Sharon has at most $25 to spend on her sister's birthday gift. She already bought a knitting machine for her, which cost
$14.99. She would also like to get her sister some skeins of yarn to go with it. Each skein costs $2.75.
a. Write an inequallty to represent this problem. Use y to represent the number of skeins of yarn.
b. What is the most number of skeins Sharon can afford to buy? Justify your answer in two or more complete
sentences.

The total money spent on a pass and lunch for each student is $850.14.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division.

here,

As mentioned in the question, Passes for 28 pupils and 4 teachers cost the school $778.88 and the school also spends $241.64 on lunch for kids only.

Total number of person  = 28 + 4
                                     = 32
Cost per pass = 778.88 / 32
                     = $24.34
Total passes of students = 25 × 24.34 = 608.5
Total spend on lunch of student = 241.64
Total spend on lunch = 241.64 + 608.5 = $850.14

Learn more about arithmetic here:

https://brainly.com/question/11424589

#SPJ1

Answer:

it is too blury to read

Step-by-step explanation:

Answer:

The answer for no 7 is A. 24 in, for no 8 is C. 10 in, for no 9 is D. similar

Step-by-step explanation:

The answer for no 7 can be calculation as follows

Since both rectangles are similar, then the corresponding side are proportional, and it follows

\(\frac{\overline{KJ}}{\overline{AB}}=\frac{x}{\overline{AD}}\)

\(\frac{48}{144}=\frac{x}{72}\)

Where \(x\) is the line segment \(\overline{MJ}\)

Multiply both sides by \(72\) to isolate \(x\)

\(\frac{48}{144}\times 72=\frac{x}{72}\times 72\)

\(\frac{48\times 72}{144}=x\)

\(\frac{3456}{144}=x\)

\(24=x\)

Since the value of \(x\) is \(24\), then the length of \(\overline{MJ}\) is \(24\) in

The answer for no 8 can be calculation as follows

Since both rectangular frames are similar,  then the corresponding side are proportional, and it follows

\(\frac{w_2}{w_1}=\frac{x}{h_1}\)

Where \(w_2\) is the width of frame \(2\), \(w_1\) is the width of frame \(1\), \(x\) is the height of frame \(2\), \(h_1\) is the height of frame 1

Substitute \(8\) for \(w_2\), \(12\) for \(w_1\), \(15\) for \(h_1\)

\(\frac{8}{12}=\frac{x}{15}\)

Multiply both sides by \(15\) to isolate \(x\)

\(\frac{8}{12}\times 15=\frac{x}{15}\times 15\)

\(\frac{8\times 15}{12}=x\)

\(\frac{120}{12}=x\)

\(10=x\)

Since the value of \(x\) is \(10\), then the height of  the second rectangular frame is \(10\) in

The answer for no 9 can be evaluated as follows

Since two polygons are similar if and only if two conditions are satisfied

Then the two polygons are similar

It is given in the question that the length of the rectangle is 6 less than double the width. Thus, we have the diagram as;

Where the length l is;

Thus, the perimeter P of a rectangle is the sum of the outer boundaries of a shape. We have;

Also, the area A of the rectangle is given as;

Answer:

70.02ft≈70ft

Step-by-step explanation:

Here,

∠ABC=35°

BC=100ft

AC=?

Now,

\(tanB=\frac{AC}{BC} \\\\\)\(tanB=\frac{AC}{BC} \\\\tan35=\frac{AC}{100ft} \\\\0.7002=\frac{AC}{100ft} \\\\100ft*0.7002=AC\\\\AC=70.02ft\)

Because tan=p/b

\(\\ \rm\rightarrowtail cot35=\dfrac{Base}{Perpendicular}\)

\(\\ \rm\rightarrowtail cot35=\dfrac{BC}{AC}\)

\(\\ \rm\rightarrowtail cot35=\dfrac{100}{AC}\)

\(\\ \rm\rightarrowtail AC=\dfrac{100}{1.43}\)

\(\\ \rm\rightarrowtail AC=69.93ft\)

Answer:

The weight that does not round to 2.46 pounds is C 2.454 pounds.

Step-by-step explanation:

Based on the given information, the weights of the four similar packs of tomatoes are as follows:

Malcolm rounds the weights to the nearest hundredth pound. To round to the nearest hundredth pound, we look at the digit in the hundredths place. If it is 5 or greater, we round up the digit in the tenths place. If it is less than 5, we leave the digit in the tenths place as it is. Therefore, we can obtain the rounded weights as follows:

From the above rounded weights, we see that Pack C rounds to 2.45 pounds and does not round to 2.46 pounds. Therefore, the weight that does not round to 2.46 pounds is C 2.454 pounds.

The measure of the unknown sides is equivalent to 12.6

The given figure is a circle geometry with the perpendicular lines intersecting both segments of the circle.

We need to determine the measure of x. Since the measure of the perpendicular lines are equal, hence the measure of the line of the segments will also be equal.

Hence:

x = 6.3 + 6.3

x = 12.6

Therefore the measure of x from the given diagram is equivalent to 12.6

Learn more on circle geometry here: https://brainly.com/question/26594685

#SPJ1

Hey there!

Solve for x :

x = 6 ✅

3x - 2 = 16

>> Add 2 to both sides :

3x - 2 + 2 = 16 + 2

3x = 18

>> Divide each side by 3 :

3x / 3 = 18 / 3

x = 6

▪️Let's verify :

3(6) - 2 ⇔18 - 2 ⇔ 16

Therefore, your answer is x = 6

Learn more about first-degree equations :

↣https://brainly.com/question/20205219

↣https://brainly.com/question/14621119

3x−2=16

Add 2 to both sides.

3x=16+2

Add 16 and 2 to get 18.

3x=18

Divide both sides by 3.

x = 18 /3

Divide 18 by 3 to get 6.

x = 6 ===> Answer

Let x = 6

3×6−2=16

18-2= 16

16 = 16

Checked ✅

Answer:

The said friend's grade in Professor Ivy's class is 85.7.

Step-by-step explanation:

Assuming the question asks for your friend's grade in Professor Ivy's class.

0.05(95) + 0.25(89) + 0.25(80) + 0.45(86) = 85.7

Answer:

i think is is 3

Step-by-step explanation:

The rate of interest with the given amount and compound interest is 5 percent.

Given that,

After 1 year: compound interest = $30 and total amount=$630.

The formula used to find the compound interest = \(A=P(1+\frac{r}{100})^{nt}\).

Here, principal = 630-30=600

630=600(1+r/100)¹

630/600 = 1+r/100

1.05=1+r/100

1.05-1=r/100

0.05=r/100

r=5%

Therefore, the rate of interest with the given amount and compound interest is 5 percent.

To learn more about the compound interest visit:

https://brainly.com/question/14295570.

#SPJ1

In the middle equation on the left side, if you let x = 3/2, then the term containing A vanishes and you can solve for B :

12*(3/2) - 25 = A (2*(3/2) - 3) + B

18 - 25 = A * (3 - 3) + B

B = -7

which makes the last option the correct answer.

Answer:

D

Step-by-step explanation:

edge 2021

Answer:

Sorry

Step-by-step explanation:

Answer:

$762

Step-by-step explanation:

50 adult tickets x $12/ticket = $600

18 child tickets x $9/ticket = $162

Add the together: $600 + $162 = $762

Answer:

Could you show the graph?

Step-by-step explanation:

Answer:

Please make clear,

Answer:

2 < y < 6

Step-by-step explanation:

Expand the brackets, multiplying by y

12 < 8y - y^2

Rearrange

0 < -y^2 + 8y - 12

Divide by -1. When dividing by a negative number, you must flip the inequality sign

0 > y^2 - 8y + 12

Factorise

0 > (y - 6)(y - 2)

The two solutions are y = 6, 2

Check using a value inbetween 2 and 6 to see if the inequality holds true. For example 3 is between 2 and 6

0 > (3 - 6)(3 - 2)

0 > -3(1)

0 > -3

As this holds true, this means that y lies between 2 and 6

Therefore, the answer is 2 < y < 6

(If the inequality did not hold true, then y would lie above 6 and below 2. y < 2 and y > 6. Not relevant for this example)

Answer:

10/10

Step-by-step explanation:

Answer:

The answer is E

Step-by-step explanation:

When multiplying exponents you just have to add them but they have to have the same denominator in order to be added.

Multiply 1/2 by 2 on the top and bottom: 2/4 and add to 1/4 to get 3/4

Answer:

3/76

Step-by-step explanation:

Answer:

-1.3n+1.5

-6.4n+9.8

-0.36n-4

Step-by-step explanation:

The two pairs of integers that satisfy the given conditions are (-3, 8) and (5, 24).

To solve the system of equations, let's assign variables to the two integers. Let the first integer be represented by 'x' and the second integer by 'y'.

According to the given information:

a. Fourteen more than twice the first integer gives the second integer:

This can be expressed as: 2x + 14 = y

b. The second integer increased by one is the square of the first integer:

This can be expressed as: y + 1 = x^2

Now, we have a system of equations:

1) 2x + 14 = y

2) y + 1 = x^2

To solve this system, we can substitute the value of 'y' from equation 1) into equation 2):

2x + 14 + 1 = x^2

2x + 15 = x^2

Rearranging the equation, we have:

\(x^2 - 2x - 15 = 0\)

Factoring the quadratic equation, we get:

(x - 5)(x + 3) = 0

Setting each factor equal to zero:

x - 5 = 0   -->   x = 5

x + 3 = 0   -->   x = -3

Substituting the values of 'x' back into equation 1), we can find the corresponding values of 'y':

For x = 5:

2(5) + 14 = y

10 + 14 = y

y = 24

For x = -3:

2(-3) + 14 = y

-6 + 14 = y

y = 8

Therefore, the two pairs of integers that satisfy the given conditions are (-3, 8) and (5, 24).

for more such question on integers visit

https://brainly.com/question/929808

#SPJ8

Step-by-step explanation:

The commonly used methods to find the LCM of 15 and 20 are:

1) Division Method

2) Prime Factorization Method

3)Listing Multiples

Answer:

x =  -5

The line x = -5 will pass through (-5, -2)

The equation that represents a quadratic relationship is y = 4x^2. Option A.

A quadratic relationship is a mathematical relationship where the variable y is a function of the variable x raised to the power of 2. In other words, it is an equation in which the highest power of the variable is 2.

Let's analyze the given equations:

1. y = 4x^2: This equation represents a quadratic relationship because the variable x is raised to the power of 2. The term 4x^2 indicates that the relationship between x and y is quadratic.

2. y = 4x^4: This equation represents a quartic relationship, not a quadratic relationship. The variable x is raised to the power of 4, which indicates a higher degree relationship than quadratic.

3. y = 4x^3: This equation represents a cubic relationship, not a quadratic relationship. The variable x is raised to the power of 3, indicating a higher degree relationship.

4. y = 4: This equation represents a linear relationship, not a quadratic relationship. It is a constant equation where y is always equal to 4, regardless of the value of x. In a quadratic relationship, the variable x should have a power of 2. Option A.

For more such questions on quadratic

https://brainly.com/question/30164833

#SPJ8

Given:

​$4,000 deposit in an account with an APR of ​8%.

Required:

We need to find APY with APR 8%

so

Explanation:

Here we find for 1 year

take n=1 in

Now to find ARP

Final answer:

$4333.15

8.33%

(A) The range and IQR for boxplot 1 is 10 and 6 respectively.

(B) The range and IQR for boxplot 2 is 12 and 7 respectively.

The interquartile range defines the difference between the third and the first quartile.

The formula for the interquartile range is given below.

Interquartile range = Upper Quartile – Lower Quartile = Q­3 – Q­1

The range is the difference between the lowest and highest values.

The formula for the interquartile range is given below.

Range = Maximum – Minimum

(A) For boxplot 1, we need to find the range and IQR from the given data set.

So, let 34 be the maximum and 24 be the minimum.

\(\text{Range}=\sf 34-24\)

\(\text{Range}=\sf10\)

Therefore, the range is 10.

Now time to find the IQR.

So, let 33 be Q3 and 27 be Q1.

\(\text{IQR}=\sf 33-27\)

\(\text{IQR}=\sf 6\)

Therefore, the IQR is 6.

(B) Now for boxplot 2, we will do the same thing as from part A.

Let's find the range.

So, let 24 be the maximum and 12 be the minimum.

\(\text{Range}=\sf 24-12\)

\(\text{Range}=\sf12\)

Hence, the range is 12.

Now for the IQR.

So, let 22 be Q3 and 15 be Q1.

\(\text{IQR}=\sf 22-15\)

\(\text{IQR}=\sf 7\)

Hence, the IQR is 7.

To know more about the range and IQR, visit:

https://brainly.com/question/31752116

#SPJ5

Answer:

A. Inscribed Angle Theorem

Step-by-step explanation:

Because the angles are inscribed in the circle, the angle lie on arcs which mean that the angles have to add up to 360 degrees just like a circle is 360 degrees, making it a quadrilateral that is inscribed!

Hope this helps actually explain the answer,

                                                   Matthew Keister aka Mattsawesome 5000 YT

The missing information in the paragraph proof is  inscribed angle theorem that if an angle is inscribed in a circle, the measure of the inscribed angle is half the measure of the intercepted arc.

Inscribed angle in a circle is formed by two chords that have a common end point on the circle. This common end point is the vertex of the angle.

We have,

Quadrilateral \(A B C D\) inscribed in Circle.

Measure of Arc \(B C D = a^0\).

Arc \(B C D\) and Arc \(B A D\) form a circle, and a circle measures \(360^0\),

Measure of Arc \(B A D = 360 - a^0\)

Because of the theorem that if an angle is inscribed in a circle, the measure of the inscribed angle is half the measure of the intercepted arc.

Therefore,

\(\angle A = \frac{a}{2}^0\)  and    

\(\angle C = (\frac{360-a}{2}) ^0\)

The sum of the measures of angles \(A\) and \(C\) is,

\(\angle A + \angle C = \frac{a}{2}^0 +(\frac{360-a}{2}) ^0=180^0\)

Therefore, angles  \(A\) and \(C\) are supplementary because their measures add up to \(180^0\).

Angles \(B\) and \(D\) are supplementary because the sum of the measures of the angles in a quadrilateral is\(360^0\).

\(\angle A + \angle C + \angle B + \angle D = 360^0\)

and using substitution,

\(180^0 + \angle B + \angle D = 360^0\)

So,

\(\angle B + \angle D = 180^0\)

So, from the above provided proof we can say that the missing information in the proof was inscribed angle theorem.

Hence, we can say that the missing information in the paragraph proof is  inscribed angle theorem that if an angle is inscribed in a circle, the measure of the inscribed angle is half the measure of the intercepted arc.

To know more about inscribed angle click here

https://brainly.com/question/15899344

#SPJ3

If the random variable x is normally distributed with a mean equal to 0.45 and a standard deviation equal to 0.40, then P(x ≥ .75) is 0.9227.

A z-score describes the position of a raw score in terms of its distance from the mean when measured in standard deviation units. The z-score is positive if the value lies above the mean and negative if it lies below the mean.

Given the problem above, we need to find what the z-score is when P(x ≥ .75).

The formula for calculating a z-score is given by:

\(Z=\dfrac{\text{x}-\mu}{\sigma}\)

Where:

Now,

\(Z=\dfrac{\text{x}-\mu}{\sigma}\)

\(Z=P(\text{x} \geq 0.75) = \huge \text(\dfrac{P(Z \geq (0.75 - 0.45)}{0.40}\huge \text)\)

\(Z= P\huge \text (\dfrac{Z \geq0.30}{0.40}\huge \text)\)

\(Z=P(Z \geq 0.75) = 1 - P(Z < 0.75)\)

\(Z=1 - 0.077337\)

\(Z\thickapprox 0.9227\)

Therefore, the z-score of P(x ≥ .75) is 0.9227.

Learn more about the z-score at:

https://brainly.com/question/31871890