The bag would move in the direction of the applied force.
What is the direction?
Recall that work is done when the force applied moves a distance in the direction of the force. In this case, we can see that the force was applied from the right. Do not also forget that the force applied must make the object to move in a given direction. The direction in which the acceleration is imparted must also be in the direction of the force.
The understanding of the impact of force on motion could be seen from the Newtons law. We know from the Newton’s law that an object would remain at rest or in a state of uniform motion unless it I acted upon by an external force. This external force makes the object to move in the direction of the force.
Looking at the question, we are told that a 20 newtons is applied from the right hence, the bag would move in the direction of the applied force.
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2. The muscles on the right side of your body are controlled by what part of your brain? the right cortex the right hemisphere the left cortex the left hemisphere
Answer:
Motor cortex
Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).
Explanation:
The tortoise and the hare A tortoise and a hare run to the East. The hare knows that it is faster, so it gives the tortoise a 30-meter head start. The tortoise is moving east at 1 m/s and the hare is moving east at 4 m/s.
The time taken for the hare to catch up with the tortoise is 10 seconds.
What is the time taken for the hare to catch the tortoise?
The time taken for the hare to catch up with the tortoise is calculated by applying the principle of relative velocity as shown below.
Distance travelled by hare + Distance travelled by tortoise = Total distance
V₁t + V₂t = d
where;
V₁ is the velocity of hareV₂ is the velocity of tortoiset is the time taken for them to meetd is the distance between themSince they are moving in the same direction, the relative velocity becomes
V₁t - V₂t = d
(V₁ - V₂)t = d
(4 - 1)t = 30
3t = 30
t = 30/3
t = 10 seconds
Thus, the time taken for the hare to catch up with the tortoise is 10 seconds.
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The complete question is below:
A tortoise and a hare run to the East. The hare knows that it is faster, so it gives the tortoise a 30-meter head start. The tortoise is moving east at 1 m/s and the hare is moving east at 4 m/s. At what time does the hare catch up with the tortoise?
In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?
According to the diagram the equivalent resistance of the group is
40.05 ohms
How to find the equivalent resistanceThe equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1
Resistors in parallel is solved by
Resistors in parallel = 1/25.4 + 1/70.8
Resistors in parallel = 0.0535 ohms
Equivalent resistance
Equivalent resistance = Resistors in parallel + Resistor in series
Equivalent resistance = 0.0535 + 40
Equivalent resistance = 40.0535
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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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A 10 KVA, 380 V, 50 Hz, 3-phas, star-connected salient pole alternator has direct axis and quadrature axis reactances of 12 ohms and 8 ohms respectively. The armature has resistance of 1 ohin per phase, The generator delivers rated load at 0.8 p,f lagging with the terminal voltage being maintained at rated value. If the load angle is 16.15, determine (i) the direct axis and quadrature axis components of armature current, (b) excitation voltage of the generator.
Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
Given:
Apparent power (S) = 10 KVA = 10,000 VA
Line voltage (V) = 380 V
Frequency (f) = 50 Hz
Xd = 12 ohms
Xq = 8 ohms
Ra = 1 ohm
Power factor (pf) = 0.8 lagging
Load angle (δ) = 16.15 degrees
(i) Armature current's direct axis and quadrature axis components
We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:
S = 3Vphase Iphase cos(φ)
Iphase = S / (3Vphase cos(φ))
For a lagging power factor, cos(φ) = 0.8, so
Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A
The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current. Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:
Id = (VL - IaRa) / Xd
Iq = (VL - IaRa) / Xq
where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,
Ia = Iphase / √3 = 10.46 / √3 = 6.03 A
Substituting the given values:
Id = (380 - 6.03 x 1) / 12 = 30.28 A
Iq = (380 - 6.03 x 1) / 8 = 46.92 A
(ii) Excitation voltage of the generator:
The excitation voltage (E) of the generator is given by:
E = Vphase + IqXq
Substituting the given values:
E = 380 + 46.92 x 8 = 765.36 V
Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
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Which type of muscle cell can have multiple nuclei
Answer:
Skeletal muscle cells
Explanation:
Skeletal muscle cells are long, cylindrical, and striated. They are multi-nucleated meaning that they have more than one nucleus. This is because they are formed from the fusion of embryonic myoblasts.
pls mark me the brainliest
What is the best flowers
Answer:
What are the best flowers? (My opinion)
Water liliesWhite rosesHydrangeaExplanation:
You're welcome.
Answer:
Tulips,
Lilies,
Lotuses on my opinion...
A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How long was the stone in the air before hitting the ground? How far did the rock land from the edge of the cliff?
Answer:
Substitute the numbers for YOUR problem this is NOT the answer.
Explanation:
An archer practicing with an arrow bow shoots an arrow straight up two times. The first time the initial speed is vi and second
time he increases the initial sped to 4v. How would you compare the maximum height in the second trial to that in the first trial?
Answer:
The maximum height reached in the second trial is 16times the maximum height reached in the first trial.
Explanation:
The following data were obtained from the question:
First trial
Initial speed (u) = v
Final speed (v) = 0
Second trial
Initial speed (u) = 4v
Final speed (v) = 0
Next, we shall obtain the expression for the maximum height reached in each case.
This is illustrated below:
First trial:
Initial speed (u) = v
Final speed (v) = 0
Acceleration due to gravity (g) = 9.8 m/s²
Height (h₁) =.?
v² = u² – 2gh₁ (going against gravity)
0 = (v)² – 2 × 9.8 × h₁
0 = v² – 19.6 × h₁
Rearrange
19.6 × h₁ = v²
Divide both side by 19.6
h₁ = v²/19.6
Second trial
Initial speed (u) = 4v
Final speed (v) = 0
Acceleration due to gravity (g) = 9.8 m/s²
Height (h₂) =.?
v² = u² – 2gh₂ (going against gravity)
0 = (4v)² – 2 × 9.8 × h₂
0 = 16v² – 19.6 × h₂
Rearrange
19.6 × h₂ =16v²
Divide both side by 19.6
h₂ = 16v²/19.6
Now, we shall determine the ratio of the maximum height reached in the second trial to that of the first trial.
This is illustrated below:
Second trial:
h₂ = 16v²/19.6
First trial:
h₁ = v²/19.6
Second trial : First trial
h₂ : h₁
h₂ / h₁ = 16v²/19.6 ÷ v²/19.6
h₂ / h₁ = 16v²/19.6 × 19.6/v²
h₂ / h₁ = 16
h₂ = 16 × h₁
From the above illustrations, we can see that the maximum height reached in the second trial is 16times the maximum height reached in the first trial.
Is altitude abiotic or biotic or neither SCIENCE WORK NEEDED BY 11:59 HELP HELP HLEP
Answer:
abiotic
Explanation:
goggle:)))))))
Which of the following is not a model?
A. an ant farm
B. a bicycle
C. an atlas
D. a plastic human skeleton
Answer:
A ant farm
Explanation:
what branch of physics does a dynamo fall in
Answer: A dynamo falls under the branch of physics known as electromagnetism or electromagnetic physics. Electromagnetism is the study of the relationship between electricity and magnetism and how they interact with each other.
A dynamo is a device that converts mechanical energy into electrical energy using the principles of electromagnetism. It typically consists of a rotating coil of wire (armature) within a magnetic field. As the coil rotates, the magnetic field induces an electric current in the wire through electromagnetic induction.
The operation of a dynamo involves the application of various electromagnetic principles, such as Faraday's law of electromagnetic induction and Lenz's law. Understanding the behavior and functioning of dynamos requires knowledge of electromagnetism, including the principles of magnetic fields, electric currents, electromagnetic induction, and the relationship between electricity and magnetism.
Therefore, the study and analysis of dynamos and their operation fall within the domain of electromagnetism, a branch of physics.
Explanation:)
"You can't see the forest for the trees" might seem an appropriate analogy for astronomers attempting to determine the shape of the Milky Way galaxy when we are in fact located inside the galaxy. Discuss techniques used by astronomers to determine the type of galaxy in which we live, why it is so difficult to determine the shape of our galaxy, and where our Sun is located in our galaxy?
Some of the techniques used by astronomers to determine the type of galaxy in which we live are:
radio, optical, infraredx-ray astronomyWhat is Astronomy?This refers to the study of heavenly bodies and space and other things that space is made up of.
Hence, we can see that the reason why it is so difficult to determine the shape of our galaxy is that astronomers can only infer its presence from the motions of stars in the galaxy, and a precise shape is difficult to be determined.
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Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Answer:
Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Explanation:
Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.
Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his motorcycle after it passes her car?
A.
The frequency of the sound will decrease.
B.
The amplitude of the sound will increase.
C.
The intensity of the sound will increase.
D.
The wavelength of the sound will decrease.
E.
The velocity of the sound will increase.
Answer:
the correct answer is A
Explanation:
This is a doppler effect exercise which is the change in frequency due to the relative movement of the sound source and the observer.
\(f' = f_o \ \frac{v+v_o}{v-v_s}\)
where v₀ is the speed of the observer and v_s the speed of the source, the signs correspond when the two are closing in
with this expression let's analyze the different answers
A) True. The observed change is in the frequency, in this case the two are moving away, so the expression that describes the phenomenon is
\(f'= f_o \ \frac {v-v_o}{ v+v_s}\)
In this case, the speed of the source is greater than the speed of the observer, so when the denominator increases faster than the numerator, consequently the frequency must decrease
B) False. The amplitude does not depend on the relative velocity
C) False. The intensity depends on the distance, by or which when increasing the distance the intensity should decrease
D) False. The speed of sound is a constant, if the frequency decreases the wavelength must increase to maintain equality
E) False. The speed of sound depends on the properties of the propagating medium, not on the relative speed of the source and the observer.
Consequently the correct answer is A
Please help with all three questions
Answer:
The correct answer is D C A
1. At t=0s, a particle moving in the x-y plane with constant acceleration has a velocity ofv; = (3î-2)) m/s, and is at the origin. At t=3s, the particle's velocity is f = (91+7j) m/s. Find (a)the acceleration of the particle (b) Its coordinates at t=3s
Answer:
the particle is at coordinates (18,15/2)
Explanation:
To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:
a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j
So the acceleration of the particle is a = 2i + 3j m/s².
To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:
r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j
We can use the kinematic equations of motion to solve this problem.
Let the acceleration of the particle be a = axî + ayj.
(a) Using the equation of motion v = u + at, where u is the initial velocity:
f = v = u + at
Substituting the given values, we get:
(91+7j) = (3î-2j) + a(3î + 3j)
Equating the real and imaginary parts, we get:
91 = 3a + 3a (coefficients of î are equated)
7 = -2a + 3a (coefficients of j are equated)
Solving these equations simultaneously, we get:
a = î(23/6) + j(1/2)
So the acceleration of the particle is a = (23/6)î + (1/2)j.
(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:
At t = 3s, the displacement of the particle is:
s = ut + (1/2)at^2
Substituting the given values, we get:
s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2
Simplifying, we get:
s = 9î + (17/2)j
So the coordinates of the particle at t=3s are (9, 17/2).
Exit Ticket:
1. A pulley is used to raise crates from a warehouse floor to the top of a stack. The crate's
weight is 650 newtons and the stack is 10 meters tall. You have to pull out 75 meters of
rope to move the crates while you exert a force of 100 Newtons on the rope.
a. How much work do you do on the pulley?
b. How much work does the pulley do on the crate?
c. What is the efficiency of this pulley?
d. What magnitude of energy was converted to heat?
a) You do 7500 Joules of work on the pulley. b) The pulley does 7500 Joules of work on the crate. c) The efficiency of this pulley is 100%. d) since the efficiency is 100%, there is no energy converted to heat.
a. To calculate the work done by pulling out the 75 meters of rope, we use the formula:
Work = Force × Distance
In this case, the force exerted is 100 Newtons, and the distance is 75 meters. Therefore,
Work = 100 N × 75 m = 7500 Joules
b. The work done by the pulley on the crate is equal to the work you do on the pulley. This is because the work done on one end of a pulley is equal to the work done on the other end.
c. Efficiency is the ratio of useful work output to the total work input. In this case, the useful work output is the work done on the crate, which is 7500 Joules. The total work input is the work you do on the pulley, which is also 7500 Joules. Therefore, the efficiency is:
Efficiency = (Useful work output / Total work input) × 100%
= (7500 J / 7500 J) × 100%
= 100%
d. In an ideal situation, where there is no energy loss, all the work done would be converted to useful work. However, in reality, some energy is usually lost as heat due to various factors like friction and mechanical inefficiencies. The magnitude of energy converted to heat can be calculated by subtracting the useful work output from the total work input.
Energy converted to heat = Total work input - Useful work output
= 7500 J - 7500 J
= 0 Joules
All the work input is utilized effectively, resulting in no energy loss.
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A hot-air balloon plus cargo has a mass of 308 kg and a volume of 2910 m3 on a day when the outside air density is 1.22 kg/m3. The balloon is floating at a constant height of 9.14 m above the ground.
Required:
What is the density of the hot air in the balloon?
9514 1404 393
Answer:
1.114 kg/m³
Explanation:
The total mass of the air in the balloon and the balloon + cargo will be the mass of the displaced air. If d is the density of the air in the balloon, then we have ...
2910d +308 = 2910×1.22
Solving for d, we find ...
2910d = 2919(1.22) -308
d = 1.22 -308/2910
d ≈ 1.114 . . . kg/m³
The density of the hot air is about 1.114 kg/m³.
The United States uses only 10% of the world's energy.
True
False
Answer:
False
Explanation:
17%
the answer to your question is false
Participating in __________ can improve flexibility.
A.
yoga
B.
pilates
C.
swimming
D.
all of the above
Answer: Participating in all of the above can improve flexibility.
Explanation:
A practice that helps in improving or developing inherent power in order to bring peace and harmony to the body of a person is called yoga.
Yoga includes different postures that also help in providing flexibility to the body.
Pilates is another method of providing muscular strength and low impact flexibility to a human body.
Swimming also a good exercise that provides flexibility.
Thus, we can conclude that participating in all of the above can improve flexibility.
Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air?
Answer:
Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.
what happened when aniline is treated with benzene diazonium chloride
Answer:
p-aminoazobenzene is formed
Explanation:
The reaction of benzene diazonium chloride and aniline takes place in a basic medium and leads to the formation of an azo compound which is also a dye. The terminal diazonium nitrogen of the benzene diazonium ion is coupled to the aniline at the para-position. The product of the reaction, p-aminoazobenzene is a yellow dye.
Benzene diazonium chloride is prepared by diazotization of aniline in the presence of hydrochloric acid. The full reaction of aniline and benzene diazonium chloride is shown in the image attached to this answer.
Question One
a. Why is it important to calibrate a measuring instrument regularly?
[1 marks]
b. An instrument with a standard signal of 4 mA - 20 mA is installed to measure the volume of
fluid in a cylindrical tank of height 40 m and a diameter of 6 m.
i.
If the sensor for the measurement of the volume should not have a direct contact with
the fluid, what type of sensor would you recommend to be installed?
[1 marks]
ii. Describe how you will calibrate the sensor to be able to measure the minimum and
maximum volume of fluid in the tank.
iii.
iv.
vi.
Attempt all questions.
vii.
[2 marks]
What is the maximum volume of the tank?
[2 marks]
What is the volume of the fluid in the tank if the output signal of the instrument is 14
[2 marks]
mA?
What will be the value of the output signal of the instrument if the volume of the fluid
in the tank is 65% of the maximum capacity of the tank?
[2 marks]
What will be the volume of the fluid if the sensor produces a signal of 17 mA? Express
it as a percentage.
[2 marks]
Comment on the instrument performance if a signal of 15.7 'mA is produced when the
volume of the fluid in tank is 75% of the maximum tank capacity. [2 marks]
type proximity
[1 marks]
c. Distinguish between a capacitive type proximity sensor and an inductive
switch.
a. It is important to calibrate a measuring instrument regularly for the following reasons:
Accuracy: Over time, measuring instruments can drift from their original calibration due to factors such as environmental conditions, wear, and tear, or component aging.
Compliance: In many industries, calibration is a requirement to comply with quality standards, regulations, and certifications.
Confidence: Calibration instills confidence in the measurement results obtained from the instrument.
b. i. If the sensor for measuring the volume of fluid should not have direct contact with the fluid, a suitable sensor would be a non-contact or remote-level sensor. Examples include ultrasonic sensors, radar sensors, or laser distance sensors. These sensors can measure the distance to the fluid surface without physically touching it.
ii. To calibrate the sensor to measure the minimum and maximum volume of fluid in the tank, the following steps can be taken:
Empty Tank Calibration: With the tank completely empty, the sensor should be calibrated to read the minimum volume of fluid, which is 0 m³, or any other reference point desired.
Full Tank Calibration: The tank should be filled to its maximum capacity. The sensor is then calibrated to read the maximum volume of fluid, which is the volume when the tank is at its full capacity.
iii. The maximum volume of the tank can be calculated using its dimensions. The formula for calculating the volume of a cylinder is:
Volume = π * (radius)² * height
Given the diameter (6 m), we can calculate the radius as 6 m / 2 = 3 m.
Maximum Volume = π * (3 m)² * 40 m
iv. The volume of the fluid in the tank can be determined using the linear relationship between the output signal of the instrument and the volume. Since the signal range is from 4 mA to 20 mA, and this range corresponds to the minimum and maximum volume of the tank, we can create a linear equation or calibration curve relating the output signal to the volume.
v. To calculate the volume of the fluid in the tank when the output signal is 14 mA, we use the calibration curve or linear equation obtained during calibration.
vi. To determine the output signal when the volume of the fluid in the tank is 65% of the maximum capacity, we use the calibration curve or linear equation obtained during calibration.
vii. To determine the volume of the fluid when the sensor produces a signal of 17 mA, we use the calibration curve or linear equation obtained during calibration and express the result as a percentage of the maximum capacity of the tank.
c. Distinguishing between a capacitive type proximity sensor and an inductive switch:
Capacitive Proximity Sensor: A capacitive proximity sensor uses changes in capacitance to detect the presence or absence of an object. It works based on the principle that the capacitance between the sensor and an object changes when the object enters the sensing range.
Inductive Switch: An inductive switch, also known as an inductive proximity sensor, operates on the principle of electromagnetic induction.
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An object of mass 10.3 kg subjected to a non-zero net force moves with an acceleration of 1.3 m/s2. Determine the net force (in N) acting on it. (Enter the magnitude only.)
The object of mass of 10.3 kg subjected to a non-zero net force moves with an acceleration of 1.3 m/s², so the net force acting on the object is 13.39 N.
What is force?According to physics, a force is an effect that has the power to change an object's motion. A force can cause a massed item to accelerate or modify its velocity. A push or a pull is a straightforward method to explain force.
It is a scalar quantity with the Newton as its SI unit.
According to the question, the given values are :
Mass, m = 10.3 kg
Acceleration, a = 1.3 m/s²
Force = mass × Acceleration
Now, substitute the given values :
Force, F = 10.3 kg × 1.3 m/s²
F = 13.39 N.
Hence, the net force on the object is 13.39 N.
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In the same liquid, the pressures are equal at all points that are
A. the same distance below the liquid surface.
B. along the vertical walls of the container.
C. not touching any immersed objects.
D. not in the sunlight.
The correct option is A. which states that in the same liquid, the pressures are equal at all points that are at the same distance below the liquid surface.
This is because the pressure is determined by the weight of the liquid column above it, which is the same for all points at the same depth. The pressure along the vertical walls of the container is not equal because the liquid is in hydrostatic equilibrium which means that the pressure is not the same at all points in the liquid, and since the walls are vertical, the pressure is the same along them. The pressure at any point not touching any immersed objects is not equal to the pressure at any other point not touching any immersed objects because the pressure is determined by the weight of the liquid column above it, which is the same for all points not touching any immersed objects. The pressure is not affected by factors such as sunlight since the pressure at any point in the sunlight is equal to the pressure at any other point not in the sunlight.
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Refraction studes show that the Moho is depressed about 10 km beneath the center of the Hawaiian Islands. Assuming that this is the value of wo and that h=34 km, E= 70 GPa, v = 0.25. Pm Pw 2300 kg m-3, and g = 10 m s -2 determine the maximum bending stress in the lithosphere.
the maximum bending stress in the lithosphere is 202 MPa
hear
Given that Hite 34 km
12 2 70 9 Pa
N 2 0. 25
ρm- ρw= 2300 kgm 3
3 = 10 ms - 2
Moh depressed about 10km beneath the centre or Islands .
We know, flexural rigidity
Equation
D=E/12 (1 - V 2 )
be neath the center of Isla g
=70 x 109 pa x 103 x ( 10 m ) 312 (1 - 0.0625 )
=70 x 1021- Nm
=12X 019375Fox 10 212
=2 6: 222 x 102 Mm
Again , total maximum bending stress in the
lithosphere 6 = = 90 - ( 8 m - Pm ) 8 u
Where , Applied load of upper Surface of lithosph
We Replaced manthe rock thickness = 34 1
Bending stress = 6. 222 x 10' Alm- 2300 108 x 10->52 x 34 km
=n3 4
= 6. 2327 10 1/m- 230 0 kg x 10 m 2 x 34 x103 x]
=2 6 . 222 x 102/ nim - . 2300 X10 x 34x103 Pa
= 6222x1021 am 2 x 18 Alm
34x 34 x 34x( 103) ,m 3
6:222 X 102 Mm
2
3 4 x 3 4x34 x 109 m 3
2 6 .222 x 1012 na
34 x 34 x 39
6. 222
- x 10 2 pa
39, 304
2 0. 000 ( 5 8 307 10 - Pas
158, 83 X 108 pa .
-'. Bendig stress - 15.83 x108 pa . 782 x 10 Pa
2 15. 53 x108 pa - 7. 8 2x108 pc
Bendig stress=202 M Pa
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It is difficult to lift a bigger stone than the smaller
stone. why?
plzzz give me short and brillient answer
PLEASE HELP IM DOING A TEST
Choose all the answers that apply.
Earth:
has the most circular orbit in the solar system
has seasons because of a tilted axis
is a perfect sphere
has the largest satellite relative to its planet
takes longer than 365 days to orbit the sun
Answer:
has seasons because of a tilted axis
takes longer than 365 days to orbit the sun
Explanation:
Note: We see 365 days for a year - from an external point of view, a year would take 366 days to orbit the sun - this is because it takes slightly less than 24 hours from sunrise to sunrise because of the rotation of the earth about the sun (a sidereal year is 366 days as compared to 365 days observed on earth)
A man of mass 80 kg climbs a slope with a height of 5m. It takes him 10s to reach the top. a. How much work is done? b. Calculate the man's power
Answer:
Explanation:
if he is moving at a constant velocity, the work changes the potential energy
W = PE = mgh = 80(9.8)(5) = 3,920 J
Power is the rate of doing work
P = W/t = 3920/10 = 392 W(atts)