The correct answer is we cannot say for sure whether this scenario represents an elastic or inelastic collision.
The conservation equations for a collision are:
- Conservation of momentum: m1v1,i + m2v2,i = m1v1,f + m2v2,f
- Conservation of energy: 1/2m1v1,i^2 + 1/2m2v2,i^2 = 1/2m1v1,f^2 + 1/2m2v2,f^2
If we substitute v1.f = V1,i and V2.f = V2.i into these equations, we get:
- Conservation of momentum: m1v1,i + m2v2,i = m1V1,i + m2V2,i
- Conservation of energy: 1/2m1v1,i^2 + 1/2m2v2,i^2 = 1/2m1V1,i^2 + 1/2m2V2,i^2
We can see that these equations are satisfied, which means that momentum and energy are conserved in this scenario.
However, this is not a solution to an elastic collision problem because in an elastic collision, kinetic energy is conserved.
In this case, we cannot determine whether kinetic energy is conserved or not because we don't have enough information about the collision.
Therefore, we cannot say for sure whether this scenario represents an elastic or inelastic collision.
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It is diffult to measure the volume of gas.Why?
Answer:
The volume of a gas is dependent on pressure and temperature.
Explanation:
Pressure and temperature affect different gases differently giving varied conclusions to the exact volume of that gas.
:-befrank
A 12 kg block is released from the top of an incline that is 5.0 m long and makes an angle of 40.0 degrees to the horizontal. A force of friction of 60.0 N impedes the motion of the box.
1. Find the acceleration of the box.
2. How long will it take the box to reach the bottom of the incline?
3. What is the coefficient of friction?
First we make a representation of the situation by building a free body diagram as attached in the figure.
We write the sum of forces on the axis of motion as:
\(P_x -fr = ma\\a = \dfrac{P_x-fr}{m}\\a = \dfrac{mg\sin \theta -fr}{m}\\\\a = \dfrac{(12\;kg)(9.8\;m/s^2)\sin 40^\circ -60N}{12\;kg}\\\\a\approx1.3 \;m/s^2\)
b) We know from cinematic that:
d = at²/2
Solving for t:
\(t = \sqrt{\dfrac{2d}{a}} =\sqrt{\dfrac{2(5\;m)}{1.3\;m/s^2}} = 2.8\;s\)
c) We write the sum of forces on the y axis as:
N - Py = 0
N = Py
N = mgcosθ
fr = μN
Solving for μ:
μ = fr/N
\(\mu = \dfrac{fr}{mg\cos\theta} = \dfrac{60\;N}{(12\;kg)(9.8\;m/s^2)\cos40^\circ} =0.67\)
1. The acceleration of the box is 1.3 m/s^2.
2. The time taken for reaching the bottom of the incline is 2.8 seconds.
3. The coefficient of friction is 0.67.
Calculation of the acceleration, time taken, and the coefficient of friction:
1.
We know that
Px - fr = ma
a = (px - fr)/m
a = (mg sin - fr)/m
= (12) (9.8) sin 0 - 60 N / 12 kg
= 1.3 m/s^2
2. The time taken should be
= √2d/a
= √295) / 1.3
= 2.8 seconds
c. The coefficient of friction should be
N - Py = 0
N = Py
μ = fr/mgcos
= 60N / (12kg) (9.8) (cos 40)
= 0.67
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Five loops are formed of copper wire of the same gauge (cross-sectional area). Loops 1-4 are identical; Loop 5 has the same height as others but is longer. At the instant shown, all the loops are moving at the same speed in the directions indicated.There is a uniform magnetic field pointing out of the page in region I; in Region II there is no magnetic field. Ignore any interactions between the loops.A) For any loop that has an induced current, indicate the direction of the current.B) Rank the magnitude of the emfs around the loops. Explain your reasoning.C) Rank the magnitudes of the currents in the loops. Explain your reasoning.
E1=E4>E5>E2=E3 is the correct order of magnitudes induced in the loop. Region I has a magnetic field that is neither uniform nor steady and points out of the page. Disregard any communication between loops.
What in physics are magnitudes?In terms of physics, magnitude is just "distance or quantity." In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope .In physics, the term "magnitude" often refers to a size or amount.
What is an example of magnitude?The definition of magnitude is "how much of a quantity." The magnitude, for instance, can be utilized to explain the contrast between the speeds of a car and a bicycle.
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HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer
C. 0 N
F=ma=0.5(0)=0 N
Answer:
c
Explanation:
hope it helps
what is the radius of the event horizon for a black hole with a mass of 7.0 times the mass of the sun
Light from an infinite distance way hits a convex lens. Where will the image form?
A.An infinite distance away
B.At the focal point of the lens
C.No image will form
D.Halfway between the focal point and the lens
If light from an infinite distance away hits a convex lens, the image will form at the focal point of the lens. So, the answer is B.
This is because when the object is at an infinite distance, the incoming light rays are parallel to each other. When these parallel rays pass through the convex lens, they converge to a point, which is the focal point of the lens.
Since the light rays converge at the focal point after passing through the lens, the image of the object will be formed at the focal point as well. Therefore, the correct option is B: at the focal point of the lens.
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When an ionic compound dissolves like salt, what breaks apart from each other in the water?
Answer:
When ionic compounds dissolve in water, they break apart into the ions that make them up through a process called dissociation. When placed in water, the ions are attracted to the water molecules, each of which carries a polar charge. ... The ionic solution turns into an electrolyte, meaning it can conduct electricity.
The bonds that is present between atoms of ionic compounds break apart when it is dissolved in water.
What happen when ionic compound dissolve in water?When ionic compounds dissolve in water, the ions in the solid separate in the solution because water molecules has polar nature which attracts that ions. The hydrogen of water molecule attracts chlorine of ionic compound whereas hydroxle ion attracts sodium of ionic compound.
So we can conclude that the bonds that is present between atoms of ionic compounds break apart when it is dissolved in water.
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A 3-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 75 m tall.
Circle one: KE / GPE / both
Show your work for finding the values of each type of energy the object has:
The potential energy and kinetic energy of the bowling ball are 2,205 J and 37.5 J respectively.
What is the gravitational potential energy of the bowling ball?The bowling ball at the given position and speed possess gravitational potential energy and kinetic energy.
The potential energy and kinetic energy of the bowling ball is calculated as follows;
P.E = mgh
where;
m is the mass of the objecth is the heightg is acceleration due to gravityP.E = (3 x 9.8 x 75 )
P.E = 2,205 J
The kinetic energy of the bowling ball is calculated as;
K.E = ¹/₂ mv²
where;
v is the speed of the bowling ballK.E = ¹/₂ ( 3 ) x (5²)
K.E = 37.5 J
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EASY QUESTIONS! DUE IN 15 MIN WILL MARK BRAINLIEST.
1. What is the sum of a vector 8 m south and a vector 12 m north? *
2. What is the sum of a vector 12 m north and a vector 8 m north? *
PLEASE SHOW WORK AND EXPLAIN
Explanation:
As they are in same direction, you can add them directly. And result is 12 + 8 m = 20 m North. If you use vector addition: Vectors = 12m & 8 m & angle b/w them is 0°(as both are in same direction).
A car starting from rest accelerates in a straight line path at a constant rate of 2.5m/s².how far will it travel in 12 seconds
The car will travel a distance of 180 meters in 12 seconds.
To determine the distance traveled by the car, we can use the equation of motion:
Distance (d) = Initial velocity (v₀) × time (t) + 0.5 × acceleration (a) × time squared (t²)
Given:
Initial velocity (v₀) = 0 m/s (starting from rest)
Acceleration (a) = 2.5 m/s²
Time (t) = 12 seconds
Plugging in the values into the equation:
Distance (d) = 0 × 12 + 0.5 × 2.5 × 12²
Distance (d) = 0 + 0.5 × 2.5 × 144
Distance (d) = 0 + 0.5 × 2.5 × 144
Distance (d) = 180 meters
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when the sunlight strikes the side of a building what form of energy is it transformed to
Answer:
When sunlight strikes a solar panel what form of energy is transformed to?
Solar radiation may be converted directly into electricity by solar cells (photovoltaic cells). In such cells, a small electric voltage is generated when light strikes the junction between a metal and a semiconductor (such as silicon) or the junction between two different semiconductors.
Explanation:
Madison applied a force of 150 N in a horizontal direction to a sleigh. Meanwhile the sleigh slid 30.0 m across a level surface of snow. The work done on the sleigh by Madison is _________ J.
Answer:
4500 joules
Explanation:
since work(joules) = force(newtons) x distance(meters),
150N x 30M = 4500 Joules
Answer:
4500 joules
Explanation:
150 N x 30 M = 4500 joules
Children on the autism spectrum are at risk for nutritional deficiencies because?
Explanation: Research highlights the individuals with ASDS are nutritionally vulnerable because they exhibit a selective or pick eating pattern and sensory sensitivity that predisposes them to restricted intakes.
I hope this helps!
Identify the necessary factors to turn collective action into a social movement. Necessary Factor(s) a ritualized patterns of behavior Press Space to open a common social or political purpose Press Space to open a violation of social norms Press Space to open an institutionalized organization
The necessary factors to turn collective action into a social movement include:
A common social or political purpose: A social movement typically arises when a group of individuals come together with a shared goal or cause. They identify a social or political issue that they believe needs to be addressed or changed.
Violation of social norms: Social movements often emerge in response to perceived injustices or violations of existing social norms. These violations can be related to issues such as inequality, discrimination, or injustice. The recognition of such violations can mobilize individuals to take collective action.
Institutionalized organization: To sustain and effectively mobilize a social movement, it often requires an institutionalized organization. This can be in the form of formal structures, such as organizations, groups, or networks, that provide the necessary coordination, leadership, and resources for the movement's activities.
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a virtual image is formed 20.5 cm from a concave mirror having a radius of curvature of 41.5 cm. (a) find the position of the object. cm in front of the mirror (b) what is the magnification of the mirror?
The magnification of the mirror after calculations is 0.99.
We can use the mirror formula and magnification formula to solve this problem:
1/f =\(1/d_o + 1/d_i\)
magnification = -\(d_i/d_o\)
where f is the focal length of the mirror, \(d_o\) is the distance of the object from the mirror, and \(d_i\) is the distance of the image from the mirror.
(a) To find the position of the object, we can rearrange the mirror formula:
\(1/d_o = 1/f - 1/d_i\)
Substituting the given values, we get:
\(1/d_o\) = 1/(-41.5 cm/2) - 1/20.5 cm
Simplifying, we get:
\(1/d_o\) = -0.0482 cm^-1
Therefore:
\(d_o\) = -20.7 cm
Note that the negative sign indicates that the object is located in front of the mirror.
Therefore, the object is located 20.7 cm in front of the mirror.
(b) To find the magnification, we can use the magnification formula:
magnification = -\(d_i/d_o\)
Substituting the calculated values, we get:
magnification = -20.5 cm / (-20.7 cm)
Simplifying, we get:
magnification = 0.99
Therefore, the magnification of the mirror is 0.99.
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which of the following are fire preventions guidelines
Answer:
there is no list of "the following" you might want to re-upload your question.
a 7,500kg railroad care is traveling at 4m/s when it strikes another 11,000kg railroad car that is at rest. if the cars lock together, what is the final speed of the two railroad cars?
The final speed of the two railroad cars is 1.62 m/s.
This problem can be solved using the conservation of momentum principle, which states that the total momentum of a closed system remains constant if no external forces act on it.
The initial momentum of the system is:
p_initial = m₁v₁ + m₂v₂, where
m₁ = 7,500 kg (mass of the first car)
v₁ = 4 m/s (velocity of the first car)
m₂ = 11,000 kg (mass of the second car, at rest)
v₂ = 0 m/s (velocity of the second car)
p_initial = (7,500 kg)(4 m/s) + (11,000 kg)(0 m/s)
= 30,000 kg×m/s
After the collision, the two cars lock together, so they become a single object with a total mass of:
M = m₁ + m₂ = 7,500 kg + 11,000 kg = 18,500 kg
Let's assume that the final velocity of the combined cars is v. According to the conservation of momentum principle:
p_final = M×v
Since no external forces act on the system, the initial momentum and the final momentum are equal:
p_initial = p_final
30,000 kgm/s = 18,500 kgv
v = 30,000 kg×m/s / 18,500 kg
= 1.62 m/s
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A transverse wave has a wavelength of 15m and a frequency of 10hz, what is the wave's speed?
So, the wave's velocity is 150 m/s.
IntroductionHi ! I will help you to explain the relationship between velocity of a waves with their frequency and wavelengths. In mechanical waves (either transverse or longitudinal) the greater value of wavelength or frequency of a waves, indicating that the wave will transmitted faster. This relationship can also be expressed in this equation:
\( \boxed{\sf{\bold{v = \lambda \times f}}} \)
With the following condition :
v = velocity of mechanical waves (m/s)\( \sf{\lambda} \) = wavelength (m)f = frequency of the waves (Hz)Problem SolvingWe know that :
\( \sf{\lambda} \) = wavelength = 15 mf = frequency of the waves = 10 HzWhat was asked :
v = velocity of mechanical waves = ... m/sStep by step :
\( \sf{v = \lambda \times f} \)
\( \sf{v = 15 \times 10} \)
\( \boxed{\sf{v = 150 \: m/s}} \)
Conclusion :So, the wave's velocity is 150 m/s.
The half life of a radioactive element is 8 hours. A sample of the element is tested and found to contain 6g of the element. How much of the element was present 32 hours before the element was tested? 0.375g 6g 48g 96g
Answer:
m₀ = 96 g
Explanation:
First, we will calculate the no. of half-lives passed:
\(n = \frac{T}{T_{1/2}}\)
where,
n = no. of half-lives passed = ?
T = Total time elapsed = 32 h
\(T_{1/2}\) = Half-Life = 8 h
Therefore,
\(n = \frac{32\ h}{8\ h}\\\\n = 4\)
Now, for the initial amount of element:
\(m = \frac{m_o}{2^n}\\\\m_o = m(2^n)\)
where,
m₀ = initial amount of element = ?
m = current amount of element = 6 g
Therefore,
\(m_o = (6\ g)(2^4)\)
m₀ = (6 g)(16)
m₀ = 96 g
blocks x and y are attached to each other by a light rope and can slide along a horizontal surface. Mass of block x is 10 kg and that of block y is 5 kg. the magnitude of force of friction on blocks x and y is 8.0 N and 4.0N respectively. Find the action-reaction forces that the blocks exert on each other if an applied force of 40 N(right) acts on block per illustration below.
Blocks x and y exerts action-reaction forces on each other with 146.1 N and 53.1 N respectively.
The given parameters:
mass of block x = 10 kg
mass of block y = 5 kg
magnitude of the frictional force of block x = 8 N
magnitude of the frictional force of block y = 4 N
the applied force to the right = 40 N
To find:
the action-reaction forces that the blocks exert on each otherThe block y pulls block x to the left with the following reaction forces;
Force of block y = force due to its own weight + frictional force
Reaction Force of block y = mg + 4 Nwhere;
g is the acceleration due to gravity = 9.81 m/s²
Reaction Force of block y = (5 x 9.81) + 4Reaction Force of block y = 49.1 + 4Reaction Force of block y = 53.1 NThus, block y reacts on block x with a force of 53.1 N
The block x acts on block y towards the right direction with following forces;
Force of block x on y = force due to its own weight + frictional force + applied force to the right
Force of block x on y = (mg) + (8 N) + (40 N)Force of block x on y = (10 x 9.81) + (48)Force of block x on y = 98.1 + 48Force of block x on y = 146.1 NThus, block x acts on block y with a force of 146.1 N
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Light waves that have been emitted or reflected by an object enter the eye and first pass through the transparent layer called the _______, where they are refracted. The light rays are then refracted again as they pass through the transparent _______.
Light rays first pass through the transparent layer called the cornea and then refracted again as they pass through the transparent lens.
How do light rays flow in the eyes?
The first factor in the journey of light via the eye is the objects being seen and how they produce, reflect, or change the light in various ways.
The visual cortex of the brain's occipital lobe serves as the destination of the light pathway, which starts with photoreceptors in the retina. Rod and cone cells are two different types of photoreceptors. When it comes to eyesight in low light and in peripheral vision, rods can be especially helpful.
The cornea is where most of the refraction occurs as light enters the eye's curved, transparent front surface. The natural or crystalline lens of the eye also distorts light rays. When an item passes in front of the eye, its rays pass through the transparent cornea and enter the eye.
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PLEASSSSSEE! PLEASE ANSWER!!! I AM DESPERATE AND THIS IS EXTEMELY URGENT! I NEED AN ANSWER ASAPPP!!!!
Answer:
most potential is someone in an airplane. second is position A, third is position c, fourth is position D, fifth is position B and least potential is a person standing on the ground.
Explanation:
hopefully you understand what I wrote
Juanita is riding the school bus. The bus stops as the driver applies the brakes.
Which of these best describes this situation? *
The bus is gaining energy because of friction.
The school bus does not lose or gain kinetic energy.
There is no force acting on the bus, so it stops moving.
A force is changing the motion of the bus.
A force is changing the motion of the bus.
What is Newton's first law of motion?Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that form unless acted upon by an external force.
The applied force on the bus in the form of brakes acts as the external force on the bus.
According to Newton's first law of motion, the external force (brakes) will change the motion of the bus.
Thus, we can conclude that a force is changing the motion of the bus.
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if an incandescent light bulb used for lighting has an efficiency rating of 5 percent, then for every 1.00 joule of electrical energy consumed by the bulb, which of the following is produced?
Answer:
0.05
Explanation:
You should list the choices.
Efficiency = energy used / energy need * 100%
Efficiency = 5%
energy used = ?
energy needed = 1
Formula
Efficiency = energy used/energy needed * 100
100 * efficiency * energy needed = energy used.
Solution
1.00 * 5% = 1.00 * 5/100 = 1.00 * 0.05 = 0.05
Your answer should be something resembling 0.05 Joules
A 57. 0-g tennis ball is traveling straight at a player at 21. 0 m/s. The player volleys the ball straight back at 25. 0 m/s. If the ball remains in contact with the racket for 0. 060 s, what average force acts on the ball?.
According to the given statement is 43.7 N average force acts on the ball.
What is the average force ?The average force is a force applied by an object travelling more than a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or accurately measured, as the word "average" implies.
Briefing:Mass of tennis ball is =57 gm
velocity of ball=21 m/s
At a speed of 25 m/s, the player volleys the ball back (i.e. in opposite of initial direction)
Time of contact=0.06 s
We know change in momentum(ΔP) = Impulse (Fdt)
Initial momentum = 57 * 10⁻³ * 21
Final momentum = -57 * 10⁻³ * 25
Change in momentum
ΔP = 57 * 10⁻³ * 21 - (-57 * 10-3 * 25)
ΔP = 57 * 10⁻³ * 46 = 2.622 kg-m/s
Now 2.622 kg-m/s = F\(_a_v_g\) * 0.06
F\(_a_v_g\) = 43.7 N
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How does the fundamental frequency in the input voltage relate to its switching frequency?
The fundamental frequency in the input voltage refers to the lowest frequency component present in the voltage waveform. It is usually associated with the power line frequency, such as 50 or 60 Hz in most countries.
The switching frequency, on the other hand, is the frequency at which a power electronic device, like an inverter or a switch-mode power supply, switches on and off. It is typically much higher than the fundamental frequency, often in the range of several kilohertz to megahertz.
The relationship between the fundamental frequency and the switching frequency depends on the specific application and the design of the power electronic system. In some cases, the switching frequency can be a harmonic or multiple of the fundamental frequency. For example, in a pulse-width modulation (PWM) scheme, the switching frequency may be a multiple of the fundamental frequency.
In other cases, the switching frequency may be unrelated to the fundamental frequency. For instance, in certain high-frequency applications, the switching frequency may be much higher than the fundamental frequency, enabling more efficient power conversion and reduced size of passive components.
Overall, the fundamental frequency and the switching frequency are separate entities that can have different values and purposes in a power electronic system.
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a very very long wire with current 2 a is straight except for a circular loop of radius 0.05 m (see image). what is the magnetic field at the center of the loop? t unanswered what is the direction of the magnetic field at the center of the loop?
The magnetic field at the center of the circular loop is approximately 8π x \(10^_-6\) Tesla. The direction of the magnetic field is perpendicular to the plane of the loop, pointing out of the page or screen.
To find the magnetic field at the center of the circular loop, we can use Ampere's law. Ampere's law states that the magnetic field around a closed loop is proportional to the current passing through the loop.
The equation for the magnetic field at the center of a circular loop is given by:
B = (μ₀ * I) / (2 * R)
where B is the magnetic field, μ₀ is the permeability of free space (4π x\(10^_-7\) Tm/A), I is the current passing through the loop, and R is the radius of the loop.
In this case, the current passing through the loop is 2 A, and the radius of the loop is 0.05 m.
Substituting the values into the equation, we have:
B = (4π x \(10^_-7\)Tm/A) * (2 A) / (2 * 0.05 m)
B = (4\pi * \(10^{-7}\)Tm/A) * (2 A) / (2 * 0.05 m)
Simplifying the equation, we get:
B = (4π x \(10^_-7\) Tm/A) * 40 A/m
B = 8π x \(10^_-6\) T
Therefore, the magnetic field at the center of the circular loop is approximately 8π x \(10^_-6\) Tesla.
Now, let's move on to the direction of the magnetic field at the center of the loop. Using the right-hand rule, we can determine that the magnetic field will be pointing perpendicular to the plane of the loop.
In other words, it will be pointing out of the page or screen if you imagine the loop in a two-dimensional representation.
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2. What do developmental psychologists study?
Answer: Developmental psychologists study human growth and development over the lifespan, including physical, cognitive, social, intellectual, perceptual, personality and emotional growth.
Explanation:
Help me please in the Next Question i will give all points to the first to arive 500 on the line
Answer: Newton's third law of motion is naturally applied to collisions between two objects. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction.
Explanation: So it is #2
A car of mass 1700kg moves in a straight line along a slope that is at an angle θ to the
horizontal, as shown in Fig. 3.1.
The car moves at constant velocity for a distance of 25m from point A to point B.
Air resistance and friction provide a total resistive force of 440N that opposes the motion of the car.
For the movement of the car from A to B:
(i) state the change in the kinetic energy.
[How do you find the change in kinetic energy?..]
The change in the kinetic energy is (22000 + 416500sinθ) J
Net force on carThe net force on the car F' = F - f - N where
F = force due to car, f = total resistive force = 440 N and N = horizontal component of weight of car = mgsinФ where m = mass of car = 1700 kg, g = acceleration due to gravity = 9.8 m/s² and θ = angle of slopeSo, F' = F - f - N
F' = F - f - mgsinθ
Since the car moves at constant velocity, the net force F' = 0
So, F' = F - f - mgsinθ
F - f - mgsinθ = 0
F = f + mgsinθ
Work-kinetic energy theorem
From the work-kinetic energy theorem,
The kinetic energy change of the car ΔK equals the work done by force on car, W
ΔK = W = Fd where
F = force on car and d = distance moved by car = 25 mΔK = Fd
= (f + mgsinθ)d
= fd + mgdsinθ
Change in kinetic energy of car
Substituting the values of the variables into the equation, we have
ΔK = fd + mgdsinθ
= 440 N × 25 m + 1700 kg × 9.8 m/s² × 25 m × sinθ
= 22000 Nm + 416500sinθ Nm
= (22000 + 416500sinθ) J
So, the change in the kinetic energy is (22000 + 416500sinθ) J
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