Solve a + 5/6 < 2/3 check your answer

Answer:

\(\boxed{ x = 23}\)

Step-by-step explanation:

=> x - 15 = 8

Adding 15 to both sides

=> x - 15 + 15 = 8 + 15

=> x = 23

Answer:

A. x = 23

Step-by-step explanation:

Step 1: Write out equation

x - 15 = 8

Step 2: Add 15 to both sides (Addition Equality)

x - 15 + 15 = 8 + 15

x = 23

It will take the town 21 years 4 months to reach 4600 in population

a rate is a ratio that compares two different quantities which have different units. For example, if we say John types 50 words in a minute, then his rate of typing is 50 words per minute. The word "per" gives a clue that we are dealing with a rate.

initial population = 3000

population increase every year = 2.5% of 3000

which is 2.5/100 x 3000 = 75

let the time taken to reach 4600 be d

increment for d number of years = 75d

Total population after d years is 75d + 3000

so 75d + 3000 = 4600

75d = 4600  - 3000

75d = 1600

d = 1600/75

d = 21.33 years which is 21 years 4 months

In conclusion 21 years 4 months is the time taken for the ton tto get tto 4600

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Answer:

(5w)^3

5^3 * w^3

\(125w^3\)

Step-by-step explanation:

Answer: 125  I'm pretty sure sorry if it's wrong

Step-by-step explanation:

because 5x5x5=125

Answer:

nineteen million thirty four thousand six hundred

I think this is right

Step-by-step explanation:

Answer:

Nineteen million thirty four thousand six hundred

Step-by-step explanation:

There are two terms in the given expression 5xy²+ 35xy².

What is meant by term?

Terms comprise expressions. A term may be a constant, a variable, or a combination of variables and constants.

What is an example of a term?

It could be a single variable (a letter), a single number (positive or negative), or a number of variables multiplied but never added or subtracted. Variables in certain words have a number in front of them. A coefficient is the number used before a phrase. Single-word examples: A single phrase is 3x.

There are two terms in the equation 5xyA ^2 + 35xyA^2 that is separated by an arithmetic operator +.

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Positive-sum games derive their name from the requirement that players (in such games) have a positive opinion of each other. This statement is FALSE.

A positive-sum game is a term used in game theory to describe an activity in which the sum of all gains and losses is zero or positive. In this kind of situation, all sides in a negotiation or a game have the potential to gain from it.Positive-sum games are also called win-win games because both parties can benefit from them.

When both players benefit, the game is win-win because no one loses. When one player wins and the other loses, the game is zero-sum.In a positive-sum game, each participant has a positive impression of the other players. These games are beneficial because they enable the players to work together for mutual gain without causing any harm to others. Because the cooperation is voluntary, it's possible for everyone to come out ahead. One person's benefit does not come at the cost of another's detriment. 

Positive-sum games are beneficial since they promote cooperation and mutual gain, which is beneficial to everyone. These games are sometimes known as win-win situations because everyone comes out ahead. In contrast, a zero-sum game is a situation in which one person's win comes at the cost of another's loss.

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The solution to the heat equation with the given initial temperature and boundary conditions is:

u(x, t) = Σ[(2/L) * sin(nπx/L) * e^(-α(nπ/L)²t)],

To derive the heat equation in the presence of heat sources, we consider a rod of length L and assume that the temperature distribution u(x, t) along the rod depends on both position x and time t. We also assume that the heat sources within the rod are represented by a function f(x, t).

The heat equation describes how the temperature u(x, t) changes over time and is given by:

∂u/∂t = α * ∂²u/∂x² + f(x, t),

where α is the thermal diffusivity of the material.

To solve the heat equation for the given initial temperature u(x, t=0) = δ(x - L/2), we need to apply appropriate boundary conditions. In this case, we have homogeneous Dirichlet boundary conditions, which means that the temperature at the ends of the rod is fixed:

u(0, t) = 0,

u(L, t) = 0.

To solve the heat equation with these boundary conditions and the initial temperature condition, we can use separation of variables and apply the method of eigenfunction expansion.

By assuming that the solution can be represented as a series of eigenfunctions and eigenvalues, we can write:

u(x, t) = Σ[A_n * sin(nπx/L) * e^(-α(nπ/L)²t)],

where A_n are coefficients to be determined, and n is a positive integer representing the mode of vibration.

To determine the coefficients A_n, we can use the initial temperature condition:

u(x, 0) = Σ[A_n * sin(nπx/L)] = δ(x - L/2).

Applying the orthogonality property of sine functions, we can find the coefficients A_n:

A_n = (2/L) * ∫[0,L] [sin(nπx/L) * δ(x - L/2)] dx.

Solving this integral, we obtain:

A_n = (2/L) * sin(nπ/2) * sin(nπ/2),

where sin(nπ/2) = 1 if n is odd and 0 if n is even.

Therefore, the solution to the heat equation with the given initial temperature and boundary conditions is:

u(x, t) = Σ[(2/L) * sin(nπx/L) * e^(-α(nπ/L)²t)],

where the sum is taken over all odd values of n.

Note that the above solution assumes a one-dimensional rod and certain simplifications. In practice, solving the heat equation with heat sources and boundary conditions may require additional considerations and techniques, depending on the specific problem and physical system involved.

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Vector \(u = \left[\begin{array}{c}-1\\-9\end{array}\right]\) and Vector  \(v = \left[\begin{array}{c}2\\3\end{array}\right]\) such that u + v is not in W.

Consider a vector:   \(W = \left[\begin{array}{c}x\\y\end{array}\right]\)  : XY ≥ 0.

if  \(Z = \left[\begin{array}{c}x\\y\end{array}\right]\) is in W then the vector c.Z = \(c \left[\begin{array}{c}x\\y\end{array}\right]\) = \(\left[\begin{array}{c}cx\\cy\end{array}\right]\) is in W.

therefore, xy ≥ 0. ( cx ) . ( cy ) = c² . (xy) ≥ 0.

Note: We can only take 'u' and 'v' as [2 x 1] Matrix because 'u' and 'v' lies in W and W is [2 x 1] Matrix.

Take \(u = \left[\begin{array}{c}-1\\-9\end{array}\right]\) then -1 x -9 = 9 ≥ 0 then vector 'u' lies in W.

also, \(v = \left[\begin{array}{c}2\\3\end{array}\right]\) then 2 x 3 = 6 ≥ 0 then vector 'v' lies in W.

Now, u + v \(= \left[\begin{array}{c}-1\\-9\end{array}\right] + \left[\begin{array}{c}2\\3\end{array}\right] = \left[\begin{array}{c}1\\-6\end{array}\right]\) here 1 x (-6) is not ≥ 0.

therefore, u + v is not in W.

Hence, Vectors  \(u = \left[\begin{array}{c}-1\\-9\end{array}\right] v = \left[\begin{array}{c}2\\3\end{array}\right]\) such that u + v is not in W.

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Disclaimer: The question given was incomplete on the portal. Here is the complete question.

Question: Let W be the union of the first and third quadrants in the XY

plane. That is, Let   \(W = \left[\begin{array}{c}x\\y\end{array}\right]\) : XY ≥ 0.

Find specific vectors u and v in W such that u + v is not in W. This is enough to show that W is not a vector space. Also read the question from the attached image.

The value of new_list is [1, 4, 9, 16].

The code given creates a new list called new_list by using a list comprehension to iterate over the values in my_list and squaring each value using the exponent operator (**).

This means that the first value in my_list (which is 1) is squared to 1, the second value (which is 2) is squared to 4, the third value (which is 3) is squared to 9, and the fourth value (which is 4) is squared to 16.

These squared values are then added to the new_list one by one, resulting in the final value of [1, 4, 9, 16].

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Answer:

-1/5

Step-by-step explanation:

We can use the formula [ y2-y1/x2-x1 ] to solve.

3-1/-5-5

2/-10

-2/10

-1/5

Best of Luck!

In regression analysis , the error term ε is a random variable with expected value of 0.

What is regression analysis?

A set of statistical procedures known as regression analysis is used to estimate the relationships between a dependent variable and one or more independent variables.

Main Body:

In regression analysis, the model in the form is called regression model.

The mathematical equation relating the independent variable to the expected value of the dependent variable; that is, E(y) = β0 + β1x, is known as regression equation.

So the answer  to error term is 0.

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By taking the difference between the y-intercepts, we conclude that the distance between the lines is 3 units.

A general linear equation is:

y = a*x + b

Where a is the slope and b is the y-intercept.

Two linear equations are parallel if and only if both lines have the same slope and different y-intercepts.

And the distance is given by the difference between the y-intercepts.

Here the lines are:

y = -3*x + 1

y = -3*x + 4

The difference between the y-intercepts gives:

4 - 1 = 3

That is the distance between the lines.

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The z-score for Sami Aalto on the horizontal bar in 2005 is approximately -1.6678.

To calculate the z-score for Sami Aalto's score on the horizontal bar in 2005, we need to use the formula:

z = (x - μ) / σ

where:
x = Sami Aalto's score (8.087)
μ = mean score under the old scoring system (9.139)
σ = standard deviation under the old scoring system (0.629)

Plugging in the values, we have:

z = (8.087 - 9.139) / 0.629

Calculating this gives us:

z ≈ -1.6678

Rounding to 4 decimal places, the z-score for Sami Aalto on the horizontal bar in 2005 is approximately -1.6678.

The z-score for Sami Aalto on the horizontal bar in 2005 is approximately -1.6678.

The z-score is a measure of how many standard deviations a data point is from the mean. It allows us to compare a particular score to the distribution of scores. In this case, we are comparing Sami Aalto's score to the distribution of scores on the horizontal bar under the old scoring system.

The z-score is calculated by subtracting the mean score from the data point and dividing it by the standard deviation. In this case, Sami Aalto's score is 8.087, the mean score is 9.139, and the standard deviation is 0.629. Plugging these values into the formula, we find that the z-score is approximately -1.6678.

The z-score for Sami Aalto on the horizontal bar in 2005 is approximately -1.6678. This means that his score is about 1.6678 standard deviations below the mean score under the old scoring system.

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Answer:

\(\sqrt{17.3}\) = 4.159.....  so approx 4.2

Step-by-step explanation:

The amount you must deposit every year if your goal is for the present value of your savings to be equal to $4,462 is $279.28.

Let the amount you need to deposit every year = P

Thus, the amount of money you will have after 10 years at an interest rate of 9% per annum = $4462

Using the formula of present value,

PV = FV/(1 + r)n

Where,

PV = present value of your savings

FV = future value of your savings

r = rate of interest

n = time period of saving

Substituting the given values,

4462 = FV/(1 + 0.09)10

Now, to find FV, we will have to multiply P by the sum of the present value of an annuity of $1 at an interest rate of 9% for ten years. This sum can be found using the formula,

A = [r(1 + r)n]/[(1 + r)n - 1]

A = [0.09(1 + 0.09)10]/[(1 + 0.09)10 - 1]

A = 0.09 × 6.4177443

A = 0.577596989

A = 0.58 (rounded to two decimal places)

Thus,

FV = P × A = P × 0.58 = 0.58 P

Therefore,

4462 = 0.58 P × (1 + 0.09)10

Simplifying the above equation, we get,

4462 / [(1 + 0.09)10 × 0.58] = P

P ≈ 279.28

Therefore, the amount you need to deposit every year is $279.28 (rounded to two decimal places).Hence, the required answer is $279.28.

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Answer:

-3

Step-by-step explanation:

 f(x)=2x^2 - 3x - 2

if x = 1

f(1) = 2(1)^2 - 3(1) - 2

= 4 - 3 - 2

= -3

Hope this helps :)

Pls brainliest...

Answer:

Quadrilateral

Step-by-step explanation:

Its a quadrilateral. Quadrilateral means four sided shape, and the pic above shows a four sided shape

0,8 cm on the map is equal to 8 m in real life

Answer:

21/10 or 2.1

Step-by-step explanation:

Answer:

2 1/10

Step-by-step explanation:

Start by setting up the numbers as improper fractions:

28/5 divided by 8/3

Then you have to flip the top and bottom number of the second fraction, and switch your division symbol to a multiplication symbol:

28/5 x 3/8

Next, you simply cross-multiply to get 84/40

Lastly, you divide 84 by 40, to get 2.1

Hope this helps! :)

1 9 , 2 114 I Hope it help this is correct

Answer:

351

Step-by-step explanation:

\(\frac{1}{3}\) p - 3 = 114 ( multiply through by 3 to clear the fraction )

p - 9 = 342 ( add 9 to both sides )

p = 351

There are 351 pages in the novel

To construct a 90% confidence interval for the population proportion using the given information (x = 120, n = 200), calculate the sample proportion, standard error, and margin of error.

To calculate the sample proportion (p-hat) by dividing the number of successes (x) by the sample size (n):

Sample Proportion (p-hat) = \(\frac{x}{n}\) = \(\frac{120}{200}\) = 0.6

Next, calculate the standard error, which is the measure of variability in the sample proportion:

Standard Error = \(\sqrt\frac{(p - hat) X (1 - p-hat)}{n}\)  

Standard Error  =  \(\frac{\sqrt{0.6 X (1 - 0.9)} }{200}\)     ≈ 0.0258

Referring to the table of critical values, for a 90% confidence level, the critical value is approximately 1.645.

Margin of Error = critical value × standard error = 1.645 × 0.0258 ≈ 0.0424

Finally,  construct the confidence interval:

Lower Bound = sample proportion - margin of error

                       = 0.6 - 0.0424 ≈ 0.5576

Upper Bound = sample proportion + margin of error

                       = 0.6 + 0.0424 ≈ 0.6424

Therefore, the 90% confidence interval for the population proportion is approximately 0.558 to 0.642.

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Answer:

D) \(1 < x\leq 4\)

Step-by-step explanation:

1 is not included, but 4 is included, so we can say \(1 < x\leq 4\)

Answer:

the second one

Step-by-step explanation:

and go to Mr.beast.com

The  values of for which the rocket's height is 29 meters are 0.75 and -0.67.

Velocity can be described as a vector quantity having both direction and magnitude which is the distance traveled per time.

We were given the  rocket's height h  as \(h=57t-5t^2\) which is an equation, and we were been given the height which is the value that can be input into the equation as  is 29 meters , then we can proceed to simplify the equation as

\(h=57t-5t^2\)

29=57t-5t^2

then we will have  \(57t-5t^2-29=0\)

with the use of quadratic formula the values of t are : 0.75 and -0.67

Then we can chose 0.75 seconds

Therefore, after the calculation with the use of the quadratic equation, we can come into conclusion that the values that are required in the question are 0.75 and -0.67.

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NOTE: This is a complete question, there were no given options, even on the internet.

Answer: 4992

Step-by-step explanation:

same, but whenever it talks about "lenghth and with" it is multiplying

hope this helps :)

75 cookies

Step-by-step explanation:

500 × 0.25(3/4 cookies sold)= 125

125 - 0.4(2/5 gave to her friends) = 75

75 cookies remain

A word problem consists of a series of sentences that describe a situation which is to be resolved mathematically through calculations

1st question: Htwe has 75 cookies left

2nd question: \(1\frac{1}{2} + \frac{4}{5} \div \frac{3}{8} \times 10\frac{5}{6} = \mathbf{\underline {25\frac{11}{18} }}\)

The reasons the above values are as follows:

1st question:

The known parameters are;

The number of cookies Htwe made = 500

The fraction  of cookies she sold = 3/4

The fraction of the cookies she gave to all her friends = 2/5 of the remainder

The required parameter:

How many cookies she has left

Solution:

The number of cookies Htwe sold = 500 cookies × 3/4 = 375 cookies

The number of  cookies remaining = (500 - 375) cookies = 125 cookies

∴ The remainder of the cookies after sale = 125 cookies

The number of cookies she gave to her friends = 2/5 × 125 cookies = 50 cookies

The number of cookies she has left = The remainder - The number given to friends

∴ The number of cookies she has left = (125 - 50) cookies = 75 cookies

The number of cookies she has left = 75 cookies

2nd question:

Required;

To evaluate, \(1\frac{1}{2} + \frac{4}{5} \div \frac{3}{8} \times 10\frac{5}{6}\)

Solution:

\(1\frac{1}{2} + \frac{4}{5} \div \frac{3}{8} \times 10\frac{5}{6} = \dfrac{5}{2} + \dfrac{\dfrac{4}{5} }{\dfrac{3}{8} } \times \dfrac{65}{6} = \dfrac{5}{2} + \dfrac{4}{5} \times \dfrac{8}{3 } \times \dfrac{65}{6} = \dfrac{461}{18}\)

Therefore;

\(1\frac{1}{2} + \frac{4}{5} \div \frac{3}{8} \times 10\frac{5}{6} = \dfrac{461}{18} = \underline {25\frac{11}{18} }\)

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If population grew by 5% from 2010 to 2015 and fell by 3% from 2015 to 2020 , then the population decrease from 2015 to 2020 is 6678    .

Let the population of the city in 2015 be = "p".

To find the population in year "2015" , we first find the growth from 2010 to 2015  ;

⇒ p = 212000×(1 + 0.05) = 212000 × 1.05 = 222600 ;

So, the population in 2015 was 222600 .

Next, we find the population in 2020 by applying the decrease of 3%:

⇒ p = 222600×(1 - 0.03) = 222600×0.97 = 215922

So, the population in 2020 was 215922.

To , find the decrease from 2015 to 2020, we subtract the population in 2020 from the population in 2015 ;

⇒ 215922 - 222600 = -6678

Therefore , the population of the city decreased by 6678 people from 2015 to 2020.

The given question is incomplete , the complete question is

In 2010, the population of a city was 212000. From 2010 to 2015, the population grew by 5%. From 2015 to 2020, it fell by 3%. How much did the population decrease from 2015 to 2020, to the nearest 100 people ?

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Using translation concepts, the translation rule is given by:

(x,y) -> (x + 13, y + 7).

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

Comparing v with v', and w with with w', we get that:

Hence the translation rule is given by:

(x,y) -> (x + 13, y + 7).

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The average cost per CD of the additional 250 CDs over 460 is $2.33. To calculate this, we first determine the cost difference between producing 710 CDs and 460 CDs, which is $82.50.

To find the average cost per CD of the additional 250 CDs over 460, we first need to determine the cost difference between producing 710 CDs and 460 CDs. The cost difference is $3182.50 - $3100 = $82.50. This $82.50 represents the cost of producing the additional 250 CDs.

To calculate the average cost per CD, we divide the cost difference by the number of additional CDs: $82.50 / 250 = $0.33. Therefore, each additional CD over 460 costs $0.33.

Now, to find the average cost per CD of the additional 250 CDs, we add the average cost per CD to the cost of producing 460 CDs. The cost of producing 460 CDs is given as $3100, so we add $3100 + ($0.33 * 250) = $3100 + $82.50 = $3182.50.

Therefore, the average cost per CD of the additional 250 CDs over 460 is $2.33.

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