Answer: 75 students
Step-by-step explanation:
Skyler goes to a school that has 100 students in it. She asks 40 random students if they like the new 8.30 am start to the day and 30 of them say no they don't like it. This shows that: 30/40 = 3/4 of the students don't like it.
Since the school has 100 students, the number of students that doesn't like the 8.30 a.m start will be:
= 3/4 of 100
= 3/4 × 100
= 3 × 25
= 75
•Sequences and functions
( 10 points )
Please help me loves with the answer and understanding
•Please actually help me out I want to better understand this
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this data represents the number of jumps in a row 10 students made during a jump-rope competition.
30,36,38,45,57,60,77,86,88,88
whats the interquartile range?
The interquartile range of the number of jumps of the 10 students during the competition is 38.
What is the interquartile range?The interquartile range is the difference between the third quartile and the first quartile. The interquartile range is used to determine the variation of a data set.
Th first step is to determine the median of the first half of the dataset. The median of the first half is the first quartile.
First half of the data set: 30, 36, 38, 45, 57
Median = first quartile = 38
The next step is to determine the median of the second half of the dataset. The median of the second half is the third quartile.
Second half of the data set: 60, 77, 86, 88, 88
Median : third quartile = 86
Interquartile range = third quartile - first quartile
86 - 38 = 48
hence , interquartile range of the number of jumps of the 10 students during the competition is 38.
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Find 6 3/4 - 4 11/12. Write your answer in simplest form.
Answer:
1 5/6
Step-by-step explanation:
first convert to /12 and put the wholes in the fraction:
6 3/4 = 81/12
4 11/12 = 59/12
Then perform the subtraction
81/12 - 59/12 = 22/12
... and simplify
22/12 = 11/6
separate the wholes
11/6 = 6/6 + 5/6 = 1 5/6
Answer:
1 10/12
Step-by-step explanation:
Bc 6 3/4=6 9/12 and 6 9/12-4 11/12 can be made into 5 21/12-4 11/12 which equals 1 10/12
Factor by grouping 4(b+c)-m(b+c)
\(4(b+c)-m(b+c)\\\\=(b+c)(4-m)\)
Answer:
(b+c) (4-m)
Step-by-step explanation:
Factor out the greatest common factor from each group.
Factor the polynomial by factoring out the greatest common factor.
Laura spent ⅕ of her money on a new pocketbook and had $90 remaining. How much did she spend on her new pocketbook?
Answer:
$18
Step-by-step explanation:
90 x 1/5
90/5
18
Answer:
$22.50
Step-by-step explanation
90 is 80% (4/5) of what number (x)? So you do 90 times 100 = 9000 and 80 times x is 80x and then 9000 divided by 80 is 112.5 so she had 112.5 to begin with but she spent 1/5 so 112.5 divided by 5 is 22.5 so 1 fifth is 22.5
Can someone PLEASE help me ASAP?? It’s due today!!
i will give brainliest if it’s correct!!
The interquartile range (IQR) for each data set is:
1. 5; 2. 3; 3. 6; 4. 4
What is the Interquartile Range (IQR) of a Data Set?The interquartile range (IQR) of a data set can be described as the difference of the third quartile and the first quartile which can simply be gotten be subtracting Q1 from Q3.
Find the third quartile (Q3) and the first quartile (Q1) of each data set, then find the IQR:
1. Given, 8,12,20,10,6,15,12,9,10, we have:
Q1 = 8.5
Q3 = 13.5
IQR = 13.5 - 8.5 = 5
2. Given 12,5,9,7,10,11,11,12,13,14, we have:
Q1 = 9
Q3 = 12
IQR = 12 - 9 = 3
3. Given 7, 3, 5, 8, 11, 6, 12, we have:
Q1 = 5
Q3 = 11
IQR = 11 - 5 = 6
4. Given 7, 11, 7, 8, 9, 8, 11, we have:
Q1 = 7
Q3 = 11
IQR = 11 - 7 = 4
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tests for tuberculosis. Suppose that for the population of adults that is taking the test; 5% have tuberculosis The test correctly identifies 74.6% of the tlme adults with tuberculosis and correctly identifies those without tuberculosis 76.53% of the time: Suppose that POS stands for the test gives positive result and S means that the adult really has tuberculosis What is the probability of an adult getting NEG result and truly having tuberculosis? A.0.0373 B.0.0127 C.0.2230 D.0,7270
The probability of an adult getting a NEG result and truly having tuberculosis is 0.01725, which is closest to option (A) 0.0373.
Let's use the following notation:
P(TB) represents the probability that an adult has tuberculosis, which is given as 0.05.
P(POS|TB) represents the probability that the test is positive given that an adult has tuberculosis, which is given as 0.746.
P(NEG|TB) represents the probability that the test is negative given that an adult has tuberculosis, which is 1 - P(POS|TB) = 0.254.
We are asked to find the probability of an adult getting a NEG result and truly having tuberculosis, which can be calculated using Bayes' theorem as follows:
P(TB|NEG) = P(NEG|TB) * P(TB) / P(NEG)
We can calculate P(NEG) using the law of total probability, which considers the two possible cases for an adult: having tuberculosis (TB) or not having tuberculosis (TB').
P(NEG) = P(NEG|TB) * P(TB) + P(NEG|TB') * P(TB')
= 0.254 * 0.05 + 0.7653 * 0.95
= 0.7352
Now we can substitute the values into Bayes' theorem:
P(TB|NEG) = 0.254 * 0.05 / 0.7352
= 0.01725
Therefore, the probability of an adult getting a NEG result and truly having tuberculosis is 0.01725, which is closest to option (A) 0.0373.
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the process standard deviation is 0.15 , and the process control is set at plus or minus 2.4 standard deviations. units with weights less than or greater than ounces will be classified as defects. what is the probability of a defect (to 4 decimals)?
The probability of a defect (weights less than -0.36 ounces or greater than 0.36 ounces) is approximately 0.0521 × 2 = 0.1042 or 10.42% to four decimal places.
To find the probability of a defect, we need to determine the range of weights that would be considered as defects. The process control limit is set at plus or minus 2.4 standard deviations, which means that any weight outside the range of mean ± 2.4× standard deviation would be considered a defect. Let's calculate the mean weight (μ): μ = 0
And the control limit (LCL and UCL):
LCL = μ - (2.4 × standard deviation)
= 0 - (2.4 × 0.15) = -0.36 UCL
= μ + (2.4 × standard deviation)
= 0 + (2.4 × 0.15) = 0.36.
Since the standard deviation is 0.15 ounces and the normal distribution is symmetrical, the probability of a weight being less than -0.36 ounces or greater than 0.36 ounces is equal. To calculate the probability, we can use the cumulative distribution function (CDF) of a standard normal distribution. Using a standard normal table or a calculator with statistical functions, we can find that the probability of a standard normal distribution being less than -0.36 or greater than 0.36 is about 0.0521 or 5.21%. So, the probability of a defect (weights less than -0.36 ounces or greater than 0.36 ounces) is approximately 0.0521 × 2 = 0.1042 or 10.42% to four decimal places.
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(6.01 )which points on the scatterplot is an outlier point A point B point C point D
Answer: it’s point c
Step-by-step explanation:
Answer C
Answer:A
Step-by-step explanation:
you just told me but thanks for the points message me if you need more answers
Alberto tiene 4 años más que Antonio. Si el producto de sus edades es 60. ¿Qué edad tiene cada uno?
Antonio is 6 years old, and Alberto is 10 years old.
Solution: Let's assume that Antonio's age is x. Therefore, Alberto's age is x+4 (since Alberto has four more years than Antonio). Now, as the product of their ages is 60, we can make an equation out of it: x(x+4) = 60x² + 4x - 60 = 0(x+10)(x-6) = 0. Either (x+10) = 0 or (x-6) = 0. Hence, x = -10 or x = 6. But we can see that it's not possible to have negative age. Therefore, we can use x=6. That means Antonio's age is 6 years old. Then, Alberto's age is x+4=6+4=10 years old.
Equations act as a scale of balance. If you've ever seen a balancing scale, you know that it needs to have an equal amount of weight on both sides in order to be deemed "balanced". The scale will tip to one side if we just add weight to one side, and the two sides will no longer be equally weighted. Equations use the same reasoning. Anything on one side of the equal sign must have the exact same value on the opposite side in order for it to not be considered unequal.
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the humane society reports that of 428 animals at their local animal shelter, 376 are household pets and the remaining 52 are wildlife animals. over the weekend, 29 of the household pets were adopted and 10 of the wildlife animals were released back into the wild. is there sufficient evidence to indicate a difference in the number of animals leaving the shelter over the weekend for the two types (household pets and wildlife animals)? use the p-value approach at the 1% level of significance.
There is sufficient evidence to believe that the number of household pets leaving the shelter over the weekend is different from the proportion of wildlife animals leaving the shelter over the weekend.
How to prove it there's sufficient evidenceTo determine if there's sufficient evidence,
Let us define the null and alternative hypotheses for this test as follows:
Null hypothesis (H0): The proportion of household pets leaving the shelter over the weekend is the same as the proportion of wildlife animals leaving the shelter over the weekend.
Alternative hypothesis (Ha): The proportion of household pets leaving the shelter over the weekend is different from the proportion of wildlife animals leaving the shelter over the weekend.
The test statistic for two sample test is given by:
z = (p1 - p2) / sqrt(p * (1 - p) * (1/n1 + 1/n2))
where
p1 and p2 are the proportions of household pets and wildlife animals leaving the shelter over the weekend, respectively,
p is the pooled proportion,
n1 and n2 are the sample sizes for household pets and wildlife animals, respectively.
Pooled proportion is
p = (x1 + x2) / (n1 + n2)
where x1 and x2 are the number of household pets and wildlife animals leaving the shelter over the weekend, respectively.
Given
-n1 = 376, n2 = 52, x1 = 29, x2 = 10
p = (29 + 10) / (376 + 52) = 0.091
The observed proportions are:
p1 = x1 / n1 = 29 / 376 = 0.0771
p2 = x2 / n2 = 10 / 52 = 0.1923
The test statistic value
z = (0.0771 - 0.1923) / sqrt(0.091 * (1 - 0.091) * (1/376 + 1/52)) = -3.04
By using a standard normal distribution table,
The p-value is 0.00238.
Since the p-value (0.00238) is less than the level of significance (0.01), we reject the null hypothesis and conclude that there is sufficient evidence to indicate a difference in the number of animals leaving the shelter over the weekend for household pets and wildlife animals.
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A school survey of 90 sixth graders showed that 25% of them play basketball and about 17% play soccer. What are the chances that a sixth grader plays basketball AND soccer?
Answer:
0.0425
Step-by-step explanation:
probability of basket player = 0.25
probability of being a soccer player = 0.17
chances that a sixth grader plays basketball AND soccer = 0.25×0.17 = 0.0425
The function below gives the cost in dollars to manufacturex items: C(x) = 10,000 + 5x – 10.000 Find the average cost per item over the interval (1,000,1,010]. Continuing with the previous problem find the average cost per item over the interval [999.5, 1000]. Continuing with the previous problem, what is the value of C' (1000) rounded to 1-decimal place?
The average cost per item over the interval (1,000,1,010] is (C(1010) - C(1000)) / (1010 - 1000) = (10,000 + 5(1010) - 10,000 - 5(1000)) / 10 = $5.50.
The average cost per item over the interval [999.5, 1000] is (C(1000) - C(999.5)) / (1000 - 999.5) = (10,000 + 5(1000) - 10,000 - 5(999.5)) / 0.5 = $5.00.
The given function C(x) represents the cost in dollars to manufacture x items. To find the average cost per item over a given interval, we use the formula: (C(b) - C(a)) / (b - a), where a and b are the endpoints of the interval.
For the interval (1,000,1,010], we substitute a = 1000 and b = 1010 into the formula to obtain (C(1010) - C(1000)) / (1010 - 1000). Simplifying the expression using the given function C(x) yields ($10,000 + $5(1010) - $10,000 - $5(1000)) / 10 = $5.50 per item.
For the interval [999.5, 1000], we substitute a = 999.5 and b = 1000 into the formula to obtain (C(1000) - C(999.5)) / (1000 - 999.5). Simplifying the expression using the given function C(x) yields ($10,000 + $5(1000) - $10,000 - $5(999.5)) / 0.5 = $5.00 per item.
To find C'(1000), we differentiate the function C(x) with respect to x, which gives C'(x) = 5. The value of C'(1000) is therefore 5, rounded to 1 decimal place.
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: Manpreet just won the lottery. She would like to use some of her winnings to set up a retirement fund that will be used to provide her with payments of $3,500 at the beginning of each month for 20 years once she is retired. She plans on retiring in 16 years. If her retirement account is expected to earn 3.96% compounded monthly (112), how much should she put aside today?
Manpreet should put aside approximately $499,501.95 today for her retirement fund, considering an expected interest rate of 3.96% compounded monthly for 20 years, in order to receive $3,500 at the beginning of each month for 20 years once she is retired, starting in 16 years.
To calculate how much Manpreet should put aside today for her retirement fund, we can use the concept of present value. The present value (PV) is the current value of a future sum of money, taking into account the time value of money and the interest rate.
In this case, Manpreet wants to receive $3,500 at the beginning of each month for 20 years once she is retired, and she plans to retire in 16 years. The interest rate is 3.96% compounded monthly.
To calculate the present value, we can use the formula for the present value of an ordinary annuity:
PV = PMT * [(1 - (1 + r)^(-n)) / r],
where PV is the present value, PMT is the payment per period, r is the interest rate per period, and n is the number of periods.
Using the values:
PMT = $3,500,
r = 3.96% / 12 (monthly interest rate),
n = 20 * 12 (number of months in 20 years).
Substituting these values into the formula:
PV = $3,500 * [(1 - (1 + (0.0396/12))^(-20*12)) / (0.0396/12)].
Calculating this expression will give us the amount that Manpreet should put aside today for her retirement fund.
To calculate the present value (PV) for Manpreet's retirement fund, we can use the formula:
PV = PMT * [(1 - (1 + r)^(-n)) / r].
Substituting the values into the formula:
PMT = $3,500,
r = 3.96% / 12 = 0.0033 (monthly interest rate),
n = 20 * 12 = 240 (number of months in 20 years).
PV = $3,500 * [(1 - (1 + 0.0033)^(-240)) / 0.0033].
Now, let's calculate this expression step by step:
1 + 0.0033 = 1.0033,
1.0033^(-240) ≈ 0.52906145,
1 - 0.52906145 ≈ 0.47093855.
Now, let's substitute these values back into the equation:
PV = $3,500 * (0.47093855 / 0.0033).
Dividing 0.47093855 by 0.0033:
PV ≈ $3,500 * 142.71498635.
Calculating the final result:
PV ≈ $499,501.95.
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What is the slope of the line that passes through the points (4, -2) and (4, 10)? Write your answer in simplest form.
Answer:
12/0 undefined slope
Step-by-step explanation:
10-(-2) 12
______ = ---
4-4 0
Answer:
Undefined Slope.
Step-by-step explanation:
The points make a vertical line.
Equation: x = 4.
what the answer for order of operations 50+50-25x0+2+2 ?
Twenty students scored the following marks in a history test: 5, 2, 5, 3, 1, 6, 2, 2, 3, 4, 2, 1, 2, 2, 4, 3, 2, 2, 2, 3. What is the mode of distribution. What is the median and mean
Answers:
Mode = 2Median = 2Mean = 2.8===================================================
Work Shown:
Original set = {5, 2, 5, 3, 1, 6, 2, 2, 3, 4, 2, 1, 2, 2, 4, 3, 2, 2, 2, 3}
Sorted set = {1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 5, 5, 6}
Do not toss out the duplicates.
The most occurring or most frequent value is 2, so this is the mode.
---------------------------
To find the median, we divide the n = 20 item set into two parts
n/2 = 10
So we'll count to the 10th slot to get to the number "2", which is the second to last "2" in the sorted list shown above.
The number just after this is also "2" in the 11th slot. Average these two values to get (2+2)/2 = 4/2 = 2
The median is 2.
----------------------------
To find the mean, we need to first add up all the data values.
1+1+2+2+2+2+2+2+2+2+2+3+3+3+3+4+4+5+5+6 = 56
Then divide this over n = 20 to get 56/20 = 2.8
The mean is 2.8
The mean being larger than the median tells us we have an outlier that is larger than the main cluster. Those outliers are 5 and 6.
is there sufficient evidence to suggest that the relaxation exercise slowed the brain waves? assume the population is normally distributed. select the [p-value, decision to reject (rh0) or failure to reject (frh0)].
Based on the given information, it is not possible to determine the p-value, decision to reject (rh0) or failure to reject (frh0) without additional data or context.
To assess whether the relaxation exercise slowed brain waves, a statistical analysis should be conducted on a sample from the population.
The analysis would involve measuring brain waves before and after the exercise and comparing the results using appropriate statistical tests such as a t-test or ANOVA. The p-value would indicate the probability of observing the data if there was no effect, and the decision to reject or fail to reject the null hypothesis would depend on the predetermined significance level.
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(427) 32-1
How do I solve this???
Answer: 13,663
Step-by-step explanation:
basically I multiply 427 and32 which u get 13,664 and then u subtract 1 and u get ur answe of 13663
what is f (-2) if f (x) = 1/2x?
\(f(x) = \dfrac{1}{2x} \\~\\~\\f(-2) = \dfrac{1}{2\cdot(-2)} \\~\\~\\f(-2) = -\dfrac{1}{4} \\~\\~\\f(-2) = -0.25\)
An ice cream shop ordered waffle cones that have a height of 4 in and volume of 3
�
π
in3. The ice cream shop is trying to determine which size ice cream scoop will be the best fit for the waffle cones. Ice cream scoops come in different sizes and have different diameters. The #12 scoop has a 2. 5 in diameter and the #6 scoop has a 3 in diameter. Unfortunately, they are waiting on their order of waffle cones and they don't know the measure of the diameter
The ice cream shop could order a different size scoop with a diameter closer to 1.732 in for an even better fit.
Ice cream scoop will be the best fit for the waffle cones need to find out the diameter of the cones.
We can use the given height and volume of the cones to calculate the diameter using the formula for the volume of a cone:
V = (1/3) × π × r² × h
V is the volume r is the radius (which is half the diameter) and h is the height.
Rearranging the formula to solve for r we get:
r = √((3V) / (πh))
Substituting the given values of V = 3π in³ and h = 4 in we get:
r = √((3π) / (4π))
= √(3/4)
= 0.866 in
So, the diameter of the waffle cones is approximately 1.732 in (twice the radius).
Now we can compare this diameter to the diameters of the #12 and #6 scoops.
The #12 scoop has a diameter of 2.5 in is larger than the cone diameter of 1.732 in so it may not be the best fit.
The #6 scoop has a diameter of 3 in is larger than the cone diameter but closer in size so it may be a better fit than the #12 scoop.
The ice cream shop could order a different size scoop with a diameter closer to 1.732 in for an even better fit.
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Guys can you please help. I dont understand. Thank you. :))))
Lines AB and CD intersect at E. If the measure of angle AEC=5x-20 and the measure of angle BED=x+50, find, in degrees, the measure of angle CEB.
Answer: 112.5
Step-by-step explanation: When line AB and CD intersect at point E, angle AEC equals BED so you set them equal to each other and find what x is. 5x -20 = x + 50, solving for x, which gives you 17.5. Finding x will tell you what AEC and BED by plugging it in which is 67.5. Angle BED and BEC are supplementary angles which adds up to 180 degrees. So to find angle CEB, subtract 67.5 from 180 and you get 112.5 degrees.
If the forecast for two consecutive periods is 1,500 and 1,400 and the actual demand is 1,200 and 1,500 , then the mean absolute deviation is 1) 500 2) 700 3) 200 4) 100
200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
How to calculate the mean absolute deviation
The absolute difference between the predicted and actual values must be determined, added together, and divided by the total number of periods.
Forecasted values are as follows: 1,500 and 1,400
Values in actuality: 1,200 and 1,500
Absolute differences:
|1,500 - 1,200| = 300
|1,400 - 1,500| = 100
Now, we calculate the MAD:
MAD = (300 + 100) / 2 = 400 / 2 = 200
Therefore, 200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
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What is the solution to this system of equations?
{x+y=6x=y+4
(1, 5)
begin ordered pair 1 comma 5 end ordered pair
(212, 112)
begin ordered pair 21 halves comma 11 halves end ordered pair
(5, 1)
begin ordered pair 5 comma 1 end ordered pair
(112, 12)
The solution to the given system of linear equations is x = 4, y = 20
System of linear equationsFrom the question, we are to determine solution to the given system of equations
The given system of equations is
x+y=6x=y+4
Thus, we can write that
x + y = 6x ----------- (1)
and
6x = y + 4 ------------(2)
Solve the two equations simultaneously
From equation (1)
x + y = 6x
y = 6x - x
y = 5x --------- (3)
Substitute into equation (2)
6x = y + 4
6x = 5x + 4
6x - 5x = 4
x = 4
Substitute the value of x into equation (3)
y = 5x
y = 5(4)
y = 20
Hence, the solution to the given system of linear equations is x = 4, y = 20
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Find dy/dx by implicit differentiation. tan^−1(5x2y) = x + 4xy^2.
The derivative of y with respect to x is (1 + 4y^2 - 10xy - 25x^4y^2)/(5x^2 - 4x - 100x^2y^2).
To find dy/dx by implicit differentiation, we need to differentiate both sides of the equation with respect to x using the chain rule and the product rule.
We have:
tan^−1(5x^2y) = x + 4xy^2
Differentiating both sides with respect to x:
d/dx(tan^−1(5x^2y)) = d/dx(x + 4xy^2)
Using the chain rule on the left side:
[1/(1+(5x^2y)^2)] * d/dx(5x^2y) = 1 + 4y^2 + 4x(dy/dx)y
Simplifying the left side using the chain rule:
[1/(1+25x^4y^2)] * (10xy + 5x^2(dy/dx)y) = 1 + 4y^2 + 4x(dy/dx)y
Multiplying both sides by (1+25x^4y^2) to eliminate the denominator on the left side:
10xy + 5x^2(dy/dx)y = (1+25x^4y^2) * (1 + 4y^2 + 4x(dy/dx)y)
Expanding the right side:
10xy + 5x^2(dy/dx)y = 1 + 4y^2 + 4x(dy/dx)y + 25x^4y^2 + 100x^2y^2(dy/dx)y
Gathering the terms with dy/dx on one side:
5x^2(dy/dx)y - 4x(dy/dx)y - 100x^2y^2(dy/dx)y = 1 + 4y^2 - 10xy - 25x^4y^2
Factorizing out dy/dx:
(5x^2 - 4x - 100x^2y^2) * (dy/dx) = 1 + 4y^2 - 10xy - 25x^4y^2
Dividing both sides by (5x^2 - 4x - 100x^2y^2):
dy/dx = (1 + 4y^2 - 10xy - 25x^4y^2)/(5x^2 - 4x - 100x^2y^2)
Therefore, the derivative of y with respect to x is (1 + 4y^2 - 10xy - 25x^4y^2)/(5x^2 - 4x - 100x^2y^2).
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PLEASE HELP I WILL GIVE BRAINLIEST
Answer:
x > 2
Step-by-step explanation:
Since the dot is not filled in, it does not include 2. Since it is moving to the right, it means it is more than 2.
Hope that helps!
Answer:
x>2
Step-by-step explanation:
since the circle on the number two is a hollowed-out circle then it is less than greater than so it is not equal to anything. and since the arrow is pointed greater than 2.
So all values of x are greater than 2
Hope this helps :)
In a container, Samantha has different colored gum: 2 white, 5 green, 6 blue, and 7 orange. If Samantha randomly selects a piece of gum, what is the probability she will select blue?
The probability of Samantha randomly selecting a blue piece of gum from the container is 3/10 or 0.3.
The probability of Samantha selecting blue gum can be calculated by dividing the number of blue gum pieces by the total number of gum pieces in the container:
Probability of selecting blue = Number of blue gum pieces / Total number of gum pieces
Probability of selecting blue = 6 / (2 + 5 + 6 + 7)
Probability of selecting blue = 6 / 20
Probability of selecting blue = 3 / 10
Therefore, the probability of Samantha selecting blue gum is 3/10 or 0.3.
Probability is a mathematical concept used to measure the likelihood of an event occurring, ranging from 0 (impossible) to 1 (certain).
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The figure to the right is comprised of a rectangle and two half circles. The rectangle is 100 ft wide and 10 ft long. Find the total area of the figure. Show your work and/or explain your reasoning.
A-1,000ft^2
B-1,314ft^2
C-120ft^2
D-1,078.5ft^2
Pls help
Answer:
D 1,078.5 ft^2
Step-by-step explanation:
You want the area of a figure composed of a rectangle 100 ft long and 10 ft wide with semicircles of diameter 10 ft at each end.
Rectangle AreaThe area of the rectangle is ...
A = LW
A = (100 ft)(10 ft) = 1000 ft²
Circle AreaThe two half-circles have the area of a whole circle with radius 5 ft.
A = πr²
A = π(5 ft)² = 25π ft² ≈ 78.5 ft²
Total AreaThe area of the figure is the sum of the areas of its parts:
total area = rectangle area + circle area
total area = 1000 ft² +78.5 ft² = 1078.5 ft²
The total area of the figure is about 1078.5 ft².
If the population of the United States is 260 million, the labor force is 130 million, and 120 million workers are employed, the rate of unemployment is:
A) 7.7%.
B) 8.3%.
C) 50%.
D) 92%.
A
7.7%. is the rate of unemployment.
What is unitary method?Area is the entire amount of space occupied by a flat (2-D) surface or an object's shape.On a sheet of paper, draw a square using a pencil. It has two dimensions. The area of a shape on paper is the area that it occupies.Consider your square as being composed of smaller unit squares.The number of unit squares necessary to completely cover the surface area of a specific 2-D shape is used to calculate the area of a figure. Some typical units for measuring area are square cms, square feet, square inches, square meters, etc.Draw unit squares with 1-centimeter sides in order to calculate the area of the square figures shown below. The shape will therefore be measured.According to our question-
Unemployment rate = number of unemployed people / total number of unemployed people * 100
Similarly,
Workforce = Employed + Unemployed
Unemployed = 130 million - 120 million. That's 10 million.
For this reason,
Unemployment rate = 10 / 130 * 100
Unemployment = 7.69% or about 7.7%.
Hence, 7.7%. is the rate of unemployment.
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If 1 pound of grass seed costs 25x cents, represent in terms of x the cost of 7 pounds of seed? In polynomial simplest form
Answer:
175 cents
Step-by-step explanation:
25x=
25 • 7
25 • 7 = 175
Therefore the cost of 7 pounds of seed is 175 cents.