Select the correct answer from each drop-down menu. Thermal energy is the , and internal energy is the.

The magnitude of the force that the object exerts on the child is 100 N.

option C is the correct answer.

Newton's third law of motion states that for every action there is an equal and opposite reaction. In other words, action and reaction are equal and opposite.

Mathematically, Newton's third is given as;

Fa = Fb

where;

If the child exerts 100 N force on the object, the reaction of the object or the upward force exerted on the child by the object is 100 N in opposite direction.

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Answer:

c. Chloroplas

Explanation:

Evolution, is a process that results in changes in the genetic material of a population over time.

Answer:

648.40N

Explanation:

Centripetal acceleration is the acceleration of an object around a circular path. Centripetal for e acting on the combined mass is expressed as:

F = ma

F = mv²/r

m is the mass of the object = 143kg

v is the linear velocity = 13.8m/s

r is the radius = 42.0m

Substitute the given parameters into the formula;

F = 143*13.8²/42

F = 27,232.92/42

F = 648.40N

Hence the magnitude of the centripetal force acting on the combined mass is 648.40N

Answer:

Acceleration = 9.8m/s²

Explanation:

Given the following data;

Initial velocity = 0m/s (since it's starting from rest).

Final velocity, v = 14.7m/s

Time, t = 1.5 seconds.

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)

\(Acceleration = \frac{v - u}{t}\)

Substituting into the equation, we have;

\(Acceleration = \frac{14.7 - 0}{1.5}\)

\(Acceleration = \frac{14.7}{1.5}\)

Acceleration = 9.8m/s²

Therefore, the average acceleration of the golf ball is 9.8m/s².

The combined momentum after the collision is M * v units, where M represents the combined mass of the putty and the bowling ball, and v represents their final velocity.

When the piece of putty moving with 1 unit of momentum strikes and sticks to the initially stationary heavy bowling ball, the law of conservation of momentum applies. According to this law, the total momentum before the collision is equal to the total momentum after the collision.

Before the collision, the momentum of the putty is 1 unit (as given), and the momentum of the bowling ball is 0 since it is initially at rest. Therefore, the total momentum before the collision is 1 + 0 = 1 unit.

After the collision, the putty sticks to the bowling ball, and they move together as a combined system. Let's assume the combined mass of the putty and the bowling ball is M, and the final velocity of the combined system is v.

The momentum of the combined system after the collision is the product of the total mass and the final velocity: M * v. Since the putty sticks to the bowling ball, the final velocity of the combined system will depend on the masses of the putty and the bowling ball and the conservation of momentum equation.

Therefore, the combined momentum after the collision is M * v units, where M represents the combined mass of the putty and the bowling ball, and v represents their final velocity.

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To determine the amplitude of the machine's displacement oscillation, we can use the concept of the spring-mass system.

Given:

Mass of the machine (m) = 5.0 kg

Deflection of the springs (x) = 0.50 mm = 0.50 * 10^-3 m

Force applied (F) = 10 N

Motor speed (ω) = 1750 rpm

The force applied to the machine in operation creates an oscillation in the system. We can relate the force, mass, and displacement using Hooke's Law and the equation for simple harmonic motion.

1. Hooke's Law:

According to Hooke's Law, the force exerted by a spring is proportional to the displacement. Mathematically, it can be expressed as:

F = -k * x

where F is the force applied, k is the spring constant, and x is the displacement from the equilibrium position.

2. Simple Harmonic Motion:

In a simple harmonic motion, the displacement of the mass can be described as:

x(t) = A * cos(ωt)

where x(t) is the displacement at time t, A is the amplitude of the oscillation, ω is the angular frequency (2π times the frequency), and t is the time.

To determine the amplitude (A) of the displacement oscillation, we need to relate the force, mass, spring constant, and displacement.

First, let's find the spring constant (k) using Hooke's Law:

F = -k * x

k = -F / x

k = -10 N / (0.50 * 10^-3 m)

Next, let's calculate the angular frequency (ω) using the motor speed:

ω = (2π * frequency)

The frequency can be calculated by converting the motor speed from rpm to Hz:

frequency = 1750 rpm / 60 s

Now, we can calculate the angular frequency:

ω = (2π * frequency)

Finally, we can determine the amplitude (A) of the displacement oscillation:

A = x / cos(ωt)

Substituting the given values:

A = (0.50 * 10^-3 m) / cos(ωt)

Please note that the value of A will depend on the specific time (t) at which we want to calculate the amplitude. In this case, the amplitude will vary over time as the machine undergoes oscillations.

If you provide a specific time (t), I can help you calculate the amplitude at that particular moment.

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Hi there!

\(\boxed{\omega = 0.38 rad/sec}\)

We can use the conservation of angular momentum to solve.

\(\large\boxed{L_i = L_f}\)

Recall the equation for angular momentum:

\(L = I\omega\)

We can begin by writing out the scenario as a conservation of angular momentum:

\(I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)\)

\(I_m\) = moment of inertia of the merry-go-round (kgm²)

\(\omega_m\) = angular velocity of merry go round (rad/sec)

\(\omega_f\) = final angular velocity of COMBINED objects (rad/sec)

\(I_b\) = moment of inertia of boy (kgm²)

\(\omega_b\)= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

\(I = MR^2\)

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

\(\omega = \frac{v}{r}\)

\(L_b = MR^2(\frac{v}{R}) = MRv\)

Plug in the given values:

\(L_b = (20)(3)(5) = 300 kgm^2/s\)

Now, we must solve for the boy's moment of inertia:

\(I = MR^2\\I = 20(3^2) = 180 kgm^2\)

Use the above equation for conservation of momentum:

\(600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}\)

Answer:

Total resistance = 96 Ohms

Explanation:

Given the following data;

Resistance = 12 Ohms

Number of resistors = 8

To find the total resistance;

Method I.

Since the resistors are connected in series, we would simply multiply the resistance by the number of resistors.

Total resistance = 12 * 8

Total resistance = 96 Ohms.

Method II.

We would add the resistance of all the eight resistors together.

Total resistance = 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12

Total resistance = 96 Ohms.

The total resistance of the circuit will be "96 Ω".

Resistance: The amount of resistance to current flow throughout an electrical circuit.

Current: The movement of electrical charge carriers such as electrons has been referred to as current. The flow of current seems to be from negative (-) to positively (+) locations.

According to the question,

Resistance = 12 Ω

No. of resistor = 8

The total resistance be:

= \(Resistance\times Number \ of \ resistors\)

By substituting the values,

= \(12\times 8\)

= \(96 \ \Omega\)

Thus the above answer is right.

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Answer:

The slope of an x vs. t graph represents instantaneous velocity. As we can see, the slope of this graph is not constant- it is changing. This means that the instantaneous velocity is also changing. Therefore, the object is accelerating.

Explanation:

The fuel must be ejected at a speed of 27.9 m/s [Down] to achieve the desired course.

Let's denote the velocity of the rocket after the fuel is ejected as v_r and the velocity of the ejected fuel as v_f. The total mass of the system is M = 4739 kg + 155 kg = 4894 kg.

Before the fuel is ejected, the momentum of the system is:

p1 = M * v1 = (4739 kg + 155 kg) * 83 m/s = 408332 kg m/s [Right]

After the fuel is ejected, the momentum of the system is:

p2 = M * v2 = 4739 kg * v_r + 155 kg * v_f

The direction of the final velocity is [Right 16 Up], which means that the vertical component of the velocity is v_r * sin(16) and the horizontal component is v_r * cos(16).

Using the conservation of momentum, we have:

p1 = p2

408332 kg m/s [Right] = (4739 kg * v_r + 155 kg * v_f) * v_r * cos(16)

Solving for v_r, we get:

v_r = sqrt(408332 kg m/s [Right] / ((4739 kg * cos^2(16) + 155 kg) * cos(16)))

v_r = 88.5 m/s [Right 16 Up]

Now, we need to find the velocity of the ejected fuel v_f. Since the engine can only eject the fuel perpendicular to the motion of the rocket, the horizontal component of v_f is zero. The vertical component of v_f is equal to the vertical component of v_r:

v_f * sin(90) = v_r * sin(16)

v_f = v_r * sin(16)

v_f = 27.9 m/s [Down]

Therefore, the fuel must be ejected at a speed of 27.9 m/s [Down] to achieve the desired course.

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The post collision speed of the Mazda Miata and the  pick up truck  as they slide across the ice are respectively 6.36 m/s and 5.64 m/s.

An elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of the collision.

Given that masses of the  Mazda Miata and the pick-up truck are respectively 976.0 kg  and 3178.0 kg.

Pre-collision speed of Ima = 12.0 m/s.

As the collision is elastic in nature,

The post collision speed of the Mazda Miata =

{(976.0 - 3178.0)/(976.0 - 3178.0)} × 12.0 m/s

= - 6.36 m/s.

The post collision speed of the pick up truck =

{(2×976.0)/(976.0 - 3178.0)} × 12.0 m/s

=5.64 m/s.

Hence, the post collision speed of  the two entangled cars  as they slide across the ice are respectively 6.36 m/s and 5.64 m/s.

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If a baseball has a negative velocity and a negative acceleration, its speed is decreasing.

Velocity is a vector quantity that includes both magnitude (speed) and direction. In this case, the negative velocity indicates that the baseball is moving in the opposite direction of a chosen positive reference direction. Acceleration, on the other hand, represents the rate of change of velocity and also includes both magnitude and direction.

When the velocity and acceleration have the same sign (both negative in this case), it means that the baseball is slowing down. This is because the acceleration is acting in the opposite direction to the velocity, which results in a decrease in speed. Therefore, the speed of the baseball is decreasing.

To determine the angle turned by the wheel, we can use the equation:

θ = (ω² - ω₀²) / 2α

where:

θ is the angle turned,

ω is the final angular speed,

ω₀ is the initial angular speed,

α is the angular acceleration.

Given:

ω₀ = 33.3 rad/s,

α = 2.15 rad/s²,

ω = 72.0 rad/s.

Plugging in the values, we have:

θ = (72.0² - 33.3²) / (2 * 2.15) ≈ 948 rad.

Therefore, the angle turned by the wheel when its angular speed reaches 72.0 rad/s is approximately 948 radians.

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A 5 MHz signal will penetrate approximately twice as far as a 10 MHz signal when their initial intensity decreases by a factor of 100.

Assuming both signals travel through the same medium and encounter the same obstacles, a 5 MHz signal will penetrate approximately twice as far as a 10 MHz signal when their initial intensity decreases by a factor of 100.

The reason for this is that lower-frequency signals have longer wavelengths, which allow them to diffract more around obstacles and penetrate deeper into materials. However, as the signal's intensity decreases, its ability to penetrate obstacles and travel further decreases as well.

When the initial intensity of each signal decreases by a factor of 100, the received power of the 5 MHz signal will be 20 dB less than the received power of the 10 MHz signal. This means that the 5 MHz signal will have only 1% of the original power, while the 10 MHz signal will have 0.01% of the original power.

Thus, while the 5 MHz signal will penetrate further than the 10 MHz signal, both signals will experience significant attenuation and their range will be limited. The exact amount of penetration will depend on various factors such as the type of medium, the obstacles in the path of the signal, and the specific frequencies being used.

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The amplitude of the current in the circuit element will depend on the impedance of the element and the frequency of the applied voltage. If the frequency of the applied voltage is increased, the impedance of the circuit element may also increase, causing a decrease in the current amplitude.

On the other hand, if the impedance of the element decreases with increasing frequency, the current amplitude may increase. This behavior is described by the frequency response of the circuit element, which is characterized by its frequency-dependent impedance.

In some cases, the frequency response may exhibit resonance, where the impedance is at a minimum and the current amplitude is at a maximum at a certain frequency. The relationship between the amplitude of the current and the frequency of the applied voltage is dependent on the impedance of the circuit element and its frequency response.

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Answer:

b.

Explanation: I do not know much about this but the answer that i think it is was b.

A rock turns a reddish color when exposed to air and water. this description is evidence of chemical weathering

Chemical weathering is demonstrated by the fact that "a rock turns a reddish colour when exposed to air and water." The breakdown of rocks occurs through a process known as chemical weathering, which involves chemical interactions with elements including water, oxygen, and acids. The iron in the rock may have oxidised, which is when iron in the rock combines with oxygen and water to generate iron oxide (rust), giving the material its reddish hue. The physical weathering produced by wind-borne particles is described in Option A, the physical weathering induced by freeze-thaw cycles is described in Option B, and the physical weathering caused by gravity and the impact of the rock striking the ground is described in Option D.

Hence option C is correct.

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Answer:

D) a Battery

Explanation:

The best real-life example of direct current is a battery. Batteries have positive and negative terminals on a battery, the electrons in the wires will begin to flow to produce a current.

Among the given options, visible light comprises the least radiation in the everyday environment. Visible light is part of the electromagnetic spectrum and falls within a specific wavelength range that is detectable by the human eye.

The electromagnetic spectrum consists of various types of radiation, including radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of radiation has different wavelengths and energy levels. It is a form of electromagnetic radiation that we encounter daily through natural sunlight, artificial lighting, and reflections from various objects.

In terms of energy and potential harm to living organisms, visible light has lower energy compared to higher-energy forms of radiation like X-rays and gamma rays. While excessive exposure to ultraviolet radiation (UV) can be harmful, visible light falls within a relatively safe range of the electromagnetic spectrum. It allows us to see our surroundings and plays a vital role in our daily activities.

It is important to note that even though visible light comprises the least radiation in the everyday environment, it is still a form of electromagnetic radiation and can have specific effects on materials and biological systems under certain conditions.

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The tension in the wire attached at 50 cm is three times the tension in the wire attached at 150 cm. However, without more information, we cannot determine the specific values of the tensions.

When a body is acted upon by a number of parallel forces, it will be in equilibrium if the following conditions are met:
1. The sum of all the forces acting on the body in one direction is equal to the sum of all the forces acting in the opposite direction. This ensures that there is no net force acting on the body.
2. The sum of all the moments (torques) acting on the body about any point is equal to zero. This ensures that there is no rotational force causing the body to rotate.

Now let's apply these conditions to the given problem:

We have a uniform metal tube suspended horizontally by two vertical wires attached at distances of 50 cm and 150 cm from the ends of the tube. We need to find the tension in each wire.

To solve this, we consider the moments acting on the tube. The weight of the tube acts downward at its center, which creates a moment about the attachment points of the wires.

Let's assume the tension in the wire attached at 50 cm is T1 and the tension in the wire attached at 150 cm is T2.

The moment created by the weight of the tube about the wire attached at 50 cm is given by:

Moment1 = T1 * 0.5 m

The moment created by the weight of the tube about the wire attached at 150 cm is given by:

Moment2 = T2 * 1.5 m

Since the tube is in equilibrium, the sum of these moments must be zero:

Moment1 + Moment2 = 0

T1 * 0.5 m + T2 * 1.5 m = 0

Now, we can solve for the tensions in the wires:

T1 + 3T2 = 0

From this equation, we can express T1 in terms of T2:

T1 = -3T2

Since the tensions cannot be negative, we can ignore the negative sign.

Thus, the tension in the wire attached at 50 cm is 3 times the tension in the wire attached at 150 cm.

To find the specific values of T1 and T2, we need additional information such as the weight of the tube or any other forces acting on it.

In conclusion, the tension in the wire attached at 50 cm is three times the tension in the wire attached at 150 cm. However, without more information, we cannot determine the specific values of the tensions.

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The length of the pendulum on the Moon with a period of 1.0 s is approximately 0.0163 meters.

On the Moon, which has one-sixth of Earth's gravity, the length of a pendulum with a period of 1.0 s can be determined using the formula for the period of a pendulum:

T = 2π√(L/g)

Where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

Given that the period of the pendulum on the Moon is 1.0 s and the Moon has one-sixth of Earth's gravity, we can substitute these values into the formula and solve for L:

1.0 = 2π√(L/(1/6g))

Simplifying the equation, we can multiply both sides by (1/6g):

\(1.0 * (1/6g) = 2π√L1/6g = 2π√L\)
Now, let's square both sides to get rid of the square root:

\((1/6g)^2 = (2π√L)^21/(6g)^2 = (2π)^2L1/(36g^2) = 4π^2L\)
Simplifying further:

\(L = 1/(4π^2(36g^2))L = 1/(144π^2g^2)L ≈ 0.0163 m\)

Therefore, the length of the pendulum with a period of 1.0 s on the Moon, which has one-sixth of Earth's gravity, is approximately 0.0163 meters.

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Answer:

Explanation:

\( = \frac{s1 t1+ s2t2 + s3t3}{t1 + t2 + t3} \)

\( = \frac{20 \times 10 + 30 \times 5 + 15 \times 5}{10 + 5 + 5} \)

\( = \frac{200 + 150 + 75}{20} \)

\( = \frac{425}{20} \)

\( = 21.25 ms\)

Answer:

C. Satellite Y is experiencing a greater gravitational force than satellite

Explanation:

the more closer an object is to the surface of the Earth the more gravitational for it will feel.

If you look at the equation Fg = (Gm1m2)/r^2, the smaller the r (distance between center of 2 objects) the greater the gravitational force.

The objects collide elastically. The total initial momentum of the system is 12.2 kg⋅m/s in the x-direction and 1.0 kg⋅m/s in the y-direction.

Utilizing the standard of protection of energy, we can settle for the last energy of item 2. The complete beginning force in the x-heading is 19.6 kg⋅m/s+3.9 kg⋅m/s = 23.5 kg⋅m/s, and the absolute last energy in the x-bearing is 12.2 kg⋅m/s. In this manner, the x-part of the last force of article 2 is 23.5 kg⋅m/s-12.2 kg⋅m/s = 11.3 kg⋅m/s.

Likewise, the absolute beginning energy in the y-course is -5.4 kg⋅m/s+6.4 kg⋅m/s=1 kg⋅m/s, and the complete last force in the y-bearing is 4.3 kg⋅m/s. In this way, the y-part of the last force of item 2 is 4.3 kg⋅m/s-1 kg⋅m/s=3.3 kg⋅m/s.

We can now utilize the last momenta of item 1 and article 2 to compute their last speeds utilizing the conditions p=mv. For object 1, we have p = 12.2 kg⋅m/s I+4.3 kg⋅m/s j and m=2.5 kg, so v=p/m (4.88 m/s) I+(1.72 m/s) j. For object 2, we have p=11.3 kg⋅m/s I+3.3 kg⋅m/s j and m=4.7 kg, so v=p/m=(2.4 m/s) I+(0.7 m/s) j.

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Answer:

The answer should be 0.825

Explanation:

I took like 20 mins to figure this out lol

The time for a steel ball to hit the ground when shot horizontally off a table is independent of the initial velocity, and the formula is \(d = v_i*t + (1/2)at^2\).

To decide the time it takes for a steel ball to stir things up around town when shot evenly off a table, we can utilize the conditions of movement, explicitly the kinematic condition:

\(d = v_i*t + (1/2)at^2\)

where:

d is the distance voyaged

v_i is the underlying speed

an is the speed increase

t is the time

We can expect that the speed increase is because of gravity, which is steady and equivalent to \(9.81 m/s^2.\)

Since the ball is shot on a level plane, its underlying vertical speed is zero. Accordingly, we can work on the situation to:

\(d = (1/2)at^2\)

Settling for t, we get:

t = sqrt(2*d/a)

To decide the distance voyaged, we can utilize the way that the ball will follow an explanatory direction and will stir things up around town simultaneously it would have taken to fall upward from a similar level. Hence, we can involve the condition for the time it takes for an item to in an upward direction fall:

t = sqrt(2*h/g)

where h is the level of the table and g is the speed increase because of gravity.

Utilizing the trial information, we can decide the level of the table and the distance the ball goes prior to stirring things up around town for every speed setting of the launcher. Then, we can work out the time it takes for the ball to stir things up around town involving the condition for t.

The time it takes for the ball to stir things up around town will be the equivalent no matter what the speed setting of the launcher, as long as the ball is shot evenly with a similar starting level. This is on the grounds that the underlying speed in the level bearing doesn't influence the time it takes for the ball to upward fall.

This outcome is steady with the way that the time it takes for an item to fall upward just relies upon the level and speed increase because of gravity. Hence, failing upward from the table top to the floor beneath would bring about a similar time it takes for the ball to raise a ruckus around town when shot evenly off the table.

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The complete question is:

If the steel ball is shot horizontally off the table, how much time would it take the ball to hit the ground for each of the velocity settings of the launcher? Explain your answer using the equations of motion and your experimental data. How does this relate to the ball being dropped vertically from the table top to the floor below.

Answer: 1260km

Explanation:

If the total energy at the top is 5 J, then the total energy at the bottom of the drop would also be 5 J. Since we are ignoring air resistance, we can apply the law of conservation of energy which states that energy cannot be created or destroyed but it can only be transformed from one form to another.

Assuming that the object starts from rest, the total energy at the top of the drop will be equal to the potential energy (PE) since there is no kinetic energy (KE) present in the object when it's at rest. Mathematically, we can represent this as:

Total energy at the top (E) = PE = mgh, Where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s²) and h is the height of the drop.

Now, as the object falls down, potential energy gets converted into kinetic energy. At the bottom of the drop, all the potential energy is converted into kinetic energy since the object has no height left to fall. Mathematically, we can represent this as:

Total energy at the bottom (E) = KE

= 1/2 mv², where v is the velocity of the object at the bottom of the drop. Since we are assuming that air resistance is ignored, we can use the law of conservation of energy to relate the total energy at the top to the total energy at the bottom.

Mathematically, we can represent this as: mgh = 1/2 mv²

Simplifying, we get: v² = 2ghv

= √(2gh)

Substituting the given values, we get: v = √(2 x 9.8 x h)

= √(19.6h)

Now, we can use the formula for KE to calculate the total energy at the bottom: Total energy at the bottom (E) = KE

= 1/2 mv²

= 1/2 m(19.6h)

= 9.8mh

Since h is the height of the drop, we can see that the total energy at the bottom is proportional to the height of the drop.

In other words, if the height of the drop is doubled, the total energy at the bottom will also be doubled. Therefore, if the total energy at the top is 5 J, then the total energy at the bottom of the drop would also be 5 J.

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Answer:

Explanation: