal to 34.50
Step-by-step explanation:
$42-$7.50=$34.50
5. Solve 6(x - 1) = 6x - 6
Answers
Answer:
Its infinite solutions because its the same exact thing when you simplify the first half of the problem.
Step-by-step explanation:
Answer:
Infinite Solution
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
6(x−1)=6x−6
(6)(x)+(6)(−1)=6x+−6 (Use Distributive Property)
6x+−6=6x+−6
6x−6=6x−6
Step 2: Subtract 6x from both sides.
6x−6−6x=6x−6−6x
−6=−6
Step 3: Add 6 to both sides.
−6+6=−6+6
0=0
Evangeline is making snack bags for her class. If she can fill 5/8 of her snack bags with 1 2/3 cups of pretzels, how many cups of pretzels are needed to fill all of the snack bags? Write a multiplication equation and a division equation for the situation, then answer the question. Show your reasoning.
Answers
Answer:
2 2/3
Step-by-step explanation:
For each of her snack bag, she can fill it with a 1/3 cup of pretzels
1/3 x 8 = 2 2/3 cups
Answer:
Step-by-step explanation:
÷*20 points* 7x + 24 = 2x - 6 How many solutions?
Answers
Answer:
x= -6
Step-by-step explanation:
so i'm thinking 1 solution.
(let me know if i'm wrong)
Answer:
infinitely many solutions.
Step-by-step explanation:
If solving an equation yields a statement that is true for a single value for the variable, like x = 3, then the equation has one solution. If solving an equation yields a statement that is always true, like 3 = 3, then the equation has
A car dealer determines that if gasoline-electric hybrid automobiles are sold for x dollars apiece and the price of gasoline is y cents per gallon, then approximately h hybrid cars will be sold each year, where
h(x,y)=3,500−19x^1/2+6(0.1y+16)^3/2
She estimates that t years from now, the hybrid cars will be selling for
x(t) = 35,050 + 350t
dollars apiece and that gasoline will cost
y(t)=300+10(3t)^1/2
cents per gallon. At what rate will the annual demand for the hybrid cars be changing with respect to time 3 years from now? Will it be increasing or decreasing?
Answers
The annual demand for hybrid cars will be changing at a rate of approximately -756 cars per year 3 years from now. The demand will be decreasing at that time.
To find the rate of change of the annual demand for hybrid cars with respect to time, we need to calculate the derivative of the demand function h(x, y) with respect to time. Given the functions x(t) and y(t) that represent the price of hybrid cars and the price of gasoline in terms of time, we can substitute these functions into the demand function h(x, y) to get h(t).
Then, we take the derivative of h(t) with respect to t and evaluate it at t = 3 to find the rate of change of the annual demand at that time. Using the chain rule and simplifying the expression, we can calculate the derivative:
h'(t) = -19\((350t)^(-1/2)\) + 6(0.1 * 10\((3t)^(-1/2) + 16)^(3/2)\)
After substituting t = 3 into the derivative function and simplifying, we find that h'(3) ≈ -756. This means that the annual demand for hybrid cars will be decreasing at a rate of approximately 756 cars per year 3 years from now.
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A carpet manufacturer is inspecting for flaws in the finished product. If there are too many blemishes, the carpet will have to be destroyed. He finds the number of flaws in each square yard and is interested in the average number of flaws per 10 square yards of material. If we assume the standard deviation of the number of flaws per square yard is 0.6, the sample mean, , for the 10 square yards will a standard deviation of
Answers
Answer:
10 square meters will have a standard deviation of 1.897.
Step-by-step explanation:
Standard deviation for n instances of a variable:
If the standard deviation for one instance of a variable is \(\sigma\), for n instances of the variable, the standard deviation will be of \(s = \sigma\sqrt{n}\)
The standard deviation of the number of flaws per square yard is 0.6
This means that \(\sigma = 0.6\)
For the 10 square yards will a standard deviation of
\(n = 10\), so:
\(s = \sigma\sqrt{n} = 0.6\sqrt{10} = 1.897\)
10 square meters will have a standard deviation of 1.897.
Select a piece of information you can get by looking up a word in the dictionary.
A word that means the opposite
Similar meaning words
The part of speech
Translation into a language
Answers
Answer: Analogy
Step-by-step explanation: (Sorry if it is not right) :(
Answer:
Step-by-step explanation:
The part of speech
PLEASE HELP ME ANSWER IF YOU HURRY ILL GIVE POINTSSSS
Answers
Answer:
3rd one and the 4th one
Step-by-step explanation:
Hopt it helps.....
A study published in 2008 in the American Journal of Health Promotion (Volume 22, Issue 6) by researchers at the University of Minnesota (U of M) found that 124 out of 1,923 U of M females had over $6,000 in credit card debt while 61 out of 1,236 males had over $6,000 in credit card debt.
10. Verify that the sample size is large enough in each group to use the normal distribution to construct a confidence interval for a difference in two proportions.
11. Construct a 95% confidence interval for the difference between the proportions of female and male University of Minnesota students who have more than $6,000 in credit card debt (pf - pm). Round your sample proportions and margin of error to four decimal places.
12. Test, at the 5% level, if there is evidence that the proportion of female students at U of M with more that $6,000 credit card debt is greater than the proportion of males at U of M with more than $6,000 credit card debt. Include all details of the test
Answers
To determine if the sample size is large enough to use the normal distribution for constructing a confidence interval for the difference in two proportions, we need to check if the conditions for using the normal approximation are satisfied.
The conditions are as follows:
The samples are independent.
The number of successes and failures in each group is at least 10.
In this case, the sample sizes are 1,923 for females and 1,236 for males. Both sample sizes are larger than 10, so the second condition is satisfied. Since the samples are independent, the sample sizes are large enough to use the normal distribution for constructing a confidence interval.
To construct a 95% confidence interval for the difference between the proportions of females and males with more than $6,000 in credit card debt (pf - pm), we can use the formula:
CI = (pf - pm) ± Z * sqrt((pf(1-pf)/nf) + (pm(1-pm)/nm))
Where:
pf is the sample proportion of females with more than $6,000 in credit card debt,
pm is the sample proportion of males with more than $6,000 in credit card debt,
nf is the sample size of females,
nm is the sample size of males,
Z is the critical value for a 95% confidence level (which corresponds to approximately 1.96).
Using the given data, we can calculate the sample proportions:
pf = 124 / 1923 ≈ 0.0644
pm = 61 / 1236 ≈ 0.0494
Substituting the values into the formula, we can calculate the confidence interval for the difference between the proportions.
To test if there is evidence that the proportion of female students with more than $6,000 in credit card debt is greater than the proportion of male students with more than $6,000 in credit card debt, we can perform a hypothesis test.
Null hypothesis (H0): pf - pm ≤ 0
Alternative hypothesis (H1): pf - pm > 0
We will use a one-tailed test at the 5% significance level.
Under the null hypothesis, the difference between the proportions follows a normal distribution. We can calculate the test statistic:
z = (pf - pm) / sqrt((pf(1-pf)/nf) + (pm(1-pm)/nm))
Using the given data, we can calculate the test statistic and compare it to the critical value for a one-tailed test at the 5% significance level. If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that there is evidence that the proportion of female students with more than $6,000 in credit card debt is greater than the proportion of male students with more than $6,000 in credit card debt.
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