The integral expression for the area between f(x) = x^3 and F(x) = x is Area = ∫[-1,1] (x^3 - x) dx.
To set up an integral expression for the area between f(x)=x^3 and F(x)=x, we can use the formula for the area between two curves:
Area = ∫[a,b] (f(x) - g(x)) dx
where f(x) is the upper curve and g(x) is the lower curve.
In this case, the curves are f(x) = x^3 and g(x) = x, and the interval of integration is not given. To find the interval, we can set the two curves equal to each other and solve for x:
x^3 = x
x(x^2 - 1) = 0
x = 0, ±1
So the interval of integration is [-1, 1], since f(x) > g(x) for x < 0 and f(x) < g(x) for x > 1.
Therefore, the integral expression for the area between f(x) = x^3 and F(x) = x is:
Area = ∫[-1,1] (x^3 - x) dx
The integral expression for the area between f(x) = x^3 and F(x) = x is Area = ∫[-1,1] (x^3 - x) dx.
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Plz help quick pls Brainly
Answer:
x is greater than or equal to -26
Step-by-step explanation:
We can use distributive property to solve the equation.
-6(x+4) in distributive property is: -6x-24
-6x-24 is less than or equal to -5x+2
+6x +6x
-24 is less than or equal to x+2
-2 -2
-26 is less than or equal to x
This means x is greater than or equal to -26
On the graph you would put a closed circle on -26 and point to the right.
Hope this helps! Good luck on your quiz!
Irma has a recipe for cornbread muffins that uses cup of sugar for 1 dozen
cornbread muffins. 1 cup of sugar is approximately 200 grams. If Irma makes 5 dozen
cornbread muffins, about how many grams of sugar will she need?
Answer:
333
Step-by-step explanation:
1/3x5= 1.66
Answer:
333
Step-by-step explanation:
i need points lol
Rewrite in simplest terms: 8(-10r-9)+9r
Answer:
-71r-72
Step-by-step explanation:
8(-10r-9)+9r
Distribute the 8
-80r -72 +9r
Combine like terms
-80r+9r -72
-71r-72
Please help! Show step by step, please! I will mark brainleist.
Answer:
(-3, 5)
Step-by-step explanation:
This is because it is on the same point on the opposite side of the grid
-Please let me know if I am wrong so I can improve
- have a nice day
-3,5 is the answer for the other side
I need help with this- thank you
Will mark brainliest! :)
Answer: 5x^{2} +3x + 4
Hope this helped! :)
Answer:
(X^2 + 2x + 7) + (4x^2 + x - 3) =
x^2 + 2x + 7 + 4x^2 + x - 3 =
5x^2 + 3x + 4
equation of the circle centered at the origin and passing through the point equation of the circle centered at the origin and passing through the point (-4,0)
The equation of the circle centered at the origin and passing through the point (-4,0) is \(x^2+y^2=16\).
Equation of a circle
A circle may also be defined as a special kind of ellipse in which the two foci are coincident, the eccentricity is 0, and the semi-major and semi-minor axes are equal.
We know that,
Equation of the circle passing through the origin is given by:-
\(x^2+y^2=r^2\)
Where,
r is the radius of the circle, and
(x,y) are the coordinates of each point of the circle.
Hence, we can write,
The radius of the circle will be :-
\(\sqrt{(0-(-4))^2+(0-0)^2} =\sqrt{ 4^2+0^2} =\sqrt{16}=4 units\)
Hence, r = 4 units.
Hence, the equation of the circle is given by:-
\(x^2+y^2=16\)
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In the expression 2 ^3, the 3 is known as the
Answer:
3 is known as the power of 2.
Answer:
The three is the exponent, it is also called power so 2 to the power of 3
Step-by-step explanation:
Let W be a symmetric positive definite matrix with Cholesky decomposition A= LLT = RTR. Prove that the lower triangular matrix L (or that the upper triangular matrix R) in the factorization is unique.
Proving the uniqueness of L (or R) in Cholesky decomposition of symmetric positive definite matrix A by assuming L1 and L2, and showing that L1 = L2 using A's positive definiteness and unique Cholesky decomposition.
To prove that the lower triangular matrix L in the Cholesky decomposition is unique, we assume that there exist two lower triangular matrices L1 and L2 such that \(A= L1L1^T = L2L2^T\). We need to show that L1 = L2.
We can start by observing that \(L1L1^T = L2L2^T\) implies that\(L1^T = (L2L2^T)^{-1} L2\). Since L1 and L2 are both lower triangular, their transpose is upper triangular, and the inverse of an upper triangular matrix is also upper triangular. Thus, \(L1^T\) and L2 are both upper triangular.
Now, let \(L = L1^T L2\). Since L1 and L2 are lower triangular, L is also lower triangular. Then we have:
\(LL^T = L1^T L2\;\; L2^T (L1^T)^T = L1^T L2\;\; L2^T L1 = L1 L1^T = A\)
where we have used the fact that L1 and L2 are both lower triangular and their transposes are upper triangular. Thus, we have shown that L is also a lower triangular matrix that satisfies \(A = LL^T\).
To show that L1 = L2, we use the fact that A is positive definite, which implies that all of its leading principal submatrices are also positive definite.
Let A1 be the leading principal submatrix of A of size k, and let L1,k and L2,k be the corresponding leading principal submatrices of L1 and L2, respectively. Then we have:
\(A1 = L1,k L1,k^T = L2,k L2,k^T\)
Since A1 is positive definite, it has a unique Cholesky decomposition \(A1 = G G^T\), where G is a lower triangular matrix. Thus, we have:
\(G G^T = L1,k L1,k^T = L2,k L2,k^T\)
which implies that G = L1,k and G = L2,k, since both L1,k and L2,k are lower triangular. Therefore, we have shown that L1 = L2, and hence the lower triangular matrix L in the Cholesky decomposition of a positive definite matrix A is unique. A similar argument can be used to show that the upper triangular matrix R in the Cholesky decomposition is also unique.
In summary, we have proved that the lower triangular matrix L (or the upper triangular matrix R) in the Cholesky decomposition of a symmetric positive definite matrix A is unique.
This is done by assuming the existence of two lower triangular matrices L1 and L2 that satisfy \(A= L1L1^T = L2L2^T\), and then showing that L1 = L2 using the fact that A is positive definite and has a unique Cholesky decomposition.
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A 440 wire is cut into three pieces the second piece is two times as long as the first the third piece is four times as long as the second how long is each piece
Step-by-step explanation:
\(x \: as \: the \: first \: piece \\ 2x \: as \: the \: second \: piece \\ 4(2x) = 8x \: as \: the \: third \: piece\)
\(x + 2x + 8x = 440 \\ 11x = 440 \\ x = \frac{440}{11} \\ x = 40 \\ 2x = 2 \times 40 = 80 \\ 8x = 8 \times 40 = 320 \)
Determine whether the series is convergent or divergent. 3^(n+1)4^-n If it is convergent, find its sum.
Geometric series is convergent if the |r|<1 where r is the common ratio.
Let Sn=∑ni=0(−3/4)i then
Sn=(−3/4)n+1−1(−3/4)−1
Now take n→∞ then
Sn→0−1(−3/4)−1=4/7
because |−3/4|<1 and so (−3/4)n→0. Now note that your sum is
lim ∑i=1n+1(−3)i−14i=lim 14∑i=1n+1(−3)i−14i−1=1/4.lim Sn=1/7.
Geometric series: A geometric series is the result of adding together geometric sequences indefinitely. Depending on the sequence given to us, such infinite sums can either be finite or infinite. A series is considered to be convergent if the partial sums gravitate to a certain value, also known as a limit. In contrast, a divergent series is one whose partial sums do not reach a limit. Divergent series frequently reach, reach, or avoid a particular number.
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What is the value of the expression 29-|7-11|
Answer: 25
Step-by-step explanation:
29-|7-11|
29-|-4|
29-4
25
The value of 29 - |7 - 11| = 25
We have the following expression -
29 - |7 - 11|
We have to find its value.
Find the value of the expression -X + | \(\pi\)Y | where Y < 0We have -
X + | \(\pi\)Y |
Since Y < 0 - therefore \(\pi\)Y < 0
Now -
|a| = - a { for a < 0}
Therefore -
X - \(\pi\)Y
According to the question, we have -
29 - |7 - 11|
29 - | -4 |
29 - 4
25
Hence, the value of 29 - |7 - 11| = 25
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are x and 12x like terms plz i need this!
Yes.
You can add them together to get 13x.
because you can add them together, they are alike terms.
i forgot how to do this can someone help.......
i need all four of them answered plz...
will someone help me pls
Answer:
C- 66
Step-by-step explanation:
Multiply the radius (10.5) by 2 and then times that (10.5x2=21) by pi (3.14)
Answer:
C=66
Step-by-step explanation:
C=2pi*r
C=2*pi*10.5
C=21*pi
C=21*3.14
C=65.94
you lose one quarter, 2 dimes, and 2 nickels
write the amount as a decimal
and as a fraction
The rim of the volcanic crater shown below is a circle. The diameter is 840 m.
What is the circumference of the rim of the crater in kilometres (km)?
Give your answer to 1 d.p.
840 m
Not drawn accurately
Answer:
2.6 kilometers
Step-by-step explanation:
To find the circumference of a circle, we can use the formula:
Circumference = π * diameter
Given that the diameter of the volcanic crater is 840 meters, we can substitute this value into the formula:
Circumference = π * 840
Using the approximate value of π as 3.14159, we can calculate the circumference:
Circumference = 3.14159 * 840
Circumference ≈ 2643.1796 meters
To convert the circumference to kilometers, we divide the value by 1000:
Circumference in kilometers = 2643.1796 / 1000
Circumference ≈ 2.6432 kilometers
Therefore, the circumference of the rim of the volcanic crater is approximately 2.6 kilometers (rounded to 1 decimal place).
What is the slope of the line represented by the following formula?
y = 2 + 6(x-3)
6
12
-3
-6
3
Answer:
slope = 6
Step-by-step explanation:
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
given
y = 2 + 6(x - 3 ( subtract 2 from both sides )
y - 2 = 6(x - 3) ← in point- slope form
with slope m = 6
Given the geometric sequence 42,16.8,6.72 find the next term
Answer:
I don't know
Step-by-step explanation:
because I don't understand which value it T1, T2, T4 etc
In his stamp album, Jamal has 48 new stamps and 72 used stamps.
Which ratio can be represented by 35?
A.The number of used stamps to the total number of stamps.
B.The number of new stamps to the number of used stamps.
D.The number of used stamps to the number of new stamps.
C.The number of new stamps to the total number of stamps.
Answer:
Its B
Step-by-step explanation:
1. Find measure of angle GBC
A. 55°
B. 125°
C. 45°
D. 60°
(Show work)
Answer:
A. 55°
Step-by-step explanation:
So the line goes through two angles, 125° and 55°
Lets check, does the angle look larger than 90°
Remember, 90° mean the line is perpendicular, or goes straight up.
I see that it is not. The angle that is less than 90° (55°) is correct.
If my answer is incorrect, pls correct me!
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-Chetan K
if (3-x),6,(7-5x) are consecutive terms of a geometric progression with constant common ratio r>0, what is the value of X and the common ratio
The value of r and x in the common ratio of geometric progression is 5/3 and - 3/5
what is Geometric progression ?
Each succeeding term in a sequence known as a geometric progression (GP) is created by multiplying each term in the sequence before it by a fixed number known as a common ratio.
Solution;
we have two equations
r = 6/(3-x)----- [1]
r = (7-5x)/6----- [2]
6/(3-x) = (7-5x)/6
36 = 21 - 22x + 5x^2
5x^2 - 22x - 15 = 0
This can be factored as (5x+3)(x-5) = 0. The two solutions common ratio are x = -3/5, x = 5.
But, x=5 gives r<0, so we choose the 1st solution, x = -3/5.
Substitute in [1] to get he value for r:
r = 6/(3--3/5) = 6/(18/5) = 5/3.
Ans: r = 5/3, x = -3/5
Therefore, The value of r and x in the common ratio of geometric progression is 5/3 and - 3/5.
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Pls help me I don’t have much time
Answer:
the answer is c
jajskdks
Answer:
the slope is 3 and the y-int is (0,-6)
Step-by-step explanation:
This is because the equation is made in slope intercept form which is y=mx+b and m is the slope and in the equation y=3x-6 3 takes the place of m so 3 would be the slope. and b is the y intercept so since -6 replaces b in the equation the y intercept is -6
If A=QR, where Q has orthonormal columns, what is the relationship between R and QT?
The upper triangular matrix R is invariant under multiplication by the transpose of Q. This relationship is sometimes referred to as the "QR factorization identity".
If A=QR, where Q is an n×n matrix with orthonormal columns and R is an n×n upper triangular matrix, then we can express A as:
A = QR = Q(QT)R
Since Q has orthonormal columns, its transpose QT is its inverse. Therefore:
Q(QT)R = I_n R = R
where I_n is the n×n identity matrix. So we can see that R is equal to Q(QT)R, which is the product of Q and the transpose of Q. This product is equal to the identity matrix times R, so we can say that:
R = QT R
In other words, the upper triangular matrix R is invariant under multiplication by the transpose of Q. This relationship is sometimes referred to as the "QR factorization identity".
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bird is flying directly above a tree you are standing 40 feet away from the tree the angle of elevation to the top of the tree is 32 degrees and the angle of elevation to the bird is 42° how far above the tree is the bird
Answer: 11 ft
Step-by-step explanation:
Given
The boy is standing 40 feet away from the tree
the angle of elevation for the tree is \(32^{\circ}\\\)
the angle of elevation for the bird is \(42^{\circ}\\\)
using figure
\(\frac{h+x}{40}=\tan 42^{\circ}\\h+x=40\tan 42^{\circ}\ldots (i)\\Now,\\\tan 32^{\circ}=\frac{h}{40}\\h=40\tan 32^{\circ}\)
Put the value of h in equation (i)
\(40\tan 32^{\circ}+x=40\tan 42^{\circ}\\x=40[\tan 42^{\circ}-\tan 32^{\circ}]\\x=40[0.9-0.624]=0.276\times 40=11.04\ ft\)
What are all the roots of
x^3 +2x=x^2 +2?
Answer:
Step-by-step explanation:
5. 3(x - 1) = 23 – 5(x + 2)
Answer:
x = 2
Step-by-step explanation:
3(x - 1) = 23 - 5(x + 2) ← distribute parenthesis on both sides
3x - 3 = 23 - 5x - 10
3x - 3 = 13 - 5x ( add 5x to both sides )
8x - 3 = 13 ( add 3 to both sides )
8x = 16 ( divide both sides by 8 )
x = 2
Answer:
x=2
Step-by-step explanation:
Find the open intervals on which the function is increasing and decreasing. Identify the function's increasing on (−2,2); decreasing on (−6,0); absolute maximum at (2,4); absolute minimum at (−2,−4) increasing on (−2,2); decreasing on (−6,−2) and (2,6); absolute maximum at (2,4); absolute minimum at (−2,−4) increasing on (−2,2); decreasing on (0,6); absolute maximum at (2,4); absolute minimum at (−2,−4) increasing on (−2,2); decreasing on (−6,−2) and (2,6); no absolute maximum; no absolute minimum
The correct answer is: increasing on (-2,2); decreasing on (-6,0); absolute maximum at (2,4); absolute minimum at (-2,-4).
To determine the intervals on which the function is increasing and decreasing, we need to analyze the behavior of the function's derivative. When the derivative is positive, the function is increasing, and when the derivative is negative, the function is decreasing.
Based on the given information, the function is increasing on the interval (-2,2). This means that the function's derivative is positive in that interval.
The function is decreasing on the interval (-6,0), indicating that the function's derivative is negative in that range.
The absolute maximum of the function occurs at the point (2,4), which means that the function reaches its highest value at x = 2, where the y-coordinate is 4.
Similarly, the absolute minimum of the function occurs at the point (-2,-4), indicating that the function reaches its lowest value at x = -2, where the y-coordinate is -4.
In summary, the function is increasing on the interval (-2,2), decreasing on the interval (-6,0), and has an absolute maximum at (2,4) and an absolute minimum at (-2,-4).
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Consider the two tables T1 and T2 shown.Show the results of the following operations: (9 points each. Total 36 points)
Table T1
P Q R
10 A 5
15 B 8
25 A 6
Table T2
A B C
10 B 6
25 C 3
10 B 5
T1 JOIN T1.P = T2.A T2
T1 (LEFT OUTER JOIN) T1.P = T2.A T2
T1 (RIGHT OUTER JOIN) T1.Q = T2.B T2
T1 JOIN (T1.P = T2.A AND T1.R = T2.C) T2
T1 LEFT OUTER JOIN T2 ON T1.P = T2.A T1.P T1.R T2.A T2.C10 B 6 NULL NULLNULL NULL NULL 7 C T2 JOIN (T1.P = T2.A AND T1.R = T2.C) T2 T1.P T1.R T2.A T2.CNULL NULL NULL NULL NULL NULL NULL NULL
Consider the two tables T1 and T2 and the operations performed on them. The results of the operations are shown above. In the first operation, a LEFT OUTER JOIN is performed on T1 and T2, where the join is made on the basis of T1.P = T2.A. In the second operation, a JOIN is performed on T1 and T2, where the join is made on the basis of T1.P = T2.A AND T1.R = T2.C. The keyword 'LEFT OUTER JOIN' has been bolded in the main answer, while 'JOIN' has been bolded in the supporting explanation.
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5.93 A roulette payoff revisited. Refer to the previous exercise. In part (d), the central limit theorem was used to approximate the probability that Sam ends the year ahead. The estimate was about 0.10 too large. Let’s see if we can get closer using the Normal approximation to the binomial with the continuity correction. (a) If Sam plans to bet on 520 roulette spins, he needs to win at least $520 to break even. If each win gives him $35, what is the minimum number of wins m he must have? (b) Given p = 1/38 = 0.026, what are the mean and standard deviation of X, the number of wins in 520 546 roulette spins? (c) Use the information in the previous two parts to compute P(X ≥ m) with the continuity correction. Does your answer get closer to the exact probability 0.396?
a) The minimum number of wins he needs is 15. b) The standard deviation of X is σ = sqrt(Var(X)) ≈ 3.641. c) Standard normal table ≈ 0.411.
In part (a), we can use the formula for a binomial distribution to find the minimum number of wins Sam needs to break even. Let X be the number of wins in 520 spins, then X ~ Bin(520, 1/38). To break even, Sam needs to win at least $520, which means he needs at least m wins where 35m ≥ 520, or m ≥ 14.86. Since m must be an integer, the minimum number of wins he needs is 15.
In part (b), we can use the mean and variance of a binomial distribution to find the mean and standard deviation of X. The mean of X is E(X) = np = 520*(1/38) ≈ 13.684, and the variance of X is Var(X) = np(1-p) = 520*(1/38)*(37/38) ≈ 13.255. Therefore, the standard deviation of X is σ = sqrt(Var(X)) ≈ 3.641.
In part (c), we can use the Normal approximation to the binomial with the continuity correction to find P(X ≥ 15). Using the continuity correction, we can convert the discrete probability P(X ≥ 15) to a continuous probability P(X > 14.5). Standardizing X, we get Z = (14.5 - 13.684) / 3.641 ≈ 0.224. Using a standard normal table, we can find that P(Z > 0.224) ≈ 0.411. Therefore, P(X > 14.5) ≈ 0.411.
This answer is closer to the exact probability of 0.396 than the previous estimate of 0.10 too large, but it still overestimates the probability slightly. This could be due to the fact that the Normal approximation to the binomial assumes a continuous distribution, while the binomial distribution is discrete. Nonetheless, the Normal approximation with continuity correction is a useful tool for approximating probabilities in situations where the sample size is large.
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which expression represents 7 less than the product of 11 and 4 .