So far, you’ve been working with an "ideal" pulley system. How do you think real pulley systems are different, and how would that affect the mechanical advantage of real pulley systems?
Plz really need help with this. And thank you so much
Answers
Answer:
In an ideal pulley system is assumed as a perfect system, and the efficiency of the pulley system is taken as 100% such that there are no losses of the energy input to the system through the system's component
However, in a real pulley system, there are several means through which energy is lost from the system through friction, which is converted into heat, sound, as well as other forms of energy
Given that the mechanical advantage = Force output/(Force input), and that the input force is known, the energy loss comes from the output force which is then reduced, and therefore, the Actual Mechanical Advantage (AMA) is less than the Ideal Mechanical Advantage of an "ideal" pulley system
The relationship between the actual and ideal mechanical advantage is given by the efficiency of the pulley system as follows;
\(Efficiency \, \% = \dfrac{AMA}{IMA} \times 100\)
Explanation:
Related Questions
Calculate the acceleration due to gravity
at a height of 300 km from the surface of
the Earth. (M = 5.98 x10²4 kg, R = 6400
km).
Answers
Answer:
8.8854 m/s²
Explanation:
Using the relation :
g = GM / (r + R)^2
G = Gravitational constant = 6.67 * 10^-11
M = mass of earth = 5.98 * 10^24 kg
r = distance = 300 km
R = Radius of earth 6400 km
g = (6.67 * 10^-11 * 5.98 * 10^24) / ((6400+300) * 10^3)^2
g = (6.67 * 5.98 * 10^(-11 + 24)) / (6700 * 10^3)^2
g = (39.8866 * 10^13) / 44890000 * 10^6
g = 0.000000888540 * 10^(13 - 6)
g = 0.000000888540 * 10^7
g = 8.8854 m/s²
which term describes when a substance is changed from a liquid to a gas
Answers
Answer:
vasporisation
Explanation:
process used to change liquid to gass
Answer:
I believe it's Evaportation or another word would be Vaporisation.
Explanation:
hope this helps! ^^
Mars has a small moon, Phobos, that orbits with a period of 7 h 39 min. The radius of Phobos' orbit is 9.4×106m. Use only this information (and the value of G) to calculate the mass of Mars.
Answers
Mass of the mars is 6.48 * \(10^{23\\\) kg.
Mars, the fourth planet from the Sun, is a dusty, cold desert world with a thin atmosphere.
Phobos is the larger of the two heavily cratered Martian moons and is dominated by three large craters.
Orbit period for Phobos = T = 7 h 39 min = 459 min
Radius of Phobos' orbit = r = 9.4 * \(10^{6}\) m
According to the Gravitational force and Centripetal force,
here both forces will be equal,
therefore (GmM/r²) = mrω²
m = mass of the Phobos
M is the mass of Mars
r is the Phobos' orbit radius
ω = (2\(\pi\)/T) = (2\(\pi\)/459)
G is the gravitational constant = 6.67 * \(10^{-11}\)
(GmM/r²) = mrω²
M = (ω²r³/G)
M = (2\(\pi\))² * (9.4 * \(10^{6}\))³/ (459 * 60)³ * 6.67 * \(10^{-11}\)
M = 6.48 * \(10^{23\\\) kg
Mass of the planet mars is 6.48 * \(10^{23\\\) kg.
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A pitcher throws a baseball horizontally from the mound to home plate. The ball falls 0. 857 m (2. 81 ft) by the time it reaches home plate 18. 3 m (60 ft) away. How fast was the pitchers pitch.
Answers
Answer:
Baseball is commonly expressed in English units - we'll use that
(Rubber to home plate is 60' 6 '' but the ball is probably released at about 60 ft)
t = S / v time of fall and time to reach plate
H = 1/2 g t^2
t = (2 H / g)^1/2 we'll use 32.,2 ft / sec^2 for g
t = (2 * 2.81 / 32.2)^1/2 = .418 sec
v = 60 ft / .418 sec = 144 ft/sec
Since 60 mph = 88 ft/sec
v = 144 / 88 * 60 = 98 mph
discuss two important realizations montag has while he is floating in the river and explain why they are important
Answers
Montag, the protagonist in Ray Bradbury's "Fahrenheit 451," has two important realizations while floating in the river. First, he understands the significance of preserving knowledge and literature. This is important because it drives him to join the group of intellectuals working to save books and rebuild society.
Secondly, Montag realizes the need for personal reflection and critical thinking. This realization is crucial as it helps him break free from the oppressive society he once served and allows him to grow as an individual. Both realizations are vital for Montag's transformation and the potential rebuilding of a more enlightened society. Montag's time spent floating in the river after his escape from the city is a pivotal moment in the novel Fahrenheit 451. During this time, Montag has two important realizations that change the course of his journey and provide insight into the themes of the novel.
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Find the magnitude of this
vector:
Answers
Answer: = 25. 5 m
Explanation:
2-D vectors can be solved using the Pythagorean theorem: \(a^{2} +b^{2} =c^{2}\)The hypotenuse, or longest side is not given and that is what must be solved forDirection can be omitted as the question only asks for magnitudeMagnitude: is the distance or quantity in which an object moves during motionSolve for C using Pythagorean theorem:
1. \(\sqrt{a^{2}+b^{2} }=c\)
2. \(\sqrt{22.2 m ^{2} +12.6m^{2} } =c\)
3. \(25.52646 m= c\)
round to lowest number of significant digits when dividing and multiplyingrounded to 3 significant digits∴ Magnitude of the vector is 25.5 m
Two resistors of resistances 6 Ω and 12 Ω, are connected first in series, and then in parallel in a circuit across a battery of 6 V. Calculate the ratio of the heat produced in the series combination to that of the parallel combination of resistors.
Answers
Answer:
0.0136
Explanation:
For the series connection
Effective resistance= 6 + 12= 18 ohm
Current= 6/18=0.33 A
Heat= I^2R= 0.33^2 × 18= 1.96 J
For parrallel
Effective resistance= 6^- 1+12^-1 = 0.167 + 0.083= 0.25 ohm
Current= 6/0.25= 24 A
Heat= 24^2 × 0.25=144J
Ratio of series to parallel= 1.96/144=0.0136
A baby's mouth is a distance of 35 cm from her father's ear and a distance of 1.60 m from her mother's ear. What is the difference between the sound intensity levels heard by the father and by the mother? Express your answer using two significant figures. βfather−βmother=？
Answers
The difference between the sound intensity levels heard by the father and by the mother is 18.4 dB.
The sound intensity level (SIL) is given by \(SIL = 10log^{\frac{1}{10} }\), where I is the sound intensity and I0 is the reference sound intensity (I₀ = 1 x 10⁻¹² W/m²).
Assuming that the baby produces the same sound intensity at both distances, we can use the inverse square law to relate the sound intensity at the two distances:
Ifather/Ibaby = (rbaby/rfather)²
Imother/Ibaby = (rbaby/rmother)²
where rbaby = 0.35 m is the distance from the baby's mouth to her own ear.
Taking the ratio of the two equations gives:
Ifather/Imother = (rbaby/rfather)² / (rbaby/rmother)² = (rmother/rfather)²
Taking the logarithm of both sides and using the SIL equation gives:
βfather - βmother = 10log(Ifather/I0) - 10log(Imother/I0) = 10log(Ifather/Imother)
Substituting the ratio above gives:
βfather - βmother = 10log[(rmother/rfather)²] = 20log(rmother/rfather)
Plugging in the given values, we get:
βfather - βmother = 20log(1.60/0.35) = 18.4 dB
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a mixture can be classified as a solution, a suspenstion, or a colliod based on the size of its............particles
Answers
Answer:
large
Explanation:
A mixture can be classified as a solution, a suspension, or a colloid based on the size of its large particles.
Hope it helps!
vf= 0 m/s + 2.00s how fast was he going when he entered the water?
Answers
13.0 m/s that's how fast he was going
i. What is the initial velocity of the car?
ii. What is the maximum velocity attained by the car?
iii. Which part of the graph represents zero acceleration?
Answers
Answer:
I. 0 m/s
II. 20 m/s
III. Part BC
Explanation:
I. Determination of the initial velocity.
From the diagram given above,
The motion of the car starts from the origin. This implies that the car start from rest and as such, the initial velocity of the car is 0 m/s
II. Determination of the maximum velocity attained.
From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.
III. Determination of the part of the graph that represents zero acceleration.
It important that we know the meaning of zero acceleration.
Zero acceleration simply means the car is not accelerating. This can only be true when the car is moving with a constant velocity.
From the graph given above, the car has a constant velocity between B and C.
Therefore, part BC illustrates zero acceleration.
Compare animal and plant cell
Answers
Answer:
A plant cell contains a large, singular vacuole that is used for storage and maintaining the shape of the cell. In contrast, animal cells have many, smaller vacuoles. Plant cells have a cell wall, as well as a cell membrane. Animal cells simply have a cell membrane, but no cell wall.
hope this helps :)
Answer:
Compare animal cell and plant cell: Both are eukaryotic cells, both contain membrane bound organelles. Both contain similar membranes such as cytosol and cytosketal elements.
Explanation:
What is the variance and standard deviation for: 13, 15, 12, 10, 4, 16, 17, 22, 9
Answers
A 230 v mains powered electrical drill draws a current of 2.5 A calculate the power of the drill at use
Answers
Which statement about local and global winds is true?.
Answers
Answer:
Global winds occur in belts around the globe.
Explanation:
This is because they blow over a limited area. They are influenced by local geography, such as nearness to an ocean.
An object carrying a force of 15N has a mass of 3kg. What is the
acceleration of this object?
Answers
Answer:
the acceleration would be 5kg
Explanation:because you would do 15 divided by 5
Factors considered when investing in rsa retail saving bonds
Answers
when investing in RSA retail saving bonds, investors should consider interest rates, investment term, risk, and liquidity. It is recommended that investors conduct thorough research and seek professional advice before making any investment decisions.
Firstly, it is important to consider the current interest rates being offered on the bonds. This will help investors determine the potential returns they can expect to earn on their investment.
Another factor to consider is the length of the investment term. RSA retail saving bonds are available in a variety of terms, ranging from 2 to 5 years.
It is also important to consider the level of risk associated with investing in RSA retail saving bonds. While these bonds are considered low-risk investments, there is always a chance that the issuer may default on the bond, resulting in the loss of the investor's principal.
Lastly, investors should consider the liquidity of the investment. RSA retail saving bonds are not easily tradable and may not be suitable for investors who require quick access to their funds.
In summary, when investing in RSA retail saving bonds, investors should consider interest rates, investment term, risk, and liquidity. It is recommended that investors conduct thorough research and seek professional advice before making any investment decisions.
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How does alpha particles transfer energy to their surroundings?
Answers
A Alpha Radiation. As charged particles, such as alpha particles, move through material, energy is transferred from the radiation to the atoms or molecules that make up the material. The major energy-loss mechanisms are electronic excitation and ionization.
Hope this helps :)
What is the detention time (minutes) in a rectangular flocculation basin when the flow is 0.7 mgd? the basin is 24 feet long, 12 feet wide, and 8 feet deep. select the closest answer.
Answers
The answer is 35 min.
The detention time (minutes) in a rectangular flocculation basin when the flow is 0.7 mgd, is 35 min.
What is flocculation basin?
The process of flocculation requires that the coagulated water be gently mixed at a propeller speed of 15 to 20 rpm in order to encourage the growth of the floc. To agglomerate the floes into sizes between 0.1 and 2.0 mm that can be removed by sedimentation, slow mixing is used. By bringing the finely divided substance into touch with the micro-floes created during rapid mixing, slow mixing is the hydrodynamic process that produces big and easily settleable floes.
These floes can then be cleaned out in a clarifier, and the leftovers can be filtered. Usually, flocculation lasts between 30 and 60 minutes.
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do we live in a simulation?
Answers
Answer:
well no, but yes
Explanation:
depends on your religion tbh
Answer:
There is a 50-50 chance that we do live in a simulation.
Explanation:
nancy is in her early 60s and nervous about growing old because she doesn’t want to be limited in her daily functioning or lose her memory or judgement. how might you reassure nancy about her fears?
Answers
I would like assure Nancy by telling her her Dementia is not inevitable; while 10% will develop dementia in their lifetime, less than half of people above age 84 will have it. So there is a 90% chance that Nancy might not lose her memory or judgement.
What is Dementia?Dementia is described as a general term for loss of memory, language, problem-solving and other thinking abilities that are severe enough to interfere with daily life.
Dementia is characterized by impairment of at least two brain functions, such as memory loss and judgement.
So there are high chances that Nancy might not lose her memory or judgement and normal functioning.
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In the figure, a small spherical insulator of mass 6.00×10−2 kg and charge +0.400 μC is hung by a thin wire of negligible mass. A charge of −0.220 μC is held 0.290 m away from the sphere and directly to the right of it, so the wire makes an angle theta with the vertical, as shown. What is the angle theta? (k=1/4πϵ0=8.99×109 N · m2/C2)
1.50∘
1.10∘
1.70∘
0.917∘
1.30∘
Answers
The angle theta in the given scenario can be determined by considering the forces acting on the small spherical insulator. The correct answer is 1.30∘.
The gravitational force acting on the small spherical insulator is balanced by the tension in the wire. Additionally, there is an electrostatic force between the charges.
The electrostatic force can be calculated using Coulomb's Law:
F = k * |q1 * q2| / \(r^2\)
where F is the force, k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between the charges.
In this case, the electrostatic force acts horizontally and must be balanced by the horizontal component of the tension in the wire. The vertical component of the tension balances the gravitational force.
Setting up the equilibrium condition, we can find the angle theta(θ):
tan(θ) = (horizontal component of tension) / (vertical component of tension)
tan(θ) = (electrostatic force) / (gravitational force)
Substituting the values given in the problem, we can calculate theta:
tan(θ) = [(k * |q1 * q2|) / \(r^2\)] / (m * g)
tan(θ) = [(8.99×\(10^9\) N · \(m^2/C^2\)) * (0.220 μC) * (0.400 μC)] / [(6.00×\(10^-^2\) kg) * (9.81 m/\(s^2\)) *\((0.290 m)^2\)]
tan(θ) ≈ 1.300
Taking the inverse tangent of 1.300, we find that θ ≈ 1.30∘.
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consider a river flowing toward a lake. the river is located 5 meters above the surface of the lake. the river flows at an average velocity of 5 m/s and volume flow rate of 1000 m3/s. the total mechanical energy per unit mass of the river water with respect to the surface of the lake is most nearly equal to
Answers
The total mechanical energy per unit mass of the river water with respect to the surface of the lake is equal to 61,550 m2/s2.
What is mechanical energy ?Mechanical energy is the energy possessed by an object due to its motion or due to its position relative to a force. It is the energy associated with the motion and position of an object. It is the energy used to perform work. It is the sum of kinetic energy and potential energy. Kinetic energy is the energy of motion while potential energy is energy stored due to the position of an object. Mechanical energy can be transformed from one form to another, but the total amount of energy remains the same.
The total mechanical energy per unit mass (or specific energy) of the river water with respect to the surface of the lake is equal to the sum of the potential energy (PE) and the kinetic energy (KE) of the river water.
PE = mgh = 1000 m3/s * 9.81 m/s2 * 5m = 49,050 m2/s2
KE = 0.5 * m * v2 = 0.5 * 1000 m3/s * (5 m/s)2 = 12,500 m2/s2
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Answer:
Use the table below to answer questions 5-6.
Answers
Answer:
its also difficult for me.
a car of mass 1200kg travelling at 30m/s runs into the back of a stationary
lorry. The car and lorry move at 4m/s after impact. Determine the mass of the
lorry.
Answers
Answer:
The mass of the lorry 7800 kg
Explanation:
Momentum conservation law for inelastic collision:
\(m1*V1 + m2*V2 =( m1 + m2)*V^{'} \\ \\1200*10^{3} g * 30 m/s + m2*0 m/s =(1200*10^{3} g + m2)*4 m/s\\ \\\frac{1200*10^{3} g * 30 m/s}{4 m/s} -1200*10^{3} g=m2\\ \\m2=9000*10^{3} g-1200*10^{3} g=7800*10^{3} g=7800 kg\)
A boat trip travels are 15 miles in the direction of 45° east of north for an hour the boat then turn and travels at 18 m/s in a direction 5° north of East for an hour
Answers
Answer:
Hello your question is incomplete below is the missing piece
What is the magnitude of the boat’s resultant velocity? Round your answer to the nearest whole number.
answer : 25.73 m/s
Explanation:
Given
V1 = 15 miles/hour = 6.71 m/s [ 45° EN ]
V2 = 18 m/s [ 5° NE ]
Calculate the resultant velocity
Vr = 6.71 m/s[45°] + 18m/s[5°].
Vr = ( 6.71 *Cos45° + 6.71 *sin45°) + ( 18 *Cos5° + 18*sin5° )
Vr = ( 4.74 + 4.74 i )+ ( 17.93 + 1.57i) = 22.67 + 12.18i.
Therefore the magnitude
= \(\sqrt{22.67^2 + 12.18^2}\) = 25.73 m/s
PLEASE HELP ILL GIVE BRAINLIEST
Answers
Answer:
Ok um this is tricky but ill give it a shot
1 Velocity because it was an object that was caught on fast by my mind rapidly.
2 Position and time graphs because I would get confused with the well to be honest everything! And I mean everything, in the module. It took me a lot of time to adjust to
3 I would study every single one to be prepared!
4 How hard is the module thats hard for me for my peers?
Explanation:
Good luck pls brainliest
An elevator is being pulled up from the ground floor to the third floor by a cable. The cable is exerting 4500 newtons of force on the elevator. According to Newton's law of action-reaction, what is the gravitational force on the elevator, in newtons, if the elevator is NOT accelerating?
Answers
Answer:
The gravitational force on the elevator = 4500N
Explanation:
The given parameters are;
The force applied by the elevator, F = 4500 N
The acceleration of the elevator = Not accelerating
From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;
F = W + Mass of elevator × Acceleration of elevator
∴ F = W + Mass of elevator × 0 = W
F = 4500 N = W
The net force on the elevator is F - W = 0
The gravitational force on the elevator = W = 4500N.
The gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.
Given data:
The magnitude of force on the elevator is, F = 4500 N.
From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows,
F = W + ma
Here, a is the acceleration of the elevator. Since, the elevator is not accelerating. Then, a = 0 .
The weight of the elevator is due to the gravitational force. So, we need to obtain the weight as gravitational force.
Solving as,
\(F = W+ma\\\\F=W +(m \times 0)\\\\4500=W\\\\W = 4500 \;\rm N\)
Thus, we can conclude that the gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.
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A cistern in the form of an inverted circular cone is being filled with water at the rate of 85 liters per minute. If the cistern is 7 meters deep, and the radius of its opening is 4 meters, find the rate at which the water level is rising in the cistern 40 minutes after the filling process began. Round any intermediate calculations, if needed, to no less than six decimal places, and round your final answer to three decimal places. (Hint: 1 m = 1000 L.) Answer 2 Points Keypad Keyboard Shortcuts m/min 3 ev
Answers
The water level is rising at a rate of 0.188 meters per minute after 40 minutes of filling the cistern.
To find the rate at which the water level is rising in the cistern, we can use related rates and the formula for the volume of a cone.
The volume of a cone can be calculated using the formula:
\(\[V = \frac{1}{3} \pi r^2 h\]\)
where \(\(V\)\) is the volume, \(\(r\)\) is the radius of the opening, and \(\(h\)\) is the height of the water level.
Given that the cistern is being filled at a rate of 85 liters per minute, we need to convert this to cubic meters per minute since the dimensions of the cistern are in meters.
Since 1 m = 1000 L, we have:
\(\[\frac{dV}{dt} = 85 \, \text{L/min} = 0.085 \, \text{m}^3/\text{min}\]\)
Now, let's differentiate the volume equation with respect to time:
\(\[\frac{dV}{dt} = \frac{1}{3} \pi \cdot 2r \cdot \frac{dr}{dt} \cdot h + \frac{1}{3} \pi r^2 \cdot \frac{dh}{dt}\]\)
We want to find the rate at which the water level is rising, \(\(\frac{dh}{dt}\)\), when \(\(t = 40\)\) minutes. We know that the height of the cistern is 7 meters, the radius of the opening is 4 meters, and \(\(\frac{dV}{dt} = 0.085 \\), \(\text{m}^3/\text{min}\)\).
Substituting these values into the equation, we can solve for \(\(\frac{dh}{dt}\)\).
First, let's find \(\(\frac{dr}{dt}\)\) using the Pythagorean theorem:
\(\[r^2 + h^2 = (4^2 + 7^2)\]\)
Simplifying, we have:
\(\[r^2 + h^2 = 65\]\)
Differentiating implicitly with respect to time, we get:
\(\[2r \cdot \frac{dr}{dt} + 2h \cdot \frac{dh}{dt} = 0\]\)
Since we are given the radius and height, we can solve for \(\(\frac{dr}{dt}\)\) and substitute them into the volume equation.
Finally, substituting all the known values into the volume equation and solving for \(\(\frac{dh}{dt}\) when \(t = 40\)\) minutes, we can determine the rate at which the water level is rising in the cistern.
The calculated result, rounded to three decimal places, is:
\(\(\frac{dh}{dt} = 0.188 \, \text{m/min}\)\)
Therefore, the water level is rising at a rate of 0.188 meters per minute after 40 minutes of filling the cistern.
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An object that is 0.5 m above the ground has the same amount of potential energy as a spring that is stretched 0.5 m. Each distance is then doubled. How will the potential energies of the object and the spring compare after the distances are doubled? The gravitational potential energy of the object will be two times greater than the elastic potential energy of the spring. The elastic potential energy of the spring will be four times greater than the gravitational potential energy of the object. The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object. The potential energies will remain equal to one another.
Answers
Answer:
The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.
Explanation:
Let U₁ = mgx be the gravitational potential energy of the object and U₂ = 1/2kx² the elastic potential energy of the spring.
Since U₁ = U₂ = U at x = x₀ = 0.5 m.
if x = 2x₀,
The gravitational potential energy is U₃ = mg(2x₀)
= 2mgx₀
= 2U
The elastic potential energy of the spring is U₄ = 1/2k(2x₀)²
= 1/2k × 4x₀²
= 4(1/2kx₀²)
= 4U
Now, U₄/U₃ = 4U/2U = 2
U₄ = 2U₃
So, the elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.
Answer: The answer is C, The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.
Explanation: