Serena paid $194.99 for a game system and then bought two equally-priced games. She spent a total of $284.97.If p represents the price of one game, which equation represents the situation?

The population mean is greater than $12.5, assuming that we know the population standard deviation is equal to 6.75.

To test whether we can infer at the 5% significance level that the mean fee for car washers (including tips) is greater than $12.5, we need to perform a one-sample t-test with the following hypotheses:

Null hypothesis: μ ≤ $12.5

Alternative hypothesis: μ > $12.5

We will use a t-distribution with degrees of freedom (df) equal to n-1 = 15-1 = 14.

The test statistic is given by:

t = (x - μ) / (s / sqrt(n))

where x is the sample mean, s is the sample standard deviation, and n is the sample size.

Substituting the given values, we get:

t = (14.9 - 12.5) / (6.75 / sqrt(15)) = 2.28

The critical value for a one-tailed test with α = 0.05 and df = 14 is 1.761. Since our calculated t-value (2.28) is greater than the critical value (1.761), we reject the null hypothesis and conclude that we can infer at the 5% significance level that the mean fee for car washers (including tips) is greater than $12.5.

To test whether we can infer at the 5% significance level that the population mean is greater than $12.5, assuming that we know the population standard deviation is equal to 6.75, we need to perform a z-test with the following hypotheses:

Null hypothesis: μ ≤ $12.5

Alternative hypothesis: μ > $12.5

We will use a standard normal distribution.

The test statistic is given by:

z = (x - μ) / (σ / sqrt(n))

where σ is the population standard deviation, which is given as 6.75.

Substituting the given values, we get:

z = (14.9 - 12.5) / (6.75 / sqrt(15)) = 2.28

The critical value for a one-tailed test with α = 0.05 is 1.645. Since our calculated z-value (2.28) is greater than the critical value (1.645), we reject the null hypothesis and conclude that we can infer at the 5% significance level that the population mean is greater than $12.5, assuming that we know the population standard deviation is equal to 6.75.

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Answer:

pie * r^2 bro where r= 10mi

Answer: -4 and 9

Step-by-step explanation:

The inequality that represents the situation is 8.50x < 35 and the pounds of shrimp Luna can buy is 4.

Inequality is a statement that two or more mathematical expressions are unequal.

Inequalities are represented as greater than (>), less than (<), greater than or equal to (≥), less than or equal to (≤), and not equal to (≠).

The cost price of shrimp per pound = $8.50

The total spending budget = $35

Let the number of pounds of shrimp Luna can buy = x

8.50x < 35

x = 4

Thus, the total amount Luna can spend on shrimp is $34 (4 x $8.50), which is less than $35.

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By applying algebra, it can be concluded that the number of candies remaining in the bag can be written as c = 150 - 8s, where s is the number of snacking.

Algebra is a branch of mathematics that uses symbols and mathematical operations, such as addition, subtraction, multiplication, and division to solve problems

Now we apply algebra to solve the problem:

Tyrone takes 8 pieces of candy each time snacking

After snacking 18 times, 6 pieces of candy remained in the bag

So the totals candies eaten = 8 * 18

                                              = 144 candies

Number of candies in the bag = candies eaten + remaining candies

                                                  = 144 + 6

                                                  = 150 candies

If s denotes the number of snacking, then the total number of candies eaten on s snacking = 8s

if c denotes the number of remaining candies, then:

c = total candies - candies eaten

c = 150 - 8s

Thus the number of candies remaining in the bag can be written as c = 150 - 8s, where s is the number of snacking.

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Answer:

honestly i got 273.6 so i'm thinking that he would have to pay about 273 times........

Step-by-step explanation:

Answer:

15$

Step-by-step explanation:

Answer:

Step-by-step explanation:

3100 ft per 50,000 years

31 ft per 500 years (Divided 100)

Convert ft to inches

372 in per 500 years

0.744 inches per year (Divided by 500)

Answer:

LA = 624 cm²

Step-by-step explanation:

h² = 5² + 12²

h = 13

LA = 4 × bh/2

LA = 4 × (24 cm)(13 cm)/2

LA = (48 cm)(13 cm)

LA = 624 cm²

Answer:

THE ADDITIVE INVERSE OF 9 IS -9 AND MULTIPLICATIVE INVERSE OF 9 IS 1/9

WE HAVE TO FIND THEIR SUM

9+1/9

TAKING LCM

\(\frac{9*9}{1*9}\)+\(\frac{1}{9}\)

81/9+1/9

82/9

Step-by-step explanation:

I HOPE IT WILL HELP YOU

Answer:

c

hypothesis is an educated guess. it follows the word if in If, then statements.

following the word then is your conclusion

Answer:

width = 9/2 m

length = 14 m

Step-by-step explanation:

Let width = x

If the length of a rectangle is 5 m more than twice the width:

⇒ length = 2x + 5

Use the given information to create a quadratic equation:

Area of a rectangle = width × length

⇒ 63 = x(2x + 5)

⇒ 63 = 2x² + 5x

⇒ 2x² + 5x - 63 = 0

Find the value of x by factorizing the quadratic:

⇒ 2x² + 5x - 63 = 0

⇒ 2x² + 5x - 63 = 0

⇒ 2x² + 14x - 9x - 63 = 0

⇒ 2x(x + 7) - 9(x + 7) = 0

⇒ (2x - 9)(x + 7) = 0

Therefore:

⇒ (2x - 9) = 0 ⇒ x = 9/2

⇒ (x + 7) = 0 ⇒ x = -7

Width cannot be negative, therefore, x = 9/2 only

⇒ width = 9/2 m

⇒ length = 2(9/2) + 5 = 14 m

The variable expression that represents Nora's finishing time, given Maria's time (m) in seconds, can be expressed as (m - 3.8). This expression shows Nora's finishing time by subtracting 3.8 seconds from Maria's time.

To determine Nora's finishing time, we start with the given information that Nora finished the race 3.8 seconds before Maria. This means that Nora's finishing time must be less than Maria's time. By subtracting 3.8 seconds from Maria's time (represented by the variable m), we obtain Nora's finishing time. The expression (m - 3.8) provides the relative time difference between Nora and Maria, where Nora finishes 3.8 seconds earlier than Maria. Therefore, by substituting the value of Maria's time into this expression, we can calculate Nora's finishing time.

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Answer:

78kg

Step-by-step explanation:

76×5= 380kg

380-72-74-75-81= 78kg

The importance and advantage of using graph representation when organizing your data are that it makes data presentable, summarizing, better way of comparison of data.

An organized diagram or pictorial representation of the relationship between values or data is referred to as a graph. it is a a diagram that depicts a variable's variation in comparison to that of one or more other variables, such as a series of points, lines, line segments, curves, or areas.

The following are the three advantages of graphs:

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It is False that by adding the number of inner loops , we get the total number of iterations.

A loop is defined as a segment of code that executes multiple times. Iteration refers to the process in which the code segment is executed once. One iteration refers to 1-time execution of a loop. A loop can undergo many iterations.

There are 3 types of iteration: tail-recursion, while loops, and for loops. We will use the task of reversing a list as an example to illustrate how different forms of iteration are related to each other and to recursion. A recursive implementation of reverse is given below.

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The cost of 3 pounds of oranges is $1.80 .

Given,

Monica paid $3.20 for 2 pounds of apples and 2 pounds of oranges.

Sarah paid $4.40 for 2 pounds of apples and 4 pounds of oranges.

Now,

According to the statement form the equation for monica and sarah .

Let the apples price be $x and oranges price be $y for both of them .

Firstly ,

For monica

2x + 2y = $3.20..............1

Secondly,

For sarah,

2x + 4y = $4.40..............2

Solve 1 and 2 to get the price of 1 pound of oranges and apples .

Subtract 1 from 2

2y = $1.20

y = $0.60

Thus the price of one pound of orange is $0.60 .

So,

Price for 3 pounds of dollars

3 *$0.60

= $1.80

So the price of 3 pounds of oranges will be $1.80 . Thus option B is correct .

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Answer:

C. Yes, she used stratified random sampling.

Explanation :

Stratified random sampling is a random method of sampling where researcher divided the population into sub group and the randomly select from these group to find the final sample.

Answer:

C

Step-by-step explanation:

Answer:

46.28

Step-by-step explanation:

i did pemdas

Vector a = (3, 2), then;

Also, vector b = (-5, 6), then;

Then, -3a + 2b = (-9, -6) + (-10, 12)

The answer is (-19,6)

The confidence interval for the given numbers, with a sample proportion of 0.88 and a confidence level of 0.94, is approximately (0.798, 0.962) when rounded to two decimal places.

To calculate the confidence interval for a random sample with a sample proportion of 0.88 and a confidence level of 0.94, we can use the formula:

\[ \text{Confidence Interval} = \text{Sample Proportion} \pm \text{Margin of Error} \]

The margin of error can be calculated using the formula:

\[ \text{Margin of Error} = \text{Critical Value} \times \text{Standard Error} \]

The critical value can be obtained from the Z-table or calculated using the inverse cumulative distribution function for the standard normal distribution.

Since the level of difficulty is set to 2, we can assume a two-tailed test. The critical value for a 94% confidence level with a two-tailed test is approximately 1.99.

The standard error can be calculated using the formula:

\[ \text{Standard Error} = \sqrt{\frac{\text{Sample Proportion} \times (1 - \text{Sample Proportion})}{\text{Sample Size}}} \]

Plugging in the values:

Sample Proportion (\( p \)): 0.88

Sample Size (\( n \)): 53

Confidence Level: 0.94

Critical Value (\( z \)): 1.99

We can calculate the standard error:

\[ \text{Standard Error} = \sqrt{\frac{0.88 \times (1 - 0.88)}{53}} \]

Now, we can calculate the margin of error:

\[ \text{Margin of Error} = 1.99 \times \text{Standard Error} \]

Finally, we can calculate the confidence interval:

\[ \text{Confidence Interval} = 0.88 \pm \text{Margin of Error} \]

Calculating the values:

Standard Error ≈ 0.041

Margin of Error ≈ 0.082

Confidence Interval ≈ (0.798, 0.962)

Therefore, the confidence interval for the given numbers, with a sample proportion of 0.88 and a confidence level of 0.94, is approximately (0.798, 0.962) when rounded to two decimal places.

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The height of Misha’s younger brother is 72 x 1/2

An equation is an expression that can be used to show the relationship between two or more numbers and variables.

Given that Misha brother is exactly half of her dad’s height. Hence:

Misha brother height = 72 * 1/2

The height of Misha’s younger brother is 72 x 1/2

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Answer:

The height is 72 x 1/2

Step-by-step explanation:

I'm sorry if I did it incorrect, I'm just trying to get points and brainliest :)

Answer:The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

A rectangular garden has a walkway around it

1. The area of the garden is 4(4.5 x + 1.5)

2. The combined area of the garden and the walkway is 5.5(8 x + 4)

We need to find the area of the the walkway

To find the area of the walkway by subtracting the area of the

rectangle from the combined area

∵ The combined area = 5.5(8 x + 4) ⇒ simplify it

∴ The combined area = 5.5(8 x) + 5.5(4)

∴ The combined area = 44 x + 22

∵ The area of the garden = 4(4.5 x + 1.5) ⇒ simplify it

∴ The area of the garden = 4(4.5 x) + 4(1.5)

∴ The area of the garden = 18 x + 6

Now subtract the area of the garden from the combined area

∵ Area of the walkway = (44 x + 22) - (18 x + 6)

∴ Area of the walkway = 44x + 22 - 18 x - 6

- Add like terms

∴ Area of the walkway = (44 x - 18 x) + (22 - 6)

∴ Area of the walkway = 26 x + 16

The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

Answer:

20$

Step-by-step explanation:

50 - (2x - 10) = x

50 + 10 = x + 2x

60 = 3x

60/3 = x

20 = x

The code creates a scatter plot of the "gamble" variable on the "income" variable, with different plotting symbols based on sex, using the "faraway" package in R.

Here's the code to make a plot of the "gamble" variable on the "income" variable using different plotting symbols based on the sex in R:

# Load the required package and data

library(faraway)

data(teengamb)

# Create a plot of a gamble on income with different symbols for each sex

plot(income ~ gamble, data = teengamb, pch = ifelse(sex == "M", 16, 17),

    xlab = "Gamble", ylab = "Income", main = "Gamble on Income by Sex")

legend("topleft", legend = c("Female", "Male"), pch = c(17, 16), bty = "n")

This code will create a scatter plot where the "income" variable is plotted against the "gamble" variable. The plotting symbols used will be different depending on the "sex" variable.

Females will be represented by an open circle (pch = 17), and males will be represented by a closed circle (pch = 16). The legend will indicate the corresponding symbols for each sex.

Make sure to have the "faraway" package installed in R and load it using 'library'(faraway) before running this code.

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Answer:  -∞ < x < ∞

Step-by-step explanation:

      The domain is all the x-values, or inputs, of a function. The range is the y-values, or outputs, of a function.

       In this case, we are looking for the x-values of the function. Since the function will keep going "out forever" in both directions, the answer should be the fourth option;

             - ∞ < x < ∞

The first step that we must take to solving this problem is to fully understand what the problem statement is asking from us and what is given us to solve the problem.  Looking at the problem statement, we can see that they are asking us to determine what the domain of the function is in the graph that was provided.  However, first of all, let us define what domain is.

Looking back at our problem, we can see that this is similar to the example that was provided in the definition.  We can see that the parabola reaches out to both positive and negative infinity in the x-direction but at a slope. Although we can only see it reach -2 and 6 we know that the parabola continues going on even after that.  

Therefore, looking at the options that were provided option D, -∞ < x < ∞ would be the best fit as it showcases that x reaches from negative infinity to positive infinity.

a) We can compare the functions about their transformations, there are some rules of translation/transformation:

*f(x)+b shifts the function b units upward

*f(x)-b shifts the function b units downward

f(x+b) shifts the function b units to the left

f(x-b) shifts the function b units to the right

-f(x) reflects the function in the x-axis.

By this, we can say that g(x) is 3 units upward f(x). h(x) is 4 units upward f(x).

k(x) is 1 unit downward f(x).

b) By the same rules, we can say that (x) is translated 2 units to the left.

s(x) is translated 4 units to the left.

q(x) is translated 2 units to the right.

Answer:

4a+4

Step-by-step explanation:

12a+8-8a-4

4a+4

Answer:

4(a+1)

Step-by-step explanation:

Need to expand first

= 12a + 8 - 8a - 4

Group like terms

= 12a - 8a + 8 - 4

Solve

= 4a + 4

Can factorize

= 4(a + 1)

The best estimate for the value of the instantaneous rate of change of V(t) at t = 2 seconds can be determined using option d) (V(2.01) - V(1.09))/(0.02). This estimate involves taking the difference in the volume values at two nearby time points (2.01 and 1.09 seconds) and dividing it by the difference in time (0.02 seconds).

To estimate the instantaneous rate of change of V(t) at t = 2 seconds, we need to calculate the difference in volume values at two nearby time points and divide it by the difference in time between those points. Option d) (V(2.01) - V(1.09))/(0.02) provides this calculation. By considering the volume values at t = 2.01 and t = 1.09 seconds, we obtain an estimate for the change in volume over a small time interval of 0.02 seconds. Dividing this change in volume by the time interval gives us the average rate of change of V(t) over that interval. As the time interval becomes smaller, this average rate of change becomes a better estimate for the instantaneous rate of change at t = 2 seconds. Therefore, option d) provides the best estimate for the value of the instantaneous rate of change of V(t) at t = 2.

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The solution to the equation is x = -2, -1.46, -1, x = 5.46

From the question, we have the following parameters that can be used in our computation:

0 = x^{5}+x^{4}-20x^{3}-68x^{2}-80x-32

Express properly

So, we have

x^5 + x^4 - 20x^3 -68x^2 -80x - 32 = 0

Next, we plot the graph of x^5 + x^4 - 20x^3 -68x^2 -80x - 32 = 0 to determine the solution graphically

See attachment for graph

From the graph, we have

x = -2, -1.46, -1, x = 5.46

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