Answer:
s
Step-by-step explanation:
11s-11sto make it easier, change it to...
11s+(-11s)
now solve.
your answer is s
Answer: 0
Step-by-step explanation:
11s-11s - Collect like terms
=0
BRAINIEST TO WHOEVER CAN ANSWER THIS QUESTION!
Answer:B
Step-by-step explanation:
Step-by-step explanation:
This is a circle with center, h,k = 3,2 and radius = 2
circle equation is ( x-h)^2 + (y-k)^2 = r^2
so:
(x-3)^2 + (y-2)^2 = 4
HELP PLSSSSS
Find the value of a, AB, BC, CD, AD in the parallelogram. Show work in full for brainliest.
Answer:
a=21
AB=23.9
BC=19.5
CD=(23.9)
AD=19.5
Step-by-step explanation:
Each pair of parallel sides are equal in a parallelogram. Sense both pairs use the same variable we can just choose the easiest to solve which would be:
a-1.5=19.5
add 1.5 to both sides
a=21
now substitute 21 in for a in each equation.
AB=CD so
AB=23.9
BC=AD so
BC=19.5
CD=(21)+2.9 so
CD=(23.9)
AD is given so
AD=19.5
An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows:F(x) =0 x < 10.31 1 ≤ x < 30.42 3 ≤ x < 40.46 4 ≤ x < 60.82 6 ≤ x < 121 12 ≤ xa) What is the pmf of X?x 1 3 4 6 12p(x) _____
For the given CDF of X, the pmf of X at 1,3,4,6 and 12 is written as :
P(X = k) = 0.30 for k = 1 , P(X = k) = 0.10 for k = 3,
P(X = k) = 0.05 for k = 4 , P(X = k) = 0.15 for k = 6,
P(X = k) = 0.40 for k = 12.
In order to find the probability mass function (PMF) of X, we need to calculate the probability that X takes on each possible value.
Since X can take on any positive integer value, we can start by calculating the probability that X equals each positive integer.
⇒ P(X = 1) = 0.30,
⇒ P(X = 3) = F(3) - F(1) = 0.40 - 0.30 = 0.10
⇒ P(X = 4) = F(4) - F(3) = 0.45 - 0.40 = 0.05
⇒ P(X = 6) = F(6) - F(4) = 0.60 - 0.45 = 0.15
⇒ P(X = 12) = F(12) - F(6) = 1 - 0.60 = 0.40
Therefore, the required PMF of X is: P(X = 1) = 0.30 , P(X = 3) = 0.10 , P(X = 4) = 0.05 , P(X = 6) = 0.15 and P(X = 12) = 0.40 .
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The given question is incomplete, the complete question is
An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholder, let X = the number of months between successive payments.
The CDF of X is as follows:
F(x) = {0 x < 1
{0.30 1 ≤ x < 3
{0.40 3 ≤ x < 4
{0.45 4 ≤ x < 6
{0.60 6 ≤ x < 12
{1 12 ≤ x
What is the pmf of X at 1,3,4,6 and 12?
A real life scenario could be like earning 15 dollars.
need written response
Answer:
Step-by-step explanation:
first of all you need to do is make a lemonade stand and make the lemonade taiste good then you can sell it for 15 dollars which is a good price to get you started with your life
Write the linear equation that gives the rule for this table.
Linear equations are two-variable equations that graph as a straight line.
What is meant by linear equation?An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. The variables in the previous sentence, y and x, are referred to as a "linear equation with two variables" at times.
Two-variable equations that graph as a straight line are said to be linear equations. The slope and y-intercept of a linear equation allow it to be graphed. Y = mx + b, where m is the slope and b is the y-intercept, is the formula used to represent a line. A graph's straight line can be represented by a linear equation.
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the following are midterm scores of an algebra class of 20 students in a high school: 69 84 52 93 81 74 89 85 88 63 87 64 67 72 74 55 82 91 68 77 find the interquartile range using r.
13.3 is the interquartile range of the data set.
Given,
The midterm scores of an algebra class of 20 students;
69 84 52 93 81 74 89 85 88 63 87 64 67 72 74 55 82 91 68 77
We have to find the interquartile range using r.
Interquartile Range;-
The second and third quartiles, or the centre half of your data set, are contained in the interquartile range (IQR). The interquartile range provides the range of the middle half of a data set, whereas the range provides the spread of the entire data set.
Interquartile range = Q3 - Q1
Q1 is the lower quarter
Q3 is the upper quarter
Q2 is the median
Here,
Q2 = 63 + 87 / 2 = 150 / 2 = 75
Q1 = 81 + 74 / 2 = 77.5
Q3 = 74 + 55 / 2 = 64.5
Then,
Interquartile range = Q3 - Q1 = - (64 . 5 - 77.5) = 13.3
That is,
The interquartile range for the given data set is 13.3
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Zara ate 75 almonds this week, or 150% as many as she ate last week. How many almonds did Zara eat last week? The percent written as a part-to-whole ratio is to 100. 150 divided by is equal to 75. 100 divided by is equal to . Zara ate almonds last week.
a. The amount of almonds that Zara ate last week is equal to 50.
b. The percent written as a part-to-whole ratio is 150:100.
c. 150 divided by 2 is equal to 75.
Let the number of almonds that Zara ate last week be L.Given the following data:
Amount of almonds = 75 almondsPercentage = 150%a. To determine the amount of almonds that Zara ate last week:
\(\frac{150}{100} \times L = 75\\\\1.5L =75\\\\L=\frac{75}{1.5}\)
L = 50 almonds
b. The percent written as a part-to-whole ratio is:
Part = 150%Whole = 100%Part-to-whole ratio = 150:100
c. 150 divided by ___ is equal to 75:
\(\frac{150}{y} =75\\\\150=75y\\\\y=\frac{150}{75}\)
y = 2
Ratio: https://brainly.com/question/12212308
Answer:
the first one is 150
second one is 2
third one is 2
fourth is 50
fifth one is 50
Step-by-step explanation:
hope this helps!! i took assignment
length of a rectangle with a width of 10 and an area of 150 meters
We know that the area of a rectangle is given by the formula A = l × w, where A is the area, l is the length, and w is the width.
In this case, we are given that the width is 10 meters and the area is 150 square meters. So, we can plug in these values into the formula to find the length:
150 = l × 10
Dividing both sides by 10, we get:
15 = l
Therefore, the length of the rectangle is 15 meters.
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A $5000 investment pays 3% interest compounded monthly. To the nearest cent, what will be the value of the investment after 10 years?
Answer:
We can use the formula for compound interest to solve this problem. The formula is:
A = P * (1 + r/n)^(n*t)
where:
A = the amount of money after t years
P = the principal amount (the initial investment)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the number of years
In this case, P = $5000, r = 0.03, n = 12 (since the interest is compounded monthly), and t = 10. Plugging these values into the formula, we get:
A = 5000 * (1 + 0.03/12)^(12*10)
A = 5000 * (1.0025)^120
A ≈ $6,621.36
So the investment will be worth approximately $6,621.36 after 10 years.
2
If 3 12, what is the value of x?
O 4
08
O 18
24
Answer:
8
Step-by-step explanation:
12 ÷ 3 = 4
2 x 4 = 8
Hope I could help :)
How much does it cost to buy 10 beaded key chains that cost $0.91 apiece?
Answer:
9.10
Step-by-step explanation:
0.91x10=9.10
Please look at the photo. Thank you!
The zeros with each multiplicity are given as follows:
Multiplicity one: x = 6.Multiplicity two: x = 11.Multiplicity three: x = -6 and x = -5.How to obtain the multiplicities?The factor theorem is used to define the functions, which states that the function is defined as a product of it's linear factors, if x = a is a root, then x - a is a linear factor of the function.
Considering the linear factors of the function in this problem, the zeros are given as follows:
(x + 6)³ -> zero at x = -6 with multiplicity of 3.(x - 11)² -> zero at x = 11 with multiplicity of 2.x - 6 -> zero at x = 6 with multiplicity of 1.(x + 5)³ -> zero at x = -5 with multiplicity of 3.More can be learned about the Factor Theorem at brainly.com/question/24729294
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-5 = -36 / m + m
pls help me with this question hurry
This is 6 grade work
The solution of the given quadratic equation -5 = -36 / m + m is,
m = - 9 or m = 4
The given equation is
-5 = -36 / m + m
After re arranging it we get,
m² + 5m - 36 = 0
This is nothing but quadratic equation,
Since we know that,
The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. The quadratic equation has the following generic form:
ax² + bx + c = 0
So now we can write,
⇒ m² + 9m - 4m - 36 = 0
⇒ m(m + 9) - 4(m + 9) = 0
⇒ (m + 9)(m - 4) = 0
Therefore,
⇒ (m + 9) = 0 or (m - 4) = 0
⇒ m = - 9 or m = 4
Thus,
The solution of the given expression is
m = - 9 or m = 4
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Select the geometric figure that fits the following description.
the collection of all points that are equidistant from a given point
Choice D is correct
Every point on circle is equidistant from the point at its centre and that fixed distance = radius of that circle.
Which of the following pairs show(s) two congruent triangles?
O B only
OB and C only
O A, B, and C
O A and C only
Answer:
B only
Step-by-step explanation:
Triangles A and C are similar, but not congruent to each other. Similar triangles have proportional sides and congruent angles, while congruent triangles have congruent sides and congruent angles.
Therefore, only B is correct
The question is asking for pairs of congruent triangles but lacks key information needed to accurately answer this, such as lengths or angles. Congruent triangles are identified in geometry based on either side-lengths or angles.
Explanation:The question is about congruent triangles, which in mathematics means triangles that have the same size and shape. But to accurately answer which pairs show two congruent triangles, we need more information. The options provided include 'A', 'B', and 'C' but without knowing more about these elements (for example their lengths or angles), it is impossible to determine which are congruent. Congruent triangles are identified in geometry based on either side lengths (SSS: Side-Side-Side, SAS: Side-Angle-Side, ASA: Angle-Side-Angle) or angles (AAS: Angle-Angle-Side, HL: Hypotenuse-Leg for right triangles). Without this vital information, we cannot definitively answer the question. Be sure to verify all the properties required to prove two triangles congruent.
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(1/2)(-27Divided by 1/3) 2/3
The value of the quotient is - 27
How to determine the quotientTo determine the quotient, first, we have
(1/2)(-27Divided by 1/3) 2/3
\( \frac{1}{2} \times \frac{ - 27 \times 3}{1} \times \frac{2}{3} \)Multiply the numerator and denominator
=
\( \frac{ - 162}{6} \)
Then divide the numerator by the denominator, we get
= - 27
Thus, the value of the quotient is - 27
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Pls answer correctly I’ll give you brainliest
Answer:
y=-1x+-3
Step-by-step explanation:
Guided Practice
Find the balance in the account.
$4000 principal earning 6% compounded annually, after 5 years
A.
$5352.90
B.
$4240
C.
$6872.20
Answer:
I guess it C.$6872.20
if not please forgive me
Answer:
A.
$5352.90
Step-by-step explanation:
A=p(1+r)^t
A=4,000×(1+0.06)^(5)
A=5,352.90
...................................................
Answer:
The Final Investment Value is
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate is the base b(t) chaging when the height h=15cm and the area A= 130cm2
Answer:
The base of the triangle decreases at a rate of 2.262 centimeters per minute.
Step-by-step explanation:
From Geometry we understand that area of triangle is determined by the following expression:
\(A = \frac{1}{2}\cdot b\cdot h\) (Eq. 1)
Where:
\(A\) - Area of the triangle, measured in square centimeters.
\(b\) - Base of the triangle, measured in centimeters.
\(h\) - Height of the triangle, measured in centimeters.
By Differential Calculus we deduce an expression for the rate of change of the area in time:
\(\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}\) (Eq. 2)
Where:
\(\frac{dA}{dt}\) - Rate of change of area in time, measured in square centimeters per minute.
\(\frac{db}{dt}\) - Rate of change of base in time, measured in centimeters per minute.
\(\frac{dh}{dt}\) - Rate of change of height in time, measured in centimeters per minute.
Now we clear the rate of change of base in time within (Eq, 2):
\(\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}\)
\(\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}\) (Eq. 3)
The base of the triangle can be found clearing respective variable within (Eq. 1):
\(b = \frac{2\cdot A}{h}\)
If we know that \(A = 130\,cm^{2}\), \(h = 15\,cm\), \(\frac{dh}{dt} = 2.5\,\frac{cm}{min}\) and \(\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}\), the rate of change of the base of the triangle in time is:
\(b = \frac{2\cdot (130\,cm^{2})}{15\,cm}\)
\(b = 17.333\,cm\)
\(\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)\)
\(\frac{db}{dt} = -2.262\,\frac{cm}{min}\)
The base of the triangle decreases at a rate of 2.262 centimeters per minute.
Jake is building a fence around his property. He wants the perimeter to be no more than 100 feet. He also wants the length to be at least 10 feet longer than the width. If he builds his fence according to these limits, which would be the maximum possible width of the fence?
A. 30 feet
B. 50 feet
C. 20 feet
D. 10 feet
Answer:
C. 20 feet
Step-by-step explanation:
Let x = width
Let y = length
If the length is at least 10 feet longer than the width:
⇒ x + 10 ≤ y
⇒ x ≤ y - 10
If the perimeter is to be no more than 100 ft:
⇒ 2x + 2y ≤ 100
⇒ x + y ≤ 50
⇒ x ≤ 50 - y
Equate the equations for x and solve for y:
⇒ y - 10 = 50 - y
⇒ 2y = 60
⇒ y = 30
Substitute found value of y into one of the inequalities for x:
⇒ x ≤ 30 - 10
⇒ x ≤ 20
Therefore, the maximum possible width of the fence is 20 feet.
the Anderson are going on a long sailing trip during the summer however one of the sails on their sailboat ripped and they have to replace it the sail is pictured below if the sailboat sails are sale for 2$ per square foot how much will the new sail cost?
Firs we need to calculate the area of a triangle
\(A=\frac{b\cdot h}{2}\)b= base
h=heigth
in our case
b=8ft
h=12ft
\(A=\frac{8\cdot12}{2}=\frac{96}{2}=48ft^2\)then we will calculate the total cost
1 square foot ----- $2
48 square feet ----- x
the total cost is 48*2=96
total cost is $96
In a class of students, the following data table summarizes how many students have a
brother or a sister. What is the probability that a student chosen randomly from the
class has a brother?
The probability that a student chosen randomly from the class has a brother is 57%.
Given is a data table summarizes how many students have a brother or a sister.
We need to find the probability that a student chosen randomly from the class has a brother,
So, we know, probability = favorable outcome / total outcome
Here, favorable outcome = having a brother = 12 + 4 = 16
Total outcomes = all the students = 12+4+10+2 = 28
So,
P(having a brother) = 16/28 = 0.57 = 57%
Hence the probability that a student chosen randomly from the class has a brother is 57%.
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from a point 1.75 m above the ground and 10 m away from a tower the angle of elevation of a top of a tower is 60 degree calculate the height of the tower
Answer:
17.32 meters
Step-by-step explanation:
Let’s call the height of the tower H. The distance from the point to the base of the tower is 10 m. The angle of elevation from the point to the top of the tower is 60 degrees.
Using trigonometry, we can calculate that:
tan (60) = H / 10
H = 10 * tan (60)
H = 10 * √3
H = 17.32 m
Therefore, the height of the tower is 17.32 meters.
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The graph shows the function f(x) = 6(3)x. What is the value of the inverse function, f −1, at x = 2?
Answer:
There is an error in the equation.
f ( x ) = 63 X?? or whatt??
Answer:
-1
Step-by-step explanation:
y = f(x)
y = 6 * 3^x
Interchange x and y
x = 6 * 3^y
Divide by 6
x/6 = 3^y
Take the log of both sides
log(x/6) = log(3)^y
Bring the y down
log(x/6) = y log(3)
Divide by log(3)
log(x/6)/log(3) = y
Let x = 2
log(2/6) / log(3) = y
-(0.4771 )/ 0.4771 = y
y = - 1
Remark
The original graph is in green
The red graph is the inverse.
The point (2,-1) is marked so that you know it falls on the inverse.
Sketch and label a net of the right triangular prism. Each square on the grid represents
1 square centimeter. Calculate the surface area of the prism by using its net.
The total surface area of the prism is determined as 216 cm².
What is the surface area of the prism?The surface area of the prism is calculated by applying the following formula.
The area of the two triangular faces is calculated as follows;
Area of the two triangles = 2 (¹/₂ x base x height )
Area of the two triangles = 2 (¹/₂ x 6 cm x 4 cm )
Area of the two triangles = 24 cm²
The area of rectangular faces is calculated as follows;
A = ( 5 cm x 12 cm ) + (5 cm x 12 cm ) + ( 6 cm x 12 cm )
A = 192 cm²
The total surface area of the prism is calculated as follows;
Area = 24 cm² + 192 cm²
Area = 216 cm²
The sketch of the triangular prism is in the image attached.
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Rotate the given triangle 270° counter-clockwise about the origin.
\(\left[\begin{array}{ccc}-1&2&2\\-1&-1&3\end{array}\right]\)
\(\left[\begin{array}{ccc}-1&[?]&[?]\\1&[?]&[?]\end{array}\right]\)
The rotation of the triangle \(\left[\begin{array}{ccc}-1&2&2\\-1&-1&3\end{array}\right]\) 270° counter-clockwise about the origin gives \(\left[\begin{array}{ccc}-1&-1&3\\1&-2&-2\end{array}\right]\)
What is transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.
If a point (x, y) is rotated 270° counter-clockwise about the origin, the new point is (y, -x)
The rotation of the triangle \(\left[\begin{array}{ccc}-1&2&2\\-1&-1&3\end{array}\right]\) 270° counter-clockwise about the origin gives \(\left[\begin{array}{ccc}-1&-1&3\\1&-2&-2\end{array}\right]\)
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Please help and answer ASAP please will mark Brainlest
What is the value for x?
Enter your answer in the box.
x =
Answer:
x=45
Step-by-step explanation:
i hope its right good luck :)
i think im wrong
9:X::63:200 show work please thank you!
Answer:
terima kasih atas poin ngratis nya
II. The students in an cighth grade class had a dance They spent $500 for a local band. The equation below can be used to find the total profil, y, if the students sold x tickets to the dance. y = 4x - 500 What does the 4 represent in the equation? A the price per ticket B the cost of the band C. the number of tickets sold D. the prodil made from selling tickets
A data set includes data from student evaluations of courses. The summary statistics are n=85, x=3.42, s=0.56. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternativehypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
What are the null and alternative hypotheses? A.) H0: μ=3.50 H1: μ>3.50 B.) H0: μ≠3.50 H1: μ=3.50 C.) H0: μ=3.50 H1: μ≠3.50 D.) H0: μ=3.50 H1: μ<3.50
Determine the test statistic= ____ (Round to two decimal places as needed.)
Determine the P-value = ____ (Round to three decimal places as needed.)
State the final conclusion that addresses the original claim. ▼ Fail to reject OR Reject H0. There is ▼ sufficient OR not sufficient evidence to conclude that the mean of the population of student course evaluations is equal to 3.50 ▼ is OR not is correct.
- The null hypothesis Is: \($H_0: \mu=4.5$\)
- The alternative hypothesis Is: \($H_1: \mu \neq 4.50$\)
- The test statistic is: t=-0.43
- The p-value of the test is of 0.6684.
What is p-value?
The p-value Is of 0.6684>0.05, which means that we can conclude that the population of student course evaluations has a mean equal to \(\mathbf{4 . 5 0}$.\)
We are going to test If the mean Is equals to 4.50, thus, the null hypothesis Is:
\(H_0: \mu=4.5\)
At the alternative hypothesis, we test If the mean Is different to 4.50, that is:
\(H_1: \mu \neq 4.50\)
Since we have the standard devlation for the sample, the t-distribution is used. The value of the test statistic Is:
\(t=\frac{\pi-\mu}{\frac{\sqrt{n}}{\sqrt{n}}}$$\)
For this problem:
\($$\begin{aligned}& t=\frac{4.30-1.5}{\frac{2.21}{\sqrt[3]{80}}} \\& t=-0.43\end{aligned}$$\)
We are testing If the mean is dlfferent from a value, thus, the p-value of test is found using a two-talled test, wlth t=-0.43 and \($80-1=79 \mathrm{df}$\).
Using a t-distribution calculator, the \($\mathrm{p}$\)-value is of \($\mathbf{0 . 6 6 8 4}$\).
The p-value is of 0.6684 > 0.05, which means that we can conclude that the population of student course evaluations has a mean equal to 4.50.
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