Solve for x . Pls help!

!! I’ll give brainliest! :)

Main Answer: The rate at which the radius is increasing is 1/3 m/min when the volume is 36πm³.

Supporting Explanation: Given that the volume of the spherical balloon is increasing at the rate of 5 m³/min and the volume of the balloon is given as 36π m³.The volume of the balloon is given by v = 4πr³ / 3. Therefore, 4πr³ / 3 = 36π. This gives the radius of the balloon as: r = cuberoot(27) = 3m.Then, differentiating the volume equation with respect to time, t, we get: dv/dt = 4π(3r²)dr/dt. Rearranging the above equation, we get: dr/dt = (1/3)(dv/dt) / r².Substituting the values, we get: dr/dt = (1/3 * 5) / 3²dr/dt = 1/3 m/min. Therefore, the rate at which the radius is increasing is 1/3 m/min when the volume is 36πm³.Here, the keywords used are spherical balloon, volume, rate, radius, and cuberoot.

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Dont use this website

Its a sham

The convolution integral y(t) = x(t) * h(t) for the given pair of signals x(t) and h(t) can be computed as follows:

y(t) = ∫[x(τ) * h(t - τ)] dτ

1) x(t) = δ(t) and h(t) = δ(t - 2) * (t - 1)

The convolution integral becomes:

y(t) = ∫[δ(τ) * δ(t - τ - 2) * (τ - 1)] dτ

To evaluate this integral, we consider the properties of the Dirac delta function. When the argument of the Dirac delta function is not zero, the integral evaluates to zero. Therefore, the integral simplifies to:

y(t) = δ(t - 2) * (t - 1)

The convolution result y(t) is equal to the shifted impulse response h(t - 2) scaled by the factor of (t - 1). This means that the output y(t) will be a shifted and scaled version of the impulse response h(t) at t = 2, delayed by 1 unit.

In summary, for x(t) = δ(t) and h(t) = δ(t - 2) * (t - 1), the convolution integral y(t) = x(t) * h(t) simplifies to y(t) = δ(t - 2) * (t - 1).

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The results are different because the simulated data is based on random numbers and may not perfectly match the probability distribution.

To simulate the emergency calls for 3 days, we need to use a cumulative hourly clock and generate random numbers to determine when the calls will occur. Let's use the following table of random numbers:

Random Number Call Time

57 1 hour

23 2 hours

89 3 hours

12 4 hours

45 5 hours

76 6 hours

Starting at 12:00 AM on the first day, we can generate the following sequence of emergency calls:

Day 1:

12:00 AM - Call

1:00 AM - No Call

3:00 AM - Call

5:00 AM - No Call

5:00 PM - Call

Day 2:

1:00 AM - No Call

2:00 AM - Call

4:00 AM - No Call

7:00 AM - Call

8:00 AM - No Call

11:00 PM - Call

Day 3:

12:00 AM - No Call

1:00 AM - Call

2:00 AM - No Call

4:00 AM - No Call

7:00 AM - Call

9:00 AM - Call

10:00 PM - Call

The average time between calls can be calculated by adding up the times between each call and dividing by the total number of calls. Using the simulated data from part a, we get:

Average time between calls = ((2+10+10+12)+(1+2+3)) / 7 = 5.57 hours

The expected value of the time between calls can be calculated using the probability distribution:

Expected value = (1/6)x1 + (1/6)x2 + (1/6)x3 + (1/6)x4 + (1/6)x5 + (1/6)x6 = 3.5 hours

The results are different because the simulated data is based on random numbers and may not perfectly match the probability distribution. As more data is generated and averaged, the simulated results should approach the expected value.

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There is a slight possibility of 0.000240 that  5 card hand contains a four-of-a-kind, where the four-of-a-kind rank is a face card.

Total possible outcomes=⁵²C₅

                                        = 2598960

P( 4-of-a-kind) = ¹³C₁ * ⁴C₄

                        = 13

P( choosing one card from the rest of the deck) = ⁴⁸C₁

                                                                                 =48

P( 4-of-a-kind card with one different card)

= desired outcome / total number of outcomes.

= (13* 48) / 2598960

= 624/2598960

= 0.000240

Therefore, we get that the probability is 0.0240% .

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Answer:

I'm pretty sure your answer would be B

Step-by-step explanation:

The teacher wants answers from all the students but it would take to long to ask every single person so it would only make sense to ask every boy in each grade

Answer:

25

Step-by-step explanation:

take the square root of 24^2+7^2

The length of the hypotenuse in the right triangle is 25 units.

Hence the correct option is B.

Given is a right triangle with base length b = 24 and the perpendicular a = 7.

We need to find the length of the hypotenuse c.

To find the length of the hypotenuse, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b).

The Pythagorean theorem can be expressed as:

c² = a² + b²

Substituting the given values:

c² = 7² + 24²

c² = 49 + 576

c² = 625

To find the length of c, we need to take the square root of both sides:

c = √625

c = 25

Therefore, the length of the hypotenuse (c) is 25.

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Answer:

12:3

Step-by-step explanation:

Proportional reasoning can be used to make an estimate about a population using data from a sample by assuming that the sample is representative of the population as a whole.

Proportional reasoning involves using the relationship between different parts of a whole to estimate an unknown value.

To apply proportional reasoning to a population estimate, you would first need to gather a random sample of individuals from the population. Then, you could use the data from the sample to estimate the value of a particular characteristic or parameter for the entire population.

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The time it will take for the ball to hit the ground can be found by solving the quadratic equation \(-16t^2 + 32t + 128 = 0\). One of the solutions will represent the time when the ball hits the ground.

The height of the ball as a function of time can be represented by an equation that considers the initial height, initial speed, and the effects of gravity. The equation takes the form of h(t) = \(-16t^2 + v0t + h0\), where h(t) represents the height at time t, v0 is the initial speed, h0 is the initial height, and -16t^2 represents the effect of gravity.

In this case, the initial height of the ball is 128 feet, the initial speed is 32 feet per second, and we want to find the time it takes for the ball to hit the ground (when the height is 0). We can set h(t) = 0 and solve the equation \(-16t^2 + 32t + 128 = 0\) for t.

By solving the quadratic equation, we can find the two possible values for t. One of the values will represent the time when the ball was thrown up, and the other value will represent the time when the ball hits the ground. We discard the negative value and consider the positive value as the time it takes for the ball to hit the ground.

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Answer:

 It will take 4 seconds for the ball to hit the ground.

Step-by-step explanation:

False. One liter is not about an ounce, a pint, a quart, or a gallon. It is a metric unit of volume that is equivalent to approximately 33.8 fluid ounces, 2.1 pints, 1.06 quarts, or 0.26 gallons.

One liter is not about an ounce, a pint, a quart, or a gallon. It is a metric unit of volume that is equivalent to approximately 33.8 fluid ounces, 2.1 pints, 1.06 quarts, or 0.26 gallons.

The liter is a unit of measurement for volume that is part of the metric system. It is used in many countries around the world, including the United States, where it is often used in scientific and medical fields. One liter is defined as the volume of a cube that is 10 centimeters on each side.  In comparison to other common units of volume measurement, one liter is equivalent to approximately 33.8 fluid ounces. This means that if you have a container that holds one liter of liquid, it would also hold approximately 33.8 fluid ounces of liquid.  One liter is also equivalent to approximately 2.1 pints. This means that if you have a container that holds one liter of liquid, it would also hold approximately 2.1 pints of liquid.

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Answer:

5A)36 5b)30(mark as brainliest)

Step-by-step explanation:

5a)6+6+6+6+12 = 36

5b)36-8=28

28+2 = 30

Answer:

a: The answer is 36 units squared

b: You would lose four square units

Step-by-step explanation:

a: You can count the pieces showing, but you also have to add the amount you cannot see, which would give you a total of 36 units squared (since it doesn't say what each unit is represented by

b: The bottom pieces that originally were not showing would now be showing, but you would lose the ones above it. These cancel out from each other. There are 4 other sides that are now no longer showing since the others that are still showing still were anyways, so there are 4 units squared missing from the surface area when you remove the top two blocks.

Numerical methods or approximation techniques such as the method of undetermined coefficients or Laplace transforms can be used to obtain an approximate solution.

a) The given equation represents the motion of a mass-spring system with damping. Here is the physical interpretation of the equation:

The mass (m): It indicates the amount of matter in the system and is given as 1 kg in this case. The mass affects the inertia of the system and determines how it responds to external forces.

Spring stiffness (k): It represents the strength of the spring and is given as 3 N/m in this case. The spring stiffness determines how much force is required to stretch or compress the spring. A higher value of k means a stiffer spring.

Damping coefficient (c): The damping term, 2x', represents the damping force in the system. The coefficient 2 determines the strength of damping. Damping opposes the motion of the system and dissipates energy, resulting in the system coming to rest over time.

External force (sin(1) + 6(1-2)): The term sin(1) represents a sinusoidal external force acting on the system, and 6(1-2) represents a constant force. These external forces can affect the motion of the mass-spring system.

The equation combines the effects of the mass, spring stiffness, damping, and external forces to describe the motion of the system over time.

b) To solve the given equation, we need to find the solution for x(t). However, since the equation is nonlinear and nonhomogeneous, it is not straightforward to provide an analytical solution. Numerical methods or approximation techniques such as the method of undetermined coefficients or Laplace transforms can be used to obtain an approximate solution.

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4 games as:

5.59 * 8 = 44.72

178.88/44.72 = 4

Answer = C. 4

Mark as Brainliest please

Based on the given data, we can calculate the control limits using 3-sigma for the diameter of the auto pistons.

a) The value of x is 155.56 mm (rounded to two decimal places).

b) The value of R is 4.44 mm (rounded to two decimal places).

c) Using 3-sigma, the Upper Control Limit (UCL) for the diameter is calculated as:

UCL = x + 3R = 155.56 + 34.44 = 156.93 mm (rounded to two decimal places)

The Lower Control Limit (LCL) for the diameter is calculated as:

LCL = x - 3R = 155.56 - 34.44 = 154.19 mm (rounded to two decimal places)

d) Using 3-sigma, the Upper Control Limit for the Range (UCLR) is calculated as:

UCLR = D4 * R = 2.115 * 4.44 = 7.89 mm (rounded to two decimal places)

The Lower Control Limit for the Range (LCLR) is always 0 in this case since negative ranges are not possible.

e) If the true diameter mean should be 155 mm, the new centerline (nominal line) would be 155 mm. In this case, the UCL and LCL would be calculated using 3-sigma as follows:

UCL = Nominal + 3R = 155 + 34.44 = 156.37 mm (rounded to two decimal places)

LCL = Nominal - 3R = 155 - 34.44 = 153.63 mm (rounded to two decimal places)

Please note that the control limits calculated using 3-sigma assume a normal distribution and the data follows the same pattern in the future.

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The complete question is:

What is the value of x? = x= 155.56 mm (round your response to two decimal places). b) What is the value of R? R= 4.44 mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Upper Control Limit (UCL) = 156.93 mm (round your response to two decimal places). Lower Control Limit (LCL) = 154.19 mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)= 7.89 mm (round your response to two decimal places). Lower Control Limit (LCLR)= 0.99 mm (round your response to two decimal places). e) If the true diameter mean should be 155 mm and you want this as your center (nominal) line, what are the new UCL and LCL? Upper Control Limit (UCL)= 156.37 mm (round your response to two decimal places). Lower Control Limit (LCL;)= 153.63 mm (round your response to two decimal places). Refer to Table 56.1-Factors for Computing Control Chart Limits (3 sigma) for this problem Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day 1 2 3 4 5 Mean x (mm) 150.9 153.2 153.6 153.5 154.6 Range R (mm) 4.0 4.8 4.1 4.8 4.5

There are 45,697,600 different number of plates that can be issued using this configuration.

To determine the number of different license plates that can be issued using the given configuration, we need to consider the number of options for each component of the license plate.

1. Letters (first two letters): Each letter can be any uppercase letter of the alphabet.

There are 26 letters in the English alphabet, so there are 26 options for each letter.

Since we have two letters, the total number of options for the first two letters is 26 * 26 = 676.

2. Digits (two digits): Each digit can be any number from 0 to 9, so there are 10 options for each digit.

Since we have two digits, the total number of options for the digits is 10 * 10 = 100.

3. Letters (last two letters): Similar to the first two letters, there are 26 options for each letter.

Therefore, the total number of options for the last two letters is also 26 * 26 = 676.

To find the total number of possible license plates, we multiply the number of options for each component:

Total number of license plates = (Number of options for letters) * (Number of options for digits) * (Number of options for letters)

Total number of license plates = 676 * 100 * 676

Total number of license plates = 45,697,600

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Answer:

c. It would decrease

Step-by-step explanation:

When you increase the sample size, you decrease the standard/marginal error since you have a bigger representation of the population. However, this would take time and money to collect data for these big samples.

Answer: £18693.96

Step-by-step explanation:

16470.45 + 16470.45(0.135)

= 16470.45(1 + 0.135)

= 16470.45(1.135)

≈ 18693.96

2x + 6y when x is -4/5 and y is 1/3

Evaluate:

2(-4/5) + 6(1/3)

= 2/5 or 0.4(decimal form)

2/5 or 0.4 would be your answer.

Hope this helps!

Answer:

18+3

Step-by-step explanation:

3x6= 18

and 18+3=21

The DWL falls when the monopolist receives the subsidy because it leads to an increase in output and a decrease in price.

The cost function and demand function of a monopolist can be found in the question. These can be used to derive the marginal revenue and marginal cost.

The optimal level of output and profit can be derived using the marginal revenue and marginal cost equations. After that, you can confirm that the demand is elastic at the optimal output.

After that, you need to calculate the markup and the DWL associated with the monopoly output. Finally, you need to find the new optimal output and determine if the DWL increases or decreases.

Given:Cost Function C(Q) = ¼ Q2 Marginal cost MC(Q) = ½ Q Demand P = 100 – ¼ Q. a.

Sketch the market demand, marginal costs, and marginal revenues.

Market demand:Marginal cost:Marginal revenue: b. What is the monopolist’s optimal level of output and profits?In the monopolistic market, the optimal level of output and profits are given by the condition that Marginal Revenue = Marginal Cost.

Marginal Revenue is the derivative of Total Revenue with respect to Quantity, which can be found by using the demand equation and solving for Q:TR(Q) = P × Q = (100 – ¼ Q)Q = 100Q – ¼ Q2MR(Q) = dTR(Q)/dQ = 100 – ½ QMarginal Cost is given by the question as MC(Q) = ½ Q.

The monopolist's optimal level of output and profits can be found by equating MR and MC:100 – ½ Q = ½ Q => Q = 66.67 units of outputWhen Q = 66.67, the price is given by the demand equation:P = 100 – ¼ Q => P = 83.33.

Therefore, the monopolist's optimal output is 66.67 and optimal profits are (P – MC) × Q = (83.33 – 33.33) × 66.67 = $2,000.

Confirm that demand is elastic at the optimal output.The demand is elastic at the optimal output if the absolute value of the price elasticity of demand is greater than one.

The price elasticity of demand is given by:Ed = (% Change in Quantity Demanded)/(% Change in Price) = (dQ/Q)/(dP/P) × P/QSince MR = P(1 - 1/Ed), MR is greater than MC if Ed is less than 1 and less than MC if Ed is greater than 1. Therefore, the optimal output occurs where Ed is equal to
Substituting the values of P and Q, we get:Ed = (dQ/Q)/(dP/P) × P/Q = -1.47Therefore, demand is elastic at the optimal output.

Calculate the firm’s markup.The markup is given by the formula (P - MC)/P.Substituting the values of P and MC, we get:(83.33 - 33.33)/83.33 = 0.6 = 60% markup .

What is the DWL associated with the monopoly output?DWL (Deadweight Loss) is the difference between the total surplus in a competitive market and the total surplus in a monopoly market.

The formula for DWL is:DWL = (1/2)(Pmon - Pcomp)(Qcomp - Qmon)DWL can be calculated by using the demand equation and finding the quantity demanded at the monopoly price and the competitive price. At the monopoly price of $83.33, the quantity demanded is 66.67.

At the competitive price of $66.67, the quantity demanded is 100. Therefore, DWL can be calculated as follows:DWL = (1/2)(83.33 - 66.67)(100 - 66.67) = $1,111.1 f.

Suppose the government offered a $10 production subsidy to the monopolist. What is their new optimal output?The new optimal output will be where the new marginal cost equals the original marginal revenue.

The subsidy reduces the marginal cost to (1/2) Q - $10.

Therefore, the monopolist's new optimal output can be found by solving for Q:100 - 1/2 Q + 10 = 1/2 Q => Q = 74.07 units of outputWhen Q = 74.07, the price is given by the demand equation:P = 100 - 1/4 Q => P = $81.48 g. Does the DWL fall or rise?The DWL falls when the monopolist receives the subsidy because it leads to an increase in output and a decrease in price.

Therefore, the deadweight loss falls.

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If Abby is collecting rainfall data, and she finds that one value of the data set is a high-value outlier, then the statement that must be true is "the outlier will pull the mean towards its value."

Outliers are the data points in a distribution that stand out from the rest. In other words, an outlier is a value that is far from the other values in the dataset.

An outlier is a value that is more than 1.5 times the interquartile range (IQR) greater than the upper quartile or less than the lower quartile plus 1.5 times the IQR, which is often referred to as the "1.5*IQR rule."

Here are a few statements that describe the impact of an outlier on a data set:

An outlier does not have an effect on the median value of the data set.

The presence of an outlier in a dataset will raise the range of the dataset.

The presence of an outlier in a dataset will raise the standard deviation of the dataset.

The outlier will pull the mean towards its value, as well as increase the value of the mean.

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complete question:

Abby is collecting rainfall data. She finds that one value of the data set is high-value outlier. Which statement must be true?

1. Abby will use a different formula for calculating the standard deviation

2. The outlier will increase the standard deviation of the data set

3. The spread of the graph of the data will not change

4. Abby will not use the mean when calculating the standard deviation

Answer:

b)The outlier will increase the standard deviation of the data set.

Step-by-step explanation:

e2020

we must find the for each fuction and we can say from it if they are parellel or perpendicular

F(x)

slope

(x2,y2)=(3,-1) and (x1,y1)=(2,4)

G(x)

(x2,y2)=(2,6) and (x1,y1)=(-3,7)

slope

when the slopes are equals the lines are parellel so This is not the case

when the slopes one is the other inverted and with a different sign they are parellel so this is not the case

So, the solution is neither

The solution of the differential equation for \( x(t)=\sin t \) using MATLAB symbolic toolbox to find the specific equation for \(y_{2}(t)\) is: \(y_{2}(t)=\frac{1}{6}\left(3\cos\left(2t\right)-\sin\left(2t\right)+e^{-3t}\right)\sin\left(t\right)\)

Given, the block diagram,

Step 1: We can rewrite the given block diagram into the equation below. \(\frac{d}{dt}y_{2}(t)=-3y_{2}(t)+3x(t)-\frac{d}{dt}y_{1}(t)\)

Step 2: To find the Laplace transform of the differential equation, we apply the Laplace transform to both sides, which gives the result below. \(sY_{2}(s)+3Y_{2}(s)-y_{2}(0)=-3Y_{2}(s)+3X(s)-sY_{1}(s)+y_{1}(0)\)

Step 3: Simplifying the above equation we get, \(sY_{2}(s)=-Y_{2}(s)+3X(s)-sY_{1}(s)\)\(\frac{Y_{2}(s)}{X(s)}=\frac{3}{s^{2}+s+3}\)

Step 4: The inverse Laplace Transform of \(\frac{Y_{2}(s)}{X(s)}=\frac{3}{s^{2}+s+3}\) can be calculated using MATLAB symbolic toolbox, which is shown below.\(y_{2}(t)=\frac{1}{6}\left(3\cos\left(2t\right)-\sin\left(2t\right)+e^{-3t}\right)\sin\left(t\right)\)

Therefore, the solution of the differential equation for \( x(t)=\sin t \) using MATLAB symbolic toolbox to find the specific equation for \(y_{2}(t)\) is: \(y_{2}(t)=\frac{1}{6}\left(3\cos\left(2t\right)-\sin\left(2t\right)+e^{-3t}\right)\sin\left(t\right)\)

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Answer:

50 and 20 that is the answer Thank you

the optimal solution to maximize Z is x1 = 25 and x2 = 0, with Z = 3000.

To solve the given linear programming model graphically, we need to plot the feasible region and identify the corner points to find the optimal solution. Here's the step-by-step process:

1. Plot the constraints:

  - Plot the line x1 = 40 (vertical line at x1 = 40).

  - Plot the line x2 = 10 (horizontal line at x2 = 10).

  - Plot the line 20x1 + 10x2 = 500 (which can be rewritten as 2x1 + x2 = 50).

  - Shade the feasible region that satisfies all the constraints.

2. Identify the corner points:

  - Determine the coordinates of the corner points where the boundary lines intersect.

3. Evaluate the objective function:

  - Calculate the value of the objective function Z = 120x1 + 80x2 for each corner point.

4. Determine the optimal solution:

  - Select the corner point that maximizes the objective function Z.

Here's the graphical representation of the feasible region:

      |

 40   |           C

      |          /

      |         /

      |        /

      |       /

      |      /

      |     /    Feasible Region

 10   |_____/_________________

      0   10  20  30  40  50

            0`

The corner points of the feasible region are:

A: (0, 0)

B: (0, 10)

C: (25, 0)

D: (20, 5)

Now, we evaluate the objective function Z = 120x1 + 80x2 for each corner point:

Z(A) = 120(0) + 80(0) = 0

Z(B) = 120(0) + 80(10) = 800

Z(C) = 120(25) + 80(0) = 3000

Z(D) = 120(20) + 80(5) = 2400

From the above calculations, we can see that the maximum value of Z occurs at point C: (25, 0).

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It takes 8 blocks with a side length of 1/4 m to fill a rectangular prism with a volume of 1 m3.

The volume of a rectangular prism is calculated by the formula V = l * w * h, where l is the length, w is the width, and h is the height. To calculate the volume of a rectangular prism with 8 blocks (each with a side length of 1/4 m), we need to determine the length, width, and height of the rectangular prism.

Since each block has a side length of 1/4 m, the length, width, and height of the rectangular prism must be a multiple of that. Therefore, the length, width, and height of the rectangular prism must be 4/4 m, 8/4 m, and 8/4 m, respectively.

Substituting this into the formula, the volume of the rectangular prism is (4/4 m) * (8/4 m) * (8/4 m) = 64/64 m3 = 1 m3. Therefore, it takes 8 blocks with a side length of 1/4 m to fill a rectangular prism with a volume of 1 m3.

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