Solve 2r/3 - 7 = r + 5

The probability of selecting a T or a P on the second draw, given that an F was selected on the first draw is 0.39.

The probability of selecting a T or a P on the second draw, given that an F was selected on the first draw, can be calculated using conditional probability.

P(A|B) = P(A and B) / P(B)

P(A and B) = P(T or P on second draw and F on first draw) = P(T on second draw and F on first draw) + P(P on second draw and F on first draw)

= (3/9) x (4/10) + (2/9) x (4/10) = 14/90

To find P(B), we know that it is 0.4.

Therefore, the conditional probability of selecting a T or a P on the second draw, given that an F was selected on the first draw, is:

P(A|B) = P(A and B) / P(B) = (14/90) / 0.4 ≈ 0.39

So the probability of selecting a T or a P on the second draw, given that an F was selected on the first draw, is approximately 0.39.

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Substitution is a method for solving systems of equations that involves solving for one variable in one equation and then substituting that value into the other equation.

Here's how we can use substitution to solve the system of equations:

5x+y=9

10x−7y=−18

Solve one equation for one variable, for example:

y = 9 - 5x

Substitute this expression of y into the other equation:

10x - 7(9 - 5x) = -18

Solve the equation resulting from the substitution

10x - 63 + 35x = -18

45x = 45

x = 1

Substitute this value of x back into one of the original equations to find the value of y.

5(1) + y = 9

y = 4

So the solution is (x,y) = (1,4)

You can check this solution by substituting it back into both original equations.

Answer:

200N

Step-by-step explanation:

Torque is defined as the turning effect of force about a point. It is expressed as;

Torque = Force × radius

T = Fr

Given parameters

Torque = 100Nm

Radius = 0.5metres

Required

Magnitude of the force F

From the formula T = Fr

F = T/r

F = 100Nm/0.5m

F = 100/(1/2)

F = 100 × 2/1

F = 200Newtons

Hence the magnitude of the force in newtons needed to supply 100 newton-meters of torque to the bolt is 200N

Answer:

-1.14285714286

Step-by-step explanation:

brainlist plz thx

If you divided 8÷-7 the result will be -1.14285714286 is negative because when you divide a positive number with a negative alway is going to be a negative.

And if you simplify it gives you

I think thats it. sorry if im wrong.

Answer:

5 loafs

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

right on edge

Answer:

Step-by-step explanation:

The answer is 67%.

To turn a decimal into a fraction you must move the decimal over two places to the left.

For example: .87% = 87%

To determine the percentage of students who read more than 8 books in Ms. Ryan's class, we need additional information regarding the total number of students and the number of students who read more than 8 books.

Without knowing the total number of students in Ms. Ryan's class or the number of students who read more than 8 books, it is not possible to calculate the exact percentage. To determine the percentage, we would need to know the numerator (number of students who read more than 8 books) and the denominator (total number of students).

Once we have the total number of students and the number of students who read more than 8 books, we can calculate the percentage by dividing the number of students who read more than 8 books by the total number of students, and then multiplying by 100. if there were 30 students in Ms. Ryan's class and 12 students read more than 8 books, the percentage would be (12/30) * 100 = 40%. This means that 40% of the students in Ms. Ryan's class read more than 8 books.

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In a college of 300 students, every student reads 5 newspaper and every newspaper is read by 60 students. The number of newspaper is ?

The area covered by a sprinkler that sprays water in a circle of an 8-foot radius is 200.96 square feet.

Circle is a 2-Dimensional shape. It has no vertex and edges. It has a center point which equidistant from any point of boundary or circumference of a circle.

Radius refers to the distance between the center and any point on the boundary or circumference of the circle.

The area of a circle is given as the product of a constant pi and the square of the radius.

A =  π\(r^2\)

A is the area

r is the radius

r = 8 feet

A = π * 8 * 8

= 3.14 * 8 * 8

= 200.96 square feet

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A. 8 pizza pies at 10 pc. per pie = 80 available pieces

B. Let X be the number of children. Number of pieces eaten = 5 per child = 5X.

c. 22 pieces are left over.

D. Combine line A and line C. Total number of pieces eaten = 80 original minus 22 left over. Result 58 pieces were eaten by X children: 58 = 5X.

E. Solve the equation 58 = 5X by dividing both sides by 5.

WHOOPS! Is this a trick question? Solving the above results in the answer that there are 11.6 children at the party. Hmmm. That 0.6 child is a question mark for me.

Looks like someone miscounted the pizza slices. Or omitted some pertinent information. But, I’m sure there is a logical answer.

Answer:

10 pizzas

Step-by-step explanation:

To find the answer for this question you need to multiply 3/8 by 25.

3/8 * 25 = 9.375

You can't buy .375 of a pizza so you round it up and get 10.

Answer: 4 and -5

Step-by-step explanation:

The coefficient is the number next to the variables.

In this example, 4y - 5x + 3, the coefficients are 4 and -5

A number line starting from 0 and directed to +30 represents  how long it took Courtney to run 3.1 miles

Given is that Alan ran 3.1 miles in 35 minutes and Courtney ran 3.1 miles 5 minutes faster than Alan.

It is given that Courtney ran 3.1 miles 5 minutes faster than Alan. This means that he runs 3.1 miles in (35 - 5) or 30 minutes.

Therefore, a number line starting from 0 and directed to +30 represents  how long it took Courtney to run 3.1 miles.

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Step-by-step explanation:

went to a calculator

it said

Angle ∠A = 55.543°

Angle ∠B = 78.28°

Angle ∠C = 46.177

\(\\ \sf\longmapsto 2(4x-1)+3(3-2x)=0\)

\(\\ \sf\longmapsto 8x-2+9-6x=0\)

\(\\ \sf\longmapsto 8x-6x-2+9=0\)

\(\\ \sf\longmapsto 2x+7=0\)

\(\\ \sf\longmapsto 2x=-7\)

\(\\ \sf\longmapsto x=\dfrac{-7}{2}\)

To graph the equation \(x=y^2\) on a TI-83 calculator, you need to follow a few steps. First, go to the "\(Y=\)" screen by pressing the "\(Y=\)" button. Then, enter the equation by typing "\(y^2\)" into the first available function slot. Press the "GRAPH" button to display the graph of the equation on the calculator screen.

To explain the process in more detail, start by turning on your TI-83 calculator and pressing the "\(Y=\)" button, which will take you to the function screen. You'll see a list of function slots labeled "\(Y1\)," "\(Y2\)," and so on. Enter the equation "\(y^2\)" in one of the slots. To enter the squared symbol, press the "^" key, usually located near the upper right corner of the calculator's keypad, followed by "\(2\)." Make sure you use the "\(y\)" variable, which can be found by pressing the "ALPHA" button and then the corresponding letter key. Once you have entered the equation, press the "GRAPH" button to plot the graph on the calculator's screen. The graph should display a parabola opening to the right, representing the equation \(x=y^2\).

By following these steps, you can easily graph the equation \(x=y^2\) on a TI-83 calculator. Remember to check if the graph is within the viewing window and adjust it if necessary using the window settings.

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Answer:

8 square units

Step-by-step explanation:

x + 1 = 0

x = -1

x + 8 = 0

x = -8

Area = (-1) * (-8) = 8 square units

Answer:

x = 28.1°

Step-by-step explanation:

Cos = adjacent side/hypotenuse

cos x = 15/17

x = arccos (15/17)

  = 28.1°

Note:  If you memorize all the definitions of the trig functions, then these kinds of problems are much easier.  OK?

Answer: B: 0 < a < 1

Step-by-step explanation:

The equation we have is:

f(x) = a^(x + h) + k.

k is the value at where we have the horizontal line. In this particular case, we can see that we have a horizontal line at y = -4, then we can conclude that:

k ≈ -4

a is the rate of growth. If a is positive and greater than 1, we would have an increasing function, for example with a = 2, k = 0 and h = 0 we have:

2^1 = 2

2^2 =4

2^3 = 8

This is an increasing function.

Now if a is greater than 0 and smaller than 1, we have a decreasing function (as seen in the graph). For example for a = 0.5, k = 0 and h = 0 we have:

0.5^1 = 0.5

0.5^2 = 0.25

0.5^3 = 0.125

This is a decreasing function.

Then the correct option is B, 0 < a < 1

Answer:

its b

Step-by-step explanation:

a p e x

The largest integer that is a divisor of (n + 1)(n + 3)(n + 5)(n + 7)(n + 9)  for all positive even integers is 15

The correct answer is an option (d)

In this question, we need to find the largest integer that is a divisor of (n + 1)(n + 3)(n + 5)(n + 7)(n + 9)  for all positive even integers n.

We can observe that (n + 1), (n + 3), (n + 5), (n + 7) and (n + 9)  are 5 consecutive odd integers

In every 5 consecutive odd positive integers, one of them is always divisible by 3 and one of them is always divisible by 5.

This means, (n + 1)(n + 3)(n + 5)(n + 7)(n + 9) will be divisible by both 3 and 5

i.e., (n + 1)(n + 3)(n + 5)(n + 7)(n + 9) will also divisible by 15 (3 * 5 = 15)

Therefore, the largest integer that is a divisior of (n + 1)(n + 3)(n + 5)(n + 7)(n + 9)  = 15

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Explanation:-

To determine whether the given expressions are functions and analyze their properties, examine each case:

(a) Given f: Z → Z+, f(x) = |x - 2| + 1

This expression represents a function since each input value from the set of integers (Z) maps to a unique output value from the set of positive integers (Z+). To check if it is one-to-one,  to verify whether different inputs yield different outputs.

For f(x) = |x - 2| + 1, consider two different inputs: x₁ and x₂.

If f(x₁) = f(x₂), then x₁ = x₂.

Assume x₁ ≠ x₂:

If x₁ > 2 and x₂ > 2:

Then |x₁ - 2| = x₁ - 2 and |x₂ - 2| = x₂ - 2.

Since f(x₁) = |x₁ - 2| + 1 and f(x₂) = |x₂ - 2| + 1, if x₁ ≠ x₂, f(x₁) ≠ f(x₂).

If x₁ < 2 and x₂ < 2:

Then |x₁ - 2| = -(x₁ - 2) and |x₂ - 2| = -(x₂ - 2).

Since f(x₁) = |x₁ - 2| + 1 and f(x₂) = |x₂ - 2| + 1, if x₁ ≠ x₂, f(x₁) ≠ f(x₂).

If x₁ < 2 and x₂ > 2:

Then |x₁ - 2| = -(x₁ - 2) and |x₂ - 2| = x₂ - 2.

Since f(x₁) = |x₁ - 2| + 1 and f(x₂) = |x₂ - 2| + 1, if x₁ ≠ x₂, f(x₁) ≠ f(x₂).

If x₁ > 2 and x₂ < 2:

Then |x₁ - 2| = x₁ - 2 and |x₂ - 2| = -(x₂ - 2).

Since f(x₁) = |x₁ - 2| + 1 and f(x₂) = |x₂ - 2| + 1, if x₁ ≠ x₂, f(x₁) ≠ f(x₂).

In all cases, if x₁ ≠ x₂, f(x₁) ≠ f(x₂). Therefore, f(x) = |x - 2| + 1 is a one-to-one function.

To determine if it is onto (surjective), to check if every positive integer has a preimage.

consider a positive integer y ∈ Z+.

If y = 1, there is only one preimage: x = 2. (|2 - 2| + 1 = 1)

For any y > 1,  find at least two preimages: x = y - 1 and x = -y + 3.

For example, if y = 3, then x = 2 and x = -1 are both preimages. (|2 - 2| + 1 = 3 and |-1 - 2| + 1 = 3)

Since every positive integer has at least one preimage, f(x) = |x - 2| + 1 is onto.

In conclusion, f(x) = |x - 2| + 1 is a one-to-one and onto function, also known as a bijection.

(b) Given f: Z → Z+, f(x) = -3x + 2

This expression represents a function since each input value from the set of integers (Z) maps to a unique output value from the set of positive integers (Z+).

To determine if it is one-to-one, we need to verify whether different inputs yield different outputs.

Assume x₁ ≠ x₂:

If x₁ > x₂:

Then -3x₁ + 2 < -3x₂ + 2.

Since f(x₁) = -3x₁ + 2 and f(x₂) = -3x₂ + 2, if x₁ ≠ x₂, f(x₁) ≠ f(x₂).

If x₁ < x₂:

Then -3x₁ + 2 > -3x₂ + 2.

Since f(x₁) = -3x₁ + 2 and f(x₂) = -3x₂ + 2, if x₁ ≠ x₂, f(x₁) ≠ f(x₂).

In both cases, we observe that if x₁ ≠ x₂, f(x₁) ≠ f(x₂). Therefore, f(x) = -3x + 2 is a one-to-one function.

However, f(x) = -3x + 2 is not onto (surjective) because for any positive integer y, there is no integer x that satisfies -3x + 2 = y. The range of this function is limited to positive integers.

In conclusion, f(x) = -3x + 2 is a one-to-one function but not onto.

(c) Given f: R → R, f(x) = x^2 – 2x + 1

This expression represents a function since each input value from the set of real numbers (R) maps to a unique output value also from the set of real numbers (R).

To determine if it is one-to-one, to verify whether different inputs yield different outputs.

Assume x₁ ≠ x₂:

If f(x₁) = f(x₂), then x₁ = x₂.

For f(x) = x^2 – 2x + 1, consider two different inputs: x₁ and x₂.

If x₁ = 1 and x₂ = 3,  f(x₁) = f(x₂) = 1^2 – 2(1) + 1 = 3.

In this case, x₁ ≠ x₂, but f(x₁) = f(x₂), so f(x) = x^2 – 2x + 1 is not a one-to-one function.

Since it is not one-to-one, it cannot be a bijection or onto.

In conclusion, f(x) = x^2 – 2x + 1 is a function but not a one-to-one or onto function.

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The function f(x) = ln(2 + sin(x))) is concave up for the range of x [0,2].

To discover the interval(s) on which f(x) = ln(2 + sin(x)) is concave up, compute the function's second derivative and check its sign.

To begin, compute the first derivative of f(x) with respect to x:

(1 / (2 + sin(x)) = f'(x)cos(x)

The second derivative of f(x) can therefore be found by taking the derivative of f'(x) with regard to x:

f''(x) = -(1/(2 + sin(x))(-sin(x)) cos2(x) + (1/(2 + sin(x))

When we simplify f''(x), we get:

f''(x) = -1/(2 + sin(x))²)sin(x)(sin(x)-2)

To discover the interval(s) where f(x) is concave up, we must first locate the interval(s) where f''(x) is positive. Because sin(x) might vary from -1 to 1, we must solve the inequality:

-(1/(2 + 1))^2(-1)(-1-2)≤f''(x)≤-(1 / (2 - 1))²(1) (1-2)

When we simplify this inequality, we get:

1/9 ≤ f''(x) ≤ -1/4

So, f is never negative at 0 ≤ x ≤ 2, so f is concave up in the range 0 ≤ x ≤ 2.

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Complete question - f(x) = ln(2 + sin(x)), 0 ≤ x ≤ 2 . Find the interval(s) on which f is concave up.

Answer:

1418 ( Hope this helps! )

Step-by-step explanation:

g= 440+990-2(440)(990) cos 164

g=193600+980100-2

g=193600+980100+837451.1895

g= 2011151.1895 Square root and round

The amount of energy waste, in terms of hours which a 60-watt light bulb would remain on, is 61.6 hours then the correct option is B.

A ratio is an ordered couple of numbers a and b, written as a/b where b can not equal 0. A proportion is an equation in which two ratios are set equal to each other.

Marco leaves the bathroom faucet running for 22 minutes while he gets ready in the morning.

Running the faucet for 5 minutes wastes the same amount of energy as leaving a 60-watt light bulb on for 14 hours.

Then we have

\(\begin{aligned} \dfrac{5\ minutes}{14 \ hours } &=\dfrac{1\ minute }{x \ hours}\\\\x &= 2.8 \ hours \end{aligned}\)

So, the rate is 2.8 hours per minute.

Since macro leaves the bathroom faucet running for 22 minutes. Then the waste of energy is leaving a 60-watt light bulb will be

→22 minutes × 2.8 hours/minute = 61.6 hours.

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The percentage of fraudulent responses (class 1 response rate) when the model is applied to the data set generated by oversampling depends on the specific circumstances and cannot be determined without evaluating the model's predictions on the oversampled data set.

The percentage of fraudulent responses (class 1 response rate) when the model is applied to the data set generated by oversampling cannot be determined without specific information about the data set, the model, and the results of applying the model.

Oversampling is a technique used to address class imbalance in a dataset, where the minority class (in this case, fraudulent responses) is underrepresented compared to the majority class. By generating additional samples of the minority class, the data set becomes more balanced.

The actual class 1 response rate after applying the model to the oversampled data set will depend on various factors, such as the performance of the model, the quality of the oversampling technique, the characteristics of the data, and the prevalence of fraudulent responses in the original data set.

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The equation for the hyperbola with foci (0,±5) and asymptotes y=± 3/4 x is:

y^2 / 25 - x^2 / a^2 = 1

where a is the distance from the center to a vertex and is related to the slope of the asymptotes by a = 5 / (3/4) = 20/3.

Thus, the equation for the hyperbola is:

y^2 / 25 - x^2 / (400/9) = 1

or

9y^2 - 400x^2 = 900

The center of the hyperbola is at the origin, since the foci have y-coordinates of ±5 and the asymptotes have y-intercepts of 0.

To graph the hyperbola, we can plot the foci at (0,±5) and draw the asymptotes y=± 3/4 x. Then, we can sketch the branches of the hyperbola by drawing a rectangle with sides of length 2a and centered at the origin. The vertices of the hyperbola will lie on the corners of this rectangle. Finally, we can sketch the hyperbola by drawing the two branches that pass through the vertices and are tangent to the asymptotes.

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Answer:

Gus jas driven 5 miles

Step-by-step explanation:

Emma did 30 miles of u were wondering

CS = x, and since AB = BC = CD = DA = 1cm -> SD = 1 - x

We see that angle DSP = angle APQ (because they simultaneously equal to 90 when added angle DPS)

So, triangle DSP = triangle APQ (equal hypotenuse - square side and equal angle.)

Similarly, we can prove triangle SCE and QBE in the same way

So, all 4 of the triangles are equal to each other.

-> SD = CE = BQ = AP = 1-x

Calculate the area of 4 triangles : [ x(1-x) : 2 ] x 4 = x(1-x) x 2

Area (PQRS) = 1 - [ x(1-x)] x 2 = 1 - 2x + 2x(squared) = \(2x^{2} -2x + 1\)

ii) Half area of PQRS = \(x^{2} -x+1\)

= \(x^{2} -\frac{1}{2} x-\frac{1}{2} x + \frac{1}{2} = x(x-\frac{1}{2} )- \frac{1}{2}(x-\frac{1}{2} ) + \frac{1}{4} = (x-\frac{1}{2})^{2} + \frac{1}{4}\)

We have : \((x-\frac{1}{2}) ^{2}\)

has the smallest value of 0 -> The smallest half value of PQRS = 1/4 -> The smallest value of PQRS = 1/2

Answer:1

Step-by-step explanation:

2/3 jug = 3 weeks

3*(2/3 jug) = 3*(3 weeks) ... multiply both sides by 3

2 jugs = 9 weeks

2/9 jugs = 9/9 weeks ... divide both sides by 9

2/9 jug = 1 week

Answer:

26

Step-by-step explanation: