show work please energy units conversion​

Answer:

Lead iodide (II) is an inorganic compound, lead salt and hydrogen acid, with the PbI2 formula.

Answer:

Lithium nitrate

Explanation:

Lithium nitrate is an inorganic compound with the formula LiNO3. It is the lithium salt of nitric acid (an alkali metal nitrate).

Answer:

12 mol

Explanation:

The freezing point of the solution containing 0.867 m glycerin is -1.61442 °C. Option C is correct

The mass of glucose in 505 mL of 10.5% glucose solution is 53.01 g or 5.30 x 10^2 g.

Option C is correct

To find the freezing point depression of the solution containing 0.867 m glycerin:

ΔTf = Kf * molality

ΔTf = (1.86°C/m) * 0.867 m

ΔTf = 1.61442 °C

The freezing point depression is 1.61442 °C.

The freezing point of the solution is:

Freezing point = 0.0 °C - ΔTf

Freezing point = 0.0 °C - 1.61442 °C

Freezing point = -1.61442 °C

To find the mass of glucose in 505 mL of 10.5% glucose solution:

Mass of glucose = Volume of solution * Density of solution * % mass

Mass of glucose = 505 mL * 1.04 g/mL * 10.5%

Mass of glucose = 53.01 g

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Answer:

40.27% Bromide in the original sample

Explanation:

The reaction of bromide ion, Br- with Pb(NO3)2 is:

2 Br- + Pb(NO3)2 → PbBr2(s)

Where the precipitate produced is PbBr2

To solve this question we must find the moles of PbBr2 filtered using its mass. Twice these moles we can find the moles of Br- and its mass. Percent bromide is:

Mass Bromide / Mass Sample (0.5014g) *100

Mass PbBr2:

1.7895g - 1.3258g = 0.4637g PbBr2

Moles -Molar mass: 367.01g/mol-

0.4637g PbBr2 * (1mol / 367.01g) =

0.001263 moles PbBr2 * (2mol Br / 1mol PbBr2) = 0.002527 moles Br

Mass Br -Molar mass: 79.904g/mol-

0.002527 moles Br * (79.904g / mol) =

0.2019g Br

Percent Bromide:

0.2019g Br / 0.5014g * 100 =

Answer:

Idon't know if this helps but I think it is a linear structure and if I am wrong I am so sorry

Answer:

2Na2O2+2H2O⟶O2+4NaOH

2×78g                           32g

156g of Na2O2 produces 32g of O2,

12g of Na2O2 produces =15632×12=10.66g.

Density of O2 at NTP=1.428g/mL.

DensityMass=Vol.

1.42810.66=7.46mL

Vol. of O2 at NTP is 7.46mL.

Explanation:

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To prepare 12 capsules each containing 80 mg of morphine sulfate and 3.2 mg of naltrexone hydrochloride, the following calculations can be used:

Calculate the total weight of the morphine sulfate and naltrexone hydrochloride: 80 mg + 3.2 mg = 83.2 mg

Calculate the weight of the diluent required: 12 capsules * 83.2 mg/capsule = 999.6 mg

Calculate the volume of the diluent required based on its density (assume a density of 0.9 g/mL for lactose): 999.6 mg / (0.9 g/mL) = 1.11 mL

Calculate the weight of the diluent required based on its volume: 1.11 mL * 0.9 g/mL = 1 g

Calculate the amount of the diluent required based on the sensitivity of the prescription balance: 1 g / (6 mg/g) = 166.7 mg

The amount of the diluent required according to this calculation is 166.7 mg. This amount should be rounded up to the nearest whole number (167 mg) to account for the 4% error tolerance. The final aliquot would therefore contain 167 mg of lactose, 80 mg of morphine sulfate, and 3.2 mg of naltrexone hydrochloride.

Answer:

True

Explanation:

Weather is short term, climate is over the long term

Answer:

true, different weather patterns are found all around the world at different times, there could be a hurricane in the gulf of mexico and as a result of the storm tornadoes could break out in texas

Explanation:

Aspirin is an uncharged acid with a pKa of 3.5. If aspirin is placed into a body fluid with a pH of 4.0, at equilibrium approximately what fraction will be in the ionized form is   : 76 %

At equilibrium, the fraction of aspirin in the ionized form can be determined using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

Where pH is the pH of the solution, pKa is the acid dissociation constant of aspirin, [A-] is the concentration of the ionized form of aspirin, and [HA] is the concentration of the un-ionized form of aspirin.

Rearranging the equation to solve for [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

Plugging in the values for pH and pKa:

[A-]/[HA] = 10^(4.0 - 3.5) = 10^0.5 = 3.16

Therefore, the fraction of aspirin in the ionized form is 3.16/(3.16 + 1) = 0.76 or 76%.

So, the correct answer is 76%.

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Answer:

...

Explanation:

Answer: The crust and the upper layer of the mantle together make up a zone of rigid, brittle rock called the Lithosphere . The layer below the rigid lithosphere is a zone of asphalt-like consistancy called the Asthenosphere . The asthenosphere is the part of the mantle that flows and moves the plates of the Earth.

Explanation:

Acetylene is made from ethane by the following synthetic process:

Reagent 1: Photobromination, Br2, and hv.

Reagent 2: Dehydrobromination using (CH3)3COK+.

Reagent 3: Bromination (Br2).

NaNH2, Elimination is Reagent 4.

What is the route for synthesis?

A synthetic pathway is the method utilised to produce a specific good. In order to study the precise components from which the desired product might be formed, chemists may need to be able to look backward.

(1) To convert ethane to bromoethane, Br2, h, and photobromination are needed as reagents.

(2) To convert bromoethane to ethene, the second necessary reagent is (CH3)3COK+, dehydrobromination.

(3) Ethene to 1,2-dibromoethane requires the following reagent:

Bromination, Br2.

(4) To convert 1,2-dibromoethane to ethyne, reagent 4 is needed.

NaNH2, eradication

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The complete question is :

Construct a multistep synthetic route for the synthesis of acetylene from ethane by identifying the reagents and products of each step. Note that each bin will hold only one item, and not every given reagent or structure will be used. (Stoichiometry is omitted.)

1. reagent 1  H3C—CH3

2. reagent 2 H-C=C—H(ethane) (acetylene)

3. reagent 3

4. reagent 4

Ions are atoms or molecules that have an unequal number of protons and electrons, resulting in a net electrical charge. When ions come into close proximity to each other, they can be attracted to or repelled by each other due to electrostatic forces.

There are two main types of electrostatic forces that can hold ions together:

1. Ionic bonds: These are electrostatic forces of attraction between positively charged metal ions and negatively charged non-metal ions. This type of bond typically forms between metal and non-metal ions that have a large difference in electronegativity, resulting in a transfer of electrons from the metal atom to the non-metal atom. The resulting oppositely charged ions are then held together by strong electrostatic forces, forming a stable ionic compound.

2. Electrostatic attraction between oppositely charged ions: This type of electrostatic attraction can occur between any two ions that have opposite charges, regardless of whether they are metals or non-metals. For example, when a positive ion (cation) and a negative ion (anion) are brought close together, they can be attracted to each other by electrostatic forces. The strength of the attraction depends on the charges of the ions and the distance between them.

Overall, the forces that hold ions together are typically electrostatic in nature and are a result of the attraction between opposite charges.

Answer:

ocean

Explanation:

Answer:

The main natural carbon sinks are plants, the ocean soul plants grab carbon dioxide from the atmosphere to use in photosynthesis; some of this carbon Is transferred to soil as plants die and decompose

Water reacts with the combustible substances forming more fire and flashes. That is why sodium require a class D fire extinguisher instead of spray water.

Combustible metal fires, such as those involving aluminum, titanium, magnesium, sodium, and potassium, are classified as class D fires. These kinds of fires frequently happen in industrial, manufacturing, or laboratory environments.

When metal fines, thin metal particles, frequently produce dust during the machining process ignite and become the fuel element in the fire triangle. Class D flames are difficult to extinguish and can result in substantial damage.

A Class D fire extinguisher must always be used to put out a flammable metal fire. Smothering the fires and removing the oxygen source is the most effective approach to put out these fires. The agent also aids in absorbing the fuel's heat. Hence, option D is correct.

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Answer:

f = 8×10¹⁴ s

Explanation:

λ × f = c ⇒ f = c/λ

(c = speed of light [3×10⁸ m/s])

(λ = wavelength)

1. Convert 375 nm to meters in order to multiply by speed of light unit (m/s)

375 nm × \(\frac{1 meter}{10 ^{9} nm}\) = 3.75 × 10⁻⁷ m

2. Plug in converted wavelength to top equation

f = (3×10⁸ m/s)/(3.75 × 10⁻⁷ m)

f = 8×10¹⁴ s

Answer

If the electronegativity difference between bounding atoms is less than 1.7 then the bond has a more covalent character. The electronegativity difference between Al and Cl is 1.55. Hence, the aluminium chloride in the solid-state will has a significant covalent character

Explanation

There are 3 ways by which aluminium chloride in the solid-state has significant covalent character that can be explained:

It can be explained in terms of ionization energy, Fajan rule, and electronegativity difference.

Al has very high ionization energy and for Cl, it's not easy to withdraw 3 electrons from Al’s outermost shell because Cl is not enough electronegative. Therefore, rather than Al losing 3 electrons, it shares its electrons with 3 Cl⁻ ions, and when electrons are shared with 2 atoms; a covalent bond is formed.

Fajan’s rule:- According to Fajan’s rule , the larger the size of an anion; the more covalent will be the bond. So, if we take for example AlCl3 and AlF3, here F⁻ ion is smaller than the Cl⁻ ion, also F has enough electronegative to withdraw Al outermost electrons and therefore AlF3 is ionic but AlCl3 is covalent

Lastly, if the electronegativity difference between bounding atoms is less than 1.7 then the bond has a more covalent character. The electronegativity difference between Al and Cl is 1.55. Hence, the aluminium chloride in the solid-state will has a significant covalent character

The Correct Option is :

One grey sphere, Four white spheres, and One red spheres.

For the pair of compounds CH 3 CH 2 CH 2 OH or CH 3 OH the one with the higher vapor pressure at a given temperature is?

Vapor pressure is always going to be inversely proportional to the boiling point. The low the boiling point, compound will have the higher vapor pressure.  

1. CH₃OH exhibits the  low boiling point in comparison to CH₃CH₂CH₂OH that exhibits the high boiling point. So, CH₃OH has high vapor pressure.

2. CH₃OH is polar and it  exhibits high boiling point because of hydrogen bonds, in comparison H₂CO exhibits low boiling point and has no hydrogen bonds. So, H₂CO has high vapor pressure.

3. CH₄ is non-polar solvent and exhibits less boiling point in comparison to that of CH₃Cl, which is polar and exhibits high boiling point. So, CH₄ has high vapor pressure.  

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The species that are responsible for the peaks near the wavelength are allura red and tartrazine.

It should be noted that wavelength simply means the distance between the identical points in the adjacent cycles of a waveform.

In this case, the chemical species is responsible for the peaks near each wavelengths include allura red and tartrazine.

It should be noted that allura red is used as a food dye and supplied as red sodium salt. Also, tartrazine is used as a food coloring agent.

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kAnswer:

Explanation:

Answer:

A

Explanation:

jsgsnsbnss care about explaimi

\(\\ \sf\bull\longmapsto \lambda=\dfrac{c}{v}\)

\(\\ \sf\bull\longmapsto v=\dfrac{c}{\lambda}\)

\(\\ \sf\bull\longmapsto v=\dfrac{3\times 10^8}{685\times 10^{-9}m}\)

\(\\ \sf\bull\longmapsto v=0.00437\times 10^{17}Hz\)

\(\\ \sf\bull\longmapsto v=4.3\times 10^{14}Hz\)

We need 1 mole of Ca(OH)2 for every 2 moles of HCl since Ca(OH)2 is a need for every 2 moles of HCl. Because HCl is in excess and Ca(OH)2 is the limiting reactant in this reaction, 2.0 moles of H2O should theoretically be created.

The stoichiometric coefficients can be used to calculate the excess reagent. Calcium hydroxide and HCl have stoichiometric coefficients of 1 and 2, respectively. Thus, HCl is the reaction's limiting reagent.

The redox reaction Ca+2H2OCa(OH)2+H2 is an illustration of this.

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To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.

Given:

Mass of Bal2 = 413 g

Volume of solution = 750 ml = 0.75 L

1. Calculate the number of moles of Bal2:

First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):

Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)

Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)

Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol

Molar mass of Bal2 = 264.61 g/mol

Now we can calculate the number of moles of Bal2:

Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2

Moles of Bal2 = 413 g / 264.61 g/mol

Moles of Bal2 ≈ 1.561 mol

2. Calculate the molarity of the solution:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity (M) = 1.561 mol / 0.75 L

Molarity (M) ≈ 2.081 M

Therefore, the molarity of the solution is approximately 2.081 M.

The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.

The molar mass of BaI₂ is:

Ba (barium) atomic mass = 137.33 g/mol

I (iodine) atomic mass = 126.90 g/mol

Molar mass of  BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)

= 137.33 + 2 × 126.90

= 137.33 + 253.80

= 391.13 g/mol

Given that the mass of BaI₂ is 413 g,

Number of moles = Mass / Molar mass

= 413 g / 391.13 g/mol

= 1.056 moles

Volume of solution = 750 ml = 750/1000 = 0.75 L

Finally, one can calculate the molarity of the solution using the formula:

Molarity = Number of moles / Volume of solution

= 1.056 moles / 0.75 L

= 1.408 M

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Answer:

Chlorine tetrachloromethane

Explanation:

Answer:The name of this compound is carbonic acid.

Explanation:

Answer: 15%

Explanation:

We must first calculate the z-score. The z-score is calculated using the following procedures:

Z = (x - ) / Z, where x is the value, we are interested in (3 in this example), and is the distribution's mean, which is taken to be 0 for the conventional normal distribution.

This equation gives us the result: z = (3 - 0) / 1 = 3.

A standard normal table may then be used to calculate the percentage of beverages that require more time to prepare than three minutes. As can be seen in the table, the area to the right of z = 3 is approximately 0.00131. Therefore, 0.13% of drinks will require more time to make than 3 minutes.

The standard score, also known as the observed value or data point, is the departure from or excess over the raw score for an item, reported in standard deviations. Standard scores are good for raw scores that are both higher and lower than the mean.

It may be determined by taking the supplied raw score and removing the population mean from it, then dividing the result by the population standard deviation. The act of converting a raw score into a standard score is known as standardization, but "normalizing" can refer to a variety of other ratio types; see normalization for more information.

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Answer:

To find the mass of the solute in the solution, we first need to convert the percent to a decimal by dividing by 100. Since the percent is 4%, we can divide by 100 to get 0.04.

Next, we can multiply the decimal value by the total mass of the solute to find the mass of the solute in the solution. In this case, the total mass of the solute is 200g, so we can multiply 0.04 by 200g to get:

0.04 * 200g = 8g

Therefore, the mass of the solute in the solution is 8g.

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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Answer:

sulfate

Explanation:

because it is anions