Answer:
a) = 11.29°
b) = 1.93 m/s²
Explanation:
θ = θ(m) sin(w(n).t + Φ)
w(n) = 2π / t
w(n) = 6.284 / 1.3
w(n) = 4.834 rad/s
θ• = θ(m).w(n).cos (w(n).t + Φ)
θ•(m) = θ(m).w(n)
v(m) = L.θ•(m)
v(m) = L.θ(m).w(n)
θ(m) = v(m) / L.w(n)
For a simple pendulum,
w(n) = √(g / l)
l = g / w(n)²
l = 9.8 / 4.834²
l = 9.8 / 23.368
l = 0.42 m
Remember, θ(m) = v(m) / l.w(n)
θ(m) = 0.4 / (0.42 * 4.834)
θ(m) = 0.4 / 2.03
θ(m) = 0.197 rad
Converting to °, we have
0.197 * 360 * 1/2π
0.197 rad = 11.29°
Thus, the amplitude of the motion is 11.29°
a(t) = l.θ(t)
Tangential acceleration occurs when θ(t) is maximum, so
θ(t) = -θ(m).w(n)².sin(w(n)t + Φ)
θ(t max) = θ(m).w(n)²
a(t max) = l.θ(m).w(n)²
a(t max) = 0.42 * 0.197 * 4.834²
a(t max) = 1.93 m/s²
Explanation:
What should you do with electrical cells and batteries that no longer work
Answer:
Yes, single-use batteries are now made of common metals deemed non-hazardous by the federal government and can be disposed of in your regular trash in all states except California, where it is illegal to throw away all types of batteries.
What tool would you use for Volume
Answer:
Volumetric cylinders and volumetric flasks are used to measure volume of liquids contained in them. They are calibrated for volume included in them - this is indicated by the marking "IN". The liquid has accurate volume when it reaches the corresponding marking on the scale. Volume is usually indicated in mL. Mark me brainliest please
A cyclist and his bicycle have a combined mass of 85 kg. If he is moving at
12 m/s, how much KE does he have?
Your nour
Answer:
211.2 kg:m/s
Explanation:
Mark brainily
Example Compute the capacitance of a parallel-plate capacitor with plates 10cm by 20cm, separation of 5mm, and a mica dielectric.
Answer:
Explanation:
Mica dielectric constant (k) is approximately 3. The distance between the plates is 5 mm = \(5\times10^{-3}\) m = d and the area of each plate is\(A = 0.1\times 0.2=2\times 10^{-2} m^{2}\). So, the capacitance of that capacitor is:
\(C=\frac{\epsilon_{0}kA}{d}=\frac{(8.85\times10^{-12})(3)(2\times10^{-2}}{5\times10^{-3}}=10.62\times10^{-11} =1.062\times10^{-10} F\)
or approximately 0.106 nF.
4. S. crossirostris's wings were made of a delicate flap of skin. If this flap of skin
tore, the animal could not fly. Use this information to explain how
S. crassirostris might have had trouble competing with bird species living during
the Mesozoic era.
Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.
What are the birds?The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.
In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.
Learn more about birds:https://brainly.com/question/13084215
#SPJ1
TRUE OR FALSE
Scientists understand the effects of gravity, but they don't know what causes it.
Answer: false
Explanation:
if a certain car, going with speed v1, rounds a level curve with a radius r1, it is just on the verge of skidding. if its speed is now doubled, the radius of the tightest curve on the same road that it can round without skidding is:
Answer:
The correct answer is 4R1
Explanation:
According to the given scenario ,the radius of the tightest curve on the same road without skidding is as follows:
As we know that
Centeripetal Acceleration is
= v^2 ÷ r
In the case when velocity becomes 2 times so the r would be 4 times
So, the radius of the tightest curve on the same road without skidding is 4R1
an airbubble at the bottom of a lake 90 m deep has a volume of 1.5 cm³. what will be the volume just below the surface if atmospheric pressure is equivalent to a height of 10m of water
The volume of the air bubble just below the surface of the lake would be 0.000015 m³ = 1.5 cm³.
How do we calculate?V₁ = 1.5 cm³
P₁ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
To convert V₁ to m³:
Volume₁ = 1.5 cm³ * (1 m / 100 cm)³ = 0.000015 m³
we then substitute the values into the equation:
Volume ₂ = 0.000015 m³ * (P₂ / (1000 kg/m³ * 9.8 m/s² * 10 m))
Pressure ₂ = ρg(10) = (1000 kg/m³ * 9.8 m/s² * 10 m)
We then substitute the value of P₂ into the equation for Volume 2:
V₂ = 0.000015 m³ * ((1000 kg/m³ * 9.8 m/s² * 10 m) / (1000 kg/m³ * 9.8 m/s² * 10 m))
Volume₂ = 0.000015 m³
Learn more about Volume at:
https://brainly.com/question/27710307
#SPJ1
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
For more such information on: mean
https://brainly.com/question/1136789
#SPJ8
Find the momentum of a 500,000 kg train that is stopped on the tracks?
a. O kg m/s
b. 250,000 kg m/s
c. 500,000 kg m/s
d. 16,000,000 kg m/s
Answer:
The answer should be A) 0m/s
Explanation:
It is stopped on the train tracks therefore it is not moving.
Please tell me if I am wrong because I'm not 100% sure on this. Hope it's right and that it helped you.
Which ones are correct??
Answer:
blanket:thermal conductivity
as it conduct heat.
aquarium glass:transparency
as light can be transfered from one side to
another.
A student graphs power (p) on the vertical axis and time (t) on the horizontal axis. The graph appears to be a hyperbola.
a) What should the student graph on each axis to test whether the relationship is actually
hyperbolic?
b) If the relationship is actually hyperbolic, what is the general equation for the relationship between power and time?
Answer: it would be daddy
Explanation:
Because I’m daddy
how to find half life
Answer: The half-life of a reaction is the time required for the reactant concentration to decrease to one-half its initial value. The half-life of a first-order reaction is a constant that is related to the rate constant for the reaction: t1/2 = 0.693/k.
Explanation:
You submerge 100 grams of steel in 200 grams of water. If the steel has an initial temperature of 90°C and the water has an initial temperature of 15°C, what is the final temperature of the system? The specific heat capacity of the steel is 0.15 cal/g•°C.
Answer:
Q=cmΔT
Q1(steel)=Q2(water)
c1•m1• (t1-t) = c2•m2• (t-t2)
628•0.1•(80-t) = 4180•0.2• (t-10)
5024-62.8t = 836t -8360
5024+8360=(836+62.8)t
t=14.9°C
Explain how the removal of heat energy affects the speed of the particles in a substance
Answer:
The removal of heat energy slows the speed of particles
Explanation:
When you add heat to a substance, the heat energy gets transferred to kinetic energy, and the molecules began to move a greater distance at a greater speed. When you remove heat, the opposite happens.
Please help I’m so desperate I’m giving about all my points
Answer:
1 and 5
Explanation:
potential energy is movement energy, and at 1 and 5 there is a lot of kinetic energy (built up energy) and not a lot of potential energy
Emma draws another diagram showing how adding energy affects this wave. How does her new diagram compare to this diagram?
A
Her diagram shows higher wavelengths.
B
Her diagram shows lower wave amplitudes.
С
Her diagram shows lower wave frequencies.
D
Her diagram shows higher wave amplitudes.
HELPPPP MEEE PLEASEEEE 55 POINTS!!!
Model rocket engines are sized by thrust, thrust duration, and total impulse, among other characteristics. A size C5 model rocket engine has an average thrust of 5.26 N, a fuel mass of 12.7 g, and an initial mass of 25.5 g. The duration of its burn is 1.90 s. If this engine is placed in a rocket body of mass 54.5 g, and if the rocket is fired in outer space, what is the final velocity of the rocket
Answer:
v_{f} = 115.95 m / s
Explanation:
This is an exercise of a variable mass system, let's form a system formed by the masses of the rocket, the mass of the engines and the masses of the injected gases, in this case the system has a constant mass and can be solved using the conservation the amount of movement. Which can be described by the expressions
Thrust = \(v_{e} \frac{dM}{dt}\)
\(v_{f}\)-v₀ = v_{e} \(ln ( \frac{M_{o} }{M_{f}} )\)
where v_{e} is the velocity of the gases relative to the rocket
let's apply these expressions to our case
the initial mass is the mass of the engines plus the mass of the fuel plus the kill of the rocket, let's work the system in SI units
M₀ = 25.5 +12.7 + 54.5 = 92.7 g = 0.0927 kg
The final mass is the mass of the engines + the mass of the rocket
M_{f} = 25.5 +54.5 = 80 g = 0.080 kg
thrust and duration of ignition are given
thrust = 5.26 N
t = 1.90 s
Let's start by calculating the velocity of the gases relative to the rocket, where we assume that the rate of consumption is linear
thrust = v_{e} \(\frac{M_{f} - M_{o} }{t_{f} - t_{o} }\)
v_{e} = thrust \(\frac{\Delta t}{\Delta M}\)
v_{e} = 5.26 \(\frac{1.90}{0.080 -0.0927}\)
v_{e} = - 786.93 m / s
the negative sign indicates that the direction of the gases is opposite to the direction of the rocket
now we look for the final speed of the rocket, which as part of rest its initial speed is zero
v_{f}-0 = v_{e} \(ln ( \frac{M_{o} }{M_{f} } )\)
we calculate
v_{f} = 786.93 ln (0.0927 / 0.080)
v_{f} = 115.95 m / s
Fill in the magnitude of net force for each case. Including the solution plss
Net forces in all above cases will be
A) F net = 0
B) F net = 1 N
C) F net = 5 N
D) F net = 5N
E) F net = 5 N
F) F net = 5 N
G) F net = 9.9 N
H) F net = 9.9 N
A) net force = upward force - downward force
= 4 - 4 = 0
B) net force = rightward force - leftward force = 4 - 3 = 1 N
C) net force
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N
D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N
E) balancing horizontal forces
rightward force - leftward force = 5 - 2 = 3 N
using Pythagoras theorem
F net = \(\sqrt{4^{2} + 3^{2} }\) = 5 N
F) balancing vertical forces
-5 + 2 = -3 N
using Pythagoras theorem
\(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N
G) using Pythagoras theorem
F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
H ) balancing horizontal forces
10 - 3 = 7 N
\(\sqrt{7^{2} + 7^{2} }\) = 9.9 N
To learn more about net force here :
https://brainly.com/question/18109210
#SPJ1
The mass of the basketball shown below is 4 times the mass of the baseball.
Basketball
Baseball
If the two balls are moving at the same speed, and the basketball and the baseball has a kinetic
energy of 10.0 J, what is the kinetic energy of the basketball?
2.5 J
5.03
10.03
20.0 J
Answer:
40.0 Joules. None of the answers is correctExplanation:
Kinetic energy of an object is expressed as;
KE = 1/2mv² where;
m is the mass of the object
V is the velocity of the object.
Let Ma be the mass of the basketball and Mb be the mass of baseball.
If the mass of the basketball shown below is 4 times the mass of the baseball, then Ma = 4Mb
KE of the basket ball = 1/2MaVa²
Va² = 2(KE)a/Ma ...... 1
KE of the baseball = 1/2MbVb²
Vb² = 2(KE)b/Mb .......... 2
Since their velocities are the same, hence Va²= Vb²
2(KE)a/Ma = 2(KE)b/Mb
Substituting Ma = 4Mb into the resulting expression.
2(KE)a/4Mb = 2(KE)b/Mb
2(KE)a/4 = 2(KE)b
Given Kinetic energy of baseball (KE)b = 10.0J, the expression becomes;
2(KE)a/4 = 2(10)
2(KE)a = 4*20
2(KE)a = 80
(KE)a = 80/2
(KE)a = 40.0J
Hence the kinetic energy of the basketball is 40.0Joules
A motor vehicle has a mass of 1.8 tonnes and its wheelbase is 3 m. The centre of gravity of the vehicle is situated in the central plane 0.9 m above the ground and 1.7 m behind the front axle. When moving on the level at 90 km/h the brakes applied and it comes to a rest in a distance of 50 m.
Calculate the normal reactions at the front and rear wheels during the braking period and the least coefficient of friction required between the tyres and the road. (Assume g = 10 m/s2)
Answer:
normal reaction, front: 11,175 Nnormal reaction, rear: 6,825 Nminimum coefficient of friction: 0.625Explanation:
The speed in meters per second is ...
(90 km/h)(1000 m/km)(1 h/(3600 s)) = 25 m/s
The braking acceleration can be found from ...
a = v²/(2d) = (25 m/s)²/(2×50 m) = 6.25 m/s²
Then the braking force is ...
F = Ma = (1800 kg)(6.25 m/s²) = 11,250 N
The torque on the center of gravity is ...
T = (11,250 N)(0.90 m) = 10,125 N·m
__
If we let x and y represent the normal forces on the front and rear wheels, respectively, then we have ...
x + y = (10 m/s²)(1800 kg) = 18000 . . . . . newtons
1.7x -1.3y = 10,125 . . . . . . . . . . . . . . . . . . . newton-meters
The latter equation balances the torque due to the wheel normal forces with the torque due to braking forces.
Multiplying the first equation by 1.3 and adding that to the second, we have ...
3.0x = (1.3)(18,000) + 10,125
x = 33,525/3 = 11,175 . . . . . . . . . . . newtons normal force on front tyres
y = 18000 -11175 = 6,825 . . . . . . . .newtons normal force on back tyres
The least coefficient of friction is the ratio of horizontal to vertical acceleration, 6.25/10 = 0.625.
An engine develops a power of 750watts while moving a car at constant velocity 3m/s therefore the work exerted on the car by the engine is. And please I need the solution
The work exerted on the car by the engine is 250 Joules.
What is Work?
Work is a physical quantity that is defined as the force applied to an object over a distance. It is a scalar quantity and is measured in units of joules (J) in the International System of Units (SI). The formula for work is W = F x d, where F is the force applied and d is the distance over which the force is applied.
The work exerted on the car by the engine can be calculated using the formula:
Work = Power x Time
Since the car is moving at a constant velocity, we can calculate the time it takes for the engine to exert the given power by using the formula:
Velocity = Work / Time
So, we can find time by using:
Time = Work / Velocity
Substituting the given values, we have:
Time = (750 watts) / (3m/s)
Therefore, the work exerted on the car by the engine is:
Work = Power x Time
Work = 750 watts x (750 watts / 3m/s)
Work = 750 * 250 Joules
So, the work exerted on the car by the engine is 250 Joules.
To learn more about work from the given link:
https://brainly.com/question/25573309
#SPJ1
7 , 1 , 5 , 3 , multiple choice quiz is on apex
From the histogram given, there were at approximately 7 downloads between 3pm and 4pm . This can be derived by counting the rows in that time period.
What is a histogram?A histogram is a graph that depicts the frequency distribution of a few data points from a single variable.
Histograms frequently divide data into "bins" or "range groups" and count the number of data points that belong to each of those bins.
Histograms are frequently used to depict the key properties of data distribution in a handy format. It is especially beneficial when working with huge data sets (more than 100 observations). It can aid in the detection of uncommon observations (outliers) or gaps in the data.2
Learn more about histogram at:
https://brainly.com/question/16819077
#SPJ1
How does Search, Setup, Smooth apply motorcycle
The concept of Search, Setup, and Smooth applies to motorcycle riding in the following way:
Search: This refers to the rider's ability to scan the road ahead and anticipate potential hazards, such as turns, traffic, and other obstacles. This is essential for safe riding as it allows the rider to make adjustments to their speed, position, and trajectory in advance.
Setup: This refers to the rider's body position and the setup of the motorcycle. This includes the rider's posture, the position of their feet on the pegs, and the position of their hands on the handlebars. A proper setup allows the rider to maintain stability and control of the motorcycle.
Smooth: This refers to the rider's ability to make smooth and controlled movements on the motorcycle. This includes smooth braking, accelerating, and turning. Smooth riding helps to maintain stability and control, and reduces the risk of accidents.
What is the concept about?The Search, Setup, and Smooth concept is a useful framework for thinking about motorcycle riding, as it highlights the importance of awareness, body position, and control in maintaining safety and stability on the road.
In summary, It emphasizes the rider's ability to anticipate hazards, maintain proper posture and motorcycle setup, and make smooth controlled movements.
Learn more about motorcycle from
https://brainly.com/question/28840082
#SPJ1
An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
For the circuit in the previous part, what happens to the maximum current if the frequency is doubled and the inductance is halved
Answer:
Following are the responses to these question:
Explanation:
Since the \(max^{m}\) is the current of ckt which depend on the reactance which inductor that also enables the ckt and inductor resistance \((X_L)\) for capacities
\(\to X_{C}=\frac{1}{W L}\)
for
\(\to X_{L}=wL\)
When \(w \longrightarrow 2w\)
\(L\longrightarrow \frac{L}{2}\)
then
\(\to X_{L}=2 w \times \frac{L}{2}=wL\)
therefore, \(X_{L}\) remains at the same so, the maximum current remains the in same ckt.
4. Maryanne is driving directly south for a distance of 100 km. Her
trip takes 1 hour. During the drive, a police officer measures her
speed at 125 kilometers per hour. Which of the statements are
accurate about her drive? (Choose all that apply)
Her average velocity was 125 kilometers per hour south.
Her instantaneous velocity was always 125 kilometers per hour
south.
Her instantaneous velocity was always 100 kilometers per hour
south.
Her average velocity was 100 kilometers per hour south
At one point, her instantaneous velocity was 125 kilometers per
hour south.
The accurate statements are:Her average velocity was 100 kilometers per hour south.At one point, her instantaneous velocity was 125 kilometers per hour south.
The accurate statements about Maryanne's drive are:
Her average velocity was 100 kilometers per hour south. Average velocity is calculated by dividing the total displacement by the total time taken. In this case, since she drove directly south for a distance of 100 km in 1 hour, her average velocity is indeed 100 km/h south.
At one point, her instantaneous velocity was 125 kilometers per hour south. Instantaneous velocity refers to the velocity at a specific moment in time. Although her average velocity was 100 km/h south, there could have been moments during her drive where her speed reached 125 km/h south, indicating her instantaneous velocity.
For more such questions on velocity
https://brainly.com/question/29396365
#SPJ8
What is the velocity of a sound wave that travels 2500 m in 8.2 s.
Explanation:
V=lander f. where,
v is the velocity of the sound wave
f is the frequency of sound wave(Hz)
L is the wavelength
so we simply just divide 2500 by 8.2 that gives us 304.88ms-¹
hopefully I get this right!
derivation of green's function for schrodinger wave equation?
The derivation of Green's function for the Schrödinger wave equation involves using the concept of superposition of solutions to find a particular solution for a given initial condition.
Green's function is a fine tool that's used to break discriminational equations, including the Schrödinger equation. The idea behind Green's function is to find a result to the discriminational equation that satisfies a given original condition. In the environment of the Schrödinger equation, Green's function represents the probability breadth of chancing a flyspeck at a particular position at a particular time, given that it started from a known original position and time.
The Green's function is attained by working the Schrödinger equation for a delta function source at the original position. To decide Green's function, one can consider the Schrödinger equation with a delta function source at some original position. This leads to the result for the surge function as a sum of two terms- a free flyspeck term and a term due to the delta function source.
Learn more about wave equation at
https://brainly.com/question/28723857
#SPJ1
Someone help ASAP please (right answers only)
Cuban tree frogs are skilled jumpers. They can launch themselves at 4.5 meters per second at an angle of 25° above horizontal. Assuming the frog is jumping on level ground, how far will the frog travel in a single jump, what is the frog’s hang time in the air during a single jump, and what is the maximum height above the ground that the frog will achieve?
The maximum height reached by the frog is 0.185 m.
What is the maximum height reached by frog?
The maximum height reached by the frog is calculated by applying the following kinematic equation.
H = u² sin²θ / 2g
where;
u is the initial velocity 4.5 m/sθ is the angle of projectiong is acceleration due to gravityH = (4.5² x (sin 25)²) / (2 x 9.8)
H = 0.185 m
Thus, the maximum height reached by the frog depends on the initial velocity and angle of the frog's projection.
Learn more about maximum height here: https://brainly.com/question/12446886
#SPJ1