Answer:
c
Step by step explanation: Linear equations don't have exponents, so that makes option c nonlinear
Scalar multiplication of a vector written in terms of i and j
ex:
v = 5i + 4j
Find: 6v
Find: -3v
The value of vector 6v is equal to 30i + 24j and value of vector -3v is equal to -15i - 12j.
Scalar multiplication of a vector written in terms of i and j means multiplying a vector by a scalar value, which scales the vector's magnitude while retaining its direction. To perform scalar multiplication of a vector, we simply multiply each component of the vector by the scalar value.
For example, suppose we have a vector v = 5i + 4j. To find 6v, we multiply each component of v by 6 to get 6v = (65)i + (64)j = 30i + 24j.
Similarly, to find -3v, we multiply each component of v by -3 to get -3v = (-35)i + (-34)j = -15i - 12j.
In both cases, we are scaling the original vector v by a factor of 6 and -3, respectively. The resulting vectors have the same direction as v, but their magnitudes are scaled accordingly.
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The mean SAT score in mathematics is 554. The standard deviation of these scores is 39. A special preparation course claims that the mean SAT score, HI, of its graduates is greater than 554. An independent researcher tests this by taking a random sample of 60 students who completed the course; the mean SAT score in mathematics for the sample was 567. At the 0.01 level of significance, can we conclude that the population mean SAT score for graduates of the course is greater than 5542 Assume that the population standard deviation of the scores of course graduates is also 39. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H. μ a р H.: 0 H: 0 х S ê 0. DO (b) Determine the type of test statistic to use. (Choose one) ロ=口 OSO 020 (c) Find the value of the test statistic. (Round to three or more decimal places.) O . $ ?
(d) Find the p-value. (Round to three or more decimal places.) 0 (e) Can we support the preparation course's claim that the population mean SAT score of its graduates is greater than 554? Yes No
We have the following details
mean = 554
n = 60
bar x = 567
alpha = 0.01
How to solve for the hypothesisA. h0. u = 554
H1. u > 554
B. Given that the standard deviation is known what we have to make use of is the independent z test
test statistics calculation
567-554/(39/√60)
= 2.582
d. at alpha = 0.01 and test statistics = 2.582, the value of the p value = 0.0049
0.0049 < 0.01. So we have to reject the null hypothesis.
e. Yes We have to accept that we support the preparation course's claim that the population mean SAT score of its graduates is greater than 554
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Given the following code fragment, which of the following expressions is always true?
int x;
scanf("%d", &x);
A) if( x = 1)
B) if( x < 3)
C) if( x == 1)
D) if((x/3) > 1)
If the expressions given, only C) if( x == 1) is always true.
In the given code fragment, the value of x is read from the user using the scanf() function. The value of x can be any integer value, depending on what the user enters. After the value of x is read, the program checks the value of x using a conditional statement (if statement) and executes the code inside the if statement only if the condition is true.
Expression A) if( x = 1) assigns the value 1 to x and then checks if x is true. This means that the condition is always true, because the assignment operation (=) returns the assigned value (in this case, 1), which is a non-zero value and therefore considered true in C programming.
Expression B) if( x < 3) checks if x is less than 3. This expression is not always true, as x can be any value greater than or equal to 3, in which case the condition would be false.
Expression C) if( x == 1) checks if x is equal to 1. This expression is always true if the user enters the value 1 for x.
Expression D) if((x/3) > 1) checks if the integer division of x by 3 is greater than 1. This expression is not always true, as x can be any value less than or equal to 3, in which case the result of the integer division by 3 would be 1 or less, in which case the condition would be false.
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the only expression that is always true in this code fragment is option C) if( x == 1).
The expression that is always true in this code fragment is option C) if( x == 1).
Option A) if( x = 1) is not always true because it is an assignment statement instead of a comparison statement. It assigns the value 1 to x instead of checking if x is equal to 1.
Option B) if( x < 3) is also not always true because x could be any number less than 3.
Option D) if((x/3) > 1) is not always true because x could be any number less than or equal to 3, in which case the expression would evaluate to false.
Therefore, the only expression that is always true in this code fragment is option C) if( x == 1).
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I will give brainliest on the first answer: If x = -3, then what is x + 11?
Answer:
8
Step-by-step explanation:
Replace x with -3:
(-3)+11=8
Rewrite the following polynomial in standard form.1+ 10x − 2x³ + x5-x^2-9
Hello!
We have the following polynomial:
\(1+10x-2x^3+x^5-x^2-9\)To put it in the standard form, we have to start with the highest exponent on the left and then write in decreasing order. Look:
\(\begin{gathered} x^5-2x^3-x^2+10x-9+1 \\ \end{gathered}\)We can simplify it by solving -9 +1, look:
\(x^5-2x^3-x^2+10x-8\)y=1/2x -2
x:0,1,2
y:
Answer:
Combine 1/2 and x.
y=x/2−2
( 0, -2) , (1 , -3/2) , ( 2, -1 )
Step-by-step explanation:
Find the area of this regular polygon. (Round to one decimal spot if necessary)
the area of a regular polygon is
A = p x a/2
where p is the perimeter of the polygon,
a is the apothem.
p = sn
n is the number of sides
s is the sides length
p = 6.7 x 7
p = 46.9
therefore,
A = 46.9 x 7/2
A = 328.3/2
A = 164sq.u
Midpoint And Distance in the Coordinate Plane
1. What is the length of AB with endpoints A(3,2) and B (8,14)
*13*
2. What is the midpoint of AB, with endpoints A (3,2) and B (8,14)?
*(5.5,8)*
3. ABC has vertices A(1,5), B(9,7),and C (7.13). M is the midpoint of AB. And N is the midpoint of BC. Which of the following is the length of MN?
*5*
Question 1
\(\sqrt{(3-8)^2 +(2-14)^2}=13\)
Question 2
\(\left(\frac{3+8}{2}, \frac{2+14}{2} \right)=(5.5, 8)\)
Question 3
\(M=\left(\frac{1+9}{2}, \frac{5+7}{2} \right)=(5, 6) \\ \\ N=\left(\frac{9+7}{2}, \frac{7+13}{2} \right)=(8, 10) \\ \\ MN=\sqrt{(8-5)^2 + (10-6)^2}=5\)
What is the intermediate step in the form (x + a)² = b as a result of
completing the square for the following equation?
x² + 6x = -201
The intermediate step in the form (x + a)² = b as a result of
completing the square for the following equation?
x² + 6x = -201 can be said to be (x + a)² = b which is (x + 3)² = -192
How do you calculate the intermediate step in completing the square?To calculate the intermediate step in completing the square, you need to do the following steps:
Take the original quadratic equation and isolate the squared term on one side and all other terms on the other side.
Add half of the coefficient of the x term squared to both sides to create a perfect square trinomial.
Factor the perfect square trinomial and simplify.
For example, consider the quadratic equation x^2 + 6x + 8 = 0.
Isolate the squared term on one side: x^2 + 6x = -8
Add half of the coefficient of the x term squared to both sides: x^2 + 6x + (6/2)^2 = -8 + (6/2)^2
Factor the perfect square trinomial and simplify: (x + 3)^2 = 1
Consequently, the intermediate step in completing the square for the equation x² + 6x = -201 is:
(x² + 6x + 9) = (-201 + 9)
(x + 3)² = -192
So, (x + a)² = b is (x + 3)² = -192
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EFGH is a parallelogram. Find the measure of EG. parallelogramefghmsidesw7 The measure of EG is .
Answer: EG = 80
Step-by-step explanation: A parallelogram is a quadrilateral with opposite sides parallel to each other.
The diagonals of a parallelogram bisect each other, which means, using the figure as example:
EJ = JG
So, to determine EG, first find w:
\(4w+4=2w+22\)
\(2w=18\)
w = 9
Substituting:
\(EJ=4w+4\)
\(EJ=4(9)+4\)
EJ = 40
Since each segment has the same measure:
EG = 2EJ
EG = 2(40)
EG = 80
The measure of EG is 80 units
f(x)=-4x-6 and g(x)=3x+5. Find (f o g)(-3) plzzzzzzzzzzz helpppppppp
Answer:
(f o g)(-3) = 10Step-by-step explanation:
f(x) = - 4x - 6
g(x)=3x+5
To find (f o g)(-3) we must first find
(f o g)(x)
To find (f o g)(x) substitute g(x) into f(x) that's for every x in f (x) replace it with g (x)
That's
(f o g)(x) = - 4( 3x + 5) - 6
= - 12x - 20 - 6
(f o g)(x)= - 12x - 26
Now to find (f o g)(-3) substitute the value of x that's - 3 into (f o g)(x) and solve
We have
(f o g)(-3) = - 12(-3) - 26
= 36 - 26
We have the final answer as
(f o g)(-3) = 10
Hope this helps you
Justin is 74 inches and casts a shawdow that is 102 inches long. At the same time , a tree casts a shadow that is 39 feet long. How tall is the tree to the nearest foot?
Answer:
The tree is 28 feet in height.
Step-by-step explanation:
This is a proportion problem. You need to keep the height of the objects on one side of the ratios and the length of the shadows on the other.
74 / x = 102/39 Cross Multiply
102x = 74*39 The inches as a unit cancel out.
102x = 2886 Divide by 102
x = 2886/102
x = 28.29 feet
Let x(l) be a band-limited signal with absolute bandwidth B Hz For each of the signals below determine whether the signal is absolutely band-limited, and if so, express the Nyquist sampling rate for the signal in terms of B (a) x(0)+x(t-1) dx(t) dt (o) x) Justify your answers.
Signal a) is not absolutely band-limited and so, its Nyquist sampling rate cannot be determined. Signal b) is absolutely band-limited with an absolute bandwidth of B Hz, and its Nyquist sampling rate is 2B.
Let x(l) be a band-limited signal with absolute bandwidth B Hz. For each of the signals below, we need to determine whether the signal is absolutely band-limited, and if so, express the Nyquist sampling rate for the signal in terms of B.
a) x(0) + x(t - 1)dx(t)dt:For this signal, let us apply the Fourier transform. The Fourier transform of the first term is 2πX(ω)δ(ω), and that of the second term is e^(-jω)X(ω).
Thus, X(ω) = 2πX(ω)δ(ω) + e^(-jω)X(ω)On rearranging this expression, we get: X(ω) = [1 / (1 - 2πδ(ω))]e^(-jω)Therefore, the signal is not absolutely band-limited because it has components at all frequencies.
Hence, the Nyquist sampling rate cannot be determined.b) x:For this signal, let us consider its Fourier transform. Its Fourier transform will be a scaled version of the Dirac comb function, centered at ω = 0, with a spacing of 2π. Hence, X(ω) = 2πBδ(ω).
The signal is absolutely band-limited with absolute bandwidth B Hz, and hence, the Nyquist sampling rate will be 2B. The Nyquist sampling rate is twice the absolute bandwidth, and so, the sampling rate for this signal will be 2B Hz.
Thus, the answer to the question is as follows:Signal a) is not absolutely band-limited and so, its Nyquist sampling rate cannot be determined. Signal b) is absolutely band-limited with an absolute bandwidth of B Hz, and its Nyquist sampling rate is 2B.
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I need help ASAP!!! Please explain your answer
Answer:
804.2 km³
Step-by-step explanation:
Volume of a cylinder: πr²h
r = radius, h = height
\(\pi r^2h\\\pi(8)^2(4)\\\pi(64)(4)\\\pi(256)\\804.2\)
25°
y
х
30°
x= [ ? 1°
Answer:
hello
how are you?
x=125
y=55
Suppose NiceGirl is the set of all nice girls, Sailor is the set of all sailors, and loves is a relation between nice girls and sailors such that n loves s means that nice girls n loves sailor s. Make precise the sentence "All the nice girls love a sailor" to expose at least two distinct meanings of this ambiguous utterance.
The sentence "All the nice girls love a sailor" can be interpreted in at least two different ways when it comes to the given sets Nice Girl and Sailor and the relation loves between them.
They are: All the nice girls love the same sailor. This interpretation would mean that there exists a sailor s ∈ Sailor such that all the girls in the set Nice Girl love s, i.e., ∀n ∈ Nice Girl, n loves s. This interpretation assumes that there is only one sailor that is loved by all the nice girls.
2. Each of the nice girls loves a different sailor. This interpretation would mean that for every girl n ∈ Nice Girl, there exists a sailor s ∈ Sailor such that n loves s, but s may be different for different girls. This interpretation assumes that each nice girl loves a different sailor.
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The first three terms of a sequence are given. Round to the nearest thousand (if necessary). 9, 18, 36 Find the 6th term.
Ex. 900. x(t)= C0 + C1*sin(w*t+theta1) + C2*sin(2*w*t+theta2)
x(t)= A0 + A1*cos(w*t) + B1*sin(w*t) + A2*cos(2*w*t) + B2*sin(2*w*t)
A0= 2, A1=-8, B1=-7, A2=-2, B2=-7, w=600 rad/sec.
Express all angles between plus and minus 180 degrees.
Determine C0, C1, theta1 (deg), C2, theta2 (deg)
The final values of the angles are:
C0 = A0 = 2
C1 = B1 = -7
theta1 = 0 degrees
C2 = B2 = -7
theta2 = 0 degrees
Here, we have,
To determine the values of C0, C1, theta1 (in degrees), C2, and theta2 (in degrees), we need to match the given expressions for x(t) with the given values for A0, A1, B1, A2, B2, and w.
Comparing the expressions:
x(t) = C0 + C1sin(wt+theta1) + C2sin(2wt+theta2)
x(t) = A0 + A1cos(wt) + B1sin(wt) + A2cos(2wt) + B2sin(2w*t)
We can match the constant terms:
C0 = A0 = 2
For the terms involving sin(wt):
C1sin(wt+theta1) = B1sin(w*t)
We can equate the coefficients:
C1 = B1 = -7
For the terms involving sin(2wt):
C2sin(2wt+theta2) = B2sin(2wt)
Again, equating the coefficients:
C2 = B2 = -7
Now let's determine the angles theta1 and theta2 in degrees.
For the term C1sin(wt+theta1), we know that C1 = -7. Comparing this with the given expression, we have:
C1sin(wt+theta1) = -7sin(wt)
Since the coefficients match, we can equate the arguments inside the sin functions:
wt + theta1 = wt
This implies that theta1 = 0.
Similarly, for the term C2sin(2wt+theta2), we have C2 = -7. Comparing this with the given expression, we have:
C2sin(2wt+theta2) = -7sin(2w*t)
Again, equating the arguments inside the sin functions:
2wt + theta2 = 2wt
This implies that theta2 = 0.
Therefore, the final values are:
C0 = A0 = 2
C1 = B1 = -7
theta1 = 0 degrees
C2 = B2 = -7
theta2 = 0 degrees
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By Simpson's rule, find the value of (tn 3/2) approximatally, dividing the range into (10) equal intervals. a) 0.4054 b) 0.4554 c) 0.4454
By applying Simpson's rule with 10 equal intervals, the approximate value of (tn 3/2) is 0.4454. The correct option is c.
Simpson's rule is a numerical integration method used to estimate the definite integral of a function over a given interval. It is based on approximating the curve by a series of quadratic polynomials. In this case, we are interested in finding the value of (tn 3/2), where n represents the interval number and tn is the midpoint of each interval.
To apply Simpson's rule, we need to divide the range into an even number of equal intervals. In this case, we have 10 equal intervals. The formula for approximating the definite integral using Simpson's rule is as follows:
∫(a to b) f(x) dx ≈ (h/3) [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + ... + 2f(xn-2) + 4f(xn-1) + f(xn)],
where h is the step size (interval width) and x0, x1, x2, ..., xn are the evenly spaced points within the interval.
By substituting the given function (tn 3/2) into the formula and performing the calculations, the approximate value is found to be 0.4454. Therefore, option c) 0.4454 is the closest approximation of (tn 3/2) using Simpson's rule with 10 equal intervals.
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A person standing close the the edge on the top of a 80 foot building throws a baseball vertically upward. the quadratic function h(t) = -8t^2 + 32t + 80 models the ball's height above the ground, h(t), in feet, t seconds after it was thrown.
How do I efficiently determine...
-- how many seconds it takes until the ball reaches max height
-- the maximum height
-- how many seconds it takes until the ball hits the ground
without graphing?
The number of seconds it takes until the ball reaches max height is 2 seconds and the maximum height is 112 feet, and the number of seconds it takes until the ball hits the ground will be 6.9 seconds.
What is a projectile motion?When a body is thrown in the air then the motion under the gravity is known as projectile motion.
A person standing close the the edge on the top of a 80 foot building throws a baseball vertically upward. the quadratic function
h(t) = -8t² + 32t + 80 models the ball's height above the ground, h(t), in feet, t seconds after it was thrown.
The number of second to reach at maximum height will be
We know that at maximum height, the rate will be zero. Then we have
h'(t) = 0
-16t + 32 = 0
t = 2 seconds
Then the maximum height will be
h(t) = -8(2)² + 32 x 2 + 80
h(t) = -32 + 64 +80
h(t) = -32 + 144
h(t) = 112 feet
Then the number of the seconds to reach at the ground will be
-8t² + 32t + 80 = -80
-8t² + 32t + 160 =0
t² - 4t - 20 = 0
Then t will be
\(\rm t = \dfrac{-(4) \pm \sqrt{(-4)^2 - 4 * 1 * -160}}{2*1}\)
Then we have
t = 6.9 and -2.9
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5 pts For the following exercise, graph the given ellipses, noting the center, vertices, and foci. (y+1)² 5 = 1 NIEU +
The given equation represents an ellipse with a center at (-1, 0), a vertical major axis, and a minor axis length of √5. The vertices are located at (-1, ±√5) and the foci are at (-1, ±√4).
The equation of the ellipse is given in the form (y - k)²/a² + (x - h)²/b² = 1, where (h, k) represents the center of the ellipse, a is the length of the semi-major axis, and b is the length of the semi-minor axis.
Comparing the given equation, (y + 1)²/5 = 1, with the standard form, we can determine that the center of the ellipse is (-1, 0). The equation indicates a vertical major axis, with the value of a² being 5, which means that the semi-major axis length is √5.
The vertices of the ellipse can be found by adding and subtracting the length of the semi-major axis (√5) to the y-coordinate of the center. Therefore, the vertices are located at (-1, ±√5).
To find the foci of the ellipse, we can use the relationship c² = a² - b², where c represents the distance from the center to the foci. Since the minor axis length is 1, we have b² = 1, and substituting the values, we find c² = 5 - 1 = 4. Taking the square root, we get c = ±√4 = ±2. Therefore, the foci are located at (-1, ±2).
In conclusion, the given equation represents an ellipse with a center at (-1, 0), vertices at (-1, ±√5), and foci at (-1, ±2).
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Figure ABCD is rotated by 180 degrees about the origin in the counterclockwise direction to obtain figure A'B'C'D': Which statement best compares the lengths of the sides of the two figures? (5 points)
Since the figure was rotated, the image figure has the same corresponding sides, the thing that changed was the position of the points and the figure but not the length of the sides.
First, we identify corresponding sides (equal sides). This is shown in the following image by drawing corresponding sides in the same color:
As we can see, the length of side AB is equal to the length of side A'B', because they are corresponding sides.
Anwer:
\(\text{Length AB=Length A'B'}\)find the absolute maximum value of g(x)=−2x2 x−1 over [−3,5].
To find the absolute maximum value of the function g(x)=−2x^2/x−1 over the closed interval [−3,5], we will use the Extreme Value Theorem (EVT).EVT states that if a function is continuous over a closed interval, then the function will have an absolute maximum and minimum over that interval.
So, for finding the absolute maximum value of the given function, we will follow these steps:Step 1: Check the function's domain.We know that the denominator of the function g(x) is x - 1, so the function is not defined at x = 1. However, the closed interval we are working with is [-3, 5], which does not include x = 1. Hence, the function is defined over this interval.Step 2: Find the critical points of the functionTo find the critical points, we need to differentiate the function g(x) and equate it to zero:g'(x) = (-4x(x-1) + 2x^2)/(x-1)^2= 2x(3-x)/(x-1)^2=0So, the critical points of g(x) are x = 0 and x = 3.Step 3: Find the end-point values of the functiong(-3) = -2/5, g(5) = -50/9.
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Linear or nonlinear?
Answer: It's linear
Step-by-step explanation:
X is increasing by 1, while y is decreasing by .2
X= 1, y= .2
576+367 having trouble
Answer:943
Step-by-step explanation:ask Siri or just add those numbers
HELP QUICK
(question in picture)
Answer:
Step-by-step explanation:
There’s a total of 10+16+20+18 = 64 candies.
There’s 10 red candies.
10 / 64 = 0.15625
Rounded: 0.2
what is the domain and range of The function f : {4, 6, 8} → {2, 3} is defined as {(4, 2), (6, 2), (8, 2)}.
The definition of the domain of the function f: {4, 6, 8} ⇒{2, 3} over {(4, 2), (6, 2), (8, 2)} is given as {4,6,8}, while the range is given as 2.
What is function?A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output. Four main categories can be used to classify different sorts of functions. One to one function, many to one function, onto function, one to one and into function—all based on the element. A relation between a domain and range is called a function when each value in the domain only has one value in the range.
Here,
function f : {4, 6, 8} → {2, 3} is defined as {(4, 2), (6, 2), (8, 2)},
domain={4,6,8}
range={2}
The domain of function f : {4, 6, 8} → {2, 3} is defined as {(4, 2), (6, 2), (8, 2)} will be {4,6,8} and range will be {2}.
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Determine the number of elements of order 15 and the number of cyclic subgroups of order 15 in Z30 ⊕ Z20.
The number of elements of order 15 in Z30 ⊕ Z20 is 8, and the number of cyclic subgroups of order 15 is 8.
In Z30 ⊕ Z20, the elements can be represented as pairs (a, b) where a belongs to Z30 and b belongs to Z20. The order of an element (a, b) in Z30 ⊕ Z20 is determined by the least common multiple (LCM) of the orders of a and b.
To find the elements of order 15, we need to consider pairs (a, b) where the LCM of the orders of a and b is 15. Since the order of any element in Z30 is a divisor of 30 and the order of any element in Z20 is a divisor of 20, we need to find pairs (a, b) where the LCM of a divisor of 30 and a divisor of 20 is 15.
There are 8 such pairs: (0, 15), (0, 5), (10, 0), (10, 15), (20, 0), (20, 5), (20, 10), and (20, 15). Each of these pairs represents an element of order 15 in Z30 ⊕ Z20.
The number of cyclic subgroups of order 15 is equal to the number of elements of order 15, which is also 8. Each element of order 15 generates a cyclic subgroup of order 15.
Therefore, in Z30 ⊕ Z20, there are 8 elements of order 15 and 8 cyclic subgroups of order 15.
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twinks are a social experiment
Answer:
Step-by-step explanation:
whT
can you guys please help me solve these
Answer:
See explanation below
Step-by-step explanation:
In all cases you need to isolate x on one side of the inequality symbol using inverse operations.
1.-
\(15+x\leq -45\\15-15+x\leq -45-15\\x\leq -60\)
where we subtracted from both side 15 in order to leave x by itself on the left.
2.-
\(x-14>12\\x-14+14>12+14\\x>26\)
where we added 14 in order to isolate x on the left
3.-
In this case we need to divide both sides by -5 in order to isolate the x which is being multiplied by the factor -5, but he have to recall that multiplying or dividing by a negative number changes the direction of the inequality symbol (in our case from < into > )
\(-5x<35\\\frac{-5\,x}{-5} >\frac{35}{-5} \\x>-7\)
4.-
\(2x>-42\\\frac{2\,x}{2} >\frac{-42}{2} \\x>-21\)
In this case we simply divide both sides by two, and there is no change in the direction of the inequality because the number we are using to divide is a positive number (2)